b. The skydriver has the fastest speed at 4 seconds statement best identifies her speed at each second.
The process by which friction slows something moving through air is known as air resistance.
The object's velocity, surface area, and shape all play a role in air resistance. Air density and resistance are affected by temperature, humidity, and altitude.
The greater the resistance, the greater the area and the greater the speed. The frequency at which air molecules come into contact with the object increases with speed. Air resistance increases as a result.
As a result, the sky driver's speed also increases as the air resistance of the 500N driver increases.
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(complete question)
A skydiver dives from an airplane. air resistance is measured each second following the skydiver’s jump.
Time after jump | Weight | Air Resistance
1 sec | 500 N | 200 N
2 sec | 500 N | 300 N
3 sec | 500 N | 400 N
4 sec | 500 N | 500 N
Which statement best identifies her speed at each second?
a. The skydriver has the slowest speed at 2 seconds
b. The skydriver has the fastest speed at 4 seconds
c. The skydriver has the slowest speed at 1 second
d. The skydriver has the fastest speed at # seconds
what is the equation describing the motion of a mass on the end of a spring which is stretched 8.8 cm from equilibrium and then released from rest, and whose period is 0.66 s ? assume that the displacement at the start of the motion is positive.
Answer:
x = A cos ω t at t = zero, x displacement equals amplitude
x = .088 m cos ω t describes the motion
We need yet to find ω in terms of P which is given
ω = √(k / m)
P = 1 / f and f = ω / (2 π)
Thus ω = 2 π f = 2 π / P since 1 / f = P
This gives us
x = .088 m cos 2 π / .66 * t
9. A piece of iron with a mass of 9.8 g has an initial temperature of 32.6°C. As it is heated, it absorbs 365J of energy. What is the final temperature of the iron? (The specific heat of iron is .46 J/g °C)
The final temperature of the piece of iron with the mass of 9.8 grams on the absorption of 365J of energy is 113.56°C.
What is Specific heat capacity?
The specific heat capacity of a material can be defined as the quantity of heat energy (J) which is absorbed per unit mass (kg) of the material when its temperature is increased by 1 K (or 1 °C). The SI unit of specific heat capacity is J/(kg K) or J/(kg °C).
The specific heat capacity of a material can be calculated by the formula:
Q = m × c × ΔT
where, Q = heat energy,
m = mass of the material,
c = specific heat capacity,
ΔT = change in temperature
The final temperature of the piece of iron can be calculated by the formula:
Q = m × c × ΔT
ΔT = (Final temperature - initial temperature)
365J = 9.8 × 0.46 × ΔT
365J = 4.508 × ΔT
ΔT = 80.96
ΔT = Final temperature = initial temperature
ΔT = (T - 32.6)
80.96 = (T - 32.6)
T = 80.96 + 32.6
T = 113.56°C
Therefore, the final temperature of the piece of iron is 113.56°C.
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Study the following systems: SYSTEM A: Electricity is used to heat a hot plate which heats water making steam which powers a turbine and a generator which makes electricity which is used to power a radio. SYSTEM B: Electricity is used to power a radio. Which system (A or B) is more energy efficient and explain why.
The system that is more energy efficient is system A because it makes use of electricity to produce more results.
What is energy efficiency?Energy efficiency is the use of less energy to perform the same task or produce the same result.
Energy-efficient homes and buildings use less energy to heat, cool, and run appliances and electronics, and energy-efficient manufacturing facilities use less energy to produce goods.
Energy efficiency has the following benefits:
It saves moneyIt increases the resilience and reliability of the electric gridIt provides environmental, community, and health benefitsAccording to this question, the following applies:
SYSTEM A: Electricity is used to heat a hot plate which heats water making steam which powers a turbine and a generator which makes electricity which is used to power a radioSYSTEM B: Electricity is used to power a radioBased on the above explanation, it can be observed that system A is more energy efficient because it uses the same electricity to achieve more.
