A square has a perimeter of 24cm. Work out its area.​

Answers

Answer 1

Answer:

A = 36 cm^2

Step-by-step explanation:

The perimeter of a square is given by

P =4s

24 = 4s

Divide by 4

24/4 = 4s/4

6 =s

The area of a square is

A =s^2

A = 6^2

A = 36 cm^2


Related Questions

The cost for an upcoming field trip is $30 per student. The cost of the field trip C. in dollars, is a function of the number of students x.

Select all the possible outputs for the function defined by
C(x)=30
a. 20
b. 30
c. 50
d. 90
e. 100​

Answers

Answer: B and D

Step-by-step explanation: since it is $30 per student the total cost would have to be a multiple of 30

PLEASE HELP!!!
Which expression shows a way to find the area of the following rectangle?

Answers

Answer:

B

Step-by-step explanation:

This rectangle appears to have 7 boxes on the bottom, and 3 box for the side.

Since area is base×height

It would be 7×3

B- 7x3 to find the area you do l•w the pic shows 6x2 but u can see there’s room for another square

A man died leaving property
worth 49000 for his three daughters and a son. Find out the share of each in inheritance?

Answers

Answer:

49000

Step-by-step explanation:

since it's the same worth

Answer:

49000

Step-by-step explanation:

since there was the same worth given to all

Al’s Produce Stand sells 6 ears of corn for $1.50. Barbara’s Produce Stand sells 13 ears of corn for $3.12. Write two equations, one for each produce stand, that model the relationship between the number of ears of corn sold and the cost.

Answers

Answer:

6n = 1.50

and

13n = 3.12

Step-by-step explanation:

Here in this question, we are interested in writing equations that relate the number of ears of corn sold and the cost.

For Al’s produce stand, let the price per corn sold be n

Thus;

6 * n = 1.50

6n = $1.50 •••••••(i)

For the second;

let the price per corn sold be n;

13 * n = $3.12

-> 13n = 3.12 •••••••••(ii)

If we did not write the equation 5x=21, instead we wrote it 21=5x,
we would get a different solution.
O True
O False

Answers

True we would get a different solution

Answer:

Step-by-step explanation:

5x = 21 and 21 = 5x are identical relationships, and so the solution would be the same in both cases.  (Commutative Property:  order of addition/subtraction is immaterial)

A shell of mass 8.0-kg leaves the muzzle of a cannon with a horizontal velocity of 600 m/s. Find the recoil velocity of the cannon, if its mass is 500kg.

Answers

Answer:

velocity of recoil velocity of cannon  is -9.6 m/sec

Step-by-step explanation:

according to law of conservation of momentum

total momentum of isolated system of body remains constant.

momentum  = mass of body* velocity of body.

__________________________________

in the problem the system is

shell + cannon

momentum of shell = 8*600 = 4800 Kg-m/sec

let the velocity of cannon be x m/sec

momentum of cannon = 500*x = 500x Kg-m/sec

initially the system of body is in rest (before the shell is fired) hence, total momentum of the system i is 0

applying  conservation of momentum

total momentum before shell fired = total momentum after the shell is fired

0 = momentum of shell + momentum of cannon

4800 + 500x = 0

x = -4800/500 = -9.6

Thus, velocity of recoil velocity of cannon  is -9.6 m/sec

here negative sign implies that direction of velocity of cannon is opposite to that of velocity of shell.

Loreto quería decorar un viejo tambor metálico para usarlo de paragüero. Para ello, contaba con un grueso cordón que pretendía pegar en el contorno del borde superior del tambor. Sabiendo que el diámetro de este era 58,5 cm, cortó el cordón, dejando el trozo más largo de 175,5 cm de longitud de modo que le alcanzara justo, pero le faltaron 7 cm. ¿Cuál fue el error de Loreto?

Answers

Answer:

u should put the question in English to so English people can also help

April typed a 5 page report in 50 mintues. Each page had 500 words at what rate is April typing

Answers

Answer:

Amy types at a rate of 50 words per minute

Step-by-step explanation:

In this question, we are interested in calculating the rate at which April is typing.

From the question, we can deduce that she typed a 5 page report, with each page having a total of 500 words.

Now, if each page has 500 words, the total number of words in all of the pages will be 5 * 500 = 2,500 words

Now, from here, we can see that 2,500 words were typed in 50 minutes.

