Answer:
300 JoulesExplanation:
This is a common question on Khan Academy's "Calculating change in kinetic energy from a force" practice exercises. (AP Physics 1)
The simplest method to use is the following: [tex]W = F * d * cos(theta)[/tex], where W represents work (joules), F represents force (newtons), d represents distance (meters), and theta represents the angle of the force that's being applied.In this scenario, the force being applied is horizontal, so we can remove the [tex]cos(theta)[/tex] from our equation.So, our equation is now: [tex]W = F * d[/tex]. This would mean that [tex]W = 20 * 15[/tex], which is equal to [tex]300[/tex]. Our answer is 300 joules. (this value is positive and not negative because kinetic energy is being GAINED, not LOST)Here's the real question without all the formatting:
A truck pushes a pile of dirt horizontally on a frictionless road with a net force of 20 N for 15.0 m. How much kinetic energy does the dirt gain?A truck pushes a pile of dirt in the horizontal direction with a force of 20 N to a distance of 15 m then the kinetic energy of the dirt is 300 J.
What is work?In physics, the term "work" refers to the measurement of energy transfer that takes place when an item is moved over a distance by an externally applied, at least a portion of which is applied inside the direction of the displacement.
The duration of the path is multiplied by the component of a force acting along the path to calculate work if the forces are constant. The work W is theoretically equivalent to the pressure f times the range d, or W = fd, to represent this idea. Work is done when a force is applied at an angle of to a displacement, or W = fd cos.
The work done, [tex]W = Force * Displacement[/tex]
W = 15× 20
W = 300 J
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I
2800000 kg
Fig. 2.1
The total mass of the rocket and its full load of fuel is 2.8 106 kg. The constant force provided by
the rocket's motors is 3.2 x 107N.
32000000 N.
(a) Calculate
(i) the total weight of the rocket and the fuel.
weight =
Answer:
W = 27468000 [N] or 27.47 [kN]
Explanation:
The weight of a body is defined as the product of mass by gravitational acceleration.
[tex]W = m*g[/tex]
where:
W = weight of the rocket with fuel [kg]
m = mass = 2800000 [kg]
g = gravity acceleration = 9.81 [m/s²]
Now we can solve:
[tex]W = 2800000*9.81\\W = 27468000 [N][/tex]
Please help!!
A person is driving in a circle at 20m/s. Are they accelerating?
A mass oscillates on a spring, bouncing up and down 5 times per second. From the highest position to the
lowest position of the mass is a distance of 16 cm.
Answer:
i kinda dnt knw srry wanted the points for the answer
Explanation:
why do feet smell and noses run?
Answer:
Nose has mucous glands with hairs which helps the body in trapping pollutants and infectants from entering inside the body. On the other hand,our feet is composed of millions of sweat pores when dirt and other things accumulate,it smells because of sweat mixed with the dirt and other dirty things of the ground.
Explanation:
Hope this helps
During a hockey game, a puck is given an initial speed of 10 m/s. It slides 50 m on the horizontal ice before it stops due to friction. What is the coefficient of kinetic friction between the pick and the ice.A) 0.12B) 0.10C) 0.11D) 0.090
Answer:
The value is [tex]\mu_k = 0.102[/tex]
Explanation:
From the question we are told that
The initial speed of the pluck is [tex]u = 10 \ m/s[/tex]
The distance it slides on the horizontal ice is [tex]s = 50 \ m[/tex]
Generally from kinematic equation we have that
[tex]v^2 = u^2 + 2as[/tex]
Here v is is the final velocity and the value is 0 m/s given that the pluck came to rest, so
[tex]0^2 = 10 ^2 + 2* a * 50[/tex]
=> [tex]a = - 1 \ m/s^2[/tex]
Here the negative sign show that the pluck is decelerating
Generally the force applied on the pluck is equal to the frictional force experienced by the pluck
So
[tex]F = F_f[/tex]
=> [tex]m * a = m* g * \mu_k[/tex]
=> [tex]1 = 9.8 * \mu_k[/tex]
=> [tex]\mu_k = 0.102[/tex]
What is the Potential Energy of a roller coaster if it has a velocity of 35 m/s and a mass of 2000 kg and is at a height of 200 m? Please answer fast
A.) 137,200,000 J
B.) 12,005,000 J
C.) 3,920,000 J
D.) 1,400,000 J
Answer:
C
Explanation:
It cant be A or D, meaning your left with B and C. there cant be an answer in the 1000's place eather
Which is an example of balanced forces acting on an object?
a kangaroo jumping
a car turning a corner
a cyclist slowing down
a leaf lying on the grass
Answer:
a leaf lying on the grass
Explanation:
there is no movement (unbalanced forces) acting on the leaf so that's why it is still lying down and not changing its motion
When the force acting on a body is zero is called balanced force. Option D is correct.