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To determine the acceleration due to gravity, g uing imple pendulum at
different place. ( SOME ONE PLEASE HELP ME ITS MY SCHOOL PROJECT MINIMUM PAGES SHOULD BE 20 )
THANK YOU
M is the mass, and R is the body's radius, hence g=R2GM (planet).The pendulum's time period varying as its acceleration with respect to gravity changes.
How do I determine the acceleration due to gravity using a simple pendulum?Example: On the surface of the earth, a basic pendulum swings for a period of time T 0. This straightforward pendulum would have a period of 12 /xT 0 on a planet with an earth-like density but a radius four times that of the earth.
Answer: T 0 = 2 π√g / L is the formula for a simple pendulum's time period.
The value of g changes in accordance with the mass of a different planet that we visit.
g= GM / R² is the result.
M, which stands for mass, and R, which stands for body radius (planet).
Given, the radius is four times larger for a different planet with the same density.
Given, the radius is four times larger for a different planet with the same density.
M=density, volume, and p = 4/3 πR³
g= G * (p 4/3 πR³ / R² = G * p 4/3 π R
Here, R = 4R
⇒ G×ρ 3 / 4 π(4R)=4g
T 0 represents the new time frame.
T0 = 2π √ L/4g = T0/2
Consequently, 12/ x = 2 /1 x=6 because of =T 0 /2.
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Between which two points on the heating curve is the substance melting
The Curve horizontal or plateaued lines represent the change in the sample's states. The first plateau is a symbol of melting and the second one is a symbol of boiling (or transition from liquid to gas).
What does a heating curve's melting point represent?Phase changes are another name for the plateaus. Melting is the initial state shift (section BC) (changing from a solid to a liquid). While a substance melts, the temperature remains constant. This temperature is 0°C for water as that is also its melting point.
What does a substance's heating curve look like?A heating curve is a plot or graph that charts the increase in temperature of a substance over time to determine
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find the maximum transverse speed of a point on the string. (f) what would be the equation y1x, t2 for this string if it were vibrating in its eighth harmonic?
In a one-dimensional string, a harmonic wave has a maximum transverse velocity and maximum transverse acceleration of 1ms-1 and 1ms-2, respectively.
What is maximum transverse speed of a point on the string?We have attached a harmonic wave with a frequency of 80 Hodge to the string. Additionally, a positive extraction travels at a speed of 12 m/s with an amplitude of 0.025 m. Next, we must create a proper wave function for this wave in the first. In light of this.
we have established that the frequency F is the hurt amplitude is 0.025 m, and the speed is 12 m/s. As a result, given that we are aware of the wave function's writing, we may determine whether or not the sign K x minus omega T applies. Omega, which equals two pi into, is the angular frequency in this case. Thus, we can say that this word has been introduced. 80 is to be purchased That makes 160 by, too.
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by studying distant galaxies in the 1920s, hubble made what important discovery that led us to conclude that the universe is expanding?
All galaxies outside the Local Group are moving away from us, and the farther away they are, the faster they're going.
How is Hubble's law defined?We may learn a lot about the nature of the cosmos from Hubble's rule, which states essentially that a known universe velocity (or, as it is commonly displayed, its redshift) is precisely proportionate to its distance. The relationship between distance and speed should not exist if the cosmos is constant and unchanging.
What is the name of Hubble's theory?The Hubble-Lemaître law, commonly referred to as Hubble's law, is the finding in astrophysics that planets are eloping from Earth at rates proportionate to their separation. In other words, they are travelling away from Earth more quickly the more away they are.
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a 6.2 kg object heading north at 3.0 m/s collides with an 8.0 kg object heading west at 3.5 m/s. if these two masses stick together upon collision, what is their velocity after collision?
The velocity of both objetcs after the collision is 3.07m/sec if both object masses are 6.2 kg and 8.0kg respectively.
To find the velocity of both objects we need to conserve the momentum. We need to follow the law of conservation of momentum which states that initial momentum is equal to final momentum.
