Option E; The pump work, the power output of this plant is 335KW
Pressure. at turbine. inlet P1 = 10 Mpa.
Enthalpy at turbine inlet = h1=3625.84 KJ/kg.
Entropy at turbine inlet S1 =6.90 KJ/kg-K.
It is given that process performed acceording to ideal rankine cycle which is "Reversible adiabatic expansion' in case of turbine wor., Since it is reversible adiabatic expansion, entropy at turbine inlet and entropy at turbine outlet is constant. So quality at turbine outlet is evaluated by using this relation. S1 = S2.
Pressure at turbine outlet = 10 Kpa.
Enthalphy of steam = hg =2675.1 KJ/kg.
Enthaphy of liquid=hf =417.51 KJ/kg
Entropy of steam = Sg =7.3589 KJ/kg-K.
Entropy of liquid =Sf =1.302 KJ/kg-K.
We know S1 = S2 =6.090=1.302+x(7.3589 - 1.302).
Quality at turbine exit x =0.79.
Enthalphy at exit = h2 = 417.51+ 0.79*(2675.1 - 417.51) =2201 KJ/kg-K.
heat transfered= mass*(enthlphy at exit of condenser - enthalphy at turbine inlet), Since pump work negleted
At exit of condenser, steam gets converted into water at 10 Kpa pressure whose enthalphy is hf =417.51 KJ/kg.
800 = m(3625.84 - 417.51).
mass flow rate of steam = 0.24 Kg/sec.
Turbine work the power output of this plant is = m(h1 - h2) =0.24(3625.84 - 2201) = 335 KW.
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In a diffraction experiment, a coherent light source illuminates a pair of identical slits in a barrier, and the resulting pattern is projected on a screen that is separated from the barrier by 2.05 m. A student sketches the pattern that appears on the screen. The locations of the centers of the bright and dark fringes are accurate, but the shading is only qualitative. The color chosen may not be an ideal match to the actual light source. TITUTE THI HT -50.0 -40.0 -30.0 -20.0 -10.0 0.0 10.0 20.0 30.0 40.0 50.0 y (cm) * 25% Part (a) Enter the ratio of the slit separation, d, to the slit width, D, as a whole number. d = D TT 7 8 9 HOME E 4 5 6 sino cos tan cotano asin acos atan acotan sinh cosho tanh) cotanh O Degrees Radians 1 2 3 + 0 END . VO BACKSPACE DE CLEAR Submit Hint Feedback I give up! Hints: 1% deduction per hint. Hints remaining: 1 Feedback: 0% deduction per feedback. A 25% Part (b) Calculate and enter the ratio of the slit width to the wavelength of the light source. A 25% Part (C) If the slit separation is 17 um, then calculate and enter the wavelength, in nanometers, of the light source. 25% Part (d) What is the slit width, in micrometers?
(a) The ratio of the slit separation d, to the slit width D;
d/D = 0.0001
(b The ratio of the slit width to the wavelength of the light source λ;
d/λ = 51.25
(c) The wavelength, in nanometers, of the light source;
λ = 331.7 nm
(d) The slit width, in micrometers;
d = 20.5 µm
(a) We know that Fringe width is given by,
[tex]\beta =\frac{D\lambda}{d}[/tex]
Where,
D = slit to screen distance
λ = wavelength
d = slit width
Given in the question,
D = 2.05 m
[tex]\beta =4 cm=0.04m[/tex]
Now,
[tex]\frac{d}{D} =\frac{\lambda}{\beta } =\frac{400*10^{-9} }{0.04}[/tex]
d/D = 0.0001
Hence,
The ratio of the slit separation d, to the slit width D;
d/D = 0.0001
(b) Ratio of d & λ,
[tex]\frac{d}{\lambda} =\frac{D}{\beta }[/tex]
[tex]\frac{d}{\lambda}=\frac{2.05}{0.04}[/tex]
[tex]\frac{d}{\lambda}=51.25[/tex]
Hence,
The ratio of the slit width to the wavelength of the light source λ;
d/λ = 51.25
(c) The wavelength of the light source,
[tex]\lambda=\frac{D\beta }{d}[/tex]
[tex]\lambda=\frac{17*10^{-6} *0.04}{2.05}[/tex]
[tex]\lambda=331.7nm[/tex]
Hence,
The wavelength, in nanometers, of the light source;
λ = 331.7 nm
(d) The slit width,
[tex]d =\frac{D\lambda}{\beta }[/tex]
[tex]d=\frac{400*10^{-9} *2.05}{0.04}[/tex]
[tex]d=20.5 \mu m[/tex]
Hence,
The slit width, in micrometers;
d = 20.5 µm
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In an experiment, students hold a closed, rectangular loop of wire of mass mm, width LyLy, and length LxLx at rest above a very long wire that has a current II. The current-carrying wire is aligned along the origin, as shown in the diagram. The students release the loop from rest, and the loop falls in a direction perpendicular to the current-carrying wire. The students use an ammeter to measure the current in the loop as the loop passes very close to the wire but does not touch it. Which of the following statements best describes the experimental results and provides the principles that explain the results?
