an early submersible craft for deep-sea exploration was raised and lowered by a cable from a ship. when the craft was stationary, the tension in the cable was 5500 n . when the craft was lowered or raised at a steady rate, the motion through the water added an 1800 n drag force.
Part A
What was the tension in the cable when the craft was being lowered to the seafloor?
Express your answer to two significant figures and include the appropriate units.
Part B
What was the tension in the cable when the craft was being raised from the seafloor?
Express your answer to two significant figures and include the appropriate units.

Answers

Answer 1

Part A: When the craft is being lowered, the tension in the cable is 6387 N

Part B: When the craft is being raised, the tension in the cable is 5227 N

The weight of the craft will be equal to the force of gravity acting on it, which can be calculated using the mass of the craft and the acceleration due to gravity (g = 9.81 m/s²).

Therefore, the tension in the cable when the craft is being lowered is:

Tension = weight + drag force

Tension = (mass x g) + drag force

Tension = (unknown mass x 9.81 m/s²) + 1800 N

Tension = (unknown mass x 9.81) + 1800 N

Part A When the craft is stationary, the tension in the cable is 5500 N. This means that the weight of the craft is equal to the tension in the cable when it's not moving,

Solving for the mass:

5500 N = (mass x 9.81) + 0 N

mass = 5500 N / 9.81 m/s²

mass = 560.3 kg

Now we can substitute the mass into the expression for tension when the craft is being lowered:

Tension = (mass x 9.81) + 1800 N

Tension = (560.3 kg x 9.81 m/s²) + 1800 N

Tension = 6387 N

Therefore, the tension in the cable when the craft is being lowered to the seafloor is 6387 N.

Part B: When the craft is being raised at a steady rate, the tension in the cable will be equal to the weight of the craft minus the drag force due to the motion through the water.

Using the same mass of the craft that we calculated in Part A, we can calculate the tension in the cable when the craft is being raised:

Tension = weight - drag force

Tension = (mass x g) - drag force

Tension = (560.3 kg x 9.81 m/s²) - 1800 N

Tension = 5227 N

Therefore, the tension in the cable when the craft is being raised from the seafloor is 5227 N.

Learn more about Motion here:

https://brainly.com/question/28205978

#SPJ11


Related Questions

Calculate the net force in each scenario below:
1.
2.
3.
4.
5.
20 N
40 N
20 N
8N
10 N
3N
7N
40 N
10 N
10 N
10 N
Net Foros:
Net Force:
Net Force:
Net Force:
Net Force:
Direction of motion:
Place a star inside the boxes that are UNBALANCED

Answers

Answer:

1. Net force: 60N (⭐️)

Direction: West

2. Net force: 60N

Direction: East

3. Net force: 18N (⭐️)

Direction: East

4. Net force: 20N

Direction: No movement

5. Net force: 20N

Direction: No movement

Explanation:

Hope you understand :)

The half life of a radioactive substance is 5 hours. If 5g of the substance is left after 20 hours, determine the original mass of the substance​

Answers

Answer:

The original mass of the substance was 10g.

Explanation:

The half-life of a radioactive substance is the amount of time it takes for half of the substance to decay. In this case, the half-life is 5 hours.

We can use the half-life formula to find the original mass of the substance:

N = N0 * (1/2)^(t/T)

where:

---N0 is the initial mass of the substance

---N is the remaining mass of the substance after time t

---T is the half-life of the substance

We know that after 20 hours, only half of the substance remains:

N = N0 * (1/2)^(20/5) = 0.5 * N0

If we solve for N0, we get:

N0 = N / 0.5 = 5g / 0.5 = 10g

Therefore, the original mass of the substance was 10g.

suppose your planet at 1 meter from the basketball represents a distance of 4 x 107 km (-0.3 al) from the star. the next closest star to the sun is 4 x 1013 km away. how far away from the model star/planet would you have to be for the distances in the system to be to scale? express your answer in meters and kilometers.

Answers

Answer: The model star/planet would have to be 1,000 km away from the next closest star.

Explanation:
We need to find out the distance required for the distances in the system to be in scale.

Let's use the proportion to solve the problem:

1 m/4 × 10⁷ km = x/4 × 10¹³ km

Where x is the distance required for the distances in the system to be in scale.

Cross-multiply: 4 × 10¹³ km × 1 m = 4 × 10⁷ km × x

Simplify: 4 × 10¹³ m = 4 × 10⁷ x

Divide both sides by 4 × 10⁷ :1 × 10⁶ = x

Therefore, the distance required for the distances in the system to be in scale is 1 × 10⁶ m or 1,000 km.

So the model star/planet would have to be 1,000 km away from the next closest star.

Learn more about distance here

https://brainly.com/question/26550516

#SPJ11

We can test our stellar ages and models for the birth, evolution, and death of stars by determining if our observations of the metallicity within each component of the galaxy match our predictions. On the basis of how the life cycles of stars affect the composition of interstellar gas with time, rank the expected metallicities of the following components of our galaxy in order from lowest to highest.halo, bulge, thin disk

Answers

The rank order of expected metallicities, from lowest to highest, is Halo, Bulge, and Thin Disk.

The expected metallicities of the components of our galaxy, ranked from lowest to highest, are as follows:

1. Halo: The halo is the oldest component of our galaxy, consisting of old stars and globular clusters. It formed early in the galaxy's history when interstellar gas had low metallicity. Therefore, the halo is expected to have the lowest metallicity among the three components.

2. Bulge: The bulge is the central, densely packed region of the galaxy. It contains a mix of old and intermediate-age stars. The bulge formed through a combination of both primordial gas collapse and subsequent mergers.

3. Thin Disk: The thin disk is the relatively young and dynamically active component of our galaxy. It contains most of the young stars, star-forming regions, and open clusters.

The thin disk formed more recently from gas with a higher metallicity due to previous generations of star formation. As a result, the thin disk is expected to have the highest metallicity among the three components.

Know more about metallicity:

https://brainly.com/question/29404080

#SPj12

why is a polarized filter helpful to a photographer? A. it transmits all light

Answers

Answer:

It blocks some light, but not all.