Now, we know that momentum =mass × velocity
So, initial momentum of first object=6.2×3=18.6Kg-m/sec
Similarly, initial momentum of second object=8×3.5=28.0kg-m/sec
Now, it is given that both object stick together, so total mass of both objects are=(6.2+8)=14.2kg
Now, both objects are moving with common velocity, so assume both have velocity v
=>So, final momentum of both objects is =14.2×v
according to law of conservation of momentum
=>18.6+25=14.2v
=>43.6=14.2v
=>v=43.6/14.2
=>v=3.07m/sec
Hence, final velocity of objects are 3.07m/sec.
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The adjacent figure shows a solid 'S' of weight 15N connected to a thread and put on an inclined plane. 1) a-Is the weight of solid 'S' a contact force or a force acting from a distance? b- List the characteristics of the weight of solid 'S'. Thread Inclined plane c- Represent the weight of solid 'S' by a vector. Choose a convenient scale. 2) a- Name the other forces acting on solid 'S' and indicate their types. b- Represent each force by a vector without respecting a scale. c- List the characteristics of each of the above forces. (Without the magnitude) 3) The thread is cut and solid 'S' moves as shown in the adjacent figure a- Name the new force that acts on solid 'S' and indicate its type. b- List the characteristics of this force.(scale 1cm-1.3N). Thread Inclined plane Solid 'S' Solid 'S'
Answer:
Here is answer
Explanation:
a) The weight of the solid 'S' is a contact force because it acts on the solid 'S' through physical contact with the ground.
b) The characteristics of the weight of solid 'S' are:
It acts in the downward direction.
It is a gravitational force that is exerted by the Earth on the solid 'S'.
It is equal to the mass of the solid 'S' multiplied by the acceleration due to gravity (W = m*g).
c) The weight of solid 'S' can be represented by a vector as shown below:
[asy]
unitsize(1cm);
draw((0,0)--(0,15),Arrow(6));
label("$W$", (0,7.5), W);
[/asy]
a) The other forces acting on solid 'S' are the normal force exerted by the inclined plane on the solid 'S' and the frictional force exerted by the inclined plane on the solid 'S'. The normal force is a contact force, while the frictional force is also a contact force.
b) These forces can be represented by vectors as shown below:
[asy]
unitsize(1cm);
draw((0,0)--(0,15),Arrow(6));
label("$W$", (0,7.5), W);
draw((0,0)--(15sqrt(2)/2,15/2),Arrow(6));
label("$N$", (7.5sqrt(2),7.5), NE);
draw((0,0)--(-15sqrt(2)/2,-15/2),Arrow(6));
label("$F_f$", (-7.5sqrt(2),-7.5), SW);
[/asy]
c) The characteristics of these forces are:
The normal force acts perpendicular to the surface of the inclined plane.
The frictional force acts in the opposite direction to the direction of motion or intended motion of the solid 'S'.
The magnitude of the normal force is equal to the weight of the solid 'S', but in the opposite direction.
The magnitude of the frictional force depends on the coefficient of friction between the solid 'S' and the inclined plane, as well as the normal force.
a) The new force acting on solid 'S' is the gravitational force, which is a force acting from a distance.
b) The characteristics of the gravitational force are:
It acts in the downward direction.
It is a force that is exerted by the Earth on the solid 'S'.
Its magnitude can be represented by the vector shown below (using a scale of 1 cm to represent 1.3 N):
[asy]
unitsize(1cm);
draw((0,0)--(0,-1.3),Arrow(6));
label("$W$", (0,-0.65), S);
[/asy]
do i need to adjust the tension on my elna super sewing machine when using denim fabric and 100/16 needles?
A tension of 3.5 to 4.5 is advised when sewing tough fabric, such denim or leather. This allows you to effortlessly maintain neatness across the fabric when sewing through it. Before starting to sew any thick material, check the attachments on your sewing machine and adjust the tension.
Depending on the thickness of the denim, I use a straight-stitch length between 3.0 mm and 4.0 mm. I also increase the tension on my machine to 4.6 (up from 4.0 for lightweight woven fabrics). If my denim has spandex in it, I use a stretch stitch, such as a narrow zigzag.
