A sprinter runs for 6.45 s at 7.44 m/s. How far does she get?
A. 0.867 m
B. 13.9 m
C. 1.15 m
D. 48.0 m ​

Answers

Answer 1

Answer:

D is the answer

Explanation:

6.45×7.44= 47.98800

Which if we round of we get 48m


Related Questions

14 km = m on conversions using a ladder method​

Answers

Using the metric units kilometer (km) and meter (m), as seen in the picture of the ladder method example. So, the answer would be 14km = 14000m

S=1/2(u+v)t

i. u as subject
ii. V as subject

Answers

Answer:

i. [tex]u=\frac{2s}{t}-v[/tex]

ii. [tex]v=\frac{2s}{t}-u[/tex]

Explanation:

i.)

[tex]s=\frac{1}{2}(u+v)t\\\\2s=(u+v)t\\\\\frac{2s}{t}=u+v\\\\\frac{2s}{t}-v=u[/tex]

ii.)

[tex]s=\frac{1}{2}(u+v)t\\\\2s=(u+v)t\\\\\frac{2s}{t}=u+v\\\\\frac{2s}{t}-u=v[/tex]

Mass is measured in
a) Litters
b) Centimeter
c) Newton
d) Kilogram

Answers

Answer:

d) Kilogram.

Hope it helps you

Mass is measured in

a) Litters

b) Centimeter

c) Newton

d) Kilogram

A box is 300 kg & it covers the area of 150 m2 find the pressure exerted by the box in the ground.​

Answers

Answer:

If we assume that the box is a cube with 150 m² surface area

Area of 1 face = 150 m² / 6 = 25 m²

The box will exert a downward force of

Force = mass * acceleration due to gravity

Force = 300 kg * 9.81 m/s² N

Force = 2943 N

The box exerts a pressure ( force / unit area) = 2943 N / 25 m²

Pressure = 117.7 N/m²

Thank you, if you found this helpful please comment.

can sound waves propagate in vacuum if yes why if no why not??​

Answers

Answer:

please mark me brainliest

Explanation:

No, sound waves cannot travel in a vacuum. This is because sound waves are mechanical waves that need a medium (such as air and water) to travel. Sound in physics is defined as a vibration that propagates as an audible wave of pressure, through a medium such as a gas, liquid or solid.

Please help me, I really need someone

Answers

Answer:

In plotting position versus time it can be seen that the green line represents  a fixed position at the various times given - the other lines represent changing position with time

The (horizontal) green line describes an object that's not moving.

Whatever TIME you pick to look at the green line, its POSITION is always the same. This is a pretty good description of "not moving".

The other three lines all have different positions at different times, so they all describe motion.

tides occurs in oceans but not in lakes.why?​

Answers

Answer:

Explanation:

Tides occur in the ocean but nit in lakes because an ocean is a free flowing body of water that can travel a large area of the globe while a lake or pond only covers a small area of the earth so it is not affected by gravity as violently and in turn, prevents the formation of tides.

If Bert the Bat travels eastward at 40 mph with a tailwind of 6 mph, what is his actual speed?

Answers

Answer:

36 mph.

Explanation:

Now Albert here is using the wind to his advantage but if say there was no wind then he would not have the 6 mph behind him so we subtract 6 from 40 to get 36. hope this helps :)

if u can solve these with work i will literally love u forever

Answers

Answer:

I cant open it neither I can download it!

what would happen if measurements such as mass,length,volume,or temperature weren't standardized and everyone made up their own units

Answers

Answer:

The world would have been blown up by now.

Explanation:

Hypothetically, lets say that someone gave Kim Jong boi a cup of coffee.

He gets mad at the "public servant" since it didn't contain 3 posafa43asdunds of sugar which makes him "big".

The public servant claims they added jfoaj4su38093 units of sugar, which is equivalent to 3 posafa43asdunds.

He gets mad and launches big cannons at Trump since he blames Boe Jiden.

Can aurora be found in other planets?