The induced current will be counterclockwise when the center of the loop is above the wire and clockwise when the center of the loop is below the wire. This is because the net magnetic field flux inside the loop is out of the page when the center of the loop is above the wire and is into the page when the center of the loop is below the wire.
Answer A: The induced current will be counterclockwise when the center of the loop is above the wire and clockwise when the center of the loop is below the wire. This is because the net magnetic field flux inside the loop is out of the page when the center of the loop is above the wire and is into the page when the center of the loop is below the wire.
A
The induced current will be clockwise until the top of the loop reaches the wire and will be counterclockwise when the top of the loop goes below this point. This is because the induced current is proportional to the rate of change of the magnetic field flux, which increases when the top of the loop is above the wire and decreases when the top of the loop is below the wire.
Answer B: The induced current will be clockwise until the top of the loop reaches the wire and will be counterclockwise when the top of the loop goes below this point. This is because the induced current is proportional to the rate of change of the magnetic field flux, which increases when the top of the loop is above the wire and decreases when the top of the loop is below the wire.
B
The induced current will always be clockwise as the loop falls. This is because the induced current is determined by the change of the magnetic flux inside the loop. The net magnetic flux is out of the page and increasing when the center of the loop is above the wire and into the page and decreasing when the center of the loop is below the wire.
Answer C: The induced current will always be clockwise as the loop falls. This is because the induced current is determined by the change of the magnetic flux inside the loop. The net magnetic flux is out of the page and increasing when the center of the loop is above the wire and into the page and decreasing when the center of the loop is below the wire.
C
The induced current will be clockwise until the bottom of the loop reaches the wire and will be counterclockwise when the bottom of the loop goes below this point. This is because the induced current is proportional to the rate of change of the magnetic field flux, which increases when the bottom of the loop is above the wire and decreases when the bottom of the loop is below the wire.
Answer D: The induced current will be clockwise until the bottom of the loop reaches the wire and will be counterclockwise when the bottom of the loop goes below this point. This is because the induced current is proportional to the rate of change of the magnetic field flux, which increases when the bottom of the loop is above the wire and decreases when the bottom of the loop is below the wire.
D
The induced current will always be counterclockwise as the loop falls. This is because the induced current is determined by the change of the magnetic flux inside the loop. The net magnetic flux is out of the page and decreasing when the center of the loop is above the wire and into the page and increasing when the center of the loop is below the wire.
The correct option is that C. The induced current will be clockwise until the bottom of the loop reaches the wire and will be counterclockwise when the bottom of the loop goes below this point. This is because the induced current is proportional to the rate of change of the magnetic field flux, which increases when the bottom of the loop is above the wire and decreases when the bottom of the loop is below the wire.
What is the current about?According to Faraday's law, the magnetic flux change rate in a circuit equals the magnitude of the induced EMF in the circuit. Additionally inversely correlated with the rate of change of magnetic flux in the circuit is hens induced current.
Lenz's law states that an induced current will flow in the opposite direction of the cause that is causing it. When the bottom of the loop is below this point, the induced current is counterclockwise until the bottom of the loop reaches the wire. This is because the magnetic field flux changes more quickly when the bottom of the loop is above the wire because the induced current is proportional to this
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A car moving with a speed of 90km/hr was brought to rest by the application of the
Brakes in 10s How far did the car travel after the brakes were applied?
The distance travelled by the car after the brake was applied is 125 m.
What is the distance travelled by the car?
The distance travelled by the car is calculated by applying the following kinematic equation as shown below.
Mathematically, the distance travelled by the car at the given average speed is calculated as;
s = [ ( v + u ) / 2 ] t
where;
v is the final velocity of the car = 0u is the initial velocity of the car = 90 km/hr = 25 m/st is the time of motion of the car = 10 sThe distance travelled by the car is calculated as;
s = [ ( 0 + 25 m/s ) / 2 ] ( 10 s )
s = 125 m
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Calculate the internal energy of 1.2moles of steam at 177degree
Answer:
18447 J
Explanation:
To calculate the internal energy of steam at a given temperature, we need to know the specific heat capacity of steam and the enthalpy of vaporization. The specific heat capacity of steam at a constant pressure is approximately 2.08 J/g*K, and the enthalpy of vaporization (latent heat) at 100°C is 2257 kJ/kg.
We can use the following equation to calculate the internal energy of steam at a given temperature:
U = m * Cp * (T - T_b) + m * L
Where U is the internal energy, m is the mass of the steam, Cp is the specific heat capacity of steam, T is the temperature of the steam, Tb is the boiling temperature of the steam, and L is the enthalpy of vaporization.
