Answer: 54.88 meters/s
Explanation:
The final velocity will be calculated by using the formula:
v = u + at
where,
v = final velocity
u = initial velocity = 0
a = 9.8
t = 5.6
Therefore, we slot the value back into the formula. This will be:
v = u + at
v = 0 + (9.8 × 5.6)
v = 0 + 54.88
v = 54.88 meters per second
Therefore, the final velocity is 54.88m/s
An object is placed 10 cm from a convex lens of focal length 20 cm. What is the lateral magnification of the object?
A) 0.50
B) 1.0
C) 1.5
D) 2.0
E) 2.5
Answer:
D 2
Explanation:
Given that
Distance of the object, u = 10 cm
Focal distance of the object, f = 20 cm
Then again, we know from the lens formula that
1/f = 1/u + 1/v
Then we solve for the distance of the image, v
1/20 = 1/10 + 1/v
1/v = 1/20 - 1/10
1/v = (1 - 2) /20
1/v = -1/20
v = -20 cm
Lateral magnification is given as
m = -v/u,
So we input our values
m = - -20/10
m = 20/10
m = 2
TRUE/FALSE, the scientific question is written like “I wonder if [dependent variable] is affected by [independent variable].”
Why are doorknobs placed at the edge of a door rather than in the center
Answer: so it can reach the frame
Explanation:
Answer:
To increase force on the door
The speed of revolution of particle going around a circlr is doubled and its angular speed is havled. What happen to the centripetal acceleration?
a) unchanged
b) doubles
c) halves
d) becomes four times
Answer: The correct answer is C
Explanation:
The maximum electric field strength in air is 3.0 Mv/m . Stronger electric fields ionize the air and create a spark. What is the maximum power that can be delivered by a 1.5cm diameter laser beam propagating through air?
Answer:
The value is [tex]P_{max} = 2.11 * 10^{6} \ W[/tex]
Explanation:
From the question we are told that
The maximized electric field strength is [tex]E = 3.0 \ MV/m = 3.0 *10^{6} \ V/m[/tex]
The diameter is [tex]d = 1.5\ cm = 0.015 \ m[/tex]
Generally the cross -sectional area is mathematically represented as
=> [tex]A = \frac{\pi * d^2 }{4}[/tex]
=> [tex]A = \frac{3.142 * 0.015^2 }{4}[/tex]
=> [tex]A = 0.0001767 \ m^2[/tex]
Generally the maximum power is mathematically represented as
[tex]P_{max} = \frac{E_{max}^2}{ 2 * \mu_o * c } * A[/tex]
Here c is the speed of light with value [tex]c = 3.0 *10^{8} \ m/s[/tex]
[tex]\mu_o[/tex] is the permeability of free space with value [tex]\mu_o = 4 \pi *10^{-7} \ H/m[/tex]
[tex]P_{max} = \frac{ (3.0 *10^{6})^2}{ 2 * (4 \pi *10^{-7}) * 3.0 *10^{8} } * 0.0001767[/tex]
=> [tex]P_{max} = 2.11 * 10^{6} \ W[/tex]
The maximum power that can be delivered by a laser beam propagating through air is equal to [tex]2.11 \times 10^6\;Watts[/tex]
Given the following data:
Electric field strength in air = 3.0 Mv/m = [tex]3 \times 10^6\;v/m[/tex]Diameter = 1.5 cm to m = 0.015 meter.Radius = [tex]\frac{Diameter}{2} = \frac{0.015}{2} = 0.0075\;meter[/tex]
Scientific data:
Permeability of free space = [tex]1.25663706 \times 10^{-6}\;H/m[/tex]Speed of light = [tex]3 \times 10^8\;m/s[/tex]To determine the maximum power that can be delivered by a laser beam propagating through air:
First of all, we would solve for the area of the laser beam as follows:
[tex]Area = \pi r^2\\\\Area = 3.142 \times 0.0075^2\\\\Area = 3.142 \times 0.00005625\\\\Area = 1.77 \times 10^{-4}\;m^2[/tex]
Now, we can determine the maximum power that can be delivered by a laser beam:
Mathematically, maximum power is given by the formula:
[tex]P_{max} = \frac{AE_{max}^2}{2 \mu_o c}[/tex]
Substituting the given parameters into the formula, we have;
[tex]P_{max} = \frac{1.77 \times 10^{-4} \;\times \;(3 \times 10^6)^2}{2 \;\times \;1.25663706 \times 10^{-6} \; \times \;3 \times 10^8}\\\\P_{max} = \frac{1.77 \times 10^{-4} \;\times \;9 \times 10^{12}}{753.982236}\\\\P_{max} = \frac{1593000000}{753.982236}\\\\P_{max} = 2.11 \times 10^6\;Watts[/tex]
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A 10.0kg object is moving at 1 m/s when a force is applied in the direction of the objects motion, causing it to speed up to 4 m/s. If the force was applied for 5s what is the magnitude of the force
Answer:
F = 6[N].
