Answer:
[tex]E_2=999984KJ/mole[/tex]
Explanation:
From the question we are told that:
Factor [tex]dK=500[/tex]
Temperature [tex]T=37 C=310k[/tex]
Activation energy [tex]E=10^6kJ/mol[/tex]
Generally the Arhenius equation is mathematically given by
[tex]ln \frac{K_2}{K_1}=\frac{ E_1-E_2}{RT}[/tex]
Where
[tex]\frac{K_2}{K_1}=500[/tex]
[tex]ln 500=\frac{ 10^6-10^3-E_2}{8.314*310}[/tex]
[tex]E_2=999984KJ/mole[/tex]
The activation energy of the new reaction is 105.99 kJ/mol.
Using the Arrhenius equation;
ln(k2/k1) = -Ea2/RT2 + Ea1/RT1
Now, from the information in the question;
k2/k1 = 500
Ea = ?
R = 8.314 JKmol-1
T2 = 37oC + 273 = 310 K
T1 = 37oC + 273 = 310 K
Substituting values;
ln (500) =- Ea2 + Ea1
6.2 = -Ea2 + 106 × 10^3 J
Ea = 106 × 10^3 J - 6.2
Ea = 105.99 × 10^3 J or 105.99 kJ/mol
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What’s the IUPAC name
O
||
CH3CH2CH2CH2COCH3
Answer:
Methyl pentanoate.
Explanation:
Hello there!
In this case, according to the given information, we can see the correct structure will be:
O
||
CH3CH2CH2CH2COCH3
Which matches with the structure of an ester due to the -COO- functional group. In such a case, the first part of the name is in function of the right side of the ester, in this case, methyl, followed by the left side, pentanoate, as it has five carbon atoms and is an ester (similar to an inorganic salt, but organic) and therefore, the name will be methyl pentanoate.
Regards!
Please help
In which atom do the valence electrons experience the larger electron affinity, Rb or
Sr? Explain why
Answer:
Explanation:
The electron affinity (EA) of an element is the energy change that occurs ... Atoms with the largest radii, which have the lowest ionization energies (affinity for their own valence electrons), also have the ... Based on their positions in the periodic table, which of Rb, Sr, or Xe would you
The word "cumulative" means that something builds on itself. Which example best shows how scientific knowledge is cumulative?
The following list of properties is most descriptive of a(n) ______________. Low melting point, non-conductor of electric current. Group of answer choices
Answer:
This question is incomplete
Explanation:
This question is incomplete but the completed question is below;
"The following list of properties is most descriptive of a(n) ______
1. High melting point, conductor of electricity when dissolved in water
2. Low melting point, non-conductor of electric current
3. Malleable, ductile, insoluble in water.
The choices for all 3 are: a) metallic solid b) molecular solid c) ionic solid d) all of these e) none of these f) more than one of these"
1. Ionic solid: Ionic solids are solids that have ionic/electrovalent bonds holding it's constituent molecules together. These bonds are strong bonds that involve the transfer of electrons from one constituent atom (the metal) to another constituent atom (the nonmetal). This strong bond causes the solid to have a high melting and boiling point. Also, when dissolved in water, the constituent atoms (involved in the electron transfer) dissociate to form ions (become charged) and thus easily carry electric charges (i.e conduct electricity).
Examples are Sodium Chloride and Potassium Iodide
2. Molecular solids: These are solids whose constituent molecules are held together by a weak bond/force known as Van der Waal forces. This forces are easily broken down when subjected to heat and thus the molecular solids have a low melting point. Also, these solids do not have carriers of heat or electric charges in them and are thus non-conductors of electric current.
Examples are Ice (frozen water) and sucrose
3. Metallic solids: These of solids made from constituent metal atoms only. The nuclei of these constituent metal atoms have the ability to move past one another without disrupting there metallic bonding; it is for this reason they are malleable and ductile. There constituent atoms however do not dissociate in water and are thus insoluble in water.
Examples are aluminium and copper crystal.
The tabulated data show the rate constant of a reaction measured at several different temperatures. Use an Arrhenius plot to determine the activation barrier and frequency factor for the reaction.
Temperature (K) Rate Constant (1/s)
300 0.0134
310 0.0407
320 0.114
330 0.303
340 0.757
Required:
Use an Arrhenius plot to determine the activation barrier for the reaction.
