A toy car with a mass of 5.5 kg is moving horizontally over flat ground at a speed of 2.1 m/s. An unknown force then directly pushes the car for a distance of 3 meters, after which the car has a speed of 7.3 m/s. You may assume that air resistance and friction are both negligible. What was the magnitude of the unknown force

Answer:

If you went to work your trap muscles you don't need a ton of fancy gym equipment. Here are four trapezius exercises you can perform using your own body.

Answer:

Write any three differences between single fixed pulley and single moveable pulley.

Single fixed pulley;

Single moved pulley;

Answer:

please like

Explanation:

hope it helps you

Answer:

Explanation:

1. Free fall implies an object falling under the gravitational influence only. During the flight, no other force acts on it except the gravitational pull.

2. Acceleration due to gravity is the earth's natural force of pull on all objects on its surface, close to its surface, or in the region where the force can be felt. This force pulls object to the surface of the earth.

3. Escape velocity is the required minimum velocity for an object to leave the gravitational influence of the earth. It has a constant value which can be determined by;

Escape velocity = [tex]\sqrt{2gR}[/tex]

where g is the gravitation force of the earth and R is the radius of the earth.

4. Centripetal force is the force of pull that is required to keep a rotation object in its curved path.

Answer:

It is respected as leaders are accountable to the people. The rule of law within a democratic country will dictate what actions is considered wrong and punishable to do in that country. This will prevent people from harming and violating each other to get what they want and form a stable and safe society

Explanation:

Answer:

Electricity is the presence and flow of electric charge. Using electricity we can transfer energy in ways that allow us to do simple chores . it's best - known form is the flow of electrons through conductor such as copper wires. The world "electricity " is sometimes used to mean "electrical energy "

Explanation:

hope it is helpful to you ☆

[tex]kavya[/tex]

Answer:

m = 1.53 kg

Explanation:

Given that,

The sides of a book are 30cm by 25cm.

Pressure exerted, P = 200 Pa

We need to find the mass of the block. We know that,

Pressure = Force/area

So,

[tex]P=\dfrac{mg}{A}\\\\m=\dfrac{PA}{g}[/tex]

Put all the values,

[tex]m=\dfrac{200\times 0.3\times 0.25}{9.8}\\\\m=1.53\ kg[/tex]

So, the mass of the block is 1.53 kg.

Answer:

Molecular compounds have molecules

Answer:

I think A

if I'm wrong I'm sorry did my best on research

Answer:

      A

IN fusion reaction two small nuclei join together to form a heavy nucleus with the emission of neutron and energy

Answer:

reducing the scale of the market for a new product

Explanation:

A product can be defined as any physical object or material that typically satisfy and meets the demands, needs or wants of customers. Some examples of a product are mobile phones, television, microphone, microwave oven, bread, pencil, freezer, beverages, soft drinks, automobiles, motorcycles, etc.

The use of technology in the manufacturing of a new product can be effectively and efficiently promoted in the market by doing the following;

I. Issuing a patent to a company that invents a new product. Patent can be defined as the exclusive or sole right granted to an inventor by a sovereign authority such as a government, which enables him or her to manufacture, use, or sell an invention for a specific period of time.

Generally, patents are used on innovation for products that are manufactured through the application of various technologies.

II. Paying a higher amount of money as wages for researchers who are saddled with the responsibility of making finding about a product.

III. Creating a training programs that would help to improve on the knowledge and skills of workers.

However, reducing the scale of the market for a new product in comparison with other products and standards does not help promote technological progress.

Answer:

a) i) x = 0.25 m, ii) x = 0.10 m, iii)  x = 0.050 m

b) i)  x = 0.40 m

Explanation:

a) For this exercise we use the rotational equilibrium equation, where we assume that the anticlockwise rotations are positive.

