A Gallup poll asked 1200 randomly chosen adults what they think the ideal number of children for a family is. Of this sample, 53% stated that they thought 2 children is the ideal number. Construct and interpret a 95% confidence interval for the proportion of all US adults that think 2 children is the ideal number.
Answer:
at 95% Confidence interval level: 0.501776 < p < 0.558224
Step-by-step explanation:
sample size n = 1200
population proportion [tex]\hat p[/tex]= 53% - 0.53
At 95% confidence interval level;
level of significance ∝ = 1 - 0.95
level of significance ∝ = 0.05
The critical value for [tex]z_{\alpha/2} = z _{0.05/2}[/tex]
the critical value [tex]z _{0.025}= 1.96[/tex] from the standard normal z tables
The standard error S.E for the population proportion can be computed as follows:
[tex]S,E = \sqrt{\dfrac{\hat p \times (1-\hat p)}{n}}[/tex]
[tex]S,E = \sqrt{\dfrac{0.53 \times (1-0.53)}{1200}}[/tex]
[tex]S,E = \sqrt{\dfrac{0.53 \times (0.47)}{1200}}[/tex]
[tex]S,E = \sqrt{\dfrac{0.2491}{1200}}[/tex]
[tex]S,E = 0.0144[/tex]
Margin of Error E= [tex]z_{\alpha/2} \times S.E[/tex]
Margin of Error E= 1.96 × 0.0144
Margin of Error E= 0.028224
Given that the confidence interval for the proportion is 95%
The lower and the upper limit for this study is as follows:
Lower limit: [tex]\hat p - E[/tex]
Lower limit: 0.53 - 0.028224
Lower limit: 0.501776
Upper limit: [tex]\hat p + E[/tex]
Upper limit: 0.53 + 0.028224
Upper limit: 0.558224
Therefore at 95% Confidence interval level: 0.501776 < p < 0.558224
Please help me Tramserran mam...
Answer: see proof below
Step-by-step explanation:
Use the following when solving the proof...
Double Angle Identity: cos2A = 1 - 2sin²B
Pythagorean Identity: cos²A + sin²A = 1
note that A can be replaced with B
Proof from LHS → RHS
Given: cos²A + sin²A · cos2B
Double Angle Identity: cos²A + sin²A(1 - 2sin²B)
Distribute: cos²A + sin²A - 2sin²A·sin²B
Pythagorean Identity: 1 - 2sin²A·sin²B
Pythagorean Identity: cos²B + sin²B - 2sin²A·sin²B
Factor: cos²A + sin²B(1 - 2sin²A)
Double Angle Identity: cos²B + sin²B · cos2A
cos²B + sin²B · cos2A = cos²B + sin²B · cos2A [tex]\checkmark[/tex]
What is the volume of this rectangular prism?
3 cm
cm
1
cm
Answer:
.75cm³
Step-by-step explanation:
To find the volume of a shape like this it is,
base×height×width.
In this case it is .5×.5×3=.75cm³
Answer:
3/4 or 0.75
Step-by-step explanation:
Length times width times height:
1/2 * 1/2 * 3
= 3/4
Simplify 6 to the second power
Answer:
36Step-by-step explanation:
[tex]6^2 =6\times 6\\\\= 36[/tex]
The ratio of two numbers is 2:3 and the sum of their cubes is 945,what are the two numbers. let the 1st no be=2x and 2nd=3x (2x)^3 + (3x)^3=945
Answer:
The first number is 6, the second number is 9Step-by-step explanation:
a:b = 2:3
a = 2x - first number
b = 3x - second number
a³ + b³ = 945
[tex](2x)^3 + (3x)^3=945\\\\8x^3 +27x^3=945\\\\35x^3 = 945\\\\x^3=945:35\\\\x^3=27\\\\ x^3=3^3\\\\x=3\\\\\\a=2\cdot3 = 6\\\\b=3\cdot3=9[/tex]
The marketing department at Quality Home Improvement Center (QHIC) uses simple linear regression analysis to predict home upkeep expenditure on the basis of home value. Predictions of home upkeep expenditures are used to help determine which homes should be sent advertising brochures promoting QHIC's products and services.
