Answer:
Volume of paint required is 3.125 litres.
Step-by-step explanation:
It would be noted that each side walls would have the shape of a trapezium. So that the areas of each wall can be determined as:
wall 1 = [tex]\frac{1}{2}[/tex](a + b) h
= [tex]\frac{1}{2}[/tex](0.5 + 1.5)2
= 2 [tex]m^{2}[/tex]
wall 2 = [tex]\frac{1}{2}[/tex](a + b) h
= [tex]\frac{1}{2}[/tex](1 + 3)2
= 4 [tex]m^{2}[/tex]
wall 3 = [tex]\frac{1}{2}[/tex](a + b) h
= [tex]\frac{1}{2}[/tex](0.5 + 1.5)2
= 2 [tex]m^{2}[/tex]
wall 4 = [tex]\frac{1}{2}[/tex](a + b) h
= [tex]\frac{1}{2}[/tex](1 + 3)2
= 4 [tex]m^{2}[/tex]
Total area of the walls = 2 + 2 + 4 + 4
= 12 [tex]m^{2}[/tex]
Area of the bottom base = l x b
= 1 x 0.5
= 0.5 [tex]m^{2}[/tex]
Total area to be painted = 12 + 0.5
= 12.5 [tex]m^{2}[/tex]
But to paint one square meter of a gap surface, we need 0.25 litres of a green paint color. Thus, to paint 12.5 [tex]m^{2}[/tex] of the gap surface:
12.5 x 0.25 = 3.125
The litres of paint required is 3.125.
Kyle built a tree house 4 ft. by 6 ft. What was the area of the tree house?
Find the area of a circle with radius, r = 5.72m.
Give your answer rounded to 2 DP.
r
The diagram is not drawn to scale.
Answer:
A≈102.79
Step-by-step explanation:
The formula for area of a circle is πr² so we need to substitute the r by 5.72.
π×5.7² = 102.79 m²
Answer:
Approximately 102.79 meters squared
Step-by-step explanation:
pi times 5.72 meters squared
Hope this helps!
PLZ ANSWER ILL GIVE BRAINLIEST
Answer:
B. neither perpendicular nor parallel
Step-by-step explanation:
to be perpendicular, the slopes have to be complete opposites. in this case, the second term would have to be y=-0.5x to be perpendicular. to be parallel, the two would have to have the same slopes; so y=2x and y=2x
The current population of Fun City is 21000 people. If the population of the city will double every 51 years then the population after 171 years would be
Answer:
The population of Fun City after 171 years would be 214563.
Step-by-step explanation:
The statement depicts a case of exponential growth, whose model is described below:
[tex]p(t) = p_{o}\cdot r^{\frac{t}{T} }[/tex] (1)
Where:
[tex]p_{o}[/tex] - Initial population, no unit.
[tex]p(t)[/tex] - Current population, no unit.
[tex]r[/tex] - Growth rate, no unit.
[tex]t[/tex] - Time, in years.
[tex]T[/tex] - Growth period, in years.
If we know that [tex]p_{o} = 21000[/tex], [tex]r = 2[/tex], [tex]t = 171\,yr[/tex] and [tex]T = 51\,yr[/tex], then the population of the city after 171 years is:
[tex]p(t) = 21000\cdot 2^{\frac{171}{51} }[/tex]
[tex]p(t) = 214563[/tex]
The population of Fun City after 171 years would be 214563.
h(x) = -4x – 7, when x = 3:
[tex]\displaystyle\bf h(x)=-4x-7\Longrightarrow h(3)=-4\cdot3-7=-19\\\\Answer:\boxed{ h(3)=-19}[/tex]
Answer:
-19
Step-by-step explanation:
heyya, so if x = 3 you just replace the x in the calculation to 3:
-4 *3 -7
= -12 -7
= -19
add the quotient of d and b and the difference of c and a
Answer:
d/b + c - a
Step-by-step explanation:
if there is nothing missing from the problem statement, then this is the only possible answer.