Explanation:

The point of polarization is to get the light to travel in a single plane. The light waves occur in a single plane. The direction of the vibration of the waves is the same. With two polarized filters, it is possible to block out nearly all the light.

a satellite is in a circular orbit around an unknown planet. the satellite has a speed of 1.89 x 104 m/s, and the radius of the orbit is 2.76 x 106 m. a second satellite also has a circular orbit around this same planet. the orbit of this second satellite has a radius of 6.98 x 106 m. what is the orbital speed of the second satellite?

Answers

The orbital speed of the second satellite is 6.55 × 10³ m/s.

The formula used to find the orbital speed of a satellite is given as v=√(GM/r).

Therefore, the value of the first satellite's speed is given as v₁=1.89×104 m/s, and the radius is r₁=2.76×106 m. Using the above formula, the mass of the planet is given as:

M= v²r/G= (1.89×104 m/s)² (2.76×106 m)/(6.6743 × 10⁻¹¹ Nm²/kg²) = 5.31 × 10²⁴ kg.

Now, the orbital speed of the second satellite, given as v₂, is equal to:

v₂ = √(GM/r₂); where G = gravitational constant = 6.6743 × 10⁻¹¹ Nm²/kg²;

M = mass of the planet = 5.31 × 10²⁴ kg;

r₂ = radius of orbit of the second satellite = 6.98 × 10⁶ m.

Substituting the values given above, we get:

v₂ = √(GM/r₂)= √[(6.6743 × 10⁻¹¹ Nm²/kg²) × (5.31 × 10²⁴ kg) / (6.98 × 10⁶ m)] = 6.55 × 10³ m/s

To know more about "orbital speed" refer here:

https://brainly.com/question/541239#

#SPJ11

Which of the following best approximates the percentages of sand, clay, and silt in a silty loam? Use the soil texture table below to answer.(picture is at the bottom)Public DomainSand 10Clay 25Silt 65Sand 70Clay 10Silt 20Sand 20Clay 60Silt 20Sand 30Clay 10Silt 60'

Answers

The  correct option iD. Sand 20% Clay 20% Silt 60% best approximates the percentages of sand, clay, and silt in a silty loam.

Soil texture is the roughness or softness of soil or soil particles. Soil texture can either be smooth/soft or rough soil texture. The soil texture table helps to determine the percentages of sand, clay, and silt in a silty loam. Among the given options, the best approximation for the percentages of sand, clay, and silt in a silty loam is 20% sand, 60% silt, and 20% clay. Therefore, the correct option for the question is option D. Sand 20% Clay 20% Silt 60%So, this is the answer to your question.

More on soil: https://brainly.com/question/8395005

#SPJ11

Use Wien's law and a sunspot temperature of 3800 K to calculate the wavelength of peak thermal emission from a sunspot. Express your answer to three significant figures and include the appropriate units.

Answers

The wavelength of peak thermal emission from a sunspot can be calculated using Wien's law and a sunspot temperature of 3800 K.

Wien's Law states that the wavelength of peak thermal emission is inversely proportional to the temperature of the body emitting radiation. It is given by:

λ_max = b/T

where b is the Wien constant, 2.898 x 10^-3 m K, and T is the temperature of the emitting body. Substituting the given values into the equation,λ_max = b/Tλ_max = (2.898 x 10^-3 m K)/(3800 K)λ_max = 7.63 x 10^-7 m

The answer is expressed to three significant figures as 7.63 x 10^-7 m, with units of meters. Therefore, the wavelength of peak thermal emission from a sunspot is 7.63 x 10^-7 m.

Learn more about Wien's law  at  brainly.com/question/1417845

#SPJ11

Based on the data in the two-way frequency table, what is the probability that a randomly selected player won a bronze medal given that the player represented Spain? A. 13.9% B. 24.4% C. 22.4% D. 5.5% Examine the two-way frequency table below_ Gold Medals Silver Medals Bronze Medals USA 20 18 42 Spain 25 France 19 13 11 27 26'

Answers

Answer: 22.4%

Explanation: A = 49/201 0.24378109 B= 11/49 0.2244898 AxB/A I took the quiz, this is correct

The probability that a randomly selected player won a bronze medal given that the player represented Spain is b)24.4%.

To calculate this probability, we need to use conditional probability formula: P(Bronze Medal | Spain) = P(Spain and Bronze Medal) / P(Spain), where P(Spain and Bronze Medal) represents the number of players from Spain who won a bronze medal, and P(Spain) represents the total number of players who represented Spain.

From the given two-way frequency table, we can see that there were a total of 25 players who represented Spain, and 11 of them won a bronze medal. So, P(Spain and Bronze Medal) = 11/100.

Similarly, the total number of players who represented Spain is 25 + 19 + 13 = 57. So, P(Spain) = 57/100.

Now, we can substitute these values into the conditional probability formula to get: P(Bronze Medal | Spain) = (11/100) / (57/100) = 0.244 or 24.4%.

Therefore, the answer is B. 24.4%.

For more similar questions on probability theory.

brainly.com/question/13604758

#SPJ11

Q4. Convert these into proper vector notation:

Westward velocity of 42 km/h.

Position 6. 5 measured in m that is North of the reference point.

Downward acceleration measured in m/s2 that has a magnitude of 1. 9.

Answers

42 km/h westward velocity can be expressed as: v is equal to (-42 km/h) * (1000 m/km) / (3600 s/h) * I . Therefore, the proper vector notation for the downward acceleration of magnitude 1.9 m/s^2 is -1.9 m/s^2 in the downward direction (k).

where the unit vector pointing west is called i. If we condense this expression, we get: v = -11.67 m/s * I Hence, -11.67 m/s in the westward direction is the correct vector notation for the 42 km/h westward velocity (i). North of the reference point, position 6.5 measured in metres, can be expressed as: r = 6.5 m * j where j represents the unit vector pointing north. Hence, 6.5 m in the northward direction is the correct vector notation for the location 6.5 m north of the reference point (j). It is possible to express a downward acceleration with a magnitude of 1.9 in m/s2 as follows: a = -1.9m/s^2 * k where k is the unit vector in the downward direction. Therefore, the proper vector notation for the downward acceleration of magnitude 1.9 m/s^2 is -1.9 m/s^2 in the downward direction (k).

learn more about vector notation here:

https://brainly.com/question/17264346

#SPJ4

a waterbed heater uses 450 w of power. it is on 35 % of the time, off 65 % . part a what is the annual cost of electricity at a billing rate of $0.13 per kwhr ? express your answer using two significant figures.

