Use the point-slope formula to determine the equation of the line that has a slope of 1⁄2 and passes through point (0, 0).
Answer:
y-0 = 1/2(x-0)
y = 1/2(x)
Step-by-step explanation:
Point slope form is
y-y1 = m(x-x1)
where m is the slope and (x1,y1) is a point on the line
y-0 = 1/2(x-0)
y = 1/2(x)
Hoa mua 2 con gà . Lan mua 4 con gà. Hỏi cả 2 bạn mua bao nhiêu con gà
Answer: 6 con ga
Step-by-step explanation:
So ga ca 2 ban mua la:
2+4=6 (con ga)
Given the function f(x) = -5x + 2, find the range ofly for x = -1, 0, 1.
O 7, 2, -3
O 7, 2, 3
O-7, -2, 3
0-7, -2, -3
Answer:
A
Step-by-step explanation:
f(-1)=7, f(0)=2, f(1)=-3
Emily, Yani and Joyce have a total of 3209 stickers. Yani has 2 times
as many stickers as Joyce. Emily has 279 more stickers than Yani. How
many more stickers does Emily have than Joyce?
Answer:
279+x
Step-by-step explanation:
Emily + Yani + Joyce=3209 stickers
if Yani has 2 times as many stickers as Joyce:this statement states that Joyce has x stickers and Yani has 2x stickers because x multiplied by 2"Emily has 279 more stickers than Yani":therefore the equation for Emily will be ;279+2xhow many stickers does Emily have than Joyce:
(279+2x)-(x)
279+2x-x
=279+x
Help me please and thank you
Answer:
D. 3
Step-by-step explanation:
Answer:
3
step by step explanitation
(2+1/2) (2^2-1+1/4) find the expression in the form of cubes and differences of two terms.
Answer:
Consider the following identity:
a³ - b³ = (a + b)(a² - ab + b²)Let a = 2, b = 1/2
(2 + 1/2)(2² - 2*1/2 + 1/2²) = 2³ - (1/2)³ =8 - 1/8Use the algebraic identity given below
[tex]\boxed{\sf a^3-b^3=(a+b)(a^2-ab+b^2)}[/tex]
[tex]\\ \sf\longmapsto (2+\dfrac{1}{2})(2^2-1+\dfrac{1}{4})[/tex]
[tex]\\ \sf\longmapsto (2+\dfrac{1}{2})(2^2-2\times \dfrac{1}{2}+\dfrac{1}{2}^2)[/tex]
Here a =2 and b=1/2[tex]\\ \sf\longmapsto 2^3-\dfrac{1}{2}^3[/tex]
[tex]\\ \sf\longmapsto 8-\dfrac{1}{8}[/tex]
look at the image below
Answer:
117.8
Step-by-step explanation:
Surface area = πr²+πrl (whee r = radius and l = slant height)
= π×3²+π×3×9.5
= 75π/2
= 117.8
Please i need to find the era bounded by the following curves
Answer:
10 2/3 or 32/ 3
Step-by-step explanation:
5 - x^2 - (2 - 2x) =
= -x^2 + 2x + 3
Integral of (-x^2 + 2x + 3)dx from -1 to 3 =
= -x^3/3 + 2x^2/2 + 3x from -1 to 3
= -x^3/3 + x^2 + 3x from -1 to 3
= -27/3 + 9 + 9 - (1/3 + 1 - 3)
= -9 + 9 + 9 - 1/3 - 1 + 3
= 11 - 1/3
= 10 2/3 = 32/3
Answer:
32/3
Step-by-step explanation:
Check the pdf :)
How do I answer this
Answer:
11. Yes
12. No
Step-by-step explanation:
11. The x values only have 1 y value, so it makes it a function.
12. The x value 0 has 2 y values -4 and 4, therefore it is not a function, because in functions that x value can only have one y value,
Please help me with this on the image
Answer:
a) Obtuse angle b) Reflex angle3 log2 (x+1) - 2 = 13
Answer:
Hello,
Answer 31
Step-by-step explanation:
[tex]3*log_2(x+1)-2=13\\\\3*log_2(x+1)=13+2\\\\log_2(x+1)=5\\\\\\x+1=2^5\\\\x=32-1\\\\\boxed{x=31}\\[/tex]
heSellsSeaShells is an ocean boutique offering shells and handmade shell crafts on Sanibel Island in Florida. Find the price SheSellsSeaShells should charge to maximize revenue if p(x)=160−2xp(x)=160−2x, where p(x)p(x) is the price in dollars at which xx shells will be sold per day.
Answer:
it's too much for me im a child u know
5 Cece draws these two figures to prove there is more
than one parallelogram with a 40° angle between a
2-cm side and a 6-cm side. Is Cece correct? Explain.
2 cm
40
4.
2 cm
Answer:
chash greatly ta 45uerywryrsyrsyrs
Figure
А A
Figure B
How many squar
w many square are in
tigne
this
Answer:
7 square are 0resent on aaaaaa
Which of the binomials below is a factor of this expression?