Since we are given the amount of steam in moles (1.2 moles) and the temperature (177°C), we can convert the moles of steam to mass using the molar mass of water (18 g/mol). The boiling temperature of water at standard atmospheric pressure is 100°C, so we can use this value for Tb.
First, we need to convert the temperature from degrees Celsius to kelvins:
T = 177°C + 273 = 450 K
Then, we can calculate the mass of the steam:
m = 1.2 moles * 18 g/mol = 21.6 g
Substituting these values into the equation for internal energy, we get:
U = 21.6 g * 2.08 J/g*K * (450 K - 273 K) + 21.6 g * 2257 kJ/kg
Solving for the internal energy, we get:
U = 18,447 J
Therefore, the internal energy of 1.2 moles of steam at 177°C is approximately 18,447 J.
the use of the doppler effect in the study of astronomy
TRUE OR FALSE in physics, every physical quantity is measured with respect to a unit. time is measured in seconds, length is measured in meters, and mass is measured in kilograms. knowing the units of physical quantities will help you solve problems in physics.
The unit of G is found out to be m³/kg * s².
The force of gravitational attraction is represented by the equation.
F = (G m₁ m₂)/r²
where,
F is the magnitude of the gravitational attraction on either body
m₁ and m₂ are the masses of the bodies,
r is the distance between them
G is the gravitational constant
We need to find the unit of G,
G = (F * r²)/(m₁ m₂)
Let us place the units for the above formula,
G = (N * m²)/kg²
N = kg m/s²
G = (kg * m * m²)/ kg² * s²
G = m³/kg * s²
Thus, the correct option is m³/kg * s².
The question is incomplete. The complete question is 'Gravity causes objects to be attracted to one another. This attraction keeps our feet firmly planted on the ground and causes the moon to orbit the earth. The force of gravitational attraction is represented by the equation.
F= Gm1 m2 /r^2
where F is the magnitude of the gravitational attraction on either body, m1 and m2 are the masses of the bodies, r is the distance between them, and G is the gravitational constant. In Sl units, the units of force are kg m/s^2, the units of mass are kg, and the units of distance are m. For this equation to have consistent units, the units of G must be which of the following?
a. kg^3/ms^2
b. kgs^2/m^3
c. m^3/kgs^2
d. m/kgs^2
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a particle moves under the influence of a conservative force. the equation for the potential energy as a function of position is given by: u(x)
A particle moves under the influence of a conservative force, The maximum x-coordinate of the particle at x = -3 m is 7 m.
Given that,
Potential energy of the particle u(x) = 5x² - 20x + 2
We know the relation between force and potential energy as,
F = -du/dx = -d/dx (5x² - 20x + 2) = -(10 x - 20 ) = 20 - 10 x at mean position x = 2.
At x = -3, amplitude is given by x = 2 - (-3) = 5
The maximum x co-ordinate is given as x = 5 + 2 = 7 m
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Design a parallel RLC circuit (see (Figure 1)) with a resonant radian frequency of 5000 rad/s. Take that L 10 mH.a) Find the value of C Express your answer to three significant figures and include the appropriate units. C= 4.00 μFb) Find the value of R so that the response is critically damped. Express your answer to three significant figures and include the appropriate units R- 25.0 Ω
The value of R so that the response is critically damped using the equation is 25.0Ω.
What is Farads?Farads is the unit of measure for capacitance, which is the amount of electrical charge stored for a given voltage. Farads can be used to measure the amount of energy stored in a capacitor, which is made up of two conductive plates separated by an insulating material. The higher the capacitance, the more energy can be stored in a given capacitor. Farads are named after Michael Faraday, the British scientist who discovered the relationship between electricity and magnetism.
The resonant frequency of an RLC circuit is given by the equation:
ω_r=1/sqrt(LC)
where ω_r is the resonant frequency in rad/s, L is the inductance in Henries, and C is the capacitance in Farads.
Given the resonant frequency of 5000 rad/s and the inductance of 10 mH, we can calculate the capacitance as follows:
C=1/(ω_r^2*L)
C=1/(5000^2*0.01)
C=4.00μF
We can find the value of R so that the response is critically damped using the equation:
R=2*sqrt(L/C)
R=2*sqrt(0.01/4.00)
R=25.0Ω
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NAME THAT DISORDER
For the following scenarios, identify the psychological disorder indicated (if there is definitely a disorder). Indicate the reason why you chose that diagnosis (i.e., what are the symptoms/behaviors presented). According to your textbook (or any other source you would like to use), what might be an appropriate course of treatment (use all that could apply) for the diagnosis you chose. Try to be as specific as possible.
Homework assignment is due prior to the start of class on WEDNESDAY, DECEMBER 14TH.
1. When Lila saw the policeman turn on his flashing blue lights and motion her to pull over, her heart rate increased, her mouth felt dry, and she quite nervous about what was going to happen.