What is balanced force?Force is defined as a push or pull of an object. Balanced forces are equal and opposite in direction. In balanced forces, there is no change in motion. In balanced force, the object is in equilibrium( i.e : the object is not moving with change in speed).
Unbalanced force is a force that can change the state of uniform motion or the rest of the body. If an object is moving with change in speed, it is said to be unbalanced.
From the given, some of them like kangaroo jumping, car turning a corner, cyclist slowing down shows motion except leaf lying on the grass. The leaf lying on the grass does not show any movement or motion, it is an example of balanced force.
Hence, the correct option is D) Leaf lying on the grass.
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A force of 64 N gives an object an acceleration of 23.53 m/s^2. What is the mass of the object?
A-2.00 kg
B-1505 kg
C-2.72 kg
D-736 kg
Lab - Wave Properties in a Spring
11-05
The wave characteristics you will observe in this lab are common to all waves (water, light, sound,
etc.). Use your prior knowledge and the book to fill in the following blanks, then go in the hall and
perform the lab.
A wave is a disturbance that moves through (propagates) through empty space or through a
_____________. There are two types of waves. A _____________________ wave requires
matter to travel. List some examples of this type:
A _____________________ wave does not require a medium. Examples include:
In order to start and transmit a mechanical wave, a source of _____________ and an
_______________ medium are required. A single disturbance is referred to as a
_______________, and a series of disturbances is a wave __________.
The questions in bold are those you should observe directly. Others will be answered using the book.
A. TYPES OF MECHANICAL WAVES: In the hall, stretch the slinky on the floor until it is
stretched (but still loose). Practice sending single pulses down the slinky by popping your wrist
from the center to the side and back to the center. Then send a continuous wave train along as
your partner holds the other end still. A piece of ribbon should be tied to one coil. Watch the
motion of this ribbon (representing a particle) as the wave travels through the spring.
In this type of wave, the particles move (perpendicular, parallel)
to the direction the wave travels. This type of wave is called a __________________ wave.
Its pulses are called ________________ and ________________.
Now send a pulse by quickly pushing the spring forward and pulling
it back, as shown. This type of wave is called _______________. Watch the motion of the ribbon.
In this type, the particles move _____________ to the direction the wave travels. Its pulses
are called _____________ and _____________. Label each.
Note that all waves transfer _____________ without transferring _______________. In
mechanical waves, particles of the medium vibrate back and forth in simple harmonic motion while
the disturbance (or _____________) moves from one place to another.
B. WAVE SPEED
Send a large pulse, followed by a small one. Does one pulse catch up to the other? ______
(Hint: The person who sends these waves should watch how the waves look when they return. Make
sure that both pulses are large enough initially to make it back to the sender!) The size of the
pulse is called the __________________ of the wave. Did the size affect the speed? ______
Generate a single transverse pulse in the slinky, keeping the stretch constant. Using a stopwatch,
time the journey of the pulse from one end to the other and back again. Take the average of
several trials. _________
Without changing your positions on the floor (therefore keeping the _____________ the pulse
travels the same), pull the slinky tighter using only about 3/4 of the coils. This makes a completely
different medium through which the pulse will travel. Time the journey as before. ___________
Does the kind of medium affect the speed of the pulse? ___________
Lab – Wave Properties in a Spring ____________________
PHYSICSFundamentals
© 2004, GPB
11-06
C. WAVELENGTH AND FREQUENCY
Shake the slinky back and forth steadily to send a
transverse wave train while your partner holds the other end still. On the diagram, label wavelength
(- Greek letter lambda). The frequency of the wave depends on how fast you shake the slinky.
Shake it regularly but slowly, then regularly but rapidly.
Higher frequency waves are generated by shaking the spring (slowly, rapidly). High frequency
waves have (short, long) wavelengths, and low frequency waves have __________.
