Answer:
grade point average (GPA) as a weighted mean = 3.14
Yes, student makes the Dean's list.
Step-by-step explanation:
Since the data is not given I will explain the question with a relevant example:
For example
Data:
Students grades are: A, C, B, A, D
The corresponding number of credit hours: 3, 3, 3, 4, 1
The grading system assigns quality points to letter grades as:
A = 4
B = 3
C = 2
D = 1
F = 0
To find:
grade point average (GPA) as a weighted mean
If the Dean's list requires a GPA of 3.00 or greater, did this student make the Dean's list?
Solution:
Weighted Mean = Σx[tex]_{i}[/tex] w[tex]_{i}[/tex] / Σw[tex]_{i}[/tex]
Here
Using the earned grades of A, C, B, A, D and corresponding quality points to these letter grades we get:
A = 4
C = 2
B = 3
A = 4
D = 1
So the values in x[tex]_{i}[/tex] are:
x
4
2
3
4
1
Now the number of credit hours are represented as weights w[tex]_{i}[/tex] :
w
3
3
3
4
1
In order to calculate weighted mean first multiply x[tex]_{i}[/tex] with w[tex]_{i}[/tex]
x[tex]_{i}[/tex] w[tex]_{i}[/tex]
4 * 3 = 12
2 * 3 = 6
3 * 3 = 9
4 * 4 = 16
1 * 1 = 1
The sum of x[tex]_{i}[/tex] w[tex]_{i}[/tex] is :
Σx[tex]_{i}[/tex] w[tex]_{i}[/tex] = 12 + 6 + 9 + 16 + 1 = 44
Σx[tex]_{i}[/tex] w[tex]_{i}[/tex] = 44
Now compute the sum of w[tex]_{i}[/tex]
Σw[tex]_{i}[/tex] = 3 + 3 + 3 + 4 + 1 = 14
Σw[tex]_{i}[/tex] = 14
Putting the values in the weighted mean formula:
Weighted Mean = Σx[tex]_{i}[/tex] w[tex]_{i}[/tex] / Σw[tex]_{i}[/tex]
= 44 / 14
= 3.1429
Weighted Mean = Σx[tex]_{i}[/tex] w[tex]_{i}[/tex] / Σw[tex]_{i}[/tex] = 3.14
Since the Dean's list requires a GPA of 3.00 or greater and the grade point average (GPA) as a weighted mean of the student is 3.14 so the student makes the Dean's list because his/her GPA is higher than 3.00
solve 4w–3w+2w=24
Please
We need to simplify the left side first.
On the left side, all the terms can be combined.
So 4w - 3w + 2w is 3w.
So we have 3w = 24.
Next, dividing both sides by 3, we have w = 8.
So our solution is w = 8.
Answer
[tex] \boxed{ \huge{ \bold{ \sf{ \boxed{w = 8}}}}}[/tex]
Step by step explanation
[tex] \sf{4w - 3w + 2w = 24}[/tex]
Collect like terms
⇒[tex] \sf{w + 2w = 24}[/tex]
⇒[tex] \sf{3w = 24}[/tex]
Divide both sides of the equation by 3
⇒[tex] \sf{ \frac{3w}{3} = \frac{24}{3} }[/tex]
Calculate
⇒[tex] \sf{w = 8}[/tex]
Hope I helped!
Best regards!!
You pull one card at random from a standard deck and you shuffle the remaining cards. Then you pull another card. Is the event independent or dependent?
Answer:
If an event is affected by previous events then it is a dependent event, while if an event is not affected by the previous event then it is an independent event.
Since we have replaced the card that we first drew from the deck, it wont affect the event of pulling a card second time.
So, we can say that it is an example of independent event.
Describe the relationship between quartiles and percentiles. ▼ are special cases of ▼ ▼ Upper Q 2 Upper Q 3 Upper Q 1 is the 25th percentile, ▼ Upper Q 2 Upper Q 1 Upper Q 3 is the 50th percentile, and ▼ Upper Q 2 Upper Q 3 Upper Q 1 is the 75th percentile.