The number of words per minute will be ;

Total number of words/Time taken = 2500 words/50 minutes

That will give a value of 50 words per minute

A cyclist travels at $20$ kilometers per hour when cycling uphill, $24$ kilometers per hour when cycling on flat ground, and $30$ kilometers per hour when cycling downhill. On a sunny day, they cycle the hilly road from Aopslandia to Beast Island before turning around and cycling back to Aopslandia. What was their average speed during the entire round trip?

Answers

Answer:

Average speed during the trip = 24 km/h

Step-by-step explanation:

Given:

Speed of cyclist uphill, [tex]v_1[/tex] = 20 km/hr

Speed of cyclist on flat ground = 24 km/h

Speed of cyclist downhill, [tex]v_2[/tex] = 30 km/h

Cyclist has traveled on the hilly road to Beast Island from Aopslandia and then back to Aopslandia.

That means, one side the cyclist went uphill will the speed of 20 km/h and then came downhill with the speed of 30 km/h

To find:

Average speed during the entire trip = ?

Solution:

Let the distance between Beast Island and Aopslandia = D km

Let the time taken to reach Beast Island from Aopslandia = [tex]T_1\ hours[/tex]

Formula for speed is given as:

[tex]Speed = \dfrac{Distance}{Time}[/tex]

[tex]v_1 = 20 = \dfrac{D}{T_1}[/tex]

[tex]\Rightarrow T_1 = \dfrac{D}{20} ..... (1)[/tex]

Let the time taken to reach Aopslandia back from Beast Island = [tex]T_2\ hours[/tex]

Formula for speed is given as:

[tex]Speed = \dfrac{Distance}{Time}[/tex]

[tex]v_2 = 30 = \dfrac{D}{T_2}[/tex]

[tex]\Rightarrow T_2 = \dfrac{D}{30} ..... (2)[/tex]

Formula for average speed is given as:

[tex]\text{Average Speed} = \dfrac{\text{Total Distance}}{\text{Total Time Taken}}[/tex]

Here total distance = D + D = 2D km

Total Time is [tex]T_1+T_2[/tex] hours.

Putting the values in the formula and using equations (1) and (2):

[tex]\text{Average Speed} = \dfrac{2D}{T_1+T_2}}\\\Rightarrow \text{Average Speed} = \dfrac{2D}{\dfrac{D}{20}+\dfrac{D}{30}}}\\\Rightarrow \text{Average Speed} = \dfrac{2D}{\dfrac{30D+20D}{20\times 30}}\\\Rightarrow \text{Average Speed} = \dfrac{2D\times 20 \times 30}{{30D+20D}}\\\Rightarrow \text{Average Speed} = \dfrac{1200}{{50}}\\\Rightarrow \bold{\text{Average Speed} = 24\ km/hr}[/tex]

So, Average speed during the trip = 24 km/h

Answer it answer it answer it.

Answers

Answer:

Option C. P = 3/q

Step-by-step explanation:

To know the the correct answer to the question, do the following:

Let us assume a certain number for P say 2 and 3, and then, find the corresponding value for q in each case to see which will give a decreased value for q.

Option A

When P = 2, q =.?

P = 3q

2 = 3q

Divide both side by 3

q = 2/3

When P = 3, q =.?

P = 3q

3 = 3q

Divide both side 3

q = 3/3

q = 1

From the above illustration, we can see that as P increase, q also increase.

Option B

When P = 2, q =.?

P – 3 = q

2 – 3 = q

q = – 1

When P = 3, q =.?

P – 3 = q

3 – 3 = q

q = 0

From the above illustration, we can see that as P increase, q also increase.

Option C

When P = 2, q =.?

P = 3/q

2 = 3/q

Cross multiply

2 × q = 3

Divide both side by 2

q = 3/2

q = 1.5

When P = 3, q =.?

P = 3/q

3 = 3/q

Cross multiply

3 × q = 3

Divide both side by 3

q = 3/3

q = 1

From the above illustration, we can see that as P increase, q decreases.

Option D.

When P = 2, q =.?

1/p = 3/q

1/2 = 3/q

Cross multiply

1 × q = 2 × 3

q = 6

When P = 3, q =.?

1/p = 3/q

1/3 = 3/q

Cross multiply

1 × q = 3 × 3

q = 9

From the above illustration, we can see that as P increase, q also increase.