Explanation:
To solve this problem we must use the principle of conservation of linear momentum, which tells us that momentum is conserved before and after applying a force to a body. We must remember that the impulse can be calculated by means of the following equation.
[tex]P=m*v\\or\\P=F*t[/tex]
where:
P = impulse or lineal momentum [kg*m/s]
m = mass = 10 [kg]
v = velocity [m/s]
F = force [N]
t = time = 5 [s]
Now we must be clear that the final linear momentum must be equal to the original linear momentum plus the applied momentum. In this way we can deduce the following equation.
[tex](m_{1}*v_{1})+F*t=(m_{1}*v_{2})[/tex]
where:
m₁ = mass of the object = 10 [kg]
v₁ = velocity of the object before the impulse = 1 [m/s]
v₂ = velocity of the object after the impulse = 4 [m/s]
[tex](10*1)+F*5=10*4\\10+5*F=40\\5*F=40-10\\5*F=30\\F=6[N][/tex]
A uniform hollow spherical ball of mass 1.75 kg and radius 40.0 cm rolls without slipping up a ramp that rises at 30.0° above the horizontal. The speed of the ball at the base of the ramp is 2.63 m/s. While the ball is moving up the ramp, find (a) the acceleration (magnitude and direction) of its center of mass and (b) the friction force (magnitude and direction) acting on it due to the surface of the ramp.
Answer:
2.94 m/s²
3.43 N
Explanation:
To start with, the combination of rotational and translational kinetic energy can be converted to gravity potential energy. So, we will apply this in solving our question.
PE = KE
mgh = ½mv² + ½Iω²
Moment of inertia of a hollow sphere
I = ⅔mr²
We also know that,
ω = v/r, so if we substitute for ω and I, we have
mgh = ½mv² + ½(⅔mr²)(v/r)², simplifying
gh = ½v² + ½(⅔r²)(v/r)², simplifying further
gh = ½v² + ⅓v², adding up
gh = (5/6)v², making h subject of formula
h = 5v²/6g
Now, we substitute for v and g to have
h = 5(2.63)² / 6(9.81)
h = 34.585 / 58.86
h = 0.588 m
To get the distance that the ball rolls on the ramp before stopping, we say
d = 0.588 / sin30.0
d = 0.588 / 0.5
d = 1.176 m
so acceleration is
a = (2.63² - 0²) / 2(1.176)
a = 6.917 - 0 / 2.352
a = 2.94 m/s
B
Neglecting friction, the sphere acts like a point mass and tends to rise.
mgh = ½mv², simplifying
h = v²/2g
h = 2.63² / 2(9.81)
h = 6.917 / 19.62
h = 0.353 m
The work done by the friction force is the same as the rotational kinetic energy of the sphere, so we say
U = KEr
Fd = ½Iω²
Fd = ½(⅔mr²)(v/r)²
Fd = ⅓mv²
F = mv²/3d
where d is the actual distance up the slope the sphere did roll.