Insert three rational numbers between -2/3 and 3/4
Answer:
1/4, 1/2 and 1/3
Step-by-step explanation:
Rational numbers are numbers that can be expressed in the form a/b
So for ease of answering, we can just select values closer to the extremes given
so we can have 1/4, 1/2 and 1/3
These three numbers are all greater than the minimum extreme (-2/3) and less than the maximum extreme
W=VI. Make V the subject of formula
Answer:
hope that is helpful
Step-by-step explanation:
W= VI
W= VI
I. I
V= W
I
Answer:
V = [tex]\frac{W}{I}[/tex]
Step-by-step explanation:
Given
W = VI ( isolate V by dividing both sides by I )
[tex]\frac{W}{I}[/tex] = V
The Cooking Club made some pies to sell during lunch to raise money for a field trip. The cafeteria helped by donating three pies to the club. Each pie was then cut into six pieces and sold. There were a total of 72 pieces to sell. How many pies did the club make?
Which equation can be used to solve this problem? Select all that apply.
Find the equation of the line that
is perpendicular to y = -4x + 3
and contains the point (8, 1).
Answer:
x-4y=8
Step-by-step explanation:
y=mx+c comparing with given eq
we get slope(m1)=-4
since both are prependicular
m1×m2=-1
-4×m2=-1
m2=1÷4
eq:-y-y1=m2 (x-x1)
y-1=(1÷4)(x-8)
x-4y=4
P=(2,3,5,7) Express it in description method and in rule method.
Answer:
prime number between 1 to7
The description of set P is the set of prime numbers less than or equal to 7 and the rule is {x | x is a prime number less than or equal to 7}
How to describe the set of P?The set P is given as:
P = {2,3,5,7}
Note that the numbers are prime numbers.
This means that the description of set P is the set of prime numbers less than or equal to 7
The rule form of the set would be:
P = {x | x is a prime number less than or equal to 7}
Read more about sets at:
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Hey there I need some assistance need on this problem. What do I mean by checkpoints and how am I supposed to find the y-intercept and the slope from the given values?
Slope Formula: y2 - y1 / x2 - x1
(m and slope represent the same quantity)
m = 1 - - 5 / -4 - 0
m = 1 + 5 / -4
m = 6 / -4
m = -3/2
Now that we know the slope, we can plug the slope and one of our points into slope-intercept form (y = mx + b) and solve for b. I will be using the point (-4,1).
y = -3/2x + b
1 = -3/2(-4) + b
1 = 6 + b
b = -5
In point form, the y-intercept is (0, -5).
Therefore, to get the equation all we need to do is plug in our slope and b-value to slope-intercept form.
Equation: y = -3/2 x - 5
To check the point (-6, -14) we plug it into our equation and see if the two sides are equal.
-14 = -3/2(-6) - 5
-14 = 9 - 5
-14 = 4
-14 does not equal 4, therefore the point is NOT on the line.
Hope this helps!
Write a pair of integers whose sum gives: a) a negative integer
b) zero
c) an integer smaller than the both integers
Answer:
a) 4-5 = -1
b) -6+6 = 0
c) 6+(-4) = 2
solve in attachment....
Answer:
2 ( Option A )
Step-by-step explanation:
The given integral to us is ,
[tex]\longrightarrow \displaystyle \int_0^1 5x \sqrt{x}\ dx [/tex]
Here 5 is a constant so it can come out . So that,
[tex]\longrightarrow \displaystyle I = 5 \int_0^1 x \sqrt{x}\ dx [/tex]
Now we can write √x as ,
[tex]\longrightarrow I = \displaystyle 5 \int_0^1 x . x^{\frac{1}{2}} \ dx [/tex]
Simplify ,
[tex]\longrightarrow I = 5 \displaystyle \int_0^1 x^{\frac{3}{2}}\ dx [/tex]
By Power rule , the integral of x^3/2 wrt x is , 2/5x^5/2 . Therefore ,
[tex]\longrightarrow I = 5 \bigg( \dfrac{2}{5} x^{\frac{5}{2}} \bigg] ^1_0 \bigg) [/tex]
On simplifying we will get ,
[tex]\longrightarrow \underline{\underline{ I = 2 }}[/tex]
Answer:
A)2
Step-by-step explanation:
we would like to integrate the following definite Integral:
[tex] \displaystyle \int_{0} ^{1} 5x \sqrt{x} dx[/tex]
use constant integration rule which yields:
[tex] \displaystyle 5\int_{0} ^{1} x \sqrt{x} dx[/tex]
