An astronaut travels to a star system 6.5 ly away at a speed of 0.80c . Assume that the time needed to accelerate and decelerate is negligible.How much time elapses in earth between the launch and the arrival of the first radio message from the astronaut saying that she has arrived? please 911

    I think I would most likely remember car, level, dog, and book. I think I would remember these words because car and level came first, I love dogs, and I like reading books. I can associate something with dogs and books so it helps me remember those words.

           [Visual encoding is when people remember things by pictures in their head, but I have aphantasia so I am honestly not the best person to answer this question

Answer:

-2+4-22--43

Explanation

This is the correct answer

Answer:

Steel

Explanation:

the most commonly used metal in the world

what's your question?

Answer:

a. as the distances increases , the gravitational force decreases

Answer:

Explanation:

Answer:

bonjour

Explanation:

bye

The definition of electric field, Coulomb's law and Newton's second law allow to find the results for the questions about the electric field and the oscillation of the test charge are:

  a) In the attachment you have the scheme of the system

  b) The point where the electric field is zero is: x = 0 m

  c) The angular velocity of the test charge is w = 0.5 rad / s

Given parameters

To find

    a) system scheme

    b) point where the field is zero

    c) The angular velocity of q₃

The electric field is the field produced by a distribution of electric charges at a point in space, it is a vector quantity, for the special case that the charges are in one dimension the sum of the field produced by a series of charges is reduced to the sum algebraic. The field produced by point charges is:

     E = [tex]k \sum \frac{q_i}{r_i^2}[/tex]  

Where E is the electric field, k is the Coulomb constant, q the value of the charge and r the distances from the charge to the point of interest.

a) In the attachment we can see a diagram of the system, the reference system, the location of the charges and the electric field vectors are shown.

b) From the diagram we see that each field is in the opposite direction, therefore the total field is:

          [tex]E_{total} = E_1 - E_2 \\E_{total}= k \frac{q_1}{(-0.5- x)^2} - k \frac{q2}{(0.5-x)^2 }\\\\E_{total = 0[/tex]

           [tex]\frac{q}{(0.5+x)^2 } = \frac{q}{(0.5-x)^2}[/tex]

The value of the two charges is the same, therefore the value of position x is:

            x = 0 m

The point where the total electric field becomes zero is at the origin of the coordinate system.

c) We look for the value of the force on the test charge introduced q₃, for this using the Coulomb equation that establishes that the force is proportional to the product of the electric charges and is inversely proportional to the square of the distance

            [tex]F_{13} = k \frac{q_1 q_3x}{(x+0.5)^2}\\F_{23} = k \frac{q_2 q_3}{(x-0.5)^2 }[/tex]

Newton's second law gives the relationship between the net force and the product of mass and acceleration.

           [tex]\sum F = m \a \\k q q_3 [ \frac{1}{(x+0.5)^2} - \frac{1}{(x-0.5)2 } }] = m \frac{d^2x}{dt^2}[/tex]

if we use the binomial development

          (0.5 + x)⁻² = 0.5 +2 x

          (0.5 -x)⁻² = 0.5 -2x

we substitute

         k q q₃ [-4x] = [tex]m \frac{d^2x}{dt^2}[/tex]  

         [tex]-(\frac{4k \ q \ q_3}{m}) \ x = m \frac{d^2x}{dt^2}[/tex]    

In oscillatory motion the general equation of motion is

          [tex]- w^2 \ x = \frac{d^2x}{dt^2}[/tex]

Equating the two expressions the angular velocity is

         [tex]w^2 = \frac{4k \ q \q_3}{m}[/tex]  

Let's calculate.

         w²= [tex]\frac{4 \ 9 \ 10^9 \ 7 \ 10^{-9} \ 1 \ 10^{-9}}{1 \ 10^{-6}}[/tex] a 4 9 10⁹ 7 10-9 1 10-9 / 1 10-6

         w =[tex]\sqrt{0.252}[/tex]

         w = 0.5 rad / s

In conclusion, using the definition of electric field, Coulomb's law and Newton's second law we can find the results for the questions about the electric field and the oscillation of the test charge are:

  a) In the attachment you have the scheme of the system.

  b) The point where the electric field is zero is: x = 0 m

  c) The angular velocity of the test charge is w = 0.5 rad / s

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Answer:

Albino possibilities

Explanation:

The force electrostatic charges allows us to find the signs of the charge of the spheres are:

Electrostatics studies the force between objects with electric charges, finding that objects with charges of the same sign repel and objects with charges of different signs attract.

