Answer: [tex]55,811.91[/tex]
Step-by-step explanation:
Given
Principal amount is 25,000
Time Period is [tex]t=15\ yr[/tex]
Rate of interest [tex]r=5.5\%[/tex]
Amount in compound interest is given by
[tex]\Rightarrow A=P\left(1+r\%\right)^t[/tex]
Insert the values
[tex]\Rightarrow A=25,000(1+\dfrac{5.5}{100})^{15}\\\\\Rightarrow A=25,000(1.055)^{15}\\\Rightarrow A=55,811.91[/tex]
Therefore, [tex]55,811.91[/tex] must be paid back
Write a compound interest function to model the following situation. Then, find the balance after the
given number of years.
$13,700 invested at a rate of 2% compounded quarterly; 6 years
Answer:
The balance after the 6 years of investment will be $ 15,442.08.
Step-by-step explanation:
Given that $ 13,700 was invested at a rate of 2% compounded quarterly during 6 years, to determine the final result of the investment, the following calculation must be performed:
13,700 x (1 + 0.02 / 4) ^ 4x6 = X
13,700 x (1 + 0.005) ^ 24 = X
13,700 x 1,005 ^ 24 = X
13,700 x 1.1271 = X
15,442.08 = X
Therefore, the balance after the 6 years of investment will be $ 15,442.08.
does the point (-4, 2) lie inside or outside or on the circle x^2 + y^2 = 25?
Given equation of the Circle is ,
[tex]\sf\implies x^2 + y^2 = 25 [/tex]
And we need to tell that whether the point (-4,2) lies inside or outside the circle. On converting the equation into Standard form and determinimg the centre of the circle as ,
[tex]\sf\implies (x-0)^2 +( y-0)^2 = 5 ^2[/tex]
Here we can say that ,
• Radius = 5 units
• Centre = (0,0)
Finding distance between the two points :-
[tex]\sf\implies Distance = \sqrt{ (0+4)^2+(2-0)^2} \\\\\sf\implies Distance = \sqrt{ 16 + 4 } \\\\\sf\implies Distance =\sqrt{20}\\\\\sf\implies\red{ Distance = 4.47 }[/tex]
Here we can see that the distance of point from centre is less than the radius.
Hence the point lies within the circle .
Someone help, I suck at math
option A.55°
Answer:
Solution given:
<x+<y=<z
exterior angle of a triangle is equal to the sum of two opposite interior angle
4n-18+n+8=133-6n
5n+6n=133+10
11n=143
n=143/11
n=13
exterior angle =133-6*13=55°
option A.55°
Solve the equation
1/x + 1/3x = 4
Answer:
x = [tex]\frac{1}{3}[/tex]
Step-by-step explanation:
[tex]\frac{1}{x} + \frac{1}{3x} = 4[/tex] (Multiply everything by LCM)
[tex]3x*\frac{1}{x} + 3x*\frac{1}{3x}=3x*4[/tex] (Simplify the fractions)
[tex]3+1=12x\\4=12x\\x=4/12\\x=\frac{1}{3}[/tex]
(PLS HELP NOW WILL GIVE BRINIEST!!!!!) A figure is formed by two pairs of parallel sides that are the same length. Which type of figure is it?
A.
hexagon
B.
square
C.
pentagon
D.
triangle
Answer: B. Square
Step-by-step explanation:
All sides of a square have the same lengthAll four angles of a square = 90°A square has two parallel sidesThe answer is B.), because if you have two pairs of parallel sides that means it looks like a square 1. || 2. _
_
- Chilio
if the measure of angle def is 65° what is the measure of arc de?
EF is tangent to the circle we'll assume; otherwise there's no progress.
Call the center C. ECD is isosceles, formed from two radii and the chord.
Angle CED is complementary to DEF
CED = 90 - 65 = 25 degrees
CDE is congruent, isosceles triangle and all that: CDE=25
That leaves DCE=180-25-25=130 degrees
That's the measure of arc DE as well:
Answer: 130 degrees, choice A
Answer:
130
Step-by-step explanation:
instructions: state what additional information is required in order to know that the triangle in the image below are congruent for the reason given
***I need help before it’s due**
SSS (side-side-side) requires that all three sides of the potentially congruent triangles be congruent.
Triangle WVU & Triangle UBW are our two triangles.
The middle line, UW and WU are congruent by the reflexive property, so that is not the information we need to prove SSS.
