a pipe of cross sectional area 1.2 m2 narrows to a pipe of cross-sectional area 0.4 m2. if the fluid is traveling at 1.7 m/s in the larger pipe, calculate the fluid speed in the narrower pipe.

An object's centre of mass must be surrounded by an equal amount of mass on both sides. It is untrue.

The centre of mass of an item typically, but not always, sits within the thing itself. For instance, a ball's centre of mass is located in its exact centre, while a book's centre of mass is located in its middle.

When two objects of equivalent mass and speed approach one another, they stay together. After staying together, the two surfaces come to rest while retaining motion but losing kinetic energy. several of the energy of motion gets converted to thermal energy, or heat.

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The speed of the person as she enters the water is 14.2 m/s.

Kinetic energy is the energy of motion. It is the energy that an object has due to its motion. This energy can be transferred from one object to another or converted into other forms of energy. Kinetic energy is dependent on an object's mass and its velocity. The greater an object's mass or velocity, the more kinetic energy it has. Kinetic energy can be used to do work, such as powering a machine or vehicle. It can also be used to generate electricity or to heat up objects.

The speed of the person as she enters the water can be calculated using the equation for kinetic energy:
KE = ½mv²
Where m is the mass of the person (65 kg) and v is the speed.
Solving for v, we get:
v = √(2KE/m)
Since the potential energy of the person just before she enters the water is equal to the kinetic energy of the person just after she enters the water, we can calculate the kinetic energy as:
PE = mgh
KE = mgh
Where m is the mass of the person (65 kg), g is the acceleration due to gravity (9.8 m/s²), and h is the height of the platform (10 m).
Plugging this into the equation for v, we get:
v = √(2mgh/m)
v = √(2gh)
v = √(2*9.8*10)
v = 14.2 m/s

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It is obvious that In the pumped storage method, a pumped water is stored in a reservoir using unique pumps. Electric pumps consume electric power, however, and so the logic of the pumped storage methods seems poor but this is not so. Water is usually pumped during off-peak hours of power consumption. An essential reason for the pumped storage method is water-level control to make sure that the power station operates at all means or indefinitely. This reason reflects the economics of power generation as well.

what is hydroelectric system?

hydroelectric is a renewable energy also known as hydroelectric power,( hydropower), electricity that is produced from generators driven by turbines that convert the potential energy of falling or flowing water into mechanical energy.

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The speed at the level of the lowest position is 5.01m/s.

Energy cannot be created or destroyed; it can only be changed from one form of energy to another, according to the law of conservation of energy. This implies that a system always has the same amount of energy, barring external energy addition.

To reduce expenses and protect the resources for future use, energy conservation is necessary. The environment is contaminated by the harmful gases released into the atmosphere by conventional energy sources. Traditional energy sources are finite and could run out one day.

This is a typical energy conservation question, Set the kinetic energy at the bottom and the potential energy at the height to be equal.

mgh = 1/2mv²

gh = v²/2

v = √2gh

v = √2×9.8×1.28m/s

v = 5.01m/s.

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Answer: Synthesis

Explanation: You are combining multiple Elements

The magnitude of Ernie's resultant velocity is    [tex]V=8.72m/s[/tex].

Velocity:

Velocity is the direction in which an object is moving and serves as a measure of the rate at which its position is changing as seen from a specific point of view and as measured by a specific unit of time. In kinematics, the area of classical mechanics that deals with the motion of bodies, velocity is a fundamental idea.

Given,

Ernie's swimming rate with respect to the river   [tex]V_{ER} =6.2 m/s[/tex]

River's current rate [tex]V_{R}=10.7 m/s[/tex]

Hence,

         The magnitude of Ernie's resultant velocity

                                               [tex]V[/tex] = [tex]V_{R} -V_{ER}=10.7i - 6.2j[/tex]

                                              [tex]V=\sqrt{(10.7)^{2}-(6.2)^{2} }[/tex]

                                              [tex]V=8.72m/s[/tex]

Hence,

           The magnitude of Ernie's resultant velocity is  [tex]V=8.72m/s[/tex].

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If the cart moves in 3.2 seconds from rest, then the distance traveled by cart is 2 meters.

How do you define distance? Regardless of direction, distance measures an object's overall movement. Distance is defined as the amount of ground covered by an object, regardless of its starting or stopping position.