Answers

The annual cost of electricity at a billing rate of $0.13 per kWhr for a waterbed heater that uses 450 W of power is $36.51.

What is the usage of the waterbed heater in a day?

For the calculation of the energy consumed, one must know the energy consumed by the heater per day. The energy consumed in one day can be calculated by multiplying the power consumed by the hours the heater is used. The power consumed by the heater is 450 W.

The heater is used 35% of the time and is off 65% of the time. The percentage of time the heater is used is calculated using the formula:

Percentage of time the heater is used = (Time heater is on/Total time) × 100

Percentage of time the heater is used = (35/100) × 100

Percentage of time the heater is used = 35%

The percentage of time the heater is off is calculated using the formula:

Percentage of time the heater is off = (Time heater is off/Total time) × 100

Percentage of time the heater is off = (65/100) × 100

Percentage of time the heater is off = 65%

Thus, the heater is used for 8.4 hours per day (i.e., 24 hours × 35%) and is off for 15.6 hours per day (i.e., 24 hours × 65%).

The energy consumed per day can be calculated by multiplying the power consumed by the time the heater is on. Energy consumed per day = Power consumed × Time heater is on

Energy consumed per day = 450 W × 8.4 hours

Energy consumed per day = 3780 Wh

Energy consumed per day = 3.78 kWh

The annual cost of electricity can be calculated by multiplying the energy consumed per year by the cost of electricity per kWh.

Annual cost of electricity = Energy consumed per year × Cost of electricity per kWh

Annual cost of electricity = 3.78 kWh × $0.13/kWh

Annual cost of electricity = $0.4914/day

Annual cost of electricity = $179.31/year

Hence, the annual cost of electricity at a billing rate of $0.13 per kWhr for a waterbed heater that uses 450 W of power is $36.51.

Learn more about Power here:

https://brainly.com/question/27442707

#SPJ11

Two very long parallel wires are a distance d apart and carry equal currents in opposite directions. The locations where the net magnetic field due to these currents is equal to double the magnetic field of one wire are found A. midway between the wires. B. The net field is not zero any where. C. a distanced/√2 to the left of the left wire and also a distance d/√2 to to the right of the right wire. a distance d /2 to the left of the left wire and also a distance d/2 to the right of the right wire. D. a distance d to the left of the left wire and also a distance d to the right of the right wire.

Answers

A distance d/√2 to the left of the left wire and also a distance d/√2 to the right of the right wire. The correct option is C.

How to calculate the distance of the magnetic field?

Let's consider a point P at a distance d/√2 to the left of the left wire. At this point, the magnetic field due to the left wire is:

B₁= μ₀I/(2π(d/√2))

Similarly, the magnetic field due to the right wire at point P is:

B₂ = μ₀I/(2π((d/√2)+d))

The net magnetic field at point P is:

Bnet = B₂ - B₁ = μ₀I/(2π((d/√2)+d)) - ₀/(2π(d/√2))

Simplifying this expression, we get:

Bnet = μ₀I/(2πd)

This is equal to the magnetic field due to one wire at a distance d from the wire. Therefore, the net magnetic field is double the magnetic field of one wire at a distance d/√2 to the left of the left wire and also a distance d/√2 to the right of the right wire. Option C is correct.

To learn more about magnetic fields follow

https://brainly.com/question/12981734

#SPJ11

calculate the electrostatic force between 1nc and 1nc charges at a distance of 1 m from each other. do not forget to mention the direction of the force, too.

Answers

The electrostatic force between 1nc and 1nc charges at a distance of 1 m from each other is 9.0 × 10^-9 N. The direction of the force is given by Coulomb's law and is along the line joining the two charges. It is either repulsive or attractive based on the type of the charges.

What is Coulomb's law? Coulomb's law is an equation used to calculate the electrostatic force between two charged particles. According to this law, the force between two point charges is proportional to the product of their charges and inversely proportional to the square of the distance between them. The equation for Coulomb's law is given by:

F = k * (q1 * q2) / r^2

Where F is the electrostatic force,k is Coulomb's constant,q1 and q2 are the charges of the particles, and r is the distance between the particles.

Given,

Charge of particle 1, q1 = 1 nc

Charge of particle 2, q2 = 1

distance between particles, r = 1

coulomb's constant, k = 9 × 10^9 N m^2/C^2

Now, we can use Coulomb's law to calculate the electrostatic force between the two charges. Substituting the given values in the equation:

F = k * (q1 * q2) / r^2= 9 × 10^9 N m^2/C^2 * (1 × 10^-9 C) * (1 × 10^-9 C) / (1 m)^2= 9.0 × 10^-9 N

Thus, the electrostatic force between 1nc and 1nc charges at a distance of 1 m from each other is 9.0 × 10^-9 N. The direction of the force is given by Coulomb's law and is along the line joining the two charges. It is either repulsive or attractive based on the type of the charges.

Learn more about  electrostatic force  at brainly.com/question/24013868

#SPJ11

The skater with a mass of 50 kg slides on an ice track with a speed of 5 m/s. How fast will she move if she throws a 2kg stone horizontally, once in front of her and once behind her, at a speed of 2m/s? Friction is not considered.

Answers

Answer:

4.92 m/s for her final velocity.

Explanation:

The momentum of the skater before throwing the stone is:

p1 = m1 * v1 = 50 kg * 5 m/s = 250 kg*m/s

where m1 is the mass of the skater and v1 is her initial velocity.

When the skater throws the stone, the total momentum of the system (skater + stone) is conserved. The momentum of the stone is:

p2 = m2 * v2 = 2 kg * 2 m/s = 4 kg*m/s

where m2 is the mass of the stone and v2 is its velocity.

Let's assume the skater throws the stone in front of her. To conserve momentum, the skater will move in the opposite direction to the stone. Let's call the skater's final velocity v3. Then:

p1 = p2 + p3

where p3 is the momentum of the skater after throwing the stone. Substituting the values we get:

250 kgm/s = 4 kgm/s + 50 kg * v3

Solving for v3, we get:

v3 = (250 kgm/s - 4 kgm/s) / 50 kg = 4.92 m/s

So the skater's speed after throwing the stone in front of her is 4.92 m/s.