2. Although doctors could find no evidence of brain damage, Ralph could not remember driving the car that was involved in the accident that resulted in the deaths of his wife and son.
3. When Sammi saw Andrea three months ago, Andrea was too busy to talk. She was involved in all kinds of plans for a vague new business that she was sure to make her a fortune. But just last week, Sammi heard that Andrea was feeling very low, was sleeping most of the time, and had given up all plans to do just about anything.
4. Timothy was having an increasingly difficult time completing his reading assignments. He was becoming unsure if what he was reading was really there or if his mind was making things up. This was not helped by the “kryptonite rays” being emitted by the smoke detector and the hidden camera spying on him from behind the mirror in his room.
5. Ever since her home was burglarized, Maria double checks to make sure the doors are locked before going to bed.
6. Randall is so afraid of bacteria that each day he must wash each dish and utensil three times in scalding, soapy water and then rinse each dish exactly twenty seconds. If he deviates from this ritual in the slightest way, he must wash all the dishes and utensils again.
7. Everything was hopeless. Francine felt that because she was such a horrible wife and mother she felt she didn’t deserve to live and that her husband should find a better person to be with. She cried all the time and couldn’t escape her sadness.
8. When the helicopter crash landed, Yusef was horrified. He and he pilot were injured and the gas tank could blow at any time. Although he had a broken arm, Yusef was able to pull both himself and the unconscious pilot out of the plane and to safety before it blew. But ever since that time, the unbroken arm he used to save himself and the pilot has been ‘paralyzed’ and Yusef does not appear to be too upset about it.
9. Carlos, who is turning 40, is very worried about having about having a heart attack since his brother, father, and grandfather died of heart attacks in their 40s.
10. On the way home, Celia found herself having difficulty breathing, and her heart was pounding so hard that she could barely see clearly. She pulled off the road where she continued to hyperventilate, feel dizzy, and have sweaty palms. After about 10 minutes or so, her breathing returned to normal and she continued on her drive home.
Where the exercise here is to name the disorder, note that:
It should be mentioned that medication (such as antidepressants or benzodiazepines) and/or counseling may be used to treat a panic disorder such as cognitive-behavioral therapy.
A suitable course of treatment for dissociative disorders may involve counseling (such as cognitive-behavioral therapy, trauma-focused therapy, or psychodynamic therapy) and/or medication.
The focus of psychodynamic therapy is on unconscious processes as they show in the client's current behavior. Client self-awareness and knowledge of the effect of the past on present behavior are the aims of psychodynamic therapy.
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A(n) ____________________ is a dynamic variable on the free store without any pointer pointing to it.
A inaccessible object is a dynamic variable on the free store without any pointer pointing to it.
How to find the height of an inaccessible object using sextant?Utilize the sextant's arc to determine the angle. By dividing the object's distance from the point of observation by the tan of the angle you calculated, you may use a scientific calculator to get the object's height.
How can heights and distances that are absent or unavailable be measured?The measuring of heights and distances that are unreachable is made easier by right-triangle trigonometry. By drawing a right triangle with the unknown height or distance as one of its sides and a known side and angle on the other, it is possible to determine the unknown height or distance.
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Answer:
dynamic variable
schedules of reinforcement farm workers are paid x amount of dollars for every basket of fruit that they pick
Schedules of reinforcement farm workers are paid x amount of dollars for every basket of fruit that they pick is based on the concept of fixed ratio.
A strengthening timetable, during which an answer or reaction is only strengthened after yet another given reaction can be determined, could be determined as a fixed ratio schedule. The particular topic gives a variety of questionnaires/solutions and therefore is subsequently rewarded by the educator or coach.
The man is under a fixed interval schedule of reinforcement, while the woman is under a fixed ratio schedule of reinforcement. Fixed interval reinforcement is a type of reinforcement that gives reward only after a specific period of time has passed. A fixed ratio reinforcement is a type of reinforcement that is based on production rate.
The other type is variable ratio. Variable Ratio schedule of reinforcement will give a person rewards after he/she fulfil a specific amount of works.
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A wire loop, 2 meters by 4 meters, of negligible resistance is in the plane of the page with its left end in a uniform 0.5-tesla magnetic field directed into the page, as shown above. A 5-ohm resistor is connected between points X and Y. The field is zero outside the region enclosed by the dashed lines.
If wire loop is being pulled to the right with a constant velocity of 3 meters per second , then the potential difference induced between points X and Y is 3V .
it is given that a 5Ω resistor is connected between points X and Y ;
the magnetic field (B) = 0.5 ;
length of wire (l) [tex]=[/tex] 2 ;
velocity of the wire loop (v) = 3 m/s ;
the potential difference will be induced because charge separation on the vertical hand wire of wire loop.
Points X and Y are the same as the top and bottom of left wire.
The EMF(potential difference) induced in wire is given by
EMF = B*l*v
substituting the values ,
we get
= (0.5)(2)(3) = 3V
Therefore , the induced potential difference between points X and Y is 3V .
