Answer:
Initial speed of stone = 12.25 m/s
Explanation:
Given:
Change in distance = 0.15 m
Force applied = 28 N
Find:
Initial speed of stone
Computation:
Using conservation of energy
(1/2)fs² = (1/2)(mv²)
fs² = (mv²)
(28)(0.15)² = (0.028)(v²)
v² = (28)(0.15)²/(0.028)
v = 12.25
Initial speed of stone = 12.25 m/s
Two planetoids with radii R1 and R2 and local accelerations g1 and g2 are separated by a centre-to-centre distance D, and are members of a simple two-body system. A rocket is located on planetoid 1 and is scheduled to launch from this planetoid to a point between the planetoids where the net gravitational force on the rocket by the two planetoids is zero. At what distance from the centre of planetoid 1 is the zero gravitational point? Choose R1 = 1400m, R2 = 1000m, g1 = 7.5m/s2, g2 = 5.3m/s2 and D = 4800m. [5 points]
Answer:
Therefore, the gravitational zero points between two planetoids lie at a distance of 3000 m from the center of planetoid 1.
Explanation:
From Newton’s gravitation formula, the expression of the mass (M) of the planet of radius R is given as,
[tex]F_{G} = mg_{1}\\ \left ( \frac{GMm}{{R_{1}}^{2}} \right )=mg_{1}\\\\M= \frac{gR^{2}}{G}\rightarrow \left ( 1 \right )[/tex]
Let's take x to be the distance of the zero gravitational points from the center of the planetoid 1.
Thus, the distance of the zero gravitational points from the center of the planetoid 2 is (D-x).
At zero gravitational point, the gravitational force between the planets and the rocket must be equal.
Un tren viaja inicialmente a 16m/s se acelera constantemente a razón de 2m/s2 en la misma dirección. ¿Cuán lejos viajará en 20s?
Answer:
d = 720 s
Explanation:
The question says, "A train initially traveling at 16m / s accelerates constantly at a rate of 2m / s2 in the same direction. How far will it travel in 20s?"
Initial speed, u = 16 m/s
Acceleration, a = 2m/s²
We need to find the distance covered by it in 20 seconds. Let the distance is d. Using the second equation of motion,
[tex]d=ut+\dfrac{1}{2}at^2\\\\d=16\times 20+\dfrac{1}{2}\times 2\times 20^2\\\\d=720\ m[/tex]
So, it will cover 720 m in 20 seconds.
6. The electric force between two charged objects is influenced by
Answer:
the amount of each charge and the distance between them. ... Coulomb's law states the the electric force between two charges is proportional to the product of the two charges and inversally proportional to the square distance that separates their centers.
what means 10² what we call this
we call it as well as 100 . so easey
Answer:
10 squared
Explanation:
10 squared
In Depth:
Let have a square that has a side length of 10.
A square four sides are equal and if we find the area of a squared, our formula is
[tex] {s}^{2} [/tex]
Our in this instance,
[tex] {10}^{2} [/tex]
or we call it
[tex]10 \: \: squared[/tex]
The potential difference across a resistor increases by a factor of 4. How
does the current change? (Ohm's law: V = IR)
A it increases by a factor of 4
B it decreases by a factor of 4
C it increases by a factor of 2
D it decreases by a factor of 2
Answer:
Correct option is C it decreases by a factor of 2
Answer: A - it increases by a factor of 4
Explanation:
Ohm's law is V = IR where V = potential difference, I = current, and R = resistance. Assuming that resistance stays constant (since the question mentioned no change in resistance), we only need to look at "V" and "I" in the equation V = IR.
"V" and "I" are directly proportional. In other words, whatever change happens to "V" will also occur to "I". Since "V" increases by a factor of 4, then "I" will also increase by a factor of 4.
You could also approach this problem by plugging in a change of 4 for the potential difference in the equation: V = I*R.
If we plug in 4V for V, we now have:
4V = I*R
Since the left side increases by a factor of 4, then the right side (only looking at current in this case) will also need to increase by a factor of 4 in order to have the right side stay equal to the left. Therefore, current will also increase by a factor of 4.
a &b
1 point
98. In the change in temperature
1°C > 1K
1°C < 1K
1°C = 1 K
1°C > 1.8K
a
Explanation:
1 degree celcious is the change
Question 12 of 15
If nitrogen, which has an electronegativity of 2.0, bonds with hydrogen, which
has an electronegativity of 2.1, the bond between the two atoms will be
classified as a(n)
covalent bond.
