A swimmer heads directly across a river swimming at 1.6 m/s relative to still water. she arrives at a point 40 m downstream from the point directly across the river, which is 80 m wide.

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Answer 1

A swimmer is swimming directly across a river at a relative velocity of 1.6m/s to still water and the velocity of the river current is 0.8 m/s.

She reaches a point 40m downstream from the point across the river, which has a width of 80m.

The direction and speed of the river current should be determined. Let's first assume that the river is flowing in the same direction as the swimmer, which means that the net velocity will be the difference between the swimmer's velocity and the river's velocity. We'll designate the velocity of the river as v.

The swimmer's velocity relative to the river is 1.6 m/s, so her total velocity is 1.6 m/s + v.

This vector is at an angle θ to the perpendicular to the shore, and we can use trigonometry to calculate the horizontal and vertical components of the vector.

The swimmer crosses the river in a time of 80 m / 1.6 m/s = 50 s.

During that time, the river current will carry the swimmer 40 m downstream.

Therefore, the speed of the river current is 40 m / 50 s = 0.8 m/s.

To summarize, the velocity of the swimmer relative to the still water is 1.6 m/s.

The velocity of the river current is 0.8 m/s.

The net velocity of the swimmer relative to the shore is the vector sum of these two velocities, which is at an angle to the perpendicular to the shore.

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Related Questions

--------- does not have its own light it shines by ------------------------ the sunlight.

Answers

Answer:The moon does not have its own light. It shines by reflecting the sunlight.

Explanation:

One point charge has a magnitude of 5.4 x 10-7 C. A second charge that is 0.25 m away has a magnitude of 1.1 x 10-17 C. What is the electric force magnitude of one charge on the other?

Answers

The magnitude of the electric force between the two charges is 8.99 x 10^9 N, Where one point charge has a magnitude of 5.4 x 10-7 C and  second charge that is 0.25 m away has a magnitude of 1.1 x 10-17 C.

The electric force between two point charges can be calculated using Coulomb's Law, which states that the force is directly proportional to the product of the charges and inversely proportional to the square of the distance between them. In this case, the magnitude of the electric force can be calculated as:
Electric force = (k * |q1| * |q2|) / r^2
Where k is the electrostatic constant (8.99 x 10^9 N m^2/C^2), |q1| and |q2| are the magnitudes of the charges (5.4 x 10^-7 C and 1.1 x 10^-17 C, respectively), and r is the distance between the charges (0.25 m).
Plugging in the values, we can calculate the magnitude of the electric force as 8.99 x 10^9 N.

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A 2kg ball is acted upon by two forces. A 2N force pulls the ball to the west and a 6N force pulls the ball to the east. In which direction will the ball move?

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To determine the direction in which the ball will move, we need to calculate the net force acting on the ball. Net force is the vector sum of all the individual forces acting on an object.

In this case, there are two forces acting on the ball: a 2 N force pulling it to the west and a 6 N force pulling it to the east. Since these forces are in opposite directions, we can subtract the magnitude of the smaller force from the magnitude of the larger force to find the net force.

Net force = 6 N - 2 N = 4 N

The net force acting on the ball is 4 N. Since the net force is in the east direction (due to the larger 6 N force), the ball will move in the east direction.

Therefore, the ball will move to the east.

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What direction would the magnetic force point, when the electron enters the magnetic field?

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When the electron enters the magnetic field, the magnetic force would point in a direction perpendicular to both the velocity of the electron and the magnetic field, according to the right-hand rule.

The magnetic force on an electron moving through a magnetic field is determined by the right-hand rule. When the electron enters the magnetic field, the direction of the magnetic force is perpendicular to both the velocity of the electron and the magnetic field.

Using the right-hand rule, if you point your thumb in the direction of the velocity of the electron and your fingers in the direction of the magnetic field, then the direction in which your palm faces represents the direction of the magnetic force on the electron.

Therefore, when the electron enters the magnetic field, the magnetic force would point in a direction perpendicular to both the velocity of the electron and the magnetic field, according to the right-hand rule.

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Water flows in a flexible tube of radius 1.5 cm at the floor level of a house. The tube is joined a second tube of smaller radius (1.2 cm), which runs to a floor 7.2 m above. If the pressure in the lower tube is 214 kPa, and the pressure in the upper tube is 107 kPa, what is the speed of water in the upper (smaller radius) tube?

Answers

We need the value of v1 (velocity in the lower tube) to calculate v2. Unfortunately, the velocity in the lower tube is not provided in the given information. Without the value of v1, we cannot determine the exact speed of water in the upper tube.

