The angles measure 90°, -2x - 6, and -1/x - 3. ⇒ x = -44. Therefore, the required measures of the angles are 90°, 82°, and 8° in the given triangle.
A right triangle is a type of triangle where one of the angles measures exactly 90 degrees. This angle is known as the right angle, and it is formed by the intersection of the two sides of the triangle that are perpendicular to each other. The other two angles of the right triangle are acute angles, meaning they measure less than 90 degrees.
The side opposite the right angle is called the hypotenuse, and it is always the longest side of the right triangle. The other two sides are called legs, and they can be of different lengths. This theorem is one of the most important and useful tools in geometry, and it allows us to solve many practical problems involving right triangles, such as finding the height of a building.
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compute the determinants in exercises 9-14 by cofactor expansions. at each step, choose a row or column that involves the least amount of computation. [\begin{array}{ccc}6&3&2&4&0\\9&0&-4&1&0\\8&-5&6&7&1\\3&0&0&0&0\\4&2&3&2&0\end{array}\right]
Answer:
Step-by-step explanation:
There are 170 deer on a reservation. The deer population is increasing at a rate of 30% per year
A function [tex]P(t) = 170.(1.30)^t[/tex] that gives the deer population P(t) on the reservation t years from now
We were told there were 170 stags on reservation. The number of deer is increasing at a rate of 30% per year.
We could see the deer population grow exponentially since each year there will be 30% more than last year.
Since we know that an exponential growth function is in form:
[tex]f(x) = a*(1+r)^x[/tex]
where a= initial value, r= growth rate in decimal form.
It is given that a= 170 and r= 30%.
Let us convert our given growth rate in decimal form.
[tex]30 percent = \frac{30}{100} = 0.30[/tex]
Upon substituting our given values in exponential function form we will get,
[tex]P(t) = 170.(1+0.30)^t[/tex]
⇒ [tex]P(t)= 170.(1.30)^t[/tex]
Therefore, the function [tex]P(t) = 170.(1.30)^t[/tex] will give the deer population P(t) on the reservation t years from now.
Complete Question:
There are 170 deer on a reservation. The deer population is increasing at a rate of 30% per year. Write a function that gives the deer population P(t) on the reservation t years from now.
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I need help pls help me find the area:
Answer:
Step-by-step explanation:
348.55
Find the probability of
drawing a spade, then
drawing a face card out of a
deck
[tex]\huge\underline{\red{A}\green{n}\blue{s}\purple{w}\pink{e}\orange{r} →}[/tex]
P of spade = 1/4
P of face cards = 3/13
{P = probability}
Step-by-step explanation:
•Total cards in a deck = 52
No. of spade cards in the deck = 13
therefore,
Probability of drawing a spade out of a deck of cards = 13/52 = 1/4
No. of face cards in a deck = 3×4 = 12 (joker,king,queen)
therefore,
Probability of drawing a face card out of a deck of cards = 12/52 = 3/13
Hope it helps you ~Consider the following exponential probability density function. f(x) = 1/3 4 e^-x/3 for x > 0 a. Write the formula for P(x < x_0). b. Find P(x < 2). c. Find P(x > 3). d. Find P(x < 5). e. Find P(2 <.x <5).
The probability that x is less than 2 is approximately 0.4866. The probability that x is greater than 3 is approximately 0.3528. The probability that x is less than 5 is approximately 0.6321. The probability that x is between 2 and 5 is approximately 0.1455.