notice that we can rewrite √x using Law of exponent therefore we obtain:
[tex] \displaystyle 5\int_{0} ^{1} x \cdot {x}^{1/2} dx[/tex]
once again use law of exponent which yields:
[tex] \displaystyle 5\int_{0} ^{1} {x}^{ \frac{3}{2} } dx[/tex]
use exponent integration rule which yields;
[tex] \displaystyle 5 \left( \frac{{x}^{ \frac{3}{2} + 1 } }{ \frac{3}{2} + 1} \right) \bigg| _{0} ^{1} [/tex]
simplify which yields:
[tex] \displaystyle 2 {x}^{2} \sqrt{x} \bigg| _{0} ^{1} [/tex]
recall fundamental theorem:
[tex] \displaystyle 2 ( {1}^{2}) (\sqrt{1} ) - 2( {0}^{2} )( \sqrt{0)} [/tex]
simplify:
[tex] \displaystyle 2 [/tex]
hence
our answer is A
khairul order one set meal at a restaurant which offer a 20% discount. there is a service charge of 10% and GST is at 7% given that he pays a total of 23.54 find the marked price of the set meal
Answer:
Market price of set = 25.14
Step-by-step explanation:
Given:
Discount percentage = 20%
Service charge = 10%
GST = 7%
Amount pays = 23.54
FInd:
Market price of set
Computation:
Assume;
Market price of set = a
Market price of set after discount = a(1-20%)
Market price of set after discount = 0.80a
Market price of set after discount + (Market price of set after discount)(Service charge) + (Market price of set after discount)(GST) = Amount pays
0.80a + (0.80a)(10%) + (0.80a)(7%) = 23.54
0.80a + 0.08a + 0.056a = 23.54
0.936a = 23.54
a = 25.14
Market price of set = 25.14
what is the measure of < B ? help !!
The choose (C) 60
The measure of the angles of a triangle is 180, and this triangle is equilateral, so 180/3=60, each angle is 60°
What is the solution of ?
Answer:
x=12 is the answer
Step-by-step explanation:
[tex] \frac{5}{2} x - 7 = \frac{3}{4} x + 14[/tex]
[tex] \frac{5}{2} x - \frac{3}{4} x = 14 + 7[/tex]
[tex] \frac{10}{4} x - \frac{3}{4} x = 21[/tex]
[tex] \frac{7}{4} x = 21[/tex]
[tex]x = 21 \div \frac{7}{4} [/tex]
[tex]x = 21 \times \frac{4}{7} [/tex]
[tex]x = 3 \times 4[/tex]
[tex]x = 12[/tex]
Plz answer this
Optional math question
Answer:
Explanation is in the attachment
hope it is helpful to you
Fifth grade students from Garden City Elementary School left for a field trip at the time shown on the clock.(6:54am) They returned from the field trip at 10:24 p.M. How long were the students on this field trip?
Answer:
15 hour(s) and 30 minute(s).
Step-by-step explanation:
Answer:
krkrkrl4k3?8999kekek
Step-by-step explanation:
the UK. I have been a while. I have been a while. I have been a while. I have been a while 6e5 the UK. I have been a while. I have been a while. I have
. How do we have a look at the moment. The comments for the first time in the UK. I
Lisa plans to watch 3 movies each month. Write an equation to represent the total number of movies n that she will watch in m months.
Answer:
someone help call the police candice just got shot
Step-by-step explanation:
ahahahahahahahhahaa
Answer:
3m
Step-by-step explanation:
1 month =3 movies
m month =3*m movies
Someone help me please !!!!!
Answer:
a=15 and x=7
Step-by-step explanation:
first we need to plug in the number to the variable than we try to get a and x by themselves.
A 2-column table with 6 rows. The first column is labeled x with entries negative 4, negative 3, negative 2, negative 1, 0, 1. The second column is labeled f of x with entries negative 10, 0, 0, negative 4, negative 6, 0.
Which is a y-intercept of the continuous function in the table?
Hello,
[tex]\begin{array}{c|c|c|}&x&f(x)\\1&-4&-10\\2&-3&0\\3&-2&0\\4&-1&-4\\5&0&-6******\\6&1&0\\\end{array}\\[/tex]
y-intercept is -6
If x=0 then y=-6
Which of the following equations have no solutions?
Choose all answers that apply:
Α.
5x + 5 = -42 – 5
B
-4x + 5= -42 - 4
–4x + 5 = -4x – 5
D
4x + 5 = -4x + 5
Answer: b and c
a) 5x + 5 = -4x - 5
9x = - 10
x = -10/9
-
b) - 4x + 5 = -4x - 4
0x = -9 (no solution)
-
c) -4x + 5 = -4x - 5
0x = -10 (no solution)
-
d) 4x + 5 = -4x + 5
8x = 0
x = 0
-
hope it helps.
