A oil company has a large tank that holds the oil before it is distributed. If it costs $3.20 per cubic meter for oil, how much money would it cost to fill the entire tank?
A. $65,280
B. $68,000
C. $5,440
D. $67,200
Answers
Answer:
Option A, $65,280
Step-by-step explanation:
The volume of the tank is,
12×20×15+40×(50-15)×12
= 3600+16800
=20400 cubic meters
For each cubic meter, it costs $3.20, so for 20400 cubic meters it'll cost,
20400×$3.20
= $65,280
Answered by GAUTHMATH
Related Questions
Someone pls help me ill give out brainliest pls don’t answer if you don’t know
Answers
Answer:
i dont know
Step-by-step explanation:
figure it out yourself
Plss Answer!!!!!!!!!
Answers
Answer:
Ecosystem: Trees
Ways to protect are as follows:-
Control over Forest FireDon't waste paper. Plant a treeSimplify. 6x-2
A.6/x^2
B.x²/6
C.1/6x^2
D.1/36x^2
Answers
Answer:
Step-by-step explanation:
[tex]a^{-m}=\frac{1}{a^{m}}\\\\6x^{-2}=6*\frac{1}{x^{2}}=\frac{6}{x^{2}}[/tex]
Solve The inequality
Answers
Answer:
D is the correct answer.
Please thank me
Step-by-step explanation:
FOR EASY BRAINLIEST ANSWER QUESTION BELOW!
1. Solve each word problem .twice a number added three times the sum of the number and 2 is more than 17. Find the numbers that satisfy condition
Answers
Answer:
x > 23/5
Step-by-step explanation:
2x+ 3(x+2)>17
2x + 3x + 6 >17
5x >23
x > 23/5
Joseph is creating a dilation through point B with a scale factor of 2. Which statements about the dilation are correct? Check all that apply.
Triangle A B C. Angle B is a right angle.
A’ will be located on ray Ray B A.
B and B’ are the same point.
Line segment B prime C prime will be One-half as long as Line segment B C.
Line segment A B and Line segment B C will be part of the image’s sides.
The image will be inside the pre-image.
Answers
Answer:
A’ will be located on ray Ray B A.
B and B’ are the same point.
Line segment A B and Line segment BC will be part of the image’s sides.
Step-by-step explanation:
Given that the dilation is made through point B, B and B’ are the same point, A’ will be located on Ray BA, C’ will be located on Ray BC, line segment B'C' will be double than line segment BC, line segment B'A' will be double than line segment BA, and the pre-image (triangle ABC) will be inside the image (triangle A'B'C').
Answer:
A B D is your answer
Step-by-step explanation:
Point A (6,2) is translated using the vector <-5,2>. Where is the new point located?
Answers
======================================================
Explanation:
The notation <-5,2> is the same as writing the translation rule [tex](x,y) \to (x-5,y+2)[/tex]
It says: move 5 units to the left and 2 units up
The point (6,2) moves to (1,2) when moving five units to the left. Then it ultimately arrives at (1, 4) after moving 2 units up. You could move 2 units up first and then 5 units to the left later on, and you'd still arrive at (1, 4). In this case, the order doesn't matter (some combinations of transformations this won't be the case and order will matter).
---------
Or you could write out the steps like so
[tex](x,y) \to (x-5, y+2)\\\\(6,2) \to (6-5, 2+2)\\\\(6,2) \to (1, 4)\\\\[/tex]
We see that (6,2) moves to (1, 4)
I need help figuring out what the answer is.