Answers

Answer:

Yes

Explanation:

Any planet with a sufficiently dense atmosphere that lies in the path of the solar wind will have aurora. It has been discoveres in planets like Jupiter, Saturn, etc.

Answer:

yes

Explanation:

A tall pea plant (Tt) is crossbred with a short pea plant (tt). The following Punnett square shows the separated alleles for two pea plants.
Which of the following shows the correct match of the box numbers and the genotype of the offspring?
A. 1 = Tt; 2 = tt; 3 = Tt; 4 = tt
B. 1 = Tt; 2 = Tt; 3 = Tt; 4 = Tt
C.1 = Tt; 2 = Tt; 3 = tt; 4 = tt
D. 1 = Tt; 2 = tt; 3 = tt; 4 = tt

Answers

[tex]Hello[/tex] [tex]There![/tex]

The answer is...

A. 1 =Tt; 2 = tt; 3 = Tt; 4 = tt.

Hopefully, this helps you!!

[tex]AnimeVines[/tex]

Use the list to answer the question.
potassium, Group 1
calcium, Group 2
iodine, Group 17
neon, Group 18

Which two elements in the list would bond together based on their ionic charges?(1 point)

potassium and neon

potassium and iodine

calcium and neon

calcium and potassium

Answers

Answer: Potassium and Iodine

Explanation:

I took the quick check and it’s right.

Burger Hut is trying to decide if it can receive money from the government for providing employees with insurance. Financial accounting or Management Accounting or Tax Accounting

Answers

We have that with these disciplines well defined, The Form of accounting that speaks the most Burger Huts situation is the discipline of Management Accounting

Firstly we define the Disciplines of Accounting below

Financial accounting

Financial Accounting, this is a branch of accounting that focuses mainly on the Recording,Encapsulating or Summing up and then Releasing a statement bearing the Affairs of a Business over a specific time frame.

Management Accounting

This Branch of accounting focuses on the use of existing Financial positions to make assessment of a business and determine the best way to move the business forward.

Tax Accounting

This is a branch of accounting that focuses on taxation.This branch is governed by stiff rule that ensure that business stay in check.

Therefore

With these disciplines well defined, The Form of accounting that speaks the most Burger Huts situation is the discipline of Management Accounting

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A train is moving with the velocity of 10m/s . It attains an acceleration of 4m/s after 5 sec . find the distance covered by train at that time.

Answers

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A car accelerates by 4 m/s^2 and travels for 2.5 mins with an initial velocity of 20m/s. Find the final velocity.

Answers

Answer:

540m/s

Explanation:

v= u + at

u change t to seconds

how do i solve this?

Answers

Answer:

hmmm i dont know....

Explanation:

i just wanted free point. TANKS YOU SIR!!

What's Centripetal force................

Answers

Answer:

a force that acts on a body moving in a circular path and is directed towards the centre around which the body is moving.

Answer:

A centripetal force is a force that makes a body follow a curved path. Its direction is always orthogonal to the motion of the body and towards the fixed point of the instantaneous center of curvature of the path.

what do you mean by acceleration of a body 10\s?

Answers

Answer:

it means that the body is moving with acceleration increased of 10m in every second.

Worth 10 points! I will give brainliest!! Please help!!! See picture!

Answers

it contains iron. so it aligns with the magnetic Field lines

Answer:

The last option

Explanation:

eo *Write any two uses of good condutor of heat​

Answers

any two uses of good conductor of heat are

aluminium, cooper, metal are good conductor of heat and they are used for making utensils.

gold, silver, are also good conductor of heat they are used for making jewelleries.

If a ball is rolling at a velocity of 1.5 m/s and has a momentum of 10.0 kg times m/s, what is the mass of the ball?

Answers

Answer:

Mass of the ball, M = 6.667 kg

Explanation:

Given data:

Momentum, Mo = 10.0 kgm/s

Velocity of the rolling ball, V = 1.5 m/s

Mass of the body, M = ?