Answer:
Q1 is the 25th percentile
Step-by-step explanation:
Quartiles are known to be one-fourth of an entity, that is, 1/4th with the whole evaluating to 1. The numerator cannot exceed four, as the division compares an item in an entity to the whole of the entity or sample.
Percentiles represents a whole entity as a 100 with the symbol "%" which denote its use.
The first quartile is 25th percentile, the second is the 50th percentile, the third is the 75th percentile while the fourth quartile which is 4/4 is the 100th percentile mark.
4. The rental for a television set changed from $80 per year to $8 per month
What is the percentage increase in the yearly rental?
Answer:
16%
Step-by-step explanation:
rental charge per year = $80
rental charge at the rate $8 per year = 8 * 12 = 96
the increased amount = 96 - 80 = 16
% = 16 / 100 = 16%
Point Q is on line segment PR. Given QR=11 and PQ=3, determine the length PR.
Answer:
[tex]\huge \boxed{14}[/tex]
Step-by-step explanation:
Q is a point on the line segment PR.
PQ = 3
QR = 11
PR = PQ + QR
PR = 3 + 11 = 14
Answer:
[tex]\huge\boxed{PR = 14}[/tex]
Step-by-step explanation:
QR = 11
PQ = 3
Given that Q is on line segmant PR
So,
PR = PQ + QR
PR = 3 + 11
PR = 14
(8x 2 −15x)−(x 2 −27x)=ax 2 +bxleft parenthesis, 8, x, squared, minus, 15, x, right parenthesis, minus, left parenthesis, x, squared, minus, 27, x, right parenthesis, equals, a, x, squared, plus, b, x If the equation above is true for all values of xxx, what is the value of b-ab−ab, minus, a ?
Answer:
5Step-by-step explanation:
Given the expression (8x² −15x)−(x² −27x) = ax² +bx, we are to determine the value of b-a. Before we determine the vwlue of b-a, we need to first calculate for the value of a and b from the given expression.
On expanding the left hand side of the expression we have;
= (8x² −15x)−(x² −27x)
Open the paranthesis
= 8x² −15x−x²+27x
collect the like terms
= 8x²−x²+27x −15x
= 7x²+12x
Comparing the resulting expression with ax²+bx
7x²+12x = ax²+bx
7x² = ax²
a = 7
Also;
12x = bx
b =12
The value of b - a = 12 - 7
b -a = 5
Hence the value of b-a is equivalent to 5
The value of b minus a is 5
Calculation of the value:Since the expression is
[tex](8x^2 -15x)-(x^2 -27x) = ax^2 +bx[/tex]
Here we have to expand the left-hand side of the expression so it should be like
[tex]= (8x^2 -15x)-(x^2 -27x)\\\\= 8x^2 -15x-x^2+27x\\\\= 8x^2-x^2+27x -15x\\\\= 7x^2+12x[/tex]
Now
[tex]7x^2+12x = ax^2+bx\\\\7x^2 = ax^2[/tex]
a = 7
Also;
12x = bx
b =12
So,
The value of b - a = 12 - 7
b -a = 5
Hence the value of b-a should be 5
Learn more about equation here: https://brainly.com/question/24540444
5
What is the equation, in point-slope form, of the line that
is parallel to the given line and passes through the point
(-3, 1)?
4
3
2
(-3, 1)
42.27
1
5 4 3 2 1
2 3 4 5 x
y-1=-{(x+3)
y-1=-{(x + 3)
y-1= {(x + 3)
y-1= {(x + 3)
(-2, 4)
Answer: [tex]y-1=\dfrac32(x+3)[/tex]
Step-by-step explanation:
Slope of a line passes through (a,b) and (c,d) = [tex]\dfrac{d-b}{c-a}[/tex]
In graph(below) given line is passing through (-2,-4) and (2,2) .
Slope of the given line passing through (-2,-4) and (2,2) =[tex]\dfrac{-4-2}{-2-2}=\dfrac{-6}{-4}=\dfrac{3}{2}[/tex]
Since parallel lines have equal slope . That means slope of the required line would be .
