An ambulance is currently traveling at 15m/s, and is accelerating with a constant acceleration of 5 m/s^2. The ambulance is attempting to pass a car that is moving at a constant velocity of 30m/s. How far must the ambulance travel until it matches the car’s velocity?

Answers

Answer 1
initial velocity=15m/s=uAcceleration=a=5m/s^2Final velocity=v=30m/sDistance be s

Using 3rd equation of kinematics

[tex]\\ \rm\longmapsto v^2-u^2=2as[/tex]

[tex]\\ \rm\longmapsto s=\dfrac{v^2-u^2}{2a}[/tex]

[tex]\\ \rm\longmapsto s=\dfrac{30^2-15^2}{2(5)}[/tex]

[tex]\\ \rm\longmapsto s=\dfrac{900-225}{10}[/tex]

[tex]\\ \rm\longmapsto s=\dfrac{675}{10}[/tex]

[tex]\\ \rm\longmapsto s=67.5m[/tex]


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