16x2 + 40xy + 25y2
16x²+40xy + 25y²
(4x+5y) (4x+5y)
(4x+5y)²
I hope I helped you^_^
the age of furaha is 1/2 of the age of her aunt if the sum of their ages is 54 years. find the age of her aunt
Answer:
I think it is twenty seven
look at the image for the question
Answer:
117.8
Step-by-step explanation:
surface area = πr²+πrl, where r = radius and l = slant height
so,
πr²+πrl
= π×3²+π×3×9.5
= 75π/2
= 117.8 (rounded to the nearest tenth)
(a) Express the prime number 3 as the difference of two squares? 3=
Answer:
2^2 - 1^2
Step-by-step explanation:
1^1 = 1
2^2 = 4
4-1 =3
2^2 - 1^1 = 3
For each kilogram of a persons weight 2.5 milligrams of a drug is to be given. what dosage should be given to a child who weighs 84 pounds? Use the fact that 1 lb = 0.45 kg
Answer:
A child who weighs 84 pounds should be given 94.5 milligrams of the drug.
Step-by-step explanation:
Givens:
1kg=2.5 milligrams of dosage
Weight of child = 84 pounds
1 pound = 0.45 kg
Solution:
Convert pounds to kilograms --> 84lbs*0.45kg = 37.8 kg
Convert weight to dosage --> 37.8kg * 2.5 mg = 94.5 mg of dosage.
pls help Describe how to find the product of the two terms 3x^2y^5 and 4x^3y^7
Answer:
12 x^5y^12
Step-by-step explanation:
3x^2y^5 * 4x^3y^7
Multiply the constants
3*4 = 12
Multiply the x terms
x^2 * x^3
We know a^b* a^c = a^(b+c)
x^(2+3) = x^5
Multiply the y terms
y^6 * y^7 = y&(5+7) = y^12
Put them back together
12 x^5y^12
The illustration below shows the graph of y as a function of x.
Complete the following sentences based on the graph of the function.
The y-intercept of the graph is the function value y=_____
The smallest positive x-intercept of the graph is located at x=_____
The greatest value of y is y=____ and it occurs when x=____
For x between x and x= 2 π the function value y___ 0
Answer:
below
Step-by-step explanation:
that is the solution above
solve for x ! please help (show work)
Answer:
x = 1/2
Step-by-step explanation:
8(-2x+1) =0
Divide each side by 8
-2x+1 = 0
Add 2x to each side
-2x+1+2x = 2x
1 = 2x
Divide by 2
1/2 = 2x/2
1/2 =x
Answer:
1/2
Step-by-step explanation:
8(-2x+1)=0
Use distributive property first
-16x+8=0
Subtract 8 on both sides
-16x=-8
Divide both sides by -16 to get x by itself
x=0.5
Which is also equal to 1/2
Therefore, x is equal to 1/2
write your answer in simplest radical form
Answer:
a = 4[tex]\sqrt{3}[/tex]
Step-by-step explanation:
Using the cosine ratio in the right triangle and the exact value
cos60° = [tex]\frac{1}{2}[/tex] , then
cos60° = [tex]\frac{adjacent}{hypotenuse}[/tex] = [tex]\frac{2\sqrt{3} }{a}[/tex] = [tex]\frac{1}{2}[/tex] ( cross- multiply )
a = 4[tex]\sqrt{3}[/tex]
Due the end of the week pls help.
This problem seems like a lot when you read through it, but when you start to analyze the problem, the whole first line is extra information that we don't actually need. The part we really need to pay attention to is:
"p = qr - f, write the equation with q solved in terms of p, r, and f."
So, all we are doing here is some manipulating of the equation to get what we want. So, if p = qr - f, we can isolate the variable (q), to get p + f = qr. Now all we have to do is divide both sides by r to isolate the variable (q) even further, and we get [tex]$\frac{p+f}{r}=q$[/tex] or [tex]$r=\frac{p+f}{r}$[tex]
find the quotient 1/5 / (-5/7) =
Answer:
-7/25
Step-by-step explanation:
1/5 ÷ (-5/7)
Copy dot flip
1/5 * -7/5
-7/25
Did any one know this?
Answer:
x sqrt(2)
Step-by-step explanation:
sqrt(a) / sqrt(b) = sqrt(a/b)
sqrt( 14 x^3) / sqrt(7x)
sqrt(14x^3/7x)
sqrt(2x^2)
sqrt(ab) = sqrt(a)sqrt(b)
sqrt(x^2) sqrt(2)
x sqrt(2)
write the first 10 multiples of 2 and 3 and find LCM.