Answer:
e−(Ea/RT): the fraction of the molecules present in a gas which have energies equal to or in excess of activation energy at a particular temperature
Match each type of muscle tissues to the action it performs in the body
Answer:
where are the muscle tissues
the pressure on a 205 mL volume of gas is decreased from 985 mm hg to 615 mm hg while constant temperature is maintained, What is the new volume of the gas?
Answer:
[tex]\boxed {\boxed {\sf 328 \ mL}}[/tex]
Explanation:
The pressure on the gas changes, while the temperature remains constant, and we want to find the new volume. So, we will use Boyle's Law, which states there is an inverse relationship between the pressure on a gas and the volume of the gas. The formula is:
[tex]{P_1V_1}= P_2V_2[/tex]
The pressure of the gas is originally 985 mm Hg and the volume is 205 milliliters.
[tex]985 \ mm \ Hg * 205 \ mL = P_2V_2[/tex]
The pressure is decreased to 615 mm Hg, but the new volume is unknown.
[tex]985 \ mm \ Hg * 205 \ mL = 615 \ mm \ Hg * V_2[/tex]
We are solving for the new volume, so we must isolate the variable V₂. It is being multiplied by 615 millimeters of mercury.. The inverse of multiplication is division, so we divide both sides of the equation by 615 mm Hg.
[tex]\frac {985 \ mm \ Hg * 205 \ mL}{615 \ mm \ Hg} = \frac{615 \ mm \ Hg * V_2}{615 \ mm \ Hg}[/tex]
[tex]\frac {985 \ mm \ Hg * 205 \ mL}{615 \ mm \ Hg} = V_2[/tex]
The units of millimeters of mercury (mm Hg) cancel.
[tex]\frac {985 \ * 205 \ mL}{615 } = V_2[/tex]
[tex]\frac{201925 }{ 615} \ mL = V_2[/tex]
[tex]328.3333333 \ mL = V_2[/tex]
The original measurements have 3 significant figures, so our answer must have the same. For the number we calculated, that is the ones place.
The 3 to the right in the tenths place tells us to leave the 8 in the ones place.
[tex]328 \ mL \approx V_2[/tex]
The new volume of the gas is approximately 328 milliliters.
What is the direct function of the energy released from the nuclear chain reaction in a nuclear power plant? turning the blades of the turbine heating water to produce steam powering the condenser carrying electricity from the plant to consumers
Answer:
the energy released is to make steam to create electricity. yes you are right i just didnt feel like being super technical
In a nuclear reaction, the direct function of the energy released from the nuclear chain reaction in a nuclear power plant is turning the blades of the turbine heating water to produce steam .
What are nuclear reactions?There are two types of nuclear reactions which are nuclear fusion and nuclear fission .They involve the combination and disintegration of the element's nucleus respectively.
In nuclear fission, the nucleus of the atom is bombarded with electrons of low energy which splits the nucleus in to two parts .Large amount of energy is released in the process.It is used in nuclear power reactors as it produces large amount of energy.
In nuclear fusion,on the other hand, is a reaction which occurs when two or more atoms combine to form a heavy nucleus.Large amount of energy is released in the process which is greater than that of the energy which is released in nuclear fission process.
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When barium hydroxide reacts with sulfuric acid, barium sulfate and water are produced. The balanced equation for this reaction is: Ba(OH)2 (aq) H2SO4 (aq) BaSO4 (s) 2H2O (l)
Answer: The balanced equation for given reaction is [tex]Ba(OH)_{2}(aq) + H_{2}SO_{4}(aq) \rightarrow BaSO_{4}(s) + 2H_{2}O(l)[/tex].
Explanation:
A chemical equation which contains same number of atoms on both reactant and product side is called a balanced chemical equation.
For example, [tex]Ba(OH)_{2}(aq) + H_{2}SO_{4}(aq) \rightarrow BaSO_{4}(s) + 2H_{2}O(l)[/tex]
Number of atoms on reactant side are as follows.
Ba = 1O = 6H = 4S = 1Number of atoms on product side are as follows.
Ba = 1O = 6H = 4S = 1Since atoms on both reactant and product side are equal. Therefore, this equation is balanced.
Thus, we can conclude that balanced equation for given reaction is [tex]Ba(OH)_{2}(aq) + H_{2}SO_{4}(aq) \rightarrow BaSO_{4}(s) + 2H_{2}O(l)[/tex].
