A milk truck carries milk with density 64.6 lb/ft3 in a horizontal cylindrical tank with diameter 8 ft.
(a) Find the force exerted by the milk on one end of the tank when the tank is full. (Round your answer to the nearest integer.) lb
(b) What if the tank is half full?

Answer:

Volume of cone = 686π/3 or 718.67 in³

Step-by-step explanation:

Given the following data;

Radius, r = 7 in

Height, h = 14 inches

From the diagram, we can see that the object is a cone

To find the volume of a cone;

Mathematically, the volume of a cone is given by the formula;

[tex] V = \frac{1}{3} \pi r^{2}h[/tex]

Where;

V is the volume of the cone.

r is the radius of the base of the cone.

h is the height of the cone.

Substituting into the equation, we have;

[tex] Volume = \frac{1}{3} * \frac {22}{7} *7^{2}*14 [/tex]

[tex] Volume = \frac{1}{3} * 22 * 7 * 14 [/tex]

[tex] Volume = \frac{1}{3} * 2156 [/tex]

[tex] Volume = 718.67 [/tex]

Volume of cone = 718.67 in³ or 686π/3 in³

9514 1404 393

Answer:

  448

Step-by-step explanation:

(4 pt/da)×(7 da/wk)×(16 oz/pt) = 448 oz/wk

That would be 448 fluid ounces per week.

Answer:

[tex]x^2 + y^2 = 52[/tex]

Step-by-step explanation:

Distance between two points:

Suppose that we have two points, [tex](x_1,y_1)[/tex] and [tex](x_2,y_2)[/tex]. The distance between them is given by:

[tex]D = \sqrt{(x_2-x_1)^2+(y_2-y_1)^2}[/tex]

Equation of a circle:

The equation of a circle with center [tex](x_0,y_0)[/tex] and radius r has the following format:

[tex](x - x_0)^2 + (y - y_0)^2 = r^2[/tex]

Center at the origin;

This means that [tex]x_0 = 0, y_0 = 0[/tex]

So

[tex](x - x_0)^2 + (y - y_0)^2 = r^2[/tex]

[tex](x - 0)^2 + (y - 0)^2 = r^2[/tex]

[tex]x^2 + y^2 = r^2[/tex]

Passes through (4, 6)

The radius is the distance from this point to the center. So

[tex]r = \sqrt{(x_2-x_1)^2+(y_2-y_1)^2}[/tex]

[tex]r = \sqrt{(4-0)^2+(6-0)^2}[/tex]

[tex]r = \sqrt{16+36}[/tex]

[tex]r = \sqrt{52}[/tex]

So

[tex]r^2 = 52[/tex]

Then

[tex]x^2 + y^2 = r^2[/tex]

[tex]x^2 + y^2 = 52[/tex]

9514 1404 393

Answer:

  4

Step-by-step explanation:

In order to evaluate f(g(-1)), you first need to find g(-1).

The graph of g(x) crosses the line x = -1 at y = 1, so g(-1) = 1.

The second step is evaluating f(1). The graph of f(x) crosses the line x=1 at y=4, so f(1) = 4.

  f(g(-1)) = f(1) = 4

Answer:

11. (a) 3/4+1/2=5/4

   (b) 4/5= 8/10 , 16/20

12. 8 children don't like choc ice cream

Step-by-step explanation:

11. 3/4 +2/4=5/4(change 1/2 by making it the same as the one next to it)

12. 3/5 of 20 = 12

     20-12=8

Answer:

wat

Step-by-step explanation:

Answer:

Step-by-step explanation:

Answer:

$1080

Step-by-step explanation:

I think I am not sure

Answer:

433 in.²

Step-by-step explanation:

Divide the figure into 2 rectangles

Area of the figure = area of the bigger rectangle + area of smaller rectangle

✔️Area of bigger rectangle = L*W

L = 29 in.

W = 13 in.

Area of the bigger rectangle = 29*13

= 377 in.²

✔️Area of the smaller rectangle = L*W

L = 7 in.

W = 8 in.

Area of the bigger rectangle = 7*8

= 56 in.²

✅Area of the figure = 377 + 56 = 433 in.²

midpoint= (x, y)

where x=(x1 + x2)/2

y=(y1 + y2)/2

x1=-3, x2=6, y1=5, y2=-11

so x=(-3 + 6)/2= 3/2

y=(5 + -11)/2= (5-11)/2= -6/2= -3

so mid point =(3/2, -3)

hope this helps

Answer:

3/2

Step-by-step explanation:

Slope 1 = (-1+7)/(-5-4) = 6/(-9) = -2/3

Slope 2 perpendicular to Slope 1 :

-1 ÷ -⅔ = 3/2

Answer:

surface area of the triangular pyramid

=(1/2×9×7.8)+(3×1/2×9×12.3)

=35.1+166.05

=201.15 inch²

Answer:

x = 4

Step-by-step explanation:

180 = 102 + 24x - 18

mid point =((4+(-4))/2,(-5+5)/2)

=(0,0)

The midpoint between the points (4, -5) and (-4, 5) is (0, 0).