Horizontal force acting on the cart, F = 11 N

Mass of the cart, m = 35 kg

To find,

Distance covered by the cart in 3.5 seconds if it starts from rest.

Solution,

Let x is the distance moved by the cart. It can be calculated using the second equation of motion as :

s = 1.925 meters

In terms of "how much land an object is covered" while traveling, distance—a scalar quantity—describes this. Displacement is a vector number that expresses the overall change in the object's location, and it is related to the phrase "how far from place the thing is."

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We may be aware that, for example, a car leaving a stop sign would move farther in a given amount of time the faster it accelerates.

acceleration is the rate of change in both speed of velocity over time. When anything moves faster or slower in a straight line, it is said to have been accelerated. So because direction is always shifting, motion on a circle accelerates even while the speed is constant.

An object's velocity is altered by a net force, and acceleration increases with net force. To accelerate at the same rate as less massive objects, more massive objects need greater net forces.

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The dependent variable go on the Y-axis on a graph.

The dependent variable is described as the variable that is being measured or tested in an experiment.

Dependent variable can be explained using the example where a test score could be a dependent variable because it could change depending on several factors such as how much you studied, how much sleep you got the night before you took the test, or even how hungry you were when you took it.

The independent variable is found on the x-axis (horizontal line) of the graph and the dependent variable is displayed on the y-axis.

The difference between independent variable and the dependent variable is that in an experiment, the independent variable is the variable that is varied or manipulated by the researcher.

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Refer to the photo taken.

The volume of the toy is 80 ml.

To find the volume of the plastic toy, Maher can use the principle of buoyancy. When an object is placed in a fluid, it will displace an amount of fluid equal to its own volume. The volume of the displaced fluid can be measured and used to calculate the volume of the object.

In this case, Maher has placed the toy in a graduated cylinder filled with water, and he has observed that the water level increased from 70 ml to 150 ml. This means that the toy displaced 150 - 70 = 80 ml of water.

The volume of the toy is equal to the volume of the displaced water, so the toy's volume is 80 ml. This is the volume of the toy when it is completely submerged in water.

It's important to note that the volume of an object can change depending on its temperature, pressure, and other factors. To get an accurate measurement of the volume of the toy, Maher should make sure to measure the volume of the displaced water carefully and under controlled conditions.

Answer:

Volume of the toy: [tex]80\; {\rm mL}[/tex].

Average density of the toy: [tex]2\; {\rm g\cdot mL^{-1}}[/tex] (or equivalently, [tex]2\; {\rm g \cdot cm^{-3}}[/tex].)

Explanation:

The graduated cylinder initially measures the volume of water in this cylinder:

[tex]V(\text{water}) = 70\; {\rm mL}[/tex].

Assume that the toy is submerged in the water. The graduated cylinder would then measure the volume of the water and the toy, combined:

[tex]V(\text{water}) + V(\text{toy}) = 150\; {\rm mL}[/tex].

Rearrange to find the volume of the toy:

[tex]\begin{aligned}V(\text{toy}) &= 150\; {\rm mL} - V(\text{water}) \\ &= 150\; {\rm mL} - 70\; {\rm mL} \\ &= 80\; {\rm mL}\end{aligned}[/tex].

To find the average density of this toy, divide mass by volume:

[tex]\begin{aligned}(\text{average density}) &= \frac{(\text{mass})}{(\text{volume})} \\ &= \frac{160\; {\rm g}}{80\; {\rm mL}} \\ &= 2\; {\rm g\cdot mL^{-1}}\end{aligned}[/tex].

The velocity on the narrow side is 11.6 m/s. This is the velocity of the water in the narrow part of the pipe.

To find the velocity of the water where the pipe is narrow, you can use the formula for the mass flow rate, which is given by:

Mass flow rate = Density * Flow rate

= Density * (Area * Velocity)

Where:

Density is the density of the fluid

Flow rate is the volume flow rate, or the rate at which volume flows through the pipe

Area is the cross-sectional area of the pipe

Velocity is the velocity of the fluid

The mass flow rate is constant, so you can set the mass flow rate on either side of the constriction equal to each other and solve for the velocity on the other side.