If the skater throws the stone behind her, the same conservation of momentum principle applies, and we get the same result of 4.92 m/s for her final velocity.

Sorry if I'm wrong

a compacted sample of hma contains 5.1 percent asphalt by weight of total mix, and the bulk density of the hma specimen is 2455kg/m3. the specific gravity of aggregate and the asphalt binder are 2.735 and 1.022, respectively. determine the vma, vtm, and vfa, neglect-ing absorption. draw sketch and write out full equations used. no sketch and missing full equations written out, minus -5 points. fyi, following solution is not solved completely as above solution requirement.

Answers

The void in mineral aggregate (VMA) is -12.35%, the void in total mix (VTM) is 0.000990 and the voids filled with asphalt (VFA) is -12.35%.

To determine the VMA, VTM, and VFA neglecting absorption, we need to calculate the following:

[tex]VMA = [(Gmb - Gsb) / Gmb] \times 100[/tex]

[tex]VTM = Gmb / ρb[/tex]

[tex]VFA = [(Gmb - Ga) / Gmb] \times 100[/tex]

Where, Gmb = bulk specific gravity of the compacted specimen of HMA.

Gsb = bulk specific gravity of the aggregate in the HMA specimen.

ρb = bulk density of the HMA specimen

Ga = apparent specific gravity of the aggregate in the HMA specimen.

Substitute the given values we get:

[tex]Gmb = 2.435, Gsb = 2.735, \rho b = 2455\  kg/m^3[/tex],

[tex]Ga = (Gmb \times Gsa) / (5.1 + 0.049 (Gmb - 2.435)) = (2.435 \times 2.735) / (5.1 + 0.049 (2.435 - 2.435)) = 2.449[/tex]

By substituting these values in the above formula, we get:

[tex]VMA = [(2.435 - 2.735) / 2.435] \times 100 = -12.35[/tex]%

[tex]VTM = 2.435 / 2455 = 0.000990[/tex]

[tex]VFA = [(2.435 - 2.735) / 2.435] \times 100 = -12.35[/tex]%

Hence, VMA = -12.35%, VTM = 0.000990, VFA = -12.35%.

The minus sign indicates that the voids are insufficient. Therefore, the mix is unstable.

Learn more about specific gravity:

https://brainly.com/question/20422535

#SPJ11

in theory, a single earthquake should have only one magnitude. true or false?

Answers

True. Earthquakes should have only one magnitude, but in practice, different measurement methods and aftershocks can result in some level of uncertainty and multiple values.

The magnitude of an earthquake is a measure of the amount of energy released during a seismic event. Theoretically, a single earthquake should only have one magnitude, which is determined by analyzing the amplitude of the seismic waves recorded on seismographs. However, in practice, different methods of measurement or different seismic stations can yield slightly different magnitude values, resulting in some level of uncertainty in the reported magnitude. Furthermore, earthquakes can cause aftershocks, which are smaller seismic events that occur after the main earthquake. These aftershocks can have their own magnitudes, which are typically smaller than the main earthquake but can still cause damage and contribute to the overall seismic activity in the region.

learn more about aftershocks here:

https://brainly.com/question/6843834

#SPJ4

Milk with a density of 970 kg/m ∧ 3 is transported on a level road in a 9−m long, 3−m diameter cylindrical tanker. The tanker is completely filled with milk, i.e., no air space in the tank. If the truck is accelerating from a stop signal at 7.0 m/s ∧ 2 to the left, determine the pressure difference between the maximum and minimum pressures in the tank. Depict on the figure the location of the minimum and maximum pressures in the tank.

Answers

ΔP = (970 kg/m^3)(7.0 m/s^2)(4.26 m) = 29,852 Pascal. Therefore, the pressure difference between the maximum and minimum pressures in the tank is 29,852 Pa. The minimum pressure occurs at the bottom of the tank, while the maximum pressure occurs at the top of the tank.

The pressure difference between the maximum and minimum pressures in the tank can be calculated using the equation for pressure:

P = ρgh

where P is the pressure, ρ is the density of the milk, g is the acceleration due to gravity, and h is the height of the liquid column. Since the tanker is cylindrical and completely filled with milk, the height of the liquid column can be determined using the formula for the volume of a cylinder:

V = πr^2h

where V is the volume of the milk, r is the radius of the tanker (which is half of the diameter), and h is the height of the milk column. Solving for h, we get:

h = V / (πr^2)

The volume of the milk can be determined using the formula for the volume of a cylinder:

V = πr^2h

where r is the radius of the tanker (which is half of the diameter), and h is the length of the tanker. Substituting the given values, we get:

V = π(3/2)^2(9) = 31.8 m^3

The height of the liquid column is:

h = V / (πr^2) = 31.8 / (π(3/2)^2) = 4.26 m

The pressure difference between the maximum and minimum pressures in the tank can be calculated using the formula:

ΔP = ρgh

where ΔP is the pressure difference, ρ is the density of the milk, g is the acceleration due to gravity, and h is the height of the liquid column. Substituting the given values, we get:

ΔP = (970 kg/m^3)(7.0 m/s^2)(4.26 m) = 29,852 Pa

Therefore, the pressure difference between the maximum and minimum pressures in the tank is 29,852 Pa. The minimum pressure occurs at the bottom of the tank, while the maximum pressure occurs at the top of the tank.

For more such questions on Pressure

https://brainly.com/question/20492463

#SPJ11

consider the specific example of a positive charge q moving in the x direction with the local magnetic field in the y direction. in which direction is the magnetic force acting on the particle?

Answers

The magnetic force acting on the particle is perpendicular to both the velocity of the particle and the magnetic field. Therefore, the force is in the z direction.


The magnetic force is acting in the direction of the z-axis. When a positive charge q moves in the x direction with the local magnetic field in the y direction, the magnetic force acting on the particle is in the direction of the z-axis. It is also important to note that the magnitude of the magnetic force acting on the particle is proportional to the magnitude of the charge q and the magnitude of the magnetic field.

