Answer:
Spaceship speed is 36000 km/h
So, in 1 hour spaceship travel 36000 km
Or we can say that in 60×60 second spaceship travel 36000 km
Therefore in 1 sec spaceship travel
=
= 10 km/s
Answer:
Explanation:
360 km/hr(1000 m/km) / 3600 s/hr) = 100 m/s
Which object has the most thermal energy?
A. 2 kg of liquid oxygen at -225°C
B. 5 kg of liquid oxygen at -220°C
C. 2 kg of oxygen gas at 20°C
D. 5 kg of oxygen gas at 30°C
5 kg of liquid oxygen at -220°C will have the most thermal energy due to its higher mass and temperature.
What is thermal energy?Thermal energy is the total heat required to raise the entire mass of a given substance.
Q = mcΔθ
where;
Q is thermal energym is mass of the substancec is specific heat capacityΔθ is change in temperatureThus, 5 kg of liquid oxygen at -220°C will have the most thermal energy due to its higher mass and temperature.
Learn more about thermal energy here: https://brainly.com/question/7541718
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What is your angular position 75 seconds after the wheel starts turning, measured counterclockwise from the top? Express your answer as an angle between 0∘ and 360∘. Express your answer in degrees.
Complete Question
A Ferris wheel on a California pier is 27 m high and rotates once every 32 seconds in the counterclockwise direction. When the wheel starts turning, you are at the very top.
What is your angular position 75 seconds after the wheel starts turning, measured counterclockwise from the top? Express your answer as an angle between 0∘ and 360∘. Express your answer in degrees.
Answer:
[tex]\phi=123.75[/tex]
Explanation:
From the question we are told that:
Height [tex]h=27m[/tex]
Period [tex]T=32sec[/tex]
Time [tex]t=75sec[/tex]
Generally the equation for angular velocity is mathematically given by
[tex]\omega=\frac{2 \pi}{T}[/tex]
[tex]\omega=\frac{2 \pi}{32}[/tex]
[tex]\omega=0.196rad/s[/tex]
Therefore
[tex]\theta=\omega t[/tex]
[tex]\theta=0.196rad/s*75sec[/tex]
[tex]\theta=843.75 \textdegree[/tex]
Therefore
[tex]\phi=\theta-2(360)[/tex]
[tex]\phi=123.75[/tex]
Expresar por notación científica:
846 000 000
Answer:
[tex]8.46*10^8[/tex]
Thermodynamic Processes: An ideal gas is compressed isothermally to one-third of its initial volume. The resulting pressure will be
Answer:
The resulting pressure is 3 times the initial pressure.
Explanation:
The equation of state for ideal gases is described below:
[tex]P\cdot V = n \cdot R_{u}\cdot T[/tex] (1)
Where:
[tex]P[/tex] - Pressure.
[tex]V[/tex] - Volume.
[tex]n[/tex] - Molar quantity, in moles.
[tex]R_{u}[/tex] - Ideal gas constant.
[tex]T[/tex] - Temperature.
Given that ideal gas is compressed isothermally, this is, temperature remains constant, pressure is increased and volume is decreased, then we can simplify (1) into the following relationship:
[tex]P_{1}\cdot V_{1} = P_{2}\cdot V_{2}[/tex] (2)
If we know that [tex]\frac{V_{2}}{V_{1}} = \frac{1}{3}[/tex], then the resulting pressure of the system is:
[tex]P_{2} = P_{1}\cdot \left(\frac{V_{1}}{V_{2}} \right)[/tex]
[tex]P_{2} = 3\cdot P_{1}[/tex]
The resulting pressure is 3 times the initial pressure.
An capacitor consists of two large parallel plates of area A separated by a very small distance d. This capacitor is connected to a battery and charged until its plates carry charges Q and - Q, and then disconnected from the battery. If the separation between the plates is now doubled, the potential difference between the plates will
Answer:
Will be doubled.
Explanation:
For a capacitor of parallel plates of area A, separated by a distance d, such that the charges in the plates are Q and -Q, the capacitance is written as:
[tex]C = \frac{Q}{V} = e_0\frac{A}{d}[/tex]
where e₀ is a constant, the electric permittivity.