The cross-sectional area of the pipe on the narrow side is given by the formula for the area of a circle:

A = pi * r^2

Where:

A is the cross-sectional area of the pipe

r is the radius of the pipe

The radius of the pipe on the narrow side is 3 cm / 2 = 1.5 cm. Plugging this value into the formula for the cross-sectional area, you get:

A = pi * (1.5 cm)^2

= 7.07 cm^2

The cross-sectional area of the pipe on the wide side is given by the same formula, with a radius of 6 cm / 2 = 3 cm:

A = pi * (3 cm)^2

= 28.27 cm^2

Since the mass flow rate is constant, you can set the mass flow rates on either side of the constriction equal to each other and solve for the velocity on the other side:

(Density * 7.07 cm^2 * v) = (Density * 28.27 cm^2 * 8 m/s)

Solving for v, the velocity on the narrow side, you get:

v = (Density * 28.27 cm^2 * 8 m/s) / (Density * 7.07 cm^2)

= 11.6 m/s

The final value for the velocity on the narrow side is 11.6 m/s. This is the velocity of the water in the narrow part of the pipe.

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Tension of the three cables connecting the  celling, 7 kg ball, 4 kg ball,  5 kg ball respectively 156.8 N,  88.2 N and 49 N.

The force communicated through a rope, string, or wire when two opposing forces draw on it is known as tension. The tension force pulls energy equally on the bodies at the ends and is applied along the entire length of the wire.

Tension of the cable connecting the  celling and 7 kg ball:

= (7 kg + 4 kg + 5Kg) × 9.8 m/s²

= 156.8 N.

Tension of the cable connecting the  7kg ball and 4 kg ball:

= (4 kg + 5Kg) × 9.8 m/s²

= 88.2 N.

Tension of the cable connecting the  4kg ball and 5 kg ball:

= 5Kg× 9.8 m/s²

= 49 N.

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To keep the car from slipping, the road and tires need to have a minimum coefficient of friction of 0.188.

The things creating friction will determine the coefficient of friction. The value is often between 0 and 1, but it can also be higher. A number of 0 indicates that there is absolutely no friction between the items; superfluidity makes this feasible. Yes. Because the adhesive forces between molecules are stronger when the contact surface is substantially polished, frictional force increases. In this situation, the friction coefficient will be higher than one.

Here m= 1402 kg

r=53

v= 9.9 m/s

g=9.8

coefficient = (v^2) / rg

coefficient = (9.9^2) / (53*9.8)

coefficient = 98.01/519.4

coefficient = 0.188

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The deductible level that would result in the lowest premium for automobile insurance is from  $250 or $500

For those who anticipate needing expensive medical care or continuous medical treatment, a plan without a deductible typically offers good coverage and is a wise decision.

In most circumstances, a plan's premium will be lower the larger its deductible. You save money on what you pay each month when you're willing to pay more up front when you need care.

The typical range for a comprehensive deductible suggested by insurance agents is between $100 and $500. It makes sense to have a smaller deductible for comprehensive claims because they often involve less damage than collision claims.

High-deductible health plans typically have cheaper premiums but need greater upfront payments before insurance will cover medical expenses. Meanwhile, higher premiums are typically associated with health insurance plans with lower deductibles since they provide more predictable expenses and frequently more robust coverage.

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The relation between the time-period of the transverse wave for the third harmonic and the time between the maximum displacement and minimum displacement is [tex]=16.3 \mathrm{~g}[/tex]

[tex]$$T_3=2 t$$Substitute$8.40 \mathrm{~ms}$[/tex]

for t in the above expression.

[tex]$$T_3=2(8.4 \mathrm{~ms})\left(\frac{10^{-3} \mathrm{~s}}{1 \mathrm{~ms}}\right)$$[/tex]

The wave velocity can be given by the following expression [tex]=0.0168 \mathrm{~s}[/tex]

[tex]v=\frac{\lambda_3}{T_3}[/tex]

Here,

[tex]$$\lambda_3$$[/tex]

is the frequency of third harmonics and

[tex]$$T_3$$[/tex]

is the time-period of third harmonics.

Substitute [tex]$0.1296 \mathrm{~m}$[/tex] for

[tex]$$\lambda_3$$[/tex]

and

[tex]$0.0168 \mathrm{~s}$ for$T_3$[/tex]

[tex]\begin{aligned}& v=\frac{0.1296 \mathrm{~m}}{0.0168 \mathrm{~m}} \\& =7.714 \mathrm{~m} / \mathrm{s}\end{aligned}[/tex]

The expression of the wave velocity is given by the following expression.

