A. Tick (1) the best alternatives. 1. What is the acceleration due to gravity on the surface of moon ? (a) 9.8m/s (b)1.6m/s2 (c) 6.67x10-1m/s (d) 9.8m/s? ​

Answers

Answer 1

Answer:

[tex] \green{ \sf \: \: 1.6 \: m {s}^{ - 2} \: \: \: is \: the \: correct \: answer}[/tex]

Explanation:

[tex] \sf \: \huge{g } _{ \small{moon}} = \frac{ {\huge{g}}_{earth}}{6} \\ \\ \sf \implies \: \sf \: \huge{g } _{ \small{moon}} = \frac{ 9.8}{6} = 1.6 \: \: m {s}^{ - 2} [/tex]


Related Questions

the pages of a book are numbered 1 to 300. Each leaf is 0.1 mm thick . If each cover is 0.25 mm thick. what is the thickness of the book​

Answers

Answer:

30.5mm

Explanation:

There are 300 pages, so to find the number of pages we do 0.1mm*300 to get 30mm. There are two covers in the book (the front and the back). 0.25mm*2 = 0.5mm. To determine the total thickness of the book we do 30mm+0.5mm to get a total of 30.5mm

Your answer is 30.5mm.

Answer:

15.5mm

Explanation:

there are 150 pages(one page has 2 sides so 300/2 = 150) and 2 covers

page's thickness is 0.1mm, cover's thickness is 0.25

so books thickness = 150*0.1+0.25*2 = 15.5mm

the resultant capacitance of four capacitorconnected in series is --------the smalest individual capacitance

Answers

Answer:

This question is misleading since

1/C = 1/C1 + 1/C2 + 1/C3 + 1/C4

so it would have to be less than the smallest individual capacitance

What is the volume of a cone with a height of 27 cm
and a radius of 13 cm? Round your answer to the
nearest tenth.
Use the button on your calculator to complete this
problem.
V =
cm?

Answers

Explanation:

Volume of cone = πr² × h/3

Here,

Radius (r) = 13 cmHeight (h) = 27 cm

→ Volume of cone = π(13)² × 27/3 cm³

→ Volume of cone = 169π × 9 cm³

→ Volume of cone = 1521π cm³

→ Volume of cone = 1521 × 22/7 cm³

→ Volume of cone = 33462/7 cm³

→ Volume of cone = 4780.28 cm³

Answer:

4,778.4 is correct

Explanation:

what will be the magnitude of work if a force of 25N pulls a stone through a distance of 5m in its direction?​

Answers

Explanation:

125 is your answer........


A steel ball is released just below the surface of thick oil in a cylinder.
During the first few centimetres of travel, what is the acceleration of the ball?
A constant and equal to 10 m / s2
B constant but less than 10 m / s2
C decreasing
D increasing

Answers

Answer:

Increasing

Explanation:

I Hope it Helps

After landing the aeroplane momentum becomes zero .Explain how the law of conservation helds here.​

Answers

Answer:

see the explanation below

Explanation:

Momentum is a product of the mass of a particle and its velocity.

and also, momentum is a vector quantity; i.e. it has both magnitude and direction.

Now a plane in the air has both magnitude and velocity

When the plane lands the velocity will amount to zero although the mass is still very much intact

Now the mass* zero velocity= zero

Hence when a plane lands the momentum is zero

Encuentre la presion en la otra seccion estrecha si las velocidades en las secciones son de 0.50m\sy 2m\s

Answers

Answer:

ΔP = 1875 Pa,   P₂ = P₁ - 1875

Explanation:

Let's use Bernoulli's equation, with the subscript 1 for the widest Mars and the subscript 2 for the narrowest part, suppose that the pipe is horizontal

          P₁ + ½ ρ v₁² + ρ g y₁ = P₂ + ½ ρ v₂² + ρ g y₂

          P₁ -P₂ = ½ ρ (v₂² - v₁²)

suppose the fluid is water

          P₁ - P₂ = ½ 1000 (2² - 0.5²)

         ΔP = 1875 Pa

this is the pressure difference between the two sections

the pressure in the narrowest section is

           P₂ = P₁ - 1875

will mark brainliest. The speed of sound is 340 m/s where a tuning fork produces the second resonance position above a closed air column that is 49.8 cm in length. The frequency of the tuning fork is ___ Hz.

Answers

Answer:

Frequency of the tuning fork[second resonance] = 512 Hz (Approx.)

Explanation:

Given:

Speed of sound = 340 m/s

Length of resonance position above a closed air column = 49.8 cm = 0.498 m

Find:

Frequency of the tuning fork

Computation:

Frequency of the tuning fork[second resonance] = 3v / 4l

Frequency of the tuning fork[second resonance] = 3(340) / 4(0.498)

Frequency of the tuning fork[second resonance] = 512.04

Frequency of the tuning fork[second resonance] = 512 Hz (Approx.)

