Answer:
55 m/s w
Explanation:
Do I add squared or not?
Answer: add it
Explanation:
Who is most likely to be offered a higher auto loan rate based on their credit-
to-debt ratio?
A. Juan has $10,000 in credit and owes $6,000.
B. Chester has $5,000 in credit and owes $750
C. Jalissa has $5000 in credit and owes $500.
credjtar
D. Nancy has $10,000 in credit and owes $2,000.
SUBMIT
HELP ME PLEASE
Answer:
A - Juan
Explanation:
I took the test!
PLEASE HELP!!!!
1. Suppose a planet orbits a star at the same distance
as Earth (1 AU) but with a period of roughly 200
Earth days. The mass of the central star is:
a. less than the mass of our sun.
b. the same as the mass of our sun.
c.greater than the mass of our sun.
d. impossible to determine without
knowing the mass of the planet.
Since the period of the supposed planet is less than the period of the earth orbiting the sun, That means the mass of the central star is greater than the mass of the sun. The answer is option C
According to Kepler's third law of planetary motion for planets and satellites, he described circular orbit about the same center body stating that:
The squared of the period is directly proportional to the cube of the radius. That is,
[tex]T^{2} \alpha r^{3}[/tex]
The orbital period formula is expressed as :
[tex]T^{2}[/tex] = 4[tex]\pi ^{2}[/tex] [tex]r^{3}[/tex] ÷ GM
Suppose a planet orbits a star at the same distance as Earth (1 AU) but with a period of roughly 200 Earth days. The mass of the central star will be greater than the mass of our sun based on the formula given above.
In a geostationary orbit, whatever the mass of the satellite may be, they will travel at the same speed in a particular orbit. mass M in the above formula becomes the mass of the sun or the center mass.
Since the period of the supposed planet is less than the period of the earth orbiting the sun, That means the mass of the central star is greater than the mass of the sun.
Therefore, the correct answer is option C
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Un bloque de cobre cuya masa es 250 gramos , absorbe calor y su temperatura se eleva de 20 ˚C a 150 `C. ¿Cuál es la cantidad de calor absorbida por el bloque de cobre?. Expresar el resultado en unidades caloríficas y en unidades mecánicas.
Dada la información de la pregunta, el calor absorbido por el cobre es de 12513 J o 2990 calorías.
El calor ganado se obtiene de la relación;
H = mcdt
Dónde;
H = calor absorbido
m = masa
c = capacidad calorífica del cobre
Δt = cambio de temperatura
La capacidad calorífica del cobre es de 385 J / kg / ° C
Entonces;
m = 250 gramos o 0,25 kg
Δt = 150 ° C - 20 ˚C = 130 ˚C
H = 0,25 kg * 385 J / kg / ° C * 130 ˚C
H = 12513 J o 2990 calorías
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Two Force 16N and 4N acts at rights angle each other calculate the resultant force
Why is it important to try to use as many renewable resources as possible?
Answer:
It is important to use renewal resources because we use so many non- renewable resources that we may lose the ability to make a lot of things like gasoline or power for our cities.
what is the formula of parallelogram method to work out the sum of two vectors
Answer:
The sum of vectors P and Q is given by the vector R, the resultant sum vector using the parallelogram law of vector addition. If the resultant vector R makes an angle ϕ with the vector P, then the formulas for its magnitude and direction are: |R| = √(P2 + Q2 + 2PQ cos θ) β = tan-1[(Q sin θ)/(P + Q cos θ)]
what would be Vy and pllzzzzzzz help
Answer:
2400m/s , 2240,2080,1920m/s
Please help me thank you
Fr+Cl=FeCl3
this is about the magnet fields. thanks in advance.
could someone answer this
The given kinematic equations of motion are derived from Newton's Laws
of Motion.
A) The ball's speed the instant it left the soccer player's foot is approximately 11.074 m/s.B) The time it took the ball to rise to its maximum height is approximately 1.129 seconds.
Reasons:
The direction the ball is kicked = Upwards in the air
Maximum height to which the ball rises = 6.25 m
A) The speed of the ball the instant it left the soccer player's foot
Solution:
The equation to use is; v² = v₀² + 2·[tex]a_y[/tex]·(y - y₀)
[tex]a_y[/tex] = The acceleration due to gravity ≈ -9.81 m/s²
At the maximum height, y - y₀ = 6.25 m
The velocity at the maximum height, v = 0
v₀ = The speed of the ball the instant it left the soccer player's foot
Which gives;
v² = v₀² + 2·[tex]a_y[/tex]·(y - y₀)
0 = v₀² - 2 × 9.81 × (6.25) = v₀² - 122.625
v₀² = 122.625
v₀ = √(122.625) ≈ 11.074
The ball's speed the instant it left the soccer player's foot, v₀ ≈ 11.074 m/s.
B) Required:
The time it takes the soccer ball to rise to the maximum height.