Full question :
The Tasty Sub Shop Case:
A business entrepreneur uses simple linear regression analysis to predict the yearly revenue for a potential restaurant site on the basis of the number of residents living near the site. The entrepreneur then uses the prediction to assess the profitability of the potential restaurant site.
And
The QHIC Case:
The marketing department at Quality Home Improvement Center (QHIC) uses simple linear regression analysis to predict home upkeep expenditure on the basis of home value. Predictions of home upkeep expenditures are used to help determine which homes should be sent advertising brochures promoting QHIC’s products and services.
Discuss the difference in the type of prediction in both cases and provide rational of the reasons that these predictions were used.
Answer and explanation:
In the first case, The Tasty Sub Shop Case, the entrepreneur aims to utlilize the predicted values from his regression analysis in ascertaining profit of his potential business. He does this using the values from number of residents in the area(independent variables) to predict the revenue for his business(dependent variables). His predictions using the number of residents in the area are largely because the residents in the area are his target consumers and are the ones to buy food from his restaurant and increase his revenue.
In the other case, the marketing department in QHIC utilizes the predicted values in determining their customers who need to be aware of their products. They get the predicted values(home upkeep expenditure and dependent variable) by plotting their relationship with home value(independent variable) and then use predicted values of home upkeep expenditures in determining their customers who they will market their products to. They do this because predicting home upkeep expenditures will enable them determine what homes can afford or will need their products and services.
one utilizes his predictions at ascertaining profit while the other uses his predictions in determining potential customer base to market products to. The first case is making a revenue/ profitability prediction while the other is making a market prediction
If a and b are acute angles such that tan (a+b)= 1.73 and tan(a-b) =1/1.73, find a and b
[tex] \LARGE{ \underline{ \boxed{ \orange{ \rm{Solution:)}}}}}[/tex]
Given,tan (a + b) = 1.73 [tex]\approx[/tex] √3tan (a - b) = 1 / 1.83 [tex]\approx[/tex] 1 / √3To find:Value of a and b in degrees....?Solution:☃️ Refer to the trigonometric table....
Then, proceeding
⇛ tan 60 ° = √3
⇛ tan 60° = tan (a + b)
⇛ 60° = a + b
Flipping it,
⇛ a + b = 60° --------(1)
And,
⇛ tan 30° = 1 / √3
⇛ tan 30° = tan (a - b)
⇛ 30° = a - b
Flipping it,
⇛ a - b = 30° ---------(2)
Now adding eq.(1) and eq.(2),
⇛ a + b + a - b = 60° + 30°
⇛ 2a = 90°
⇛ a = 90° / 2
⇛ a = 45°
Putting value of a in eq.(1),
⇛ 45° + b = 60°
⇛ b = 15°
☄ So, Our Required answers:
a = 45°b = 15°━━━━━━━━━━━━━━━━━━━━
when simplifying the expression y=(2x(x-3)(x-3))/(x-1)(x-3) do all of the x-3 s get cancelled or just one in the numerator and one in the denominator?
Answer:
x-3 is cancelled and just one remains in numerator.
A movie theater conducted a survey to see what customers preferred at the concession stand. The theater asked every fifth person who entered the movie theater every Friday for a month what his or her favorite movie snack was. Were the results of the survey valid? A. No, because the theater did not survey everyone in the theater. B. Yes, because the theater only surveyed children. C. Yes, because the theater surveyed a random sample. D. No, because the theater did not use a random sample.
Answer:
A) No because the theater did not survey everyone in the theater.
Answer:
Yes, because the theater surveyed a random sample.
Step-by-step explanation:
The survey is valid because there was a random sample. They surveyed every fifth person, so there was a variety of age groups, genders, and preferences included in the sample. Therefore, the correct answer is yes, because the theater surveyed a random sample.
Write a function rule for the table
х
f(x)
0
3
1
4
2
5
3
6
Answer:
f(x) = x +3
Step-by-step explanation:
The first differences for adjacent x-values are all 1, so this is a linear function. Because those differences are all 1, it is a linear function with a slope of 1. We observe that f(0) = 3, so that is the y-intercept.
__
The slope-intercept form of a linear function is ...
y = mx + b . . . . . where m is the slope (1) and b is the y-intercept (3).
