The centripetal acceleration of the piece of clay on the wheel at the given tangential speed is 20 m/s².
The given parameters;
radius of the potter's wheel, r = 0.2 mlinear speed, v = 2 m/sThe centripetal acceleration of the piece of clay on the wheel is calculated as follows;
[tex]a = \frac{v^2}{r} \\\\a = \frac{2^2}{0.2} \\\\a = 20 \ m/s^2[/tex]
Thus, the centripetal acceleration of the piece of clay on the wheel at the given tangential speed is 20 m/s².
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Which of the following correctly compares gravitational force and distance between two objects?
A. As the distance increases, the gravitational force decreases.
B. As the distance decreases, the gravitational force decreases.
C. There is no relationship between gravitational force and distance between two objects.
D. As the distance increases, the gravitational force increases.
Help pls…
Answer:
a. as the distances increases , the gravitational force decreases
A student uses a spring (with a spring constant of 180 N/m) to launch a marble vertically into the air. The mass of the marble is 0.004 kg and the spring is compressed 0.03 m. How high will the marble go? Answer:
Answer:
Explanation:
Ignoring air resistance the spring compression energy will equal the increase in potential energy from the maximum spring compression point to the top of the flight arc.
mgh = ½kx²
h = kx²/2mg
h = 180(0.03²) / (2(0.004)(9.8))
h = 2.06632...
h = 2.1 m
A photographer wants to determine the color of light he can use in the darkroom that will not expose the films he is processing. In one trial, he used a blue incandescent bulb. Which bulb can he use for another trial?
A. Red incandescent bulb C. Red fluorescent bulb
B. Blue incandescent bulb D. Blue fluorescent bulb
For a photographer that wishes to determine the color of light that he can use in a dark room that will not expose the films he is processing, having used a Blue Incandescent bulb, he should proceed to use a Red Incandescent bulb for the next trial.
The photographer in question is performing an experiment. For these kinds of experiments it is important to identify the variables present, which can be of three kinds:
Control variablesDependent variables Independent variablesFor this experiment, the dependent variable is the exposure of the light onto the films, given that this is what we wish to measure. The independent variable will be the color of the light being used which is what will affect the dependent variable.
The remaining variable must be the control variable. Unlike the previous variables, we can have more than one of these. The control variable is there to make sure that only the dependent variable is affecting the outcome. We do this by keeping the control variable the same through each trial, which is why the photographer should not change the type of bulb in the second experiment, changing only the color of the light.
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5. A quarterback throws the football to a stationary receiver who is 31.5 m
down the field. If the football is thrown at an initial angle of 40.0° to the
ground, at what initial speed must the quarterback throw the ball for it
to reach the receiver? What is the ball's highest point during its flight?
The projectile launch equations allow to find the results for the questions about the movement of the ball are:
The initial velocity is: v₀ = 17.7 m / s. The maximum height is: y = 16 m.
Given parameters
Horizontal distance x = 31.5 m Launch angle tea = 40ºTo find
The initial speed. Maximum height.
Projectile launching is an application of kinematics, where on the x-axis there is no acceleration and on the y-axis is the gravity acceleration.
The range is the distance traveled for the same departure height, see attached.
.
R =[tex]\frac{v_o^2 \ sin 2\theta}{g}[/tex]
[tex]v_o^2 = \frac{ g R}{sin 2 \theta }[/tex]
Let's calculate.
v₀² = [tex]\frac{9.8 \ 31.5}{sin \ (2 \ 40)}[/tex]9.8 31.5 / sin (2 40.0)
[tex]v_o = \sqrt{313.46}[/tex]o = ra 313.46
v₀ = 17.7 m / s
At the point of maximum height the vertical speed is zero.
v² = v₀² - 2 g y
0 = v₀² - 2g y
y = [tex]\frac{v_o^2}{2g}[/tex]
Let's calculate.
y = [tex]\frac{17.7^2}{2 \ 9.8}[/tex]
y = 16 m
In conclusion, using the projectile launch equations we can find the results for the questions about the movement of the ball are:
The initial velocity is: v₀ = 17.7 m / s The maximum height is: y = 16 m.
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A rocket accelerates from rest at 27 m/s^2 for 11 s.
How far will it cover during this time?
Answer in units of m.
Answer:
297m
Explanation:
297 x 11
:)
Lakepointe Tower in Chicago is the tallest apartment building in the United States (although not the tallest building in which there are apartments). Suppose you take the elevator from street level to the roof of the building. The elevator moves almost the entire distance at constant speed, so that it does 1.15x10^5 J of work on you as it lifts the entire distance. If your mass is 60.0 kg, how tall is the building? Ignore the effects of friction.