It indicates that we have three balls hanging, balls 1 and 2 attract each other, consequently they must have a different sign of charge.

Spheres 2 and 3 repel each other, therefore their charge must be of the same sign.

Let's analyze all the possibilities that meet the two previous conditions.

Spheres of non-conductive material.

Spheres 1 and 3 of non-conductive and sphere 2 of metallic  material.

In conclusion using the force electrostatic charge we can find the signs of the charge of the spheres are:

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This question involves the concepts of general gas equation and pressure.

The force exerted by the gas on one of the walls of the container is "74.08 KN".

First, we will use the general gas equation to find out the pressure of the gas:

[tex]PV = nRT[/tex]

where,

P = Pressure of the gas = ?

V = Volume of cube = (side length)³ = (10 cm)³ = (0.1 m)³ = 0.001 m³

n = no. of moles = 3 (since molecules equal to avogadro's number make up 1 mole)

R = general gas constant = 8.314 J/mol.K

T = Absolute Temperature = 24°C + 273 = 297 K

Therefore,

[tex]P = \frac{(3)(8.314\ J/mol.k)(297\ K)}{0.001\ m^3}[/tex]

P = 7407.78 KPa

Now, the force on one wall can be given as follows:

[tex]P =\frac{F}{A}\\\\F=PA[/tex]

where,

A = area of one wall = (side length)² = (0.1 m)² = 0.01 m²

Therefore,

[tex]F=(7407.78\ KPa)(0.01\ m^2)\\[/tex]

F = 74.08 KN

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Answer:

Explanation:

reduction yan ba answer mo

Answer:Pb

●Galvanic cell / voltaic cell

●Write the reaction for Q1

Answer:

Explanation:

Ignoring air resistance the spring compression energy will equal the increase in potential energy from the maximum spring compression point to the top of the flight arc.

mgh = ½kx²

    h = kx²/2mg

    h = 180(0.03²) / (2(0.004)(9.8))

    h = 2.06632...

    h = 2.1 m

Answer:

hi there is that OK for the weekend of the following week as well

Explanation:

6th of March is fine for me

The minimum safe radius of curvature for an unprotected pilot flying an F-15 in a horizontal circular loop at 729 km/h is approximately 838.1 meters.

To determine the minimum safe radius of curvature for an unprotected pilot flying an F-15 in a horizontal circular loop, we need to consider the maximum acceleration the pilot can withstand without losing consciousness.

Given:

Maximum acceleration without losing consciousness = 5.00g

Acceleration with g-suits to avoid blackout = 9.00g

First, we need to convert the speed of the F-15 from km/h to m/s:

Speed = 729 km/h = (729 * 1000) m/3600 s ≈ 202.5 m/s

Next, we'll calculate the acceleration experienced by the pilot in the circular loop. In a horizontal circular motion, the centripetal acceleration is given by:

Acceleration = ([tex]\rm Velocity^2[/tex]) / Radius

We can rearrange the equation to solve for the radius:

Radius = ([tex]\rm Velocity^2[/tex]) / Acceleration

Using the maximum acceleration of 5.00g, we convert it to [tex]\rm m/s^2[/tex]:

Maximum acceleration = 5.00g ≈ (5.00 * 9.8) [tex]\rm m/s^2[/tex] = 49 m/s^2

Now, we can calculate the minimum safe radius of curvature:

Radius = ([tex]\rm 202.5^2[/tex]) / 49 ≈ 838.1 meters

Therefore, the minimum safe radius of curvature for an unprotected pilot flying an F-15 in a horizontal circular loop at 729 km/h is approximately 838.1 meters.

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Density of liquid try thank you so much

Answer:

  a) measure the change in volume when the object is immersed; compute from range data

  b) find the ratio of mass to volume for a measured mass and volume

Explanation:

a) The volume of a small enough irregular body can be found by measuring the difference in volume of the (semi-)fluid in which it is immersed, before and after immersion.

For irregular bodies for which that approach does not work, various 3D scanners are available for measuring volume and surface area. They may rely on optical (laser or camera), sonic, or radar measurements, and generally involve computation from distances to various points.

__

b) Density is the ratio of mass to volume. So, measurements of mass and volume of a liquid sample are sufficient to provide the basis for determining density.