Answer:

The frequency is 512 Hz.

Explanation:

speed, v = 340 m/s

length, L = 49.8 cm = 0.498 m

let the frequency is f.

[tex]f =\frac{3 v}{4 L}\\\\f = \frac{3 \times 340 }{4\times 0.498}\\\\f = 512 Hz[/tex]

Which image illustrates refraction?

Answers

Answer:

B illustrates refraction

what change will occur in gravitational force between two bodies if mass of both object is doubled and distance between their center is halved

Answers

The gravitational force between 2 bodys decreases with distance between the two bodies.

f=G m1m2/r2

Answer:

if the distance between 2 objects is halved than the gravitation doubles ,as gravitation is inversely propotional, between the distance of 2 objects.

An electron travelling at 7.72 x 107 m/s [E] enters a force field that reduces its velocity to 2.46 x 107 m/s [E]. The acceleration is constant. The displacement during the acceleration is 0.478 m [E]. Determine (a) the electron’s acceleration (b) the time interval over which the acceleration occurs.

Answers

Answer:

Acceleration of this electron: [tex]-5.60 \times 10^{15}\; \rm m \cdot s^{-2}[/tex].

Time taken: approximately [tex]9.39 \times 10^{-9}\; \rm s[/tex].

Explanation:

Let [tex]u[/tex] denote the velocity of this electron before the change.Let [tex]v[/tex] denote the velocity of this electron after the change.Let [tex]x[/tex] denote the displacement.Let [tex]a[/tex] denote the acceleration.Let [tex]t[/tex] denote the time taken.

Apply the SUVAT equation that does not involve time:

[tex]v^{2} - u^{2} = 2\, a \, x[/tex].

Equivalently:

[tex]\begin{aligned}a &= \frac{v^{2} - u^{2}}{2\, x}\end{aligned}[/tex].

By this equation, the acceleration of this electron would be:

[tex]\begin{aligned}a &= \frac{v^{2} - u^{2}}{2\, x} \\ &= \frac{(7.72 \times 10^{7}\; \rm m \cdot s^{-1})^{2} - (2.46 \times 10^{7} \; \rm m \cdot s^{-1})^{2}}{2 \times 0.478\; \rm m} \\ &\approx -5.60 \times 10^{15}\; \rm m \cdot s^{-2}\end{aligned}[/tex].

The speed of this electron has changed from [tex]u = 7.72 \times 10^{7}\; \rm m\cdot s^{-1}[/tex] to [tex]v = 2.46 \times 10^{7}\; \rm m \cdot s^{-1}[/tex]. Calculate the time required to achieve this change at a rate of [tex]a \approx -5.60 \times 10^{15}\; \rm m\cdot s^{-2}[/tex]:

[tex]\begin{aligned}t &= \frac{v - u}{a} \\ &\approx \frac{2.46\times 10^{7}\; \rm m \cdot s^{-1} - 7.72 \times 10^{7}\; \rm m\cdot s^{-1}}{-5.60 \times 10^{15}\; \rm m\cdot s^{-2}} \\ &\approx 9.39 \times 10^{-9}\; \rm s\end{aligned}[/tex].

The current in a light bulb is 2 A. How long does it take for a total charge of 4 C to pass a point in the wire

Answers

Answer:

2min

Explanation:

i think it will be clear from photo

Answer: The formula for current is charge/time

so here we have to change subject so we are asked to look for time  

Explanation: so it would be T=Q/I

T=4/2

T=2s

hope this helpss

PLEASE HEEEEEEELP
Assume that the velocity of the soda bottle falling from a height of 0.8 m will be 4 m/s. Record this velocity for each mass in Table A, and use it in calculating the predicted kinetic energy of the soda bottle for the masses of 0.125 kg, 0.250 kg, 0.375 kg, and 0.500 kg using the equation: KE=1/2 mv^2 When solving for kinetic energy (KE), m is mass, and v is the speed (or velocity).