Given the information supplied in the question, the height of the building is 196 m.
The work done on you is a work done in a gravitational field. Recall that the work done in a gravitational field is given by mgh where;
m = mass of the body
g = acceleration due to gravity
h = height
Given that;
Work done = 1.15x10^5 J
Acceleration due to gravity = 9.8 ms-2
Mass = 60.0 kg
Substituting values;
h = W/mg
h = 1.15x10^5 J/ 60.0 kg × 9.8 ms-2
h = 196 m
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Another engine reaches its top speed in 7.5s. It is able to perform 250,000 J of wok in that time. How much power this engine have in that time?
Answer:
33,333.3J/s
Explanation:
Energy expended which is the work done in Joule
=250,000J
Time taken to expend the energy =7.5s
Power =Unknown
Formula
Power = Work
Time
Hence, Power = 250,000J
7.5s
Power = 33,333.3J/s
which of the following is used to transport sound waves
A.medium
B.vacuum
C.mass
D.light
I think the answer is d.right?
PLS I NEED YOUR HELP WILL MARK AS BRAINIEST
Drag each chemical equation to the correct label.
Answer:
Explanation:
now that you know about newton's first law of motion, how might you use it to ride a skateboard safely?
Answer:
newton's first law of motion was developed by English scientist Isaac Newton around 1700. Newton was one of the greatest scientists of all time. He developed three laws of motion and the law of gravity, among many other contributions.
Explanation:
Lupert walked 5.8 m east in 8.9 s, stopped for 3.7 s, turned North and went 7.9 m in 12.5 s, stopped for 6.3s , and then went 3.2 m west in 4.7s. What was his average speed?
The average speed of Lupert for the entire journey is 4.58 m/s.
The given parameters;
initial position of Lupert, = 5.8 m easttime of motion, = 8.9 s, extra time = 3.7 ssecond position of Lupert, = 7.9 m, Northtime of motion, = 12.5 s, extra time = 6.3 sfinal position of Lupert = 3.2 m westtime of motion = 4.7 sThe average speed of Lupert is calculated as the ratio of the total distance to total time of motion;
[tex]average \ speed = \frac{(5.8 \times 8.9) \ + \ (7.9 \times 12.5) \ + \ (3.2 \times 4.7)}{8.9 \ + \ 3.7 \ + \ 12.5 \ + \ 6.3\ +\ 4.7} \\\\average \ speed = \frac{165.41}{36.1} \\\\average \ speed =4.58 \ m/s[/tex]
Thus, the average speed of Lupert for the entire journey is 4.58 m/s.
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Required information
Medical testing has established that the maximum acceleration a pilot can be subjected to without losing consciousness is
approximately 5.00g. A pilot can avoid "blackout" at accelerations up to approximately 9.00g by wearing special "g-suits"
that help keep blood pressure in the brain at a sufficient level.
What is the minimum safe radius of curvature for an unprotected pilot flying an F-15 in a horizontal circular loop at 729 km/h?
Answer:
hi there is that OK for the weekend of the following week as well
Explanation:
6th of March is fine for me
The minimum safe radius of curvature for an unprotected pilot flying an F-15 in a horizontal circular loop at 729 km/h is approximately 838.1 meters.
To determine the minimum safe radius of curvature for an unprotected pilot flying an F-15 in a horizontal circular loop, we need to consider the maximum acceleration the pilot can withstand without losing consciousness.
Given:
Maximum acceleration without losing consciousness = 5.00g
Acceleration with g-suits to avoid blackout = 9.00g
First, we need to convert the speed of the F-15 from km/h to m/s:
Speed = 729 km/h = (729 * 1000) m/3600 s ≈ 202.5 m/s
Next, we'll calculate the acceleration experienced by the pilot in the circular loop. In a horizontal circular motion, the centripetal acceleration is given by:
Acceleration = ([tex]\rm Velocity^2[/tex]) / Radius
We can rearrange the equation to solve for the radius:
Radius = ([tex]\rm Velocity^2[/tex]) / Acceleration
Using the maximum acceleration of 5.00g, we convert it to [tex]\rm m/s^2[/tex]:
Maximum acceleration = 5.00g ≈ (5.00 * 9.8) [tex]\rm m/s^2[/tex] = 49 m/s^2
Now, we can calculate the minimum safe radius of curvature:
Radius = ([tex]\rm 202.5^2[/tex]) / 49 ≈ 838.1 meters
Therefore, the minimum safe radius of curvature for an unprotected pilot flying an F-15 in a horizontal circular loop at 729 km/h is approximately 838.1 meters.