Solution:
The equation of motion required is v = v₀ + [tex]a_y[/tex]·t
At the maximum height, v = 0
v₀ ≈ 11.074 m/s
v = v₀ + [tex]a_y[/tex]·t
Which gives;
0 = 11.074 - 9.81 × t
[tex]t \approx \dfrac{11.074}{9.81} \approx 1.129[/tex]
The time it took the ball to rise to its maximum height, t ≈ 1.129 seconds
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Question 4 of 5
Which pair of objects would repel each other?
O A. A positively charged particle and a neutral particle
OB. A negatively charged particle and a neutral particle
O C. Two positively charged particles
OD. A positively charged particle and a negatively charged particle
Answer:
Two positively charged particles
Explanation:
I said two positively charged particles because if I say c or d what ever it is for you guy it can be wrong so just pick the one that says Two positively charged particles
Answer: C Two positively charged particles.
Explanation:
just trust me on it, i've done the same quiz.
The sandbox of the previous exercises had 10kg of sand. It was initially at 15°C and the specific heat of this sand is 830 j/(kg°C). What will be the final temperature of the sand? (-8100J=|0kg)
Answer:
Sorry I need points [tex] \boxed{}[/tex]
Please can someone solve this for me i will really appreciate it
Answer:
• Average current = 25,000 Amperes
• Time = 0.80 seconds
a)
[tex]{ \rm{quantity \: of \: charge = current \times time}} \\ { \rm{q = 25000 \times 0.80}} \\ { \boxed{ \mathfrak{answer : \: { \rm{quantity \: of \: charge = 20000 \: coulombs}} }}}[/tex]
b)
[tex]{ \rm{number \: of \: electrons = \frac{current}{charge \: quantity} }} \\ \\ { \rm{n = \frac{25000}{20000} }} \\ \\ { \boxed{ \mathfrak{ \: answer : \: { \rm{n = 1.25 \: }}}}}[/tex]
[tex]{ \underline{ \mathfrak{ \green{Good \: grace}} \: \:⚜ \: \: { \blue{ \mathfrak{Good \: God}}}}}[/tex]
What distance does a police car travel if it is going 3.0 m/s for 20 seconds
Answer:
60 meters
Explanation:
If you are going 3 meters in a second, and you are traveling for 20 seconds, you have to multiply
3meters/second*20seconds
cross out the seconds and you have
3 meters*20
60 meters
A 9.0V battery is connected across a 2.2kilo ohms and 6.8kilo omhs resistors connected in series. what is the potential differences across 2.2kilo ohms resistor.
Answer:
[tex]V_{2.2} =2.2V[/tex]
Fast and loose: that's a classic voltage divider. the drop from the i-th resistor is [tex]R_i \over {\sum R}[/tex] of the drop across the whole series. In our situation, it's [tex]2.2\cdot 10^3 \over {2.2\cdot10^3 + 6.8\cdot 10^3[/tex] of 9 V. By plugging numbers in a calculator, it's 22/90 of 9V, or 2.2V
With Ohm's Law
The series is equivalent of a single resistor of Resistance [tex]2.2\cdot 10^3+6.8\cdot 10^3 \Omega = 9.0 k\Omega[/tex]. By Ohm's first Law ([tex]V=Ri[/tex]) the current flowing through the resistor is [tex]9V = 9*10^3\Omega i \rightarrow i=1mA[/tex]. At this point, the drop across the first resistor is, again by Ohm's law[tex]V = 2.2 \cdot 10^3 \Omega \cdot 1\cdot 10^{-3} A = 2.2V[/tex]
H is a chemical (blank) and H2 is a chemical (blank)
Please I need help!
Answer:
"H" is a chemical symbol and "H2" is chemical formula.
1. A truck is traveling at a speed of 12 km/s is going to school. It took 10 seconds to get to school. What was the distance?
Answer:
120km
Explanation:
To get speed you divide distance by time.
A Rocket took 5 minutes to travel the 185 km. How fast did the Rocket travel in kilometers per minute (km/min)?
Answer:
The rocket travelled 37km per minute
Explanation:
185÷5=37
solve by formulae method and completing the square method. 4x²-29x+7=0
Answer:
(4x - 1) (x - 7)
Explanation:
4x^2 - 29x + 7 = 0
(4*-7=-28) and: (1*- 1 = -1)
-28 - 1 = -29 and - 1 times -7 = 7
most of the waves in the electromagnetic spectrum are
Answer:
The entire electromagnetic spectrum, from the lowest to the highest frequency (longest to shortest wavelength), includes all radio waves (e.g., commercial radio and television, microwaves, radar), infrared radiation, visible light, ultraviolet radiation, X-rays, and gamma rays.
what is pole of magnet
and
define the term magnetic line of force
Answer:
1. The magnetic pole is the region at each end of a magnet where the external magnetic field is the strongest.
2. magnetic line of force - a line of force in a magnetic field. field line, line of force - an imaginary line in a field of force; direction of the line at any point in the direction of the force
Explanation:
Select the correct answer.
Planet A Planet B
Distance from Sun 0.72 AU 9.54 AU
Planet composition rocky mantle, iron core hydrogen, helium
Gases in atmosphere very dense atmosphere that is 96.5% poisonous carbon dioxide and 3.5% nitrogen mostly hydrogen and helium
Number of moons 0 62
Rings no rings visible rings
Which planet is planet A?
