A lever of length 1.20 m has a load of 50 kg at a distance of 30 cm from one end and fulcrum at the end of shorter arm. The effort is applied at the end of the bigger arm. Draw a diagram and find: (a) the length of load arm (b) the length of effort arm (c) the mechanical advantage (d)the effort required.
Answers
a) length of load arm = 1 m
b) length of effort arm = 0.3 m
c) mechanical advantage = 1
d) effort required = 50 kg
The Diagram is as follows -
Where:
F is the effort appliedO is the fulcrumL is the loada)
To find the length of the load arm (a), we can use the following formula:
a = L / F
Substituting the values given in the problem, we get:
a = 50 kg / 50 kg = 1 m
b)
To find the length of the effort arm (b), we can use the following formula:
b = a * d
where d is the distance from the fulcrum to the effort. Substituting the values given in the problem, we get:
b = 1 m * 30 cm / 100 cm/m = 0.3 m
c)
To find the mechanical advantage (MA), we can use the following formula:
MA = L / F
Substituting the values given in the problem, we get:
MA = 50 kg / 50 kg = 1
This means that the lever does not provide a mechanical advantage, since the MA is equal to 1.
d)
To find the effort required (F), we can use the following formula:
F = L / MA
Substituting the values given in the problem, we get:
F = 50 kg / 1 = 50 kg
This is the effort required to balance the load of 50 kg.
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a) length of load arm = 1 m
b) length of effort arm = 0.3 m
c) mechanical advantage = 1
d) effort required = 50 kg
The Diagram is as follows -
Where:
F is the effort applied
O is the fulcrum
L is the load
a)To find the length of the load arm (a), we can use the following formula:
a = L / F
Substituting the values given in the problem, we get:
a = 50 kg / 50 kg = 1 m
b)
To find the length of the effort arm (b), we can use the following formula:
b = a * d
where d is the distance from the fulcrum to the effort. Substituting the values given in the problem, we get:
b = 1 m * 30 cm / 100 cm/m = 0.3 m
c)To find the mechanical advantage (MA), we can use the following formula:
MA = L / F
Substituting the values given in the problem, we get:
MA = 50 kg / 50 kg = 1
This means that the lever does not provide a mechanical advantage, since the MA is equal to 1.
d) To find the effort required (F), we can use the following formula:
F = L / MA
Substituting the values given in the problem, we get:
F = 50 kg / 1 = 50 kg
so it will probaly be 50
Related Questions
1. Two main-sequence stars have the same temperature. If star A is four times more luminous than star B, thena) star B is two times farther away than star A.b) star B is four times farther away than star A.c) star B is eight times farther away than star A.d) star B and star A lie at the same distance from us.e) it is impossible to determine their relative distances from the information given.
Answers
The temperature of two main-sequence stars is the same. Star B is two times further away than star A if star A is four times more brilliant.
What's the connection between temperature and luminosity for main sequence stars?The temperature and brightness of a main-sequence star depend on its mass. Bigger is always hotter and brighter. A star with ten times the mass of the sun contains nuclear energy. The brightness is 3000 times that of the sun.
Does a star's luminosity have to be the same for stars with the same temperature?Even stars with the same temperature inevitably have different luminosities. As an illustration, consider stars A and E, which have the same temperature but differ in luminosity.
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A block of mass 4 kg slides on a horizontal frictionless surface with a speed of 2 m/s. It is brought to rest in compressing a spring in its path. If the force constant of the spring is 400 N/m, by how much the spring will be compressed?
a. 2 x 10(-2) mb. 0,2 mc. 20 md. 200 m
Answers
A block with mass 4 kg glides at a speed of 2 m/s across a horizontal, frictionless surface. By compressing a spring in its journey, it comes to rest. The spring has a 0.2 m compress.
What process does kinetic energy undergo to become potential energy?But when you exert force on the battery, the charged particles begin to function, transforming the potential energy into kinetic energy. Similar to this, when you turn on a light, the potential energy goes through your wiring and is transformed into light and heat, both of which are examples of kinetic energy.
Given that,
Block weight: 4 kg
Speed = 2 m/s.
400 N/m force constant; we must determine the distance.
The elastic potential energy of the spring is created from the kinetic energy of the block.
Kinetic energy and potential energy in relationship
1/2mv^2=1/2kx^2
x^2=mv^2/k
put the value into the formula
x^2= 4*2^2/400
x^2=.04
x= .2m
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Suppose a rocket is fired vertically upward from the surface of the earth with one-half of the esacpe speed. How far from the center of the earth will it reach vefore it begins to fall back?