Linen, cotton and denim: These fabrics hold wrinkles well, so they require the highest heat, from 150 to 200 degrees. If needed, you may also use steam or spray water from a bottle or your iron.
The longer the stitch length, the easier and faster it will be to pull the fabric along the gathering threads. However, the shorter the stitch length, the easier it will be to achieve even gathers. We find a 4.5 mm setting to be a good compromise, but it's always a good idea to test and see what you prefer.
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a 1,402-kg car rounds an unbanked curve with a radius of 53 m at a speed of 9.9 m/s. what minimum coefficient of friction must exist between the road and tires to prevent the car from slipping?
To keep the car from slipping, the road and tires need to have a minimum coefficient of friction of 0.188.
The things creating friction will determine the coefficient of friction. The value is often between 0 and 1, but it can also be higher. A number of 0 indicates that there is absolutely no friction between the items; superfluidity makes this feasible. Yes. Because the adhesive forces between molecules are stronger when the contact surface is substantially polished, frictional force increases. In this situation, the friction coefficient will be higher than one.
Here m= 1402 kg
r=53
v= 9.9 m/s
g=9.8
coefficient = (v^2) / rg
coefficient = (9.9^2) / (53*9.8)
coefficient = 98.01/519.4
coefficient = 0.188
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let's say you see a comet's nebulous (meaning `cloudy-looking') tail stretching across the sky, and it's several million kilometers long. how big is the solid object that has developed this tail, and what's it made of?
The solid object that created the comet's nebulous tail is likely the nucleus of the comet, which is typically made of ice, dust, and rocky material.
What is comet?Comet is a web application development technique that enables web applications to send and receive data from a server asynchronously without the need for a browser page refresh. It creates an interactive user experience by enabling a continuous connection between the client and server so that data can be exchanged in both directions. This type of communication is also known as a bi-directional, full-duplex connection. Comet is an umbrella term for several techniques for achieving this kind of communication.
The nucleus of a comet can range in size from a few hundred meters to tens of kilometers, though their average size is typically around 5 kilometers. As the comet approaches the Sun, its frozen material turns to gas, which is pushed away from the Sun by the solar wind and forms the nebulous tail that stretches millions of kilometers across the sky.
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a 65 kg person dives into the water from the 10 m platform. a. what is her speed as she enters the water?
The speed of the person as she enters the water is 14.2 m/s.
What is kinetic energy?Kinetic energy is the energy of motion. It is the energy that an object has due to its motion. This energy can be transferred from one object to another or converted into other forms of energy. Kinetic energy is dependent on an object's mass and its velocity. The greater an object's mass or velocity, the more kinetic energy it has. Kinetic energy can be used to do work, such as powering a machine or vehicle. It can also be used to generate electricity or to heat up objects.
The speed of the person as she enters the water can be calculated using the equation for kinetic energy:
KE = ½mv²
Where m is the mass of the person (65 kg) and v is the speed.
Solving for v, we get:
v = √(2KE/m)
Since the potential energy of the person just before she enters the water is equal to the kinetic energy of the person just after she enters the water, we can calculate the kinetic energy as:
PE = mgh
KE = mgh
Where m is the mass of the person (65 kg), g is the acceleration due to gravity (9.8 m/s²), and h is the height of the platform (10 m).
Plugging this into the equation for v, we get:
v = √(2mgh/m)
v = √(2gh)
v = √(2*9.8*10)
v = 14.2 m/s
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Question 8 of 20
You heat a pot of water on a gas stove. Not all the energy from the
combustion of the gas is transformed into thermal energy. What happens to
the rest of the energy released when the gas burns?
OA. It is transformed into light energy.
OB. It is transformed into chemical energy.
C. It is transformed into electrical energy.
OD. It is transformed into nuclear energy.