[tex]v=\sqrt{\frac{T}{m / L}}[/tex]

Rearrange the above expression for

[tex]$$m$$[/tex]

[tex]\text { Substitute } 5.00 \mathrm{~N} \text { for } T, 0.1944 \mathrm{~m} \text { for } L \text {, and } 7.714 \mathrm{~m} / \mathrm{s} \text { for } v \text { in the above expression. }[/tex]

[tex]\begin{gathered}m=\frac{(5.00 \mathrm{~N})(0.1944 \mathrm{~m})}{(7.714 \mathrm{~m} / \mathrm{s})^2} \\=(0.0163345 \mathrm{~kg})\left(\frac{1000 \mathrm{~g}}{1 \mathrm{~kg}}\right) \\=16.3 \mathrm{~g}\end{gathered}[/tex]

The anti-nodes in the standing waves are at a distance half a wavelength. The time-period is twice the time from maximum displacement to minimum displacement of the anti-node.

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So let's talk about billiard balls and the law of conservation of momentum. For the purposes of this simplified discussion, momentum is always conserved for collisions between balls.

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Answer:

1800J

Explanation:

E = ½mv²

E = ½(4)(30)²

E = 2 x 900

E = 1800J

During a game of bowling the ball's motion:

The correct options are A,B and E.

Bowling ball motion is commonly divided into sequential skid, hook, and roll phases. When the ball moves down the lane in the skid and hook phases, frictional contact with the lane causes the ball's forward (translational) speed to continually decrease, but to continually increase its revolution rate (rotational speed).

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sheesh sheesh                                                    

Explanation:

The mass of the rock will be 20 kg. This can be determined from the kinetic energy equation, k = 1/2 mv².

Kinetic energy, which may be seen in the movement of an item or subatomic particle, is the energy of motion. Kinetic energy is present in every particle and moving object. Kinetic energy may be transmitted from one thing to another, for example during collisions, and is determined by the mass of an item and its movement or speed.

Given in the question,

Kinetic Energy of rock = 2000J

Velocity of rock = 20 m/s

also, k.e. = 1/2 mv²

       2000 = 1/2 m × 20²

       m = 20 kg

The mass of rock that blew in the sky was 20 kg.

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The force due to gravity will be 0.0272 Newtons.

The force between two mass-containing objects that are drawn toward one another is referred to as the gravitational pull. There is gravity everywhere around us. For instance, it maintains the planets in our solar system in orbit around the Sun. Additionally, because to gravity, the Moon maintains its orbit around the Earth.

Despite being weak and appealing, gravitational forces exist.

Given, mass of one object= 2300 kg

mass of another object= 4000 kg

distance between the two objects= 0.150 m

value of G is universal, [tex]G= 6.67[/tex]×[tex]10^{-11}[/tex] [tex]N m^{2} / kg^{2}[/tex]

the equation is, [tex]F=G\frac{M1 . M2}{d^{2} }[/tex]

                       [tex]F=0.0272 N[/tex]

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An energy eigenstate can always be written as (x,t) = (x)e-iEt/1. Probability density is equal to |(x,t)|2 (x,t) (x)e-iEt/1 * (x,t) ψ*(x)e+iEt/1 = ψ (x) The wave function *(x) = |(x)|2 exhibits time-dependent phase.

For the system of a particle or particles interacting with a set of constraints, V(x) is a potential energy function. These restrictions can be compared to fields that exert a force on the desired particle or particles.

The term "energy eigenvalues," which comes from the German word eigen, which means "characteristic" or "unique," refers to such particular discontinuous (step-like) energies. We refer to these energies as discrete energy eigenvalues or as quantized energies.

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The energy levels and the corresponding eigenstates of a particle of mass m subject to a potential energy v(x) g can be determined by solving the time-independent Schrodinger equation.

What is potential energy?

Potential energy is energy that is stored and can be released in the future. It is the energy of position or condition, as opposed to kinetic energy which is energy in motion. Potential energy can be stored in many forms such as gravitational, chemical, elastic, nuclear, and electromagnetic. Gravitational potential energy is the energy stored in an object due to its position in a gravitational field, while chemical potential energy is the energy stored in the bonds of chemical compounds. Elastic potential energy is energy stored in objects that can be stretched or compressed, such as a spring, while nuclear potential energy is the energy stored in the nucleus of an atom. Electromagnetic potential energy is the energy stored in the electric and magnetic fields of an object.