A suitable function rule is ...
f(x) = x +3
Solve for x : 2^(x-5) . 5^(x-4) = 5
Answer:
x = 5
Step-by-step explanation:
Notice that there is also a base 5 on the right hand side of the equation, therefore, let's move [tex]5^{x-4}[/tex] to the right by dividing both sides by it. and then re-writing the right hand side as 5 to a power:
[tex]2^{x-5}\,*\,5^{x-4}=5\\2^{x-5}=5/5^{x-4}\\2^{x-5}=5\,*\,5^{4-x}\\2^{x-5}=5^{5-x}[/tex]
Now apply log to both sides in order to lower the exponents (where the unknown resides):
[tex](x-5)\,log(2)=(5-x)\,log(5)[/tex]
Notice that when x = 5, this equation is true because it makes it the identity: 0 = 0
So, let's now examine what would be the solution of x is different from 5, and we can divide by (x - 5) both sides of the equation:
[tex]log(2)=\frac{5-x}{x-5} \,log(5)\\log(2)=-1\,\,log(5)\\log(2)=-log(5)[/tex]
which is an absurd because log(2) is [tex]\neq[/tex] from log(5)
Therefore our only solution is x=5
Answer:
if decimal no solution
if multiply x =5
Step-by-step explanation:
If this is a decimal point
2^(x-5) . 5^(x-4) = 5
Rewriting .5 as 2 ^-1
2^(x-5) 2 ^ -1 ^(x-4) = 5
We know that a^ b^c = a^( b*c)
2^(x-5) 2 ^(-1*(x-4)) = 5
2^(x-5) 2 ^(-x+4) = 5
We know a^ b * a^ c = a^ ( b+c)
2^(x-5 +-x+4) = 5
2^(-1) = 5
This is not true so there is no solution
If it is multiply
2^(x-5) * 5 ^(x-4) = 5
Divide each side by 5
2^(x-5) * 5 ^(x-4) * 5^-1 = 5/5
We know that a^ b * a^c = a^ ( b+c)
2^(x-5) * 5 ^(x-4 -1) = 1
2^(x-5) * 5 ^(x-5) = 1
The exponents are the same, so we can multiply the bases
a^b * c*b = (ac) ^b
(2*5) ^ (x-5) = 1
10^ (x-5) = 1
We know that 1 = 10^0
10^ (x-5) = 10 ^0
The bases are the same so the exponents are the same
x-5 = 0
x=5
An air traffic controller spots two airplanes at the same altitude converging to a point as they fly at right angles to each other. One airplane is 150 miles from the point and has a speed of 300 miles per hour. The other is 200 miles from the point and has a speed of 400 miles per hour.(a) At what rate is the distances between the planes decreasing?(b) How much time does the air traffic controller have to get one of the planes on a different flight path?
Answer:
The answer to this question can be defined as follows:
In option A, the answer is "- 357.14 miles per hour".
In option B, the answer is "-0.98".
Step-by-step explanation:
Given:
[tex]\frac{dx}{dt} =- 300 \text{ miles per hour}[/tex]
[tex]\frac{dy}{dt} =- 400 \text{ miles per hour}[/tex]
find:
[tex]\frac{ds}{dt} =?[/tex] when
[tex]x= 150 \\y= 200\\s=x+y\\\\[/tex]
[tex]= 150+200 \\\\=350[/tex]
[tex]\to s^2=x^2+y^2\\[/tex]
differentiate the above value:
[tex]\to 2s\frac{ds}{dt}= 2x \frac{dx}{dt}+2y \frac{dy}{dt}[/tex]
[tex]\to 2s\frac{ds}{dt}= 2(x \frac{dx}{dt}+y \frac{dy}{dt})\\\\\to \frac{ds}{dt}= \frac{(x \frac{dx}{dt}+y \frac{dy}{dt})}{s}\\\\[/tex]
[tex]= \frac{(150 \times -300 +200 \times -400 )}{350}\\\\= \frac{-45000+ (-80000) }{350}\\\\= \frac{- 125000 }{350}\\\\= - 357.14 \ \text{miles per hour}[/tex]
In option B:
[tex]\to d=rt\\\\ \to t= \frac{d}{r}[/tex]
[tex]\to \ \ d= 350 \ \ \ \ \ \ r= -357.14\\[/tex]
[tex]\to t= - \frac{350}{357.14}\\\\\to t= - 0.98[/tex]
when the point ( k, 3 ) lies on each of these lines, find the value of k y= 3x+1 , y= 4x-2 , y=1/2x - 1 and 2x+3y=4
Answer:
see explanation
Step-by-step explanation:
Since (k, 3) lies on each of the lines, the point satisfies the equations.