(let g = 9.8 m/s^2 and Re = 6370 km)
A. 1.3 * 104 km
B. 8.5 * 103 km
C. 9.6 * 103 km
D. 2.6 * 104 km
E. 1.9 * 104 km
The correct answer: B.
I do not understand why I am not getting the correct answer.
Answers
The distance before it falls back to the earth is 8.5 * 103 km. Option B
What is the escape velocity?We know that the escape velocity has to do with the velocity that has to be supplied to a material so that the material can be able to escape from the earth's gravitational pull. Let us recall that the whole earth is a large gravitational field. If we throw an object up then the object would have to certainly fall doen to the ground under the influence of gravity.
It is therefore clear that gravity is the force that draws any object that goes upwards down back to the ground. Given that we have been told here that the speed is one-half of the escape speed, then then the magnitude of the speed is 5590.3 m/s.
Given that;
v^2 = u^2 - 2gh
v = final velocity
u = initial velocity
g = acceleration due to gravity
h = height
Then;
u^2 = 2gh
h = u^2/2g
h = ( 5590.3)^2/2 * 9.8
= 8.5 * 103 km
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in the Pollowing figures the horizontal surface on which this block slides is frictionless . if the two Forces acting on
each have magnitude F= 30. №
10.kg What is the magnitude
of the resulting acceleration of the block
Answers
The magnitude of the resulting acceleration of the block is 5.60 m/s.
What is Newton's second law?The product of the block's mass and acceleration is the net force acting on the block. Newton's second law of motion is what is known as this.
The following is the expression for Newton's second law:
F = ma
The net horizontal force acting on the block is as follows:
Fnet =F + FcosΘ
Here, F is the force acting on the block, and 8 is the angle at which the force is applied to the block.
Substitute 30Θ for 8 and 30 N for F.
Fnet =30 N + (30 N)cosΘ = 55.98 N
From Newton's second law, the expression for the force is.
Fnet = ma
Substitute 10.0 kg for m and 55.98 N for Fnet
55.98 N = (10 kg)a
a (55.98 N /10 kg)
a = 5.598 m/s2 a = 5.60 m/s
Therefore, the acceleration of the block is 15.60 m/s
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The question is incomplete. Your most probably complete question is given below: The figure is added.
if the short-term passive test indicates a radon level reading of 18 pci/l, which of the following statements is the most correct?
Answers
Radon is a radioactive gas which has no smell, colour or taste.
What is radon?When you breathe in radon gas, it decomposes into solid radioactive particles that can become trapped in your lungs. These particles release small energy bursts as they degrade further. Over the course of ones lifetime, this can cause lung tissue to deteriorate and result in lung cancer.
Lung cancer has radon as one of its main causes. Depending on the average radon level across the nation and the prevalence of smoking, radon is thought to be responsible for anywhere from 3% to 14% of all lung cancers. Smokers are more likely to develop lung cancer due to the interaction between radon and smoking cigarettes.
There are tried-and-true, long-lasting, and reasonably priced ways to keep radon out of new construction and reduce it in existing structures.
With a small passive detector, it is simple to measure the amount of radon indoors.
The amount of radon in the air is measured in “picocuries per liter of air,” or “pCi/L
Note that your information is incomplete and a overview was given.
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A bowling ball accidentally falls out of the cargo bay of an airliner as it flies along in a horizontal direction. As observed by a person standing on the ground and viewing the plane as in the figure below, which of the paths 1-5 would the bowling ball most closely follow as it falls to the ground.a. 10
b. 2
c. 4
d. 45
Answers
4th paths out of 1 - 5 would the bowling ball most closely follow as it falls to the ground
The bowling ball moves due to the resultant force of the vertical and horizontal direction.
What is resultant force ?The overall force operating on the item or body as well as the direction in which the body is moving are referred to as the resultant force. When the object is stationary or moving at the same speed as it, there is no consequent force.
The outcome is what is produced when vectors are added together. The biggest (maximum) consequent when adding two vectors is equal to their sum when forces are acting in the same direction.
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Suppose you are at mission control on the moon, in charge of launching a moon-orbiting communications satellite.