SUBMIT
Answer:
None of the choices you provided are correct. When a gas burns, it releases energy in the form of heat and light. Some of this energy is transferred to the pot of water, increasing its temperature, but some of the energy is also released as light. However, the rest of the energy is not transformed into chemical, electrical, or nuclear energy. Instead, it is lost to the environment in the form of waste heat. This is why gas stoves can become hot to the touch - they are releasing excess energy in the form of heat that is not being used to heat the pot of water.
Explanation:
Three point charges are arranged in a straight line. The point charges are q1 = 10.0 μC, q2 = –40.0 μC, and q3 = –30.0 μC. Charge q1 is 10.0 cm from charge q2, and charge q3 is 20.0 cm from charge q2. Determine the magnitude of the net electric force on charge q1.
Let us find first the forces at 1, 2 & 3 points.
We know that ke= 8.99 * 109N.m2 / C2
The forces are: -
F1 = keq1q2 / r212 = {8.99 * 109N.m2 / C2} * {10 * 10-6 C} * {40 * 10-6 C} / {10 * 10-2 m}2
F1 = 359.6 N
F2 =keq1q3 / r213 = {8.99 * 109N.m2 / C2} * {10 * 10-6 C} * {30 * 10-6 C} / {30 * 10-2 m}2
F2 = 29.96 N
F3 = keq2q3 / r213 = {8.99 * 109N.m2 / C2} * {40 * 10-6 C} * {30 * 10-6 C} / {20 * 10-2 m}2
F3 = 269.7 N
Now,
The net force on q1 is F1 – F2,
i.e. F1 + F2 = 359.6 + 29.96
F(q1) = 389.56 N to the left
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- Determine the tension in each cable in the diagram to the right.
Tension of the three cables connecting the celling, 7 kg ball, 4 kg ball, 5 kg ball respectively 156.8 N, 88.2 N and 49 N.
What is tension?The force communicated through a rope, string, or wire when two opposing forces draw on it is known as tension. The tension force pulls energy equally on the bodies at the ends and is applied along the entire length of the wire.
Tension of the cable connecting the celling and 7 kg ball:
= (7 kg + 4 kg + 5Kg) × 9.8 m/s²
= 156.8 N.
Tension of the cable connecting the 7kg ball and 4 kg ball:
= (4 kg + 5Kg) × 9.8 m/s²
= 88.2 N.
Tension of the cable connecting the 4kg ball and 5 kg ball:
= 5Kg× 9.8 m/s²
= 49 N.
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WILL GIVE BRAINLY IF RIGHT
what would happen if you dropped, at the same time, particles of different shapes from a boat into still water
Explanation:
If you dropped particles of different shapes from a boat into still water, they would fall straight down due to the force of gravity. The speed at which they fall would depend on their mass and the shape of the particles could affect how they move through the water, but ultimately they would all sink to the bottom of the water body. If the particles are buoyant, they may float instead of sinking.
which deductible level would result in the lowest premium for automobile insurance?
The deductible level that would result in the lowest premium for automobile insurance is from $250 or $500
Is a greater or lower deductible preferable?For those who anticipate needing expensive medical care or continuous medical treatment, a plan without a deductible typically offers good coverage and is a wise decision.
In most circumstances, a plan's premium will be lower the larger its deductible. You save money on what you pay each month when you're willing to pay more up front when you need care.
The typical range for a comprehensive deductible suggested by insurance agents is between $100 and $500. It makes sense to have a smaller deductible for comprehensive claims because they often involve less damage than collision claims.
High-deductible health plans typically have cheaper premiums but need greater upfront payments before insurance will cover medical expenses. Meanwhile, higher premiums are typically associated with health insurance plans with lower deductibles since they provide more predictable expenses and frequently more robust coverage.
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A 20 kg wagon is pulled along the level ground by a rope inclined 30 degrees above the horizontal (friction is
negligible) (A) How large is the pulling force is the wagon accelerates of .40 m/s²? (B) What is the normal force of
the wagon?