The speed of a wave in any medium is equal to the _______________ of the wave X
________________. This wave equation ___________________ shows that f and are
______________ proportional. Write the units for each of the variables in this equation.
The exercise involves filling in the gaps with the possible wave
properties that can be obtained from a spring.
How is the Wave Properties in a Spring Lab exercise correctly completed?The correctly completed exercise is presented as follows;
A wave is a disturbance that moves through a medium. There are two
types of waves. A mechanical wave requires matter to travel. List some
examples of this type: sound wave, water wave, spring waves.
A electromagnetic wave does not require a medium. Examples include: Light waves
In order to start and transmit a mechanical wave, a source of
disturbance and a physical medium are required. A single disturbance is
referred to as a pulse, and a series of disturbance is a wave train.
This type of wave is called transverse wave. Its pulses are called crest
and troughs.
Now send a pulse by quickly pushing the spring forward and pulling it
back, as shown. This type of wave is called longitudinal wave. Watch the
motion of the ribbon. In this type, the particles move parallel to the
direction the wave travels. Its pulses are called compression and
rarefactions. Note that all waves transfer energy without transferring
matter. In mechanical waves, particle of the medium vibrate back and
forth in simple harmonic motion while the disturbance (or energy)
moves from one place to another.
B. Wave speed
Does the pulse catch up to the other? yes. The size of the pulse is called
the amplitude of the wave.
Did the size of the pulse affect the speed? No.
The average time wave it takes the wave to travel
Without changing your positions therefore keeping the distance the
pulse travels the same), pull the slinky tighter using only about 3/4 of
coils. This makes a completely different medium through which the
pulse will travel. Time the journey as before time record. Does the kind
of medium affect the speed of the pulse? Yes
C. Wavelength and Frequency
High frequency waves have short wavelengths and low frequency waves
have long wavelengths.
The speed of a wave in any medium is equal to the frequency of the wave × the wavelength. This wave equation [tex]\underline{f = \dfrac{v}{\lambda } }[/tex] shows that f and λ are
inversely proportional. The units of the variables are;
Units of the frequency, f is hertz unit HzUnits of the velocity, v, is m/sUnits of the wavelength, λ, is meters (m)Learn more about waves here:
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A bullet fired into a fixed target loses half of its velocity after penetrating 3 cm. How much further it will penetrate before coming to rest assuming that it faces constant resistance to motion
[tex]{\mathfrak{\underline{\purple{\:\:\: Given:-\:\:\:}}}} \\ \\[/tex]
[tex]\:\:\:\:\bullet\:\:\:\sf{First \: penetrating \: length\:(s_{1}) = 3 \: cm}[/tex]
[tex]\\[/tex]
[tex]{\mathfrak{\underline{\purple{\:\:\:To \:Find:-\:\:\:}}}} \\ \\[/tex]
[tex]\:\:\:\:\bullet\:\:\:\sf{Left \: Penetration \: length \: before \: it \: comes \: to \: rest \:( s_{2} )}[/tex]
[tex]\\[/tex]
[tex]{\mathfrak{\underline{\purple{\:\:\: Calculation:-\:\:\:}}}} \\ \\[/tex]
[tex]\:\:\:\:\bullet\:\:\:\sf{Let \: Initial \: velocity = v\:m/s} \\\\[/tex]