Moon mass =7.36×10 22
kg Moon radius =1.74×10 6
m
a. First, how much would a
1500 kg
satellite weigh near the surface of the moon? b. The satellite is to have an altitude of
100 km
above the moon's surface. What is the radius of the orbit of the satellite? c. When the satellite is in orbit, how big will the centripetal force be? Explain. d. Find the required orbital velocity for the satellite. e. How long will it take the satellite to orbit the moon? (This time is called the orbital period.) f. Is this satellite accelerating while in orbit? If so, what is the direction and magnitude of the acceleration?
Answers
Suppose you are in mission control on the moon, in charge of launching a moon-orbiting communications satellite.
a) 2430 N.
b) 1.84 x 10^6 m.
c) F = m * v^2 / r
d) 2157 m/s
e) 2.87 x 10^4 s
f)1.17 x 10^-3 m/s^2
What is the weight of the statlite?a. The weight of the satellite near the surface of the moon would be the mass of the satellite multiplied by the acceleration due to gravity on the moon. The acceleration due to gravity on the moon is about 1.62 m/s^2, so the weight of the satellite would be
1500 kg * 1.62 m/s^2 = 2430 N.
b. The radius of the orbit of the satellite would be the distance from the center of the moon to the altitude of the satellite. The radius of the moon is 1.74 x 10^6 m, so the radius of the orbit of the satellite would be
1.74 x 10^6 m + 100 km = 1.84 x 10^6 m.
c. The centripetal force is the force that is required to keep an object in circular motion. It is equal to the mass of the object times its velocity squared, divided by the radius of its orbit. To find the centripetal force on the satellite, we need to know its velocity. We can find this using the equation for the centripetal force, which is:
F = m * v^2 / r
where F is the centripetal force, m is the mass of the object, v is the velocity of the object, and r is the radius of the orbit.
d. To find the required orbital velocity for the satellite, we can rearrange the equation for the centripetal force to solve for v:
v = sqrt(F * r / m)
Plugging in the values, we get:
v = sqrt(2430 N * 1.84 x 10^6 m / 1500 kg) = 2157 m/s
e. The orbital period is the time it takes for an object to complete one orbit. It is equal to the circumference of the orbit divided by the velocity of the object. The circumference of the orbit is 2 * pi * r, where r is the radius of the orbit. The velocity of the object is the orbital velocity we calculated above. Plugging these values into the equation, we get:
T = 2 * pi * r / v
Plugging in the values, we get:
T = 2 * pi * 1.84 x 10^6 m / 2157 m/s = 2.87 x 10^4 s
f. Yes, the satellite is accelerating while in orbit. The direction of the acceleration is towards the center of the orbit, and the magnitude of the acceleration is the centripetal acceleration, which can be calculated using the equation:
a = v^2 / r
Plugging in the values, we get:
a = 2157 m/s^2 / 1.84 x 10^6 m = 1.17 x 10^-3 m/s^2
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A 59-kgkg person riding a bike puts all her weight on each pedal when climbing a hill. The pedals rotate in a circle of radius 18 cmcm . What is the maximum torque she exerts?
Answers
A 59-kg person riding a bike puts all her weight on each pedal when climbing a hill. The pedals rotate in a circle of radius 18 cm. the maximum torque she exerts is 104.07Nm.
given that :
mass ,m = 59 kg
radius , r = 18 cm
The force , F = mg
F = 59 × 9.8
F = 578.2 N
The torque is expressed as:
torque = force × radius
torque = 578.2 N × 0.18 m
torque = 104.07 Nm
Thus, if the mass is 59 kg and the radius is 18 cm then maximum torque she exerts is the 104.07 Nm.
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9. What is the mass of a sky diver falling at a velocity of 52 m/s who has a kinetic energy of
97344 Joules?
Answers
Answer: m = 72 kg
Explanation:
During the heating season, a damper in the bypass duct is closed to prevent air from passing through the humidifier. Electronic humidistats are equipped with solid-state sensors in place of a hygroscopic element. Evaporative humidifiers contain an element that is kept damp. False
Answers
This statement is False because Solid-state sensors are used in place of a water - absorbing element in electronic humidistats. A damper in the bypassed duct is closed during the summer period to stop airflow.
What is hygroscopic and example?Hygroscopy - A material is said to be hygroscopic if it has the capacity to adsorb and retain water or water from its immediate surroundings. Examples include ethanol, glycerin, concentrated sulfuric acid, honey, silica gel, and methanol.