Now we can isolate V, the potential difference between the plates as:
[tex]V = \frac{Q}{e_0} *\frac{d}{A}[/tex]
Now, notice that the separation between the plates is in the numerator.
Thus, if we double the distance we will get a new potential difference V', such that:
[tex]V' = \frac{Q}{e_0} *\frac{2d}{A} = 2*( \frac{Q}{e_0} *\frac{d}{A}) = 2*V\\V' = 2*V[/tex]
So, if we double the distance between the plates, the potential difference will also be doubled.
A boy at a football field practice kicked a 0.500-kg ball with a force of 100N. How fast will the ball move after reaching a distance of 7m?
Answer:
v(7) = 52.915 m/s
Explanation:
First, find the value for acceleration.
F = ma
100 = .5 * a
a = 200 m/s²
Next find the velocity at x = 7 using kinematic equations.
v² = v₀² + 2a(Δx)
v² = (0)² + 2(200)(7)
v = [tex]\sqrt{2800}[/tex]
v = 52.915 m/s
A total of 25.6 kJ of heat energy is added to a 5.46 L sample of helium at 0.991 atm. The gas is allowed to expand against a fixed external pressure to a volume of 18.7 L .
Required:
a. Calculate the work done on or by the helium gas units of joules, J.
b. What is the change in the helium a internal energy in units kilojoules, KJ?
Answer:
(a) W = 1329.5 J = 1.33 KJ
(b) ΔU = 24.27 KJ
Explanation:
(a)
Work done by the gas can be found by the following formula:
[tex]W = P\Delta V[/tex]
where,
W = Work = ?
P = constant pressure = (0.991 atm)([tex]\frac{101325\ Pa}{1\ atm}[/tex]) = 100413 Pa
ΔV = Change in Volume = 18.7 L - 5.46 L = (13.24 L)([tex]\frac{0.001\ m^3}{1\ L}[/tex]) = 0.01324 m³
Therefore,
W = (100413 Pa)(0.01324 m³)
W = 1329.5 J = 1.33 KJ
(b)
Using the first law of thermodynamics:
ΔU = ΔQ - W (negative W for the work done by the system)
where,
ΔU = change in internal energy of the gas = ?
ΔQ = heat added to the system = 25.6 KJ
Therefore,
ΔU = 25.6 KJ - 1.33 KJ
ΔU = 24.27 KJ
A 215 N sign is supported by two ropes. One rope pulls up and to the right 1=29.5∘ above the horizontal with a tension 1 , and the other rope pulls up and to the left 2=44.5∘ above the horizontal with a tension 2 , as shown in the figure. Find the tensions 1 and 2 .
The sign is held in equilibrium. Using Newton's second law, we set up the equations of the net forces acting on the sign in the horizontal and vertical directions:
∑ F (horizontal) = T₁ cos(29.5°) - T₂ cos(44.5°) = 0
(right is positive, left is negative)
∑ F (vertical) = T₁ sin(29.5°) + T₂ sin(44.5°) - 215 N = 0
(up is positive, down is negative)
Solve the system of equations. I use elimination here:
• Multiply the first equation by sin(29.5°) and the second by cos(29.5°):
sin(29.5°) (T₁ cos(29.5°) - T₂ cos(44.5°)) = 0
cos(29.5°) (T₁ sin(29.5°) + T₂ sin(44.5°) - 215 N) = 0
T₁ cos(29.5°) sin(29.5°) - T₂ cos(44.5°) sin(29.5°) = 0
T₁ cos(29.5°) sin(29.5°) + T₂ cos(29.5°) sin(44.5°) = (215 N) cos(29.5°)
• Subtract the first equation from the second to eliminate T₁ :
T₂ cos(29.5°) sin(44.5°) - (- T₂ cos(44.5°) sin(29.5°)) = (215 N) cos(29.5°)
• Solve for T₂ :
T₂ (cos(29.5°) sin(44.5°) + cos(44.5°) sin(29.5°)) = (215 N) cos(29.5°)
T₂ sin(74.0°) = (215 N) cos(29.5°)
… … … (using the fact that sin(x + y) = sin(x) cos(y) + cos(y) sin(x))
T₂ = (215 N) cos(29.5°) / sin(74.0°)
T₂ ≈ 195 N
• Solve for T₁ :
T₁ cos(29.5°) - T₂ cos(44.5°) = 0
T₁ cos(29.5°) = T₂ cos(44.5°)
T₁ = T₂ cos(44.5°) / cos(29.5°)
T₁ ≈ 160. N
* 1a Average speed
Carl Lewis runs the 100 m sprint in about 10 s.