Aluminum hydroxide is insoluble in pure water but dissolves in a solution of sodium hydroxide because: Select the correct answer below: hydroxide ions neutralize the Al3 ion, a Lewis acid aluminum participates in an acid-base reaction in the presence of sodium hydroxide the excess of hydroxide ions pushes the equilibrium toward further dissolution of Al(OH)3 aluminum forms a complex ion with excess hydroxide
Answer:
aluminum forms a complex ion with excess hydroxide
Explanation:
Complex formation accounts for the dissolution of certain compounds. For instance,reaction of aluminum and sodium hydroxide yields insoluble aluminum hydroxide as follows;
Al(s) + 3NaOH(aq) -----> Al(OH)3(s) +Na(s)
However, in excess NaOH, the solid aluminum hydroxide dissolves as due to the formation of a complex Al(OH)4^- in the solution.
There are three naturally occurring isotopes of neon: neon-20, mass 19.9924 amu, abundance 90.84% neon-21, mass 20.9940 amu, abundance 0.260% neon-22 mass 21.9914 amu, abundance 8.90% What is the atomic mass of neon to 2 sig fig
Answer:
Molar mass Ne = 20 amu
Explanation:
The atomic mass of an atom is defined as the sum of the mases of the isotopes times their abundance. For Neon, the atomic mass is obtained as follows:
Molar mass Ne = 19.9924amu*0.9084 + 20.9940amu*0.00260 + 21.9914amu*0.0890
Molar mass Ne = 20 amu
Plastic is a polymer
-True
-False
TRUE
Explanation:
*not sure about this answer
What is the molecular geometry of CIO3F as predicted by the VSEPR model?
Multiple Choice
trigonal pyramidal
square planar
square pyramidal
tetrahedral
octahedral
Explanation:
since there are no lone pairs on the central atom, the shape will be tetrahedral
______ drives the aminoacylation reaction hydrolysis of gtp hydrolysis of phosphate phosphorylation hydrolysis of pyrophosphate
Answer:
Hydrolysis of pyrophosphate
Explanation:
The hydrolysis of pyrophosphate into two molecules of inorganic phosphate (Pi) reaction which is highly energetic that drives the other two reactions. These two reactions highly exergonic reactions that take place inside the aminoacyl-tRNA synthetase which is specific for that amino acid. Exergonic reactions are the reactions that produce free energy that can be used in the next phases of reactions so we can say that hydrolysis of pyrophosphate is responsible for the happening of aminoacylation reaction.
The elemental mass percent composition of succinic acid is 40.68% C, 5.12% H, and 54.19% O. Determine the empirical formula of succinic acid. Express your answer as a chemical formula.
Answer:
C₂H₃O₂
Explanation:
To determine the empirical formula of succinic acid, we need to follow a series of steps.
Step 1: Divide each mass percent by the atomic mass of the element
C: 40.68/12.01 = 3.39
H: 5.12/1.01 = 5.07
O: 54.19/16.00 = 3.39
Step 2: Divide all the numbers by the smallest one, i.e. 3.39
C: 3.39/3.39 = 1
H: 5.07/3.39 ≈ 1.5
O: 3.39/3.39 = 1
Step 3: Multiply all the numbers by a factor that makes them all integers, i.e. 2
C: 1 × 2 = 2
H: 1.5 × 2 = 3
O: 1 × 2 = 2
The empirical formula of succinic acid is C₂H₃O₂.
A gas occupies a volume of 202 ml at a pressure of 505 torr. To what pressure must the gas be subject in order to change the volume to 65.0 ml
Answer:
1569 torr
Explanation:
Assuming ideal behaviour and constant temperature, we can solve this problem by using Boyle's law, which states:
V₁P₁ = V₂P₂Where in this case:
V₁ = 202 mLP₁ = 505 torrV₂ = 65.0 mLP₂ = ?We input the data given by the problem:
202 mL * 505 torr = 65.0 mL * P₂And solve for P₂:
P₂ = 1569 torrWhat type of intermolecular force exist between H2O and Br2
Answer:
welcome to mobile legends
Explanation:
ml ka muna maya kana mag module
Which acid or base (along with its corresponding salt) should be used to generate a buffer solution with pH around 3.5
Answer:
Formic acid
Sodium formiate
Explanation:
To determine acid or base that can generate a buffer solution with pH around 3.5, we have to think in the acid whose pKa = pH.
Although we have to also think in buffer capacity, a measure which can cause a change of 1 pH unit in 1 L of solution.