Answer:
(A) 9.2 Newtons
(B) 200.8 Newtons
Explanation:
Attached is the free body diagram I drew along with some of the work/formulas I used. Please ask me any questions you have in the comments about my diagram/work. I'd be happy to walk you through it.
sir lancelot, who weighs 800 n, is assaulting a castle by climbing a uniform ladder that is 5.0 m long and weighs 180 n. the bottom of the ladder rests on a ledge and leans across the moat in equilibrium against a frictionless, vertical castle wall. the ladder makes an angle of 53.1 deg with the horizontal. lancelot pauses one third of the way up the ladder. (a) find the normal force and friction forces on the base of the ladder. (b) find the minimum coefficient of static friction needed to prevent slipping at the base. (c) find the magnitude and direction of the contact force on the base of the ladder. (that is, the vector sum of the forces at the base.)
(a) The normal force is 267.7 N and frictional force is 980 N.
(b) The minimum coefficient of static friction is 0.27, which is needed to prevent slipping at the base.
(c) The direction of the contact force is 1016 N.
∈(t) = 0
N₂ ( L sinθ ) = 800 ( [tex]\frac{L}{3}[/tex] cosθ )
N₂ = 267.7 N
(a) Normal force F(d) = N₂ = 267.7 N
Frictional force N = 800 + 180
N = 980 N
(b) The minimum coefficient of static friction,
F(d) = μ N₁
μ = F / N₁
μ = 267.7 / 980
μ = 0.27
(c) The direction of the contact force,
R = [tex]\sqrt{(980)^{2} + (267.7)^{2} }[/tex]
R = 1016 N
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a simple harmonic oscillator takes 11.5 s to undergo five complete vibrations. (a) find the period of its motion. s (b) find the frequency in hertz. hz (c) find the angular frequency in radians per second. rad/s
The required values are a) T = 2.3 seconds, b) f = 0.434 Hz, c) ω = 2.7 rd/s.
Which of the following motions is simply harmonic?Simple harmonic motion, a particular kind of periodic motion in which a particle repeatedly oscillates around a mean location, In U-tube oscillating liquid column motion is hence simple harmonic.
According to question:Given,
Time = 11.5 seconds to five complete vibrations.
a) Time period is time taken to complete one vibration,
So T = 11.5/5 = 2.3 seconds
b) Frequency(f) = 1/T
f = 1/2.3 = 0.434 second inverse.
c) By using formula of angular frequency ω = 2π/T
ω = 2π/2.3 = 2.7 hz
Thus, final values are a) T = 2.3 seconds, b) f = 0.434 second inverse, c) ω = 2.7 rd/s.
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a system releases heat to the surroundings and no work is done on or by the system. what are the signs of qsystem and wsystem?
Heat that is emitted into the environment is harmful. The system's work output is zero.
The movement of mechanical energy from one item to another is referred to as work. Work is measured in the same units as energy since it is a movement of energy: joules (J). The total energy of an object will change as a force is applied to it across a distance. The object's kinetic energy will vary as a result of either acceleration or deceleration. Its potential energy will change, for instance, if it is raised up to a given height while being pulled by gravity.
Hence, sign are used based on the release and absorbed.
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when you look at a single slit diffraction pattern produced on a screen by light of a single wavelength, you see a bright central maximum and a number of maxima on either side, their intensity decreasing with distance from the central maximum. if the wavelength of the light is increased:_____.
The pattern gets bigger as the light wave length gets longer. other maxima are further from the central one and are wider.
What wavelength does it have?A wavelength is the distance between two identical locations (adjacent crests) in successive cycles in a waveform signals that is transmitted by a wire or in space. Typically, this length is expressed in feet (m), millimeters (cm), or millimeters (mm) in wireless systems (mm).
What do wavelengths and frequencies refer to?The distance that separates two wave crests is known as the wavelength, and it also applies to troughs. The number of vibrations that pass across a certain area in a second, or 60hz (Hz), is the unit of measurement for frequency (Hertz).
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ernie is trying to swim directly across a rushing river. ernie can swim at a rate of 6.2 m/s. the river's current is moving at a rate of 10.7 m/s. calculate the magnitude of ernie's resultant velocity?
The magnitude of Ernie's resultant velocity is [tex]V=8.72m/s[/tex].