A magnetic field is a vector field that can be depicted by magnetic lines of force. They are concentrated in magnetic poles and tend to flow from the North Pole to the South Pole, with these imaginary lines never intersecting each other. Magnetic fields are present in regions of space around magnets and moving electric charges (electric currents).As per the right-hand rule, when a positive charge q moves in the x direction with the local magnetic field in the y direction, the magnetic force acting on the particle will be directed in the z-axis direction. The right-hand rule is a technique that can be used to establish the direction of a magnetic field around a wire or a conductor when there is a flow of electric current in it.

Read more about force :

https://brainly.com/question/12785175

#SPJ11

An automatic saw has several forces acting on it. In a Cartesian system, a position-dependent force applied to the saw is =-kxy2j, with k = 2.50 N m³. Let's consider the displacement of the saw from the origin to point C (4.0 m, 4.0 m). Calculate the work done on the saw by if the displacement is along the straight-line y = x that connects these two points.​

Answers

The work done on the saw by the force if the displacement is along the straight-line y = x that connects these two points is -640.0 J.

How to calculate work done?

To calculate the work done on the saw by the force as it moves along the straight-line y = x that connects the two points, we need to first find the displacement vector and then use it to calculate the work done.

The displacement vector from the origin to point C is given by:

r = (4.0 m) i + (4.0 m) j

The force acting on the saw is given by:

F = -kxy² j = -2.50 (N m³) (x) (y²) j

Since it is moving along the straight-line y = x, we can substitute x = y into the expression for F:

F = -2.50 (N m³) (x) (y²) j = -2.50 (N m³) (y³) j

Substituting x = y = 4.0 m:

F = -2.50 (N m³) (4.0 m)³ j = -160.0 j N

The work done by the force is given by the dot product of the force and displacement vectors:

W = F · r = (-160.0 N j) · (4.0 m i + 4.0 m j)

W = (-160.0 N) (4.0 m cos(45°))

W = -640.0 J

Therefore, the work done on the saw by the force as it moves along the straight-line y = x that connects the two points is -640.0 J.

Find out more on Cartesian system here: https://brainly.com/question/4726772

#SPJ1

my favorite radio station is npr, which transmits a signal that is has a wavelength of 3.38 m. what is the frequency of this signal? remember, light speed is 3.0 x108 m/s.

Answers

The frequency of NPR radio station is 8.87 x 107 Hz.

What is frequency?

Frequency is the number of waves that pass a fixed point in a given amount of time. The unit of frequency is hertz (Hz).

What is wavelength?

The distance between two successive crests or troughs of a wave is known as wavelength. The unit of wavelength is meters.

What is the formula to calculate frequency?

The frequency of a wave is equal to the speed of light divided by its wavelength. In mathematical terms, it can be written as:

F = c/λ

where

F is frequency,c is the speed of light, and λ is the wavelength given in meters.

What is the frequency of NPR radio station?

Given:

Wavelength of the signal = λ = 3.38 mSpeed of light = c = 3.0 x 108 m/sFrequency of the signal = ?

Formula:

F = c/λ

Substitute the given values:

F = (3.0 x 108)/3.38F = 8.87 x 107 Hz

Therefore, the frequency of the NPR radio station is 8.87 x 107 Hz.

Learn more about NPR radio station: https://brainly.com/question/28483533

#SPJ11

Question 15 (3. 33 points) Solve: What work is done when 3. 0 C is moved through an electric potential difference of 1. 5 V?

A)
0. 5 J

B)
2. 0 J

C)
4. 0 J

D)
4. 5 J

Answers

The following formula can be used to determine the work involved in moving a charge via an electric potential difference:

W = qΔV

where W stands for work completed, q for charge transported, and V for potential difference.

Inputting the values provided yields:

W = (3.0 C) x (1.5 V) = 4.5 J

As a result, 3.0 C moving across a 1.5 V electric potential differential requires 4.5 J of labour.

Response: D) 4.5 J

learn more about electric potential here:

https://brainly.com/question/12645463

#SPJ4

4. Once the child in the sample problem reaches the bottom of the hill,
she continues sliding along flat; snow-covered ground until she comes
to a stop. If her acceleration during this time is -0.392 m/s², how long
does it take her to travel from the bottom of the hill to her stopping
point?

Answers

Answer:

8.04 seconds

Explanation:

Assuming that the child starts from rest at the bottom of the hill and travels until she comes to a stop, we can use the following kinematic equation:

v_f^2 = v_i^2 + 2ad

where v_f is the final velocity (which is zero since the child comes to a stop), v_i is the initial velocity (which is the velocity at the bottom of the hill), a is the acceleration (-0.392 m/s²), and d is the distance traveled.

We can solve for d:

d = (v_f^2 - v_i^2) / (2a)

= (0 - v_i^2) / (2-0.392)

= v_i^2 / 0.784

Since the child is sliding along flat snow-covered ground, there is no change in elevation, so we can use the distance traveled from the bottom of the hill to the stopping point as the distance d.

To find the time it takes for the child to travel this distance, we can use the following kinematic equation:

d = v_it + 0.5a*t^2

where t is the time and all other variables are as previously defined.

Substituting the expression for d obtained above, we get:

v_i^2 / 0.784 = v_it + 0.5(-0.392)*t^2

Solving for t, we get:

t = (2 * v_i) / 0.392

We still need to find the value of v_i, the initial velocity of the child at the bottom of the hill. To do so, we can use conservation of energy. The child starts at rest at the top of the hill, so all the initial energy is potential energy. At the bottom of the hill, all the potential energy has been converted to kinetic energy. Assuming no energy is lost to friction, we can equate these two energies:

mgh = 0.5mv_i^2

where m is the mass of the child, g is the acceleration due to gravity (9.8 m/s²), and h is the height of the hill.

Solving for v_i, we get:

v_i = √(2gh)

Substituting this expression for v_i into the expression for t obtained earlier, we get:

t = (2 * √(2gh)) / 0.392

Plugging in the values of g, h, and a, we get:

t = (2 * √(29.820)) / 0.392 = 8.04 seconds

A student walks 1.0 kilometer due east and 1.0 kilometer due south. Then
she runs 2.0 kilometers due west. The magnitude of the student's
resultant displacement is closestto
A. 3.4 km
B. 1.4 km
C. 4.0 km
D. O km

Answers

The resulting displacement will be 3.4 km. The correct option is A.

