A student is ordering a flower arrangement. She can choose any combination of tulip and carnations for her flower arrangement , and she does not want to spend more than $45. If tulip cost $5 each and carnations cost $3 each, which inequality represents all possible combinations of x tulips and y carnations ? A. 5x + 3y < 45 B. 5x + 3y <= 45 C. 3x + 5y > 45 3x + 5y <= 45
Helppp!

Answers

Answer 1

Answer:

[tex]5x+3x \leq 45[/tex] represents all possible combinations of x tulips and y carnations

Step-by-step explanation:

We are supposed to find inequality represents all possible combinations of x tulips and y carnations

Cost of 1 tulip = $5

Cost of x tulips = 5x

Cost of 1 carnation =$3

Cost of y carnations = 3y

We are given that she does not want to spend more than $45.

So, She can spend less than or equal to 45

So, required inequality :[tex]5x+3x \leq 45[/tex]

So, Option B is true

[tex]5x+3x \leq 45[/tex] represents all possible combinations of x tulips and y carnations

Answer 2

Answer:

it would be 5x + 3y <= 45

Step-by-step explanation:

I literally just did this question on my math homework and I got it right .


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Answer:

y = -2x - 8

Step-by-step explanation:

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~ an aesthetics lover

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(fog)(x)=18x+1029x+1. (gof)(x)=27x+87x−8. Explanation: Given: f(x)=3x−12x+5 and g(x)=7x+33x−1. Solution for (fog)(x).

Step-by-step explanation:

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Step-by-step explanation:

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Step-by-step explanation:

I'll explain why.

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Step-by-step explanation:

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Step-by-step explanation:

Answer:

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Step-by-step explanation:

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Answers

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Step-by-step explanation:

That's the most common number there

Answer:

9

Step-by-step explanation:

The mode of a set of data values is the value that appears most often.

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If you have a cubic polynomial of the form y = ax^3 + bx^2 + cx + d and lets say it passes through the points (2,28), (-1, -5), (4, 220), and (-2, -20) what would the coefficients a, b, c, and d equal? So confused, I'd greatly appreciate help! Thank you!

Answers

Step-by-step explanation:

Step 1:  Solve using the first point

(2, 28)

[tex]28 = a(2)^3 + b(2)^2 + c(2) + d[/tex]

[tex]28 = 8a + 4b + 2c + d[/tex]

Step 2:  Solve using the second point

(-1, -5)

[tex]-5 = a(-1)^3 + b(-1)^2 + c(-1) + d[/tex]

[tex]-5 = -a + b - c + d[/tex]

Step 3:  Solve using the third point

(4, 220)

[tex]220 = a(4)^3 + b(4)^2 + c(4) + d[/tex]

[tex]220 = 64a + 16b + 4c + d[/tex]

Step 4:  Solve using the fourth point

(-2, -20)

[tex]-20 = a(-2)^3 + b(-2)^2 + c(-2) + d[/tex]

[tex]-20 = -8a + 4b - 2c + d[/tex]

Step 5:  Combine the first and fourth equations

[tex]28 - 20 = 8a - 8a + 4b + 4b + 2c - 2c + d + d[/tex]

[tex]8 = 8b + 2d[/tex]

[tex]8 - 8b = 8b - 8b + 2d[/tex]

[tex](8 -8b)/2 = 2d/2[/tex]

[tex]4 - 4b = d[/tex]

Step 6:  Solve for c in the second equation

[tex]-5 + 5 = -a + b - c + d + 5[/tex]

[tex]0 + c = -a + b - c + c + d + 5[/tex]

[tex]c = -a + b + d + 5[/tex]

Step 7:  Substitute d with the stuff we got in step 5

[tex]c = -a + b + (4 - 4b) + 5[/tex]

[tex]c = -a + b + 4 - 4b + 5[/tex]

[tex]c = -a - 3b + 9[/tex]

Step 8:  Substitute d and c into the first equation

[tex]28 = 8a + 4b + 2(-a - 3b + 9) + (4 - 4b)[/tex]