The speed of water in the upper tube can be calculated using Bernoulli's equation, which relates the pressure, velocity, and height of a fluid.

Given:

Radius of the lower tube (r1) = 1.5 cm = 0.015 m

Radius of the upper tube (r2) = 1.2 cm = 0.012 m

Pressure in the lower tube (P1) = 214 kPa

Pressure in the upper tube (P2) = 107 kPa

Height difference (h) = 7.2 m

Acceleration due to gravity (g) = 9.8 m/s^2

Using Bernoulli's equation:

P1 + 1/2 ρ v1^2 + ρ g h1 = P2 + 1/2 ρ v2^2 + ρ g h2

Where:

ρ is the density of water (approximately 1000 kg/m^3)

v1 is the velocity of water in the lower tube

v2 is the velocity of water in the upper tube

h1 is the height of the lower tube

h2 is the height of the upper tube

Since the tube is at the floor level, the height difference (h) is the same as h2.

Now, let's solve the equation step by step:

Convert the pressures to Pascals:

P1 = 214 kPa = 214,000 Pa

P2 = 107 kPa = 107,000 Pa

Plug in the given values into the equation:

214,000 + 1/2 * 1000 * v1^2 + 1000 * 9.8 * 0 = 107,000 + 1/2 * 1000 * v2^2 + 1000 * 9.8 * 7.2

Simplify the equation:

1/2 * 1000 * v1^2 = 1/2 * 1000 * v2^2 + 1000 * 9.8 * 7.2

Cancel out common terms:

v1^2 = v2^2 + 9.8 * 7.2

Rearrange the equation to solve for v2:

v2^2 = v1^2 - 9.8 * 7.2

Take the square root of both sides to find v2:

v2 = √(v1^2 - 9.8 * 7.2)

Now, we need the value of v1 (velocity in the lower tube) to calculate v2. Unfortunately, the velocity in the lower tube is not provided in the given information. Without the value of v1, we cannot determine the exact speed of water in the upper tube.

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A box is sliding across a wooden floor. Eventually, it comes to a stop. The box stops because the frictional force decreased the amount of kinetic energy in the box. This kinetic energy was transformed into:



(A)Gravitational potential energy


(B)Surface energy


(C)Thermal energy


(D)The energy was not transformed, rather it just decreased.

Answers

The box stops because the frictional force decreased the amount of kinetic energy in the box. This kinetic energy was transformed into thermal energy.

What is Kinetic Energy?

Kinetic energy is the energy of motion. Kinetic energy can be transferred from one object to another to do work when a force acts upon it.

The frictional force is the force that opposes the motion of a body when it is in contact with another body. The frictional force is caused by the microscopic roughness of the two surfaces in contact. When a box slides across a wooden floor, the frictional force acts in the opposite direction of the box's motion, causing it to slow down and eventually stop.

What does the frictional force do?

The frictional force converts the kinetic energy of the moving box into heat energy, causing the box to slow down and eventually stop. Therefore, when the box stops, the kinetic energy is transformed into thermal energy.

Hence, the correct option is C) Thermal energy.

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A 900 kg car is taking a turn with a radius of 9.5 m while experiencing a centripetal acceleration of 3.79 m/s2.


How fast is the car moving?


What centripetal force is the car experiencing?


Name the force responsible for creating this centripetal motion in the car.

Answers

the car is experiencing a centripetal force of 3411.1 N.

The speed at which the 900 kg car is moving while taking a turn with a radius of 9.5 m while experiencing a centripetal acceleration of 3.79 m/s² can be calculated using the formula given below:

v = √(r × a)

Where:

v is the speed at which the car is moving

r is the radius of the turn

a is the centripetal acceleration

v = √(r × a) = √(9.5 × 3.79) = 7.08 m/s

Therefore, the car is moving at a speed of 7.08 m/s.

The centripetal force that the car is experiencing can be calculated using the formula given below:

F = m × a

Where:

F is the force the car is experiencing

m is the mass of the car (900 kg)

a is the centripetal acceleration

F = m × a = 900 × 3.79 = 3411.1 N

Therefore, the car is experiencing a centripetal force of 3411.1 N.

The force responsible for creating this centripetal motion in the car is the frictional force between the tires of the car and the road surface.

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A ball of mass m is attached to a string of length r and negligible mass. The ball moves clockwise in a vertical circle, as shown above. When the ball is at point p, the string is horizontal. Point q is at the bottom of the circle and point z is at the top of the circle. Air resistance is negligible. Express all algebraic answers in terms of the given quantities and fundamental constants.