[tex]\:\:\:\:\bullet\:\:\:\sf{Left \: velocity \: after \: s_{1} \: penetration = \dfrac{v}{2} \:m/s} \\\\ [/tex]
[tex]\:\:\:\:\bullet\:\:\:\sf{s_{1} = \dfrac{3}{100} = 0.03 \: m}[/tex]
[tex]\\[/tex]
☯ As we know that,
[tex]\\[/tex]
[tex]\dashrightarrow\:\: \sf{ {v}^{2} = {u}^{2} + 2as }[/tex]
[tex]\\[/tex]
[tex]\dashrightarrow\:\: \sf{ \bigg(\dfrac{v}{2} \bigg)^{2} = {v}^{2} + 2a s_{1}}[/tex]
[tex]\\[/tex]
[tex]\dashrightarrow\:\: \sf{ \dfrac{ {v}^{2} }{4} = {v}^{2} + 2 \times a \times 0.03 }[/tex]
[tex]\\[/tex]
[tex]\dashrightarrow\:\: \sf{ \dfrac{ {v}^{2} }{4} - {v}^{2} = 0.06 \times a }[/tex]
[tex]\\[/tex]
[tex]\dashrightarrow\:\: \sf{\dfrac{ - 3{v}^{2} }{4} = 0.06 \times a }[/tex]
[tex]\\[/tex]
[tex]\dashrightarrow\:\: \sf{a = \dfrac{ - 3 {v}^{2} }{4 \times 0.06} }[/tex]
[tex]\\[/tex]
[tex]\dashrightarrow\:\: \sf{ a = \dfrac{ - 25 {v}^{2} }{2}\:m/s^{2} ......(1) }[/tex]
[tex]\\[/tex]
[tex]\:\:\:\:\bullet\:\:\:\sf{ Initial\:velocity=v\:m/s} \\\\ [/tex]
[tex]\:\:\:\:\bullet\:\:\:\sf{ Final \: velocity = 0 \: m/s }[/tex]
[tex]\\[/tex]
[tex]\dashrightarrow\:\: \sf{ {v}^{2} = {u}^{2} + 2as}[/tex]
[tex]\\[/tex]
[tex]\dashrightarrow\:\: \sf{{0}^{2} = {v}^{2} + 2 \times \dfrac{ - 25 {v}^{2} }{2} \times s }[/tex]
[tex]\\[/tex]
[tex]\dashrightarrow\:\: \sf{ - {v}^{2} = - 25 {v}^{2} \times s }[/tex]
[tex]\\[/tex]
[tex]\dashrightarrow\:\: \sf{ s = \dfrac{ - {v}^{2} }{ - 25 {v}^{2} }}[/tex]
[tex]\\[/tex]
[tex]\dashrightarrow\:\: \sf{ s = \dfrac{1}{25} }[/tex]
[tex]\\[/tex]
[tex]\dashrightarrow\:\: \sf{ s = 0.04 \: m }[/tex]
[tex]\\[/tex]
☯ For left penetration (s₂)
[tex]\\[/tex]
[tex]\dashrightarrow\:\: \sf{s = s_{1} + s_{2} }[/tex]
[tex]\\[/tex]
[tex]\dashrightarrow\:\: \sf{ 0.04 = 0.03 + s_{2}}[/tex]
[tex]\\[/tex]
[tex]\dashrightarrow\:\: \sf{ s_{2} = 0.04 - 0.03 }[/tex]
[tex]\\[/tex]
[tex]\dashrightarrow\:\: \sf{s_{2} = 0.01 \: m = {\boxed{\sf{\purple{1 \: cm }}} }}[/tex]
[tex]\\[/tex]
[tex]\star\:\sf{Left \: penetration \: before \: it \: come \: to \: rest \: is \:{\bf{ 1 \: cm}}} \\ [/tex]
10. A boy weighs 475 N. What is his mass? (acceleration due to gravity on Earth is 9.8m/s2 = g)
Answer: mass = 48.47 kg.
Explanation:
Formula : Weight = mg , where m = mass of body , g= acceleration due to gravity .
Given: Weight = 475 N
[tex]g= 9.8\ m/s^2[/tex]
Substitute all values in formula , we get
[tex]475= m \times9.8\\\\\Rightarrow\ m = \dfrac{475}{9.8}\\\\\Rightarrow\ m \approx 48.47\ kg[/tex]
Hence, his mass = 48.47 kg.
a wandering dog walks 1 km due east, 1 km due south, then runs 2 km due west. the magnitude of the dogs displacement is closest to
a. 0 km
b. 1.4 km
c. 3.4 km
d. 4.0 km
Answer:
b) 1.4km
Explanation:
characteristics of projectile motion.
Answer:
Objects experiencing projectile motion have a constant velocity in the horizontal direction and a constantly changing velocity in the vertical direction. The trajectory resulting from this combination always has the shape of a parabola.
Explanation:
QUESTION 23
How much electric energy will be used by a 115 V, 60 W Eghtbulb in one minute
69.
2215
5800
6900)
*
Xpwe-
Answer:
E = 3600 J
Explanation:
Given that,
Voltage, V = 115 V
Power of electric bulb, P = 60 W
We need to find the electric energy used in 1 minute. The electric energy use is given by :
[tex]E=P\times t\\\\E=60\ W\times 60\ s\\\\E = 3600\ J[/tex]
Hence, the electrical energy is 3600 J.