Buffer capacity does not only depend on the concentration of its components but also of the relationship between that concentrations.
When pH = pKa, buffer capacity is maximum which means that the concentration of conjugated species is the same and the ability to oppose pH changes is maximum.
One example with pH = pKa or nearly if:
COOH⁻ + Na⁺ → NaCOOH
HCOOH + H₂O → COOH⁻ + H₃O⁺ Ka: 1.8×10⁻⁴
pKa = 3.74
A 100.0-g sample of sodium hydroxide contains sodium, oxygen, and hydrogen. The
sample contains 2.53 g of hydrogen and 40.0 g of oxygen. What mass of sodium is in
the sample? (Record your answer as a 3 digit number)
Answer:
57.47 grams of sodium is in the sample.
Explanation:
Given that a 100.0-g sample of sodium hydroxide contains sodium, oxygen, and hydrogen, and the sample contains 2.53 g of hydrogen and 40.0 g of oxygen, to determine what mass of sodium is in the sample the following calculation must be performed:
100 - (40 + 2.53) = X
100 - 42.53 = X
57.47 = X
Therefore, 57.47 grams of sodium is in the sample.
Fluorine gas and water vapor react to form hydrogen fluoride gas and oxygen. What volume of oxygen would be produced by this reaction if "3.0" of water were consumed g
Answer:
[tex]V_{O2}= 1.5m^3[/tex]
Explanation:
From the question we are told that:
Volume of H_2O consumed [tex]V_{H2O}=3.0cm^3[/tex]
Balanced equation of Reaction is
[tex]2 F_2 + 2 H_2O -> 4 HF + O_2[/tex]
Therefore
O_2 produced in Volume is
[tex]V_{O2}= \frac{1}{2}*V_{H2O}[/tex]
[tex]V_{O2}= \frac{1}{2}*3.0m^3[/tex]
[tex]V_{O2}= 1.5m^3[/tex]
Convert 52.09 km/h into m/s.
Answer:
52.09×5/18
14.44 m/s
I hope it's helps you
Convert 52.09 km/h into m/s.
answer....
52.09 km/h=14.469 metres per second
(divide the speed value by 3.6)..........
which molecule has 9 carbon atoms
Answer:
c9h8o2
Explanation:
The molecule which has 9 carbon atom is [tex]C_{9} H_{8} O[/tex](cinnamaldehyde).
What is molecule?More than one atoms make up a molecule. If they have more than one atom, atoms could be the same for example, an oxygen molecule contains two oxygen atoms) as well as different (for example, a hydrogen molecule contains two hydrogen atoms.
What is cinnamaldehyde?Cinnamaldehyde is a kind of organic chemical with the formula C6H5CH=CHCHO and the formula C6H5CH=CHCHO. It's mostly the trans isomer that's found in nature.
It is known that the number of carbon atom is 9 hence molecule will be cinnamaldehyde
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Write the precipitation reaction for silver sulfate in aqueous solution: (Use the lowest possible coefficients. Be sure to specify states such as (aq) or (s). If a box is not needed, leave it blank.)
Answer:
The balanced chemical reaction is :
[tex]2Ag^+(aq)+SO_4^{2-}(aq)\rightarrow Ag_2SO_4(s)[/tex]
Explanation:
The precipitation reaction is defined as a chemical reaction in which a solid substance is formed when two aqueous solutions of different compounds are allowed to react with each other.
When an aqueous solution of silver ion and sulfate ions are mixed together solid white precipitate of silver sulfate is formed.
The balanced chemical reaction is written as:
[tex]2Ag^+(aq)+SO_4^{2-}(aq)\rightarrow Ag_2SO_4(s)[/tex]
Which group of carbohydrates is unique in that its members are strong anions, containing a significant concentration of carboxylate and sulfate
Answer:
The options are
A) Glycosaminoglycans
B) Gangliosides
C) Peptidoglycans
D) Proteoglycans
E) Selectins
The answer is A) Glycosaminoglycans
Glycosaminoglycans are polysaccharides which comprises of repetitive disaccharides. They are negatively charged as a result of the strong anions present. They are present in some cells of the body and they help in transmission of signals between cells etc.
They also comprise of carboxylate and sulfate groups in its structure.