How to calculate the displacement?

The displacement is calculated by finding the displacement from east to west, which is 2.0 km, and subtracting the displacement from north to south, which is 1.0 km.

A student walks 1.0 kilometers due east and 1.0 kilometers due south. Then she runs 2.0 kilometers due west. The magnitude of the student's resultant displacement is closest to 3.4 km.

To begin with, we may use the Pythagorean Theorem to determine the resultant displacement's magnitude. The Pythagorean Theorem is a formula that is used to determine the length of a right triangle's sides when one is missing. This theorem is used to calculate the magnitude of the resultant displacement, which is a quantity. It's a good idea to draw a diagram to help you understand the problem.

Here's a rough sketch of the scenario: We will now apply the Pythagorean theorem in this way: The resultant displacement's magnitude is 3.4 kilometers. Thus, the correct option is A.

To know more about displacement follow

https://brainly.com/question/14637077

#SPJ11

Which of the following statements are true? Choose all that apply.- The magnetic force is always perpendicular to both the magnetic field and the velocity of the charge .- Magnetic fields cause charges to speed up.- Magnetic fields are created by moving charges.- Magnetic fields don't do any work on charges.- The magnetic field is always perpendicular to the velocity of the charge.- Magnetic fields deflect moving charges.

Answers

The following statements are true:

The magnetic force is always perpendicular to both the magnetic field and the velocity of the charge.Magnetic fields don't do any work on charges.Magnetic fields deflect moving charges.

Magnetic fields are created by moving charges, and the magnetic field is always perpendicular to the velocity of the charge.


The magnetic force is always perpendicular to both the magnetic field and the velocity of the charge. The magnetic force is always perpendicular to both the magnetic field and the velocity of the charge. Magnetic force is the force on a charged particle that is due to the magnetic field. The magnetic force is always perpendicular to both the magnetic field and the velocity of the charge. This implies that it can change the direction of motion of the particle, but not the speed of the particle.

Magnetic fields don't do any work on charges because they always act perpendicular to the motion of the charge. Since work is defined as force times the distance over which it acts and the magnetic field is always perpendicular to the direction of motion, the angle between force and displacement is 90°, and the work done is zero. Magnetic fields deflect moving charges. Magnetic fields deflect moving charges because magnetic fields exert a force on a moving charge. The direction of the magnetic field is perpendicular to the direction of motion of the charge, causing it to experience a deflecting force.

You can learn more about the magnetic force at: https://brainly.co.id/tugas/50355801

#SPJ11

an unsaturated parcel of air has a temperature of -5c at an elevation of 3000 meters. the parcel, remaining unsaturated, sinks all the way to the surface. what is the temperature of the parcel when it reaches the surface?

Answers

The temperature of the unsaturated parcel of air when it reaches the surface will be higher than -5°C. As the parcel descends, it will expand, which increases the air's internal energy and causes the temperature to rise. The amount of temperature rise depends on the rate of descent, which is determined by the parcel's buoyancy and surrounding air density.


In general, the temperature increase of an unsaturated parcel of air is approximately 0.65°C per 100 m of descent. For a parcel descending from 3000 m elevation to the surface, the temperature increase will be approximately 19.5°C (0.65°C/100 m * 3000 m). Therefore, the temperature of the unsaturated parcel of air when it reaches the surface will be approximately 14.5°C (19.5°C + -5°C).


The temperature of the unsaturated parcel of air when it reaches the surface after descending from an elevation of 3000 meters is +11°C.

What is the unsaturated parcel of air?

In meteorology, an unsaturated parcel of air refers to a parcel of air that has a relative humidity that is less than 100 percent. If the temperature of the unsaturated parcel of air is lower than the dew point temperature, the relative humidity of the parcel of air is decreased as the temperature of the air rises. In this case, since the parcel is unsaturated, we can make the assumption that the lapse rate is dry and equal to 10°C/km or 1°C/100 meters. Calculating the temperature of the unsaturated parcel when it reaches the surface can use the dry adiabatic lapse rate to determine the temperature of the unsaturated parcel of air when it reaches the surface. Since the lapse rate is dry and the parcel is unsaturated, the dry adiabatic lapse rate is used in the calculation. The formula used in this calculation is: T = T_0 + (dry adiabatic lapse rate × altitude)where T = temperature, T_0 = initial temperature, and altitude = elevation temperature of the unsaturated parcel of air at an elevation of 3000 meters is -5°C. Using the dry adiabatic lapse rate of 1°C/100 meters, we get: Altitude = 3000 meters Dry adiabatic lapse rate = 1°C/100 metersInitial temperature (T_0) = -5°CT = -5°C + (1°C/100 meters × 3000 meters)T = -5°C + 30°CT = 25°CAfter descending to the surface, the temperature of the unsaturated parcel of air is +11°C, according to the above calculation.

For more information follow the link: https://brainly.com/question/11464844

#SPJ11

A particle in an infinite square well potential has an initial wave function psi (x, t = 0) = Ax (L - x). Find the time evolution of the state vector. Find the expectation value of the position as a function of time.

Answers

The position expectation value as a function of time is constant and is equal to L/3.

Given a particle in an infinite square well potential has an initial wave function Ψ (x, t = 0) = Ax (L - x).The time evolution of the state vector: The time evolution of the state vector is given by Ψ(x,t) = ΣC_nΨ_n (x) e^(-iE_n t/h).The expectation value of the position as a function of time:The expectation value of the position as a function of time is given by the formula given below:x = Σa_n^2x_nΨ_n(x)Ψ_n*(x). Where,

a_n is the coefficient for each energy level.

Energy levels for infinite square well potential is given byE_n = n^2h^2 / 8mL^2Now, let us find the value of coefficient A. We know that a particle in a square well is normalized using the following formula:

∫Ψ^2 dx = 1. 0 to L∫Ax(L-x)^2dx = 1A(L^3)/3 = 1, A = √(3/L^3).

Now, the wavefunction for the particle is given by:

Ψ (x, t = 0)

= Ax (L - x)

= √(3/L^3) x (L - x).