Angelica inhaled deeply into a plastic cup. Why did the cup collapse?
Answer:
Air vacuum.
Explanation:
Air may seem like nothing, but there are tons of molecules in it. Air takes up space. When Angelica inhales, the air rushes into into and escapes the cup. Since theres no air anymore, the cup collapses because thereis no more space in it. She removes the air from the cup and it creates a vacuum inside, sucking the sides of the cup in.
Details
A 70 kg student rides the Gravitron at a carnival. The
Gravitron has a radius of 2.75 meters. The student feels
a centripetal force of 2100 N. How fast is the Gravitron
spinning?
Answer:
1400 math quiz
Explanation:
40s n shorty's
The amplitude of a pendulum is doubled. This means:
a
the pendulum will have twice its original mass.
b
the frequency of the pendulum will be twice as high.
c
the pendulum will swing twice as far away from the center.
d
the period of the pendulum will be twice as long.
Answer:
the period of the pendulum will be twice as long.
Explanation:
because i looked it up
What type of electromagnetic wave is a TV remote and a cloud
Answer: Kids learn about the types of electromagnetic waves in the science of physics ... Microwaves are useful in communication because they can penetrate clouds, ... These are the infrared waves that are used in your TV remote to change channels
Explanation:
Find the current if 55 C of charge pass a particular point in a circuit in 5 seconds.
Answer:
The current is 11 Amperes
Explanation:
Electric Current
The electric current is defined as a stream of charged particles that move through a conductive path.
The current intensity can be calculated as:
[tex]\displaystyle I=\frac{Q}{t}[/tex]
Where:
Q = Electric charge
t = Time taken by the charge to move through the conductor
The current intensity is often measured in Amperes.
The charge passing through a point in a circuit is Q= 55 c during t=5 seconds, thus the current intensity is:
[tex]\displaystyle I=\frac{55}{5}[/tex]
I = 11 Amp
The current is 11 Amperes
WGVU-AM is a radio station that serves the Grand Rapids, Michigan area. The main broadcast frequency is 1480kHz. At a certain distance from the radio station transmitter, the magnitude of the magnetic field of the electromagnetic wave is 3.0x10^-11T.
a. Calculate the wavelength
b. What is the angular velocity?
c. Find the wave number of the wave.
d. What is the amplitude of the electric field at this distance from the transmitter?
Answer:
a
[tex]\lambda = 202.7 \ m[/tex]
b
[tex]w = 9.3 *10^{6} \ rad/s[/tex]
c
[tex]k = 0.031 m^{-1}[/tex]
d
[tex]E_{max} = 9.0 *10^{-3} \ V/m[/tex]
Explanation:
From the question we are told that
The frequency of the radio station is [tex]f= 1480 \ kHz = 1480 *10^{3}\ Hz[/tex]
The magnitude of the magnetic field is [tex]B = 3.0* 10^{-11} \ T[/tex]
Generally the wavelength is mathematically represented as
[tex]\lambda = \frac{c}{f}[/tex]
Here c is the speed of light with value [tex]c = 3.0 *10^{8} \ m/s[/tex]
So
[tex]\lambda = \frac{3.0 *10^{8}}{ 1480 *10^{3}}[/tex]
=> [tex]\lambda = 202.7 \ m[/tex]
Generally the angular frequency is mathematically represented as
[tex]w = 2 \pi * f[/tex]
=> [tex]w = 2 * 3.142 * 1480 *10^{3}[/tex]
=> [tex]w = 9.3 *10^{6} \ rad/s[/tex]
Generally the wave number is mathematically represented as
=> [tex]k = \frac{2 \pi }{\lambda}[/tex]
=> [tex]k = \frac{2 * 3.142 }{ 202.7}[/tex]
=> [tex]k = 0.031 m^{-1}[/tex]
Generally the amplitude of the electric field at this distance from the transmitter is mathematically represented as
[tex]E_{max} = c * B[/tex]
=> [tex]E_{max} = 3.0 *10^{8} * 3.0* 10^{-11}[/tex]
=> [tex]E_{max} = 9.0 *10^{-3} \ V/m[/tex]
Help me please..
