A soccer player has made 3 of her last 10 field goals, which is a field goal percentage of 30%. How many more consecutive field goals would she need to make to raise her field goal percentage to 50%?

Answers

Answer 1

Answer:

4 consecutive goals

Step-by-step explanation:

If 3 of last 10 field goals = 30%

Which is equivalent to

(Number of goals scored / total games played) * 100%

(3 / 10) * 100% = 30%

Number of consecutive goals one has to score to raise field goal to 50% will be:

Let y = number of consecutive goals

[(3+y) / (10+y)] * 100% = 50%

[(3+y) / (10+y)] * 100/100 = 50/100

[(3+y) / (10+y)] * 1 = 0.5

(3+y) / (10+y) = 0.5

3+y = 0.5(10 + y)

3+y = 5 + 0.5y

y - 0.5y = 5 - 3

0.5y = 2

y = 2 / 0.5

y = 4

Therefore, number of consecutive goals needed to raise field goal to 50% = 4


Related Questions

A laboratory tested n = 98 chicken eggs and found that the mean amount of cholesterol was LaTeX: \bar{x}x ¯ = 86 milligrams with σ = 7 milligrams. Find the margin of error E corresponding to a 95% confidence interval for the true mean cholesterol content, μ, of all such eggs.

Answers

Answer:

1.3859

Step-by-step explanation:

The formula for Margin of Error is given as:

Margin of Error = Critical value × Standard Error

Critical value = z score

In the question, we are given a confidence interval of 95%.

Z score for a 95% confidence level is given as: 1.96

Hence, critical value = 1.96

Standard Error = σ / √n

Where n = number of samples = 98 chicken eggs

σ = Standard deviation = 7 milligrams

Standard Error = 7/√98

Standard Error = 0.7071067812

Hence, Margin of Error = Critical value × Standard Error

Margin of Error = 1.96 × 0.7071067812

Margin of Error = 1.3859292911

Therefore, the margin of error corresponding to a 95% confidence interval for the true mean cholesterol content, μ, of all such eggs is approximately 1.3859

Decide whether the normal sampling distribution can be used. If it can be​ used, test the claim about the population proportion p at the given level of significance using the given sample statistics.

Claim: p>0.12; α=0.05; Sample statistics: Modifying above p with caret equals 0.08, n is equal to 250

Answers

Answer:

There is no sufficient evidence to support the claim

Step-by-step explanation:

From the question we are told that

     The level of significance is  [tex]\alpha = 0.05[/tex]

     The  sample proportion is  [tex]\r p = 0.08[/tex]

     The  sample size is  [tex]n = 250[/tex]

     

Generally for normal sampling distribution can  be used

     [tex]n * p > 5[/tex]

So  

     [tex]n* p = 250 * 0.12 = 30[/tex]

Since  

     [tex]n * p > 5[/tex] then  normal sampling distribution can  be used

The null hypothesis is  [tex]H_o : p = 0.12[/tex]

  The alternative hypothesis is  [tex]H_a : p > 0.12[/tex]

The  test statistic is evaluated as

            [tex]t = \frac{\r p - p }{ \sqrt{ \frac{p(1- p)}{n} } }[/tex]

substituting values

            [tex]t = \frac{0.08 - 0.12 }{ \sqrt{ \frac{0.12 (1- 0.12)}{250 } } }[/tex]

            [tex]t = -1.946[/tex]

The  p-value is obtained from the z  table and the value is

        [tex]p-value = P(t > -1.9462) =0.97512[/tex]

Since the [tex]p-value > \alpha[/tex]

    Then we fail to reject the null hypothesis

Hence it means there is no sufficient evidence to support the claim

 

     

Find the 14th term in the sequence 1, 1/3, 1/9, … Find the sum of the first 10 terms of the sequence above.