Equation of a line passing through (a,b) and has slope m is given by :_
(y-b)=m(x-a)
Then, Equation of a line passing through(-3, 1) and has slope = is given by
[tex](y-1)=\dfrac32(x-(-3))\\\\\Rightarrow\ y-1=\dfrac32(x+3)[/tex]
Required equation: [tex]y-1=\dfrac32(x+3)[/tex]
Evaluate |3 - 5 + 7|. -5 5 -15 15
Answer:
5
Step-by-step explanation:
|3 - 5 + 7|
= |-2 + 7|
= |5| = 5
Answer:
The correct answer would be 5.
Step-by-step explanation:
u and v are position vectors with terminal points at (-1, 5) and (2, 7), respectively. Find the terminal point of -2u + v.
==================================================
Work Shown
We'll be using these vector properties
Rule 1: (a,b) + (c,d) = (a+c, b+d)Rule 2: k*(a,b) = (k*a, k*b)To get the following
-2u + v = -2*(-1, 5) + (2,7)
-2u + v = (-2*(-1), -2*5) + (2,7) .... apply rule 2
-2u + v = (2, -10) + (2, 7)
-2u + v = (2+2, -10+7) .... use rule 1
-2u + v = (4, -3)
What is the area of this composite figure?
Answer:
C.) 7.14 in²
Step-by-step explanation:
The figure is made up of a square and a circle. The circle is divided in half and each piece is set on one side of the square. This means that the diameter of the circle is equal to the length of the sides of the square, 2 inches.
The area of the square can be found by multiplying length times the width:
[tex]2*2=4[/tex]
The area of the square is 4 inches, and since we multiplied two lengths, we square the value:
A=4in²
Now find the area of the circle using the formula:
[tex]A=\pi r^2[/tex]
The radius is half of the diameter, so the radius is 1. Insert values and solve:
[tex]A=\pi *1^2\\\\A=\pi *1\\\\A=\pi[/tex]
The area of the circle is equal to π. Add the values together:
[tex]4+\pi =7.14[/tex]
The area of the figure is 7.14 in²
:Done
5 diferrent representations of the value 3
Answer:
3
= 15/5
= [tex]\sqrt[3]{27}[/tex]
= 1.5*2
= 3/1
= 3*1
= 3¹
= 1/3⁻¹
= 3⁴ / 3³
= 3⁵ * 3⁻⁴
Can Someone help ill rate brainliest!!
Answer:
2
Step-by-step explanation:
Let Ishan’s age equal an unknown quantity we’ll call “x”.
An age 4 times Ishan’s would be 4 times x, written “4x”.
An age 6 years older than Ishan’s would be written “x+6”.
Now, through the magic of algebra, we can write an equation: 4x = x+6 . This means that “four times Ishan’s age is equal to his age plus six.”
The magic continues: you can subtract an”x” from each side of the equation. You can subtract any quantity from either side, but subtracting”x” will leave 6 on the right and “3x” on the left: 3x = 6.
Divide both sides by the same quantity: 3.
This will give you x =2. This indicates Ishan’s age is 2.
Answer:
Ishaan is 2 years old.
Step-by-step explanation:
We can create a systems of equations for this, assuming b is Ben's age and i is Ishaan's age.
[tex]b = 4i[/tex]
[tex]b = i+6[/tex]
Let's solve via substitution.
[tex]4i = i+6[/tex]
Subtract i from both sides:
[tex]3i = 6[/tex]
Divide both sides by 3:
[tex]i = 2[/tex]
So Ishaan is 2 years old. Ben is:
[tex]4(2) = 8[/tex] years old.
Hope this helped!
Ifx= 15t2 and y= 10t2, find dy by
dx
Answer:
2/3
Step-by-step explanation:
dy/dx equals derivative of y by x
dy/dx=20t/30t=2/3
Point E is on line segment DF. Given DE=9 and DF=11, determine the length EF.
Answer:
EF = 2 units
Step-by-step explanation:
Given:
Line segment DF and point E on it.
DF = 11 unit
DE = 9 Unit
Find:
EF
Computation:
We know that,
DF = DE + EF
11 = 9 + EF
EF = 11-9
EF = 2 units
What is the volume of this rectangular prism?