How hydroscopic is water?Around the soil particles, some water in the soil creates an incredibly thin, firmly held layer. It's referred to as hydroscopic water. A little amount of water in the soil is chemically linked to soil components in the soil. We refer to it as mixed water.
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given a feeder serving three motors with full-load currents of 5a, 10a, and 15a, the minimum feeder ampacity is
Answers
The minimum feeder ampacity of the given feeder with three motors with full load currents of 5A, 10A, and 15A is 18.75A.
Minimum Circuit Ampacity (MCA) is a value that specifies the minimum main power wire size. It is also used to decide the minimum wire size needed for a field-wired product.
This specification is needed to guarantee that the wiring will not overheat under the conditions that are operating. More accurately, we can say that the MCA is the highest steady-state electrical current that the unit can withstand when operating correctly.
MCA is found using the formula
MCA = 1.25 x Amperage value of feeder (here)
= 1.25× 15 A
= 18.75 A
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in the figure, light is incident at angle on a boundary between two transparent materials. some of the light travels down through the next three layers of transparent materials, while some of it reflects upward and then escapes into the air.
Answers
(a) θ5 in the air is 56.9° and (b) θ4 in the bottom material 35.30°. Normally, a light beam that strikes an angle on a prism's refracting face emerges from the opposite face.
How to calculate?(a) Approximating n=1 for air, we have
n1. sinθ1 = (1)sinθ5 ⇒56.9°=θ5
and with the more accurate value for n air in Table below, we obtain 56.80.(b) Equation n1 sinθ c =n2 sin 90° leads to,
n1 sinθ 1=n2 sinθ2 =n3 sinθ 3 =n4 sinθ 4
so that. θ4 =sin −1( n1/n4.sinθ 1 )=35.30° .
What does angle of incidence mean?The angle of incidence is formed by a line drawn perpendicular to the reflecting barrier and the wave's direction of motion.
Is the incidence angle of refraction?Refraction Depending on the Refractive Indices in the Two Media and the Angle of Incidence. Snell's law states that the angle of incidence, I and the proportion of the refractive indices of the two media that make up the interface determine the angle of refraction, r.
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Zach, whose mass is 70 kg, is in an elevator descending at 12 m/s.The elevator takes 3.0s to brake to a stop at the first floor.
a. What is Zach's apparent weight before the elevator startsbraking ?
b. What is Zach's apparent wight while the elevator is braking?
Answers
Zach's apparent weight before the elevator starts breaking is 686 N.
Zach's apparent weight while the elevator starts breaking is 966 N.
Given that, mass of Zach = 70 kg
His weight W = mg = 70* 9.8 = 686 N
If the elevator is going down at a constant velocity then, acceleration is zero and the apparent weight before braking is 686 N.
v = u + a * t
where,
t = Time taken
u = Initial velocity
v = Final velocity
a = Acceleration
Making a as subject from the above equation,
Acceleration a = (v - u)/t = (0-12)/3 = -4 m/s²
While the elevator is braking it has acceleration -4 m/s².
W = m ( g - a) = 70 (9.8 - (-4)) = 70(9.8 + 4 ) = 966 N
The apparent weight of Zach is 966 N.
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With respect to stellar spectra, select all of the correct statements from the following list.
Doppler shifts in spectral lines give clues to the motions of stars.
The Lyman and Paschen series of the hydrogen spectrum are not visible.
Stellar spectra are absorption spectra.
Spectra can reveal the chemical composition of stars.
Answers
With respect to stellar spectra Doppler shifts in spectral lines give clues to the motions of stars.
What do spectral lines tell us?The spectral lines of an element can be used by astronomers to determine the element's temperature as density within the star. The spectral line may also be used to display the star's electric flux. The width of the line may be used to gauge how rapidly the material is moving. We can learn something about stellar winds from this.
How are elements recognized by spectral lines?Dark bands in a broad band can be used to identify components, and it can also reveal an object's temperature: The spectrum has more green, blue, and violet hues as the temperature rises. The spectrum of relatively cool objects is dominated by deep red or red and yellow.
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A rod has a length 2.0000m at 20.0C. The length of the rod increases to 2.0005
Answers
5.00 × 10-3/K is the coefficient of thermal expansion of the material from which the rod is made as it increases its length to 2.0005m
What is the purpose of the thermal expansion coefficient?The coefficient of thermal expansion explains how an object's size varies when temperature changes. In particular, it measures the fractional size change per degree change in temperature at constant pressure, where lower coefficients denote a reduced propensity for size change.