When the slope of a velocity vs. time graph is negative and constant,
what type of motion is occurring?
A) No motion
B) Constant speed
C) Acceleration
D) Constant Velocity
E) Going in circles
Help me please..
Velocity is defined as a
and a?
A) speed, direction
B) change, direction
C) speed, acceleration
D) change, acceleration
Answer:
Speed and direction.....
What are conducting patterns?
Answer:
A conducting pattern is a pattern in which your dominant hand follows in order to establish beats and tempo to the choir. Conductors that are directing large orchestras and choirs will often times use a baton so that the entire group can clearly see the motions.
Explanation:
A radioactive nuclide of atomic number Z emits an alpha particle and the daughter nucleus then emits a beta particle. What is the atomic number of resulting nuclide?
A) Z-1
B) Z+1
C) Z-2
D) Z-3
Answer:
A) Z-1
Explanation:
when a radioactive element of atomic number Z emits an alpha particle, the mass of the new nucleus decreases by 2, i.e the new atomic number of the element = ( Z- 2).
Also, when the daughter nucleus emits a beta particle, the new nucleus increases by 1, that is the new atomic number of the element = (Z + 1).
Thus, the atomic number of resulting nuclide = Z ( - 2) + ( + 1).
= Z - 2 + 1
= Z - 1
Therefore, the atomic number of resulting nuclide is Z - 1
20 pts.
Which of the following statements is true?
O Electromagnets use electrlcity and magnets.
O Magnetic fields are strongest around the poles of a magnet.
O The south pole of a magnet will repel the south pole of another magnet.
O all of the above
Answer:
all are true so d is right
Explanation:
Electromagnets use electrlcity and magnets is true.
Magnetic fields are strongest around the poles of a magnet is true.
The south pole of a magnet will repel the south pole of another magnet is true
and since all of them is true the answer is d all of the above
Bonnie and Clyde are trying to steal the world's largest diamond from a 10 story
building. Bonnie needs to make a landing spot for when Clyde jumps with the
diamond. She knows they will be jumping from 58 feet. Neglecting air resistance,
what is the speed Clyde will be falling at right before hitting the ground?
Answer:
The speed Clyde will be falling at is 33.72.
James is planning on registering for a course in electrical engineering which of the following sub disciplines could he opt for instrumentation engineering prosthetics plant design or signal processing
Answer:
Instrmentation engineering
Explanation:
Hope this helps!
A tennis ball is traveling at 50 m/s and has a kinetic energy of 75J. Calculate the mass of the tennis ball.
A string of length 10.0 m is tied between two posts and plucked. This sends a wave down the string moving at a speed of 130 m/s with a frequency of 215 Hz. How many complete wavelengths of this wave will fit on the string?
Answer:
16.
Explanation:
In any wave, by definition, there exists a fixed relationship between the speed v, the frequency f , and the wavelength λ, as follows:[tex]v = \lambda * f (1)[/tex]
In our case, v = 130 m/s and f= 215 Hz, so solving for λ in (1), we get:[tex]\lambda = \frac{v}{f} = \frac{130m/s}{215 hz} = 0.61 m (2)[/tex]
In order to know how many wavelengths of this wave will fit on the string, we need just do divide the length of the string (10.0 m) over one single wavelength, as follows:[tex]n = \frac{L}{\lambda} = \frac{10.0m}{0.61m} = 16.4 (3)[/tex]
Since we need to take the integer value from this expression, the number of complete wavelengths that will fit on this string is just 16.A particular engine has a power output of 2 kW and an efficiency of 27%. If the engine expels 9085 J of thermal energy in each cycle, find the heat absorbed in each cycle. Answer in units of J.
Answer:
12445 J
Explanation:
Given that
Power output, P = 5 kW
efficiency of the engine, e = 27% = 0.27
Thermal energy expelled, Q(c) = 9085 J
Heat absorbed, Q(h) = ?
Using the formula
e = W/Q(h)
e = [Q(h) - Q(c)] / Q(h)
e = 1 - Q(c)/Q(h)
Now, substituting the values into the formula, we have
0.27 = 1 - 9085/Q(h)
9085/Q(h) = 1 - 0.27
9085/Q(h) = 0.73
Q(h) = 9085 / 0.73
Q(h) = 12445 J
Thus, the heat absorbed is 12445 J