Now, haven done the above, only option C gives a decreased value for q as the value of P increases.

c  

this before

Step-by-step explanation:

20 PTS PLEASE HELP!!!!

Select the correct answer from each drop-down menu.

The function below describes the number of students who enrolled at a university, where f(t) represents the number of students and t represents the time in years.


Initially, (1.03, 3, 19,055, 18,500) students enroll at the university. Every,(1years, t years, 2years, 3years) the number of students who enroll at the university increases by a factor of (1.03, 3, 19,055, 18,500).

Answers

Answer:

Initially 18,500 students

Every 1 year

increase by a factor 1.03

Step-by-step explanation:

The missing information is selected from the given options from the drop down menu. The correct answers are : Initially 18,500 students enroll at the university. Every 1 years the number of students who enroll at the university increases by a factor 1.03.

F(t) = 18,500 * (1.03)^t

if your ans is correct i will choose you as a brainlist when the number of student of a school was increased by 30% it became 455. Find the previous number student.

Answers

Step-by-step explanation:

find 30% of 455

which is = 136.5

then subtract 136.5 from the original number(455)

455 - 136.5

=318.5 student

Previous number student was 350

The drama club is selling tickets to its play. An adult ticket costs $15 and a student ticket costs $11. The auditorium will seat 300 ticket-holders. The drama club wants to collect at least $3630 from ticket sales.

Answers

Answer:

83 adult tickets and 217 student tickets.

Step-by-step explanation:

Let number of adult tickets sold = [tex]x[/tex]

Given that total number of tickets = 300

So, number of student tickets = 300 - [tex]x[/tex]

Cost of adult ticket = $15

Cost of student ticket = $11

Total collection from adult tickets = $[tex]15x[/tex]

Total collection from student tickets =  [tex](300-x)\times 11 = 3300-11x[/tex]

Given that overall collection = $3630

[tex]15x+(3300-11x) = 3630\\\Rightarrow 15x-11x=3630-3300\\\Rightarrow 4x = 330\\\Rightarrow x = 82.5[/tex]

So, for atleast $3630 collection, there should be 83 adult tickets and (300-83 = 217 student tickets.

Now , collection = $3632

Manuel made at least one error as he found the value of this expression. Identify the step in which Manuel made his first error. After identifying the step with the first error, explain the corrected steps and find the final answer.

Answers

Answer:

Manuel made his first mistake in step 2 leading to the continuous mistakes

Final answer=185

Step-by-step explanation:

Manuel made at least one error as she found the value of this expression. 2(-20) + 3[5/4(-20)] + 5[2/5(50)] + 4(50) Step 1: 2(-20) + 3(-25) + 5(20) + 4(50) Step 2: (3 + 2)(-20 + -25) + (5 + 4)(20 + 50) Step 3: 5(-45) + 9(70) Step 4: -225 + 630 Step 5: 405 Identify the step in which Chris made her first error. After identifying the step with the first error, write the corrected steps and find the final answer.

2(-20) + 3[5/4(-20)] + 5[2/5(50)] + 4(50)

Step 1: 2(-20) + 3(-25) + 5(20) + 4(50)

Step 2: -40 - 75 + 100 +

200

Step 3: -115 + 300

Step 4: 185

Manuel made his first error in step 2 by combining two different terms into one as he has done

(3 + 2)(-20 + -25) and also (5 + 4)(20 + 50)

Step 2: (3 + 2)(-20 + -25) + (5 + 4)(20 + 50)

Step 3: 5(-45) + 9(70) Step 4: -225 + 630 Step 5: 405

He should have evaluated the terms separately as I have done above, giving us 185 as the final answer in contrast to his 405 final answer.

Identify whether each phrase is an expression, equation, or inequality.
Term
Phrase
Expression
3 - 53 =y
Inequality
7-5 <2.9
2 + 0
Equation
24"
t

Answers

Answer:

The identities of the terms are;

3 - 53 = y is an equation

7.5 < 2.9 is an inequality

2 + 0 is an expression

t is a term

24" is a term

Step-by-step explanation:

An equation is an expression with the equal to sign

3 - 53 = y is an equation

An inequality is a mathematical expression that contains an inequality sign

7.5 < 2.9 is an inequality

A term is a sole number or variable or the product of variables and numbers that come before and after mathematical operators such as +, ×, -, or ÷

t and 24" are terms.