The given question is incomplete , the complete question is
A wire loop, 2 meters by 4 meters, of negligible resistance is in the plane of the page with its left end in a uniform 0.5-tesla magnetic field directed into the page. A 5-ohm resistor is connected between points X and Y. The field is zero outside the region enclosed by the dashed lines. The loop is being pulled to the right with a constant velocity of 3 meters per second. Make all determinations for the time that the left end of the loop is still in the field, and points X and Y are not in the field.
Determine the potential difference induced between points X and Y.
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crane lifts a 400 kg crate upward with an acceleration of 3.00 m/?. Determine the force on the crane.
The crane is under 5120 N of force. The crane touches the rock boulder and uses mechanical force to lift it.
What are the units of a force?Force is a physical phenomenon that can change an object's shape as well as its state of motion or rest. The SI unit of force is the Newton.
Cranes fall under which of the following three forces?Jib, gantry, and overhead cranes are the three pieces of machinery used most frequently in the industry. Depending on the type of item to be moved, either a chain or wire rope hoist will be used. In the shipbuilding sector, material handling is the main use of overhead cranes during the assembly process.
Briefing:
Mass (m) = 400kg
Acceleration (a) = 3.00 m/s^2
Gravitational acceleration (g) = 9.81 m/s^2
Force (F) = mg + ma
Force (F) = m (g + a)
Force (F) = 400 (9.81+3)
Force (F) = 5120 N
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Field poles are electromagnets whose ____ change as the flow of current alternates in the field windings.
Field poles are electromagnets whose polarities change as the flow of current alternates in the field windings.
An electromagnet is a sort of magnet wherein the magnetic area is produced with the aid of an electric current. Electromagnets generally encompass cord wounds into a coil. A cutting edge through the wire creates a magnetic discipline that is focused inside the hole in the middle of the coil.
Electromagnets create a magnetic discipline through the application of power. When you introduce the modern, either from a battery or any other supply of strength, it flows through the wire. This creates a magnetic discipline around the coiled cord, magnetizing the metal as though it were a permanent magnet.
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A staging that weighs Wstaging supports a painter weighing 300 N. The reading on the left scale is 580 N and the reading on the right scale is 270 N. What is the weight of the staging?
The weight of the staging is 550N.
The weight of an object, the gravitational force caused by the presence of a large second object such as the Earth or the Moon.
The unit of measurement for weight is indeed a unit of force. This unit in the International System of Units (SI) is the Newton.
Given data : Weight of the painter ([tex]W_{p}[/tex]) = 300 N
Left scale's weight reading [tex](W_{L} )[/tex] = 580 N
Right scale's weight reading [tex](W_{R} )[/tex] = 270 N
To find the weight of the staging [tex](W_{s} )[/tex], we will set all the weight in the equilibrium.
Since the force of the staging and painter's weight is going downward we will denote them as negative. The opposite will be placed for the reading of weight on the left and right scale, which is positive.
[tex]-W_{p} -W_{s} +W_{L}+W_{R} = 0[/tex]
[tex]-300N-W_{s} +580N + 270N = 0\\[/tex]
[tex]W_{s}[/tex] [tex]= -300N+580N+270N[/tex]
[tex]W_{s}[/tex] [tex]= 550N[/tex]
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when the glass gob comes out of the oven, it is dangerously hot. What happens to the thermal energy of the gob between that time and when it is a bottle than can be touched?
Answer:
decreases
Explanation:
The thermal energy of the gob decreases by heating the air around the gob and the mold in which the bottle is made
Joan is initially driving her car at 10 m/s when she decides to go faster. She accelerates uniformly at 4 m/s2 for 100 meters. How fast is Joan going?
a
50 m/s
b
35 m/s
c
30 m/s
d
26 m/s
Joan is going with speed 30 m/s. Hence, option (C) is correct.
What is acceleration?Acceleration is the rate at which a velocity changes over time. It qualifies as a vector quantity because it possesses both direction and magnitude. Meter/second^2 (m/s^2) is the SI unit of acceleration.
Given that: initial speed of the car: u = 10 m/s.
Uniform acceleration of the car: a = 4 m/s^2.
Distance travelled: s = 100 meters.
Let, the final speed is = v
Using the formula v² = u² + 2as, we get:
v = √(10² + 2×4×100) m/s.
= 30 m/s.
Hence, final speed of the car is 30 m/s.
