A penny is thrown from the top of a 26.6-meter building and hits the ground 3.59 seconds after it was thrown. The penny reached its maximum height above the ground 0.77 seconds after it was thrown.

1. Define a quadratic function, h, that expresses the height of the penny above the ground (measured in meters) as a function of the number of seconds elapsed since the penny was thrown, t.

2.What is the maximum height of the penny above the ground?

Answers

Answer 1

Answer:

it is at 200 mph

Step-by-step explanation:

bc i did the test

Answer 2

The quadratic function which models the motion of the penny is h(t) = -4.9t² + 10.18t + 26.6 and the maximum height reached is 31.53 meters

The relationship can be expressed in the form :

h(t) = - 0.5gt² + vt + h (downward motion)

g = 9.8 m/s²

h = 26.6 m

v = ?

We can obtain v thus ;

h(t) = -0.5gt² + vt + 26.6

h(t) = - 4.9t² + vt + 26.6

Time when penny hits the ground ; t = 3.59

h(3.59) = 0

0 = -4.9(3.59)² + v(3.59) + 26.6

− 63.15169 + 3.59v + 26.6 = 0

3.59v = 36.55169

v = 36.55169 /3.59

v = 10.181 m/s

Equation becomes :

h(t) = -4.9t² + 10.18t + 26.6

2.) The maximum height of the penny above the ground ;

t = 0.77 seconds

h(0.77) = -4.9(0.77^2)+ 10.18(0.77) + 26.6

Maximum height reached = 31.53 meters

Therefore, the maximum height reached is 31.53 meters

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Related Questions

Consider a right-tailed test (upper tail) and a sample size of 40 at the 95% confidence level. The value of t is ________.
a. +2.023
b. -2.023
c. -1.685
d. +1.685

Answers

Answer:

The correct option is d.

Step-by-step explanation:

The directional hypothesis is:

[tex]H_{a}:\mu>\mu_{0}[/tex]

The sample size is, n = 40.

The significance level is:

[tex]\alpha =1-0.95=0.05[/tex]

Use the t-table to compute the right-tailed t-critical value as follows:

[tex]t_{\alpha,\ (n-1)}=t_{0.05, (40-1)}[/tex]

             [tex]=t_{0.05, 39}\\\\\approx t_{0.05, 40}\\\\=1.684\\\\\approx 1.685[/tex]

The value is positive since the directional hypothesis suggests that the test is right tailed.

The correct option is d.

The perimeter of a triangle is 69Cm. Side a is 5cm shorter then side b. side c is 5 more than twice side b. Find the length of each side

Answers

Step-by-step explanation:

Given parameters:

Perimeter of triangle  = 69cm;

 

Unknown:

Length of each side  = ?

Solution:

   Side a is 5cm shorter than side b;

         b  = a + 5  ----- i

   Side c is 5 more than twice side b;

          c = 2b + 5

The three sides of triangle are a, b and c;

  Perimeter is the sum of sides of a body;

      a + b + c  = 69

From i;

        a  = b - 5

        b

       c  = 2b + 5

so;

          b - 5 + b + 2b + 5  = 69

           4b = 69

            b  = 17.25cm

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Step-by-step explanation:

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Answers

Answer:

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Step-by-step explanation:

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Answers

Answer:

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Step-by-step explanation:

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Answer:

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Answer:

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Step-by-step explanation:

Jeisejsoshsisjnakakaajhsixndkdjsjdhjdjdjdhsjshehhss

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Answers

Answer:

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Step-by-step explanation:

Answer:

AB = 8, HB = 6, Area of ∆ABC = 8[tex]\sqrt{3}[/tex], Perimeter of ∆ABC = 12 + 4[tex]\sqrt{3}[/tex]

Step-by-step explanation:

To find AB:

∆ABC is an 30,60,90∆

Using the theorem, you can find AB = 2AC = 2*4 = 8

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To find HB:

You need to find AH to subtract from AB

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then substitute, and get [tex]2^{2} + CH^{2} = 4^{2}[/tex]

calculate and get CH = 2[tex]\sqrt{3}[/tex]

then the height = CH =  2[tex]\sqrt{3}[/tex]

solve the area and get

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(optional perimeter)

to find perimeter of ∆ABC:

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you find CB by using opposite to 30°

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I WILL MARK BRAINLIST

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Step-by-step explanation:

Hope that helped! Have a great rest of your day!

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Answers

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Answers

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Answers

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Answers

Answer: Choice D

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==================================================

Work Shown:

[tex]f(x) = x^2 + 9\\\\f(g(x)) = (g(x))^2 + 9\\\\f(g(x)) = (\sqrt{x+3})^2 + 9\\\\f(g(x)) = x+3 + 9\\\\f(g(x)) = x+12\\\\(f \circ g)(x) = x+12\\\\[/tex]

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Find the volume of the cylinder please

Answers

Answer:

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Step-by-step explanation:

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