1) Complete the table
2) find the mean of the random variable x. Use the formula in the photo

Answers

Answer:

a. Please check the explanation for filling of the empty column on the table

b. The mean of the random variable x is 7/11

Step-by-step explanation:

a. Firstly, we are concerned with completing the table.

To do this, we simply need to multiply the values in the column of x by the values in the column of p(x)

Thus, we have the following;

2. 3 * 2/36 = 6/36

3. 4 * 3/36 = 12/36

4. 5 * 4/36 = 20/36

5. 6 * 5/36 = 30/36

6. 7 * 6/36 = 42/36

7. 8 * 5/36 = 40/36

8. 9 * 4/36 = 36/36

9. 10 * 3/36 = 30/36

10. 11 * 2/36 = 22/36

11. 12 * 1/36 = 12/36

b. We want to find the mean of the random variable x.

All what we need to do here is add all the values of x•P(x) together, then divide by 11.

Thus, we have

(2/36 + 6/36 + 12/36 + 20/36 + 30/36 + 42/36 + 40/36 + 36/36 + 30/36 + 22/36 + 12/36)/11

Since the denominator is same for all, we simply add all the numerators together;

(252/36) * 11 = 252/396 = 63/99 = 7/11

Find the length of the base and the height and calculate the area

Answers

Answer:

44

Step-by-step explanation:

base = 3- -5 = 8

height = 8 - -3 = 11

1/2 bh

1/2(8)(11) = 44

Find the total surface area.

Answers

Answer:

143.4 mi²

Step-by-step explanation:

Top: 8x6=48

Bottom: 3x8=24

Sides: 3x8=24 and 24

Trapezoids sides: (6+3)/2*2.6=4.5*2.6=11.7 and 11.7

TOTAL: 48+24+24+24+11.7+11.7= 143.4 mi²

Can someone plz help me ASAP!!!!!!!!

Answers

Answer:

A) The number halfway between -2 and 6 is 2.

B) -10 is halfway between -18 and 8

6 points are place on the line a, 4 points are placed on the line b. How many triangles is it possible to form such that their verticies will be the given points, if a ∥b?

Answers

Answer: 96

Step-by-step explanation:

Ok, lines a and b are parallel.

We can separate this problem in two cases:

Case 1: 2 vertex in line a, and one vertex in line b.

Here we use the relation:

"In a group of N elements, the total combinations of sets of K elements is given by"

[tex]C = \frac{N!}{(N - K)!*K!}[/tex]

Here, the total number of points in the line is N, and K is the ones that we select to make the vertices of the triangle.

Then if we have two vertices in line a, we have:

N = 6, K = 2

[tex]C = \frac{6!}{4!*2!} = \frac{6*5}{2} = 3*5 = 15[/tex]

And the other vertex can be on any of the four points on the line b, so the total number of triangles is:

C = 15*4 = 60.

But we still have the case 2, where we have 2 vertices on line b, and one on line a.

First, the combination for the two vertices in line b is:

We use N = 4 and K = 2.

[tex]C = \frac{4!}{2!*2!} = \frac{4*3}{2} = 6[/tex]

And the other vertice of the triangle can be on any of the 6 points in line a, so the total number of triangles that we can make in this case is:

C = 6*6 = 36

Then, putting together the two cases, we have a total of:

60 + 36 = 96 different triangles

G(x)= -\dfrac{x^2}{4} + 7g(x)=− 4 x 2 ​ +7g, left parenthesis, x, right parenthesis, equals, minus, start fraction, x, squared, divided by, 4, end fraction, plus, 7 What is the average rate of change of ggg over the interval [-2,4][−2,4]open bracket, minus, 2, comma, 4, close bracket?

Answers

Answer:

-1/2

Step-by-step explanation:

Given the function [tex]G(x)= -\dfrac{x^2}{4} + 7[/tex], the average rate of change of g(x) over the interval [-2,4], is expressed as shown below;

Rate of change of the function is expressed as g(b)-g(a)/b-a

where a - -2 and b = 4

[tex]G(4)= -\dfrac{4^2}{4} + 7\\G(4)= -\dfrac{16}{4} + 7\\G(4)= -4 + 7\\G(4) = 3\\[/tex]

[tex]G(-2) = -\dfrac{(-2)^2}{4} + 7\\G(-2)= -\dfrac{4}{4} + 7\\G(-2)= -1 + 7\\G(-2)= 6[/tex]

average rate of change of g(x) over the interval [-2,4] will be;

[tex]g'(x) = \frac{g(4)-g(-2)}{4-(-2)}\\ g'(x) = \frac{3-6}{6}\\\\g'(x) = -3/6\\g'(x) = -1/2[/tex]

Find the coefficient of third term of (2x−1)^6.