The given probability density function is an exponential distribution with a rate parameter of λ = 1/3. The formula for P(x < x_0) is the cumulative distribution function (CDF) of the exponential distribution, which is given by:
F(x_0) = ∫[0,x_0] f(x) dx = ∫[0,x_0] 1/3 * 4 * e^(-x/3) dx
a. Write the formula for P(x < x_0):
Using integration, we can solve this formula as follows:
F(x_0) = [-4e^(-x/3)] / 3 |[0,x_0]
= [-4e^(-x_0/3) + 4]/3
b. Find P(x < 2):
To find P(x < 2), we simply substitute x_0 = 2 in the above formula:
F(2) = [-4e^(-2/3) + 4]/3
≈ 0.4866
Therefore, the probability that x is less than 2 is approximately 0.4866.
c. Find P(x > 3):
To find P(x > 3), we can use the complement rule and subtract P(x < 3) from 1:
P(x > 3) = 1 - P(x < 3) = 1 - F(3)
= 1 - [-4e^(-1) + 4]/3
≈ 0.3528
Therefore, the probability that x is greater than 3 is approximately 0.3528.
d. Find P(x < 5):
To find P(x < 5), we simply substitute x_0 = 5 in the above formula:
F(5) = [-4e^(-5/3) + 4]/3
≈ 0.6321
Therefore, the probability that x is less than 5 is approximately 0.6321.
e. Find P(2 < x < 5):
To find P(2 < x < 5), we can use the CDF formula to find P(x < 5) and P(x < 2), and then subtract the latter from the former:
P(2 < x < 5) = P(x < 5) - P(x < 2)
= F(5) - F(2)
= [-4e^(-5/3) + 4]/3 - [-4e^(-2/3) + 4]/3
≈ 0.1455
Therefore, the probability that x is between 2 and 5 is approximately 0.1455.
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A number exceeds 20% of itself by 40. find the number.
WITH STEPS
Answer:
50
Step-by-step explanation:
Let the number = x.
20% of the number is 20% of x = 0.2x.
Since the number exceeds 20% of itself by 40, then teh number minus 20% of itself is 40.
x - 0.2x = 40
0.8x = 40
x = 40/0.8
x = 50
solve( 3x^ 2)+2y +4=0
Answer:
Step-by-step explanation:
You can’t solve this equation as none of the numbers have the same coefficient to solve. If you wanted to solve for x and y, you will need two equations as there are two unknown variables in the equation and the only way to solve for x and y is to use simultaneous method which includes two equations.
ab +3a² - 7a+ab+a² simplify this algebraic expression
Simplifying the algebraic expression ab + 3a² - 7a + ab + a² = a(4a + 2b - 7)
What is an algebraic expression?An algebraic expression is a mathematical expression in which letters are used to represent the variables.
Since we have the algebraic expression ab + 3a² - 7a + ab + a², and we want to simplify it. We proceed as follows
ab + 3a² - 7a + ab + a²
First, we collect the like terms together
ab + 3a² - 7a + ab + a² = 3a² + a²- 7a + ab + ab
Adding the similar terms together, we have
= 3a² + a²- 7a + ab + ab
= 4a²- 7a + 2ab
= 4a²- 7a + 2ab
Factorizing out a, we have that
= a(4a - 7 + 2b)
= a(4a + 2b - 7)
So, ab + 3a² - 7a + ab + a² = a(4a + 2b - 7)
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what is the surface area of a cube if all sides are equal to 2
Proof Complete the proof of the cancellation property of vector addition by justifying each step. Prove that if u, v, and w are vectors in a vector space V such that u + w = v + w, then u = v.
The successfullly completed the proof of the cancellation property of vector addition.
Complete proof of the cancellation property of vector addition:Let u, v, and w be vectors in a vector space V such that u + w = v + w. We have to show that u = v. We know that the cancellation property of vector addition states that for all vectors u, v, and w in a vector space V, if u + w = v + w, then u = v.So, u + w = v + w can be written as, u + w - w = v + w - w, applying subtraction on both sides.u + 0 = v + 0 (as - w + w = 0)0 is an additive identity, so it can be dropped off.u = v, which is the desired result.The statement "u + w = v + w" was given, and we have shown that it implies that "u = v". Hence, we have successfully completed the proof of the cancellation property of vector addition.