Substitute x = k, y = 3 into each and solve for k
y = 3x + 1
3 = 3k + 1 ( subtract 1 from both sides )
2 = 3k ( divide both sides by 3 )
k = [tex]\frac{2}{3}[/tex]
-------------------------------------------------------
y = 4x - 2
3 = 4k - 2 ( add 2 to both sides )
5 = 4k ( divide both sides by 4 )
k = [tex]\frac{5}{4}[/tex]
--------------------------------------------------------
y = [tex]\frac{1}{2}[/tex] x
3 = [tex]\frac{1}{2}[/tex] k ( multiply both sides by 2 to clear the fraction )
k = 6
---------------------------------------------------------
2x + 3y = 4
2k + 3(3) = 4
2k + 9 = 4 ( subtract 9 from both sides )
2k = - 5 ( divide both sides by 2 )
k = - [tex]\frac{5}{2}[/tex]
Need to find the Domain and Range
Answer:
D: {x∈R | -2 ≤ x ≤ 2 }
R: {y∈R | 0 ≤ y ≤ 4 }
Step-by-step explanation:
The domain ranges between -2 and 2
The range ranges between 0 and 4
Parabolic microphones are used for field audio during sports events. The microphones are manufactured such that the equation of their cross section is x=1/34y^2, in inches. The feedhorn part of the microphone is located at the focus
a. How far is the feedhorn from the edge of the parabolic surface of the microphone?
b. What is the diameter of the microphone? Explain your reasoning
c. If the diameter is increased by 5 inches, what is the new equation of the cross section of the microphone?
Answer:
a. 8.5 in.
b. 34 in
c. x = 1/39 x^2.
Step-by-step explanation:
Part a.
x = 1/34 y^2
y^2 = 34x
Comparing with y^2 = 4px where p is the focus:
4p = 34
p = 8.5 in.
Part b.
The diameter = 4p = 34 in.
Part c.
Diameter = 4p = 34 + 5 = 39 in
The new equation is x = 1/39 x^2.
According to data from the U.S. Department of Education, the average cost y of tuition and fees at public four-year institutions in year x is approximated by the equation where x = 0 corresponds to 1990. If this model continues to be accurate, during what year will tuition and fees reach $4000?
Answer:
Graphing Calculator
Step-by-step explanation:
Two shaded identical rectangular decorative tiles are first placed (one each) at the top and at the base of a door frame for a hobbit's house, as shown in Figure 1. The distance from W to H is 45 inches. Then the same two tiles are rearranged at the top and at the base of the door frame, as shown in Figure 2. The distance from Y to Z is 37 inches. What is the height of the door frame, in inches?
Answer:
41 inches
Step-by-step explanation:
Let the point at the top of the door on the left be x
Wx + xH = 45
Let the point at the top of the door on the right be c
Yc + cZ = 37
We know the door is
xH + plus the width of the tile
The width of the tile is Yc
xH + Yc
On the right door
cZ + the height of the tile
cZ + Wx
Add the two doors together
xH + Yc + cZ + Wx = 2 times the height of the door
Rewriting
xH + Wx + Yc + cZ = 2 times the height of the door
45+ 37 = 2 times the door height
82 = 2 times the door height
Divide by 2
41 = door height
What is the answer??
c — 10 ≥ 15
Answer:
Step-by-step explanation:
c - 10 ≥ 15 =
c ≥ = 15 + 10
c ≥ = 25
c = 26 ( or numbers above 26)
Simplify the expression a-2b, when a=1.4 - 2x and b=-0.2x + 1.7 *
Answer:
a-2b= -1.6x-2.0
Step-by-step explanation:
[tex]a=1.4-2x\\b=-0.2x+1.7\\a-2b= (1.4-2x)-2(-0.2x+1.7)\\a-2b= 1.4-2x+0.4x-3.4\\a-2b=-1.6x-2.0\\[/tex]
{By, substituting the values of a and b in a-2b , we can find the value of a-2b}
ux=x+y/k, solve for x
Answer:
x = y/( ku-1)
Step-by-step explanation:
Here in this question, we are asked to solve for x.