Answers

the minimum speed of the ball at point Z is given by v = √(g(r/g - 1)/(1 - r/g)).

we have T = mv²/r... (1)

where v is the speed of the ball at point P.

We can rewrite this equation as v = √(Tr/m)... (2)

At point Q, the ball has its maximum speed and minimum tension.

Thus, we can write T - mg = mv²/r... (3)

where v is the speed of the ball at point Q.

From equation (3), we can write v² = (T/m)(r + g)... (4)

Substituting the value of v² from equation (4) into equation (3), we get

T - mg = (T/m)(r + g)T - mg = Tr/m + Tg/mT/m = g/(1 - r/g)T = mg/(1 - r/g)... (5)

Substituting the value of T from equation (5) into equation (4), we getv² = g(r/g + 1)/(1 - r/g)v²

= g(2 - r/g)v = √(g(2 - r/g))... (6)

At point Z, the ball has its minimum speed and maximum tension.

Thus, we can write T + mg = mv²/r... (7)

where v is the minimum speed of the ball at point Z. From equation (7), we can write

v² = (T/m)(r - g)... (8)

Substituting the value of T from equation (5) into equation (8), we get

v² = g(r/g - 1)/(1 - r/g)v

= √(g(r/g - 1)/(1 - r/g))... (9)

Hence, the tension at point P is given by

T = mv²/r or T = mg/(1 - r/g),

the speed of the ball at point Q is given by

v = √(g(2 - r/g)), and the minimum speed of the ball at point Z is given by

v = √(g(r/g - 1)/(1 - r/g)).

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Write a topic about one of the cosmic natural phenomena, explaining the reasons for the occurrence of this phenomenon

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Topic: The Formation of Black Holes: Unveiling the Cosmic Gravity Abyss

Explanation: Black holes, enigmatic cosmic entities, are formed through the gravitational collapse of massive stars. When a star exhausts its nuclear fuel, it undergoes a cataclysmic explosion known as a supernova. During the supernova event, the star's core collapses under its immense gravitational force, leading to the formation of a black hole.

The collapse occurs when the core's mass exceeds a critical threshold, resulting in an intense gravitational pull. This gravitational force becomes so strong that it overcomes all other forces, including those that typically support the structure of matter. As a result, the core collapses to a point of infinite density called a singularity, surrounded by an event horizon from which nothing can escape, not even light.

The formation of black holes exemplifies the extreme nature of gravity and the profound effects it can have on the fabric of the universe. Understanding the processes behind black hole formation enhances our knowledge of stellar evolution, gravity's influence on massive objects, and the fundamental laws governing the cosmos.

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A 58. 0kg sailor jumps from a dock into a 28. 0kg rowboat at rest. If the velocity of the sailor is 2. 20m/s as he leaves the dock, what is the velocity of the sailor and the boat

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A 58.0 kg sailor jumps from a dock into a 28.0 kg rowboat at rest. If the velocity of the sailor is 2.20 m/s as he leaves the dock, the velocity of the sailor and the boat is 1.485 m/s.

We can use the principle of conservation of momentum. According to this principle, the total momentum before the jump is equal to the total momentum after the jump.

Before the jump, we have:

Initial momentum of the sailor = mass of the sailor × velocity of the sailor

[tex]P_s=m_s*v_s[/tex]

After the jump, the sailor and the boat move together, so their momenta add up:

Final momentum of the sailor and the boat = (mass of the sailor + mass of the boat) × velocity of the sailor and the boat

[tex]P_f=(m_s+m_b)*v_f[/tex]

Since momentum is conserved, we have:

[tex]P_s=P_f[/tex]

[tex]m_s*v_s=(m_s+m_b)*v_f[/tex]

Given:

mass of the sailor ([tex]m_s[/tex]) = 58.0 kg

velocity of the sailor ([tex]v_s[/tex]) = 2.20 m/s

mass of the boat ([tex]m_b[/tex]) = 28.0 kg

We can rearrange the equation to solve for [tex]v_f[/tex]:

[tex]v_f=(m_s*v_s)/(m_s+m_b)[/tex]

[tex]v_f=(58.0Kg *2.20m/s)/(58.0Kg+28.0Kg)\\\\v_f=1.485 m/s[/tex]

Therefore, the velocity of the sailor and the boat after the jump is approximately 1.485 m/s.

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In the absence of external force, the total momentum before a collision is _________ the total momentum after a collision

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In the absence of external force, the total momentum before a collision is equal to the total momentum after a collision.