The average friction force is thus
F = 1.75(2.63)² / 3(1.176)
F = 1.75 * 6.917 / 3.528
F = 12.1 / 3.528
F = 3.43 N
What happens to the molecules of water when it moves from a liquid to a gas?
A. Water molecules condense and move slower.
B. Water molecules spread out and move slower.
C. Water molecules spread out and move faster.
D. Water molecules condense and move faster.
its A or D but im not sure which one ik it moves fast
Brandon hits a golf ball with an initial velocity of 30 m/s at an angle of 30 above the horizontal. How long is it in the air?
Given :
Brandon hits a golf ball with an initial velocity of 30 m/s at an angle of 30 above the horizontal.
To Find :
How long is it in the air.
Solution :
We know, the formula of time of flight is :
[tex]T = \dfrac{2usin\ \theta}{g}\\\\T = \dfrac{2\times 30\times sin\ 30^o}{9.8}\\\\T = 3.06\ seconds[/tex]
Therefore, the ball is in air for 3.06 seconds.
Two cars each have a mass of 1050 kg. If the gravitational force between
them is 2.27 x 10-7N, how far apart are they? G = 6.67 10-11 N:(m/kg)2
A. 21 m
B. 5.6 m
C. 33 m
D. 18 m
DUBMIT
Answer: D.
Explanation:
d = ± √ G m 1 m 2 /F
Because distance cannot be negative there it goes:
d = √ G m 1 m 2 /F
d = √ 6.67 ⋅ 10 − 11 ⋅ 1050 ⋅ 1050 2.27 ⋅ 10 − 7
d = √ 0.0000735 2.27 ⋅ 10 − 7
d = √ 3239504.405
d ≈ 1799.86 m = 18m
What are Newton’s 3 laws of motion?
Answer: It states that for every action, there is an equal and opposite reaction.
I hope this helps, and Happy Holidays! :)
7. Which of the following is true about Earth's gravity?
A. Gravity does not act on objects that are at rest or not moving.
B. Gravity only acts on oljects that are accelerating,
C. Gravity only acts on objects that are falling down.
D. Gravity acts on all objects on Earth, whether it is at rest or moving.
Answer:
D
Explanation:
Gravity is always having an effect on every object on earth, whether or not its moving.
An aluminum baking sheet with a mass of 225 g absorbs 2.4 x 104 J from an oven. If its temperature was initially 25 C, what will its new temperature be?
Answer:
The value is [tex]T_2 =416.9 \ K[/tex]
Explanation:
From the question we are told that
The mass of the aluminum baking sheet is [tex]m = 225 \ g = 0.225 \ kg[/tex]
The energy absorbed is [tex]E = 2.4 *10^{4} \ J[/tex]
The initial temperature is [tex]T_1 = 25 ^oC = 25 + 273 = 298 \ K[/tex]
Generally the heat absorbed is mathematically represented as
[tex]Q = m * c_a * [T_2 - T_1][/tex]
Here [tex]c_a[/tex] is the specific heat capacity of aluminum with value [tex]c_a = 897 \ J / kg \cdot K[/tex]
So
[tex]2.4 *10^{4 } =0.225 * 897 * [ T_ 2- 298][/tex]
=> [tex]T_2 - 298 = 118.915[/tex]
=> [tex]T_2 =416.9 \ K[/tex]
1+1=?
FIRST ONE TO ANSWER GETS BRAINLIEST!
Answer:
Thx for points merry Christmas answer 2
Explanation:
Answer:2
Explanation:
When an element ejects an alpha particle, the mass number of that element
A.reduce by 4.
B.remains unchanged.
C.increase by 1.
D. reduce by 1.
Answer:
A.reduce by 4.
Explanation:
In Chemistry, an alpha particle which is typically a helium nucleus has an atomic mass (number of nucleons) of four (4). Therefore, the ejection of an alpha particle by any chemical element simply means that, the mass number of that particular chemical element would be reduced by four (4).