Also, I think that Brainly is an awesome app, but there's an app which is doing great work for me in maths, named Gauthmath. I will suggest it. Video concepts and answers from real tutors.
Two sides of a triangle have the following measures, Vind the range of possible measures for
the third side,
13) 8,7
14) 12,6
A) 1
B) 2 < x < 14
C) 1
D) 1
A) 8
B) 9
C) 8 < X < 18
D) 6 < X < 18
Answer:
[tex](13)\ 1 <x < 15[/tex]
[tex](14)\ 6 <x < 18[/tex]
Step-by-step explanation:
Question 13:
[tex]a,b = 8,7[/tex] -- the two sides
Using triangle inequality theorem, we have:
[tex]a + b > x[/tex]
[tex]a + x > b[/tex]
[tex]x + b > a[/tex]
So, we have:
[tex]a + b > x[/tex]
[tex]8 + 7 > x[/tex]
This gives:
[tex]15 > x[/tex]
[tex]a + x > b[/tex]
[tex]8 + x > 7[/tex]
Collect and evaluate like terms
[tex]x > -1[/tex]
[tex]x + b > a[/tex]
[tex]x + 7 > 8[/tex]
Collect and evaluate like terms
[tex]x > 1[/tex]
Ignore the inequality with a negative value.
So, we have:
[tex]x > 1[/tex] and [tex]15 > x[/tex]
Rewrite as:
[tex]1< x[/tex] and [tex]x < 15[/tex]
Merge
[tex]1 <x < 15[/tex]
Question 14:
[tex]a,b = 12,6[/tex] -- the two sides
Using triangle inequality theorem, we have:
[tex]a + b > x[/tex]
[tex]a + x > b[/tex]
[tex]x + b > a[/tex]
So, we have:
[tex]a + b > x[/tex]
[tex]12 + 6 > x[/tex]
This gives:
[tex]18 > x[/tex]
[tex]a + x > b[/tex]
[tex]12 + x > 6[/tex]
Collect and evaluate like terms
[tex]x > -6[/tex]
[tex]x + b > a[/tex]
[tex]x + 6 > 12[/tex]
Collect and evaluate like terms
[tex]x > 6[/tex]
Ignore the inequality with a negative value.
So, we have:
[tex]x > 6[/tex] and [tex]18 > x[/tex]
Rewrite as:
[tex]6< x[/tex] and [tex]x < 18[/tex]
Merge
[tex]6 <x < 18[/tex]
find the area of the rhombus. pic included, thank you
Answer:
80in 2
Step-by-step explanation:
Answer:
a=(d1×d2)÷2
(20×12)÷2
240/2
120
Please help me with this
Answer:
x = 23
Step-by-step explanation:
if line j is parallel to line k then
5x + 9 + 33 + x = 180 add like terms
6x + 42 = 180 subtract 42 from both sides
6x = 138 divide both sides by 6
x = 23
Which equation is NOT true?
Answer:
[tex]{ \bf{15x + 30 = 180}}[/tex]
A line has slope 3 and y–intercept 4.
Which answer is the equation of the line?
Answer:
y= 3x+4
Step-by-step explanation:
Slope-intercept form of an equation is
y=mx+b
m=slope
b=y-intercept
Just plug the values in and you get y=3x+4
Which is the best estimate of 162% of 79?
I think it's answer is 79 just guess
If a flexible air-filled container has a volume of 40 cu ft on the surface, what would the volume be at 99 feet in sea water
Answer:
50 cu ft
Step-by-step explanation:
The volume of flexible air filled container at 99 feet in sea water is 10 cu.ft.
What is Boyle's law?Boyle's Law states that If the temperature is constant, the volume of a gas is inversely proportional to the absolute pressure.
V 1/V2 =P2/P1
V2 = P1 x V1 /P2
Substitute 60 psi for P2, 14.7 psi for P1 and 40cu.ft for V1, we get the volume V2
V2 = 40 x 14.7 / 60
V2 = 9.8 cu.ft
Volume is approximately 10 cu.ft.
Thus, the volume of flexible air filled container at 99 feet in sea water is 10 cu.ft.
Learn more about Boyles law.
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