A rectangle is to be inscribed in an isosceles right triangle in such a way that one vertex of the rectangle is the intersection point of the legs of the triangle and the opposite vertex lies on the hypotenuse. Find the largest area (in cm 2 ) of the rectangle and its dimensions (in cm) given that the two equal legs of the triangle have length 4.
Answers
Answer:
x = 2 cm
y = 2 cm
A(max) = 4 cm²
Step-by-step explanation: See Annex
The right isosceles triangle has two 45° angles and the right angle.
tan 45° = 1 = x / 4 - y or x = 4 - y y = 4 - x
A(r) = x* y
Area of the rectangle as a function of x
A(x) = x * ( 4 - x ) A(x) = 4*x - x²
Tacking derivatives on both sides of the equation:
A´(x) = 4 - 2*x A´(x) = 0 4 - 2*x = 0
2*x = 4
x = 2 cm
And y = 4 - 2 = 2 cm
The rectangle of maximum area result to be a square of side 2 cm
A(max) = 2*2 = 4 cm²
To find out if A(x) has a maximum in the point x = 2
We get the second derivative
A´´(x) = -2 A´´(x) < 0 then A(x) has a maximum at x = 2
The maximum area of the rectangle inscribe in the right isosceles triangle
is [tex]\rm \bold{4\;cm^2}[/tex]
Given that a rectangle is to be inscribed in an isosceles triangle
As per the attached figure we can write the following
Let ΔABC represents the isosceles triangle from the given data in the question we can write the following observations
Length of AB = 4
Length of BC = 4
∠ACB = 45°
∠BAC = 45°
Length of AC = [tex]\rm 4\sqrt2[/tex]
We have to consider a rectangle within the isosceles triangle such that
area of rectangle is maximum
The area of rectangle is given by equation (1)
[tex]\rm Area \; of \; rectangle = Length \times Breadth ........(1) \\[/tex]
Let the area of rectangle inscribed by the isosceles triangle is " A"
Let the lenght of the rectangle be "x "
Let the width of the rectangle be " y "
So according to equation (1) the area of rectangle inscribed into the triangle is given by
[tex]\rm A = x \times y.......(2)[/tex]
In ΔAED we can write
[tex]\int\limits^a_b {x} \, dx \rm tan 45= \dfrac{Perpendicular}{Base } = \dfrac{4-y}{x} \\1 = \dfrac{4-y}{x} \\ x = 4-y .......(3) \\[/tex]
From equation (2) and (3) we get
[tex]\rm A = (4-y)(y) \\A = 4y -y^2......(4)[/tex]
On differentiating the given function with respect to y we get
[tex]\rm A' = 4- 2y \\[/tex]
On putting A' =0 we get
[tex]\rm 4-2y =0 \\2y = 4\\y = 2[/tex]
A'' is negative hence it is the maximum value of y
So we can conclude that the maximum value of y is 2
So from equation (4) the maximum area is [tex]\rm 2\times 2 = 4\; cm^2[/tex]
The maximum area of the rectangle inscribe in the right isosceles triangle
is [tex]\rm \bold{4\;cm^2}[/tex]
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Answer:
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Answers
Answer:
The Sample Size Need To be at least 114
Step-by-step explanation:
According to the Question,
Given, A university dean of students wishes to estimate the average number of hours students spend doing homework per week. The standard deviation from a previous study is 6.2 hours.The Maximum Error(E) is given as 1.5 hours and the standard deviation(σ) is 6.2 hours.
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Answer:
[tex]5^{15} * 5^{5}[/tex]
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Answer:
[tex]- 2\frac{1}{6}[/tex]
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[tex](2\frac{1}{6} -1\frac{2}{3}) - 2 \frac{2}{3}[/tex]
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Answer:
x = 15
LN and MO both equal 43
Step-by-step explanation:
LN and MO are diagonals in rectangle
Diagonals of a rectangle are congruent Hence, 4x - 17 = 2x + 13
Now we solve for x
4x - 17 = 2x + 13
Add 17 to both sides
4x = 2x + 30
Subtract 2x from both sides
2x = 30
Divide both sides by 2
x = 15
Now we want to find the values of LN and MO
To do so we substitute 15 for x in it's given expression ( note: because LN = MO we only need to do this process once )
LN = 4x - 17
Substitute 15 for x
4(15) - 17
Multiply
60 - 17
Subtract
LN and MO = 43
Jackson made 36 calls in 2.25 hours. How many calls per hour did he make?
Answers
Answer:
16 calls
Step-by-step explanation:
make an equation based off this ratio -- 36 calls: 2.25 hours and x calls: 1 hour
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Answer:
M=4 N=6
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The club with an occupancy of 100 will sell out at $25 per ticket. If the owner decides to increase the price by $5, then 2 less tickets will be sold. Determine the revenue function if x is the number of $5 increases.
Answers
Answer:
100 + (5X) = -2X
Step-by-step explanation:
Since the club with an occupancy of 100 will sell out at $ 25 per ticket, and if the owner decides to increase the price by $ 5, then 2 less tickets will be sold, to determine the revenue function if X is the number of $ 5 increases the following calculation must be performed:
100 + (5X) = -2X
So, for example, if the price were increased by $ 15, the equation would apply as follows:
15/5 = 3
100 + (5x3) = -2 x 3
100 + 15 = -6
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plz it's do to day HELP PLZ
Answers
Answer:
9 units^3
Step-by-step explanation:
V = l*w*h
= 1 1/2 * 4 * 1 1/2
Change to improper fractions
= 3/2 * 4 * 3/2
= 36/4
= 9 units^3