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pls help me… I missed the whole lesson and I have no clue what to do-
Answer:
1) 50 facing towards the right
2) 150 facing right
3) 200 facing right
4) 0- no direction
5) 50- facing left
6) 50 facing right
Explanation:
forces in opposite directions and equal magnitudes counteract each other. in number 2 they face the same direction so they would just be added. in number 4 they oppose each other so would be subtracted
The acceleration produced by a net force on an object is and why?
A.)inversely proportional to the mass of the object.
B.)directly proportional to the magnitude of the net force
C)in the same direction as the net force
D)all of the above
Answer:
A i think
Explanation:
Place a beaker covering its free surface with a paper over a coin as shown in the figure- 1. The coin can be seen through the sides of the beaker. (i) Fill the beaker with water. Is the coin seen through the sides of the beaker? If not, why? (ii) Drop water over the coin. Is the coin seen through the sides of the beaker? If yes, why?
Answer:
bonjour
Explanation:
bye
An object travels 120 m in 6 seconds. How fast is it moving?
Answer:
I actually don't understand what you are asking for....but if you denote second then...
Explanation:
Just divide 120/6=20
Hence, it's traveling 20m per second.
Answer:
20 m/s
Explanation:
Speed = Distance/Time
Speed = 120m/6s
Speed = 20 m/s
arrange the events that are believed to have formed the hydrosphere in their order of occurrence.
Answer:
Explanation:
It is not very likely that the total amount of water at Earth’s surface has changed significantly over geologic time. Based on the ages of meteorites, Earth is thought to be 4.6 billion years old. The oldest rocks known are 3.9 billion to 4.0 billion years old, and these rocks, though altered by post-depositional processes, show signs of having been deposited in an environment containing water. There is no direct evidence for water for the period between 4.6 billion and 3.9–4.0 billion years ago. Thus, ideas concerning the early history of the hydrosphere are closely linked to theories about the origin of Earth.
Earth is thought to have accreted from a cloud of particles around the Sun. This gaseous matter condensed into small particles that coalesced to form a protoplanet, which in turn grew by the gravitational attraction of more particulates. Some of these particles had compositions similar to that of carbonaceous chondrite meteorites, which may contain up to 20 percent water. Heating of this initially cool, unsorted conglomerate by the decay of radioactive elements and the conversion of kinetic and potential energy to heat resulted in the development of Earth’s liquid iron core and the gross internal zonation of the planet (i.e., differentiation into core, mantle, and crust). It has been concluded that Earth’s core formed over a period of about 500 million years. It is likely that core formation resulted in the escape of an original primitive atmosphere and its replacement by one derived from the loss of volatile substances from the planetary interior (see evolution of the atmosphere).
PLEASE HELP WITH THESE WILL GIVE BRAINLEIST
When you rub your hands together quickly, you can feel the heat it generates!
what is the activity illustration?
what is the type of force?
Answer: type of force is friction
Explanation:
Answer:
When you rub your hands together, the action of scraping the
surface of your skin back and forth against each other causes
the molecules in your skin to move a little faster. The faster
that molecules move, the higher the temperature. So the
friction of rubbing your hands together makes them feel
warmer.
The force is friction. It's a force that opposes motion. It is present whenever two surfaces rub over each other, such as when you rub your hands together, or when you apply the brakes on a bike or in a car.
Explanation: I hope this helped you!
hey I just wanted to know if any of the guys here are able to help answer my physics questions , it would be a great thankyou xoxoxoxo
what's your question?
PLEASE HELP!!!
If a 40cm rope with a 220g bob can hold a maximum tension of 3N
a) what are the maximum angular velocity and inclination angle it can reach before the rope break?
b) Angle of inclination
Answer:
ω = 3.1 rad/s
θ = 36° from vertical
Explanation:
I will ASSUME that the bob and string is acting as a pendulum.
Please understand that the string will break when the bob is at the lowest point of the swing where the vectors of gravity and centripetal acceleration align. It will NOT break at the angle of maximum inclination measured from vertical. This angle is only a component of the maximum potential energy that gets converted to maximum kinetic energy at the lowest point of the swing.
At the bottom of the swing, the string must support the weight of the bob plus supply the required centripetal acceleration.
F = mg + mω²R
F/m = g + ω²R
F/m - g = ω²R
ω = √((F/m - g)/R)
ω = √((3/0.220 - 9.8)/0.40)
ω = 3.09691...
ω = 3.1 rad/s
Potential energy will convert to kinetic energy
mgh = ½mv²
h = v²/2g
R - Rcosθ = v²/2g
R(1 - cosθ) = v²/2g
1 - cosθ = v²/2gR
cosθ = 1 - v²/2gR
cosθ = 1 - (Rω)²/2gR
cosθ = 1 - Rω²/2g
cosθ = 1 - 0.40(3.1²)/(2(9.8))
cosθ = 0.804267
θ = 36.46045...
