algebra 2 help pls answer

We have that

x - 3y = 12 and -x + y = 4

We add the 2 equations together

x - 3y + (-x + y) = 16

-> -2y = 16

-> y = -8 (1)

We plug y = -8 into -x + y =4

-> -x - 8 = 4

-> -x = 12

-> x = - 12 (2)

From (1) and (2) we could conclude that the answer is B

Answer:

f(-5) = 7

Step-by-step explanation:

f(-5) means find the y value when x = -5

y = 7 when x = -5

Answer:

d

Step-by-step explanation:

Answer:

10

Step-by-step explanation:

the small engine tanks that Harvey have = 5 ÷ ½ = 10

Answer:

64

Step-by-step explanation:

2x2x2x2x2x2 = 64

Answer:

let

diagonal 1=6cm

diagonal 2=10cm

Area of rhombus=½*diagonal 1*diagonal 2=½*6*10

=30cm²

Answer:

Area of rhombus is 30cm².

Step-by-step explanation:

A rhombus having diagonals 6cm and 10cm . Find the area of rhombus.

Solution :-

Let us assume that

Finding the area of rhombus

Using Formula :-

Area of rhombus = ½ × [tex]diagonal_1[/tex]×[tex]diagonal_2[/tex]

Substitute the values of both diagonals.

Area of rhombus = ½ × 6cm × 10cm

Multiply the numbers

Area of rhombus = ½ × 60cm²

Divide we get ,

Area of rhombus = 30 cm

Answer two 20p coins make 40p

Step-by-step explanation:

Answer:

20 number of 20p makes £4.

Step-by-step explanation:

Let the number of 20p be x

Therefore,

                [tex]x \times 0.20 = 4\\\\x = \frac{4}{0.20} = \frac{4 \times 100}{ 20} = 4 \times 5 = 20[/tex]

Answer:

A = 127.48 rounded

Step-by-step explanation:

Area of a circle:  

A = [tex]\pi r^{2}[/tex]

A = [tex]\pi[/tex][tex](6.37)^{2}[/tex]

A = 127.48 rounded

Answer:

It's 127.47

First we take the radius and square it

6.37^2

then we multiply it by pi

40.5769 x π = 127.47

Answer:

[tex]q < 33[/tex]

Step-by-step explanation:

[tex]q < 11 \times 3[/tex]

[tex]q < 33[/tex]

Answer:

33

Step-by-step explanation:

q/3<11

q=11×3

q=33

:. The answer is 33.

Answer:

Step-by-step explanation:

x - y = 30

Substitute 15 for y.

x - (15) = 30

Add 15 to both sides.

x = 45

Answer:

1134

Step-by-step explanation:

We have 3 digits:

a, b, c

a 3 digit number can be written as:

a*100 + b*10 + c*1

Such that these numbers can be:

{1, 2, 3, 4, 5, 6, 7, 8, 9}

Let's assume that:

a < b < c

Then the 3 smaller numbers are:

a*100 + b*10 + c

a*100 + c*10 + b

b*100 + a*10 + c

The 3 larger numbers are:

b*100 + c*10 + a

c*100 + a*10 + b

c*100 + b*10 + a

We know that the sum of the 3 smaller numbers is equal to 540, then:

(a*100 + b*10 + c) + (a*100 + c*10 + b) + (b*100 + a*10 + c) = 540

Let's simplify this:

(a + a + b)*100 + (b + c + a)*10 + (c + b + c) = 540

(2a + b)*100 + (b + c + a)*10 + (2c + b) = 540

The sum of the 3 larger numbers is equal to X, we want to find the value of X:

(b*100 + c*10 + a) + (c*100 + a*10 + b) + (c*100 + b*10 + a) = X

Now let's simplify the left side:

(b + c + c)*100 + (c + a + b)*10 + (a + b + a)*1 = X

(b + 2*c)*100 + (c + a + b)*10 + (2a + b) = X

Then we have two equations:

(2a + b)*100 + (b + c + a)*10 + (2c + b) = 540

(b + 2*c)*100 + (c + a + b)*10 + (2a + b) = X

Notice that the terms are inverted.

By looking at the first equation, we can see that:

(2c + b) = 10    (because the units digit of 540 is 0)

Then, we can see that:

(b + c + a + 1 ) = 14   (the one comes from the previous 10)

finally:

(2a + b + 1) = 5   (the one comes from the previous 14)

Then we can rewrite:

(2*c + b) = 10

(b + c + a) = 14 -1  = 13

(2a + b) = 5 - 1 = 4

Now we can replace these 3 in the equation:

(b + 2*c)*100 + (c + a + b)*10 + (2a + b) = X

(10)*100 + (13)*10 + 4 = X

1000 + 130 + 4 = X

1134 = X

The sum of the 3 largest numbers is 1134.