For SSS, we need to know that sides WV and UB are congruent.
Hope this helps!
Can someone help me with this math homework please!
Answer:
4
Step-by-step explanation:
7h-15h+40=-72
-8h=-32
h=4
What is the slope of the graph?
help pls and explain!!!
If x^2 + kx + 6 = (x+n)(x + 3) for all values of x, where k and n are constants, what is the value of k?
A) 5
B) 3
C) 2
D) 1
Answer:
A) 5
Step-by-step explanation:
We are given that:
[tex]x^2+kx+6=(x+n)(x+3)[/tex]
Where k and n are constants.
And we want to find the value of k.
We can expand the right-hand side:
[tex]\displaystyle =x(x+n)+3(x+n)\\ \\ = x^2+nx+3x+3n \\ \\ = x^2 + (n+3)x+3n[/tex]
Hence:
[tex]x^2+kx+6=x^2+(n+3)x+3n[/tex]
The coefficients of each term must be equivalent. In other words:
[tex]k=n+3\text{ and } 6=3n[/tex]
Solve for n:
[tex]n=2[/tex]
Now, we can solve for k:
[tex]k=(2)+3=5[/tex]
Our answer is A.
Maths Assignment
4-a^2
Answer:
(2-a)^2
(2+a) (2-a)...
Answer:
Step-by-step explanation:
Use the identity: a² - b² = (a+ b)(a - b)
4 - a² = 2² - a² {Here a = 2 and b = a}
= (2 +a) (2 - a)
Integration. Please help ASAP
Answer:
I hope this helps
Step-by-step explanation:
Look at pic for question and answer choices.
Question 4 of 10 What is the equation of the following line? Be sure to scroll down first to see all answer options. (6,2) O A y= 22 B. y=-3x O c. y=6x O D. y = 1 x O E y=3x O F. y = 1 x
The equation of the line will be y = 1/3x. The correct option is F.
What is an equation of the line?An equation of the line is defined as a linear equation having a degree of one. The equation of the line contains two variables x and y. And the third parameter is the slope of the line which represents the elevation of the line.
The general form of the equation of the line:-
y = mx + c
m = slope
c = y-intercept
The slope of the line is calculated as,
[tex]m = \dfrac{y_2-y_1}{x_2-x_1}[/tex]
The two points are (6,2) and (0,0). Calculate the slope of the line,
[tex]m = \dfrac{0 - 2}{0-6}[/tex]
m = 1 / 3
The equation of the line can be written as,
y = mx +c
y = 1/3x + 0
y = 1/3x
To know more about an equation of the line follow
https://brainly.com/question/18831322
#SPJ7
Help me out plz bbbhbbhh
the solution is in the picture ☝️
ANSWER: 240 hours
this is for n.12
Jorge compro en la papeleria 3 Borradores y 2 lápices, por ellos pago $47.50. si la suma de lo que cuesta un borrador y un lápizes $20 ¿cuanto vale cada borrador y cada lápiz?
Por favor es urgente
Answer:
Cost of each pencil = $12.5
Cost of each eraser = $7.5
Step-by-step explanation:
Given:
Number of eraser bought = 3
Number of pencil bought = 2
Total amount paid = $47.50
Cost of one pencil and one eraser = $20
Find:
Each cost
Computation:
Let;
Cost of each eraser = e
Cost of each pencil = p
So,
e + p = 20
e = 20 - p .................................... eq1
3e + 2p = 47.50
3(20 - p) + 2p = 47.50
60 - 3p + 2p = 47.50
-p = -12.5
Cost of each pencil = $12.5
e = 20 - p
e = 20 - 12.5
e = 7.5
Cost of each eraser = $7.5
Help please I don’t understand
Answer:
you need to solve for 'X'
mean 49 = 55 + 42 + 32 +48 + 55 + X
49 = (232+X) / 6
49 * 6 = 232 + X
294 = 232 + X
294 - 232 = X
62 = X
so therefore X is 62
Step-by-step explanation:
please give me a brainliest
Please help me with this, no clue.
The sum of the measures of two of the angles formed by the intersection of two lines is 114 degrees. Find the measures of all angles. (There are 4 boxes to fill out for the answer)
Answer:
57°,123°,57°,123°
Step-by-step explanation:
as vertical angles are equal
so one angle=114/2=57°
other angle=180-57=123°
Answer:
pic pls
Step-by-step explanation:
An acute angles measure is
A. Between 0 and 90
B. Between 90 and 180
C. Exactly 90
Answer: the correct answer is A. Between 0 and 90
If an angle is between 0 and 90 it is acute
If an angle is EXACTLY 90 it is a right angle
If an angle is between 90 and 180 it is obtuse angle
If it's 360 then it is a full circle
(3/2)^(-2).......................................................................