1) L = 2W  

we set our reference system in the center of the bar where the fulcrum is

              ∑τ = 0

              W 0.50 - L x = 0

              x = 0.50 W / L

we substitute the value

              x = 0.50 W / 2W

              x = 0.25 m

ii) L = 5W

we calculate

              x = 0.50 W / 5W

              x = 0.10 m

iii) L = 10 W

               x = 0.50 W / 10W

              x = 0.050 m

b) a new weight is placed at x₂ = 30 cm on the left side

              W 0.50 + W 0.30 - L x = 0

              x = (0.50 + 0.30) W / L

              x = 0.80 W / L

we calculate

i)  L = 2W

                x = 0.80 w / 2w

                x = 0.40 m

Answer:

4 m

Explanation:

From the question given above, the following data were obtained:

Initial velocity (u) = 10 m/s

Acceleration (a) = –8m/s²

Time (t) = 2 s

Displacement (s) =?

The displacement of the object can be obtained as follow:

s = ut + ½at²

s = (10 × 2) + (½ × –8 × 2²)

s = 20 + (–4 × 4)

s = 20 + (–16)

s = 20 – 16

s = 4 m

Thus, the displacement of the object is 4 m.

Answer:

C: time of contact is increased

Explanation:

When a ball is falling from height, it maintains the same mass but velocity may change depending on the conditions in that environment.

Now, to catch the ball on your palm, you need to find a way to reduce the momentum of the ball upon hitting your hand.

Now, to reduce the momentum, we need to apply impulse.

This is because we know that;

Impulse(I) = F × t = change in momentum (m(v - u))

Thus;

I = Ft

F = I/t

We are told that extending the hand reduces the force of contact on your hand.

Thus;

For F which is the force to be reduced, the denominator (t) has to be increased.

Thus, the correct answer is that time of contact is increased

Answer:

2a.

a=1.13ms^-2

2b.

S=277m

2c.

V=27.7ms-¹

Explanation:

Initial Velocity (U)=22m/s¹

Final Velocity (V)=43m/s²

Time(t) =18.6s

a. a=V-U/t

a=43-22/18.6

a=1.129

a=1.13m/s²

2b.

S=ut+1/2 at²

s=22(10)+1/2×1.13(10)²

s= 220+0.57(10)²

s= 220+0.57(100)

s= 220+57

s=277m

2c.

V=U+AT

V=22+1.13(5)

V=22+5.65

V=22+5.7

V=27.7m/s¹

Answer:A

Explanation:i just took the test

Answer:

A.

Explanation:

The pad extends the time so the impulse changes.

Answer:

A. The pad extends the time so the impulse changes

Explanation:

in term of physics it has same mass:)

Answer:

True

Explanation:

When non-conservative forces are present, the amount of work done increases with the length of the path, this is true because, when a force is applied, the force does when and the non-conservative forces also do work. Since the non-conservative force work against the force  applied, this tend to increase the net work done by the applied force to compensate for the loss in energy due to the work done by the non-conservative forces.

Answer:

El equilibrio térmico se alcanzará a los 152ºC.

Explanation:

Dado que un ladrillo de 2kg que se encuentra a 200º c, se sumerge en 5 kg de agua a 32º, para determinar a qué temperatura se alcanza el equilibrio térmico se debe realizar el siguiente cálculo:

2+5 = 7

(200 x 5 + 32 x 2) / 7 = X

1064 / 7 = X

152 = X

Por lo tanto, el equilibrio térmico se alcanzará a los 152ºC.

Let v be the billiard ball's initial speed. The total momentum of the ball-marble system is conserved between the times before and after their collision, so that

(1 kg) v + (0.1 kg) (0 m/s) = (1 kg) (0.3 m/s) + (0.1 kg) (3 m/s)

Solve for v :

v + 0 = 0.3 m/s + 0.3 m/s

v = 0.6 m/s

Answer:

(a) 37.5 kg

(b) 4

Explanation:

Force, F = 150 N

kinetic friction coefficient = 0.15

(a) acceleration, a = 2.53 m/s^2

According to the newton's second law

Net force = mass x acceleration

F - friction force = m a

150 - 0.15 x m g = m a

150 = m (2.53 + 0.15 x 9.8)

m = 37.5 kg

(b) As the block moves with the constant speed so the applied force becomes the friction force.