Answer here
SUBMIT
Answer:
Covalent bond.
Explanation:
There are 4 main types of bonds:
Covalent, ionic, metallic, and hydrogen.
Covalent bond: Involves the sharing of pairs of electrons, here the difference between the electronegativity of the atoms is not too large. Covalent bonds usually form an octet of electrons.
Ionic bond: This happens because the electrostatic attraction between the atoms whit very different electronegativities
Hydrogen bond: Electrostatic attractive force between an electronegative atom and a hydrogen atom covalently bonded to another electronegative atom.
Metallic bond: Type of bond that makes the metallic atoms to stay really tightly together. The atoms bond because of the electrostatic atractive force between conduction electrons and positively charged metal ions.
Now, in this case, we have the bond between Nitrogen (electronegativity = 2.0) and Hydrogen (electronegativity = 2.1)
So we can see that:
The elements are not metals, so we can discard metallic bond.
For a hydrogen bond, we need 3 atoms (one of which is hydrogen), here we have two, so we can discard this option.
Ionic bond needs different electronegativities, here the electronegativities are really close together, so the ionic bond can be discarded.
we can conclude that the bond will be a covalent bond.
If the electric force between two charges is 4.2 × 10-2 N, what would the new force be if the distance between the charges is doubled and the charge on one of the charges is tripled?
Answer:
New force = 0.063 N
Explanation:
Given that,
The electric force between two charges is[tex]4.2\times 10^{-2}\ N[/tex]
The formula for the electric force is:
[tex]F=\dfrac{kq_1q_2}{r^2}[/tex]
If the distance between the charges is doubled, r' = 2r and one of the charges is tripled, q₁' = 2q₁, q₂' = 3q₂
Put all the values,
[tex]F'=\dfrac{kq_1'q_2'}{r'^2}\\\\\dfrac{F}{F'}=\dfrac{\dfrac{kq_1q_2}{r^2}}{\dfrac{kq_1'q_2'}{r'^2}}\\\\\dfrac{F}{F'}=\dfrac{\dfrac{q_1\times q_2}{r^2}}{\dfrac{2q_1\times 3q_2}{(2r)^2}}\\\\\dfrac{F}{F'}=\dfrac{4}{6}=\dfrac{2}{3}\\\\F'=\dfrac{3\times 4.2\times 10^{-2}}{2}\\\\F'=0.063\ N[/tex]
So, the new force is 0.063 N.
Answer:
The force becomes 0.0315 N.
Explanation:
Force, F = 4.2 x 10^-2 N
When the distance is doubled, a charge is tripled, Let the force is F'.
The force between the two charges is
[tex]F = \frac{K qq'}{r^2}\\[/tex]
when, q' = 3 q' and r is 2 r so
[tex]F' = \frac{K 3qq'}{4r^2} = \frac{3 F}{4} = \frac {3\times 4.2\times 10^{-2}}{4}=0.0315 N[/tex]
Hai vận động viên chạy trên cùng 1 đoạn đường, vận động
viên A chạy với vận tốc 12 m/s vận động viên B chạy với vận tốc 36
km/h. Hỏi vận động viên nào chạy nhanh hơn?
Answer:
Pemain A
Explanation:
Mengingat data berikut;
Kecepatan pemain A = 12 m/s
Kecepatan pemain B = 36 km/h
Untuk menentukan siapa pelari tercepat di antara dua pemain;
Pertama-tama, kita harus mengubah kecepatan menjadi satuan standar pengukuran yang sama.
Jadi, mari kita gunakan pengukuran umum meter per detik.
Konversi:
36 km/h = (36 * 1000)/(60 * 60)
36 km/h = 36000/3600
36 km/h = 10 m/s
Kecepatan pemain B = 10 m/s
Oleh karena itu, dibandingkan dengan kecepatan pemain A; pemain A lebih cepat.
PLS HELP ME I DONT HAVE MUCH TIME LEFT
The Euler buckling load of a 160-cm-long column will be _____ times the Euler buckling load of an equivalent 120-cm-long column.