His average speed in units of m/s would be:
of
Answer:
Explanation:
[tex] \implies v_{av} = \dfrac{total \: displacement}{total \: time} [/tex]
[tex] \implies v_{av} = \dfrac{100}{10} [/tex]
[tex]\implies v_{av} =10 \: {ms}^{ - 1} [/tex]
? What is the difference between the Primitive cell and convectional cell
explain relative velocity briefly
Answer:
Explanation:
Relative velocity is defined as the velocity of an object B in the rest frame of another object A.
We have seen that when you generate a wave on a stretched spring, as long as the medium doesn’t change (that is, the tension and the linear mass density remain the same), the speed of the wave on the spring is constant. Does this mean that the particles of the spring always have zero acceleration? Explain why or why not.
Answer:
No, the acceleration is not always zero.
Explanation:
It does not mean that the acceleration of the particle is zero.
The velocity of wave is different from the velocity of particle.
The acceleration of wave is different from the acceleration of particle.
the acceleration of the particle is given by
[tex]a =- w^2 y[/tex]
where, w is the angular frequency and y is the displacement from the mean position.
So, the acceleration is zero at mean position only and it varies as the position changes.
A motorcycle of mass 160 kg accelerates from rest to 53 m/s in 9 seconds. Ignore air resistance. Assuming there's no slipping between the wheels and the pavement of the road.
Required:
a. What is the average horizontal component of the force that the road exerts on the wheels (total force on all two wheels, not the force on one wheel)?
b. How far does the motorcycle travel in 9 seconds?
c. In the point-particle analysis of this situation, what is the work done by this force?
d. For the real system, how much work is done by the force of the road on the wheels?
Answer:
a) [tex]F=940.8N[/tex]
b) [tex]S=234.14m[/tex]
c) [tex]W=2.2*10^5J[/tex]
d) [tex]W=0[/tex]
Explanation:
Mass [tex]m=160kg[/tex]
Velocity [tex]v=53m/s[/tex]
Time [tex]t=9seconds[/tex]
a)
Generally the Newton's equation for motion is mathematically given by
[tex]a=\frac{v}{t}[/tex]
[tex]a=\frac{53}{9}[/tex]
[tex]a=5.9m/s^2[/tex]
Therefore
F=ma
[tex]F=160*5.88[/tex]
[tex]F=940.8N[/tex]
b)
Generally the Newton's equation for motion is mathematically given by
[tex]S=0.5at^2[/tex]
[tex]S=0.5*5.9*9^2[/tex]
[tex]S=234.14m[/tex]
c)
Generally the Newton's equation for work done is mathematically given by
[tex]W=Fd[/tex]
[tex]W=940.8*238.14[/tex]
[tex]W=2.2*10^5J[/tex]
d)
Generally the Newton's equation for work done by the force of the road on the wheels is mathematically given by
[tex]W=Fdcos\theta[/tex]
[tex]W=0[/tex]
what is the critical angle of light traveling from vegetable oil into water
56.1∘
Question: A glass is half-full of water, with a layer of vegetable oil (n = 1.47) floating on top. A ray of light traveling downward through the oil is incident on the water at an angle of 56.1∘ .
A glass is half-full of water, with a layer of vegetable oil (n ...https://study.com › academy › answer › a-glass-is-half-ful...
Estimate the average power of a water wave when it hits the chest of an adult standing in the water at the seashore. Assume that the amplitude of the wave is 0.56 m , the wavelength is 2.0 m , and the period is 3.4 s . Assume that the area of the chest is 0.14 m^2.