A.
Mars
B.
Saturn
C.
Uranus
D.
Venus
Answer:
D, Venus
Explanation:
Using the facts
Which layer is the igneous rock type?
options:
A
B
C
D
When a capacitor is charged, the electric field E, and hence the electric flux Φ, between the plates changes. This change in flux induces a magnetic field, according to Ampère's law as extended by Maxwell: ∮B⃗ ⋅dl⃗ =μ0(I+ϵ0dΦdt). You will calculate this magnetic field in the space between capacitor plates, where the electric flux changes but the conduction current I is zero. A parallel-plate capacitor of capacitance C with circular plates is charged by a constant current I. The radius a of the plates is much larger than the distance d between them, so fringing effects are negligible. Calculate B(r), the magnitude of the magnetic field inside the capacitor as a function of distance from the axis joining the center points of the circular plates. Express your answer in terms of μ0 and given quantities. B(r) =
The magnitude of the magnetic field B(r) inside the capacitor as a function of distance from the axis is [tex]\mathbf{B(r) =\dfrac{\mu_o I r}{2 \pi a^2} }[/tex]
A charged capacitor usually cause changes between the plates of electric field E and the electric flux Φ
As seen in Ampere's law which is extended by Maxwell:
[tex]\mathbf{\oint B^{\to} .dl^{\to} = \mu_o \Big( I+\dfrac{d \phi }{dt} \Big)}[/tex]
To meet the equilibrium equation of electric charge, Maxwell modified Ampere's law by incorporating the displacement current through into electric current component.
∴
The displacement current can be expressed by the relation;
[tex]\mathbf{I = \varepsilon_o \dfrac{dE}{dt} }[/tex]
From the given information, the displacement current density through area A can now be expressed as:
[tex]\mathbf{I = \varepsilon_o A \dfrac{dE}{dt} }[/tex]
Replacing the value of displacement current density into Maxwell modified Ampere Law, we have:
[tex]\mathbf{\oint B .dl= \mu_o I_{enclosed} }[/tex]
[tex]\mathbf{B \times (2 \pi r) = \mu_o I\Big (\dfrac{\pi r^2}{\pi a^2} \Big) }[/tex]
[tex]\mathbf{B(r) =\dfrac{\mu_o I r}{2 \pi a^2} }[/tex]
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See screen shot...momentum in collision
Please find attached photographs for your answer.
Hope it helps.
Do comment if you have any query.
A person travels from C to D. One third of the time travels at v1 = 42km/h, the rest of the time travels at v2 = 36km/h. Find his average speed as he travels from C to D.
Answer:39km/h
Explanation:we know V=(u+v)/2. Here is u=42 and v=36
why is all motion relative
Explanation:
All motions are relative to some frame of reference. Saying that a body is at rest, which means that it is not in motion, merely means that it is being described with respect to a frame of reference that is moving together with the body
Answer:
Motion is always described in relation to a reference point.
Explanation:
For example, if a car is driving at the speed of 30 miles per hour and you are standing by the road, to you, the car appears to be moving 30 miles per hour down the road. However, if you were in a car also driving at 30 miles per hour next to the truck, the same truck wouldn't appear to move.
Consider the following arrangement with a frictionless/massless pulley. Determine the force F required to move block A if the coefficient of static friction between block A and the floor is 0.35 and the coefficient of static friction between block A and block B is 0.25
Answer: The free - body diagrams for blocks A and B. frictionless surface by a constant horizontal force F = 100 N. Find the tension in the cord between the 5 kg and 10 kg blocks. The string that attaches it to the block of mass M2 passes over a frictionless pulley of negligible mass. The coefficient of kinetic friction Hk between M.
Explanation: Hope this helped :)
What is the Scientific name for Ectoparasites?
Ectoparasites are a taxonomically diverse group of organisms that infest the skin of human beings and other animals. Ectoparasitic arthropods and nematodes are similar in that an individual organism can produce skin lesions that are large enough to see with the unaided eye. Ectoparasitic infestations are often intensely itchy, causing considerable annoyance and discomfort. These conditions are often focally hyperendemic in impoverished communities, with a particularly high prevalence in vulnerable families, households, and neighborhoods.
Pediculosis (infestation by head and body lice) and scabies are found to some degree in all human populations, but myiasis (fly larva infestation), tungiasis (sand flea disease), and cutaneous larva migrans occur mainly in tropical and subtropical environments. Except for body lice, the organisms discussed in this article are not vectors of pathogenic microorganisms. In other words, most ectoparasites do not carry disease-causing agents; they are, instead, the direct cause of disease. Mortality is low, but the cumulative morbidity from the direct discomfort, secondary bacterial infections, and sequelae of those infestations and infections is considerable.
Despite the abundant presence of ectoparasitic infestations across human populations, biomedical science lacks firm evidence-based practices to reliably control these organisms. In addition, head lice and scabies are developing resistance to some chemical compounds employed to treat infested individuals, prevent spread, and control outbreaks.
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