[tex]28 = 8a + 4b - 2a - 6b + 18 + 4 - 4b[/tex]

[tex]28 - 22 = 6a - 6b + 22 - 22[/tex]

[tex]6 / 6 = (6a - 6b) / 6[/tex]

[tex]1 + b = a - b + b[/tex]

[tex]1 + b = a[/tex]

Step 9:  Substitute a, b, and c into the third equation

[tex]220 = 64(1 + b) + 16b + 4(-(1 + b) - 3b + 9) + (4 - 4b)[/tex]

[tex]220 = 64 + 64b + 16b + 4(-1 - b - 3b + 9) + 4 - 4b[/tex]

[tex]220 - 100 = 60b + 100 - 100[/tex]

[tex]120 / 60 = 60b / 60[/tex]

[tex]2 = b[/tex]

Step 10:  Find a using b = 2

[tex]a = b + 1[/tex]

[tex]a = (2) + 1[/tex]

[tex]a = 3[/tex]

Step 11:  Find c using a = 3 and b = 2

[tex]c = -a - 3b + 9[/tex]

[tex]c = -(3) - 3(2) + 9[/tex]

[tex]c = -3 - 6 + 9[/tex]

[tex]c = 0[/tex]

Step 12:  Find d using b = 2

[tex]d = 4 - 4b[/tex]

[tex]d = 4 - 4(2)[/tex]

[tex]d = 4 - 8[/tex]

[tex]d = -4[/tex]

Answer:  [tex]a = 3, b = 2, c = 0,d = -4[/tex]

Answer:

a = 3

b = 2

c = 0

d = -4

Step-by-step explanation:

Form 4 equations and solve simultaneously

28 = a(2)³ + b(2)² + c(2) + d

28 = 8a + 4b + 2c + d (1)

-5 = -a + b - c + d (2)

220 = 64a + 16b + 4c + d (3)

-20 = -8a + 4b - 2c + d (4)

(1) + (4)

28 = 8a + 4b + 2c + d

-20 = -8a + 4b - 2c + d

8 = 8b + 2d

d = 4 - 4b

Equation (2)

c = -a + b + d + 5

c = -a + b + 4 - 4b+ 5

c = -a - 3b + 9

28 = 8a + 4b + 2c + d (1)

28 = 8a + 4b + 2(-a - 3b + 9) + 4 - 4b

28 = 6a - 6b + 22

6a - 6b = 6

a - b = 1

a = b + 1

220 = 64a + 16b + 4c + d (3)

220 = 64(b + 1) + 16b + 4(-b - 1 - 3b + 9) + 4 - 4b

220 = 60b + 100

60b = 120

b = 2

a = 2 + 1

a = 3

c = -3 - 3(2) + 9

c = 0

d = 4 - 4(2)

d = -4

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Answer:

investment 2 $400 Simple Interest Rate

Step-by-step explanation:

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Answers

I am pretty sure that four would equal 59 degrees because 60+61 equals 121 degrees and that line should in total equal 180. So you would do 180-121 which gives you 59.

can someone help me please?

Answers

Answer:

(10,11)

(8,7)

(6,3)

(4,-1)

(2,-5)

(0,-9)

(-2,-13)

(-4,-17)

Answer: the image of how its supposed to be graphed is listed down below! hope this helped!

Step-by-step explanation:

The graph of a function f is the set of all points in the plane of the form (x, f(x)). We could also define the graph of f to be the graph of the equation y = f(x). So, the graph of a function if a special case of the graph of an equation.

In a group of 30 people, 10 drink milk but not tea 5 drink tea
but not milk and 13 drink neither tea nor milk. find how many people drink both tea and milk.​

Answers

Answer:

2

Step-by-step explanation:

10 + 13 + 5 = 28 who drink either, or, or neither

30 - 28 = 2

Answer:

2 drink both tea and milk

Step-by-step explanation:

30 people - 13 drink neither = 17 - 10 drink milk but not tea = 7 - 5 drink tea but not milk = 2 drink both tea and milk.

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