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Students will design an experiment to determine how the magnitude of the force on a segment of straight, current-carrying wire depends on the length of the wire segment and on the strength of the magnetic field. Which of the following experimental procedures will allow the students to determine both of these relationships? A Making measurements of the force on several different straight segments of wire, increasing the length of the wire and increasing the magnetic field strength with each measurement. B Making measurements of the force on several different straight segments of wire, increasing the length of the wire and decreasing the magnetic field strength with each measurement с Making measurements of the force on several different straight segments of wire, keeping the length of the wire constant while increasing the magnetic field strength with each measurement. D Making measurements of the force on several different straight segments of wire, increasing the length of the wire while keeping the magnetic-field strength the same with each measurement, then repeating the measurements while decreasing the length of the wire and increasing the magnetic field strength with each measurement E Making measurements of the force on several different straight segments of wire, increasing the length of the wire while keeping the magnetic-field strength constant with each measurement, then repeating the measurements while keeping the length of the wire constant while increasing the magnetic field strength with each measurement.
The experimental procedures that will allow the students to determine both of these relationships is option E:
Making measurements of the force on several different straight segments of wire, increasing the length of the wire while keeping the magnetic-field strength constant with each measurement, then repeating the measurements while keeping the length of the wire constant while increasing the magnetic field strength with each measurement.What happens to the magnetic field when the length of wire increases?The formula F = IL x B calculates the magnetic force acting through a magnetic field on a current-carrying wire. The magnetic field acts on a wire when a current is conducted through it in a direction that is perpendicular to both the magnetic force.
By increasing the amount of current flowing through the wire, the magnetic field's strength can be enhanced. As you get further from the wire, the strength gets weaker. If the amount of current flowing through it stays constant, its length and thickness have no bearing.
Therefore, the length of the wire in the magnetic field has an impact on the magnetic force's strength as well. The force acting on a wire increases with wire length in a magnetic field.
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Two point-like particles, each of mass m, are originally separated by a distance d and moving in opposite directions each with a speed of v. What is the maximum value for v so that the particles will eventually move back together under the influence of the mutual gravitational attraction?
The angular momentum of a system does not depend on the point about which it is taken, according to equation (iv). the particles eventually move back together because of mutual gravitational attraction.
How to repair?As depicted in the following diagram, assume that two particles are present at positions P and Q at some point in time.
Think about a point R that is y miles away from a point Q, or QR=y PR=dy.
LP=mv0+mvd=mvd is the system's angular momentum around point P.
I The system's angular momentum around point Q is given by LQ=mvd+mv0=mvd.....(ii)
System's angular momentum about point R is given by LR=mv(d, y)+mv(y, d)=mvd....(iii)
The result of comparing equations I (ii), and (iii) is L P = LQ = LR....... (iv)
The angular momentum of a system does not depend on the point about which it is taken, according to equation (iv).
What causes the gravitational pull of objects?All objects with mass are attracted to one another by the gravitational attraction, which has a magnitude that is directly proportional to the masses of the two objects and inversely proportional to the square of their distance from one another.
What are the benefits of gravitational attraction?Our feet remain firmly planted on the ground thanks to gravity, which also keeps the Moon in orbit around the Earth, the Earth in orbit around the Sun, the Sun in orbit around the galactic core of our Milky Way galaxy, and the Milky Way and Andromeda galaxies orbiting each other.
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based on the graphic, in what part of the electromagnetic spectrum does vegetation have the strongest response?
Between 400 nm and 700 nm of the electromagnetic spectrum, vegetation has the strongest response.
The electromagnetic spectrum travels in waves and spans an extensive spectrum from very long radio waves to very brief gamma rays. The human eye can simplest come across only a small portion of this spectrum called visible light.
In order from maximum to lowest power, the sections of the EM spectrum are named: gamma rays, X-rays, ultraviolet radiation, visible mild, infrared radiation, and radio waves.
In a tumbler, the purple mild travels the fastest, and the violet light travels the slowest of all seven hues. Velocity and wavelength are without delay proportional.
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if an object producing sound is moving away from you, you would observe a wavelength than an object moving toward you. group of answer choices
If an object producing sound is moving away from us, the wavelength of the sound heard is longer than the actual wavelength. The conclusion is from the concept of Doppler effect.
What is the Doppler effect?The Doppler's effect is a phenomenon when the source of a wave and an observer move relative to each other, the frequency heard is not the same with the actual frequency.
The equation of the Doppler effect is
f₀ = [(v ± v₀)/(v ± vs)] × fs
Where
f₀ = observer frequency of soundv = speed of sound waves (340 m/s)v₀ = observer velocityvs = source velocityfs = actual frequency of sound wavesNote:
v₀ (+) if the observer moves closer to the sound source.vs (+) if the sound source moves away from the observer.When an object producing sound is moving away from us, the frequency of the sound we heard changed.
Let's say we are at rest, it means v₀ = 0. The sound source is moving away makes vs (+).
With the Doppler's effect, we get
f₀ = [(v+0) / (v+vs)] × fs
f₀/fs = v/(v+vs)
v < v+vs
f₀ < fs
The frequency of sound we heard is lower that the actual frequency.
The wavelength is inversely proportional to the frequency. It is described in the equation:
λ = c/f
It means that the lower the frequency, the longer the wavelength.
