A macaroni and cheese recipe calls for 2/5 of a 2 1/2 pound a block of cheese. How many pounds are needed?​

Answer:

A

Step-by-step explanation:

the function for this graph is:

[tex]y = {(x - 1)}^{2} [/tex]

so the domain (the input AKA THE x values) is all the real numbers.

Answer:

46,000 yards

Step-by-step explanation:

if in the hundreds place the number is 0-499 round down

if it's 500-999 round up

9514 1404 393

Answer:

  (b)  x = 1

Step-by-step explanation:

A graph shows the solution to f(x) = g(x) is x = 1.

__

We want to solve ...

  g(x) -f(x) = 0

  x^3 +2x^2 -x -2 -(-11/3x +11/3) = 0

  x^2(x +2) -1(x +2) +11/3(x -1) = 0 . . . . . factor first terms by grouping

  (x^2 -1)(x +2) +11/3(x -1) = 0 . . . . .  . the difference of squares can be factored

  (x -1)(x +1)(x +2) +(x -1)(11/3) = 0 . . . . we see (x-1) is a common factor

  (x -1)(x^2 +3x +2 +11/3) = 0

The zero product rule tells us this will be true when x-1 = 0, or x = 1.

__

The discriminant of the quadratic factor is ...

  b^2 -4ac = 3^2 -4(1)(17/3) = 9 -68/3 = -41/3

This is less than zero, so any other solutions are complex.

Answer:

Kindly check explanation

Step-by-step explanation:

Rounding each number to 4 significant figures and expressing in standard notation :

(a) 102.53070,

Since the number starts with a non-zero, the 4 digits are counted from the left ;

102.53070 = 102.5 (4 significant figures) = 1.025 * 10^2

(b) 656.980,

Since the number starts with a non-zero, the 4 digits are counted from the left ; the value after the 4th significant value is greater than 5, it is rounded to 1 and added to the significant figure.

656.980 = 657.0 (4 significant figures) = 6.57 * 10^2

(c) 0.008543210,

Since number starts at 0 ; the first significant figure is the first non - zero digit ;

0.008543210 = 0.008543 (4 significant figures) = 8.543 * 10^-3

(d) 0.000257870,

Since number starts at 0 ; the first significant figure is the first non - zero digit ;

0.000257870 = 0.0002579 (4 significant figures) = 2.579 * 10^-4

(e) -0.0357202,

Since number starts at 0 ; the first significant figure is the first non - zero digit ;

-0.0357202 = - 0.03572 (4 significant figures) = - 3.572* 10^-2

Answer:

Read below

Step-by-step explanation:

I would guess based on measurement because I would do the following.

3 1/4 x 3 1/4 = 10 9/16

10 9/16 x 3 = 31 11/16

Hope it helps c:

Answer:

5/4

Step-by-step explanation:

Use the slope formula which is y2-y1/x2-x1.

1. Plug the given values into the equation: 3-(-7)/4-(-4)=5/4

Answer:

(w^3)^8 * (w^5)^5 = w^49

Step-by-step explanation:

(w^24) * (w^25)

using exponent rule

w^24 • w^25 = w^24+25

w^49

Answer:

Step-by-step explanation:

(W^24)*(W^25)

W^24+25

=W^49

Answer:

4

Step-by-step explanation:

2x - (4y - 3) + 5xz

Let  x = -3, y = 2, and z = ‐1.

2(-3) -( 4(2) -3) +5(-3)(-1)

-6 - (8-3) +15

-6 - 5 +15

-11 +15

4

Answer:

0.01375 = 1.375% probability that the number of lost-time accidents occurring over a period of 10 days will be no more than 2.

Step-by-step explanation:

We have the mean during the interval, which means that the Poisson distribution is used.

Poisson distribution:

In a Poisson distribution, the probability that X represents the number of successes of a random variable is given by the following formula:

[tex]P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}[/tex]

In which

x is the number of sucesses

e = 2.71828 is the Euler number

[tex]\mu[/tex] is the mean in the given interval.