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Red hair (autosomal recessive) is found in approximately 4% of the people in Norway. if we assume that the Norwegian population is in Hardy-Weinberg equilibrium with respect to hair color: A) what are the frequencies of the red hair (r) and non-red hair (R) alleles? B) what is the frequency of heterozygotes? C) what is the proportion of matings that CAN NOT have a child with red hair?
The answer is: A) r=0.04; R=0.96 B) 8% C) 92.16%.
The Hardy-Weinberg equilibrium is a method for determining the frequency of certain genetic traits in a population. The following are the frequencies of the red hair (r) and non-red hair (R) alleles in the Norwegian population, according to the question: A) The total frequency of alleles is 1. If red hair (r) is found in approximately 4% of the people in Norway, then the frequency of the R allele must be 0.96 or 96%. R = 0.96 r = 0.04 B) The frequency of hetero zygotes in a population can be determined by multiplying the frequency of the R allele by the frequency of the r allele and then multiplying that number by 2.
Heterogeneous genotype = 2pq Here, p represents the frequency of the R allele, and q represents the frequency of the r allele. p = R = 0.96 q = r = 0.04 Therefore, 2pq = 2(0.96 x 0.04) = 0.077, or approximately 8%. C) In order for a child to have red hair, both parents must carry the r allele. If both parents are homozygous for the R allele, there is no chance that their child will have red hair. This means that the proportion of matings that cannot result in a child with red hair is (0.96 x 0.96) = 0.9216 or 92.16%.
Therefore, the answer is: A) r=0.04; R=0.96 B) 8% C) 92.16%.
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7. Select all expressions which give the measure of angle A.
(A.) arccos (28/53)
(B.) arccos (45/53)
(C.) arcsin (28/53)
(D.) arcsin (45/53)
(E.) arctan (28/45)
(F.) arctan (45/28)
We cannot use arccos (28/53) and arcsin (28/53) because they correspond to angle B, not angle A. Similarly, arctan (28/45) and arctan (45/28) do not give the measure of angle A.
What accomplishes arccos function?The cosine function has an opposite known as the arccos function. It provides the angle whose cosine is the specified value. Try it. Drag any vertex of the triangle and watch how the angle C is determined using the arccos() function. Meaning: A 30 degree angle is one whose cosine is 0.866.
What is the sine of two?The inverse cosine function is the arccosine. The arccosine function's input values range from -1 to 1, matching the cosine function's output range of -1 to 1. So, for x=2, arccos x is undefined.
From the given figure, we can see that:
cos A = 28/53
sin A = 45/53
Therefore, the expressions that give the measure of angle A are:
(B.) arccos (45/53)
(D.) arcsin (45/53)
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Find the unknown lengths in these similar triangles. (Round off to two decimal places.)
The value of the unknown lengths in these similar triangles is FH is 6.67 units and EG is 27 units.
What is triangle?A triangle is a polygon with three sides and three angles. It is a two-dimensional shape that is commonly studied in mathematics, geometry, and other fields. The sum of the angles in a triangle is always 180 degrees, and the lengths of the sides can vary. Triangles can be classified based on the lengths of their sides and the measures of their angles. Common types of triangles include equilateral, isosceles, scalene, acute, right, and obtuse triangles. Triangles have many important properties and are used in various applications, including construction, engineering, and physics.
Here,
1. Let x be the length of FH. We have:
AB/EF = BD/FH
12/8 = 10/x
Cross-multiplying, we get:
12x = 80
x = 80/12
x ≈ 6.67
Therefore, FH ≈ 6.67.
2. Let y be the length of EG. We have:
AC/BD = FH/EG
15/9 = 5/y
Cross-multiplying, we get:
5y = 135
y = 135/5
y ≈ 27
Therefore, EG ≈ 27.