What does thermal expansion mean?The propensity of matter to alter shape, volume, and area in reaction to a change in temperature is known as thermal expansion. The average molecular kinetic energy of a substance has a monotonic relationship with temperature.
How is thermal expansion calculated?Use the equation for linear thermal expansion ΔL=αLΔT Δ L = α L Δ T to calculate the change in length, ΔL .
How to solve?Get your rod hot enough to achieve, say, 1% linear thermal expansion.
The rod's dimension has increased to 1.01 units.
The rod is 1.030301 times its original size, or 1.013 larger than it was before heating.
This equals 1.03 when rounded to three major figures. In other words, its volume is 3% higher than that of the cold specimen.
The linear expansion is tripled, or 3%, by the volumetric expansion.
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Complete question:
A rod has a length 2.0000 m at 20.0°C. The length of the rod increases to 2.0005 m when the temperature increases to 40.0°C. What is the coefficient of thermal expansion of the material from which the rod is made?
A 1000-kilogram space vehicle travels at 5 meters per second along the level road. The magnitude of the normal force acting on the vehicle is approximately A) 1000N B) 5000N C) 10000N D) 50000N
Answers
Answer:
C = 10000N
Explanation:
On a level surface, with no other force acting on the vehicle,
|Normal force| = |Weight|,
Weight = mass * acceleration due to gravity
= 1000 kg * 9.8 m/s^2 or N/kg
= 9800 N
--> 10000 N rounded to one significant digit
You drop a 2.00 kg book to a friend who stands on the ground at distance D = 10.0 m below. If your friend's outstretched hands are at distance d = 1.50 m above the ground (Fig. 8-28), (a) how much work Wg does the gravitational force do on the book as it drops to her hands? (b) What is the change ΔU in the gravitational potential energy of the book–Earth system during the drop? If the gravitational potential energy U of that system is taken to be zero at ground level, what is U(c) when the book is released and (d) when it reaches her hands? Now take U to be 100 J at ground level and again find (e) Wg, (f) ΔU, (g) U at the release point, and (h) U at her hands.
The aswers are as follows:
a) 167J, b) -167J, c) 196J, d)29J, e)167J, f)-167J g)296J, and h) 129J
Answers
If your friend's outstretched hands are at distance d = 1.50 m above the ground, (a) work Wg does the gravitational force do on the book as it drops to her hands 167J, b) -167J, c) 196J, d)29J, e)167J, f)-167J g)296J, and h) 129J
a) Work = mg(Ac)
= 2 × 9.8 × (10 - 1.5) = 167j
b) ΔU = Ubc - Uab = Mg(bc) - Mg(ab)
= mg(bc - ab)
= 2 × 9.8 (1.5 - 10) = -167j
c) Potential energy at reach point v = mg(AB) = 2 × 9.8 × 10 = 196J
d) Potential energy at reach point U = mg (bc) = 2 × 9.8 × 1.5 = 29.4j
e) Total work wg = mg (ac) = 2 × 9.8 × 3.5 = 167j
f) ΔU = -wg = - 167j
g) ui = mg × AB + 100 = 196 + 100 = 296j
h) uf = mg × bc + 100 = 29.4 + 100 = 129j
Given the possibility of motion, gravitational forces can sort phases of various densities. Although high temperatures are not anticipated for the early Earth, widespread melting is one possibility. Sorting in response to the outgassing of deeply buried ices is a more feasible scenario. Such processes would have altered the moment of inertia, necessitating an adjustment to the angular velocity. Friction opposes gravitational settling and prevents it from being conservative, which makes quantification dubious. The ensuing phase separation and angular momentum alterations would not need to be as extensive as commonly believed if an iron protocore existed.
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A student received this anemometer as gift: He wants to try it out but the wind is not blowing outdoors He turns on an electric; fan and places the anemometer a constant 0.5 meter in front of the fan_ He sees these digital readings during 10 seconds: 9.62,9.61, 9.63,9.61,9.63,9.61 and 9.62 km/hr: These data are demonstrating which Ptype of experimental error intrinsic systematic error random error in measurement systematic error in measurement intrinsic random error
Answers
A cup anemometer, made up of three or four cups with a conical or hemispherical shape set symmetrically around a vertical spindle, is typically used to measure wind speed. The spindle turns because of the wind blowing into the cups.