Answers

240

using pascals trianle

for the power 6 it is

1, 6,15,20, 15,6, 1

and for the third term (2x)^4 and (-1)^2

[tex]15 \times {(2x)}^{4} \times {( - 1)}^{2} [/tex]

[tex]240 {x}^{4} [/tex]

Since only the coefficient is needed

the answer is 240.

The required coefficient of third term is 480.


Coefficient of the third term of (2x−1)^6 to be determine.

What is coefficient?

Coefficient is defined as the integer present adjacent to the variable.

Here,  (2x−1)^6
Using binomial expansion,
Third term = P(6,2)(2x)^6-2(-1)^2
                  =   6*5*16x^4
                  = 480x^4

Thus, the required coefficient of third term is 480.


Learn more about coefficient here:

https://brainly.com/question/2507029

#SPJ2

Angles L and M are supplementary. What is the sum of
their measures?
The sum of the measures of angles L and M is

Answers

180 degree

Step-by-step explanation:

supplementary means anhke havinv sum of 180 degree

so sum to two supplemrntary angles is 180 drgree

Answer: 180

Supplementary angles always add to 180.

One way I think of it is "supplementary angles form a straight angle", and both the words "supplementary" and "straight" start with the letter "S".

In contrast, complementary angles form a corner. Both "complementary" and "corner" start with "co". By "corner", I mean a 90 degree corner.

jim buys a calculator that is marked 30% off. If he paid $35, what was the original price?

Answers

Answer:

x = 50

Step-by-step explanation:

Let x be the original price.

He got 30% off

The discount is .30x

Subtract this from the original price to get the price he paid

x - .30x = price he paid

.70x = price he paid

.70x = 35

Divide each side  by .7

.70x/.7 = 35/.7

x=50

The answer is- $45.05

A timeline. 27 B C E to 180 C E PAX ROMANA. 44 B C E The Roman Empire was founded. 80 C E The Colosseum was built. 121 C E Hadrian's Wall was built in England to keep out enemies. 306 C E Constantine became emperor.
How many years passed between the building of the Colosseum and the building of Hadrian’s Wall?

201
121
41
36

Answers

Answer:

the answer is 41

Step-by-step explanation:

C. 41

Step-by-step explanation:

A study was conducted on students from a particular high school over the last 8 years. The following information was found regarding standardized tests used for college admitance. Scores on the SAT test are normally distributed with a mean of 982 and a standard deviation of 198. Scores on the ACT test are normally distributed with a mean of 19.6 and a standard deviation of 4.5. It is assumed that the two tests measure the same aptitude, but use different scales.If a student gets an SAT score that is the 20-percentile, find the actual SAT score.SAT score =What would be the equivalent ACT score for this student?ACT score =If a student gets an SAT score of 1437, find the equivalent ACT score.ACT score =

Answers

Answer:

Actual SAT Score = 815.284

Equivalent ACT Score = 15.811

The equivalent ACT Score = 29.95

Step-by-step explanation:

From the given information:

Scores on the SAT test are normally distributed with :

Mean = 982

Standard deviation = 198

If a student gets an SAT score that is the 20-percentile

Then ;

P(Z ≤ z ) = 0.20

From the standard z-score for percentile distribution.

z = -0.842

Therefore, the actual SAT Score can be computed as follows:

Actual SAT score = Mean + (z score × Standard deviation)

Actual SAT score =  982 +  (- 0.842 × 198)

Actual SAT score = 982 + ( - 166.716)

Actual SAT score =  982  - 166.716

Actual SAT Score = 815.284

Scores on the ACT test are normally distributed with a mean of 19.6 and a standard deviation of 4.5.

Mean = 19.6

Standard deviation = 4.5

Equivalent ACT Score = 19.6 +  (- 0.842 × 4.5)

Equivalent ACT Score = 19.6 +  ( - 3.789)

Equivalent ACT Score = 15.811

If a student gets an SAT score of 1437, find the equivalent ACT score.