Answers
Answer:
A
Step-by-step explanation:
A particle is projected with a velocity of [tex]40ms^-^1[/tex] at an elevation of 60°. Calculate the vertical component of its velocity at a height of 50m. (Take g = [tex]9.8ms^-^2[/tex])
A. [tex]25\sqrt{3} ms^-^1\\\\B.20\sqrt{3} ms^-^1\\\\c. 2\sqrt{545} ms^-^1[/tex]
Answers
Answer:
[tex]2\sqrt{55}\text{ m/s or }\approx 14.8\text{m/s}[/tex]
Step-by-step explanation:
The vertical component of the initial launch can be found using basic trigonometry. In any right triangle, the sine of an angle is equal to its opposite side divided by the hypotenuse. Let the vertical component at launch be [tex]y[/tex]. The magnitude of [tex]40\text{ m/s}[/tex] will be the hypotenuse, and the relevant angle is the angle to the horizontal at launch. Since we're given that the angle of elevation is [tex]60^{\circ}[/tex], we have:
[tex]\sin 60^{\circ}=\frac{y}{40},\\y=40\sin 60^{\circ},\\y=20\sqrt{3}[/tex](Recall that [tex]\sin 60^{\circ}=\frac{\sqrt{3}}{2}[/tex])
Now that we've found the vertical component of the velocity and launch, we can use kinematics equation [tex]v_f^2=v_i^2+2a\Delta y[/tex] to solve this problem, where [tex]v_f/v_i[/tex] is final and initial velocity, respectively, [tex]a[/tex] is acceleration, and [tex]\Delta y[/tex] is distance travelled. The only acceleration is acceleration due to gravity, which is approximately [tex]9.8\:\mathrm{m/s^2}[/tex]. However, since the projectile is moving up and gravity is pulling down, acceleration should be negative, represent the direction of the acceleration.
What we know:
[tex]v_i=20\sqrt{3}\text{ m/s}[/tex] [tex]a=-9.8\:\mathrm{m/s^2}[/tex] [tex]\Delta y =50\text{ m}[/tex]Solving for [tex]v_f[/tex]:
[tex]v_f^2=(20\sqrt{3})^2+2(-9.8)(50),\\v_f^2=1200-980,\\v_f^2=220,\\v_f=\sqrt{220}=\boxed{2\sqrt{55}\text{ m/s}}[/tex]
Write the expression as an exponent:
5^8 x 25
6^15 x 36
Answers
Answer:
a.) 5¹⁰
b.) 6¹⁷
Step-by-step explanation:
a.) 5⁸ × 25
Write 25 in the exponential form with the base of 5.
5⁸ × 5²To calculate product use exponent rule
5⁸+²5¹⁰b.) 6¹⁵ × 36
Similarly, 6¹⁵ × 36
Write 25 in the exponential form with the base of 6.
6¹⁵ × 6²To calculate product use exponent rule.
6¹⁵ + ²6¹⁷Answer:
[tex] \displaystyle {5}^{10} [/tex]
[tex] \displaystyle {6}^{17} [/tex]
Step-by-step explanation:
Question-1:we want to rewrite the following expression as an exponent
[tex] \displaystyle {5}^{8} \times {25}[/tex]
remember that 25 is the square of 5 therefore
[tex] \displaystyle {5}^{8} \times {5}^{2} [/tex]
recall that,
[tex] \displaystyle {x}^{m} \times {x}^{n} = {x}^{m + n} [/tex]
with that law we obtain:
[tex] \displaystyle {5}^{8 + 2} [/tex]
simplify addition:
[tex] \displaystyle {5}^{10} [/tex]
Question-2:likewise Question-1 36 is the square of 6 Thus,
[tex] \displaystyle {6}^{15} \times {6}^{2} [/tex]
similarly apply law of exponent:
[tex] \displaystyle {6}^{15 + 2} [/tex]
simplify addition:
[tex] \displaystyle {6}^{17} [/tex]
hence,
we have written the expression as an exponent
Find the constant of proportionality if y is
proportional to x.
A. 25
B. 21
C. 26
D. 28
HELPPP!!!!!!
Answers
What is dummy variable? Explain interaction effects using dummy variables? Explain Autoregressive Conditional Heteroskedasticity (ARCH) and Generalized Autoregressive Conditional Heteroskedasticity (GARH) models. What to do when find problem of Autocorrelation?
Answers
Answer:
u here then today the thats yjvfh dfnrugevc5hdb
What is the vertex of the graph of the function f(x) = (x + 2)^2 − 3?