Answers

Answer:

This is a geometric progresion that begins with 1 and each term is 1/3 the preceeding term

   Let Pn represent the nth term in the sequence

 

   Then Pn = (1/3)^n-1

 

   From this P14 = (1/3)^13 = 1/1594323

 

5. The sum of the first n terms of a GP beginning a with ratio r is given by

   Sn = a* (r^n+1 - 1)/(r - 1)

 

   With n = 10, a = 1 and r = 1/3, S10 = ((1/3)^11 - 1)/(1/3 - 1) = 1.500

PLEASE ANSWER ASAP!!!

Equation in the picture


Solve for r in the equation in the picture. You must use the LCD (Least Common Denominator) to simplify. You can also use cross products to solve.

Must show work

A. r = 19

B. r = 21

C. r = 25

D. r = 30



any unrelated answer will be reported​

Answers

Answer:

r = 19

Step-by-step explanation:

( r-5) /2 = ( r+2) /3

The least common denominator is 6

3/3 *( r-5) /2 = ( r+2) /3 * 2/2

3( r-5) /6 = 2( r+2) /6

Since the denominators are the same, the numerators are the same

3( r-5) = 2(r+2)

Distribute

3r -15 = 2r+4

Subtract 2r from each side

3r-2r -15 = 2r+4-2r

r-15 =4

Add 15 to each side

r-15+15 = 4+15

r = 19

ASAP
Which of the following factors determine a plane? A. line and a point on the line B. two lines C. a straight line D. a line and a point not on that line

Answers

Answer:

D. a line and a point not on that line

Step-by-step explanation:

That is how you determine a plane.

The factors which determine a plane are a line and a point not on that line.

What is plane ?

In geometry, a plane is a flat surface that extends into infinity.

In a three dimensional space, a plane can be defined by three points it contains, as long as those points are not on the same line.

Therefore, the factors which determine a plane are a line and a point not on that line.

Hence, option D is correct.

Learn more about plane here:

https://brainly.com/question/17458011

#SPJ2

Your friend Iggy tells you that the product of 80 and 70 will have four zeroes. Explain to Iggy why his estimation is incorrect, and how to fix it.

Answers

4 zeroes basically means [tex]10^4[/tex]

$80=2^3\cdot 10$ and $70=7\cdot10$

there will be $10^2$ when you take the product not $10^4$

hence it will have 2 zeroes not 4

Give this problem a try and try to solve this​

Answers

Answer:

No solution

Step-by-step explanation:

Given equation is,

[tex]\frac{x^{\frac{1}{2}}+x^{-\frac{1}{2}}}{1-x}+\frac{1-x^{-\frac{1}{2}}}{1+x^\frac{1}{2}}-\frac{(4+x)^\frac{1}{2}}{(1-x)^\frac{1}{2}}=0[/tex]

[tex]\frac{x^{\frac{1}{2}}+x^{-\frac{1}{2}}}{1-x}+\frac{1-x^{-\frac{1}{2}}}{1+x^\frac{1}{2}}=\frac{(4+x)^\frac{1}{2}}{(1-x)^\frac{1}{2}}[/tex]

[tex]\frac{(x+1)}{\sqrt{x}(1-x)}+\frac{(\sqrt{x}-1)}{\sqrt{x}(1+\sqrt{x})}=(\frac{4+x}{1-x})^{\frac{1}{2}}[/tex]

[tex]\frac{(\sqrt{x}+1)(x+1)+(\sqrt{x}-1)(1-x)}{\sqrt{x}(1-x)(1+\sqrt{x})}=(\frac{4+x}{1-x})^{\frac{1}{2}}[/tex]

[tex]\frac{x\sqrt{x}+x+\sqrt{x}+1+\sqrt{x}-1-x\sqrt{x}+x}{\sqrt{x}(1-x)(1+\sqrt{x})}=(\frac{4+x}{1-x})^\frac{1}{2}[/tex]