Answers

[tex]\large{\underbrace{\underline{\fcolorbox{White}{pink}{\bf{ANSWER♥︎}}}}}[/tex]kinetic energy is given as

KE = (0.5) m v²

given that : v = speed of the bottle in each case = 4 m/s when m = 0.125 kg

KE = (0.5) m v² = (0.5) (0.125) (4)² = 1 J

when m = 0.250 kg KE = (0.5) m v² = (0.5) (0.250) (4)² = 2 J

when m = 0.375 kg KE = (0.5) m v² = (0.5) (0.375) (4)² = 3 J

when m = 0.0.500 kg KE = (0.5) m v² = (0.5) (0.500) (4)² = 4 J

Calculate the maximum absolute uncertainty for R if:

R = B - A
A = 32 +/- 2 seconds
B = 11 +/- 3 seconds

43 seconds


1 second


21 seconds


5 seconds


6 seconds

Answers

Answer:

 ΔR = 5 s

Explanation:

The absolute uncertainty or error in an expression is

       ΔR = | [tex]\frac{dR}{dB}[/tex] | ΔB + | [tex]\frac{dR}{dA}[/tex] | ΔA

the absolute value guarantees to take the unfavorable case, that is, the maximum error.

We look for the derivatives

       [tex]\frac{dR}{dB}[/tex] = 1

       [tex]\frac{dR}{dA}[/tex] = -1

we substitute

       ΔR = 1 ΔB + 1 ΔA

       

of the data

       ΔB = 3 s

       ΔA = 2 s

         

       ΔR = 3 + 2

       ΔR = 5 s

What's the resultant of the 3 forces?​

Answers

Answer:

Explanation:

We need to find the x-components of each of these vectors and then add them together, then we need to find the y-components of these vectors and then add them together. Let's get to that point first. That's hard enough for step 1, dontcha think?

The x-components are found by multiplying the magnitude of the vectors by the cosine of their respective angles, while the y components are found by multiplying the magnitude of the vectors by the sine of their respective angles.

Let's do the x-components for all the vectors first, so we get the x-component of the resultant vector:

[tex]F_{1x}=12 cos0[/tex] and

[tex]F_{1x}=12[/tex]

[tex]F_{2x}=9cos90[/tex] and

[tex]F_{2x}=0[/tex]

[tex]F_{3x}=15 cos126.87[/tex] and

[tex]F_{3x}=-9.0[/tex]  (the angle of 126.87 is found by subtracting the 53.13 from 180, since angles are to be measured from the positive axis in a counterclockwise fashion).

That means that the x-component of the resultant vector, R, is 3.0

Now for the y-components:

[tex]F_{1y}=12sin0[/tex] and

[tex]F_{1y}=0[/tex]

[tex]F_{2y}=9sin90[/tex] and

[tex]F_{2y}=9[/tex]

[tex]F_{3y}=15sin126.87[/tex] and

[tex]F_{3y}=12[/tex]

That means that the y-component of the resultant vector, R, is 21.

Put them together in this way to find the resultant magnitude:

[tex]R_{mag}=\sqrt{(3.0)^2+(21)^2}[/tex] which gives us

[tex]R_{mag}=21[/tex] and now for the angle. Since both the x and y components of the resultant vector are positive, our angle will be where the x and y values are both positive in the x/y coordinate plane, which is Q1.

The angle, then:

[tex]tan^{-1}(\frac{21}{3.0})=82[/tex] degrees, and since we are QI, we do not add anything to this angle to maintain its accuracy.

To sum up: The resultant vector has a magnitude of 21 N at 82°

The direction equivalent to {40° W of S} is:
A. 40 ° E of S
B. 40° W of N
C. 40° E of N
D. 50° S of W
E. 50° E of N

Answers

Answer:

c

Explanation:

4. A body in motion is said to be in equilibrium when it is
A moving with uniform velocity.
B at rest.
C accelerated by a force.
D moving in an indefinite path.​

Answers

Answer:

A. moving with uniform velocity.

Explanation:

Was this hepfull

Answer:

A

Explanation:

Equilibrium is a state in which opposing forces or influences are balanced hence A being correct

A bus Starts from rest. If the acceleration of bus become 10 m/s2 after 15 sec Calculate the final Velocity of the bus​

Answers

The bus starts from the rest if the acceleration of bus becomes an M/S2 at the 15 seconds tackled the final Yossi of the bus. The answer is 20

Even through there is equal and opposite reaction,usually the two forces are not seen balanced.Why?

Answers

Answer:

This may refer to a situation like:

"one person pushes a box, if there is equal and opposite reaction why the box moves and the person does not?"

Remember the second Newton's law:

F = m*a

suppose that the mass of the person is 3 times the mass of the box.

So, if the box has a mass M, the person will have a mass 3*M

Then the Newton's equation for the box when the person pushes with a force F is:

F = M*a

solving for the acceleration, we get:

F/M = a

While the person is also pushed by the box with a force with the same magnitude, then the equation for the person is:

F = (3*M)*a'

Solving for the acceleration, we get:

F/(3M) = a'

Now we can compare the acceleration of the box (F/M) with the acceleration of the person (F/3M).

Is easy to see that the acceleration of the box is 3 times the acceleration of the person.

So regardless of the fact that both the box and the person experience a force with the same magnitude, the box will move more due to this force.