Lost-time accidents occur in a company at a mean rate of 0.8 per day.

This means that [tex]\mu = 0.8n[/tex], in which n is the number of days.

10 days:

This means that [tex]n = 10, \mu = 0.8(10) = 8[/tex]

What is the probability that the number of lost-time accidents occurring over a period of 10 days will be no more than 2?

This is:

[tex]P(X \leq 2) = P(X = 0) + P(X = 1) + P(X = 2)[/tex]

In which

[tex]P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}[/tex]

[tex]P(X = 0) = \frac{e^{-8}*8^{0}}{(0)!} = 0.00034[/tex]

[tex]P(X = 1) = \frac{e^{-8}*8^{1}}{(1)!} = 0.00268[/tex]

[tex]P(X = 2) = \frac{e^{-8}*8^{2}}{(2)!} = 0.01073[/tex]

So

[tex]P(X \leq 2) = P(X = 0) + P(X = 1) + P(X = 2) = 0.00034 + 0.00268 + 0.01073 = 0.01375[/tex]

0.01375 = 1.375% probability that the number of lost-time accidents occurring over a period of 10 days will be no more than 2.

Answer:

16%

Step-by-step explanation:

$31 - $25 = 6

100/6 = 16.66666667

Answer:

24%

Step-by-step explanation:

Using the formula below, you can plug in the numbers and use PEMDAS.

(31 - 25)

-----------    x 100

   25

 6

-----  =  0.24

 25

0.24 x 100 = 24

The answer is 24%

Answer:

-36/7

Step-by-step explanation:

-22-14=6x+x

-36=7x

-36/7=7x/7

x=-36/7

Answer:

Orthocenter would be in the middle of the shape.

Step-by-step explanation:

B.

Answer:

Graph (a)

Step-by-step explanation:

Given

[tex]y = \sqrt[3]{x+ 6} -3[/tex]

Required

The graph

First, calculate y, when x = 0

[tex]y = \sqrt[3]{0+ 6} -3[/tex]

[tex]y = \sqrt[3]{6} -3[/tex]

[tex]y = -1.183[/tex]

The above value of y implies that the graph is below the origin when x = 0. Hence, (c) and (d) are incorrect because they are above the origin

Also, only the first graph passes through point (0,-1.183). Hence, graph (a) is correct

Answer:

the answer is A

Step-by-step explanation:

Answer:

b

Step-by-step explanation:

Answer:

[tex]\mathbb{R} \backslash \displaystyle \left\lbrace \left. \frac{1}{23}\, \left(k\, \pi + \frac{\pi}{2}\right) \; \right| k \in \mathbb{Z} \right\rbrace[/tex].

In other words, the [tex]x[/tex] in [tex]f(x) = 3\, \tan(23\, x)[/tex] could be any real number as long as [tex]x \ne \displaystyle \frac{1}{23}\, \left(k\, \pi + \frac{\pi}{2}\right)[/tex] for all integer [tex]k[/tex] (including negative integers.)

Step-by-step explanation:

The tangent function [tex]y = \tan(x)[/tex] has a real value for real inputs [tex]x[/tex] as long as the input [tex]x \ne \displaystyle k\, \pi + \frac{\pi}{2}[/tex] for all integer [tex]k[/tex].

Hence, the domain of the original tangent function is [tex]\mathbb{R} \backslash \displaystyle \left\lbrace \left. \left(k\, \pi + \frac{\pi}{2}\right) \; \right| k \in \mathbb{Z} \right\rbrace[/tex].

On the other hand, in the function [tex]f(x) = 3\, \tan(23\, x)[/tex], the input to the tangent function is replaced with [tex](23\, x)[/tex].

The transformed tangent function [tex]\tan(23\, x)[/tex] would have a real value as long as its input [tex](23\, x)[/tex] ensures that [tex]23\, x\ne \displaystyle k\, \pi + \frac{\pi}{2}[/tex] for all integer [tex]k[/tex].