In the absence of external force, the law of conservation of momentum states that the total momentum of a system remains constant before and after a collision. This fundamental principle is derived from Newton's third law of motion, which states that for every action, there is an equal and opposite reaction.

When two objects collide, they exert equal and opposite forces on each other, resulting in a transfer of momentum. Before the collision, the objects possess individual momenta based on their mass and velocity. The total momentum of the system is the vector sum of these individual momenta. During the collision, the objects interact and exert forces on each other, causing their momenta to change.

However, the total momentum of the system remains unchanged, as the gains and losses in momentum of individual objects cancel each other out.

Hence, the total momentum before the collision is equal to the total momentum after the collision. This principle is widely applicable in various fields, such as physics, engineering, and sports, and serves as a valuable tool in understanding and analyzing the dynamics of interacting objects.

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Sunlight travels in a straight line with a constant speed of 300,000 km/s and reaches earth in 8 minutes what is light's acceleration.

Answers

Answer:zero

Explanation:

Light always travels at a constant speed of 299,792 kilometers per second in a vacuum, and it does not have an acceleration.

Therefore, the acceleration of sunlight is zero.

The wavelength of red light is about 700 nanometers or [tex][7*10^{-7}[/tex]. The frequency of the red light reflected from a metal surface and the frequency of the vibrating electron that produces it are the same. What is this frequency?

Answers

The frequency of a wave can be calculated using the equation:

frequency (f) = speed of light (c) / wavelength (λ)

The speed of light is approximately 3 × 10^8 meters per second.

Given that the wavelength of red light is about 700 nanometers, or 700 × 10^(-9) meters, we can calculate the frequency as follows:

f = (3 × 10^8 m/s) / (700 × 10^(-9) m)

Simplifying the expression:

f ≈ 4.29 × 10^14 Hz

Therefore, the frequency of the red light reflected from the metal surface and the frequency of the vibrating electron that produces it is approximately 4.29 × 10^14 Hz.

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Halley's comet orbits the sun about every 75 years due to the gravitational force the sun provides. Compare the gravitational force between halley's Comet and the sun when the comet is at aphelion (its greatest distance from the sun) and d is about 4.5 x 10^10 m to the force at perihelion (or closest approach), where d is about 5.0 x 10^10 m. B) In part A, what is the comet's acceleration a) at aphelion? b) at perihelion? (M of the sun=1.99 x 10^30) Please help!!!

Answers

To compare the gravitational force between Halley's Comet and the Sun at aphelion and perihelion, we can use Newton's law of universal gravitation:

F = G * (m1 * m2) / r^2, where F is the gravitational force, G is the gravitational constant (approximately 6.67430 x 10^-11 N*m^2/kg^2), m1 and m2 are the masses of the two objects (in this case, the mass of the Sun and the mass of Halley's Comet), and r is the distance between the two objects. Let's calculate the gravitational force at aphelion first: F_aphelion = G * (m_Sun * m_comet) / r_aphelion^2. where m_Sun is the mass of the Sun (1.99 x 10^30 kg) and r_aphelion is the distance between the comet and the Sun at aphelion (4.5 x 10^10 m). F_aphelion = (6.67430 x 10^-11 N*m^2/kg^2) * (1.99 x 10^30 kg * m_comet) / (4.5 x 10^10 m)^2. Now, let's calculate the gravitational force at perihelion: F_perihelion = G * (m_Sun * m_comet) / r_perihelion^2, where r_perihelion is the distance between the comet and the Sun at perihelion (5.0 x 10^10 m). F_perihelion = (6.67430 x 10^-11 N*m^2/kg^2) * (1.99 x 10^30 kg * m_comet) / (5.0 x 10^10 m)^2. To calculate the comet's acceleration at aphelion and perihelion, we can use Newton's second law of motion: F = m * a, where F is the force and m is the mass of the comet. At aphelion: F_aphelion = m_comet * a_aphelion. a_aphelion = F_aphelion / m_comet At perihelion: F_perihelion = m_comet * a_perihelion. a_perihelion = F_perihelion / m_comet. To calculate the acceleration, we need to know the mass of Halley's Comet. Let's assume it's 1 kg for the sake of calculation. Now we can plug in the values and calculate the gravitational forces and accelerations at aphelion and perihelion.

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If an egg person starts from rest then falls directly downward and hits the ground with a velocity of 12 m/s but their starting height was 10 m, what would their velocity be upon hitting the ground without air resistance?