Answer:
multiples of 2 2,4,6,8,10,12,14,16,18,20
multiples of 3 3,6,9,12,15,,18,21,24,27,30
Step-by-step explanation:
Lcm is 6
3 to the fourth power
Answer:
It's 81
Step-by-step explanation:
You can use a calculator on go.ogle :D
a cycle travel 1st km at therateof 10 km per hour the second km at the rate of 3 per hour and third at therate of 6 km.find the average speed of cyclea cycle travel 1st km at therateof 10 km per hour the second km at the rate of 3 per hour
Answer:
18 kilometers 120 kilometers
Two sides of a triangle have lengths 13 m and 19 m. The angle between them is increasing at a rate of 2°/min. How fast is the length of the third side increasing when the angle between the sides of fixed length is 60°? (Round your answer to three decimal places.)
Answer:
The third side is increasing at an approximate rate of about 0.444 meters per minute.
Step-by-step explanation:
We are given a triangle with two sides having constant lengths of 13 m and 19 m. The angle between them is increasing at a rate of 2° per minute and we want to find the rate at which the third side of the triangle is increasing when the angle is 60°.
Let the angle between the two given sides be θ and let the third side be c.
Essentially, given dθ/dt = 2°/min and θ = 60°, we want to find dc/dt.
First, convert the degrees into radians:
[tex]\displaystyle 2^\circ \cdot \frac{\pi \text{ rad}}{180^\circ} = \frac{\pi}{90}\text{ rad}[/tex]
Hence, dθ/dt = π/90.
From the Law of Cosines:
[tex]\displaystyle c^2 = a^2 + b^2 - 2ab\cos \theta[/tex]
Since a = 13 and b = 19:
[tex]\displaystyle c^2 = (13)^2 + (19)^2 - 2(13)(19)\cos \theta[/tex]
Simplify:
[tex]\displaystyle c^2 = 530 - 494\cos \theta[/tex]
Take the derivative of both sides with respect to t:
[tex]\displaystyle \frac{d}{dt}\left[c^2\right] = \frac{d}{dt}\left[ 530 - 494\cos \theta\right][/tex]
Implicitly differentiate:
[tex]\displaystyle 2c\frac{dc}{dt} = 494\sin\theta \frac{d\theta}{dt}[/tex]
We want to find dc/dt given that dθ/dt = π/90 and when θ = 60° or π/3. First, find c:
[tex]\displaystyle \begin{aligned} c &= \sqrt{530 - 494\cos \theta}\\ \\ &=\sqrt{530 -494\cos \frac{\pi}{3} \\ \\ &= \sqrt{530 - 494\left(\frac{1}{2}\right)} \\ \\&= \sqrt{283\end{aligned}[/tex]
Substitute:
[tex]\displaystyle 2\left(\sqrt{283}\right) \frac{dc}{dt} = 494\sin\left(\frac{\pi}{3}\right)\left(\frac{\pi}{90}\right)[/tex]
Solve for dc/dt:
[tex]\displaystyle \frac{dc}{dt} = \frac{494\sin \dfrac{\pi}{3} \cdot \dfrac{\pi}{90}}{2\sqrt{283}}[/tex]
Evaluate. Hence:
[tex]\displaystyle \begin{aligned} \frac{dc}{dt} &= \frac{494\left(\dfrac{\sqrt{3}}{2} \right)\cdot \dfrac{\pi}{90}}{2\sqrt{283}}\\ \\ &= \frac{\dfrac{247\sqrt{3}\pi}{90}}{2\sqrt{283}}\\ \\ &= \frac{247\sqrt{3}\pi}{180\sqrt{283}} \\ \\ &\approx 0.444\text{ m/min}\end{aligned}[/tex]
The third side is increasing at an approximate rate of about 0.444 meters per minute.
9514 1404 393
Answer:
0.444 m/min
Step-by-step explanation:
I find this kind of question to be answered easily by a graphing calculator.
The length of the third side can be found using the law of cosines. If the angle of interest is C, the two given sides 'a' and 'b', then the third side is ...
c = √(a² +b² -2ab·cos(C))
Since C is a function of time, its value in degrees can be written ...
C = 60° +2t° . . . . . where t is in minutes, and t=0 is the time of interest
Using a=13, and b=19, the length of the third side is ...
c(t) = √(13² +19² -2·13·19·cos(60° +2t°))
Most graphing calculators are able to compute a numerical value of the derivative of a function. Here, we use the Desmos calculator for that. (Angles are set to degrees.) It tells us the rate of change of side 'c' is ...
0.443855627418 m/min ≈ 0.444 m/min
_____
Additional comment
At that time, the length of the third side is about 16.823 m.
__
c(t) reduces to √(530 -494cos(π/90·t +π/3))
Then the derivative is ...
[tex]c'(t)=\dfrac{494\sin{\left(\dfrac{\pi}{90}t+\dfrac{\pi}{3}\right)}\cdot\dfrac{\pi}{90}}{2\sqrt{530-494\cos{\left(\dfrac{\pi}{90}t+\dfrac{\pi}{3}}}\right)}}}\\\\c'(0)=\dfrac{247\pi\sqrt{3}}{180\sqrt{283}}\approx0.443855...\ \text{m/min}[/tex]