Answer:

See Explanation

Step-by-step explanation:

Given

[tex]0 \to[/tex] Correct

[tex]1 \to[/tex] Defective

Required

The probability that the next is defective

The question is incomplete because the list of bottles that came out is not given.

However, the formula to use is:

[tex]Pr = Num ber\ o f\ d e f e c t i v e \div T o t a l\ b o t t l e s[/tex]

Take for instance, the following outcomes:

[tex]0\ 1\ 0\ 0\ 0\ 1\ 0\ 0\ 1\ 1\ 0\ 0\ 0\ 1[/tex]

We have:

[tex]Total = 14[/tex]

[tex]D e f e ctive = 9[/tex] --- i.e. the number of 0's

So, the probability is:

[tex]Pr = 9 \div 14[/tex]

[tex]Pr = 0.643[/tex]

Answer:

1/20

Step-by-step explanation:

000000000000100000

It is asking the probability of a defective bottle

there is one defective bottle out of 20

Answer:

so both tables are proportional

1. in the green table

y divided by x =

1/5 for each row

2. in the blue table

y divided by x =

2/5 for each row

Step-by-step explanation:

/ means divided by

divide y by x

for both tables

in each table

if y divided by x

show the same number

for every row

then its proportional

1. in the green table

y divided by x =

1/5 for each row

2. in the blue table

y divided by x =

2/5 for each row

so both tables are proportional

Answer:

-4

Step-by-step explanation:

bc it is

.......................

Answer:

b + 24

Step-by-step explanation:

b and 24 would be b + 24

Answer:

[tex]\displaystyle x=-\frac{2}{3}[/tex]

Step-by-step explanation:

We want to solve the equation:

[tex]\displaystyle \sqrt{x^2-4x+8}+x=2-x[/tex]

We can isolate the square root. Subtract x from both sides:

[tex]\sqrt{x^2-4x+8}=2-2x[/tex]

And square both sides:

[tex](\sqrt{x^2-4x+8})^2=(2-2x)^2[/tex]

Expand:

[tex]x^2-4x+8=4-8x+4x^2[/tex]

Isolate the equation:

[tex]3x^2-4x-4=0[/tex]

Factor:

[tex]\displaystyle (3x+2)(x-2)=0[/tex]

Zero Product Property:

[tex]3x+2=0\text{ or } x-2=0[/tex]

Solve for each case. Hence:

[tex]\displaystyle x=-\frac{2}{3}\text{ or } x=2[/tex]

Now, we need to check for extraneous solutions. To do so, we can substitute each value back into the original equation and check whether or not the resulting statement is true.

Testing x = -2/3:

[tex]\displaystyle \begin{aligned} \sqrt{\left(-\frac{2}{3}\right)^2-4\left(-\frac{2}{3}\right)+8}+\left(-\frac{2}{3}\right)&\stackrel{?}{=}2-\left(-\frac{2}{3}\right)\\ \\ \sqrt{\frac{4}{9}+\frac{8}{3}+8}-\frac{2}{3}&\stackrel{?}{=}2+\frac{2}{3} \\ \\ \sqrt{\frac{100}{9}}-\frac{2}{3}& \stackrel{?}{=} \frac{8}{3}\\ \\ \frac{10}{3}-\frac{2}{3} =\frac{8}{3}& \stackrel{\checkmark}{=}\frac{8}{3}\end{aligned}[/tex]

Since the resulting statement is true, x = -2/3 is indeed a solution.

Testing x = 2:

[tex]\displaystyle \begin{aligned}\sqrt{(2)^2-4(2)+8}+(2) &\stackrel{?}{=}2-(2) \\ \\ \sqrt{4-8+8}+2&\stackrel{?}{=}0 \\ \\ \sqrt{4}+2&\stackrel{?}{=}0 \\ \\ 2+2=4&\neq 0\end{aligned}[/tex]

Since the resulting statement is not true, x = 2 is not a solution.

Therefore, our only solution to the equation is x = -2/3.  

Step-by-step explanation:

Hey there!

Given;

[tex] \sqrt{ {x}^{2} - 4x + 8} + x = 2 - x[/tex]

Take "X" in right side.

[tex] \sqrt{ {x - 4 + 8}^{2} } = 2 - 2x[/tex]

Squaring on both sides;

[tex] {( \sqrt{ {x}^{2} - 4x + 8 } )}^{2} = {(2 - 2x)}^{2} [/tex]

Simplify;

[tex] {x}^{2} - 4x + 8 = {(2)}^{2} - 2.2.2x + {(2x)}^{2} [/tex]

[tex] {x }^{2} - 4x + 8 = 4 - 8x + 4 {x}^{2} [/tex]

[tex]3 {x}^{2} - 4x - 4 = 0[/tex]

[tex]3 {x}^{2} - (6 - 2)x - 4 = 0[/tex]

[tex] 3 {x}^{2} - 6x + 2x - 4 = 0[/tex]

[tex]3x(x - 2) + 2(x - 2) = 0[/tex]

[tex](3x + 2)(x - 2) = 0[/tex]

Either;

3x+2 = 0

x= -2/3

Or;

x-2 = 0

x= 2

Check:

Keeping X= -2/3,

√(x²-4x+8 ) +X = 2-x

√{(-2/3)²-4*-2/3+8}+(-2/3) = 2+2/3

8/3 = 8/3 (True)

Now; Keeping X= 2

√{(2)²-4*2+8}+2 = 2-2

8 ≠0 (False)

Therefore, the value of X is -2/3.