[tex]\frac{2x+2\sqrt{x}}{\sqrt{x}(1-x)(1+\sqrt{x})}=(\frac{4+x}{1-x})^\frac{1}{2}[/tex]

[tex]\frac{2(\sqrt{x}+1)}{(1-x)(1+\sqrt{x})}=(\frac{4+x}{1-x})^\frac{1}{2}[/tex]

[tex]\frac{2}{1-x}=(\frac{4+x}{1-x})^\frac{1}{2}[/tex]  if x ≠ ±1

[tex](\frac{2}{1-x})^2=\frac{4+x}{1-x}[/tex]  [Squaring on both the sides of the equation]

[tex]\frac{4}{(1-x)}=(4+x)[/tex]

4 = (1 - x)(4 + x)

4 = 4 - 4x + x - x²

0 = -3x - x²

x² + 3x = 0

x(x + 3) = 0

x = 0, -3

But both the solutions x = 0 and x = -3 are extraneous solutions, given equation has no solution.

Answer:

Could you please help me Genius??????

Twice the difference of a number and 9 is 3. Use the variable b for the unknown number.

Answers

Answer:

b = 10.5

Step-by-step explanation:

2(b-9) = 3

then:

2*b + 2*-9 = 3

2b - 18 = 3

2b = 3 + 18

2b = 21

b = 21/2

b = 10.5

check:

2(10.5 - 9) = 3

2*1.5 = 3

On a class trip with 40 students, 14 are male. What percentage of the class is female?

66%
60%
65%
58%

Answers

Answer:

65%

Step-by-step explanation:

If 14 are male, then 26 are female.

To find the percent female, divide the number of females by the total.

26/40 = 0.65

So, the percentage of the class that is female is 65%

Answer:

C. 65%

Step-by-step explanation:

We know that of the 40 total students, 14 are male, which means the remaining students are female.

To find how many are female, we subtract 14 from 40:

40 - 14 = 26 females

Percentage is simply a part divided by a whole, multiplied by 100. Here, the "part" is the number of females, which is 26. The "whole" is the total number of students, which is 40. So, we have:

(26 / 40) * 100 = 65

The answer is thus C, 65%.

~ an aesthetics lover

Solve for x. 2x+3≤x−5 x≤−8 x≤2 x≤8 x≤−2

Answers

Answer:

x≤−8

Step-by-step explanation:

2x+3≤x−5

Subtract x from each side

2x-x+3≤x-x−5

x+3≤−5

Subtract 3 from each side

x+3-3≤−5-3

x≤−8

Answer:

[tex]\huge \boxed{x \leq -8}[/tex]

Step-by-step explanation:

[tex]2x+3 \leq x-5[/tex]

[tex]\sf Subtract \ x \ from \ both \ parts.[/tex]

[tex]2x+3 -x\leq x-5-x[/tex]

[tex]\sf Simplify \ the \ inequality.[/tex]

[tex]x+3 \leq -5[/tex]

[tex]\sf Subtract \ 3 \ from \ both \ parts.[/tex]

[tex]x+3-3 \leq -5-3[/tex]

[tex]\sf Simplify \ the \ inequality.[/tex]

[tex]x \leq -8[/tex]

(a) A survey of the adults in a town shows that 8% have liver problems. Of these, it is also found that 25% are heavy drinkers, 35% are social drinkers and 40% are non-drinkers. Of those that did not suffer from liver problems, 5% are heavy drinkers, 65% are social drinkers and 30% do not drink at all. An adult is chosen at random, what is the probability that this person i. Has a liver problems?

Answers

Answer:

The probability that the selected adult has liver problems is 0.08

Step-by-step explanation:

In this question, from the data given, we want to calculate the probability that an adult selected at random has liver problems.

Let E(L) be the event that an adult has liver problems.

The probability is directly obtainable from the question and it is given as 8%

Thus, the probability that the selected adult has liver problems; P(L) = 8% = 8/100 = 0.08

Write the expression (x4)8 in simplest form.