Answers
Find the domain and range for each of the relations described by the sets of
ordered pairs below.
4. (-1, 2), (2, 51), (1,3), (8, 22), (9,51)
Domain:
Range:
Answers
Answers:
Domain = {-1, 2, 1, 8, 9}
Range = {2, 51, 3, 22}
==================================
Explanation:
The domain is the set of allowed inputs of a function. So it's the set of possible x values. We simply list the x coordinates of each point to form the domain.
The range is the set of possible y values or y outputs. So we simply list the y coordinates of the points. We toss out any duplicates. Since order doesn't matter in a set, we can have the values listed any way we want.
Side notes:
This is a function since we don't have any repeated x values between any of the points. This graph passes the vertical line test.This function is not one-to-one because we have y = 51 correspond to multiple x values (x = 2 and x = 9 simultaneously). This graph fails the horizontal line test.what is the measure of 2?
Answers
Answer:
Value of x:
[tex]{ \tt{(7x + 1) \degree + (18x + 4) \degree = 180 \degree}} \\ { \tt{25x + 5 = 180}} \\ { \tt{25x = 175}} \\ x = 7[/tex]
Finding m‹2 :
[tex]{ \tt{m \angle2 = (7x + 1) \degree}} \\ { \tt{m \angle2 = (7 \times 7) + 1}} \\ { \bf{m \angle2 = 50 \degree}}[/tex]
Answer:
m∠2 = 50
Step-by-step explanation:
7x + 1 and 18x + 4 are angles in a linear pair.
Sum of linear pair angles is supplementary.
7x + 1 + 18x + 4 = 180
7x + 18x + 1 + 4 = 180
25x + 5 = 180
25x = 180 - 5
25x = 175
x = 175 / 25
x = 7
Substitute x = 7 in 7x + 1,
7x + 1
= 7 ( 7 ) + 1
= 49 + 1
= 50
7x + 1 and ∠2 are vertically opposite angles and vertically opposite angles are equal.
∠2 = 7x + 1
∠2 = 50
what is the product of the prime factors of 24
Answers
Answer:
So the prime factorization of 24 is 24 = 2 · 2 · 2 · 3 = 23 · 3. A good way to check the result is to multiply it out and make sure the product is 24.
Step-by-step explanation:
(A) Given that the expression x^3-ax^2+bx+c leaves the same remainder when divided by x+1 or x-2, find a in term of b.
(B) (2x-1)^3+6(3+4x^2) is divided by 2x+1.
Answer those two question please. I need it quickly. No silly answers would not be allowded.
Answers
Hello,
A:
[tex]\begin{array}{c|ccc|c}&x^3&x^2&x&1\\&1&-a&b&c\\x=-1&&-1&a+1&-a-b-1\\---&---&---&---&---\\&1&-a-1&a+b+1&-a-b+c-1\\\end{array}\\\\\\\begin{array}{c|ccc|c}&x^3&x^2&x&1\\&1&-a&b&c\\x=2&&2&-2a+4&-4a+2b+8\\---&---&---&---&---\\&1&-a+2&-2a+b+4&-4a+2b+c+8\\\end{array}\\\\\\\\-a-b+c-1=-4a+2b+c+8\\\\\boxed{b=a-3}\\[/tex]
B:
[tex](2x-1)^3+6(3+4x^2)\\\\=8x^3-12x^2+6x-1+18+24x^2\\\\=8x^3+12x^2+6x+17\\\\\\\begin{array}{c|ccc|c}&x^3&x^2&x&1\\&8&12&6&17\\x=-\dfrac{1}{2} &&-4&-4&-1\\---&---&---&---&---\\&8&8&2&16\\\end{array}\\\\\\(2x-1)^3+6(3+4x^2)=(2x+1)(4x^2+4x+1)+16[/tex]
Situation:
Find the age of
A student in Greece discovers a pottery
bowl that contains 28% of its original
amount of C-14.