Hope it helps!

Answer:

[tex]n=\frac{S}{180}+2[/tex]

Step-by-step explanation:

Hi there!

[tex]S=(n-2)180[/tex]

We can isolate n by performing inverse operations on both sides to cancel out values.

First, divide both sides by 180 to isolate n-2:

[tex]\frac{S}{180}=n-2[/tex]

Now, add 2 to both sides to isolate n:

[tex]\frac{S}{180}+2=n\\n=\frac{S}{180}+2[/tex]

I hope this helps!

Answer:

6 yds

Step-by-step explanation:

If we label the shorter side as x, the longer side can be represented as 2x + 2. Now, we can write an equation to model the situation. The area of a rectangle is the sides multiplied by each other:

84 = x(2x + 2)

84 = 2x^2 + 2x

Since all terms are divisible by two, we can divide both sides by it:

42 = x^2 + x

We can write the quadratic equation in standard form:

x^2 + x - 42 = 0

Now, we can factor. We are looking for numbers that multiply to -42 and add to 1. These numbers are 7 and -6. Factored the equation would be written as followed:

(x + 7)(x - 6) = 0

Using the zero-product property, we can obtain two equations and solve them:

x + 7 = 0

x  = -7

x - 6 = 0

x = 6

Since the side of a rectangle can't be negative, the answer must be 6 yds.

Answer:

7/50 = x/75

x = 10.5

therefore he would run 10.5 miles in 75 minutes

Answer:

In 75 minutes, she runs (7/50) x 75 = 10.5.

She runs 10.5 miles in 75 minutes.

Step-by-step explanation:

Answer:

(y-1)

Step-by-step explanation:

simplified you split y^2-1y+-4y+4 this is further simplified by splitting equation into y(y-1)   -4(y-1) this leaves you with (y-4)(y-1)/(y-4) y-4 will cancel out and you are left with y-1

Answer:

[tex]{ \tt{h(t) = - 10t + 6}} \\ - 44 = - 10t + 6 \\ - 10t = - 50 \\ t = 5[/tex]

Answer:

h(5)

Step-by-step explanation:

Equate - 10t + 6 and - 44 and solve for t

- 10t + 6 = - 44 ( subtract 6 from both sides )

- 10t = - 50 ( divide both sides by - 10 )

t = 5 , that is

h(5) = - 44

Answer:

9 < x

6 - f

t × 6

1/2n

Step-by-step explanation:

Given expressions:

9 less than x

Less than (<)

9 less than x = 9 < x

6 minus f

Minus (-)

= 6 - f

t multiplied by 6

Multiplication (×)

= t × 6

one half of a number n

One half = 1/2

one half of a number n

= 1/2 × n

= 1/2n

= n/2

The closer to 1 the r value the closer the dots make a straighter line.

A positive value the distance move up to the right, a negative value the dots move down to the right.

A = r = -0.33

B = r = -0.75

C = r = 0.72

D = r = 0.89

Answer:

1/9

You are being asked to "complete the square"

you need to find a value to make the quadratic a "perfect square:

the focus is -2/3 you need to "add" one half of -2/3 squared to the

equation (1/2 * -2/3)^2 .... (-2/6)^2 .... 4/36 .... 1/9

Step-by-step explanation:

Answer:

Step-by-step explanation:

[tex]sin^2 \ x + sin ^2 \ x + 2cos^ 2\ x = 2\\\\2sin^2 \ x + 2 cos^2 \ x = 2\\\\2 ( sin^2 \ x + cos^2 \ x ) = 2 \\\\2 \times 1 = 2 \\\\2 = 2 \\\\LHS = RHS \\\\Hence \ proved.[/tex]

Solution given:

it is a right angled isosceles triangle

so

perpendicular [p]=base[b]=5

hypotenuse [h]=x

we have

by using Pythagoras law

p²+b²=h²

5²+5²=h²

50=h²

h=[tex]\sqrt{50}[/tex]

x=[tex]\bold{5\sqrt{2}}[/tex]

Answers:  x = 1 and y = -1

Explanation:

Start where your teacher left off, which is -3y = 3.

We solve for y by dividing both sides by -3

That turns -3y = 3 into y = -1

Then we use this y value to find x

x - 5y = 6

x - 5(-1) = 6

x + 5 = 6

x = 6-5

x = 1

The solution is (x,y) = (1, -1)

Answer:

-1,1

Step-by-step explanation:

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