Hence, the phenomenon which the wavelength of the sound we heard is longer than the actual wavelength when the sound source is moving away from us is called the Doppler's effect.
Here is the group of answer choices:
(a) Band width
(b) Doppler's effect
(c) Sound refraction
(d) Vibrations
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What does the law of conservation of energy state?
energy cannot be destroyed but it can change forms
energy always gets used up in every chemical reaction
energy can be destroyed but not created
energy is always the same and it cannot be changed
I think it is "energy cannot be destroyed but it can change forms".
which of the following sequences lists methods for determining distance in the correct order from nearest to farthest?
Parallax, main-sequence fitting, cepheid variables, Tully-Fisher relation, and Hubble's law are the sequence lists methods for determining distance.
Parallax is the closest method for determining distance. This method uses the principle of triangulation to measure the distance of a nearby star relative to Earth. Main-sequence fitting is another method used to measure the distance of stars. This method compares the brightness of a star to other stars of known distance and luminosity to determine its distance.
Cepheid variables are stars whose brightness varies in a predictable way over time. This method uses the period of the star's brightness to determine its intrinsic luminosity, and then its distance. The Tully-Fisher relation is a method for measuring the distance of galaxies. This method uses the rotation speed of the galaxy and its brightness to calculate its distance.
Finally, Hubble's law is the most distant method for determining distance. This law states that the farther away a galaxy is, the faster it moves away from us. This allows us to calculate the distance of galaxies by measuring their rate of recession.
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In the figure, a climber leans out against a vertical ice wall that has negligible friction. Distance a is 0.945 m and distance L is 1.95 m. His center of mass is distance d = 0.89 m from the feet-ground contact point. If he is on the verge of sliding, what is the coefficient of static friction between feet and ground?
The coefficient of static friction between feet and ground is 0.2522.
What is static friction?Static friction is defined as when there is no motion between the two surfaces, the force that one surface applies to another. The friction that exists between two or more objects when they are not moving relative to one another is referred to as static friction.
The coefficient of static friction between his feet and the ground, denoted by the symbol s, determines how to express the frictional force as
fs =μsFN1
The μs can be calculated as
μs = a / √L² - a² x d / L
μs = 0.945 / √(1.95)² - (0.945)² x 0.89 / 1.95
μs = 0.945 / √2.91225 x 0.89 / 1.95
μs = 0.2522
Thus, the coefficient of static friction between feet and ground is 0.2522.
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When the turntable is turned on and rotates at 45.0 rev/min, calculate the centripetal force needed to keep the fly from slipping?
The centripetal force needed to keep the fly from sleeping will be zero point 0.00176 Newton in magnitude.
The mass of the fly is 2 gram and it is selling itself on a phonograph turntable.
The fly is at a distance of 4 cm away from the center of the phonograph turntable and when the turntable is turned on and retreats with 45 Revolution per minute the centripetal force that would be working on the fly will be given by,
F = Mw²R
Where,
M is mass of the fly,
w is the angular speed of the fly and,
R is the radius of the turnable.
Putting all the values,
F = 0.002×(4.7)²×0.04
F = 0.00176N.
So, a centripetal force of magnitude 0.00176 Newton will be required in order to keep the fly from slipping.
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Complete question- A fly of mass 2.00 g is sunning itself on a phonograph turntable at a location that is 4.00 cm from the center. When the turntable is turned on and rotates at 45.0 rev/min, calculate the centripetal force needed to keep the fly from slipping?
Question 9 of 25
Describe the path of the light ray that hits a mirror after passing through its
focus.
OA. It reflects back through the focus.
B. It hits the mirror and reflects back exactly the way it came in.
C. It is refracted through the mirror.
D. It is reflected back parallel to the principal axis.
SUBMIT
The path taken by a light beam after passing through a mirror's focus is where it hits the mirror and reflects back in exactly the same direction as it went in.
What, when striking the surface, causes the light to reflect back?Specular reflection is the name for this. A smooth surface allows light to bounce back at the same angle that it was incident. Rays of light that are reflected off of a smooth surface go in that same direction.
Where does a light beam travel?The narrow beams of light that travel in straight lines along their courses as electromagnetic waves are known as rays. Though its path might be altered by reflection or refraction, light always moves in a straight line.