Answer:
[tex]P=45.2W[/tex]
Explanation:
From the question we are told that:
Amplitude [tex]A=0.56m[/tex]
Period [tex]T=3.4s[/tex]
Wavelength [tex]\lambda=2.0[/tex]
Area [tex]a=0.14m^2[/tex]
Generally the equation for Power is mathematically given by
[tex]Power = 2 \pi ^2 \rho a(\frac{\lambda}{T})(\frac{1}{T})*A[/tex]
[tex]P= 2 3.142^2 1025 0.14(\frac{2.0}{3.4})(\frac{1}{3.4})^2*0.56^2[/tex]
[tex]P=45.2W[/tex]
State what is meant by a gravitational potential at point A is -1·70 × 109 J kg-1.
Answer:
The energy stored in a body due to either it's position or change in shape is called gravitational potential energy.
What is the kinetic energy of a 6.00 kg toy car that is going at 1.75 m/s across the floor?
Answer:
9.1875 Joules
Explanation:
The kinetic energy of an object can be given by the equation [tex]EK = \frac{1}{2} mv^{2}[/tex], in which m is the mass and v is the velocity. Plugging in the mass and velocity values into the equation, we get:
[tex]EK = \frac{1}{2} (6kg)(1.75m/s)^2\\EK = 9.1875 J[/tex]
Answer:
[tex]\boxed {\boxed {\sf 9.19 \ Joules}}[/tex]
Explanation:
Kinetic energy is the energy an object possesses due to motion. The following formula is used to calculated kinetic energy.
[tex]E_k= \frac{1}{2} mv^2[/tex]
In this formula, m is the mass and v is the velocity.
The car has a mass of 6.00 kilograms and a velocity of 1.75 meters per second.
m= 6.00 kgv=1.75 m/sSubstitute the values into the formula.
[tex]E_k= \frac{1}{2} (6.00 \ kg )(1.75 \ m/s)^2[/tex]
Solve the exponent.
(1.75 m/s)²= 1.75 m/s *1.75 m/s = 3.0625 m²/s²[tex]E_k= \frac{1}{2}(6.00 \ kg )(3.0625 \ m^2/s^2)[/tex]
Multiply the numbers together.
[tex]E_k=\frac {1}{2} (18.375 \ kg*m^2/s^2)[/tex]
[tex]E_k= 9.1875 \ kg*m^2/s^2[/tex]
The original measurements of mass and velocity both have 3 significant figures, so our answer must have the same. For the number we calculated, that is the hundredths place. The 7 in the thousandths place to the right (9.1875) tells us to round to 8 up to a 9.
[tex]E_k \approx 9.19 \ kg*m^2/s^2[/tex]
1 kilogram meter squared per second squared is equal to 1 Joule. Our answer of 9.19 kg*m²/² is equal to 9.19 Joules.
[tex]E_k \approx 9.19 \ J[/tex]
The kinetic energy of the toy care is approximately 9.19 Joules.
In a race, Usain Bolt accelerates at
1.99 m/s2 for the first 60.0 m, then
decelerates at -0.266 m/s2 for the final
40.0 m. How much time did the race take?
(Unit = s)
Answer:
65.87 s
Explanation:
For the first time,
Applying
v² = u²+2as.............. Equation 1
Where v = final velocity, u = initial velocity, a = acceleration, s = distance
From the question,
Given: u = 0 m/s (from rest), a = 1.99 m/s², s = 60 m
Substitute these values into equation 1
v² = 0²+2(1.99)(60)
v² = 238.8
v = √238.8
v = 15.45 m/s
Therefore, time taken for the first 60 m is
t = (v-u)/a............ Equation 2
t = (15.45-0)/1.99
t = 7.77 s
For the final 40 meter,
t = (v-u)/a
Given: v = 0 m/s(decelerates), u = 15.45 m/s, a = -0.266 m/s²
Substitute into the equation above
t = (0-15.45)/-0.266
t = 58.1 seconds
Hence total time taken to cover the distance
T = 7.77+58.1
T = 65.87 s
What to do when having a cold
Answer:I would prefer ginger with lemon and honey tea...Stay hydrated,Rest,
Explanation:
Answer:
You can ease cold symptoms by resting, drinking plenty of water and using things like decongestants and painkillers.