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the velocity of the egg person upon hitting the ground without air resistance would be 14 m/s. by using the kinematic equation:v² = u² + 2as,

Initial velocity, u = 0Final velocity, v = 12 m/s Distance traveled, s = 10 m Acceleration due to gravity, g = 9.8 m/s²The initial velocity of the egg person is zero. The final velocity of the egg person can be found by using the kinematic equation:v² = u² + 2as, where s is the distance travelled by the egg person from rest to final velocity.v² = 0 + 2 × 9.8 × 10v² = 196v = √196v = 14 m/s Therefore, the velocity of the egg person upon hitting the ground without air resistance would be 14 m/s.

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Therefore,  their velocity  upon hitting the ground without air resistance is 14m/s.

Velocity calculation.

According to the principle of conservation, potential energy is equal to kinetic energy.

Mgh = 1/2mv²

v =√ 2 * g* h

h = 10m

g = 9.8mls

v = √  2 * 10 * 9.8

v= √ 2 * 98

v = √ 196

the velocity v = 14mls

Therefore,  their velocity  upon hitting the ground without air resistance is 14m/s.

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Carson takes his bike down a large hill. As he is going down the hill, he squeezes on the breaks to slow his speed. When he stops at the bottom of the hill, his leg brushes against the break and it burns his leg. Construct a CER to answer the question: What caused the break to become hot?

Answers

Claim: The brakes became hot because of the friction generated between the brake pads and the bike's wheel.

Evidence: When Carson squeezed the brakes to slow down his speed while going down the hill, friction was created between the brake pads and the wheel. Friction is the resistance that opposes the motion between two surfaces in contact. The brake pads exerted a force on the rotating wheel, causing it to slow down. As a result, the kinetic energy of the moving wheel was converted into thermal energy due to the frictional forces between the brake pads and the wheel. This increase in thermal energy caused the brake pads to heat up.

Reasoning: Friction generates heat as it converts mechanical energy into thermal energy. When Carson squeezed the brakes, the friction between the brake pads and the rotating wheel caused the brake pads to heat up. The heat transferred from the brake pads to Carson's leg when it accidentally brushed against them at the bottom of the hill. This incident indicates that the heat generated by the brakes was the cause of the burns on Carson's leg.

In conclusion, the brakes became hot because of the friction generated between the brake pads and the bike's wheel. The conversion of kinetic energy into thermal energy due to the frictional forces caused the brake pads to heat up, leading to the burns on Carson's leg when it came into contact with the hot brakes.

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Indicate whether the given statement is true or false by circling the answer.


Plantation farming was very labor intensive, thereby encouraging the institution of slavery

Answers

True

Plantation farming was indeed very labor-intensive, which encouraged the institution of slavery.

Plantations, particularly in the historical context of the Americas, relied heavily on agricultural production of cash crops such as tobacco, cotton, sugar, and coffee. These crops required significant manual labor for planting, cultivating, harvesting, and processing. Due to the large-scale operations and labor-intensive nature of plantation farming, plantation owners sought to maximize profits by acquiring a cheap and abundant workforce. This led to the establishment and expansion of slavery, as enslaved individuals were forcibly brought from Africa to work on plantations. The institution of slavery was deeply intertwined with the economic structure and profitability of plantation farming, making it an integral part of the system. The labor-intensive nature of plantation farming thus played a significant role in encouraging and perpetuating slavery.

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Does it matter if the triple beam of light hits the triangle at different angles?

Answers

Yes, the angle at which the triple beam of light hits the triangle can have an impact on the behaviour of the light.

In the case of a triangle, if the light hits the triangle at different angles, it will be reflected or refracted differently depending on the angle of incidence at each point of contact. This can result in variations in the path of the light as it interacts with different parts of the triangle.

Additionally, the angle at which the light hits the triangle can affect the perception of the triangle's shape and size when observed from different viewing angles. The angle of incidence and the resulting angle of reflection or refraction can impact the apparent position and orientation of the triangle as seen by an observer.

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A banana slides down a 5 m high ramp. At the bottom of the ramp, the banana slides across a rough section of pavement where the coefficient of friction is 0.23. How far will the banana slide before coming to a stop if it started with an initial velocity of 0.5 m/s

Answers

The banana will slide a distance of 20.75 m on the pavement before coming to a stop.

we have

v² = u² + 2ghv² = 0.5² + 2 × 9.8 × 5v²

= 0.25 + 98v² = 98.25v

= √98.25v

≈ 9.91 m/s

When the banana reaches the pavement, the force of friction is responsible for the stopping of the banana.