In other words, [tex]\tan(23\, x)[/tex] would have a real value as long as [tex]x\ne \displaystyle \frac{1}{23} \, \left(k\, \pi + \frac{\pi}{2}\right)[/tex].

Accordingly, the domain of [tex]f(x) = 3\, \tan(23\, x)[/tex] would be [tex]\mathbb{R} \backslash \displaystyle \left\lbrace \left. \frac{1}{23}\, \left(k\, \pi + \frac{\pi}{2}\right) \; \right| k \in \mathbb{Z} \right\rbrace[/tex].

Answer:

1 / 97290

Step-by-step explanation:

The number of ways of selecting 3 specific route capitals from 47 states can be obtained thus :

Probability = required outcome / Total possible outcomes

Total possible outcomes = 47P3

Recall :

nPr = n! / (n-r)!

47P3 = 47! / (47-3)! = 47! / 44! = 97290

Hence, probability of selecting route if 3 specific capitals is = 1 / 97290

Answer:

Its quantitive cause its giving a number and quantity/quantitive is for numbers

Answer:

The data is quantitative (because it is asking for measurement or numbers).

Step-by-step explanation:

The second and third I'm not sure how to answer, however,

"A discrete function is a function with distinct and separate values. This means that the values of the functions are not connected with each other. For example, a discrete function can equal 1 or 2 but not 1.5. A continuous function, on the other hand, is a function that can take on any number within a certain interval. For example, if at one point, a continuous function is 1 and 2 at another point, then this continuous function will definitely be 1.5 at yet another point. A continuous function always connects all its values while a discrete function has separations. Now, let's look at these two types of functions in detail."

Hope this helps :)

Answer:

p - 2q and p - 3q

Step-by-step explanation:

A Series is given to us and we need to find the next two terms of the series . The given series to us is ,

[tex]\rm\implies Series = p+q , p , p - q [/tex]

Note that when we subtract the consecutive terms we get the common difference as "-q" .

[tex]\rm\implies Common\ Difference = p - (p + q )= p - p - q =\boxed{\rm q}[/tex]

Therefore the series is Arithmetic Series .

Arithmetic Series:- The series in which a common number is added to obtain the next term of series .

And here the Common difference is -q .

Fourth term :-

[tex]\rm\implies 4th \ term = p - q - q = \boxed{\blue{\rm p - 2q}}[/tex]

Fifth term :-

[tex]\rm\implies 4th \ term = p - 2q - q = \boxed{\blue{\rm p - 3q}}[/tex]

Therefore the next two terms are ( p - 2q) and ( p - 3q ) .

Answer:

Increasing a number by 5% and then by 20% is the same as increasing the original number by 26%.

Step-by-step explanation:

Take a number, x.

Now increase it by 5%.

1.05x

Now increase it by 20%.

1.2 * 1.05x = 1.26x

1.26x = 126% of x = 100% of x + 26% of x

100% of x is the same as x, so it is the same as the original x.

The increase is 26% of the original number.

Increasing a number by 5% and then by 20% is the same as increasing the original number by 26%.

Step-by-step explanation:

50-20=30 rate of markup

Answer:

12

Step-by-step explanation:

Answer:

The expected value for an event with outcomes:

{x₁, x₂, ..., xₙ}

Each one with probability:

{p₁, p₂, ..., pₙ}

Is just:

Ev = x₁*p₁ + ... + xₙ*pₙ

here we have two outcomes:

x₁ = the object worths $25

x₂ = the object is worth $4.

Each one with probability p₁ and p₂ respectively, such that:

p₁ + p₂ = 1

Then the expected value is:

Ev = p₁*($25) + p₂*($4)

Now we want to know how should be the probabilities, such that buying the object for $16 is whort.

Well, the purchase will be whort if the expected value is larger than $16.

