a stone attached to 1m long string is moving with the speed of 5ms in a circle find the centripetal acceleration of the stone​

Answer:

Given information:-

[tex]\clubsuit[/tex]The displacement of the cyclist will be shortest distance from his initial to final positions which is nothing but diameter of the circle = 2r

We know that,

[tex] \underline{ \boxed{ \sf{Speed = \frac{Distance \: covered }{Time \: taken}}}}[/tex]

[tex]\longrightarrow \sf{\frac{636 \times 3.14 m}{90s}} \\ \\ \longrightarrow \sf22.18 m/s[/tex]

[tex]\sf{Velocity = \frac{Displacement }{ Time} }[/tex]

[tex]\longrightarrow \sf{ \frac{2 \times 636m}{90s} } \\ \\ \longrightarrow \sf{14.13 \: m/s}[/tex]

Thank You :)

Answer:

136 m.

Explanation:

From the question given above, the following data were obtained:

Time (t) = 0.80 s

Speed of sound (v) = 340 m/s

Distance (x) =?

The distance of the player from the wall can be obtained as follow:

v = 2x / t

340 = 2x / 0.80

Cross multiply

2x = 340 × 0.80

2x = 272

Divide both side by 2

x = 272 / 2

x = 136 m

Thus, the distance of the player from the wall is 136 m

Answer:

H + H ------> He + energy. He + He -----> H + H + He.

Explanation:

Hydrogen having one proton and no neutron fuse with hydrogen having one proton and one neutron forming helium atom with the release of photon. After that two helium atoms combine together forming two hydrogen atoms having one proton each whereas one helium atom having two protons and two neutrons present in their nucleus so the end product of this reaction is hydrogen atoms and helium.

Answer:

Finding time period of SHM from equation of displacement

Explanation:

0

Say for example I've got the equation of a SHM as:

x=Acos(ωt+ϕ)

where A is the amplitude.

How do I find the time period of this motion?

I tried by finding the second order differential of the given equation.

a=d2xdt2=−Aω2cos(ωt+ϕ)

Comparing it with the general equation for acceleration a=−ω2x, we can find ω from here.

But that is where the problem is coming. It makes no sense if I write ω=ωA−−√.

What is the correct method to find the time period of the SHM? What am I missing?

There is a very simple mistake in your math. Notice A is part of x, it is factored so you'll get to ω=ω again. If you want to find a meaning to ωT=2π, consider the fact that cos (or sin) are periodic functions with period 2π. Hence, every time you have a time difference such that ω(t1−t2)=2π you are back at the same point. Hence the period is given by ωT=2π.

Explanation:

Given that,

Mass of an object, m = 250 g = 0.25 kg

Spring constant, k = 48 N/m

The amplitude of the oscillation, A = 5.42 cm = 0.0542 m

1. At equilibrium,

ma = kx

Where

a is the acceleration of the object

So,

[tex]a=\dfrac{kx}{m}\\\\a=\dfrac{48\times 0.0542}{0.25}\\\\a=10.4\ m/s^2[/tex]

2. The maximum speed of the object is :

[tex]v=A\omega\\\\v=A\sqrt{\dfrac{k}{m}}\\\\v=0.0542\times \sqrt{\dfrac{48}{0.25}}\\\\v=0.75\ m/s[/tex]

Hence, this is the required solution.

Answer:

235.6m/s

Explanation:

you have to use one of the kinematic formulas the best that suits the question given in this case you can use v=u+at.since the time, acceleration and initial velocity have been given in the question

v=116+(9.2)13^2

v=116+119.6

=235.6m/s

I hope this helps

Answer:

displacement=specific distance

*Velocity=∆displacement/time

*acceleration=∆velocity/time

Answer:

Explanation:

Answer:

It was created during the French Revolution in 1799 and has enabled for the international exchange of scientific and technical information. Calculating with SI units is also a lot easier than using the English system.

Answer:

[tex]{ \bf{false}}[/tex]

Explanation:

Because it breaks the law of moments.

here's the answer to your question

Answer:

Velocity is the rate of change of position with respect to time, whereas acceleration is the rate of change of velocity. Both are vector quantities (and so also have a specified direction), but the units of velocity are meters per second while the units of acceleration are meters per second squared.

Answer:

asdiieiwihebebwiwo3o2iwjw3

Answer:

3.14*1²

3.14 cm²

I hope this will help

Answer:

3.14 cm squared

Explanation:

I hope this will help.