The frictional force, f = μR

Here, R is the reaction force that acts perpendicular to the surface. So, R = mg, where m is the mass of the banana and g is the acceleration due to gravity. f = μmg

Also, the force that is responsible for stopping the banana is the frictional force, f.

So, f = ma

Here, a is the acceleration of the banana just after it leaves the ramp and starts moving on the pavement.

So, we can write,

μmg = ma

μg = a

At the instant when the banana leaves the ramp and starts moving on the pavement, its velocity is 9.91 m/s.

Therefore, using the equations of motion,

v² = u² + 2as0 = 9.91² + 2a × ss = (0 - 98.2)/2 × (-0.23)s = 20.75 m

The banana will slide a distance of 20.75 m on the pavement before coming to a stop.

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A 5 kg toy falls from a height of 3.7 m. How fast will the toy be traveling just before it hits the ground?







Velocity =

Answers

The gravitational potential energy of the toy is converted into kinetic energy as it falls.

We will utilize the law of conservation of energy to determine the velocity of the toy just before it strikes the ground, which is mgh = 1/2mv²,

where m is the mass of the toy,

h is the height from which it is falling,

g is the acceleration due to gravity, and

v is the velocity with which it hits the ground.

Using the provided figures, we get, m = 5 kg,

h = 3.7 m, and

g = 9.8 m/s².

Substitute these values in the formula. 5*9.8*3.7 = 1/2(5)v²

On solving, we get v² = 181.3 or

v = √(181.3)

V = 13.5 m/s (approx).Hence, the velocity of the toy just before it hits the ground is 13.5 m/s.

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Suppose that an object weighs 30 Newton on the
surface of the earth (a distance of R from its center). If
the same object is located a distance of 2R above the
Earth's surface (a distance of 3R from its center), then
the force of gravity upon it would be
Newton.
a. 3.33
b. 7.50
c. 10.0
d. 15.0
e. 30.0
f. 60.0
g. 90.0
h. 120.
i. 270

Answers

The force of gravity upon the object located a distance of 2R above the Earth's surface is 15 Newtons.

The correct answer is option D.

To determine the force of gravity upon an object located a distance of 2R above the Earth's surface (a distance of 3R from its center), we can use the inverse square law of gravity. The force of gravity between two objects is proportional to the product of their masses and inversely proportional to the square of the distance between their centers.

Let's assume that the mass of the object remains the same regardless of its position. The weight of an object is the force of gravity acting on it, so if the object weighs 30 Newton on the surface of the Earth (at a distance of R from its center), we can use this information to calculate the force of gravity at the new distance.

According to the inverse square law of gravity, the force of gravity (F) at a distance of 2R from the Earth's surface is given by:

F = (30 N) *[tex](R/R^2)^2[/tex]

Simplifying this equation:

F = (30 N) * (1/R)

Now, substituting the value of 2R for R:

F = (30 N) * (1/(2R))

F = 15 N/R

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A pitcher is pitched with a speed of 35 m/s if the baseball has a mass of 0. 146 kg what is its kinetic energy

Answers

According to the information we can infer that the kinetic energy of the baseball is approximately 85.68 joules.

What is the kinetic energy of the baseball?

The formula to calculate kinetic energy is

KE = 0.5 * mass * velocity².

Given:

Mass of the baseball (m) = 0.146 kgVelocity of the baseball (v) = 35 m/s

Plugging these values into the formula, we have:

KE = 0.5 * 0.146 kg * (35 m/s)²

Simplifying the equation:

KE = 0.5 * 0.146 kg * 1225 m²/s²KE ≈ 85.68 joules

According to the above, the kinetic energy of the baseball is approximately 85.68 joules.

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The certain region of the electric field is (1) - 5) × 10+5 N is present. Through an area of
(3% - 37) × 10+2cm? the electric flux is

Answers

Simplifying the expression,

Electric flux (Φ) = (1) - 5) × 10+5 N * (3% - 37) × 10^-2 m²

To calculate the electric flux through a given area, we need to multiply the electric field strength by the area and by the cosine of the angle between the electric field and the normal to the area.

Given:

Electric field strength (E) = (1) - 5) × 10+5 N

Area (A) = (3% - 37) × 10+2 cm²

First, we need to convert the given values to the appropriate SI units:

1 cm² = 10^-4 m²

1 N = 1 kg·m/s²

Area (A) = (3% - 37) × 10^-2 m²

Next, we can calculate the electric flux using the formula:

Electric flux (Φ) = E * A * cosθ

Since the angle (θ) between the electric field and the normal to the area is not given, we assume that the electric field is perpendicular to the area, resulting in θ = 0 degrees. In this case, cosθ = 1.