4/3
4/3
4/3
Answer:
[tex]\frac{64}{27}[/tex] cm³
Step-by-step explanation:
The volume (V) of the prism is calculated as
V = lbh ( l is length, b is breadth and h is height ), thus
V = [tex]\frac{4}{3}[/tex] × [tex]\frac{4}{3}[/tex] × [tex]\frac{4}{3}[/tex] = [tex]\frac{4^3}{3^3}[/tex] = [tex]\frac{64}{27}[/tex] cm³
Answer:
64/27 would be your answer.Step-by-step explanation:
I am more than happy to answer anymore questions. If needed an explanation I can put one in the comments.
5 - (4 - 3x) = 10
how would u distubute in this problem
Answer:
x = 3
Step-by-step explanation:
Given
5 - (4 - 3x) = 10 ← distribute the terms in the parenthesis by - 1
5 - 4 + 3x = 10, that is
1 + 3x = 10 ( subtract 1 from both sides )
3x = 9 ( divide both sides by 3 )
x = 3
This event is independent, true or false?
There are eight shirts in your closet, four blue and four green. You randomly select one to wear on Monday and then a different one on Tuesday.
Answer:
False
Step-by-step explanation:
Because the question says you pick a different shirt on Tuesday than on Monday, that means you have one less shirt you can select, so the event is dependent.
In a right angled triangle ABC, ACB =30 and AC=10cm a. calculate BAC b. calculate line AB
Answer:
10 cm is the answer because 30÷3 angles
circle the volume in cm^3 of a cylinder with the radius 5cm and height 8cm
Answer:
628 [tex]cm^{3}[/tex]
Step-by-step explanation:
Since the formula to find the volume of a cylinder is [tex]\pi r^{2}[/tex]h, we just need to fill things in.
Since the radius is 5 and the height is 8 and we know that pi=3.14, our new equation is:
3.14*5^2*8.
5*5=25. Now we simplify.
3.14 * 25 * 8
78.5 * 8
628 [tex]cm^{3}[/tex]
Hope this helps!! <3 :)
Answer:
628.32
Step-by-step explanation: googled it lol
Please answer this question now
Step-by-step explanation:
Hi, there!!!
Here, the question is about the volume of cone,
given that,
diameter = 12m
radius of a circle= 12m/2= 6m
height (h)=9 m
now, we have,
volume of a cone= 1/3×pi× r^2×h
or, v= 1/3×3.14×(6)^2×9
After simplifying it we get,
v= 339.12 m^3
Hope it helps....
An octagonal pyramid ... how many faces are there, how many vertices and how many edges? A triangular prism ... how many faces are there, how many vertices and how many edges? a triangular pyramid ... how many faces are there, how many vertices and how many edges?
1: 8 faces and 9 with the base 9 vertices and 16 edges
2: 3 faces and 5 with the bases 6 vertices and 9 edges
3: 3 faces and 4 with the base 4 vertices and 6 edges
Answer:.
Step-by-step explanation:.
(2a-b)2-(a-2b)2 factorial
Hello, we know that for a and b real numbers
[tex]a^2-b^2=(a-b)(a+b)[/tex]
So,
[tex](2a-b)^2-(a-2b)^2=(2a-b-a+2b)(2a-b+a-2b)\\\\=(a+b)(3a-3b)\\\\\boxed{=3(a+b)(a-b)}[/tex]
Thank you.
What is the distance between (-6, 2) and (8,10) on a coordinate grid?
Answer:
A. 260
Step-by-step explanation:
Answer:
square root 260
Step-by-step explanation:
On mine it is D. but the answer is the square root of 260
Suppose triangle TIP and triangle TOP are isosceles triangles. Also suppose that TI=5, PI=7, and PO=11. What are all the possible lengths TO? Enter the possible values, separated by commas.
===========================================
Explanation:
Refer to the diagram below.
In order for triangle TOP to be isosceles, the missing side x must be either 5 or 7. This way we have exactly two sides that are the same length.
--------
If TP = 5, then the value of y could be either 5 or 11 to ensure that triangle TIP has exactly two sides the same length.
If TP = 7, then y = 7 or y = 11 for similar reasons.
--------
Therefore, the possible lengths for segment TO are 5, 7, and 11.