Answers

The Answer is = 8x^4

Hope this helps! :)

Answer:

the 4 and 8 are exponents

Step-by-step explanation:

Today only, a suit is being sold at a 26% discount. The sale price is $259.
What was the price yesterday?

Answers

Answer:

$350

Step-by-step explanation:

1. Set up the equation. The sale price of $259 is 74% of the original price.

[tex]\frac{74}{100}[/tex] = [tex]\frac{259}{x}[/tex]

2. Cross multiply

74x = 25900

3. Solve

x = 350

find the derivative by using product rule and distribution
pls help quickly and show work ​

Answers

Answer:

Below

Step-by-step explanation:

First method:

● f(x)= (x^3-2x+1)×(x-3)

● f'(x)= (x^3-2x+1)' ×(x-3) + (x^3-2x+1)×(x-3)'

●f'(x)= (3x^2-2)×(x-3) + (x^3-2x+1) × 1

●f'(x) = 3x^3-9x^2-2x+6 + x^3-2x+1

● f'(x)= 4x^3-9x^2-4x+7

■■■■■■■■■■■■■■■■■■■■■■■■■■

Second method:

●f(x) = (x^3-2x+1)×(x-3)

●f(x) = x^4-3x^3 -2x^2+6x+x-3

●f(x) = x^4-3x^3-2x^2+7x-3

●f'(x) = 4x^3-9x^2-4x+7

We got the same result using both methods.

Please help me with this question

Answers

Answer:

  0 ≤ x ≤ 10

Step-by-step explanation:

The domain of f(x) is the set of values of x for which the function is defined. Here, the square root function is only defined for non-negative arguments, so we require ...

  -x^2 +10x ≥ 0

  x(10 -x) ≥ 0

The two factors in this product will both be positive only for values ...

  0 ≤ x ≤ 10 . . . . the domain of f(x)

How to simplify this expression??

Answers

Answer :

[tex] \frac{2 {x}^{3} + 7 {x}^{2} + 3x - 4}{ {x}^{3} + 3 {x}^{2} + x - 1} [/tex]

Step-by-step-explanation :

I did the explanation in the picture.

The letters x and y represent rectangular coordinates. Write the given equation using polar coordinates (r,θ) . Select the correct equation in polar coordinates below.

x2+y2−4x=0

a.  r=4 sinθ
b. r=4 cosθ
c. r cos2θ=4 sinθ
d. r sin2θ=4 cosθ

Answers

Answer:

B. r = 4cosθ

Step-by-step explanation:

Given the expression in rectangular coordinate as x²+y²−4x=0, in order to write the given expression in polar coordinates, we need to write the value of x and y as a function of (r, θ).

x = rcosθ and y = rsinθ.

Substituting the value of x and y in their polar form into the given expression we have;

x²+y²−4x=0

( rcosθ)²+( rsinθ)²-4( rcosθ) = 0

Expand the expressions in parenthesis

r²cos²θ+r²sin²θ-4rcosθ = 0

r²(cos²θ+sin²θ)-4rcosθ = 0

From trigonometry identity, cos²θ+sin²θ =1

The resulting equation becomes;

r²(1)-4rcosθ = 0

r²-4rcosθ = 0

Add 4rcosθ to both sides of the equation

r²-4rcosθ+4rcosθ = 0+4rcosθ

r² = 4rcosθ

Dividing both sides by r

r²/r = 4rcosθ/r

r = 4cosθ

Hence the correct equation in polar coordinates is r = 4cosθ

What is the measure of B, in degrees?