Electric flux (Φ) = (1) - 5) × 10+5 N * (3% - 37) × 10^-2 m² * 1

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there’s 30g/L of salt in salted water, and in unsalted water there’s 1g/L of salt how much water are you going to ADD to make a 20 ml container of salted water unsalted? use C1V1=C2V2

Answers

Answer:

Water ADD to make a 20 ml container of salted water unsalted is 620 mL

Explanation:

To make a 20 mL container of salted water unsalted using the formula C1V1 = C2V2, we can calculate the volume of water (V2) that needs to be added.

V2 = (C1V1) / C2

V2 = (30 g/L * 20 mL) / 1 g/L

V2 = 600 mL

It is important to consider the final total volume of the solution after adding the water, which would be 20 mL (initial volume) + 600 mL (volume of water added) = 620 mL.

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A 3kg Snickers candy bar is dropped off the top of the Washington Monument. If the Monument is 170m tall, how fast does the Snickers hit the ground? (this is the orignal question)


The Snickers bar actually lands with a speed of 52m/s. How much energy was lost so air resistance?

Answers

To determine the amount of energy lost due to air resistance, we can use the principle of conservation of mechanical energy. Initially, the Snickers bar has gravitational potential energy, and upon hitting the ground, it has kinetic energy.

The gravitational potential energy (PE) of an object is given by the equation:

PE = m * g * h

Where:

m is the mass of the object (3 kg)

g is the acceleration due to gravity (approximately 9.8 m/s^2)

h is the height of the Washington Monument (170 m)

Calculating the potential energy, we have:

PE = 3 kg * 9.8 m/s^2 * 170 m

PE = 4998 J (joules)

At the moment of impact, all the potential energy is converted into kinetic energy, given by:

KE = 1/2 * m * v^2

Where:

m is the mass of the object (3 kg)

v is the velocity at impact (52 m/s)

Calculating the kinetic energy, we have:

KE = 1/2 * 3 kg * (52 m/s)^2

KE = 4056 J (joules)

The energy lost due to air resistance is the difference between the initial potential energy and the final kinetic energy:

Energy Lost = PE - KE

Energy Lost = 4998 J - 4056 J

Energy Lost = 942 J (joules)

Therefore, the amount of energy lost due to air resistance is 942 joules.

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1)A solution said to be super saturated if
a)It can dissolve more solute at that temperature
b) It cannot dissolve more salute at that temperature
c) It contains more solute dissolved than in saturated solution at that temperature d) It's solubility is zero

2) 27 gm of saturated solution of NaCl at 20°C when evaporated to dryness leaves a solid residue of 7 gm. Calculate the solubility of NaCl at 20°C.
a) 25.92 b)35 c)28.57 d)285.7

3) The process of transformation of nitrogen to nitrates of ammonia is
a) Nitrogen fixation
b) Nitrification.
c)Ammonification.
d) Denitrification

4)When TanA=1
a) sinA-cosA=tanA
b)sinA-cosA=0
c)tanA=sinA
d)tanA=cosA

5)What is the difference between the arithmetic mean and geometric mean between 3 and 27 is
a)15
b)6
c) 12
d)0

6) If a+ib =0 then
a) a =0, bGO
b)aGO, bGO
c)a=0, b=0
d) All​

Answers

1) c) It contains more solute dissolved than in a saturated solution at that temperature.

2) To calculate the solubility of NaCl at 20°C, we need to divide the mass of NaCl dissolved in the saturated solution by the mass of the solvent (water) in the solution.

Solubility = Mass of solute (NaCl) / Mass of solvent (water)

Given:

Mass of saturated solution = 27 gm

Residue after evaporation = 7 gm

Mass of NaCl dissolved = Mass of saturated solution - Residue after evaporation

= 27 gm - 7 gm

= 20 gm

Solubility = 20 gm / 27 gm

Using a calculator, the solubility of NaCl at 20°C is approximately 0.7407 or 28.57% (rounded to two decimal places).

Therefore, the answer is c) 28.57.

3) a) Nitrogen fixation.

Nitrogen fixation is the process by which atmospheric nitrogen (N2) is converted into a usable form, such as ammonia (NH3) or nitrates (NO3-). This process is primarily carried out by nitrogen-fixing bacteria, which convert nitrogen gas into ammonia through biological or industrial processes.

4) a) sinA - cosA = tanA

Given that tanA = 1, we can substitute tanA into the equation:

sinA - cosA = 1

5) The arithmetic mean is the average of two numbers, while the geometric mean is the square root of their product.