To find the midpoint between two points ([tex]x_1, y_1[/tex]) and ([tex]x_2, y_2[/tex]), you can use the midpoint formula:

Midpoint = [tex]((x_1+ x_2)/2, (y_1+ y_2)/2)[/tex]

In this case, the two points are (4, -5) and (-4, 5).

So, the midpoint using the formula:

[tex]x_1[/tex] = 4

[tex]y_1[/tex] = -5

[tex]x_2[/tex]= -4

[tex]y_2[/tex] = 5

Midpoint

= ((4 + (-4)) / 2, (-5 + 5) / 2)

= (0 / 2, 0 / 2)

= (0, 0)

Therefore, the midpoint between the points (4, -5) and (-4, 5) is (0, 0).

Learn more about midpoint here:

https://brainly.com/question/24089949

#SPJ2

Answer:

5 overtime hours

Step-by-step explanation:

Given that :

Pay per hour = 240

Overtime pay = 1 1/2 * pay per hour = 1 1/2 * 240 = 360 per hour

Amount earned for the week = 11400

Let overtime hours = x

Total hours worked = 40 + x

Earning for the week based on hours worked :

240(40) + 360x = 11400

9600 + 360x = 11400

360x = 1800

x = 1800 / 360

x = 5 hours

Answer:

p-value = 0.0145

Hence, Since p-value ( 0.0145 ) is less than significance level ( 0.05 )

we reject null hypothesis.

Therefore, there is sufficient evidence to conclude that Car accidents are NOT equally distributed throughout the year

Step-by-step explanation:

Given the data in the question;

Hypothesis;

Null hypothesis             : H₀ : Car accidents are equally distributed throughout the year

Alternative hypothesis : Hₐ : Car accidents are NOT equally distributed throughout the year

significance level ∝ = 0.05

x ;

Spring = 27

Summer = 39

Fall = 31

Winter = 53

Test Statistics;

Chi Square = ∑[ (O – E)²/E ]

                         O               E                   (O – E)²/E

Spring               27            37.4                2.94

Summer            39            37.4                0.06

Fall                    31             37.4                1.1267

Winter               53            37.4                6.4067

Total                 150           150                 10.5334

so; z = ∑[ (O – E)²/E ] = 10.5334

{from table}

p-value = 0.0145

Hence, Since p-value ( 0.0145 ) is less than significance level ( 0.05 )

we reject null hypothesis.

Therefore, there is sufficient evidence to conclude that Car accidents are NOT equally distributed throughout the year

In this exercise we have to use probability knowledge to calculate the distribution during the year, so we find that:

There is sufficient evidence to conclude that car accidents are not equally distributed throughout the year.

Given the data in the question;

Now the values ​​given in the statement can be exemplified below as:

In this way, we can assemble a table of values ​​with the statistical data previously informed and using the formula given below:

[tex]Z=\sum[\frac{(O-E)^2}{E}][/tex]

[tex]Z = 10.5334[/tex]

So:

[tex]\ \ \ \ \ \ \ \ \ \ \ O \ \ \ \ \ E \ \ \ \ (O - E)^2/E\\Spring \ \ 27 \ \ 37.4 \ \ \ \ 2.94\\Summer \ 39 \ 37.4 \ \ \ \ 0.06\\Fall \ \ \ \ \ \ 31 \ 37.4 \ \ \ \ 1.1267\\Winter \ \ \ 53 \ 37.4 \ \ \ 6.4067\\Total \ 150 150 \ 10.5334[/tex]

Hence, Since pvalue ( 0.0145 ) is less than significance level ( 0.05 ), so we reject null hypothesis.

See more about probability at brainly.com/question/795909

That is the same as writing [tex]10\sqrt{30}[/tex]

======================================================

Explanation:

The diagram shows that

That must mean DC = AC-AD = 60-50 = 10

We'll use this to help find BD as shown below

AD/BD = BD/DC

AD*DC = BD*BD .... cross multiply

(BD)^2 = AD*DC

BD = sqrt(AD*DC) ..... geometric mean formula

BD = sqrt(50*10)

BD = sqrt(500)

----------------------

Now apply the pythagorean theorem to find AB. Focus on triangle ABD.

(AD)^2 + (BD)^2 = (AB)^2

(AB)^2 = (AD)^2 + (BD)^2

(AB)^2 = (50)^2 + (sqrt(500))^2

(AB)^2 = 2500 + 500

(AB)^2 = 3000

AB = sqrt(3000)

AB = sqrt(100*30)

AB = sqrt(100)*sqrt(30)

AB = 10*sqrt(30)

Answer:

Step-by-step explanation:

From the given information:

ΔG° = -30.5 kJ/mol

By applying the following equation to calculate the value of K.