This is equivalent to:

p₁*($25) + p₂*($4) - $16 > $0

Knowing that:

p₁ + p₂ = 1

we can rewrite:

p₂ = 1 - p₁

replacing that in the above inequality we get:

p₁*($25) + ( 1 - p₁)*($4) - $16 > $0

Now we can solve this for p₁

p₁*($25 - $4) + $4 - $16 > $0

p₁*$21 - $12 > $0

p₁*$21 > $12

p₁ > $12/$21 = 0.571

The probability of the object being authentic should be larger than  0.571 to take the gamble.

Answer:

4(a).

Expression of dy/dx :

[tex]{ \tt{ \frac{dy}{dx} = - 2(3 - 2x) {}^{2} + 24}}[/tex]

5(a).

[tex]{ \tt{ \frac{dy}{dx} = 54 - 2(2x - 7) {}^{2} }}[/tex]

Answer:

4a^2 x for a = − 2, x = −4

Step-by-step explanation:

4a^2 x for a = − 2, x = −4

Answer:

0.2405 = 24.05% probability that the sample proportion of households spending more than $125 a week is less than 0.31.

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal Probability Distribution

Problems of normal distributions can be solved using the z-score formula.

In a set with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the z-score of a measure X is given by:

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem establishes that, for a normally distributed random variable X, with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean [tex]\mu[/tex] and standard deviation [tex]s = \frac{\sigma}{\sqrt{n}}[/tex].

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

For a proportion p in a sample of size n, the sampling distribution of the sample proportion will be approximately normal with mean [tex]\mu = p[/tex] and standard deviation [tex]s = \sqrt{\frac{p(1-p)}{n}}[/tex]

Assume the population proportion is 0.34 and a simple random sample of 124 households is selected from the population.

This means that [tex]p = 0.34, n = 124[/tex]

Mean and standard deviation:

[tex]\mu = p = 0.34[/tex]

[tex]s = \sqrt{\frac{0.34*0.66}{124}} = 0.0425[/tex]

What is the probability that the sample proportion of households spending more than $125 a week is less than 0.31?

This is the p-value of Z when X = 0.31, so:

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

[tex]Z = \frac{0.31 - 0.34}{0.0425}[/tex]

[tex]Z = -0.705[/tex]

[tex]Z = -0.705[/tex] has a p-value of 0.2405.

0.2405 = 24.05% probability that the sample proportion of households spending more than $125 a week is less than 0.31.

Answer:

0.0475 = 4.75% probability that a randomly selected complaint takes more than 15 minutes to be settled.

Step-by-step explanation:

Normal Probability Distribution

Problems of normal distributions can be solved using the z-score formula.

In a set with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the z-score of a measure X is given by:

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

Mean of 10 minutes and a standard deviation of 3 minutes

This means that [tex]\mu = 10, \sigma = 3[/tex]

Find the probability that a randomly selected complaint takes more than 15 minutes to be settled.

This is 1 subtracted by the p-value of Z when X = 15, so:

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

[tex]Z = \frac{15 - 10}{3}[/tex]

[tex]Z = 1.67[/tex]

[tex]Z = 1.67[/tex] has a p-value of 0.9525.

1 - 0.9525 = 0.0475.

0.0475 = 4.75% probability that a randomly selected complaint takes more than 15 minutes to be settled.

9514 1404 393

Answer:

  476 +598 = 1074

Step-by-step explanation:

In order for the sum to be smallest, the two most-significant digits must be the smallest possible. That is, they must be 4 and 5.

The two least-significant digits must be even. The remaining even digits are 6 and 8. Then the tens digits are the digits left over: 7 and 9.

Possible sums are ...

  476 +598 = 1074

  478 +596 = 1074

  496 +578 = 1074

  498 +576 = 1074

The sum is 1074.

Answer:

2ab(3b^2+2a+4)

Step-by-step explanation:

6ab^3 + 4a^2b + 8ab

2*3*a*b*b^2 +2*2*a*a*b +2*2*2*a*b

Factor out the common terms

2ab( 3*b^2 +2*a +2*2)

2ab(3b^2+2a+4)