To help you get better more quickly:
rest and sleep
keep warm
drink plenty of water (fruit juice or squash mixed with water is OK) to avoid dehydration
gargle salt water to soothe a sore throat
Some copper wire has a resistance of 200 ohms at 20 degrees C . A current is then passed through the same wire and the temperature rises to 90 degrees C. Determine the resistance of the wire at 90 degrees correct to the nearest ohm assuming the coefficient of resistance is 0.004/degree C at 0 degrees
Answer:
256 ohms
Explanation:
Applying,
R = R'[1+α(T-T')]............. Equation 1
Where R = Final resistance of the wire, R' = Initial resistance of the wire, T = Final temperature, T' = Initial temperature, α = Temperature coefficient of resistance
From the question,
Given: R' = 200 ohms, T = 90 degrees, T' = 20 degrees, α = 0.004/degree
Substitute these values into equation 1
R = 200[1+0.004(90-20)]
R = 200[1+0.28]
R = 200(1.28)
R = 256 ohms
The resistance of the wire at 90 °C correct to the nearest ohm assuming the coefficient of resistance is 0.004 °C¯¹ is 256 ohm
Data obtained from the question Original resistance (R₁) = 200 ohmOriginal temperature (T₁) = 20 °C Coefficient of resistivity (α) = 0.004 °C¯¹New temperature (T₂) = 90 °C New resistance (R₂) =? How to determine the new resistanceα = R₂ – R₁ / R₁(T₂ – T₁)
0.004 = R₂ – 200 / 200(90 – 20)
0.004 = R₂ – 200 / 200(70)
0.004 = R₂ – 200 / 14000
Cross multiply
R₂ – 200 = 0.004 × 14000
R₂ – 200 = 56
Collect like terms
R₂ = 56 + 200
R₂ = 256 ohm
Learn more about linear expansion:
https://brainly.com/question/23207743
when we jump on a concrete surface,the feet get injured.Why
Answer:
Explanation:
Bhjb
Explanation:
its because a concrete surface is a hard surface which doesn't absorb the energy of gravitation when we fall down so we get hurt more badly..
hope this helps
When the gun fires a projectile with a mass of 0.040 kg and a speed of 380 m/s, what is the recoil velocity of the shotgun and arm–shoulder combination?
Complete question:
The recoil of a shotgun can be significant. Suppose a 3.6-kg shotgun is held tightly by an arm and shoulder with a combined mass of 15.0 kg. When the gun fires a projectile with a mass of 0.040 kg and a speed of 380 m/s, what is the recoil velocity of the shotgun and arm–shoulder combination?
Answer:
The recoil velocity of the shotgun and arm–shoulder combination is 1.013 m/s
Explanation:
Given;
combined mass of the shotgun and arm–shoulder, m₁ = 15 kg
mass of the projectile, m₂ = 0.04 kg
speed of the projectile, u₂ = 380 m/s
let the recoil velocity of the shotgun and arm–shoulder combination = u₁
Apply the principle of conservation of linear momentum;
m₁u₁ + m₂u₂ = 0
m₁u₁ = - m₂u₂
[tex]u_1 = -\frac{m_2u_2}{m_1} \\\\u_1 = - \frac{0.04\times 380}{15} \\\\u_1 =-1.013 \ m/s\\\\u_1 = 1.013 \ m/s \ \ \ in \ opposite \ direction[/tex]
Therefore, the recoil velocity of the shotgun and arm–shoulder combination is 1.013 m/s
why the change of the pressure and temperature affect the velocity of the sound
Air pressure has no effect at all in an ideal gas approximation. This is because pressure and density both contribute to sound velocity equally, and in an ideal gas the two effects cancel out, leaving only the effect of temperature. Sound usually travels more slowly with greater altitude, due to reduced temperature.
The diagram below shows snapshots of an oscillator at different times. What is the amplitude of oscillation?
Answer:
the amplitude of the oscillation of the given mass is 0.1 m.
Explanation:
The amplitude of an oscillation is the maximum displacement of the object from the equilibrium position.
The equilibrium position of the given mass in question is at the zero (0) mark.
The maximum displacement of the object from the equilibrium position is 0.1 m upwards or 0.1 m downwards.
Therefore, the amplitude of the oscillation of the given mass is 0.1 m.
Which is a product of nuclear fusion?