In lab (write this down in your lab protocol), you will be given a stock solution that has a glucose concentration of 60 mg/dL. You need to make 1 mL of each of the following glucose concentrations: 0.94 mg/dL, 1.88 mg/dL, 3.75 mg/dL, 7.5 mg/dL, 15 mg/dL, and 30 mg/dL. Distilled water will be the solvent in these dilutions. Enter your numbers only. 1. What is the dilution factor for this serial dilution? 2. What is the V2 for this serial dilution in mL? 3. What is the V1 for this serial dilution in mL?
Answer:
1. The dilution factor for the serial dilution = 2
2. V2 = 1 mL
3. V1 = 0.5 mL
Explanation:
1. Dilution factor is the ratio of the initial concentration to the final concentration.
Dilution factor = initial concentration / final concentration
First dilution: initial concentration = 60 mg/dL
final concentration = 30 mg/dL
Dilution factor = 60 mg/dL / 30 mg/dL = 2
Second dilution: initial concentration = 30 mg/dL
final concentration = 15 mg/dL
Dilution factor = 30 mg/dL / 15 mg/dL = 2
Therefore, the dilution factor for the serial dilution = 2
2. From the dilution formula, C1V1 = C2V2; V2 = final volume to be prepared.
Since 1 mL of the various glucose solutions are to be prepared, the final concentration, V2 = 1 mL
3. From the dilution formula, C1V1 = C2V2; V1 = initial concentration of the solution to be prepared.
C1/C2 = V2/V1
Since the dilution factor, C1/C2 is 2, V2/V1 = 2
V1 = V2/2
V1 = 1 mL / 2
V1 = 0.5 mL
A mixture of 1-heptyne, 2-heptyne, and 3-heptyne was hydrogenated in the presence of a palladium catalyst until hydrogen uptake ceased. How many seven-carbon hydrocarbons were produced
Answer:
four
Explanation:
Recall that the hydrogenation of 1-heptyne, 2-heptyne, and 3-heptyne is an addition reaction. The hydrogen is added across the triple bond in the presence of palladium serving as the catalyst.
Note that 1-heptyne and 2-heptyne do not exist as geometric isomers hence they yield one corresponding hydrocarbon each. However, 3-heptyne exhibits geometric isomerism. As a result of this, 3-heptyne yields cis and trans products making a total of four seven-carbon hydrocarbons produced.
So, the number of seven carbon hydrocarbons produced is one.
1-heptyne, 2-heptyne, and 3-heptyne
Note that if there is excess hydrogen, then all triple bonds will be substituted by hydrogen so only heptane is formed, double bonds and tirple bonds disappear to
[tex]CH_3-(CH_2)_5-CH_3[/tex]
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Carbon monoxide, a product of combustion, is a toxic gas that has an extremely high affinity for hemoglobin (much higher than that of oxygen for hemoglobin); consequently, as soon as it dissolves in the liquid part of blood at low partial pressure, it diffuses quickly into red blood cells and binds to hemoglobin. In carbon monoxide (CO) poisoning, even with very low partial pressure of inspired CO, CO rapidly binds to hemoglobin (Hgb), leaving a lower fraction of oxygen binding sites on Hgb available to be occupied by oxygen. What would you expect to find if you measure the arterial PO2 of a person with CO poisoning
Answer:
Decreases.
Explanation:
The arterial PO2 of a person is decreasing because of carbonmonoxide poisoning due to higher affinity to hemoglobin than oxygen. The PO2 in the blood of arteries are used up by the cells and then there is higher concentration of carbonmonoxide in the blood as compared to oxygen. Due to this higher amount of carbonmonoxide in the blood, many complications occur such as headache, dizziness, weakness, upset stomach, vomiting, chest pain, and confusion.
net ionic equation for 2AgF(aq) + k2S = Ag2S (s) + 2KF(aq)
Answer:
The net ionic equation shows the actual reaction more clearly and closer to reality because it writes soluble ionic compounds as the ions and then cancel the spectator ions not involved in the chemical reaction . The net ionic equation results shows the actual chemical reaction taking place.
The net ionic equation for for 2AgF(aq) + k₂S = Ag₂S (s) + 2KF(aq) will be; 2 Ag⁺(aq) + S²⁻(aq) → Ag₂S(s).
To write the net ionic equation for the reaction, we first need to write the balanced molecular equation and then convert it into the ionic equation before finally identifying the net ionic equation.