Basically, this process is referred to as an alpha decay and can be defined as a radioactive disintegration of a chemical element that causes it to emit an alpha particle and as a result reducing its mass number by four (4).
Hence, when an element ejects an alpha particle, the mass number of that element reduces by 4.
how large amount of energy is produced during the fission of uranium
Answer:
answer is a very large amount of energy is produced from a very small mass
Explanation:
nuclear energy is produced either by fusion or fission the former is fusion of lighter atoms into heavier elements while the letter is the splitting of a heavier atom into lighter atoms. both produce tremendous amount of energy fusion causes compassion of mass wild fission reduces it. and produce it. fusion does not produce radioactive particles while fission does (alpha and beta particles and neutrons)
A 300 kg piano needs to be moved to the other side of the room. The maximum static frictional force is equal to 90 N and the kinetic frictional force is equal to 70 N. Calculate the acceleration of the piano for an applied force of 100 N.
Answer:
a = 0.1 m/s²
Explanation:
If the maximum static frictional force is 90 N, this means that any applied force that will overcome this force, will cause the piano to slide, so kinetic frictional force applies.Under these conditions, the net force in the horizontal direction is just the difference between the applied force (which is larger that the static friction force) and the kinetic frictional force, as follows:[tex]F_{net} = F_{app} -F_{frk} = 100 N - 70 N = 30 N (1)[/tex]
By the same token, according Newton's 2nd Law, this force is just equal to the product of the mass of the piano, times the acceleration, as follows:[tex]F_{net} = m* a = 300 Kg * a = 30 N (2)[/tex]
Solving for a:[tex]a = \frac{F_{net}}{m} = \frac{30 N}{300kg} = 0.1 m/s2 (3)[/tex]
I need help ASAP!
1. Two wave pulses move towards each other as shown below. The pulses have the same width and amplitudes.
What is the resulting wave pattern when the centers of the two pulses meet?
Answer:
b.
Explanation:
The resulting wave pattern when the centers of the two pulses meet is undergo constructive interference.
When two waves meet?Waves are pulses of energy that propagate through space periodically. When two waves overlap in the same region of space, interference occurs, which results in another wave with different intensity. These variations in the intensity of the resulting wave are called interference fringes.
The two pulses propagate with the same phase and in opposite directions, when they meet, they suffer constructive interference, which will cause the sum of the amplitudes. After interference, each wave goes its way as if nothing happened.
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An observer sitting on shore sees a canoe traveling 5.0 m/s east, and a sailboat traveling 15.0 m/s west. What is the velocity of the sailboat as observed on the canoe (relative to the canoe)?
Answer:
Vs/c = 20 [m/s]
Explanation:
This is a problem of relative velocities, as velocity is a vector we can use addition or subtraction of vectors for the solution.
We are asked for the velocity of the sailboat with respect to an observer located in the canoe.
[tex]V_{s/c}=V_{sailboat}-V_{canoe}\\V_{s/c}=15-(-5)\\V_{s/c}=20[m/s][/tex]
Why is the speed of the canoe negative?, it is negative because the canoe moves in the opposite direction to the sailboat.
what is mean by combination reaction ?
[tex] \underline{\purple{\large \sf Combination \: reaction :-}} [/tex]
Those reaction in which two or more substances combine to form a one new substance are called Combination reaction
In this reaction, We can add :
Two or more elements can combine to form a compound.Two or more compounds can combine to from a one new compound.An element and a compound can combine to form a new compound.[tex] \underline{\green{\large \sf For\: example :}} [/tex]
[tex] \sf 2H_{2} + O_{2} \: \underrightarrow{Combination} \: 2H_{2}o[/tex]
In this, Hydrogen is an element and Oxygen is another element. Both are combined to form compound 'Hydrogen oxide'. Hydrogen oxide is commonly known as water.