Answers

Answer:

B = 32

Step-by-step explanation:

Since this is an isosceles triangle, C is also equal to 74 degrees

 the angles of a triangle add to 180

A + B+ C = 180

74+ B + 74 = 180

148 + B = 180

B = 180-148

B =32

Use Lagrange multipliers to find three numbers whose sum is 30 and the product P = x3y4z is a maximum. Choose the answer for the smallest of the three values. Question 20 options: a) 21/4 b) 5 c) 15/4 d) 3

Answers

We want to maximize [tex]x^3y^4z[/tex] subject to the constraint [tex]x+y+z=30[/tex].

The Lagrangian is

[tex]L(x,y,z,\lambda)=x^3y^4z-\lambda(x+y+z-30)[/tex]

with critical points where the derivatives vanish:

[tex]L_x=3x^2y^4z-\lambda=0[/tex]

[tex]L_y=4x^3y^3z-\lambda=0[/tex]

[tex]L_z=x^3y^4-\lambda=0[/tex]

[tex]L_\lambda=x+y+z-30=0[/tex]

[tex]\implies\lambda=3x^2y^4z=4x^3y^3z=x^3y^4[/tex]

We have

[tex]3x^2y^4z-4x^3y^3z=x^2y^3z(3y-4x)=0\implies\begin{cases}x=0,\text{ or}\\y=0,\text{ or}\\z=0,\text{ or}\\3y=4x\end{cases}[/tex]

[tex]3x^2y^4z-x^3y^4=x^2y^4(3z-x)=0\implies\begin{cases}x=0,\text{ or}\\y=0,\text{ or}\\3z=x\end{cases}[/tex]

[tex]4x^3y^3z-x^3y^4=x^3y^3(4z-y)=0\implies\begin{cases}x=0,\text{ or}\\y=0,\text{ or}4z=y\end{cases}[/tex]

Let's work with [tex]x=3z[/tex] and [tex]y=4z[/tex], for which we have

[tex]x+y+z=8z=30\implies z=\dfrac{15}4\implies\begin{cases}x=\frac{45}4\\y=15\end{cases}[/tex]

The smallest of these is C. 15/4.

A young sumo wrestler decided to go on a special high-protein diet to gain weight rapidly. When he started his diet, he weighed 79.5 kilograms. He gained weight at a rate of 5.5 kilograms per month. Let y represent the sumo wrestler's weight (in kilograms) after x months. Which of the following could be the graph of the relationship? graph of an increasing linear function in quadrant 1 with a positive y-intercept (Choice B) B graph of an increasing linear function in quadrants 1 and 4 with a positive x-intercept and negative y-intercept (Choice C) C graph of a decreasing linear function in quadrants 1 and 4 with a positive x-intercept and positive y-intercept (Choice D) D graph of a decreasing linear function in quadrant 4 with a negative y-intercept

Answers

Answer:

(Choice A) A graph of an increasing linear function in quadrant 1 with a positive y-intercept.

Step-by-step explanation:

The weight of the sumo wrestler starts at a positive value of 79.5 kilograms, and we are given that the sumo wrestler gains a linear amount of weight per month at 5.5 kilograms per month.

If we were to graph this relationship, the sumo wrestler's weight would be represented on the y-axis, and the amount of time on the x-axis.

So the initial weight would occur at (0, 79.5) which is the positive y-intercept.

And since his weight is increasing at 5.5 kilograms per month, the slope of the linear function is positive.

Hence, the graph of the linear increasing function in quadrant 1 with a positive y-intercept.

Cheers.

Solve the following equation using the square root property.
9x2 + 10 = 5

Answers

Answer: -5/81

Solving Steps:

9x^2+10=5
Simplify- 81x+10=5
Subtract 10 from both sides- 81x +10 -10= 5 -10
Simplify- 81x= -5
Divide both sides by 81- 81x/81= -5/81
Simplify- X= -5/81

the coefficient of 6x

Answers

Answer:

The coefficient is 6

Step-by-step explanation:

The coefficient is the number in front of the variable

The variable is x

The coefficient is 6

Answer:

6

Step-by-step explanation: The coefficient of this would be the real number that is in front of a variable that is not a variable like x, and that number is 6. So, the coefficient of 6x is 6.