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I need to show my work please help
Answer:
x=15
Step-by-step explanation:
use the side splitter theorem
(x-6)/x = 3/5 (cross-multiply)
3x=5(x-6) distributive property
3x=5x-30
2x = 30
x = 15
1. Describe the historical data on Nando’s sales, including a discussion of thegeneral direction of sales and any seasonal tendencies that might beoccurring. 2. Discuss, giving your justifications, which time series forecasting techniquesare appropriate for producing forecasts with this data set. 3. Apply the appropriate forecasting techniques and compare the models basedon ex post forecasts. Choose the best model. 4. Use your chosen forecasting model to generate forecasts for each of themonths in year 2021. 5. Discuss how these forecasts might be integrated into the planning operationsand policy makings in NIH
In Rosettenville, a suburb of Johannesburg, South Africa, Robert Brozin and Fernando Duarte acquired the Chicken Land restaurant in 1987, launching Nando's.
The eatery was renamed Nando's in honor of Fernando. The restaurant incorporated influences from former Mozambican Portuguese colonists, many of whom had relocated to Johannesburg's southeast after their country gained independence in 1975. Expansion was an essential component of their vision from the beginning. Nando's had already grown from one restaurant in 1987 to four by 1990. It became increasingly difficult to implement a common strategy and decision-making became inefficient as new outlets were maintained as separate businesses.
In 1995, Nando's International Holdings (NIH) was established as a new international holding because managing this growingly complex global structure had become extremely challenging. The South African branch of Nando's Group Holdings (NGH) was successfully listed on the Johannesburg Stock Exchange on April 27, 1997. NGH was 54% owned by NIH, with the remaining 26% available to the general public and former joint venture partners. The main goals of the share offer and listing were to broaden the group's capital base and enable group restructuring.
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the heights of adult men can be approximated as normal with a mean of 70 and standard eviation of 3 what is the probality man is shorter than
Question: The heights of adult men can be approximated as normal, with a mean of 70 and a standard deviation of 3, the probability that a man is shorter than 65 inches is approximately 0.0475 or 4.75%.
Let X be the height of an adult man, which follows a normal distribution with mean μ = 70 and standard deviation σ = 3. Then, we need to find the probability that a man is shorter than some height, say x₀. We can write this probability as P(X < x₀).To find P(X < x₀), we need to standardize the random variable X by subtracting the mean and dividing by the standard deviation. This yields a new random variable Z with a standard normal distribution. Mathematically, we can write this transformation as:Z = (X - μ) / σwhere Z is the standard normal variable.
Now, we can find P(X < x₀) as:P(X < x₀) = P((X - μ) / σ < (x₀ - μ) / σ) = P(Z < (x₀ - μ) / σ)Here, we use the fact that the probability of a standard normal variable being less than some value z is denoted as P(Z < z), which is available in standard normal tables.
Therefore, to find the probability that a man is shorter than some height x₀, we need to standardize the height x₀ using the mean μ = 70 and the standard deviation σ = 3, and then look up the corresponding probability from the standard normal table.In other words, the probability that a man is shorter than x₀ can be expressed as:P(X < x₀) = P(Z < (x₀ - 70) / 3)We can now use standard normal tables or software to find the probability P(Z < z) for any value z.
For example, if x₀ = 65 (i.e., we want to find the probability that a man is shorter than 65 inches), then we have:z = (65 - 70) / 3 = -1.67Using a standard normal table, we can find that P(Z < -1.67) = 0.0475. Therefore, the probability that a man is shorter than 65 inches is approximately 0.0475 or 4.75%. Thus, P(X < 65) = 0.0475 or 4.75%. Therefore, the probability that a man is shorter than 65 inches is approximately 0.0475 or 4.75%.
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an amusement park charges a $ entrance fee. it then charges an additional $ per ride. which of the following equations could bum so use to properly calculate the dollar cost, , of entering the park and enjoying rides?
The equation you would use to properly calculate the dollar cost of entering the park and enjoying rides is Total Cost = Entrance Fee + (Number of Rides x Ride Fee).