Other methods include measuring buoyancy forces, and/or the depth of submersion of something that floats in the liquid. For specific liquids, hydrometers are available for measuring their density relative to that of water.

Answer:

Each gram of carbohydrate and protein yield 4 calories/gram. Each gram of fat yields 9 calories. A calorie is a measurement, just like a teaspoon or an inch. Calories are the amount of energy released when your body breaks down (digests and absorbs) food.

Answer:

ojuppuhp

Explanation:

A fundamental kind of consequentialism holds that whether an action is ethically right or bad depends only on whether its results are inherently preferable to those of any other course of action one could take in the given situation.

A fundamental kind of consequentialism holds that whether an action is ethically right or bad depends only on whether its results are inherently preferable to those of any other course of action one could take in the given situation.

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1.98 kilograms

weight on the moon = (weight on Earth / acceleration of Earth's gravity) x acceleration of the moon's gravity

weight on the moon = (12 kg. / 9.81 m/s^2) x 1.63 m/s^2

weight on the moon = 1.98 kg.

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Answer: The answer is D: 300,000km/s

Explanation:

Answer:

(Question) A child is on a playground they start to slide down a large slide. At what point is the child in dynamic equilibrium with the slide?

(Answer) As the child is in motion as they are sliding down.

(Question) Which statement correctly defines dynamic equilibrium?

(Answer) Forces acting on a object are balanced and the object stays in motion.

(Question) While you push a box you begin to decrease the force you are exerting on the box. When will the box reach static equilibrium?

(Answer) When F^push = F^friction

(Question) What is the fastest motion that can be measured in any frame of reference?

(Answer) 300,000 km/s

(Question) Two people are on a train that is moving at 10 m/s north. They are walking 1 m/s south relative to the train. Relative to the ground, their motion is 9 m/s north;   Why are we able to use these motions to describe the motion relative to the ground?  

(Answer) The people are moving much slower than the speed of light so the ground acts as a frame of reference.

Explanation:

just did the quick check UwU

(a) will have the furthest distance of the two when at an initial height.

Case b will have the maximum horizontal distance based on the data collected.

The range of a projectile is the horizontal distance traveled by the projectile.

The magnitude of a range of projectile is calculated as follows;

R = (u²sin2θ)/g

R = (u²sin (2 x 30))/g

R = (u²sin 60)/g

R = 0.866u²/g

R = (u²sin (2 x 45))/g

R = (u²sin 90)/g

R = u²/g

Thus, maximum horizontal distance of a projectile occurs when the angle of projection is 45 degrees. Case b will have the maximum horizontal distance.

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For a photographer that wishes to determine the color of light that he can use in a dark room that will not expose the films he is processing, having used a Blue Incandescent bulb, he should proceed to use a Red Incandescent bulb for the next trial.

The photographer in question is performing an experiment. For these kinds of experiments it is important to identify the variables present, which can be of three kinds:

For this experiment, the dependent variable is the exposure of the light onto the films, given that this is what we wish to measure. The independent variable will be the color of the light being used which is what will affect the dependent variable.

The remaining variable must be the control variable. Unlike the previous variables, we can have more than one of these. The control variable is there to make sure that only the dependent variable is affecting the outcome. We do this by keeping the control variable the same through each trial, which is why the photographer should not change the type of bulb in the second experiment, changing only the color of the light.

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Answer: type of force is friction

Explanation:

Answer:

When you rub your hands together, the action of scraping the

surface of your skin back and forth against each other causes

the molecules in your skin to move a little faster. The faster

that molecules move, the higher the temperature. So the

friction of rubbing your hands together makes them feel

warmer.

The force is friction. It's a force that opposes motion. It is present whenever two surfaces rub over each other, such as when you rub your hands together, or when you apply the brakes on a bike or in a car.

Explanation: I hope this helped you!

The work required to stretch the spring by a displacement of 5.2 cm = 0.052 m is

1/2 (7.0 N/m) (0.052 m)² ≈ 0.0095 J

which is stored as potential energy in the spring. When the mass is released, as the spring relaxes, this potential energy is gradually converted into more and more kinetic energy.