1.78
0.56
0.75
2.37
1.33
0.42
Calculate the minimum area moment of inertia for a rectangular cross-section with side lengths 3 cm and 8 cm.
201 cm4
18 cm4
128 cm4
4 cm4
24 cm4
Answer:
A certain source of 12V with an internal resistance 1colomb is connected to 5colomb external resistance what is the current
Calculate the mass in grams of a toy car if a force of 2 N causes it to accelerate by 10 m/s2
Answer:
m=0.2kg=200g
Explanation:
F=2N, a=10m/s²
F=ma⇒ m=F/a=2/10=0.2kg=200g
Answer:
[tex]\boxed {\boxed {\sf 200 \ grams}}[/tex]
Explanation:
According to Newton's Second Law of Motion, force is the product of mass and acceleration.
[tex]F=m*a[/tex]
The force is 2 Newtons and the acceleration is 10 meters per square second. First, we should convert the units of Newtons to make unit cancellation easier. 1 Newton is equal to 1 kilogram meter per second squared. The force of 2 N equals 2 kg*m/s²
Substitute the known values into the formula.
F= 2 kg*m/s²a= 10 m/s²[tex]2 \ kg*m/s^2 = m * 10 \ m/s^2[/tex]
We are solving for the mass, so we must isolate the variable m. It is being multiplied by 10 meters were second squared. The inverse of multiplication is division. Divide both sides by 10 m/s².
[tex]\frac { 2 \ kg *m/s^2}{10 \ m/s^2}=\frac{ m* 10 m/s^2}{10 \ m/s^2}[/tex]
[tex]\frac { 2 \ kg *m/s^2}{10 \ m/s^2}= m[/tex]
The units of meters per second squared cancel.
[tex]\frac { 2 \ kg}{10}= m[/tex]
[tex]0.2 \ kg =m[/tex]
Now, we must convert the mass to grams. There are 1000 grams in 1 kilogram. We can multiply the mass by 1000 or set up a ratio.
[tex]0.2 \ kg * \frac{1000 \ g}{1 \ kg}= 0.2 * 1000 \ g = 200 \ g[/tex]
The toy car's mass is 200 grams.
When 2 moles of helium gas expand at a constant pressure p= 1.0×10^5 pascals, the temperature increase from 2 °c to 112 °c. If the initial volume of the gas was 45 liters. Cp= 20.8j/mol.K, Cv= 12.6j/mol.K. Determine i. The work done W by the gas as it exands
Answer:
1,900 J
Explanation:
The number of moles of helium gas, n = 2 moles
The pressure of the helium gas, p = 1.0 × 10⁵ Pa
The initial temperature of the gas, T₁ = 2°C = 275.15 K
The final temperature of the gas, T₂ = 112°C = 385.15 K
The initial volume of the gas, V₁ = 45 liters
Cp = 20.8 J/(mol·K), Cv = 12.6 J/(mol·K)
The work done by the gas having constant pressure expansion is given as follows;
From the ideal gas law, we have;
[tex]V_2 = \dfrac{T_2 \times n \times R}{P}[/tex]
Where;
R = The universal gas constant = 8.314 J/(mol×K)
Therefore, we get;
[tex]V_2 = \dfrac{385.15 \, K \times 2 \, moles \times 8.314 \, \dfrac{J}{mol \cdot K} }{1.0 \times 10^5 \ Pa} \approx 64.0 \, L[/tex]
The work done, W = P ×ΔV = P × (V₂ - V₁)
∴ W = 1.0 × 10⁵ Pa × (64.0 L - 45.0 L) = 1,900 J
The work done by the gas as it expands, W = 1,900 J.
A block of density 2400 km/m3 has a volume of 0.20 m3 what is it's mass
Answer:
Data:
D = 2400 kg/m³
V = 0.20 m³
M = ?
∴ Density = [tex]\frac{Mass}{Volume}[/tex]
2400 kg/ = [tex]\frac{Mass}{0.2 m^{3} }[/tex]
Mass = 2400 kg/m³ × 0.20 m³
Mass = 480 kg (answer)
Answer:
Therefore, the mass of the block is 480 kg.