Momentum, Mo = Mass, M x Velocity, V

10.0 kgm/s = M x 1.5 m/s

Divide each side by 1.5 m/s

M = 10.0 kgm/s / 1.5 m/s

M = (6⅔) kg

:. Mass of the ball, M = 6.667 kg

a) A car accelerates uniformly at 3.7 m s⁻² as it passes a stationary road train. The initial speed of the car is 30 m s⁻¹, and it reaches the speed limit of 130 km h⁻¹ as it passes the front of the cab. Calculate the length of the road train. Give your answer to 3 significant figures. include units in your answer.
b) The braking distance of a road train travelling at 15 m s⁻¹ is 70 m. Assuming that the same deceleration is applied at all speeds, calculate the braking distance of a road train travelling at 25 m s⁻¹

Answers

(a) The length of the train is 54.6 m

(b)  The braking distance of the road train is 194.44 m

The given parameters:

acceleration of the car, a = 3.7 m/s²

initial velocity of the car, u = 30 m/s

final velocity of the car, v = 130 km/h = 36.11 m/s

To find:

the length of the train

The length of the train is the distance travelled by the car

The distance traveled by the car is calculated as:

[tex]v^2 = u^2 + 2as\\\\2as = v^2 - u^2\\\\s = \frac{ v^2 - u^2}{2a} \\\\where;\\\\s \ is \ the \ distance \ travelled \ by \ the \ car\\\\s = \frac{(36.11)^2 - (30)^2}{2\times 3.7} \\\\s = 54.585 \ m\\\\s \approx 54.6 \ m[/tex]

Thus, the length of the train is 54.6 m

(b) The braking distance of a road train travelling at 25 m s⁻¹

[tex]a = \frac{v_1^2}{2s_1} = \frac{v_2^2}{2s_2} \\\\Given;\\\\s_1 = 70 \ m\\\\v_1 = 15 \ m/s\\\\v_2 = 25 \ m/s\\\\s_2 = ?\\\\2s_2v_1^2 = 2s_1v_2^2\\\\s_2 = \frac{ 2s_1v_2^2}{2v_1^2} \\\\s_2 = \frac{s_1v_2^2}{v_1^2} \\\\s_2 = \frac{70\times 25^2}{15^2} \\\\s_2 = 194.44 \ m[/tex]

Thus, the braking distance of the road train is 194.44 m

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maize is called monocot why?​

Answers

Answer:

Rice, wheat, maize all have one cotyledon in their seed, so they are monocots. Explanation: The monocot plants have a single cotyledon. They have a fibrous root system, leaves in monocots have parallel venation.

Explanation:

seharitat -The distance of a panet from the earth is 2.5 x 10^7 km and the gravitational force between them them is 3.82 x 10^18 N. Mass of the planet and earth are equal, each being 5.98 x 10^24 Kg. Calculate the universal gravitation constant.​

Answers

F=3.82×10^18NMass of earth=M=5.98×10^24kgMass of planet=m=5.98×10^24kgDistance=r=2.5×10^7km

Universal gravitation constant=G

We know

[tex]\boxed{\sf F=G\dfrac{Mm}{r^2}}[/tex]

[tex]\\ \sf\longmapsto G=\dfrac{Fr^2}{Mm}[/tex]

[tex]\\ \sf\longmapsto G=\dfrac{3.82\times 10^{18}(2.5\times 10^7)^2}{(5.98\times 10^{24})^2}[/tex](M=m)

[tex]\\ \sf\longmapsto G=\dfrac{3.82\times 10^{18}(6.25\times 10^{14})}{35.7\times 10^{48}}[/tex]

[tex]\\ \sf\longmapsto G=\dfrac{23.87\times 10^{32}}{35.7\times 10^{48}}[/tex]

[tex]\\ \sf\longmapsto G=0.668\times10^{-16}[/tex]

[tex]\\ \sf\longmapsto G=6.68\times 10^{-15}[/tex]

1 point
30. A ray passing through the centre of curvature of a concave mirror.
after reflection is reflected back along the same path. Which is the correct
figure for the above statement.