Let x be the displacement (relative to the equilibrium position, with 0 < x < 0.052 m) at which this energy is split evenly between potential energy P and kinetic energy K, so that

P + K = 2P = 0.0095 J

or

P ≈ 0.0047 J

At this displacement, the spring is storing

P = 1/2 (7.0 N/m) x²

of potential energy. Solve for x :

1/2 (7.0 N/m) x² ≈ 0.0047 J

x² ≈ (0.0047 J) / (1/2 (7.0 N/m))

x ≈ √((0.0047 J) / (1/2 (7.0 N/m)))

x ≈ 0.037 m = 3.7 cm

The big bang is how astronomers explain the way the universe began. It is the idea that the universe began as just a single point, then expanded and stretched to grow as large as it is right now—and it is still stretching!

What's This Big Bang All About?

In 1927, an astronomer named Georges Lemaître had a big idea. He said that a very long time ago, the universe started as just a single point. He said the universe stretched and expanded to get as big as it is now, and that it could keep on stretching.

What an Idea!

The universe is a very big place, and it’s been around for a very long time. Thinking about how it all started is hard to imagine.

Some More Information

Just two years later, an astronomer named Edwin Hubble noticed that other galaxies were moving away from us. And that’s not all. The farthest galaxies were moving faster than the ones close to us.

This meant that the universe was still expanding, just like Lemaître thought. If things were moving apart, it meant that long ago, everything had been close together.

Everything we can see in our universe today—stars, planets, comets, asteroids—they weren't there at the beginning. Where did they come from?

A Tiny, Hot Beginning

When the universe began, it was just hot, tiny particles mixed with light and energy. It was nothing like what we see now. As everything expanded and took up more space, it cooled down.

The tiny particles grouped together. They formed atoms. Then those atoms grouped together. Over lots of time, atoms came together to form stars and galaxies.

The first stars created bigger atoms and groups of atoms. That led to more stars being born. At the same time, galaxies were crashing and grouping together. As new stars were being born and dying, then things like asteroids, comets, planets, and black holes formed!

Answer:

917 N

Explanation:

I hope this helps!!

A. The initial mass of oxygen in the tank is 480.96 g

B. The mass of oxygen that leaked out is 384.96 g

A. Determination of the initial mass of oxygen in the tank.

Volume (V) = 0.1 m³

Pressure (P) = 4×10⁵ Pa

Temperature (T) = 47 °C = 47 + 273 = 320 K

Gas constant (R) = 8.314 Pa.m³/Kmol

PV = nRT

0.1 × 4×10⁵ = n × 8.314 × 320

40000 = n × 2660.48

Divide both side by 2660.48

n = 40000 / 2660.48

mole = 15.03 moles

molar mass of oxygen gas = 32 g/mol

Mass = mole × molar mass

Mass of oxygen gas = 15.03 × 32

Therefore, the initial mass of oxygen in the tank is 480.96 g

B. Determination of the mass of oxygen that leaked out of the tank.

Volume (V) = 0.1 m³

Pressure (P) = 3×10⁵ Pa

Temperature (T) = 27 °C = 27 + 273 = 300 K

Gas constant (R) = 8.314 Pa.m³/Kmol

PV = nRT

0.1 × 3×10⁵ = n × 8.314 × 300

30000 = n × 2494.2

Divide both side by 2494.2

n = 30000 / 2660.48

mole = 12.03 moles

molar mass of oxygen gas = 32 g/mol

Mass = mole × molar mass

Mass of oxygen gas = 12.03 × 32

Therefore, the mass of oxygen that leaked out of tank is 384.96 g

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Answer:

yes

Explanation:

because is pure ohmic risistance

Answer:

I actually don't understand what you are asking for....but if you denote second then...

Explanation:

Just divide 120/6=20

Hence, it's traveling 20m per second.

Answer:

20 m/s

Explanation:

Speed = Distance/Time

Speed = 120m/6s

Speed = 20 m/s

Answer:

116.66N

Explanation:

work done = force x distance

1400 = force x 12

1400 / 12 = force

116.66N = force

F = W / d

 =1400 / 12

 = 116.6 N

Work = Force × Distance. The SI unit for work is the joule (J), or Newton • metre (N • m). One joule equals the amount of work that is done when 1 N of force moves an object over a distance of 1 m.

"Distance is defined to be the magnitude or size of displacement between two positions. Note that the distance between two positions is not the same as the distance travelled between them. Distance travelled is the total length of the path travelled between two positions. Distance travelled is not a vector."

"The push or pull on an object with mass that causes it to change its velocity. Force is an external agent capable of changing the state of rest or motion of a particular body. It has a magnitude and a direction."

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