We have that
The wombats total displacement is
[tex]d_t=2100m[/tex]
The average velocity during that time is
[tex]v_{avg}=5m/s[/tex]
From the question we are told that:
initial Velocity [tex]V_1=5m/s[/tex]
initial Time [tex]T_1=4min=>240sec[/tex]
Final Velocity [tex]V_2=4m/s[/tex]
Final time [tex]T_2=3min=>180sec[/tex]
a)
Generally, the equation for displacement is mathematically given by
d_t=(Initial +final) displacement
Where
initial displacement
[tex]d_1=V_1*t_1\\\\d_1=5*240[/tex]
[tex]d_1=1200m[/tex]
Final displacement
[tex]d_2=V_2*t_2\\\\d_2=5*180[/tex]
[tex]d_2=900m[/tex]
Therefore
[tex]d_t=(Initial +final) displacement[/tex]
[tex]d_t=1200+900[/tex]
[tex]d_t=2100m[/tex]
b)
Generally, the equation for Average velocity is mathematically given by
[tex]v_{avg}=\frac{d_t}{t_1+t_2}[/tex]
[tex]v_{avg}=\frac{2100m}{240+180}[/tex]
[tex]v_{avg}=5m/s[/tex]
in conclusion
The wombats total displacement is
[tex]d_t=2100m[/tex]
The average velocity during that time is
[tex]v_{avg}=5m/s[/tex]
For more information on this visit
https://brainly.com/question/11934397
The elevators in the John Hancock building in Chicago move 783 ft in 33 s. What is this speed in miles per hour?
Answer:
16.18 mph
Explanation:
the speed of elevators =
(783×3600)/(33×5280) =
2,818,800/174,240 = 16.18 mph
Round 0.010229 to four sig figs
It would be 0.01023.
0.010229 has 5 sig. fig.'s (leading zeros do not count)
So rounding to 4 sig. fig.'s is just a matter of rounding off the last digit, which leaves you with 0.01023.
Slove these problem physics
Answer:
element name = neon
no of proton = 10
no. if neutron = 9
atomic no. = 10
atomic weight = 20.17179u
it lies in group 18 and period 2
it is nonmetal because it is a noble gas .
hope this helped you ☺️