Answer:

Distancia, D = 170,000 metros

Explanation:

Dados los siguientes datos;

Para encontrar la distancia recorrida, en metros;

Matemáticamente, la distancia recorrida por un objeto se calcula mediante la fórmula;

Distancia = velocidad * tiempo

Sustituyendo los valores en la fórmula, tenemos;

Distancia = 85 * 2

Distancia = 170 kilómetros

A continuación, convertiríamos el valor en kilómetros a metros;

Conversión:

1 kilómetros = 1000 metros

170 kilómetros = D metros

Multiplicación cruzada, tenemos;

D = 170 * 1000

D = 170,000 metros

Por lo tanto, habría viajado 170,000 metros después de 2 horas.

Answer:

1.12 × 10⁴ m/s

Explanation:

The escape velocity of the object v = √(2GM/R) where G = gravitational constant = 6.67 × 10⁻¹¹ Nm²/kg², M = mass of the Earth = 6 × 10²⁴ kg and R = radius of the Earth = 6.4 × 10⁶ m

Since v = √(2GM/R)

Substituting the values of the variables into the equation, we have

v = √(2GM/R)

v = √(2 × 6.67 × 10⁻¹¹ Nm²/kg² × 6 × 10²⁴ kg/6.4 × 10⁶ m)

v = √(13.34 × 10⁻¹¹ Nm²/kg² × 6 × 10²⁴ kg/6.4 × 10⁶ m)

v = √(80.04 × 10⁻¹¹ × 10²⁴Nm²/kg/6.4 × 10⁶ m)

v = √(80.04 × 10¹³Nm²/kg ÷ 6.4 × 10⁶ m)

v = √(80.04 ÷ 6.4 × 10¹³ ÷ 10⁶Nm/kg)

v = √(12.50625 × 10⁷ Nm/kg)

v = √(125.0625 × 10⁶ Nm/kg)

v = 11.18 × 10³ m/s

v = 1.118 × 10 × 10³ m/s

v = 1.118 × 10⁴ m/s

v ≅ 1.12 × 10⁴ m/s

Answer:

The number of turns in the solenoid is 19506.

Explanation:

Length of solenoid, L = 0.28 m

Magnetic field, B = 7 T

Current, I = 80 A

Let the number of turns is N.

The formula used to find the magnetic field is

[tex]B = \frac{\mu 0N I}{L}\\\\7 = \frac{4 \times 3.14\times 10^{-7}\times N\times 80}{0.28}\\\\N = 19506[/tex]

Work = force x distance

Work = 5500 x 1.8

Work = 9900 N

The work measure of energy transfer that occurs when an object is moved over a distance by an external force at least part of which is applied in the direction of the displacement.

Work = force x distance

Work = 5500 x 1.8

Work = 9900 N

therefore, work does 9900 N

Work is force applied over distance. Examples of work include lifting an object against the Earth's gravitation, driving a car up a hill, and pulling down a captive helium balloon. Work is a mechanical manifestation of energy. The standard unit of work is the joule (J), equivalent to a newton - meter (N · m).

Work is defined as transferring energy into an object so that there is some displacement. Energy is defined as the ability to do work. Work done is always the same. Energy can be of different types such as kinetic and potential energy.

To learn more about work, refer

https://brainly.com/question/19987285

#SPJ2

Answer:

Obeying to weights & measurement regulations in both national and international metrology legislation, standards and test procedures is a requirement to participate in any market because it's aimed to safeguard the consumers and promote fair competition, which provides efficiency and saves unnecessary costs to U.S. businesses and stakeholders.

Explanation:

In the U.S., the National Institute of Standards and Technology (NIST) has an Office of Weights and Measures (OWM) that represents the country in the International Organization of Legal Metrology (OIML)

Let F₁ and F₂ denote the two forces, and R the resultant force.

F₁ and F₂ point perpendicularly to one another, so their dot product is

F₁ • F₂ = 0

We're given that one of these vectors, say F₁, makes an angle with R of 30°, so that

F₁ • R = ||F₁|| ||R|| cos(30°)

But we also have

F₁ • R = F₁ • (F₁ + F₂) = (F₁ • F₁) + (F₁ • F₂) = F₁ • F₁ = ||F₁||²

So, knowing that ||R|| = 100 N, we get that

(100 N) ||F₁|| cos(30°) = ||F₁||²

(100 N) cos(30°) = ||F₁||

||F₁|| ≈ 86.6 N

(And the same would be true for F₂.)