How to measure wind speed?Anemometers, the devices used to measure wind, may record wind speed, direction, and gust force.The nautical mile per hour (0.51 m sec-1 = 1.15 mph) is the standard unit for expressing wind speed. Wherever the wind is blowing, the wind's direction is reported and measured in relation to true north (not magnetic north). A wind blows from the east or 90 degrees, the south or 180 degrees, and the west or 270 degrees, which is the direction of a westerly wind.Normal wind speed increases with height above the earth's surface, and it is greatly influenced by things like the terrain's roughness and the existence of nearby structures, trees, and other obstructions.There should be no significant obstructions within 300 metres of the tower and the exposure should be flat with uniformly rough terrain. In reality, only a small number of sites in the observing network actually match this condition for all incident wind directions, but the majority are fairly typical of an open site.To Learn more About wind speed refer to:
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A pulley system is used to lift up a 90N boulder. What is the mechanical advantage if you only need to use 15N of force to lift the boulder?
Answers
By simply creating more loops or pulleys, the pulley system's mechanical advantage can be accomplished.
Equation:
It is known that a pulley system can lift a crate with 90 newtons of force. Finding the pulley system's mechanical advantage is important if the input force is 15 newtons.
The force makes the distance longer as though it were working. Mechanical advantage is not greatly affected by the number of pulleys. This is only based on the amount of weight that needs to be lifted.
Therefore,
F1/F2 = 90/15
F1/F2 = 6
Given that the crate's weight is 90 N and the input force is 15 N, this makes sense.
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Can someone help me and tell me as soon as possible
Answers
Answer:
copy and complete this diagram so that the system is in equilibrium
An oil layer floats (at rest) on 90 cm of water in a tank. The pressure at the bottom of the tank is 113.0 kPa .How thick is the oil? Suppose that the density of the oil is 900kg/m3. (The density of water is 1000kg/m3.)
Answers
The thickness of the oil is 0.327 m.
The bottom pressure of the tank is given by atmospheric pressure, pressure given by oil and pressure of water. It is mathematically given as,
P = Patm + ρoil g* t + ρwater g * h
Making 't' as subject, we have,
ρoil g* t = P - Patm - ρwater g * h
t = (P - Patm - ρwater g * h)/ρoil g -------(1)
Given that, Height of the tank h = 0.9 m
Pressure at the bottom of the tank P = 113 kPa
Patm = 1.013 * 10⁵ Pa
g = 9.8 m/s²
ρwater = 1000 kg/m³
ρoil = 900 kg/m³
Placing the values in the above equation,
t = (P - Patm - ρwater g * h)/ρoil g
t = (113* 10³ - 1.013 * 10⁵ - 10³* 9.8* 0.9 )/(900* 9.8)
⇒ (113* 10³ - 101.3* 10³ - 8.82* 10³)/(900* 9.8) = 2.88 * 10³/(900* 9.8)
⇒ 0.327 m
Thus, the thickness of the oil is found to be 0.327 m.
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five coins are stacked in the smooth plastic container. if each coin weighs 0.0235 lb, determine the normal reactions of the bottom coin on the container at points a and b.
Answers
The smooth plastic jar has five pennies placed inside of it. The normal reactions of the bottom coin on the container at locations a and b will be 0.0705 lb and 0.1175 lb respectively if each coin weighs 0.0235 lb.
What does normal force mean?A contact force, the normal force is often referred to as the normal reaction force. On two surfaces that are not attached to one another, a normal force cannot be applied.
What normal force is present during deceleration?The body's weight determines the usual deceleration force. A body's position relative to the ground tells us when it is about to fall. The normal force is the portion of a force that is perpendicular to any contact surface.
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tunneling is a variation of techniques used to achieve higher degrees of privacy for browsing on the internet
Answers
Tunneling is a variation of techniques used to achieve higher degrees of privacy for browsing on the internet. This is true.
What is privacy?The right to privacy is a fundamental component of human rights that also supports equality before the law and the freedoms of association, expression, and thought. But defining it is difficult. Different individuals and nations have various points of view. In general, the right to privacy includes the freedom from interference and invasion.
This acknowledges that each person has a domain of existence and activity that rightfully belonged to that person alone, where he or she ought to be unrestricted by coercion or even unwanted observation.
Packets can be moved between networks using tunneling. Encapsulation is how tunneling functions: A tunneling protocol in computer networks is a communication protocol that permits the transfer of data between networks. It entails using a technique called encapsulation to allow private network communications to be sent across a public network.