Answers

Explanation:

when the object is between the pole and focus

how many seconds are there in 1 day . solve along with steps​

Answers

One minute has 60 seconds, One hour has 60 minutes and one day has 24 hours. Thus, 80 x 60 x 24 = 86,400 sec

if my answer helps you than mark me as brainliest

Answer:

[tex]thank \: you[/tex]

A shift inward of the production possibilities curve signifies that _

A. The demand for the products has increased, so the supply will increase
B. The available resources have increased, so potential production levels will increase
C. The available production resources have decreased, so potential production levels will decrease
D. The demand for the products has decreased so, the supply will decrease

Answers

Answer:

c

Explanation:

A shift inward of the production possibilities curve signifies that: C. The available production resources have decreased, so potential production levels will decrease.

A production possibilities curve (PPC) is also referred to as production possibilities frontier (PPF) and it can be defined as a curve that illustrates the maximum (best) combinations of two (2) products which can be produce in an economy if they both depend on these two (2) main factors;

Fixed technology. Fixed resources.

Basically, the production possibilities curve (PPC) illustrates the maximum combinations of goods that are available with fixed technology and resources.

Furthermore, an inward shift of the production possibilities curve (PPC) signifies that the available resources used for production have decreased, so potential production levels would also decrease.

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A wombat runs south in a straight line with an average velocity of 5 m/s for 4
minutes and then with an average velocity of 4 m/s for 3 minutes in the same
direction.
What is the wombats total displacement?
What is the average velocity during that time?

Answers

We have that

The wombats total displacement is

[tex]d_t=2100m[/tex]

The average velocity during that time is

[tex]v_{avg}=5m/s[/tex]

From the question we are told that:

initial Velocity [tex]V_1=5m/s[/tex]

initial Time [tex]T_1=4min=>240sec[/tex]

Final Velocity [tex]V_2=4m/s[/tex]

Final time  [tex]T_2=3min=>180sec[/tex]

a)

Generally, the equation for displacement is mathematically given by

d_t=(Initial +final) displacement

Where

initial displacement

[tex]d_1=V_1*t_1\\\\d_1=5*240[/tex]

[tex]d_1=1200m[/tex]

Final displacement

[tex]d_2=V_2*t_2\\\\d_2=5*180[/tex]

[tex]d_2=900m[/tex]

Therefore

[tex]d_t=(Initial +final) displacement[/tex]

[tex]d_t=1200+900[/tex]

[tex]d_t=2100m[/tex]

b)

Generally, the equation for Average velocity is mathematically given by

[tex]v_{avg}=\frac{d_t}{t_1+t_2}[/tex]

[tex]v_{avg}=\frac{2100m}{240+180}[/tex]

[tex]v_{avg}=5m/s[/tex]

in conclusion

The wombats total displacement is

[tex]d_t=2100m[/tex]

The average velocity during that time is

[tex]v_{avg}=5m/s[/tex]

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An ambulance is currently traveling at 15m/s, and is accelerating with a constant acceleration of 5 m/s^2. The ambulance is attempting to pass a car that is moving at a constant velocity of 30m/s. How far must the ambulance travel until it matches the car’s velocity?

Answers

initial velocity=15m/s=uAcceleration=a=5m/s^2Final velocity=v=30m/sDistance be s

Using 3rd equation of kinematics

[tex]\\ \rm\longmapsto v^2-u^2=2as[/tex]

[tex]\\ \rm\longmapsto s=\dfrac{v^2-u^2}{2a}[/tex]

[tex]\\ \rm\longmapsto s=\dfrac{30^2-15^2}{2(5)}[/tex]

[tex]\\ \rm\longmapsto s=\dfrac{900-225}{10}[/tex]

[tex]\\ \rm\longmapsto s=\dfrac{675}{10}[/tex]

[tex]\\ \rm\longmapsto s=67.5m[/tex]

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