Write the balanced molecular equation:
2 AgF(aq) + K₂S(aq) → Ag₂S(s) + 2 KF(aq)
In this reaction, silver fluoride (AgF) reacts with potassium sulfide (K₂S) to produce silver sulfide (Ag₂S) and potassium fluoride (KF).
Write the complete ionic equation:
In the complete ionic equation, we separate all the aqueous species (dissociated ions) into their individual ions. Only the solid (s) and gas (g) compounds remain unchanged.
2 Ag⁺(aq) + 2 F⁻(aq) + 2 K⁺(aq) + S²⁻(aq) → Ag₂S(s) + 2 K⁺(aq) + 2 F⁻(aq)
Identify the spectator ions and then write the net ionic equation:
The spectator ions are the ions that do not participate in the actual chemical reaction and remain the same on both sides of the equation. In this reaction, the potassium ions (K⁺) and fluoride ions (F⁻) are spectator ions because they appear on both sides of the equation unchanged.
Net ionic equation:
2 Ag⁺(aq) + S²⁻(aq) → Ag₂S(s)
The net ionic equation shows only the species that actively participate in the chemical reaction. In this case, the silver ions (Ag⁺) and sulfide ions (S²⁻) are the ones involved in forming the silver sulfide (Ag₂S) precipitate.
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--The given question is incomplete, the complete question is
"Write the net ionic equation for this reaction. 2AgF(aq) + k₂S = Ag₂S (s) + 2KF(aq)."--
Use dimensional analysis to solve the following problems. Pay attention to correct use of units and correct use of significant figures in calculations.
1) Convert 8.00 moles of aluminum to grams.
2) Convert 10.5 moles of aluminum chloride to grams.
Answer:
Solution given:
1:
1 mole of aluminum =26.98 gram
8 mole =26.98*8=215.84 gram
8.00 moles of aluminum =215.84grams.
2:
1 mole of aluminum chloride =133.34 grams
10.5 moles of aluminum chloride =133.34*10.5=1400.07 grams
10.5 moles of aluminum chloride =1400 grams.
#1
Molar mass of Al=27g/mol1mol.of Al=27g
8mol of Al=27(8)=216g
#2
Molar mass of AlCl3=133.5g/mol
1 mol of AlCl3=133.5g
10.5mol.of AlCl3=10.5(133.5)=1401.75g
3. At 35 C, a sample of gas has a volume of 256 ml and a pressure of 720.torr. What would the volume
be if the temperature were changed to 22 C and the pressure to 1.25 atmospheres
Answer:
The volume will be 185.83 mL.
Explanation:
Gay-Lussac's law indicates that when there is a constant volume, as the temperature increases, the pressure of the gas increases. And when the temperature is decreased, the pressure of the gas decreases. Gay-Lussac's law can be expressed mathematically as follows:
[tex]\frac{P}{T} =k[/tex]
Where P = pressure, T = temperature, k = Constant
Boyle's law says that the volume occupied by a given gaseous mass at constant temperature is inversely proportional to pressure. Boyle's law is expressed mathematically as:
P*V=k
Where P = pressure, V = volume, k = Constant
Finally, Charles's Law consists of the relationship that exists between the volume and the temperature of a certain quantity of ideal gas, which is kept at a constant pressure. For a given sum of gas at a constant pressure, as the temperature increases, the volume of the gas increases and as the temperature decreases, the volume of the gas decreases because the temperature is directly related to the energy of the movement of the gas molecules. .
In summary, Charles's law is a law that says that when the amount of gas and pressure are kept constant, the quotient that exists between the volume and the temperature will always have the same value:
[tex]\frac{V}{T} =k[/tex]
Combined law equation is the combination of three gas laws called Boyle's, Charlie's and Gay-Lusac's law:
[tex]\frac{P*V}{T} =k[/tex]
Studying two different states, an initial state 1 and a final state 2, it is satisfied:
[tex]\frac{P1*V1}{T1} =\frac{P2*V2}{T2}[/tex]
In this case:
P1= 720 torr V1= 256 mLT1= 35 C= 308 K (being 0 C= 273 K)P2= 1.25 atm= 950 torr (being 1 atm= 760 torr)V2= ?T2= 22 C= 295 KReplacing:
[tex]\frac{720 torr*256 mL}{308 K} =\frac{950 torr*V2}{295 K}[/tex]
Solving:
[tex]V2= \frac{295K}{950 torr} *\frac{720 torr*256 mL}{308 K}[/tex]
V2= 185.83 mL
The volume will be 185.83 mL.