What is the critical F value when the sample size for the numerator is seven and the sample size for the denominator is six

Answers

Answer:

Critical F value  = 4.9503

Step-by-step explanation:

Given that:

The sample size of the numerator = 7

The sample size of the denominator = 6

The degree of freedom for the numerator df = n -1

The degree of freedom for the numerator df = 7 - 1

The degree of freedom for the numerator df = 6

The degree of freedom for the denominator df = n - 1

The degree of freedom for the denominator df = 6 - 1

The degree of freedom for the denominator df = 5

The assume that the test is two tailed and using a level of significance of ∝ = 0.10

The significance level for the two tailed test = 0.10/2 = 0.05

From the standard normal F table at the level of significance of 0.05

Critical F value  = 4.9503

7 1/4 x−x=9 3/8 HELLLLPPPPP PLLSSSS

Answers

-1.5

Step-by-step explanation:

So, you do 7.25 - 1 (because it is) and you get 6.25. Make it a fraction inton 25/4 and divide bu 75/8 (9 3/8 simplified) and you get -1.5 voila.

Answer:

x = 3/2

Step-by-step explanation:

7 1/4 = 7 + 1/4 = 28/4 + 1/4 = 29/4

9 3/8 = 9 + 3/8 = 72/8 + 3/8 = 75/8

then:

7 1/4 x = 29x/4

29x/4 - x = 75/8

29x/4 - 4x/4 = 75/8

25x/4 = 75/8

x = (75/8)/(25/4)

x = (75*4)/(8*25)

x = 300/200

x = 3/2

Checking:

(29/4)(3/2) = (29*3)(4*2) =  87/8

87/8 - 3/2 = 75/8

3/2 = 12/8

then:

87/( - 12/8 = 75/8

Two numbers, if the first one increases by 1, and the second one decreases by 1, then their product increases by 2020. If the first number decreases by 1, and the second one increases by 1, what value does the product decrease?

Answers

Answer:

The product decreases 2022.

Step-by-step explanation:

(x + 1)(y - 1) = xy + 2020

xy - x + y - 1 = xy + 2020

-x + y = 2021

(x - 1)(y + 1) = xy + x - y - 1

  + 2021   =       -x + y

----------------------------------

(x - 1)(y + 1) + 2021 = xy - 1

(x - 1)(y + 1) = xy - 2022

The product decreases 2022.

Sugar, flour, and oats are stored in three drawers. The first drawer is labeled "oats", the second is labeled, "flour", the third is labeled "oats or flour". The label of each drawer does not correspond to what is stored inside of it. In which drawers is what stored?

Answers

Answer:

first = flour, second = oats, third = sugar

Step-by-step explanation:

Since the labels are "wrong", we know that the third drawer doesn't have oats or flour, therefore it has sugar. Since the first doesn't have oats, it must have flour and that makes the second drawer oats.

Answer:

first drawer has flour, second has oats, third is sugar

Step-by-step explanation:

on the first drawer, it is labelled oats, so it cannot be oats. on the second it cannot be flour, and on the third it cannot be oats or flour, which means it HAS to be sugar leaving oats and flour to be in either the first, or second.

i know it may sound a little confusing but please let me know if you dont understand

Working together, it takes two computers 10 minutes to send out a company's email. If it takes the slower computer 50 minutes to do the job on its own, how long will it take the faster computer to do the job on its own? don't round

Answers

Answer:

12.5 minutes

Step-by-step explanation:

When working together,It takes two computers 10 minutes to send out an email

It takes the slower computer 50 minutes to send out an email

Let x represent the time taken by the faster computer to do the job in its own

Therefore, the time required by the faster computer can be calculated as follows

1/x + 1/50= 1/10

Collect the like terms

1/x= 1/10-1/50

1/x= 4/50

Cross multiply both sides

4 × x = 50×1

4x=50

Divide both sides by the coefficient of x which is 4

4x/4=50/4

x= 12.5

Hence the time taken by the faster computer to finish the job on its own is 12.5 minutes

Which geometric sequence has a first term equal to 55 and a common ratio of -5? {-55, 11, -2.2, 0.44, …} {55; 275; 1,375; 6,875; …} {55, 11, 2.2, 0.44, …} {55; -275; 1,375; -6,875; …}

Answers

Answer:

The answer is 55, -275, 1375, -6875......