Why gases are easily compressed?
Answer:
photosynthesis is the process by which green leaves prepare their food in the presence of sunlight,air and water
You slide a 325-N trunk up a 20.0° inclined
plane with a constant velocity by exerting a
force of 211 N parallel to the inclined plane.
a. What is the component of the trunk's
weight parallel to the plane?
b. What is the sum of your applied force, fric-
tion, and the parallel component of the
trunk's weight? Why?
C. What is the size and direction of the friction
force?
d. What is the coefficient of friction?
Answer:
A) 111 N
B) F_net = 0 N
C) 100 N, in the opposite direction of the motion.
D) μ = 0.3274
Explanation:
A) The component of the trunks weight acts parallel to the plane but in the vertical direction and so;
W = Fsin θ
W = 325 sin 20
W = 325 × 0.3420
W ≈ 111 N
B) We are told the trunk is moving with a constant velocity and for this reason the sun of the forces will equal to zero.
Thus; F_net = 0 N
C) Since the kinetic friction force needs to balance the component of the weight, the magnitude is;
F_f = 211 - 111 = 100 N
The direction will be in the opposite direction since it's against the motion.
D) From friction formula, we know that;
F_f = μW cos θ
100 = μ × 325 × cos 20
μ = 100/(325 × cos 20)
μ = 0.3274
A sound wave traveling at 340 m/s is generated by a 480 Hz tuning fork.
How long is the sound wave?
Answer:
Wavelength = 0.7083 meters
Explanation:
Given the following data;
Speed of wave = 340 m/s
Frequency = 480 Hz
To find how long is the sound wave, we would determine its wavelength;
Mathematically, the wavelength of a waveform is given by the formula;
Wavelength = velocity/frequency
Wavelength = 340/480
Wavelength = 0.7083 meters
Compare the MKS, CGS & FPS system of units. which system of units are convenient to use? Justify your answer.
Answer: The system of unit which is most convenient for use is the MKS unit.
Explanation:
System of units is defined as the complete set of units which comprises of both the fundamental units and the derived units. The mass, length and time are considered to be the fundamental quantities and their units are called the fundamental units. The systems of unit which are in common use can be compared through their description below:
--> MKS system of unit: In this system of unit, the unit of length is in meter (m). The unit if mass is in kilogram (k). The unit of time is in seconds (s). Hence the name m.k.s system of unit.
--> CGS system of unit: In this system of unit, the unit of length is in centimeter (cm). The unit if mass is in grams (g). The unit of time is in seconds (s). Hence the name c.g.s. system of unit.
--> FPS system of unit: In this system of unit, the unit of length is in foot (Ft). The unit if mass is in pound (Lb). The unit of time is in seconds (s). Hence the name m.k.s system of unit.
The system of unit which is most CONVENIENT for use is the MKS unit. This is because of the introduction of the international system of units (S.I unit). This unit was endorsed by the International Standard Organisation (ISO) to form a logical and interconnected framework for all measurements in science and technology. The MKS system of unit was made the SI units enabling physical quantities to be represented by only one unit.
Which of the following is evidence that supports the big bang theory?
A. Light from other galaxies sometimes takes thousands of years to
reach Earth, which shows that the galaxies are moving away from
Earth.
B. Light from other galaxies shows that light elements formed before
heavier elements.
C. Light from other galaxies always travels at the same speed, which
shows that the galaxies are moving away from Earth.
D. Light from other galaxies appears shifted toward the red end of
the spectrum, which shows that the galaxies are moving away
from Earth
Answer:
D
Explanation:
Answer:
D
Explanation:
Light from other galaxies appears shifted toward the red end of
the spectrum, which shows that the galaxies are moving away
from Earth
79. A skater glides along a circular path of radius 5.00 m in clockwise direction. When he coasts around one-half of the circle, starting from the west point, find (a) the magnitude of his displacement vector and (b) how far he actually skated. (c) What is the magnitude of his displacement vector when he skates all the way around the circle and comes back to the west point
What current flows through a 2.54cm diameter rod of pure silicon that is 20cm long when 1000V is applied?