A solid disk with a mass of 0.8 kg and a radius of 12cm is rotating at a rate of 2.6 rev/s. Another disk with half the mass and half the radius is dropped on top of the first disk. What is the new angular speed of both disks when they are rotating together?
Answer:
The new angular speed of both disks when they are rotating together is 2.311 revolutions per second.
Explanation:
This situation can be analyzed by the Principle of Conservation of Angular Momentum since there are no external forces and moments being exerted on the system, whose definition is presented below:
[tex]I_{o}\cdot \omega_{o} = I_{f}\cdot \omega_{f}[/tex] (1)
Where:
[tex]\omega_{o}[/tex], [tex]\omega_{f}[/tex] - Initial and final angular speeds, measured in revolutions per second.
[tex]I_{o}, I_{f}[/tex] - Initial and final moments of inertia, measured in kilograms per square meter.
The initial and final moments of inertia of the system are, respectively:
[tex]I_{o} = \frac{1}{2}\cdot m_{o}\cdot r_{o}^{2}[/tex] (2)
[tex]I_{f} = \frac{1}{2}\cdot \left[m_{o}\cdot r_{o}^{2}+\frac{1}{2}\cdot m_{o}\cdot \left(\frac{1}{2}\cdot r_{o} \right)^{2}\right][/tex]
[tex]I_{f} = \frac{1}{2}\cdot m_{o}\cdot r_{o}^{2}+\frac{1}{16}\cdot m_{o}\cdot r_{o}^{2}[/tex]
[tex]I_{f} = \frac{9}{16}\cdot m_{o}\cdot r_{o}^{2}[/tex] (3)
By applying (2) and (3) in (1), we obtain the following expression:
[tex]\frac{1}{2}\cdot m_{o}\cdot r_{o}^{2}\cdot \omega_{o} = \frac{9}{16}\cdot m_{o}\cdot r_{o}^{2}\cdot \omega_{f}[/tex]
[tex]\frac{1}{2}\cdot \omega_{o} = \frac{9}{16}\cdot \omega_{f}[/tex]
[tex]\omega_{f} = \frac{8}{9}\cdot \omega_{o}[/tex] (4)
If we know that [tex]\omega_{o} = 2.6\,\frac{rev}{s}[/tex], then the new angular speed of both disks when they are rotating together is:
[tex]\omega_{f} = \frac{8}{9}\cdot \left(2.6\,\frac{rev}{s} \right)[/tex]
[tex]\omega_{f} = 2.311\,\frac{rev}{s}[/tex]
The new angular speed of both disks when they are rotating together is 2.311 revolutions per second.
Two motorcycles are traveling due east with different velocities. However, 3.63 seconds later, they have the same velocity. During this 3.63-second interval, motorcycle A has an average acceleration of 4.55 m/s2 due east, while motorcycle B has an average acceleration of 18.9 m/s2 due east. (a) By how much did the speeds differ at the beginning of the 3.63-second interval, and (b) which motorcycle was moving faster
Answer:
52.095 m/s
Motorcycle a was moving faster
Explanation:
We start by using one of the equations of motion
V = u + at
If the first motorcycle starts with an initial speed of u(a) and accelerates at a value of a(a) = 4.55 m/s², then the final speed after a time of 3.63 seconds is V(a). We then represent it as
V(a) = u(a) + a(a).t
If the second motorcycle starts with an initial speed of u(b) and accelerates at a value of a(b) = 18.9 m/s², then the final speed after a time of 3.63 seconds is V(b). We then represent it as
V(b) = u(b) + a(b).t
Assuming that the final speeds v(a) = v(b), and then subtract the equation of the second motorcycle from that of the first, we have
0 = u(a) - u(b) + a(a).t - a(b).t
-u(a) + u(b) = a(a).t - a(b).t, on rearranging, we have
u(b) - u(a) = [a(a) - a(b)]t
Since we have the values for acceleration and the time, we substitute so that
u(b) - u(a) = (4.55 - 18.9)3.63
u(b) - u(a) = -14.35 * 3.63
u(b) - u(a) = -52.095, or we rearrange to get
u(a) - u(b) = 52.095 m/s
Putting the selected answers in parenthesis
A cation has a (Negative, Positive, Neutral) charge, because they have (Lost, Maintained, Gained) electrons. An anion has a (Negative, Positive, Neutral) charge, because they have (Lost, Maintained, Gained) electrons. An atom with the same number and protons and neutrons have a (Negative, Positive, Neutral) charge.