we have;
Ux = x+ u/ k
cross multiply;
k * Ux = x + y
kUx = x + y
kUx- x = y
x(KU-1) = y
x = y/( ku-1)
Find the missing the side of the triangle A. 130−−−√ m B. 179−−−√ m C. 42–√ m D. 211−−−√ m
Answer:
The answer is option AStep-by-step explanation:
Since the triangle is a right angled triangle we can use the Pythagoras theorem to find the missing side
Using the Pythagoras theorem
That's
[tex] {a}^{2} = {b}^{2} + {c}^{2} [/tex]
From the question
x is the hypotenuse or the longest side of the triangle
Substituting the values into the above formula we have
[tex] {x}^{2} = {9}^{2} + {7}^{2} [/tex]
[tex] {x}^{2} = 81 + 49[/tex]
[tex] {x}^{2} = 130[/tex]
Find the square root of both sides
We have the final answer as
x = √130 mHope this helps you
PLEASE HELP!! It’s for a math class and I can’t figure it out been trying every website nothing has helped!
Answer:
11.6%
I hope this helps!
What is the rule for the transformation below?
=================================================
Explanation:
The translation notation T(-5, 3) looks like an ordered pair point, but it is not. Instead, it is a rule to tell you how to shift any point left/right and up/down. The first number is the left/right shifting as its done along the x axis. The negative value means we shift left, so we shift 5 units to the left. The positive 3 in the y coordinate place means we shift 3 units up.
We see this shifting happen when we go from
A = (-1, -1) to A ' = (-6, 2) B = (2, 3) to B ' = (-3, 6)C = (5, -3) to C ' = (0, 0)The translation notation T(-5, 3) is the same as writing [tex](x,y) \to (x-5, y+3)[/tex] which may be a more descriptive notation to use, and it would avoid confusion with ordered pair point notation.
Write each expression using a positive exponent. ("/" means division)("^" means to the power of) 9^-4
Answer:
[tex]\frac{1}{9^4}[/tex].
Step-by-step explanation:
[tex]9^{-4}[/tex]
= [tex]\frac{1}{9^4}[/tex]
= [tex]\frac{1}{9 * 9 * 9 * 9}[/tex]
= [tex]\frac{1}{81 * 81}[/tex]
= [tex]\frac{1}{6561}[/tex]
= 0.0001524157903.
Hope this helps!
the sum of 35 and one fifth part of itself is added to the sum of one seventh of 11 and 8
Answer:
313/7
Step-by-step explanation:
Here, we are interested in turning the wordings of the statement to numeric values.
We take it one at a time.
Sum of 35 and 1/5(35) = 35 + 7 = 42
This is added to 1/7(11 + 8)
= 1/7(19) = 19/7
So we have;
42 + 19/7 = (294 + 19)/7 = 313/7
need help...!!ASAP..!! plz....
the answer for this is A
Answer:
Correct option is A
Step-by-step explanation:
3x - 7
Three times a number x minus 7
Or
The difference of there times a number and 7
2x + 3y = 40
5x + 2y = 30
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Hi my lil bunny!
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A) Let's solve for x. [tex]2x + 3y = 40[/tex]
Step 1: Add -3y to both sides.
[tex]2x + 3y + -3y = 40 + -3y[/tex]
[tex]2x = -3y + 40[/tex]
Step 2: Divide both sides by 2.
[tex]\frac{2x}{2} = \frac{-3y + 40}{2}[/tex]
[tex]x = \frac{-3}{2} y + 20[/tex]
Answer : [tex]\frac{-3}{2} y + 20[/tex]
~~~~~~~~~~~~~~~~~
B) Let's solve for x. [tex]5x + 2y = 30[/tex]
Step 1: Add -2y to both sides.
[tex]5x + 2y + -2y = 30 + -2y[/tex]
[tex]5x = -2y + 30[/tex]
Step 2: Divide both sides by 5.
[tex]\frac{5x}{5} = \frac{-2y + 30}{5}[/tex]
[tex]x = \frac{-2}{5} y + 6[/tex]
Answer : [tex]\frac{-2}{5} y + 6[/tex]
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Hope this helped you.