Ent
N= Noekt
No
= inital amount of C-14 (at time
t = 0)
N = amount of C-14 at time t
k = 0.0001
t = time, in years
Answers
Answer:
Step-by-step explanation:
I'm assuming you need the age of the bowl. Start with the fact that you have remaining 28% of the original amount before any of it decayed. You always start with 100% of something unless you're told differently. That means that the equation looks like this:
[tex]28=100e^{-.0001t}[/tex] and begin by dividing both sides by 100 to get
[tex].28=e^{-.0001t}[/tex] . To solve for t we have to be able to bring it down from its current position of exponential. To do this we would either take the log or the natural log since the rules for both are the same. However, the natural log is the inverse of e, so they undo each other. We take the natural log of both sides which allows us to pull down the -.0001t. At the same time remember that the natural log and e are inverses of each other so they are both eliminated when we do this.
ln(.28) = -.0001t Now it's easy to solve for t.
[tex]\frac{ln(.28)}{-.0001}=t[/tex] and
[tex]\frac{-1.272965676}{-.0001}=t[/tex] so
t = 12729.65676 years or rounded, 12730 years.
find the distance between the points (-3,-2) and (1,-5)
Answers
The prime factorization of K is: K = 3x5x7. List all the composite factors of K.
Answers
Answer:
15, 21, 35, 105
Step-by-step explanation:
A composite number is a positive integer that has more than two different factors. For example, composite number include 4, 6, 8, 9, 10, 12, 14, 15, 16, 18...etc.
So, if we multiply 3x5x7=105
All the factors of 105 are 1, 3, 5, 7, 15, 21, 35, 105. So we just need to figure out the factors that are composite which are
15, 21, 35, 105
The list all the composite factors of K : 15, 21, 35, 105
What is prime integer?"It is an integer that has only two different factors 1 and that integer itself."
What is prime factorization of a number?"It is a method to find the prime factors of a given number."
What is composite integer?"It is an integer that has more than two different factors. "
For given question,
The prime factorization of K is:
K = 3 × 5 × 7
This means the number K is, 3 × 5 × 7 = 105
The factors of 105 are: 1, 3, 5, 7, 15, 21, 35, 105.
We need to list all the composite factors of K.
From above factors of 105 we can observe that,
15 has factors 1, 3, 5, 15;
21 has factors 1, 3, 7, 21;
35 has factors 1, 5, 7, 35;
and 105 has more than two factors factors as mentioned above.
This means, the numbers 15, 21, 35 and 105 are composite numbers.
Therefore, the list all the composite factors of K : 15, 21, 35, 105
Learn more about the prime factorization of number here:
https://brainly.com/question/22692933
#SPJ2
if the measure of angle def is 65° what is the measure of arc de?
Answers
EF is tangent to the circle we'll assume; otherwise there's no progress.
Call the center C. ECD is isosceles, formed from two radii and the chord.
Angle CED is complementary to DEF
CED = 90 - 65 = 25 degrees
CDE is congruent, isosceles triangle and all that: CDE=25
That leaves DCE=180-25-25=130 degrees
That's the measure of arc DE as well:
Answer: 130 degrees, choice A
Answer:
130
Step-by-step explanation:
If < A and < B are vertical angles, and < A is 43 ° , then what is the measure of < B?
Select one:
a. 47 °
b. 137 °
c. 21 °
d. 43 °
Answers
Answer:
d
Step-by-step explanation:
vertical angles are congruent , so
∠ B = ∠ A = 43°
Class 3 question ,pls help
Answers
Answer:
bigger number minus larger number plus 1
430-421 = 9 + 1 = 10
573 - 567 = 6+1 = 7
898 - 890 = 8+ 1 = 9
Step-by-step explanation:
Johnny asks you to guess the specific coins he has in his pocket if he has $3.70 in change. You say you need a little
more information, to guess. So he tells you all he has is quarters and dimes and that he has 22 colns in all.