Answer:
gimmie
Explanation:
When a object is electrically charged, ____ have been added or removed.
A) Neutrons
B) Electrons
C)Protons
Answer:
B, electrons.
Explanation:
An electrical charge is created when electrons are transferred to or removed from an object. Because electrons have a negative charge, when they are added to an object, it becomes negatively charged. When electrons are removed from an object, it becomes positively charged.
32. Which type of electromagnetic wave is used for nuclear power and medical treatment?
A. UV wave
B.Radio wave
C.Visible light wave
D. Gamma ray
Which of the following is a way that microwaves and x-rays are similar?
A. They both have technological uses.
B. They are both high energy waves,
C. They are both safe to be exposed to at high doses
D. They are both used to transmit information.
Answer:
Answers at the bottom!!
Explanation:
For the first answer: Gamma ray
Gamma rays and x-rays consist of high-energy waves that can travel great distances at the speed of light and generally have a great ability to penetrate other materials. For that reason, gamma rays (such as from cobalt-60) are often used in medical applications to treat cancer and sterilize medical instruments.
For the second answer: They both have technological uses.
In my opinion I'm pretty sure it's A because we do use microwaves and x-rays as technological uses.
Hope this helps!!
Happy Holidays and Season Greeting!!
ii Feliz Navidad a todos !!
Gamma rays and x-rays consist of high-energy waves that can travel great distances at the speed of light and generally have a great ability to penetrate other materials. For that reason, gamma rays (such as from cobalt-60) are often used in medical applications to treat cancer and sterilize medical instruments.
What are gamma rays ?"A gamma ray (g) is a packet of electromagnetic energy (photon) emitted by the nucleus of some radionuclides following radioactive decay." Gamma photons are the most energetic photons in the electromagnetic spectrum.
What are x-rays ?"An X-ray, or, much less commonly, X-radiation, is a penetrating form of high-energy electromagnetic radiation." Most X-rays have a wavelength ranging from 10 picometers to 10 nanometers, corresponding to frequencies in the range 30 petahertz to 30 exahertz and energies in the range 145 eV to 124 keV.
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They both have technological uses.
Microwaves and x-rays have in common is all electromagnetic waves, electric and magnetic fields that oscillate together, perpendicular to each other.
What is technological usage?
"The application of practical sciences to industry or commerce." The methods, theory, and practices governing such application. a highly developed technology. The total knowledge and skills available to any human society for industry, art, science, etc.
What are technological uses of microwave and x-ray ?Microwaves are used in spacecraft communication, and much of the world's data, TV, and telephone communications are transmitted long distances by microwaves between ground stations and communications satellites. Microwaves are also employed in microwave ovens and in radar technology.
They are used on such products as aircraft and rocket parts and structures, canned and packaged foods, electronics, semiconductors and microchips, thermal insulations, and automobile tires. Material processing technologies use X-ray systems to automatically control the density or thickness of layers of substances.
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A car starts from point A, goes 100 km to point B, immediately turns around, and returns to point A. The round trip takes 4 hours.
What is the average speed of the car?
Answer:
50 km/h
Explanation:
200 km = 4 hours
200/4=50
50km/h
A car jack works when a mechanic uses a force 3.8 N, on a small piston of radius 10 cm. What force can he exert on a larger piston of radius 0.22 m?