ΔG° =-RT㏑K

making ㏑ K  the subject of the formula:

[tex]\mathtt{ In \ K} = \dfrac{\Delta G^0}{-RT}[/tex]

where;

Temperature at 25° C = (25 + 273)K

= 298K

R = 8.3145 J/mol.K (gas cosntant)

[tex]\mathtt{ In \ K} = \dfrac{-30.5 \times 10^{3}\ J /mol} {-(8.3145 \ J/mol. K \times 298 \ K}[/tex]

[tex]\mathtt{ In \ K} = \dfrac{-30.5 \times 10^{3}\ J /mol} {-2477.721 J/mol }[/tex]

㏑K = 12.309

[tex]K = e^{12.309}[/tex]

K = 221682.17

K = 2.22 × 10⁵

b) The reaction for the metabolism of glucose is given as:

[tex]C_6H_{12} O_6 + 6O_{2(g)} \to + 6CO_{2(g)} + 6H_2O_{(l)}[/tex]

From the above expression, let calculate the Gibbs free energy by using the formula:

[tex]\Delta G^0_{rx n }= \Delta G^0_{product}- \Delta G^0_{reactant}[/tex]

[tex]\Delta G^0_{rx n }= [6 \times \Delta G^0_{f}(CO_2) + 6 \times \Delta G^0_{f}(H_2O)] - [1 \times \Delta G^0_{f}(C_6H_{12}O_6) + 6 \times \Delta G^0_{f}(O_2)][/tex]

At standard conditions;

The values of corresponding compounds are substituted into the equation above:

Thus,

[tex]\Delta G^0_{rx n }= [6 \times (-394) + 6 \times (-237)] - [1 \times (-911) + 6 \times (0)] \ kJ/mol[/tex]

[tex]\Delta G^0_{rx n }= [-2364-1422] - [-911+0] \ kJ/mol[/tex]

[tex]\Delta G^0_{rx n }= -3786 +911 \ kJ/mol[/tex]

[tex]\Delta G^0_{rx n }= -2875 \ kJ/mol[/tex]

[tex]\Delta G^0_{rx n }= -2875000 \ J/mol[/tex]

Now, the no of ATP molecules generated = [tex]\dfrac{\Delta G^0 \text{of metabolism for glucose}}{\Delta G^0 \text{of hydrolysis for ATP}}[/tex]

= (-2875000 J/mol ) / -30500 J/mol

= 94.26

≅ 94 ATP molecules generated

Try this option, the answer is marked with red colour.

Answer:

The Answer to the Ultimate Question of Life, the Universe, and Everything is 42

Step-by-step explanation:

In this equation, the number 42 is called a minuend.

15 is a subtrahend because it is being subtracted from another number.

The number 27 would be called the difference.

Answer: The company will recognize commission expense in the amount of $2,400 in December

Step-by-step explanation:

Based on the information given in the question, the company will recognize commission expense in the amount of $2,400 in December.

A commission is regarded as a fee which is paid to a salesperson by a company in exchange for completing a sale.

It should be noted that in the accrual basis of accounting, commission should be recorded in the same period as when the sale generated was generated.

Answer:

b. The company will recognize commission expense in the amount of $2,400 in December.

Step-by-step explanation:

Based on the information given the statements that is true will be: THE COMPANY WILL RECOGNIZE COMMISSION EXPENSE IN THE AMOUNT OF $2,400 IN DECEMBER reason been that each salesperson were paid a commission in the amount of $800 for each cycle sold, which is 3 cycles during the month of December.

Calculation to determine the Commission Expense

Commission Expense=$800*3 cycles

Commission Expense=$2,400

Therefore The company will recognize commission expense in the amount of $2,400 in December.

Answer:

−7.361097448

Step-by-step explanation:

Step-by-step explanation:

the other answer is correct.

just for a little bit of explanation :

the first position after the decimal point is for tenths. the second position for hundredths. the third for thousandths. then ten-thousandths, hundred-thousandths, millionths, ...

so, you would need 1000 thousandths to have a 1 at the first position before the decimal point. everything less than that has to be a number after the decimal point. and thousandths have to end (writing from left to right) with the thousandths-position. hundredths with the hundredths-position and so on.

Answer:

h(t) = -16t2 + 186t + 43

at the ground h = 0

hence;  -16t2 + 186t + 43 = 0  

solving this quadratic equation using the quadratic formula ; a = -16, b = 186, c = 43 ; x = (-b +-(b2 - 4ac)1/2)/2a

gives t = 11.8 seconds to the nearest tenth (note that the negative root has no practical significance)

Step-by-step explanation:

Answer:

55 chairs

Step-by-step explanation:

825/15=55

i think the correct answer is 2 hours and 10 mins

Answer:

[tex]\sqrt{x^2 + y^2}[/tex]

Step-by-step explanation:

to find diatance between AB

A(0 , 0) = (x1 , y1)

B(x , y) = (x2 , y2)

distance formula = [tex]\sqrt{(x2 - x1)^2 + (y2 - y1)^2}[/tex]

=[tex]\sqrt{(x - 0)^2 + (y - 0)^2}[/tex]

=[tex]\sqrt{x^2 + y^2}[/tex]

Answer:

21.161

Step-by-step explanation:

use Pythagoras theorem ti find your slant height

then you use your formula which

[tex]1 \3\pi {r }^{2} h[/tex]