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For a particular nonlinear spring, the relationship betweem the magnitude of the applied force F and the resultant displacement x from equilibrium is given by the equation F = k x^2 What is the amount of work done by stretching the spring a distace x0? A) kx0^3 B) (1/2)kx0 C) (1/2)kx0^3 D) (1/3)kx0^2 E) (1/3)kx0^3
To get the work, you have to integrate the force as a function of [tex]$x$[/tex] from zero displacement to Xo
[tex](Integral of) $\mathrm{k} \mathrm{x}^{\wedge} 2 \mathrm{dx}$ from 0 to $\mathrm{Xo}_{\mathrm{o}}=(1 / 3) \mathrm{k}\left(\mathrm{Xo}^{\wedge}\right)^{\wedge} 3$[/tex]
The work done by stretching the spring to the given distance is [tex]W=\frac{k x_0}{3}[/tex]
The given parameters:
- Applied force on the spring [tex]$=F$[/tex]
- Extension of the spring [tex]$=x_0$[/tex]
The work done by stretching the spring to the given distance is calculated as follows;
[tex]W=\frac{k x_0}{3}[/tex]
[tex]$$\begin{aligned}& W=\int_{x_a}^{x_b} F d x \\& W=\int_{x_a}^{x_b} k x^2 d x \\& W=k \int_{x_a}^{x_b} x^2 d x \\& W=k\left[\frac{x^3}{3}\right] \\& W=k\left[\frac{x_b-x_a}{3}\right] \\& W=k\left[\frac{x_0-0}{3}\right] \\& W=\frac{k x_0}{3}\end{aligned}[/tex]
Thus, the work done by stretching the spring to the given distance is
[tex]W=\frac{k x_0}{3}[/tex]
measure of energy transfer that occurs when an object is moved over a distance by an external force at least part of which is applied in the direction of the displacement.
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a hydraulic lift (jack) has two pistons, one large and one small. the pistons are at the same elevation. if it is equilibrium, which piston exerts the greatest force
The force exerted at the large piston will be double in magnitude in comparison with the force applied at the smaller piston.
We know, according to the pascal's law,
The pressure applied at any point in the incompressible fluid is equal in magnitude at each and every point.
So,
P = Force/Area
Where P is pressure,
If pressure is same, then we can write,
F₁/A₁ = F₂/A₂
Where,
F₁ is the force applied at the small piston,
A₁ is the area of the smaller piston,
F₂ is the force at the larger piston,
A₂ is the area of the larger piston,
It is also given that, area if the larger piston is two times the area of the smaller piston so,
A₂ = 2A₁
So, putting the values we get,
F₂/F₁ = 2
So, F₂ = 2F₁
It means that the force exerted by the larger piston will be double in magnitude.
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(1) A table tennis ball is dropped
onto the floor from a height of
4m and it rebounds to a height of
3m. If the time of contact with the floor is 0.01s, what is the magnitude and direction of the acceleration during the contact.
Answer:
Here, h1=4.00m,h92)=3.00m,Delta t =0.01 s.Letv1 be the velocity of the ball (actind downwards) just before striking the floor an dv20 be the velocity of the ball (acting upwaeds) ust after striking the floor. Then, change in velocity of the ball in time Δtv2−(−v1)v2+v1
:. acceleration, a=v2+v1Δt ..(i)
When body falls from height h1,
then u=o,v1,a=gandS=h1
As, v21=u2+2aS,
:. v_(1) ^(2) =0 + g h_(10 or v12–√gh1
Taking motion of the ball after striking the floor, then u=v2,v=0,a=−g,S=h2
As, v2=u22as,∴v21=0+2gh1orv_(1) =sqrt 32 g h_(1)Tak∈gmotionoftheballa>erstrik∈gthe⌊,⌋thenu=v_(2), v=0, a=- g, S=h_(2)As,v2=u2+2aS,wehave0 = v_(2)^(2) +2 (-g) h_92) otr v2=2–√gh2
Putting values in (i) we get,
a=2–√gh2+2–√gh1Δt)
a=2–√×9.8×3+2–√×9.8×40.01
= 1652m/s2.
Explanation:
A certain 50.0-Hz AC power line radiates an electromagnetic wave having a maximum electric field strength of 13.0 kV/m. (a) What is the wavelength of this very low frequency electromagnetic wave? (b) What is its maximum magnetic field strength?
An electromagnetic wave radiating from a specific 50.0-Hz AC power line has a maximum electric field strength of 13.0 kV/m. This extremely low frequency electromagnetic pulse has a wavelength of 6.00 x [tex]10^{6}[/tex]m.
An electromagnetic wave is what?A sinusoidal graph illustrates electromagnetic waves. It is made up of time-varying electric and magnetic fields that are perpendicular to each other and to the direction that waves travel.
How do wavelength and frequency relate to one another?Inverse proportionality describes the relationship between frequency and wavelength. Longer wavelengths are correlated with lower frequency, and vice versa. The fact that a wave's speed is equal to the product of its frequency and wavelength helps to explain how these two properties are related.
Briefing:
Given that,
Frequency of the power line, f = 50.0 Hz
Value of maximum electric field strength of 13.0 kV/m
The wavelength of this very low frequency electromagnetic wave is given by using relation as:
[tex]c = f[/tex]λ
λ [tex]= \frac{c}{f}[/tex]
λ [tex]= \frac{3.8 * 10^{8} m/s }{50}[/tex]
λ = 6 x [tex]10^{6}[/tex] m
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