Answer:
18.392 N
Explanation:
Given that,
Smaller force acting on the car, F₁ = 3.8 N
Radius of smaller radius, r₁ = 10 cm = 0.1 m
The radius of the larger piston, r₂ = 0.22 m
We need to find the force exerted on the larger piston. Let it is F₂.
Using the relation,
[tex]\dfrac{F_1}{F_2}=\dfrac{A_1}{A_2}\\\\\dfrac{F_1}{F_2}=\dfrac{\pi r_1^2}{\pi r_2^2}\\\\\dfrac{F_1}{F_2}=\dfrac{r_1^2}{r_2^2}\\\\F_2=\dfrac{F_1r_2^2}{r_1^2}\\\\F_2=\dfrac{3.8\times (0.22)^2}{(0.1)^2}\\\\F_2=18.392\ N[/tex]
Hence, the force exerted on the larger piston is 18.392 N.
A tennis ball moves 16 meters northward, then 22 meters southward, then 12 meters northward, and finally 32 meters southward.
What is the relationship between kinetic and potential energy of a falling object
Answer:
See the explanation below.
Explanation:
According to the law of energy conservation. This can be transformed from potential energy to kinetic or vice versa.
For example, when you have a body at rest at a height with respect to the ground level, this body possesses potential energy with respect to the ground, but the moment that the body falls the potential energy decreases as it loses height with respect to the ground, but as the potential energy decreases, the kinetic energy increases, that is to say, the potential energy is transformed into kinetic energy as the body is falling.
As the energy relationship is maintained we can say that the potential and kinetic energies are equal.
[tex]E_{pot}=m*g*h\\E_{kin}=\frac{1}{2} *m*v^{2} \\E_{pot}=E_{kin}[/tex]
A 5.0-g object carries a net charge of 3.8 micro-Coulomb. It acquires a speed v when accelerated from rest through a potential difference V. A 2.0-g object acquires twice the speed under the same circumstances. What is its charge?
Answer:
The value is [tex]q_2 = 6.1 *10^{-6} \ C[/tex]
Explanation:
From the question we are told that
The mass of the object is [tex]m_1 = 5.0 \ g = 0.005 \ kg[/tex]
The net charge is [tex]q = 3.8 \mu C= 3.8 *10^{-6} \ C[/tex]
The mass of the second object is [tex]m_1 = 2.0 \ g = 0.002 \ kg[/tex]
Generally for the first object the potential energy gained at the end of its acceleration is equal to its kinetic energy
i.e
[tex]\frac{ 1}{ 2} * m_1 * v^2_1 = q_1 * \Delta V \ \ --- (1)[/tex]
Here [tex]v_1[/tex] is the velocity of the first object
[tex]\Delta V[/tex] is the potential difference through which it is accelerated
Generally for the second object the potential energy gained at the end of its acceleration is equal to its kinetic energy
i.e
[tex]\frac{ 1}{ 2} * m_2 * v^2_2 = q_2 * \Delta V[/tex]
Here [tex]v_2[/tex] is the velocity of the second object and from the question it is
[tex]v_2 = 2 v_1[/tex]
[tex]\Delta V[/tex] is the potential difference through which it is accelerated
So
[tex]\frac{ 1}{ 2} * m_2 * (2v)^2_1 = q_2 * \Delta V[/tex]
=> [tex]m_2 * 2v^2_1 = q_2 * \Delta V \ \ ---(2)[/tex]
Generally dividing equation 2 by equation 1
[tex]\frac{2m_2 v^2_1 }{ \frac{1}{2} * m_1 * v_1^2} = \frac{q_2 \Delta V }{ q_1 * \Delta V}[/tex]
=> [tex]q_2 = \frac{4m_2 * q_1 }{m_1}[/tex]
=> [tex]q_2 = \frac{4* 0.002 * 3.8 *10^{-6} }{0.005}[/tex]
=> [tex]q_2 = 6.1 *10^{-6} \ C[/tex]
=> [tex]q_2 = 6.1 *10^{-6} \ C[/tex]