So , if the SAT Score = 1437

Then , using the z formula , we can determine the equivalent ACT Score

[tex]z = \dfrac{X - \mu}{\sigma}[/tex]

[tex]z = \dfrac{1437 - 982}{198}[/tex]

[tex]z = \dfrac{455}{198}[/tex]

z =2.30

The equivalent ACT Score = 19.6 + (2.30 × 4.5)

The equivalent ACT Score = 19.6 +  10.35

The equivalent ACT Score = 29.95

Both Fred and Ed have a bag of candy containing a lemon drop, a cherry drop, and a lollipop. Each takes out a piece and eats it. What are the possible pairs of candies eaten? A. Lemon-lemon, cherry-lemon, lollipop-lollipop, lemon-cherry, cherry-cherry, lemon-lollipop, lollipop-cherry, cherry-lollipop, lollipop-lemon B. Cherry-lemon, lemon-lollipop, lollipop-cherry, lollipop-lollipop, lemon-lemon C. Lemon-cherry, lemon-cherry, lemon-cherry, lemon-lollipop, lemon-lollipop, lemon-lollipop, cherry-lollipop, cherry-lollipop, cherry-lollipop D. Lemon-lemon, cherry-lemon, lollipop-lollipop, lemon-lollipop, cherry-cherry, lemon-lollipop, lollipop-cherry, cherry-lemon, lollipop-lemon

Answers

Answer:

A. Lemon-lemon, cherry-lemon, lollipop-lollipop, lemon-cherry, cherry-cherry, lemon-lollipop, lollipop-cherry, cherry-lollipop, lollipop-lemon

Step-by-step explanation:

From the above question, we are told that both Fred and Ed have a bag of candy containing a lemon drop, a cherry drop, and a lollipop

There are two events here's

2 people = Fred and Ed

3 bags of different sweets = Lemon Cherry and Lollipop

The number of ways that both of them can eat this singly is calculated using combination formula

C(n, r) = nCr = n!/r! (n - r)!

n = 3, r = 2 = 3C2 = 3!/2! (3 - 2)!

= 3 × 2 × 1/2 × 1

= 3

We were asked to find the possible pairs

Hence = 3² = 9

There are 9 possible pairs through which Fred and Ed can eat their sweets and they are:

1) Lemon - Lemon

2) Cherry - Cherry

3) Lollipop - Lollipop

4) Lemon - Cherry

5) Cherry - Lemon

6) Lollipop - Cherry

7) Cherry - Lollipop

8) Lollipop - Lemon

9) Lemon - Lollipop.

Therefore, Option A is the correct option

Answer:

LEMONS BURN YOUR HOUSE DOWN JK its this A. Lemon-lemon, cherry-lemon, lollipop-lollipop, lemon-cherry, cherry-cherry, lemon-lollipop, lollipop-cherry, cherry-lollipop, lollipop-lemon

Step-by-step explanation:

From the above question, we are told that both Fred and Ed have a bag of candy containing a lemon drop, a cherry drop, and a lollipop

There are two events here's

2 people = Fred and Ed

3 bags of different sweets = Lemon Cherry and Lollipop

The number of ways that both of them can eat this singly is calculated using combination formula

C(n, r) = nCr = n!/r! (n - r)!

n = 3, r = 2 = 3C2 = 3!/2! (3 - 2)!

= 3 × 2 × 1/2 × 1

= 3

We were asked to find the possible pairs

Hence = 3² = 9

There are 9 possible pairs through which Fred and Ed can eat their sweets and they are:

1) Lemon - Lemon

2) Cherry - Cherry

3) Lollipop - Lollipop

4) Lemon - Cherry

5) Cherry - Lemon

6) Lollipop - Cherry

7) Cherry - Lollipop

8) Lollipop - Lemon

9) Lemon - Lollipop.

Therefore, Option A is the correct option

Multiply. (2x - 3)(x + 4) a 2x² + 11x - 12 b 2x² + 5x - 12 c 2x² + 11x - 7 d 2x² + 3x - 7

Answers

Answer:

2x^2 +5x-12

Step-by-step explanation:

(2x - 3)(x + 4)

FOIL

first 2x*x = 2x^2

outer  2x*4 = 8x

inner  -3x

last -3*4 = -12

Add these together

2x^2 +8x-3x-12

Combine like terms

2x^2 +5x-12

Solve using quadratic formula.