Answer:
Creation of energy by joining the nuclei of two hydrogen atoms to form helium
What is the resistance of a copper wire 200 ft long and
0.01 in. in diameter (T 20°C)?
Answer:
R = 20.21 ohms
Explanation:
Given that,
The length of the wire, l = 200 ft
The diameter of the wire, d = 0.01 in
Radius, r = 0.005 in
200 ft = 60.96 m
0.005 in = 0.000127 m
The resistivity of copper is, [tex]\rho=1.68\times 10^{-8}\ \Omega-m[/tex]
So, the resistance of a wire is given by :
[tex]R=\rho \dfrac{l}{A}\\\\R=\rho \dfrac{l}{\pi r^2}\\\\R=1.68\times 10^{-8}\times \dfrac{60.96 }{\pi \times (0.000127 )^2}\\\\R=20.21\ \Omega[/tex]
So, the resistance of the copper wire is 20.21 ohms.
How much work does a supermarket checkout attendant do on a can of soup he pushes 0.420 m horizontally with a force of 4.60 N? Express your answer in joules and kilocalories.
We know
[tex]\boxed{\sf Work\:Done=Force\times Displacement} [/tex]
[tex]\\ \rm\longmapsto Work\:done=0.420\times 4.60[/tex]
[tex]\\ \rm\longmapsto Work\:done=1.932J[/tex]
the roque requried to turn the crank on an ice cream maker is 4.50 N.m how much work does it take to turn the crank through 300 full turns
Answer:
the work required to turn the crank at the given revolutions is 8,483.4 J
Explanation:
Given;
torque required to turn the crank, T = 4.50 N.m
number of revolutions, = 300 turns
The work required to turn the crank is given as;
W = 2πT
W = 2 x 3.142 x 4.5
W = 28.278 J
1 revolution = 28.278 J
300 revlotions = ?
= 300 x 28.278 J
= 8,483.4 J
Therefore, the work required to turn the crank at the given revolutions is 8,483.4 J
Violet light of wavelength 405 nm ejects electrons with a maximum kinetic energy of 0.890 eV from a certain metal. What is the binding energy (in electronvolts) of electrons to this metal
Answer:
Ф = 2.179 eV
Explanation:
This exercise has electrons ejected from a metal, which is why it is an exercise on the photoelectric effect, which is explained assuming the existence of energy quanta called photons that behave like particles.
E = K + Ф
the energy of the photons is given by the Planck relation
E = h f
we substitute
h f = K + Ф
Ф= hf - K
the speed of light is related to wavelength and frequency
c = λ f
f = c /λ
Φ = [tex]\frac{hc}{\lambda } - K[/tex]
let's reduce the energy to the SI system
K = 0.890 eV (1.6 10⁻¹⁹ J / 1eV) = 1.424 10⁻¹⁹ J
calculate
Ф = 6.63 10⁻³⁴ 3 10⁸/405 10⁻⁹ -1.424 10⁻¹⁹
Ф = 4.911 10⁻¹⁹ - 1.424 10⁻¹⁹
Ф = 3.4571 10⁻¹⁹ J
we reduce to eV
Ф = 3.4871 10⁻¹⁹ J (1 eV / 1.6 10⁻¹⁹ J)
Ф = 2.179 eV
While standing at the edge of the roof of a building, a man throws a stone upward with an initial speed of 6.63 m/s. The stone subsequently falls to the ground, which is 14.5 m below the point where the stone leaves his hand.
At what speed does the stone impact the ground? Ignore air resistance and use =9.81 m/s2 for the acceleration due to gravity.
impact speed:
18.1151
m/s
How much time is the stone in the air?
elapsed time:
Answer:
Explanation:
You final velocity is correct but not to the correct number of significant digits. The actual answer should be 18.1 m/s. We will use that to find the total time the stone was in the air in the equation:
v = v₀ + at
18.1 = 6.63 + (-9.81)t and
11.5 = -9.81t so
t = 1.17 seconds.
We know this was how long the stone was in the air (as compared to the time that the stone took to reach its max height or some other height) because we used the velocity with which the stone hit the ground to find the total time the rock was in the air before it hit the ground going at that velocity.