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tunneling is a variation of techniques used to achieve higher degrees of privacy for browsing on the internet
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what should be the value of 'x' such that the mass то exerts a force of mg on the inclined surface at P. (N=mg)
Answers
The value of 'x' such that the mass то exerts a force of mg on the inclined surface at P. (N=mg) is given by
x = N / (mg cos θ)
What is value of 'x'?Generally, To determine the value of 'x', you need to know the angle of inclination of the surface and the mass of the object. The force of gravity (N) acting on the object is equal to the mass of the object (m) multiplied by the acceleration due to gravity (g). The force of gravity is also equal to the normal force (N) exerted by the surface on the object, which is perpendicular to the surface.
If the surface is inclined at an angle θ with respect to the horizontal, the normal force will be equal to the component of the force of gravity along the surface. This component can be calculated using the formula N = mg cos θ, where θ is the angle of inclination and m is the mass of the object.
Therefore, to determine the value of 'x', you need to solve the equation N = mg cos θ for 'x'. To do this, you can rearrange the equation to solve for x:
x = N / (mg cos θ)
Substituting the values of N, m, and θ into this equation will give you the value of 'x' that you are looking for.
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The smoke from the Old Man’s furnace travels up from the basement at a velocity of |.5 meters per second. Ralphie is sitting in the kitchen above and can smell the smoke within 6 seconds. What is the approximate distance that the smoke travels up from the furnace?
Answers
The approximate distance that the smoke travels up from the furnace is 9metres.
What is distance?Distance is described as a numerical or occasionally qualitative measurement of how far apart objects or points are. In the field of physics or everyday usage, distance is usually referred to a physical length or an estimation based on other criteria.
Parameters given:
Velocity = 1.5
time = 6 seconds
We know that distance = speed x time
Hence, distance = 1.5 x 6 seconds
distance = 9 meters.
Distance is a scalar quantity that refers to how much ground an object has covered in the course of its motion while we can describe displacement as a vector quantity that refers to "how far out of place an object is"; it is the object's overall change in position.
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a wire of length l is wrapped into a coil with n turns this coil is then placed in a magnetic field of strength b
Answers
Maximum torque developed is (BIL²/4[tex]\pi[/tex]n).
Torque is a measure of force that can cause an object to rotate about an axis.
A force causes an object to accelerate in linear kinematics. Similarly, torque causes angular acceleration. Torque can therefore be defined as the rotational equivalent of a linear force. The line about which the object rotates is called the axis of rotation. In physics, torque is simply the tendency of a force to rotate or twist.For any structure such as a solenoid, toroid, and circular arc, the magnetic field at a certain point of the structure is always proportional to the number of turns of the coil.
As we know magnetic field is (BIL²/4[tex]\pi[/tex]n)
2[tex]\pi[/tex]rn = L
r = (L/2[tex]\pi[/tex]n)
A = [tex]\pi[/tex]r²
A = (L²/4[tex]\pi[/tex]n²)
M = niA
M = (iL²/4n[tex]\pi[/tex])
Then Torque is Z = MBSin90°
The question is incomplete, the complete question is "a wire of length l is wrapped into a coil with n turns this coil is then placed in a magnetic field of strength b, the maximum possible torque developed is?"
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An ice skater with rotational inertia I0I0 is spinning with angular speed ω0ω0. She pulls her arms in, thereby increasing her angular speed to 4ω04ω0. Her rotational inertia is then:
a. I0I0
b. I02I02
c. 2I02I0
d. I04I04
e. 4I0
Answers
The new rotational inertia or final moment of inertia of the girl is I₀ / 4.
option D is the correct answer.
What is rotational inertia?
Rotational inertia is a property of any object which can be rotated.
Rotational inertia or moment of inertia of an object is a measure of the resistance of an object to changes in its angular velocity.