1.)5x^2+13x=6

2.)3x^2+1=-5x

PLEASE HELP!!! WILL MARK BRAINLIEST!!!

Answers

Answer:

1. 2/5,-3 2. [tex]x=\frac{-5+-\sqrt{13} }{6}[/tex]

Step-by-step explanation:

i used the quadratic formula to find x also please note that 2 has 2 answers bc of the +- beofre the sqrt of 13  

Step-by-step explanation:

1).

5x² + 13x - 6 = 0

Using the quadratic formula

[tex]x = \frac{ - b± \sqrt{ {b}^{2} - 4ac} }{2a} [/tex]

a = 5 , b = 13 c = - 6

We have

[tex]x = \frac{ - 13± \sqrt{ {13}^{2} - 4(5)( - 6) } }{2(5)} [/tex]

[tex]x = \frac{ - 13± \sqrt{169 + 120} }{10} [/tex]

[tex]x = \frac{ - 13± \sqrt{289} }{10} [/tex]

[tex]x = \frac{ - 13±17}{10} [/tex]

[tex]x = \frac{ - 13 + 17}{10} \: \: \: \: \: or \: \: \: \: x = \frac{ - 13 - 17}{10} [/tex]

x = 2/5 or x = - 3

2).

3x² + 5x + 1 = 0

a = 3 , b = 5 , c = 1

[tex]x = \frac{ -5 ± \sqrt{ {5}^{2} - 4(3)(1)} }{2(3)} [/tex]

[tex]x = \frac{ - 5± \sqrt{25 - 12} }{6} [/tex]

[tex]x = \frac{ - 5± \sqrt{13} }{6} [/tex]

[tex]x = \frac{ - 5 + \sqrt{13} }{6} \: \: \: \: or \: \: \: x = \frac{ - 5 - \sqrt{13} }{6} [/tex]

Hope this helps you

In politics, marketing, etc. We often want to estimate a percentage or proportion p. One calculation in statistical polling is the margin of error - the largest (reasonble) error that the poll could have. For example, a poll result of 72% with a margin of error of 4% indicates that p is most likely to be between 68% and 76% (72% minus 4% to 72% plus 4%). In a (made-up) poll, the proportion of people who like dark chocolate more than milk chocolate was 32% with a margin of error of 2.2%. Describe the conclusion about p using an absolute value inequality.

Answers

Answer: |p-72% |≤ 4%

Step-by-step explanation:

Let p be the population proportion.

The absolute inequality about p using an absolute value inequality.:

[tex]|p-\hat{p}| \leq E[/tex] , where E = margin of error, [tex]\hat{p}[/tex] = sample proportion

Given:  A poll result of 72% with a margin of error of 4% indicates that p is most likely to be between 68% and 76% .

|p-72% |≤ 4%

⇒    72% - 4% ≤ p ≤ 72% +4%

⇒  68%  ≤ p ≤  76%.

i.e. p is most likely to be between 68% and 76% (.

The conclusion about p using an absolute value inequality is in the range of 29.8% to 34.2%.

What is absolute value inequality?

An expression using absolute functions and inequality signs is known as an absolute value inequality.

We know that the absolute value inequality about p using an absolute value inequality is written as,

[tex]|p-\hat p| \leq E[/tex]

where E is the margin of error and [tex]\hat p[/tex] is the sample proportion.

Now, it is given that the poll result of 72% with a margin of error of 4% indicates that p is most likely to be between 68% and 76%. Therefore, p can be written as,

[tex]|p-0.72|\leq 0.04\\\\(0.72-0.04)\leq p \leq (0.72+0.04)\\\\0.68 \leq p\leq 0.76[/tex]

Thus, the p is most likely to be between the range of 68% to 76%.

Similarly, the proportion of people who like dark chocolate more than milk chocolate was 32% with a margin of error of 2.2%. Therefore, p can be written as,

[tex]|p-\hat p|\leq E\\\\|p-0.32|\leq 0.022\\\\(0.32-0.022)\leq p \leq (0.32+0.022)\\\\0.298\leq p\leq 0.342[/tex]

Thus, the p is most likely to be between the range of 29.8% to 34.2%.

Hence, the conclusion about p using an absolute value inequality is in the range of 29.8% to 34.2%.

Learn more about Absolute Value Inequality:

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