θ = 36°
Two electrons are separated by 2.00 nm. What is the magnitude of the electric force each electron exerts on the other?
Answer:Two electrons are separated by 2.00 nm. What is the magnitude of the electric force each electron exerts on the other?
Explanation:
Two electrons are separated by 2.00 nm. What is the magnitude of the electric force each electron exerts on the other?
How do energy and matter move in ecosystems?(1 point)
Energy and matter flow in one direction.
Matter flows in one direction, and energy cycles through the environment.
Energy flows in one direction, and matter cycles through the environment.
Energy and matter cycle through the environment.
Answer
Explanation:
Energy flows in one direction,and matter cycle the environment
Energy flows in one direction and matter cycles through the environment in an ecosystem.
What is an ecosystem?
Ecosystem is defined as a system which consists of all living organisms and the physical components with which the living beings interact. The abiotic and biotic components are linked to each other through nutrient cycles and flow of energy.
Energy enters the system through the process of photosynthesis .Animals play an important role in transfer of energy as they feed on each other.As a result of this transfer of matter and energy takes place through the system .Living organisms also influence the quantity of biomass present.By decomposition of dead plants and animals by microbes nutrients are released back in to the soil.There are many ecosystems present in the environment.
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An airplane has a mass of 33,000 kg and takes off under the influence of a constant net force of 44,000 N. What is the net force that acts on the plane's 70 kg pilot
Answer:
Explanation:
acceleration a = F/m = 44000/33000 = 1.3m/s²
F = ma = 70(1.3) = 93 N
A ball is launched into the air at an angle of 32ᵒ with an initial speed of 18 m/s. Neglecting air resistance, determine how high the ball will go, how long it will be in the air, and how far it will travel.
Hiii Can somebody take their precious time to answer this question?
Answer:
557
A ball is launched into the air at an angle of 32ᵒ with an initial speed of 18 m/s. Neglecting air resistance, determine how high the ball will go, how long it will be in the air, and how far it will travel.
Hiii Can somebody take their precious time to answer this question?
Describe how you can determine:
a) Volume of an irregular body
b) Density of a liquid
Density of liquid try thank you so much
Answer:
a) measure the change in volume when the object is immersed; compute from range data
b) find the ratio of mass to volume for a measured mass and volume
Explanation:
a) The volume of a small enough irregular body can be found by measuring the difference in volume of the (semi-)fluid in which it is immersed, before and after immersion.
For irregular bodies for which that approach does not work, various 3D scanners are available for measuring volume and surface area. They may rely on optical (laser or camera), sonic, or radar measurements, and generally involve computation from distances to various points.
__
b) Density is the ratio of mass to volume. So, measurements of mass and volume of a liquid sample are sufficient to provide the basis for determining density.
Other methods include measuring buoyancy forces, and/or the depth of submersion of something that floats in the liquid. For specific liquids, hydrometers are available for measuring their density relative to that of water.
An object is projected horizontally with the velocity 4m/s from a height of 20 m. the horizontal displacement is (angle x) :
Answer:
Δx = 8 m
Explanation:
The time needed to fall from vertical rest
h = ½gt²
t = √(2h/g)
t = √(2(20)/9.8)
t = 2.0 s
the horizontal distance traveled in that time is
d = vt
d = 4(2)
d = 8 m
Do you expect the normal dicrystalline resistance in the forward bias to be pure ohmic resistance or what ?!
Answer:
yes
Explanation:
because is pure ohmic risistance
To see how visual encoding works, read over this list of words: car,
level, dog, truth, book, value. If you were asked later to recall the
words from this list, which ones do you think you'd most likely
remember? Why those words?
I think I would most likely remember car, level, dog, and book. I think I would remember these words because car and level came first, I love dogs, and I like reading books. I can associate something with dogs and books so it helps me remember those words.
[Visual encoding is when people remember things by pictures in their head, but I have aphantasia so I am honestly not the best person to answer this question
If a car skids to a stop in 3.8s while undergoing a uniform acceleration of -9.55 m/s2, what is the car’s velocity?
Answer:
36.29 m/s
Explanation:
We know from theory that [tex]v= v_0 +a\Delta t[/tex]. Let's replace the value we know in our equation and solve for the only value left.
[tex]0 = v_0 - 9.55 \cdot 3.8 \\ v_0 = 9.55 \cdot 3.8 = 36.29 m/s[/tex]
True or false. The buildings in cities are getting larger
Answer:
trueExplanation:
cuase the city is getting more people than before