In this case, Total Cost is the cost of entering the park and enjoying rides, Entrance Fee is the fee for entering the park, Number of Rides is the number of rides you will be taking, and Ride Fee is the fee charged for each ride.
Thus, plugging in the given values, the equation becomes Total Cost = Entrance Fee + (Number of Rides x Ride Fee).
Therefore, if the Entrance Fee is $ and each ride costs an additional $ , the Total Cost of entering the park and enjoying rides is $ .
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Please write how we can find.
Answer:
15
Step-by-step explanation:
Answer can only be found through estimation.
This means you have to do:
[tex]\frac{50*3}{\sqrt{100} }[/tex]
This will get you 15.
Marisa bought a car for $9,632. She paid $2,000 down. She will pay the remainder
in 24 monthly payments. How much will she pay each month?
Explain your answer.
Answer: $318/mo
Step-by-step explanation:
First, we get the remainder, which is the difference between $9, 632 and $2,000. That gives us $7, 632.
Then, since we know she will pay in 24 months, we assume she pays the same amount each month and divide $7, 632 by 24 = $318/mo
Fractions MUST SHOW WORKING!!
Total seats in plane: 186
108+64+14
5/7 of 14 is: 10
14÷7= 2
2x5= 10
5/16 of 64 is: 20
64÷16=4
5×4= 20
5/9 of 108 is: 60
108÷9= 12
12x5= 60
60+20+10=90
90/186 of seats are being used
simplified: 15/31
No
Given the function y = 4x + 3 do the following. Find its average rate of change: from x = 2 to x = 5
Answer: 4 is the average rate of change
Step-by-step explanation:
The equation to find the average rate of change is:
[tex]\frac{f(x_{2})-f(x_{1} ) }{x_{2}-x_{1} }[/tex]So f(2)= 11 and f(5)=23 then you plug these numbers in:
[tex]\frac{23-11}{5-2}[/tex] = [tex]\frac{12}{3}[/tex] = 4
A love expert carried out a study to quantify the effect of love songs on emotion. To do so, he used 30 volunteers. He random
Publishers
assigned the 30 volunteers to listen to either a love song or classical music. Then he asked them to draw a heart on a piece of paper. He measured the size of the heart drawn from bottom to top, in inches, for each person. The results are displayed in the stem and leaf plots.
The analysis of the data to obtain the confidence interval of the difference in the means indicates;
99% confidence interval for [tex]\bar x[/tex]₁ - [tex]\bar x[/tex]₂
The correct options are;
Name of Procedure
Two sample interval for [tex]\bar{x}[/tex]₁ - [tex]\bar{x}[/tex]₂Random
The volunteers are randomly selectedWe have a random sample of 15 subjects who listen to love songsWe have a random sample of 15 subjects who listen to classical music10%
The 10% condition is metNormal/Large Sample
The stemplot of the classical music sample data shows no strong skewness or outliersThe stemplot of the love song music sample data shows no strong skewness or outliers99% CI = (-0.302, 2.301)
Conclude;
We are 99% confident that the interval give in the previous step captures -0.301 to 2.301 = the true difference in mean heart height for all subject like these who listen to love songs versus classical music.
What is a confidence interval?A confidence interval is a range of value that is likely to contain the true value of a population parameter with a certain degree of confidence.