Now, we can express this wave function in terms of the energy eigenfunctions as below:

Ψ (x, t = 0)

= Σ a_nΨ_n (x)

= Σa_n sin((nΠx)/L).

We can calculate the value of coefficient a_n by integrating the product of the initial wavefunction with the energy eigenfunctions, which is given by: a_n = 2/L ∫Ψ(x, t = 0) sin((nΠx)/L) dx.

Now, let us calculate the value of coefficient

a_n.a_n = 2/L ∫Ψ(x, t = 0) sin((nΠx)/L) dxa_n

= 2/L ∫√(3/L^3) x (L - x)sin((nΠx)/L) dxa_n = 2√3/L^2 ∫x(L - x)sin((nΠx)/L) dx.

From the previous results of integration,

a_n = (-1)^n+1 24√3/nΠ^3

a_n = (-1)^n+1 24√3/nΠ^3

Ψ(x,t) = ∑ a_nΨ_n(x) exp(-iE_n t/ℏ). Where E_n = n²h²π² / 2mL².

Substituting the values of a_n in the above formula, Ψ(x,t) = Σ(-1)^n+1 24√3/nΠ^3 sin(nΠx/L) exp(-in²π²h²t/2mL²ℏ²). Expectation value of the position as a function of time: The expectation value of the position is given by the formula, x = Σa_n²x_n. Where x_n is the position of nth energy level.

So, x_n = L/nSo,x = L∑a_n²/n From the previous results of coefficient, Σa_n²/n = 1/3. Now, x = L/3. Hence the position expectation value as a function of time is constant and is equal to L/3.

Learn more about expected value: brainly.com/question/24305645

#SPJ11

If the resulting trajectory of the charged particle is a circle, what is ⍵, the angular frequency of the circular
motion?
Express ⍵ in terms of g, m, and Bo.

Answers

The angular frequency of circular motion is given by the expression:

ω = [tex]\sqrt{qB/m}[/tex]

If the resulting trajectory of the charged particle is a circle, the angular frequency (ω) of the circular motion can be expressed in terms of g, m, and Bo as follows:

ω = [tex]\sqrt{qB/m}[/tex]

where q is the charge of the particle, B is the magnetic field strength, and m is the mass of the particle.

This formula is known as the cyclotron frequency equation.

The circular motion occurs because the magnetic force (F = qvB) on the charged particle is perpendicular to its velocity (v) and results in a centripetal force that keeps the particle in a circular path with a constant speed.

The angular frequency (ω) represents the rate at which the particle completes a full revolution (2π radians) around the center of the circular path per unit of time.

To know more about cyclotron frequency, refer: https://brainly.com/question/12946099

#SPJ11

how far, in centimeters, would you have to compress this spring to store this energy?

Answers

Use the equation for elastic potential energy to determine how far a spring must be squeezed to store a given quantity of energy. Adjust the equation to account for x, then, if required, convert to centimeters.

The elastic potential energy equation must be used to determine how far a spring would have to be compressed to store a certain quantity of energy. This equation links the spring constant and the distance a spring is compressed or extended to the energy contained in the spring. With the spring constant and the required quantity of energy to be stored in the spring, the equation may be changed to solve for the distance x. You may convert a distance measured in meters to centimeters by multiplying the result by 100. To prevent mistakes, it's crucial to utilise consistent units throughout the computation.

learn more about elastic potential here:

https://brainly.com/question/29311518

#SPJ4

Assume the motions and currents mentioned are along the x axis and fields are in the y direction.
(a) Does an electric field exert a force on a stationary charged object?
YesNo
(b) Does a magnetic field do so?
YesNo
(c) Does an electric field exert a force on a moving charged object?
YesNo
(d) Does a magnetic field do so?
YesNo
(e) Does an electric field exert a force on a straight current-carrying wire?
YesNo
(f) Does a magnetic field do so?
YesNo
(g) Does an electric field exert a force on a beam of moving electrons?
YesNo
(h) Does a magnetic field do so?
YesNo

Answers

(a) Yes, an electric field can exert a force on a stationary charged object. A stationary charged object will experience a force in the direction of the electric field due to the Coulombic interaction between the charges.

(b) No, a magnetic field does not exert a force on a stationary charged object. A stationary charged object does not experience a force due to a magnetic field unless it is moving.

(c) Yes, an electric field can exert a force on a moving charged object. A moving charged object will experience a force perpendicular to its velocity and the electric field direction, known as the Lorentz force.

(d) Yes, a magnetic field can exert a force on a moving charged object. A moving charged object in a magnetic field will experience a force perpendicular to both its velocity and the magnetic field direction, also known as the Lorentz force.

(e) Yes, an electric field can exert a force on a straight current-carrying wire. The electric field exerts a force on the charges in the wire, causing them to move, which results in a net force on the wire.

(f) Yes, a magnetic field can exert a force on a straight current-carrying wire. The magnetic field exerts a force on the moving charges in the wire, resulting in a net force on the wire.

(g) Yes, an electric field can exert a force on a beam of moving electrons. The electric field exerts a force on the electrons, causing them to accelerate or decelerate depending on the direction of the field.

(h) Yes, a magnetic field can exert a force on a beam of moving electrons. The magnetic field exerts a force on the moving electrons, causing them to experience a deflecting force perpendicular to their velocity and the magnetic field direction.

To learn more about electric field refer to:

brainly.com/question/15800304

#SPJ4

C. Demonstrate the effect of simple machines on work.
Simple machines make work.
but not
Explain which simple machine(s) you can use in each situation and how
it will help make work easier:
1. Putting a motorcycle into the back of a trailer.
2. Lifting a flag to the top of the flagpole.
3. Moving dirt from the front yard to the backyard.
4. Attaching two boards together.
5. Splitting a log in half.
6. Cutting paper.
7. Lifting a car to change the tire.
8. Moving from the bottom floor of the house to the top floor.
9. Opening a can of peaches.
10. Cutting a piece of cheese.

Answers

Putting a motorcycle into the back of a trailer: A ramp is a simple machine that can be used to make this task easier. By placing a ramp at the back of the trailer, the motorcycle can be rolled up the ramp instead of being lifted manually.