Answer:
4/9
Step-by-step explanation:
First of all we need to get rid of the -2 exponent and make it positive in order to solve this equation.
Therefore to do this we just use the reciprocal of 3/2 which is 2/3
Now we have (2/3)^2
Since 2/3 is being squared we used the following equation below:
(2/3) * (2/3)
We multiply 2/3 by itself twice since 2 is the exponent.
Then we get:
2^2
-----
3^2
2 squared is 4 and 3 squared is 9.
Therefore the final answer is 4/9.
I hope this helps have a good rest of your day!
Answer:
4/9
Step-by-step explanation:
(3/2)^(-2)
(3/2)^2=(3/2)(3/2)=9/4
However, ^(-2) means 1/(9/4), which gives you 4/9.
Solve the following linear quadratic system of equations algebraically.
y=^2+3x-2
y+3=5x
Answer:
[tex]x=1[/tex]
[tex]y=2[/tex]
Step-by-step explanation:
[tex]y=x^2+3x-2[/tex] , [tex]y+3=5x[/tex]
Replace all occurrences of [tex]y[/tex] in [tex]y+3=5x[/tex] with [tex]x^2+3x-2.[/tex]
[tex](x^2+3x-2)+3=5x[/tex]
[tex]y=x^2+3x-2[/tex]
Add [tex]-2[/tex] and 3.
[tex]x^2+3x+1=5x[/tex]
[tex]y=x^2+3x-2[/tex]
Subtract 5x from both sides of the equation.
[tex]x^2+3x+1-5x=0[/tex]
[tex]y=x^2+3x-2[/tex]
Subtract 5x from 3x.
[tex]x^2-2x+1=0[/tex]
[tex]y=x^2+3x-2[/tex]
Rewrite 1 as [tex]1^2[/tex].
[tex]x^2-2x+1^2=0[/tex]
[tex]y=x^2+3x-2[/tex]
Check that the middle term is two times the product of the numbers being squared in the first term and third term.
[tex]2x=2[/tex] · [tex]x[/tex] · [tex]1[/tex]
[tex]y=x^2+3x-2[/tex]
Rewrite the polynomial.
[tex]x^2-2[/tex] · [tex]x[/tex] · [tex]1[/tex] [tex]+[/tex] [tex]1^2=0[/tex]
[tex]y=x^2+3x-2[/tex]
Factor using the perfect square
trinomial rule [tex]a^2-2ab+b^2=(a-b)^2,[/tex]
where a = x and b = 1.
[tex](x-1)^2=0[/tex]
[tex]y=x^2+3x-2[/tex]
Set the [tex]x-1[/tex] equal to 0.
[tex]x-1=0[/tex]
[tex]y=x^2+3x-2[/tex]
Add 1 to both sides of the equation.
[tex]x=1[/tex]
[tex]y=x^2+3x-2[/tex]
Replace all occurrences of [tex]x[/tex] in
[tex]y=x^2+3x-2[/tex] with 1.
[tex]y=(1)^2+3(1)-2[/tex]
[tex]x=1[/tex]
[tex]y=2[/tex]
Y varies directly as x and k = 5
Y=kx
Find y when x = 5
Answer:
y = 25
Step-by-step explanation:
Given y = kx and k = 5 then
y = 5x ← equation of variation
When x = 5 , then
y = 5 × 5 = 25
simplify (-81)÷9 pls ans
Answer:
[tex] \frac{ - 81}{9} [/tex]
[tex] - 9[/tex]
(100 points)
4. MIke divided the group into 5 groups. If there were 28 people in each group how big was the original group?
a. What are they asking for? __________________
b. identify all the necessary numbers. __________________
c. write the equation or problem in numeric form. ______________
d. solve the math. ______________________________
e.write the answer. ______________________________
5. If he difference is 589 and the subtrahend is 339,what is the minuend?
a. What are they asking for? __________________
b. identify all the necessary numbers. __________________
c. write the equation or problem in numeric form. ______________
d. solve the math. ______________________________
e.write the answer. ______________________________
6. If the quotient is 17 and the dividend 765, what is the divisor?
a. What are they asking for? __________________
b. identify all the necessary numbers. __________________
c. write the equation or problem in numeric form. ______________
d. solve the math. ______________________________
e.write the answer. ______________________________
4. MIke divided the group into 5 groups. If there were 28 people in each group how big was the original group?
a. What are they asking for?
how big was the original group?
b. identify all the necessary numbers.