Velocity:
Velocity is the direction in which an object is moving and serves as a measure of the rate at which its position is changing as seen from a specific point of view and as measured by a specific unit of time. In kinematics, the area of classical mechanics that deals with the motion of bodies, velocity is a fundamental idea.
Given,
Ernie's swimming rate with respect to the river [tex]V_{ER} =6.2 m/s[/tex]
River's current rate [tex]V_{R}=10.7 m/s[/tex]
Hence,
The magnitude of Ernie's resultant velocity
[tex]V[/tex] = [tex]V_{R} -V_{ER}=10.7i - 6.2j[/tex]
[tex]V=\sqrt{(10.7)^{2}-(6.2)^{2} }[/tex]
[tex]V=8.72m/s[/tex]
Hence,
The magnitude of Ernie's resultant velocity is [tex]V=8.72m/s[/tex].
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a constriction in a pipe reduces its diameter from 4.0 cm to 2.0 cm. where the pipe is narrow the water speed is 8.0 m/s. where it is wide the water speed is:
The velocity on the narrow side is 11.6 m/s. This is the velocity of the water in the narrow part of the pipe.
How to find velocity ?To find the velocity of the water where the pipe is narrow, you can use the formula for the mass flow rate, which is given by:
Mass flow rate = Density * Flow rate
= Density * (Area * Velocity)
Where:
Density is the density of the fluid
Flow rate is the volume flow rate, or the rate at which volume flows through the pipe
Area is the cross-sectional area of the pipe
Velocity is the velocity of the fluid
The mass flow rate is constant, so you can set the mass flow rate on either side of the constriction equal to each other and solve for the velocity on the other side.
The cross-sectional area of the pipe on the narrow side is given by the formula for the area of a circle:
A = pi * r^2
Where:
A is the cross-sectional area of the pipe
r is the radius of the pipe
The radius of the pipe on the narrow side is 3 cm / 2 = 1.5 cm. Plugging this value into the formula for the cross-sectional area, you get:
A = pi * (1.5 cm)^2
= 7.07 cm^2
The cross-sectional area of the pipe on the wide side is given by the same formula, with a radius of 6 cm / 2 = 3 cm:
A = pi * (3 cm)^2
= 28.27 cm^2
Since the mass flow rate is constant, you can set the mass flow rates on either side of the constriction equal to each other and solve for the velocity on the other side:
(Density * 7.07 cm^2 * v) = (Density * 28.27 cm^2 * 8 m/s)
Solving for v, the velocity on the narrow side, you get:
v = (Density * 28.27 cm^2 * 8 m/s) / (Density * 7.07 cm^2)
= 11.6 m/s
The final value for the velocity on the narrow side is 11.6 m/s. This is the velocity of the water in the narrow part of the pipe.
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the force between between two objects increases by what factor if the distance between them is changed 4.5 times the original separation?
The new gravitational force between the object will be 1/20.25 times of the original force.
The gravitational force between any two object is defined as the product of the masses of the object and it is inversely proportional to the square of the distance between them which is given by,
F = GMm/R²
Here,
G is the universal gravitational constant, M and m are the mass of the body and R is the distance between them.
As per the given question the distance between the object is increased 4.5 times the original separation.
R' = 4.5R.
The new force of attraction between the object will be,
F' = GMm/(R')²
F' = GMm/(4.5R)²
F' = GMm/20.25R²
F' = F/20.25
So, the new force of attraction between the two objects will become 1/20.25 times of original force.
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a type of cuckoo clock keeps time by having a mass bouncing on a spring, usually something cute like a cherub in a chair. what force constant (in n/m) is needed to produce a period of 0.340 s for a 0.0200 kg mass?
According to the information available in the question, the force constant is 6.83N/m.
Using the relation;
T = 2π√m/k
T = period = 0.340 s
m = mass in kilograms = 0.0200 kg
k = spring constant = ?