The two-sample t-test can be used to construct the 99% confidence interval as follows;
([tex]\bar x[/tex]₂ - [tex]\bar x[/tex]₁) ± t(α/2, df) × √(s₁²/n₁ + s₂²/n₂)
Where;
[tex]\bar x[/tex]₂ and [tex]\bar x[/tex]₁ = The sample means of the love song and classical music groups
s₁, and s₂ = The sample standard deviations
n₁ and n₂ = The sample sizes
df = The degrees of freedom
t(α/2, df) = The value from the t-distribution table with a significance level of 0.01 and df = n₁ + n₂ - 2
The data indicates;
n₁ = n₂ = 15
[tex]\bar x[/tex]₁ = 5.07, s₁ = 1.63
[tex]\bar x[/tex]₂ = 4.07, s₂ = 1.13
Therefore, we get;
([tex]\bar x[/tex]₂ - [tex]\bar x[/tex]₁) ± t(α/2, df) × √(s₁²/n₁ + s₂²/n₂)
= (5.07 - 4.07) ± t(0.005, 28) × √(1.62²/15 + 1.13²/15)
= 1 ± 2.763 × 0.469
= 1 ± 1.301
The 99% confidence interval for the difference in the true mean heart for subjects who listen to a love song versus classical music is; (-0.301, 2.301).
The correct statement is; 99% confidence interval for [tex]\bar x[/tex]₁ - [tex]\bar x[/tex]₂
The correct statements, placed in the box are;
Name of Procedure;
Two sample interval for [tex]\bar x[/tex]₁ - [tex]\bar x[/tex]₂
Random
The volunteers are randomly selected
The random condition is met
We have a random sample of 15 subjects who listen to a love song
We have a random sample of 15 subjects who listen to classical music
10%
The 10% condition is met
15 < 10% of all subjects like these who listen to love songs
15 < 10% of all subjects like these who listen to classical music
Normal/Large Sample
The Normal/Large condition is met
The stemplot of the classical music sample data shows no strong skewness or outliers
The stemplot of the love song music sample data shows no strong skewness or outliers
Therefore;
99% CI = (-0.301, 2.301)
Conclude;
We are 99% confident that the interval given in the previous step captures -0.301 to 2.301 = the true difference in mean heart height for all subject like these who listen to love songs versus classical music.
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I NEED HELP PLEASE !!
can i also get an easy explanation so i can know how to do the other problems pls
Answer:
Proofs attached to answer
Step-by-step explanation:
Proofs attached to answer
In order to test a claim that more than 40% of all calls to the emergency 911 phone number are actually not for emergency situations, 40 recordings of 911 calls are selected at random from those received in the past year, and 22 calls are classified as non-emergency. What are the p-value and conclusions for this test?A. P-value = 0.0264. There is strong evidence to show that no more than 40% of 911 calls are actually not emergency, at significance level a-0.05.B. P-value = 0.0264. There is strong evidence to show that more than 40% of 911 calls are actually not emergency, at significance level a 0.05.C. P-value = 0.0528. There is no strong evidence to show that more than 40% of 911 calls are actually not emergency, at significance level a 0.05.D. P-value = 0.0528. There is strong evidence to show that more than 40% of 911 calls are actually not emergency, at significance level a=0.05.
Answer:
0.005
Step-by-step explanation:
Which expressions are equivalent to (x−2)2
?
Select the correct choice
The expressions that are equivalent to (x-2)² is x² - 4x + 4. (option B)
Now, let's look at the expression (x-2)². This is a binomial expression that can be simplified by applying the rules of exponents. Specifically, we can expand this expression as follows:
(x-2)² = (x-2) * (x-2)
= x * x - 2 * x - 2 * x + 2 * 2
= x² - 4x + 4
So, the expression (x-2)² is equivalent to x² - 4x + 4.
However, the problem asks us to identify other expressions that are equivalent to (x-2)². To do this, we can use the process of factoring. We know that (x-2)² can be factored as (x-2) * (x-2). Using this factorization, we can rewrite (x-2)² as:
(x-2)² = (x-2) * (x-2)
= (x-2)²
So, (x-2)² is equivalent to itself.
Hence the correct option is (B).
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Complete Question:
Which expressions are equivalent to (x−2)²?
Select the correct choice.
A. (x + 2) (x - 2)
B. x² - 4x + 4
C. x² - 2x + 5
D. x² + x - 2x
Hi pls help me! Correct my answers if they’re wrong and I need help with 5-9! Thank you :D
Answer:
Proofs attached to answer
Step-by-step explanation:
Proofs attached to answer
in a school of hundred students, 40 are in the hockey team and 70 are in the football team.