[tex]F = \mu m g \\\\150 = \mu\times 37.5\\\\\mu = 4[/tex]

Answer:

1

Explanation:

Answer:

I think 1 amu

Sorry if it is wrong.

Answer:

The brightness of a light depends on the amplitude of the light wave, which is the extent the waves moves from their equilibrium position. The brightness is also related to the amount of light that is emitted or reflected by an object

Therefore, compared to dim light, light that look bright have a higher amplitude and emit or reflect more light energy (photons)

Explanation:

Answer:

[tex] { \tt{velocity = \frac{distance}{time}}} \\ \\ { \tt{velocity = \frac{2750}{10.5} }} \\ = { \tt{261.9 \: {ms}^{ - 1} }}[/tex]

Answer:

[tex]R=240m[/tex]

Explanation:

From the question we are told that:

Velocity [tex]v=25m/s[/tex]

Force of friction f = 0

Angle [tex]\theta=15[/tex]

Generally the equation for  Radius of curvature is mathematically given by

[tex]R=frac{v^2}{tan\theta *g}[/tex]

[tex]R=frac{25^2}{tan 15 *9.81}[/tex]

[tex]R=240m[/tex]

Answer:

Wheel and axle is a simple machine. As we know thatsimple machines makesour work easier faster and more convenient. Like this wheel and axle help us in different ways like it helps to change the direction of force, helps to multiply force applied, helps to do work safely, etc.

I hope this answer will help you. Stay safe.

Answer:

provides forms of transportation and many other gadgets that aid daily life

Explanation:

ex: car tires, bicycles, windmills, doorknobs

Answer:

A. Energy only is the answer to your question

Answer:

Q = 165.95 cm³ / s,  1)    v = [tex]\sqrt{0.55^2 + 19.6 y}[/tex],  2)  v = 2.05 m / s,

3)  d₂ = 1.014 cm

Explanation:

This is a fluid mechanics exercise

1) the continuity equation is

         Q = v A

where Q is the flow rate, A is area and v is the velocity

the area of ​​a circle is

        A = π r²

radius and diameter are related

        r = d / 2

substituting

       A = π d²/4

       Q = π/4   v d²

let's reduce the magnitudes

       v = 0.55 m / s = 55 cm / s

let's calculate

       Q = π/4   55   1.96²

       Q = 165.95 cm³ / s

If we focus on a water particle and apply the zimematics equations

        v² = v₀² + 2 g y

where the initial velocity is v₀ = 0.55 m / s

        v = [tex]\sqrt{0.55^2 + 2 \ 9.8\ y}[/tex]

        v = [tex]\sqrt{0.55^2 + 19.6 y}[/tex]

2) ask to calculate the velocity for y = 0.2 m

        v = [tex]\sqrt{0.55^2 + 19.6 \ 0.2}[/tex]

        v = 2.05 m / s

3) We write the continuous equation for this point 2

        Q = v₂ A₂

        A₂ = Q / v₂

let us reduce to the same units of the SI system

        Q = 165.95 cm³ s (1 m / 10² cm) ³ = 165.95 10⁻⁶ m³ / s

        A₂ = 165.95 10⁻⁶ / 2.05

        A₂ = 80,759 10⁻⁶ m²

area is

        A₂ = π/4   d₂²

        d₂ = [tex]\sqrt{4 A_2 / \pi }[/tex]

        d₂ = [tex]\sqrt{ \frac{4 \ 80.759 \ 10^{-6} }{\pi } }[/tex]

        d₂ = 10.14 10⁻³ m

        d₂ = 1.014 cm