Making k the subject of the formula;
k = 4π^2m/T^2
k = 4 × (3.142)^2 × 0.0200/(0.340 )^2
k = 4 × (3.142)^2 × 0.0200/(0.340 )^2
k = 6.83 N/m
In physics, force is that power that can change the motion of an item. It also can be described intuitively as a push or a pull. A force has both value and path, making it a vector quantity.
Force is a push or a pull and it affects our daily lives because, without force, people might not be capable of opening and near stuff or lifting up their arms or legs.
Variety of Forces :
* Frictional Forces
* Tension force.
* Spring force.
* Gravitational force.
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Where does the depenent variable go on a graph?
The dependent variable go on the Y-axis on a graph.
what is a dependent variable?The dependent variable is described as the variable that is being measured or tested in an experiment.
Dependent variable can be explained using the example where a test score could be a dependent variable because it could change depending on several factors such as how much you studied, how much sleep you got the night before you took the test, or even how hungry you were when you took it.
The independent variable is found on the x-axis (horizontal line) of the graph and the dependent variable is displayed on the y-axis.
The difference between independent variable and the dependent variable is that in an experiment, the independent variable is the variable that is varied or manipulated by the researcher.
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9) During a game of bowling, which of the following describe the ball's motion?(SELECT ALL ANSWERS THAT APPLY)
A) The ball is accelerated while it is pushed by the student's hand due to an
unbalanced force.
B) The ball slows down as it rolls because friction exerts an unbalanced force.
C) The ball is accelerated while it is held in the student's hand due to balanced
Forces.
D) The ball does not change its motion as it rolls because of the balanced force
provided by friction.
E) The ball does not change its motion while it is held in the student's hand due to
balanced forces.
During a game of bowling the ball's motion:
The ball is accelerated while it is pushed by the student's hand due to an unbalanced force.The ball slows down as it rolls because friction exerts an unbalanced force.The ball does not change its motion while it is held in the student's hand due to balanced forces.The correct options are A,B and E.
Description of a bowling ball's motionBowling ball motion is commonly divided into sequential skid, hook, and roll phases. When the ball moves down the lane in the skid and hook phases, frictional contact with the lane causes the ball's forward (translational) speed to continually decrease, but to continually increase its revolution rate (rotational speed).
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Can someone please help me with this calculation? It's a bit confusing for me.
You are calculating the average speed, velocity, and acceleration of a toy car.
I'm not sure what the speed of the toy car was or the acceleration. I only have the times of the meters.
first meter: 2.00, second meter: 4.00, third meter: 6.20, fourth meter: 8.01, fifth meter: 10:13, sixth meter: 12:13, seventh meter: 14:13, eighth meter: 16:14, ninth meter 18:18 and tenth meter: 20:00.
Answer the following questions.
Did the car travel at a constant speed? (Hint: you must calculate the speed at every meter)
What was the average speed of the car?
Describe the overall motion of the car.
What are some practical applications for determining the motion of an object?
Answer: See Explanation
Explanation:
Did the car travel at a constant speed?
This means "Is the speed at each interval the same?"
There are 10 intervals for which to calculate from.
For each one, the speed is the distance traveled divided by the time.
Each interval is 1 meter long (distance).
1st: 1 meter / 2.00 s = 0.5 m/s
2nd: 1 meter / (4.00 - 2.00) s = 0.5 m/s
3rd: 1 meter / (6.2 - 4.0) s = 0.454 m/s
Right here you can see that the speed is different, NO is the answer.
Average Speed = total distance divided by total time
v = d / t v = (10 m) / (20:00 s) = 0.5 (m/s)
Describe the overall motion: (continue on with step one to see the total motion over the 10 meters)
4th: 0.552
5th: 0.472
6th: 0.5
7th: 0.5
8th: 0.4975
9th: 5.39
10th: 0.55
Overall motion stayed steady from 0-2 meters, slowed for the 3rd meter, sped up for the 4th, slowed down the 5th, stayed steady until slowing down in the 8th meter, then increased speed til the 10th meter.
Races would be practical applications to see where people/cars pace themselves, push themselves, etc.