Each student is in at least one team. Find the number of students who are in both teams.
Answer: There are 10 students who are in both the hockey and football teams.
Step-by-step explanation: We can use the principle of inclusion-exclusion to find the number of students who are in both the hockey and football teams.
The total number of students in both teams is the sum of the number of students in the hockey team and the number of students in the football team, minus the number of students who are in both teams (to avoid double-counting):
Total = Hockey + Football - Both
Substituting the given values, we get:
100 = 40 + 70 - Both
Simplifying, we get:
Both = 40 + 70 - 100
Both = 10
Therefore, there are 10 students who are in both the hockey and football teams.
What is the y-intercept of y = 2/3 x + 2? Responses A (3, 2)(3, 2) B (2, 3)(2, 3) C (-3, 0)(-3, 0) D (0, 2)
Answer:
Y intercept is (0,2) Answer D.
Step-by-step explanation:
I included a graph for equation y=2/3 x + 2.
The temperature recorded at Bloemfontein increased from -2 degrees C to 13 degrees C.what is the difference in temperature
Answer: 15
Step-by-step explanation:
13--2 = 13 + 2 = 15
● Thornton
1 centimeter =
50 kilometers
Peter's mother is a pilot. She often makes deliveries
near their community. Peter and his mother flew from
Charlton to Thornton to make a mail delivery. Then they
continued on to Avon and Ashton and returned to Charltc
How many kilometers did Peter and his mother
travel in all?
The answer is 250 kilometers. Peter and his mother traveled a total distance of 250 kilometers on their mail delivery.
What is distance?Distance is a numerical measurement of how far apart two objects or points are. It is a scalar quantity, meaning that it is only expressed as a magnitude, or numerical value, without any direction.
1 centimeter is equal to 0.01 kilometers, so 50 kilometers would be equal to 5,000 centimeters. The total distance between the four cities is 5,000 centimeters, which is equal to 50 kilometers.
Charltc to Thornton is 1,000 centimeters, Thornton to Avon is 1,500 centimeters, Avon to Ashton is 1,000 centimeters, and Ashton to Charltc is 1,500 centimeters. This gives us a total of 5,000 centimeters, or 50 kilometers.
This can be calculated by multiplying the total distance between the four cities (50 kilometers) by the number of times they traveled the route (5 times, since they flew from Charltc to Thornton, then to Avon, then to Ashton, and then back to Charltc). This gives us 250 kilometers, which is the answer to the question.
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Peter and his mother traveled a total distance of 250 kilometers on their mail delivery. The answer is 250 kilometers.
What is distance?Distance is a numerical measurement of how far apart two objects or points are. It is a scalar quantity, meaning that it is only expressed as a magnitude, or numerical value, without any direction.
1 centimeter = 0.01 kilometers,
so 50 kilometers = 5,000 centimeters.
Charlton to Thornton= 1,000 centimeters,
Thornton to Avon= 1,500 centimeters,
Avon to Ashton= 1,000 centimeters,
and Ashton to Charlton= 1,500 centimeters.
Total distance= 1,000+1,500+1,000+1,500
= 5,000 centimeters, or 50 kilometers.
The total distance between the four cities is 5,000 centimeters, which is equal to 50 kilometers.
This can be calculated by multiplying the total distance between the four cities (50 kilometers) by the number of times they traveled the route (5 times.
=50*5
=250
Since they flew from Charlton to Thornton, then to Avon, then to Ashton, and then back to Charlton.
250 kilometers is the answer to the question.
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Question:
Peter's mother is a pilot. She often makes deliveries near their community. Peter and his mother flew from Charlton to Thornton to make a mail delivery. Then they continued on to Avon and Ashton and returned to Charlton. How many kilometers did Peter and his mother travel in all?