Based on the law of conservation of angular momentum, the formula for her new rotational inertia is given as;
I₀ω₀ = I₁ω₁
where;
I₀ is the initial moment of inertiaI₁ is the final moment of inertiaω₀ is the initial angular velocity of the objectω₁ is the final angular velocity of the objectThe given parameters include,
initial angular velocity = ω₀
final angular velocity = 4ω₀
initial moment of inertia = I₀
The final moment of inertia of the girl is calculated as
I₁ = ( I₀ω₀ ) / (ω₁)
I₁ = ( I₀ω₀ ) / (4ω₀)
I₁ = I₀ / 4
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A toy spacecraft is launched directly upward. When the toy reaches its highest point, a spring is released and the toy splits into two parts with masses of 0.01 kg and 0.09 kg, respectively. Immediately after the separation, the 0.01 kg part moves horizontally due east. Air resistance is negligible. True statements about the 0.09 kg part include which of the following? I. It could move north immediately after the spring is released. II. It takes longer to reach the ground than does the 0.01 kg part. III. It strikes the ground closer to the launch point than does the 0.01 kg part. (A) I only (B) III only (C) I and II only (D) II and III only (E) I, II, and III
Answers
Air resistance is hardly noticeable. true regarding the 0.09-kilogram component. This causes 0.01kg to land farther from the launch site than 0.09kg did.
0.09kg will move to the west due to momentum conservation (opposite of 0.01 kg). Additionally, since both are at the same height above the ground, it will take them equal amounts of time to descend to the ground.
Allowing v to be the speed of 0.01 kg, which means that the speed of 0.09kg will be smaller than 0.01 kg,
0.01v - (0.09)V = 0
V = 0.01 v/ 0.09 = 0.111v
The speed of 0.09 kg = 0.111v
The speed of 0.09 kg is less than 0.01kg.
Because of this, 0.01kg hits the ground farther from the launch point than 0.09kg did.
The amount of resistance in an electrical circuit represents the resistance to current flow. The Greek letter omega (), which represents resistance, represents ohms. German physicist Georg Simon Ohm (1784–1854), who investigated the connection between voltage, current, and resistance, is the name given to the unit of resistance known as an ohm.
Resistance measurements are typically performed in order to evaluate the health of a component or a circuit.
Current flow is inversely correlated with resistance. Conductor damage from corrosion or burning could be one of several potential causes if it is extremely high.
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A single loop of copper wire lying flat in a plane, has an area of 7.80 cm^2 and a resistance of 2.70 Ω A uniform magnetic field points perpendicular to the plane of the loop. The field initially has a magnitude of 0.500 T, and the magnitude increases linearly to 3.50 T in a time of 1.10 s. What is the induced current (in mA) in the loop of wire over this time?
Answers
The induced current in the loop of the copper wire is found to be 7.85 mA.
The single loop of the copper wire is lying in flat plane and the magnetic field is pointing perpendicular to the plane of the loop. The area of the loop is given to be 7.8cm²
The magnetic field initially has a magnitude of 0.500 Tesla and it finally increases manner to grow to a magnitude of 3.50 Tesla in a time 1.10 seconds.
The induced EMF in the circuit will be given by the relation,
E = A∆B/∆T
Where,
B is magnetic field,
A is the area and T is the time taken.
Putting all the values,
E = 0.00078×(3.5-0.5)/1.1
E = 21.2mV.
The resistance in the copper loop is given to be 2.7 ohm.
Now, the induced current in the circuit will be given by the relation,
I = E/R
Putting all the values
I = 21.2/2.7
I = 7.85 mA.
So, the induced current in the wire is 7.85 milliamps.
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A wire is formed into a circle having a diameter of 20.0 cm and placed in a uniform magnetic field of 2.50 mT. The wire carries a current of 5.00 A.
(a) Find the maximum torque on the wire.
_____ µN·m
(b) Find the range of potential energies of the wire-field system for different orientations of the circle.
minimum
_____µJ
maximum
_____ µJ
Answers
The maximum torque on the wire is 392.3 µN·m and the range of potential energy is -392.3µN·m(minimum) to +392.3µN·m(maximum)
Torque: Torque is a measure of the force that can cause an object to rotate about an axis. It is a vector quantity.
Given that,
diameter D=20cm
Radius r =10cm
magnetic field B =2.5mT
current I=5A
Torque= n×B
=nBsinФ
torque=nB= NIAB
= 1×5×π×[tex]10^{2}[/tex]×[tex]10^{-4}[/tex]×2.5×[tex]10^{-3}[/tex]
= 39.23×[tex]10^{-5}[/tex]
= 392.3µN·m
minimum potential energy= -nB= -392.3µN·m
maximum potential energy =+nB= +392.3µN·m
Therefore the maximum torque on the wire is 392.3 µN·m when is placed in an uniform magnetic field of 2.50mT and the range of potential energy is -392.3µN·m(minimum) to +392.3µN·m(maximum)
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