Answer:
7, 11
Step-by-step explanation:
its right- trust me-
Mrs. Yadav purchase 25 kg of vegetable at Rs 20 per kg and sold at a loss of Rs 50 find her
Selling rate and loss percent
Answer:
[tex] \boxed{loss\% \: = 10\%}[/tex][tex] \boxed{selling \: price = Rs 450}[/tex]Step-by-step explanation:
Given,
Cost price of 25 kg of vegetables ( CP ) = 25 × 20
= Rs 500
Loss amount = Rs 50
Selling price ( SP ) = ?
Loss percent = ?
Now, let's find the loss percent :
[tex] \mathsf{ \frac{loss}{cost \: price} \times 100\%}[/tex]
[tex] \mathsf{ = \frac{50}{500} \times 100\%}[/tex]
[tex] \mathsf{ = 10\%}[/tex]
Loss % = 10 %
Now, let's find the selling price:
[tex] \mathsf{ \frac{CP(100 - l\%)}{100} }[/tex]
[tex] \mathsf{ = \frac{500(100 - 10)}{100}} [/tex]
[tex] \mathsf{ = \frac{500 \times 90}{100} }[/tex]
[tex] \mathsf{ = \frac{45000}{100} }[/tex]
[tex] \mathsf{= 450}[/tex]
Hope I helped!
Best regards!
Find the derivative of f(x) = -2x2 + 11x at x = 9.
Answer:
The value of the derivative at x = 9 is -25
Step-by-step explanation:
Here in this question, we are told to find the derivative of the given equation at the point where x = 9
What we need to do here is simply, differentiate f(x), then substitute that value x = 9 into the differentiated equation
In notation form, what we are to find is f’(9)
So;
f(x) = -2x^2 + 11x
f’(x) = -4x + 11
So therefore;
f’(9) = -4(9) + 11
f’(9) = -36 + 11
f’(9) = 11-36
f’(9) = -25
Please Answer THIS QUESTION ASAP ty!! First 2 answer right is BRAINLESS
Hi there! :)
Answer:
[tex]\huge\boxed{A = 119.44 cm^{2} }[/tex]
To find the area of the shaded region, we will need to find the areas of both the rectangle and the circle:
Rectangle: A = l × w
A = 11 × 12
A = 132 cm²
Circle: A = πr² (Let π = 3.14)
A = π(2)²
A = 4π
A ≈12.56 cm²
Subtract the area of the circle from the area of the rectangle:
132 - 12.56 = 119.44 cm².
find the perimeter of the quadrant whose radius is 21cm
Answer:
75 cm
Step-by-step explanation:
∅=90° , r = 21 cm
Arc length= (2πr∅)/360
=(2π×21×90)/360
=33 cm
Perimeter= arc length + 2(radius)
=33+2(21)
=33 + 42
= 75 cm
Given: -1/2x > 6. Choose the solution set. A {x | x R, x > -12} B{x | x R, x > -3} C{x | x R, x < -3}D {x | x R, x < -12}
Answer:
D
Step-by-step explanation:
-1/2x > 6 (you have to flip the sign when you multiply or divide by negative
x < -12
Pls help me , idk how to do
Answer:
PQRS is a parallelogram with right-angle corners
Step-by-step explanation:
We know that the midsegment of a triangle is parallel to the base.
QR is the midsegment of triangle BCD, so is parallel to BD.
SP is the midsegment of triangle DAB, so is parallel to BD.
QR and SP are both parallel to BD, so are parallel to each other.
RS is the midsegment of triangle CAD, so is parallel to AC.
PQ is the midsegment of triangle ABC, so is parallel to AC.
RS and PQ are both parallel to AC, so are parallel to each other.
__
We have shown that opposite sides of PQRS are parallel to each other, so the figure is at least a parallelogram.
__
By virtue of the congruence of corresponding angles where a transversal crosses parallel lines, each of the so-far named lines can be shown to be perpendicular to any of the lines it meets.* Hence the figure PQRS must be a parallelogram with right angles, a rectangle.
_____
* Transversal BD crosses PQ, AC, and RS at right angles. Hence, transversals RS and PQ cross QR, BD, and SP at right angles. That is, the angles at corners P, Q, R, and S of the parallelogram are right angles.