The Explanation of the simple machines to be used

Lifting a flag to the top of the flagpole: A pulley is a simple machine that can be used to make this task easier. By attaching a pulley to the top of the flagpole and another pulley at ground level, a rope can be run through the pulleys, allowing the flag to be lifted with less force.

Moving dirt from the front yard to the backyard: A wheelbarrow is a simple machine that can be used to make this task easier. By loading dirt into the wheelbarrow and pushing it, the person doing the work can move more dirt with less effort.

Attaching two boards together: A screw is a simple machine that can be used to make this task easier. By using a screwdriver to turn a screw into one board and then into the other, the boards can be securely attached with less effort.

Splitting a log in half: A wedge is a simple machine that can be used to make this task easier. By positioning a wedge at the center of the log and hitting it with a mallet or hammer, the log can be split into two pieces with less force.

Cutting paper: Scissors are a simple machine that can be used to make this task easier. By using the scissors' blades to apply force to the paper, the person cutting can apply less force than if they were tearing the paper by hand.

Lifting a car to change the tire: A jack is a simple machine that can be used to make this task easier. By placing the jack under the car and using a handle to lift the car off the ground, the person changing the tire can exert less force than if they were trying to lift the car manually.

Moving from the bottom floor of the house to the top floor: Stairs are a simple machine that can be used to make this task easier. By using the inclined plane formed by the stairs, the person climbing the stairs can expend less effort than if they were climbing a straight ladder.

Opening a can of peaches: A can opener is a simple machine that can be used to make this task easier. By using the can opener's sharp blade to cut through the can lid, the person opening the can can apply less force than if they were trying to pry the lid off by hand.

Cutting a piece of cheese: A knife is a simple machine that can be used to make this task easier. By using the knife's sharp edge to cut through the cheese, the person cutting can apply less force than if they were trying to tear the cheese by hand.

Read more about simple machines here:

https://brainly.com/question/28750066

#SPJ1

A simple machine is an expression used to basically describe a tool that helps make work easier.

What are examples of simple machines?

A simple machine is a mechanical device that changes the direction or magnitude of a force such that things can be lifted with less effort.

For example, a lever system like a crane could be used to put a motorcycle into the back of a trailer; or to lift a flag to the top of the flagpole. While, an inclined plane, such as a ramp, can be used to move dirt from the front yard to the backyard. And a screw can be used to attach two boards together.

A wedge, on the other hand, can be used to split a log in half.  A pair of scissors, which is a type of lever, can be used for cutting paper. Meanwhile, a hydraulic jack could be used for lifting a car to change the tire.

A can opener, which is also a type of wedge can be used for opening a can of peaches. And then, lastly, a knife, which is a type of wedge, is ideal for cutting a piece of cheese.

You can learn more about simple machines here https://brainly.com/question/14696504

#SPJ1

Other Questions
determine how houses can constructed from writing a story about a boy who wants to join the circus using building blocks? 4. Using a series of arrows, draw the branched metabolic reaction pathway described by the following statements, and use the diagram to answer the questions. Pyruvate can be converted to either Oxaloacetate or ActeylCoA.AcetylCoA can be converted to Citrate.Citrate can be converted to KetoglutarateKetoglutarate can be converted to Glutamate or Succinate.Glutamate can be converted to Glutamine.Succinate can be converted to Fumarate.The enzyme that converts Succinate to Fumarate requires Mg++ Glutamine is a competitive inhibitor of the enzyme that catalyzes reaction of Ketoglutarate to Glutamate.Fumarate is a noncompetitive inhibitor of the enzyme that catalyzes the reaction of Pyruvate to AcetylCoA.Explain the function of Mg++ When the concentration of fumarate is very high, explain what happens to the concentrations of Glutamine and Oxaloacetate?Is this an example of feedback inhibition or allosteric regulation? Explain your answer. What other information might be needed to make a better answer? PLS HELP!!!Match the terms to the appropriate definitions or descriptions albert speer list 7 fast facts about his life and role during the holocaust. what is controversial about him? what does two check marks mean on a text message on android Kaitlin likes a particular design theme, but she is not sure about every single color for bullets, backgrounds, etc. found in the theme. which feature should she apply to modify the theme to her liking? a. background style b. edit master slides c. theme variantsd. custom slide Volcanic activity created the _____ that is important to the economy of the village of Vestmannaeyjar on the island of Heimaey, near Iceland. fishing port. 13Select the correct answer.Solve the following equation for x.-x-36=0 .OB.OC.O D.X = 1; x = -36x= -1; x = 36x = -6; x = 6x=-18; x = 18 Determine which one of the three portfolios dominates another. Name the dominated portfolio and the portfolio that dominates it. Portfolio Green has an expected return of 23 percent and risk of 30 percent. The expected return and risk of portfolio Red are 22 percent and 24 percent, and for the Orange portfolio are 22 percent and 23 percent. Portfolio Red dominates portfolio Orange. Portfolio Orange dominates portfolio Red. Portfolio Green dominates portfolio Red. Portfolio Green dominates portfolio Orange. .2 In the diagram below, given that XY = 3cm, XZY = 30 and YZ = x, is it possible to solve for x using the theorem of Pythagoras? Motivate your answer. Show Calculations choose all that apply. how do you determine the authority of a piece of content? Determine whether each of the following conditional statements is true or false. (a) If 10 What 3 part chamber is shared between the respiratory and digestive systems? after a year during which interest is compounded quarterly, an investment of $800 is worth $851. what is the annual rate of interest? what is the effective annual yield? A group of 500 middle school students were randomly selected and asked about their preferred television genre. A circle graph was created from the data collected.a circle graph titled preferred television genre, with five sections labeled drama 14 percent, sports 22 percent, documentaries, reality 20 percent, and sci-fi 20 percentHow many middle school students prefer the Documentaries television genre? 24 76 120 86.4 1. Most medicines are derived from plants. For example a natural compound can undergo aminor chemical modification to give a currently used drug. Give an illustrated diagram to provethe above statement (10 marks) Solve for x. using the tangent lines.50 degXx =[?]^ true or false to complete a 20 person-month project in 10 months, a team should have 4 full-time staff members assigned to the project which of the following issues are not included in a true learning disability? multiple select question. Explain 2 ways the goal setting can help learners for individuals who have lost their income due to Covid 19 positively change their situation