The arithmetic mean between 3 and 27 is (3 + 27) / 2 = 30 / 2 = 15.

The geometric mean between 3 and 27 is √(3 × 27) = √81 = 9.

The difference between the arithmetic mean and geometric mean is 15 - 9 = 6.

Therefore, the answer is b) 6.

6) c) a = 0, b = 0.

If a + ib = 0, it implies that both the real part (a) and the imaginary part (b) are zero.

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In areas with large numbers of phytoplankton, there are also large numbers of fish, marine mammals, and other animals. For example, the west coast of the U. S. Has many fisheries due to the large numbers of phytoplankton in those waters. What provides the energy to support so many animals in these areas?

Answers

The energy to support a large number of animals in areas with abundant phytoplankton comes from the primary production of phytoplankton through photosynthesis, forming the basis of the marine food web.

The large numbers of animals in areas with abundant phytoplankton are supported by the energy derived from the process of photosynthesis. Phytoplankton are microscopic algae that contain chlorophyll and other pigments, allowing them to convert sunlight, carbon dioxide, and nutrients into organic matter through photosynthesis. This primary production by phytoplankton forms the foundation of the food web in marine ecosystems.As phytoplankton grow and reproduce, they become a rich source of energy and nutrients for other organisms. Zooplankton, which are small marine animals, feed on phytoplankton, and in turn, become food for larger organisms such as fish and marine mammals. This transfer of energy and nutrients continues up the food chain, supporting the entire ecosystem. The high productivity of phytoplankton in certain areas, such as the west coast of the U.S., can be attributed to various factors. These factors include nutrient availability, sunlight exposure, and oceanographic conditions that promote upwelling, bringing nutrient-rich deep waters to the surface. The combination of these factors creates favorable conditions for phytoplankton growth, resulting in an abundance of energy to support diverse and thriving marine ecosystems.

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Tim was walking at a speed of 6 miles/hr on his way to Chipotle at 5 PM. He ordered his food and headed back at a rate of 14 miles/hr at 6 PM. What was his total acceleration?



8 m/hr/hr


12m/hr/hr


6 m/hr/hr


14 m/hr/hr

Answers

To calculate the total acceleration, we need to determine the change in velocity and the time it took for that change to occur. Thus, option a) 8 m/hr/hr is the correct answer.

In this scenario, Tim initially walks to Chipotle at a speed of 6 miles/hr. At 6 PM, he heads back at a speed of 14 miles/hr. The change in velocity can be calculated by subtracting the initial velocity from the final velocity: 14 miles/hr - 6 miles/hr = 8 miles/hr.

To find the time it took for this change in velocity, we need to consider the time elapsed between Tim's departure and return. Since Tim started walking at 5 PM and returned at 6 PM, the time interval is 1 hour.

Acceleration is defined as the change in velocity divided by the time interval. Therefore, the total acceleration is 8 miles/hr divided by 1 hour, which gives us an acceleration of 8 m/hr/hr.

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Find the missing side in each triangle using any method. Check your answers using a different method. Show your work or explain your thinking.

Answers

To find the missing side in each triangle, we need more information or measurements. Without specific values for the angles or sides of the triangles, we cannot determine the missing side lengths.

To find the missing side in a triangle, we typically use trigonometric ratios such as sine, cosine, or tangent. However, in this case, the problem statement does not provide any angles or side lengths for the triangles. Without these measurements, it is impossible to determine the missing side lengths. We need specific values to apply trigonometric ratios or other geometric properties to solve the problem accurately.  Without specific values for the angles or sides of the triangles, we cannot determine the missing side lengths.

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CHARLES' LAW


Solve:


At 190 K and constant pressure, a sample of gas has a volume of 32 cm? What


volume does the gas occupy at 250 K?


Show your work below and put the answer in the yellow box.

Answers

The volume of the gas at 250 K is approximately 42.105 cm³. Charles' Law, also known as the law of volumes, describes the relationship between the volume and temperature of a gas at constant pressure.

To solve this problem using Charles' Law, we can use the formula:

V1 / T1 = V2 / T2

where V1 and T1 are the initial volume and temperature, and V2 and T2 are the final volume and temperature.

Given:

V1 = 32 cm³ (initial volume)

T1 = 190 K (initial temperature)

T2 = 250 K (final temperature)

We can rearrange the formula to solve for V2:

V2 = (V1 * T2) / T1

Substituting the given values into the equation, we get:

V2 = (32 cm³ * 250 K) / 190 K

Calculating this expression, we find:

V2 ≈ 42.105 cm³

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