Could you maybe give brainliest..?
❀*May*❀
For all x, 5-3(x-4)=?
Answer:
the answer that i find is 17-3x
One hundred people, ages 11-15, were randomly surveyed to find their opinion of their favorite leisure time activity. Sixty-four percent of them said they liked to spend time watching TV. If there are 1500 students in your school, about how many of them would you predict would enjoy watching t.v. A.2343 B.960 C.640 D.500
Answer:
If there are 1500 students in your school then 960 students would enjoy watching TV
Step-by-step explanation:
Step 1: We know that 64% of kids aged from 11 to 15 enjoy watching TV and there is 1500 students in your school
Step 2: We now want to find 64% of 1500, we can rewrite 64% as 0.64. We multiple 1500 by 0.64 to find out how many students enjoy watching TV
0.64 x 1500 = # of students who like watching TV
960 = # of students who like watching TV
Therefore out of 1500 students, 960 would enjoy watching TV
If everybody on the team scores 6 points, and the team has a total of 42 points, how many people are on the team? 6 p = 42 7 p = 42 6 + p = 42 42 - p = 6
If everybody on the team scores 6 points, and the team has a total of 42 points, the people that are on the team are 7 people.
What is addition?The addition is one of the four basic mathematical operations, the others being subtraction, multiplication, and division. When two whole numbers are added together, the total quantity or sum of those values is obtained.
The addition is a method of merging items and counting them as a single, large group. In mathematics, addition is the process of joining two or more integers.
The process of adding two or more numbers together to get their sum is known as an addition. The addition is a fundamental arithmetic operation that is used to compute the sum of two or more numbers. For instance, 7
+ 7 = 14.
6p = 42
P = 42/6
P = 7
Therefore, the people that are on the team are 7 people.
To learn more about addition, refer to the link:
https://brainly.com/question/29560851
#SPJ2
[tex] \frac{ {9x}^{2} - {(x}^{2} - 4) {}^{2} }{4 + 3x - {x}^{2} } [/tex]
pls help me need help asap
Answer:
[tex] { x^2+3x-4} [/tex]
Step-by-step explanation:
Factor top and bottom.
The numerator is a difference of two squares, and the denominator is a quadratic.
[tex] \frac{ {9x}^{2} - {(x}^{2} - 4)^{2} }{4 + 3x - {x}^{2} } [/tex]
= [tex]\frac{ (3x+x^2-4)(3x-x^2+4) }{(1+x)(4-x)}[/tex]
= [tex] \frac{ (x-1)(x+4) (1+x)(4-x) }{(1+x)(4-x)} [/tex]
If x does not equal -1 and does not equal 4, we can cancel the common factors in italics to give
= [tex] { (x-1)(x+4)} [/tex]
= [tex] { x^2+3x-4} [/tex]
Answer:
The answer is
x² + 3x - 4Step-by-step explanation:
[tex] \frac{9 {x}^{2} - ( { {x}^{2} - 4})^{2} }{4 + 3x - {x}^{2} } [/tex]
To solve the expression first factorize both the numerator and the denominator
For the numerator
9x² - ( x² - 4)²
Expand the terms in the bracket using the formula
( a - b)² = a² - 2ab + b²
(x² - 4) = x⁴ - 8x² + 16
So we have
9x² - (x⁴ - 8x² + 16)
9x² - x⁴ + 8x² - 16
- x⁴ + 17x² - 16
Factorize
that's
(x² - 16)(-x² + 1)
Using the formula
a² - b² = ( a + b)(a - b)
We have
(x² - 16)(-x² + 1) = (x + 4)(x - 4)( 1 - x)(1 + x)
For the denominator
- x² + 3x + 4
Write 3x as a difference
- x² + 4x - x + 4
Factorize
That's
- ( x - 4)(x + 1)
So we now have
[tex] \frac{(x + 4)(x - 4)( 1 - x)(1 + x)}{ - (x - 4)(x + 1)} [/tex]
Simplify
[tex] \frac{ - (x + 4)(1 - x)(1 + x)}{x + 1} [/tex]
Reduce the expression by x + 1
That's
-( x + 4)( 1 - x)
Multiply the terms
We have the final answer as
x² + 3x - 4Hope this helps you