Answer:

301.6 N

Explanation:

The length of the wire L₀ = 8 m and its diameter, d = 4 mm = 4 × 10⁻³ m. Since its temperature drops by  10°C, it will have a change in length ΔL = L₀αΔθ where α = linear expansivity of steel, a 12 × 10⁻⁶ /K, and Δθ = temperature change = -10°C = -10 K(negative since it is a drop)

So, the strain, ε = ΔL/L₀ = αΔθ = 12 × 10⁻⁶ /K × 10 K = 12 × 10⁻⁵

Now the Young's modulus of steel, Y = σ/ε where σ = stress = T/A where T = increase in tension in steel wire and A = cross-sectional area of wire = πd²/4 where d = diameter of wire = 4 × 10⁻³ m and ε = strain = 12 × 10⁻⁵

So, σ = Yε

Since Y = 2 × 10¹¹ N/m².

Substituting the values of the variables into the equation, we have

σ = Yε

σ = 2 × 10¹¹ N/m² × 12 × 10⁻⁵

σ = 24 × 10⁶ N/m²

Since σ = T/A

T = σA

T = σπd²/4

Substituting the values of the variables into the equation, we have

T = σπd²/4

T = 24 × 10⁶ N/m² × π × (4 × 10⁻³ m)²/4

T = 24 × 10⁶ N/m² × π × 16 × 10⁻⁶ m²/4

T = 24 × 10⁶ N/m² × π × 4 × 10⁻⁶ m²

T = 96 N × π

T = 301.59 N

T ≅ 301.6 N

So, the increase in tension in the steel wire is 301.6 N

Answer:

658.2 nm

Explanation:

Since the galaxy is moving at relavitistic speed, we use the equation for relativistic Doppler shift of light.

So, the wavelength of light observed on the Earth is λ

λ = λ'([tex]\sqrt{\frac{ 1 + \frac{v}{c} }{1 - \frac{v}{c} } }[/tex])

where  λ' = wavelength of light emitted by galaxy = 656 nm, v = speed of galaxy = 1000 km/s (positive since the galaxy is moving away from the Earth) and c = speed of light = 300000 km/s

So, substituting the values of the variables into the equation, we have

λ = λ'(√[{1 + (v/c)}/(1 - (v/c)]

λ = 656 nm(√[{1 + (1000 km/s/300000 km/s)}/(1 - (1000 km/s/300000 km/s)]

λ = 656 nm(√[{1 + 1/300}/(1 - 1/300]

λ = 656 nm(√[{(300 + 1)/300}/{(300 - 1)/300}]

λ = 656 nm(√[{(301)/300}/{(299)/300}]

λ = 656 nm(√[301/299])

λ = 656 nm(√1.0067)

λ = 656 nm × 1.0033

λ = 658.19 nm

λ ≅ 658.2 nm

So, the wavelength observed on Earth is 658.2 nm

Answer:

smoke particles move in brownian motion (zig -zag motion ) .

Explanation:

this is because air molecules collide against smoke particles hence they attain kinetic energy which keeps them in continuous motion .

The motion of the smoke particles is Brownian motion that is the zigzag motion of the particles that particles move in a random direction.

In chemistry, the term "Brownian Movement" refers to the random zigzagging motion of a particle that is typically seen under a high power ultra-microscope. The term "Brownian movement" refers to the exact motion of pollen grains in water, as described by Robert Brown.

More crucially, Albert Einstein eventually clarified the Brownian movement in his study by claiming that water molecules were responsible for moving the pollen. This discovery provided compelling proof that atoms and molecules exist.

According to the question, the reason is that air molecules collide against smoke particles, hence the particles get kinetic energy which keeps them in continuous motion or in zigzag motion.

To get more information about Brownian Movement :

https://brainly.com/question/20350065

#SPJ2

Answer:

A. Cilvil court.........

Civil court  would you go to if you wanted to declare bankruptcy. The correct option is A.

Thus, According to the United States Bankruptcy Code, bankruptcy proceedings are typically filed in a federal bankruptcy court.

The federal court system includes these courts, which deal with Chapter 7, Chapter 11, and Chapter 13 bankruptcy cases.

The additional alternatives (U.S. Court of Appeals, Supreme Court, and U.S. District Court) are not the main courts where bankruptcy cases are generally filed.

Thus, Civil court  would you go to if you wanted to declare bankruptcy. The correct option is A.

Learn more about Civil court, refer to the link:

https://brainly.com/question/29614273

#SPJ3

Answer:

4 d

Explanation:

because the spring is balanced with t

Answer:

[tex] \green{ \sf \: \: 1.6 \: m {s}^{ - 2} \: \: \: is \: the \: correct \: answer}[/tex]

Explanation:

[tex] \sf \: \huge{g } _{ \small{moon}} = \frac{ {\huge{g}}_{earth}}{6} \\ \\ \sf \implies \: \sf \: \huge{g } _{ \small{moon}} = \frac{ 9.8}{6} = 1.6 \: \: m {s}^{ - 2} [/tex]

Answer:

B

Explanation:

the Halogen families have 7 valence electrons