The energy levels and the corresponding eigenstates of a particle of mass m subject to a potential energy v(x) g can be determined by solving the time-independent Schrodinger equation:
Hψ = Eψ
Where H is the Hamiltonian operator, ψ is the wavefunction, and E is the energy. For a particle of mass m subject to a potential energy v(x) g, the Hamiltonian can be written as:
H = -(h2/2m)*d2/dx2 + v(x) g
The solution of the Schrodinger equation for this Hamiltonian yields the energy levels E and the corresponding wavefunctions ψ. The energy levels are determined by solving the equation:
E - v(x) g = 0
This equation can be solved for the different energy levels E, and the corresponding wavefunctions can then be determined by solving the Schrodinger equation. The wavefunctions represent the probability distribution of the particle, and are determined by the boundary conditions imposed by the potential energy.
In summary, the energy levels and the corresponding eigenstates of a particle of mass m subject to a potential energy v(x) g can be determined by solving the time-independent Schrodinger equation. The energy levels are found by solving the equation E - v(x) g = 0, and the corresponding wavefunctions are found by solving the Schrodinger equation.

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Explanation:

If you dropped particles of different shapes from a boat into still water, they would fall straight down due to the force of gravity. The speed at which they fall would depend on their mass and the shape of the particles could affect how they move through the water, but ultimately they would all sink to the bottom of the water body. If the particles are buoyant, they may float instead of sinking.

The statement that explains how energy is conserved during this chemical reaction is " The potential energy lost by the reaction system (C) is gained by the surroundings".

option A is the correct answer.

The law of conservation of energy states that energy can  neither be created nor destroyed but can be transformed from one form to another.

Based on the law of conservation of energy, the potential energy of a system can be converted into kinetic energy or heat energy gained by the surrounding.

ΔP.E = ΔH

Pf - Pi =  C

where;

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Processor-A uses 20 W of power components and 80 W cpu dynamic power 3 GHz.

When there is no design activity occurring, static power—also known as "leakage"—is used up. It closely relates to the transistor's idle current, which is based on the transistor's characteristics.

While leakage, or the current that passes through a transistor while there is no activity, makes up static power, switching or short-circuit power are components of dynamic power. Any of the following things may influence each power component's value: Activity. Frequency.

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The two-ball system's center of mass will accelerate at a rate of "g" with respect to the earth.

It represents the system's average location as weighted by each component's mass. The center of mass for straightforward stiff objects with homogeneous density is found at the centroid.

Finding the center of mass for symmetrical objects is significantly easier because symmetrical points on one side of the item will negate those same points on the other. Consider a uniform cylinder that is upright as an illustration.

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The new gravitational force between the object will be 1/20.25 times of the original force.

The gravitational force between any two object is defined as the product of the masses of the object and it is inversely proportional to the square of the distance between them which is given by,

F = GMm/R²

Here,

G is the universal gravitational constant, M and m are the mass of the body and R is the distance between them.

As per the given question the distance between the object is increased 4.5 times the original separation.

R' = 4.5R.

The new force of attraction between the object will be,

F' = GMm/(R')²

F' = GMm/(4.5R)²

F' = GMm/20.25R²

F' = F/20.25

So, the new force of attraction between the two objects will become 1/20.25 times of original force.

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Answer:

5 m

Explanation:

Displacement is the straight-line distance from the starting point to the end point.  Student ends up 4m north and 3m west from where he started. Use pythagorean theorem to solve for displacement (d).  

d² = 3² + 4² = 25

d = [tex]\sqrt{25}[/tex] = 5 m

Or, if you remember from geometry, a right triangle with legs of 3 and 4 has a hypotenuse of 5 (3-4-5 right triangle)

Answer:

S = V1 t + 1/2 a t^2        distance traveled for linear acceleration

θ = ω1 t + 1/2 α t^2       equivalent angle for rotational acceleration

ω1 = 240 / min * 2 π * 240 / (60 s/min) = 8 π / s

ω2 = 360 rpm = 12 π / s

α = 4 π/ 6.5 s^2  = .62 π / s^2    angular acceleration

θ = 8 π / s  6.5 s + .62 π / 2 * 6.5^2

θ = 52 π + 13 π = 65 π = 65 * π / (2 π / rev) = 32.5 rev

1 rev = 2 * π * R = 2 * π * .4 m = 2.51 m / rev

S = 32.5 rev * 2.5 m/rev =  81 m