Step-by-step explanation:


On dividing polynomial p(x) by a linear binomial, X - a, we get a quotien
statements must be proven true for the remainder theorem to be true

Answers

Answer:

Step-by-step explanation:

Hello, we can write

(1) p(x)=(x-a)q(x)+r

[tex]\boxed{\sf v}[/tex] True

It means that p(a)=0 * q(a) + r = r

so the first one is true.

[tex]\boxed{}[/tex] False

The second one is not to be proven true from the remainder theorem.

[tex]\boxed{\sf v}[/tex] True

For x different from a we can divide the equation (1) by (x-a).

[tex]\boxed{}[/tex] False

We cannot say anything on q(a).

[tex]\boxed{\sf v}[/tex] True

If the rest is 0 then it means that p(a) = 0

[tex]\boxed{\sf v}[/tex] True

If p(a) = 0 it means that the rest r = 0 and then p(x)=q(x)(x-a)

Thank you

Three 3.0 g balls are tied to 80-cm-long threads and hung from a single fixed point. Each of the balls is given the same charge q. At equilibrium, the three balls form an equilateral triangle in a horizontal plane with 20 cm sides. What is q?

Answers

Answer:

q = 0.105uC

Step-by-step explanation:

We can determine the force on one ball by assuming two balls are stationary, finding the E field at the lower right vertex and calculate q from that.

Considering the horizontal and vertical components.

First find the directions of the fields at the lower right vertex. From the lower left vertex the field will be at 0° and from the top vertex, the field will be at -60° or 300° because + charge fields point radially outward in all directions. The distances from both charges are the same since this is an equilateral triangle. The fields have the same magnitude:

E=kq/r²

Where r = 20cm

= 20/100

= 0.2m

K = 9.0×10^9

9.0×10^9 × q /0.2²

9.0×10^9/0.04

2.25×10^11 q

These are vector fields of course

Sum the horizontal components

Ecos0 + Ecos300 = E+0.5E

= 1.5E

Sum the vertical components

Esin0 + Esin300 = -E√3/2

Resultant = √3E at -30° or 330°

So the force on q at the lower right corner is q√3×E

The balls have two forces, horizontal = √3×E×q

and vertical = mg, therefore if θ is the angle the string makes with the vertical tanθ = q√3E/mg

mg×tanθ = q√3E.

..1

Then θ will be...

Since the hypotenuse = 80cm

80cm/100

= 0.8m

The distance from the centroid to the lower right vertex is 0.1/cos30 =

0.1/0.866

= 0.1155m

Hence,

0.8×sinθ = 0.1155

Sinθ = 0.1155/0.8

Sin θ = 0.144375

θ = arch sin 0.144375

θ = 8.3°

From equation 1

mg×tanθ = q√3E

g = 9.8m/s^2

m = 3.0g = 0.003kg

0.003×9.8×tan(8.3)

0.00428 = q√3E

0.00428 = q×1.7320×E

Where E=kq/r²

Where r = 0.2m

0.0428 = kq^2/r² × 1.7320

K = 9.0×10^9

0.0428/1.7320 = 9.0×10^9 × q² / 0.2²

0.02471×0.04 = 9.0×10^9 × q²

0.0009884 = 9.0×10^9 × q²

0.0009884/9.0×10^9 = q²

q² = 109822.223

q = √109822.223

q = 0.105uC

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