28,5
c. write the equation or problem in numeric form.
x=28*5
d. solve the math.
x=140
e.write the answer
. the original group contains 140 people.
5. If he difference is 589 and the subtrahend is 339,what is the minuend?
a. What are they asking for?
what is the minuend?
b. identify all the necessary numbers.
589,339
c. write the equation or problem in numeric form.
x=589-339
d. solve the math.
x=250
e.write the answer.
minuend=250
6. If the quotient is 17 and the dividend 765, what is the divisor?
a. What are they asking for?
what is the divisor?
b. identify all the necessary numbers.
17,765
c. write the equation or problem in numeric form.
x=765/17
d. solve the math.
x=45
e.write the answer.
divisor is 45.
4. Solution
a. How big was the original group?
b. 28 and 5
c. x = 28×5
d. x = 140
e. There are 140 people in original group.
5. Solution
a. What is the minuend?
b. 589 and 339
c. x = 589-339
d. x = 250
e. The minuend is 250.
6. Solution
a. What is the divisor?
b. 17 and 765
c. x = 765/17
d. x = 45
e. Hence, 45 is the divisor.
Find the area of the triangle from the coordinate plane.
Y
A
10-
5-1
с
B.
0
-20
-15
-10
-5
Answer:
Find the area of the triangle from the coordinate plane.
Y
A
10-
5-1
с
B.
0
-20
-15
-10
-5Step-by-step explanation:
asap answer pls -------------------
Answer:
f(2) = - 5
Step-by-step explanation:
Using the recursive rule and f(1) = - 3 , then
f(2) = 2f(1) + 1 = 2 × - 3 + 1 = - 6 + 1 = - 5
A fire extinguisher releases 27/4  liters of carbon dioxide in 9/16 minutes what is the speed in terms of liters per minute
Answer:
12 liters per min
Step-by-step explanation:
Math
27/4 = x
9/16 1
27/4=(9/16)x
Divide both sides by 9/16
12=x
Solve using suitable properties. Also mention the names of the property used. -3/4 × 4/5 - 1/2 × 1/4 +4/5 × 7/5
Answer:
0.395
Step-by-step explanation:
We need to solve the given expression.
[tex]-\dfrac{3}{4}\times \dfrac{4}{5}-\dfrac{1}{2}\times\dfrac{1}{4}+\dfrac{4}{5}\times \dfrac{7}{5}[/tex]
We can also write it as :
[tex]-\dfrac{3}{4}\times \dfrac{4}{5}+\dfrac{4}{5}\times \dfrac{7}{5}-\dfrac{1}{2}\times\dfrac{1}{4}\\\\=\dfrac{4}{5}(\dfrac{-3}{4}+\dfrac{7}{5})-\dfrac{1}{2}\times\dfrac{1}{4}[/tex](Distributive property is used)
So,
[tex]=\dfrac{4}{5}\times \dfrac{13}{20}-\dfrac{1}{2}\times\dfrac{1}{4}\\\\=\dfrac{4}{5}\times \dfrac{13}{20}-\dfrac{1}{8}\\\\=\dfrac{13}{25}-\dfrac{1}{8}\\\\=0.395[/tex]
So, the value of the given expression is equal to 0.395.
X2+y2-6x+2y-39=0 what is the radius and the center
Answer:
(centre = (3, - 1 ) and radius = 7
Step-by-step explanation:
The equation of a circle in standard form is
(x - h)² + (y - k)² = r²
where (h, k) are the coordinates of the centre and r is the radius
Given
x² + y² - 6x + 2y - 39 = 0 ( collect x/ y terms and add 39 to both sides )
x² - 6x + y² + 2y = 39
Using the method of completing the square
add ( half the coefficient of the x/ y terms )² to both sides
x² + 2(- 3)x + 9 + y² + 2(1)y + 1 = 39 + 9 + 1
(x - 3)² + (y + 1)² = 49 ← in standard form
with centre (3, - 1 ) and r = [tex]\sqrt{49}[/tex] = 7