Answers
Answer:
10 quarters and 12 dimes :)
Step-by-step explanation:
what is the percentage of 690 out of 800
Answers
Answer:
the percentage of 690 out of 800 is 86.25%
Step-by-step explanation:
690/800 = 0.8625
0.8625*100 = 86.25
hope it helped :)
mark me brainliest
Answer:
86.25%
Step-by-step explanation:
1. Students were surveyed and asked if they play lacrosse and/or football. The results are shown below.
What percent of football players also play lacrosse?
Answers
36%
Step-by-step explanation:
28 + 16 = 44 Football players
Of those, 16 are on the lacrosse team.
16 / 44 × 100 = 36.36% (We round to 36%)
To verify:
44 × 36.36% = 15.84 (Which we can round to 16)
Pardon me if it's wrong
given that O is the center of the circle, find the measure of angle BAC of arc DC = 120
Answers
Answer:
30 degrees.
Step-by-step explanation:
DC is given as 120, so start off by finding arc BC.
180-120= Semicircle-DC=60.
BC=60.
Inscribed angles are half of their arcs.
60/2=30.
The number of strokes in which a hole is designed to be played. [ Choose ] The person who is farthest away from the hole is said to have _____.
Answers
Answer:
the answer is more strokes since the farther away you are the more strokes it takes
Hope This Helps!!!
Which equation could be used to solve for the value of n if n + 2 = 6?
O2 + 6 = n
O 2-6 =n
O 6 +2=n
06-2=n
Answers
d
Step-by-step explanation:
6-2=n will be used because when 2 goes to other side then positive sign turns to negative sign
Evidencia de aprendizaje Se desea obtener 80 kilogramos de café molido mezclando café arábico de S/18 el kilogramo y café torrado de S/10 el kilogramo. Si se quiere que el precio del kilogramo de mezcla sea de S/13, ¿Qué cantidad de café de S/18 debe usar? Responde las siguientes preguntas: ¿Qué estrategias utilicé para validar la solución al sistema de ecuaciones? ¿Para qué me servirá lo que aprendí?, ¿Qué dificultades encontraron en este aprendizaje? A partir de la situación planteada ¿A qué conclusión puedo llegar?
Answers
Answer:
50kg de café torrado
30kg de café arábico
Step-by-step explanation:
Queremos obtener un total de 80kg de café molido.
Se utilizarán:
Café arábico, que cuesta $18 el kg
Café torrado, que cuesta $10 el kg
Queremos que el precio, por kilo, de la mezcla de 80kg sea $13.
Ok, primero debemos definir las variables:
Definamos:
x = cantidad de café arábico usado
y = cantidad de café torrado usado.
Entonces, como la mezcla deberá tener 80kg en total, tenemos:
x + y = 80kg
Y el costo total de esta mezcla será:
x*$18 + y*$10
Si lo dividimos por el peso total, tendremos el costo por kilo, que es:
(x*$18 + y*$10)/80kg
Y queremos que esto sea igual a $13, entonces tenemos la ecuación
(x*$18 + y*$10)/80kg = $13
Ok, ahora tenemos dos ecuaciones, es decir, tenemos un sistema de ecuaciones:
x + y = 80kg
(x*$18 + y*$10) = $13*80kg
(donde reescribimos levemente la segunda ecuación)
Ok, para resolver este sistema trataremos de reemplazar variables, para ello, el primer paso es aislar una de las variables en una de las ecuaciones.
Aislemos x en la primera:
x = 80kg - y
Ahora reemplazamos esto en la otra ecuación:
(x*$18 + y*$10) = $13*80kg
(( 80kg - y)*$18 + y*$10) = $13*80kg
Ahora podemos resolver esto para la variable y:
$18*80kg - $18*y + $10*y = $13*80kg
$18*80kg - $13*80kg = $18*y - $10*y
($18 - $13)*80kg = ($18 - $10)*y
$5*80kg = $8*y
($5*80kg)/$8 = y
50kg = y
Se usan 50kg de café torrado.
y como:
x + y = 80kg
x = 80kg - y
x = 80kg - 50kg = 30kg
Entonces los 30kg restantes serán de café arábico.
y la estrategia utilizada fue el remplazo de variables.