This is why in situations like this, the forces do not seem balanced.

I’m steel, the solvent is And the solute is. .

Answers

iron is the solvent and carbon is the solute.

Give reasons for the following,
a. Pascal is a derived unit.
b. Mass is a fundamental quantity,
c. Unit of power is a derived unit,
d. Unit of length is a fundamental unit. ​

Answers

Answer:

a) Pascal is a derived unit because it is derived from the unit of force and area

b)Mass is a fundamental quantity because it doesn't depends upon others physical quantity and made up of only one unit

c) unit of power is a derived unit because they are dependent quantities

D) unit of length is a fundamental unit because it cannot be expressed in terms of another quantity.

An object of 4 cm length is placed at a distance of 18 cm in front of a convex mirror of radius of curvature 30 cm. Find the position of the image ,its nature and size?​

Answers

Answer:

The position is 8.18cm from the mirror.

Nature is b=virtual

Size is 1.82cm

Explanation:

Note that for a convex mirror, the image distance and the focal length are negative;

Given

Object height H0 = 4cm

object distance u = 18cm

Radius of curvature R = 30cm

Since f = R/2

f = 30/2

f = -15cm

Recall that:

[tex]\frac{1}{f} =\frac{1}{u}+ \frac{1}{v}\\\frac{1}{-15}=\frac{1}{18}+\frac{1}{v} \\\frac{1}{v} =\frac{1}{-15} -\frac{1}{18}\\ \frac{1}{v} = \frac{-18-15}{270}\\\frac{1}{v} = \frac{-33}{270}\\v=\frac{-270}{33}\\v=-8.18cm[/tex]

Since the image distance is negative, this shows that the image is a virtual image.

To get the size:

[tex]\frac{H_1}{H_0}=\frac{v}{u}\\\frac{H_1}{4}=\frac{8.18}{18}\\18H_i=32.72\\H_i=\frac{32.72}{18}\\H_i= 1.82cm[/tex]

Using your Periodic Table, which element below has the smallest atomic radius? A.) Sodium, B.) Chlorine, C.) Phosphorus, D.) Iron

Answers

Chlorine is the smallest because up right extreme of the periodic table

Drag each label to the correct location on the image. Identify the particles and characteristics on this model of an atom.
Positively charged
Electron
Proton
Neutron
Negatively charged

Answers

Answer:

cant see picture

Explanation:

Answer:

please add picture so i can help you

Explanation:

a car travel the first 20km with a speed of 40km/h and the next 40km with a speed of 80km/h . find the average speed​

Answers

Answer:

average speed is 60km/h

Explanation:

you sum up the speed attained in each distance covered and divide it by 2 to get your answer

Example to measure the interval of time of a small stone dropped from 1m height.

Answers

Answer:

The time required is 0.45 s.

Explanation:

Height, h = 1 m

initial velocity, u = m/s

Let the time is t.

Use second equation of motion

[tex]h = u t + 0.5 at^2\\\\1 = 0 +0.5 \times 9.8 \times t^2\\\\t = 0.45 s[/tex]

The thermal energy in a heat engine is used to move a piston. Which best describes why this is possible?

The increase in thermal energy results in an increase in pressure.
The decrease in thermal energy results in an increase in pressure.
The increase in thermal energy results in a decrease in pressure.
The decrease in thermal energy results in a decrease in pressure.

Answers

The increase in entropy is directly related to the increase in temperature.

¿Cuál de las siguientes no es un tipo de fuerza de roce

Answers

enertia es el answer de tu question

Which of the following are true about simile and metaphor? Select all that apply.
similes and metaphors make comparisons for emotional effect
simile uses "like" or "as": metaphor does not
similes and metaphors make comparisons to give us mental pictures
both are the same

Answers

Answer:

It is simile uses "like" or "as": metaphor does not

Explanation:

it just it

Answer:

third one

Explanation:

i cant think of anymore

True or false: The maximum tensile force a solid, cylindrical wire can withstand increases as the thickness of the wire increases.

True

False

Answers

Answer:

True

Explanation:

The tensile stress, σ, on a solid cylindrical wire is given by the following relationship;

[tex]\sigma = \dfrac{F_t}{A_o}[/tex]

Where;

[tex]F_t[/tex] = The tensile force

[tex]A_o[/tex] = The original cross sectional area of the cylindrical wire = π·R²

R = The radius of the wire

Therefore;

[tex]F_t[/tex] = σ × [tex]A_o[/tex] = σ × π × R²

Therefore, the tensile force is directly proportional to the square of the radius of the cylindrical wire, and as the radius of the wire increases, which is by increasing the thickness of the wire, the tensile force is largely increased

The correct option is; True.

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