Answer: [tex]0.0039\ A[/tex]
Explanation:
Given
Diameter of the rod [tex]d=2.54\ cm[/tex]
length of rod is [tex]l=20\ cm[/tex]
Resistivity of silicon is [tex]\rho=6.4\times 10^2\ \Omega-m[/tex]
cross-section of the rod [tex]A[/tex]
[tex]\Rightarrow A=\dfrac{\pi d^2}{4}\\\\\Rightarrow A=\dfrac{3.142\times 2.54^2\times 10^{-4}}{4}\\\\\Rightarrow A=5.067\times 10^{-4}\ m^2[/tex]
Resistance of rod is R
[tex]\Rightarrow R=\dfrac{\rho l}{A}[/tex]
[tex]\Rightarrow R=\dfrac{640\times 0.20}{5.067\times 10^{-4}}\\\\\Rightarrow R=25.26\times 10^4\ \Omega[/tex]
Current is given by
[tex]\Rightarrow I=\dfrac{V}{R}\\\\\Rightarrow I=\dfrac{1000}{25.26\times 10^4}\\\\\Rightarrow I=0.0039\ A[/tex]
Help please please
is calculate total distance travelled
Here's the fact that you need to know:
"The AREA under a speed/time graph is the distance traveled during the time covered by the graph."
Now ... What's the area of that nice trapezoid on the graph ?
Hint: Area of a trapezoid is
(1/2) • (height) • (base-1 + base-2)
The length of a brick is 30cm,breadth 20 cm and volume 9000 cm³.Find the height of the brick.
ans should come 15cm
plz do write the formula too
Answer:
l=30cm
w=20cm
v=9000cm³
h=?
according to formula
h=V/A
h=9000/(30×20) ∴A=l×w
h=9000/600
h=15cm
mark as brainliest plz
Determine the force that the block of metal would exert when resting on a flat surface in Newtons
Answer:
normal force
tension force
and other example of force
Using your Periodic Table, which of the following elements below has the largest atomic radius? A.) Aluminum B.) Sodium C.) Sulfur, D.) Fluorine
Answer:
sodium
Explanation:
it is highly reactive metal.
Answer:
aluminium
Explanation:
In a period , as we go from left to right in a periodic table, atomic number increases .
Differentiating electrons enters into same shell hence the effective nuclear charge decreases .
Hence atomic radius decreases along period.
Conculsion:
Aluminium is the element which has greater atomic radius and sulphur has smaller atomic radius.
True or false: Ultimate tensile strength increases as the thickness of a solid material sample increases.
True
False
Answer:
False.
Explanation:
Tensile strength should remain constant, regardless of thickness. For larger cross sections, it can slightly increase because the atoms in the center become more constricted and therefore less responsive to the applied stress.
Answer:
Tensile strength should remain constant, regardless of thickness. For larger cross sections, it can slightly increase because the atoms in the center become more constricted and therefore less responsive to the applied stress.FALSE
A 3.00 kg box sliding west at 2.00 m/s makes an inelastic collision with a second box sliding 1.50 m/s east. Afterwards, they both come to a stop. What was the mass of the second box?
Let west be the negative direction, and east be positive. Then the total momentum of the system is conserved such that
(3.00 kg) (-2.00 m/s) + m (1.50 m/s) = 0
Solve for m :
m = (3.00 kg) (2.00 m/s) / (1.50 m/s) = 4.00 kg
how to find work done by load
A student initially 10.0 m East of his school walks 17.5 m West. The magnitude of the student's displacement, relative to the school is _________ m? The direction of the student's displacement, relative to the school is ______?
Answer:
1. 7.5 m
2. towards west side
explanation:
I hope it will help you
1.10) For a fixed mass of gas at constant temperature, if the volume of the gas (V) increases to twice its original amount, the pressure of the gas (P) will be
A)2P
В )1/2 Р
C)P
D)4P
Answer:
B
Explanation:
According to boyle's law for a gas the pressure and volume are inversely proportional.this simply means when one increases the other one reduces and when the other one reduces the other increases.so in this case the volume increased to twice it original amount meaning the pressure will reduce to half the volume.
I hope this helps
The pressure at the ice point for a constant-volume gas thermometer is 4.81 x 10^4 Pa. While that at the steam point is 6.48 x 10^4 Pa.
What pressure would the thermometer indicate at 50°c?
when you get the answer please tell me