A distribution of class scores on a test is approximately normal with a mean of 75 and a
standard deviation of 8. Edna scores an 85%. Does her score place her in the top 10% of
this class?
O A. No, 10.6% of the class scored above her test score
B. Yes, 10.6% of the class scored above her test score
C. No, she scored better than 10.6% of her classmates
D. Yes, less than 10% of the class scored better than her test score

Answers

Answer 1

Answer:

O A. No, 10.6% of the class scored above her test score

Explanation:

Using the standard normal distribution (Z score) to solve this problem. The formula is as follows:

Z = x - μ/σ

Where;

σ = standard deviation

μ = mean score

x = Edna's score

According to the information given in this question:

σ = 8

μ = 75%

x = 85%

Z = 85 - 75/8

Z = 10/8

Z = 1.25

Using the table of normal distribution probabilities, we check for Z score of 1.2 under 5 = 0.8944

This means that Edna's percentage score is 89.44%. Hence, (100 - 89.44) = 10.56% is above Edna's score in the class

Approximately, 10.6% of the class scored above Edna's test score, meaning that she is not among the top 10% of her class.


Related Questions

b) The chemical equation below summarizes photosynthesis.
Energy (sunlight) + 6 H20 + 6 CO2 - C6H1206 + 6 02
Write a similar chemical equation for cellular respiration. Be sure to include a
description of the form of energy that results from cellular respiration. (3 points)
Pls help me

Answers

Answer:

The chemical equation for cellular respiration would be: C6H12O6 + 6 O2 → 6 CO2 + 6 H2O.

Explanation:

C6H12O6 (1 Glucose molecule) + 6 O2 (6 Oxygen molecules)  → 6 CO2 (6 Carbon dioxide molecules) + 6 H2O (6 Water molecules)

19. What percent of forest is found in Nepal at present? 1. 50% 2. 28% 3. 29% 4. 39%​

Answers

Answer:

1. 50%

hola hai

have a great dayy

How can algal blooms be
harmful to an aquatic
environment?

A. by blocking all sunlight and killing the bottom plants
causing no oxygen to go into the water

B. by putting oxygen up into the air for the
surrounding plants

C. by absorbing the phosphorus in the atmosphere and
having a symbiotic relationship with cyanobacteria

Answers

Answer:

(A) By blocking all sunlight and killing the bottom plants

causing no oxygen to go into the water

What bug is this please help I found it on the ground and want to make it my pet I need answers ASAP what bug is this please

Answers

Maybe European earwig or normal earwig kinda hard to see

A student is conducting their science experiment on the effects of sugar on bullfrogs. He has 3 groups of test subjects. 1 group of frogs that receives nothing, they are the control group. The 2nd group of frogs receives half a sugar pill each, and the 3rd group receives a whole sugar pill each. He will measure their activity levels and jump heights after giving them the pills. When he is setting up his data table, what should go in the first column?

Answers

Answer:

Group 1 of frogs.

Explanation:

It is the first thing because you have to note which of the frogs you're talking about before you start.

Which species of gymnosperms has reddish cones and strap like leaves that tear up from the harsh desert conditions?

A. gnetum
B. welwitschia
C. ephedra

Answers

Answer:

welwitschia

Explanation:

hello guys, Define wave length.I think this will be easy for u guys good day thank u​

Answers

Answer:

the distance between successive crests of a wave, especially points in a sound wave or electromagnetic wave.

Explanation:

Please tell me if it helps

Climate change as well as other human-driven environmental changes continue to cause loss of biodiversity in the
coming decades in addition to high rates of species extinctions. Biodiversity is a term that can be used to describe
biological diversity at a variety of different scales, but for now let's consider species diversity. Each rectangle represents a
plant community containing individuals of various species indicated by color and the total number of individuals
corresponds to the productivity of the ecosystem. Based on trends illustrated by the images, what conclusions apply?
Choose ALL that are appropriate.
-)))
A)
While species may fluctuate, biomass remains constant.
Scientific
Calc
B)
The green species increases in abundance during warm years,
C)
The productivity of the ecosystem decreases as the climate changes.
D)
Invasive species, represented by red, move in and displace native
species.
Highlight
Time
maining
3:17:40
e Tools
E)
Decrease in one species is compensated for by an increase in another
species.
24)

Answers

Answer:

e) decrease in one species is compensated for by an increase in another. is the answer.☺️

which statement describes a process associated with meiosis

Answers

Answer:

homologous chromosomes pair up

Answer:

Haploid cells join to form an organism that has a complete set of chromosomes.

Explanation:

3. Define the following terms A) Transparent B) Translucent c) Opaque​

Answers

Answer:

Transparent-->Allows all light to pass through.

Translucent-->Allows only some/partial light to pass through.

Opaque-->Allows no light to pass through.

New world monkeys have:______.
a. None of the above
b. have short legs and no tails to help them balance on top of the branches where they walk
c. have prehensile tails to aid in their 3-D movement through the trees
d. have broad and flat bodies with the scapula on the back of the ribcage, allowing a greater range of motion in the shoulder and for them to hold their arms above their heads.

Answers

Answer:

d num have broad and flat bodies

Answer:

C. have prehensile tails to aid in their 3-D movement through the trees

Explanation:Monkeys need tails to balance themselves when walking and jumping from tree to tree

part of the eye that gives people different eye colors​

Answers

the answer to this question is iris

plz give a correct answer for the question how do canine and molar differ.​

Answers

Answer:

Canine teeth is conical in structure and it is used to tear meat but the molar teeth has two or three cusps and is used for grinding food

Describe ways that water pollution occurs. Describe how greenhouse gases contribute to climate change.

Answers

Greenhouse gases are transparent to incoming (short-wave) radiation from the sun but block infrared (long-wave) radiation from leaving the earth's atmosphere. This green house effect traps radiation from the sun and the planet's surface.

I need help! Pls help!!!

Answers

(iii) Enzymes P, Q and R (choose any one)

P - pepsin / protease

Q - amylase / carbohydrase

R - lipase / trypsin / protease / amylase

(c) There are many ways in which different types of enzymes are using in preparing baby foods such as the amylase breaks down the starch and the starch breaks down to maltose or glucose. The protease breaks down protein and the protein breaks down into amino acids. The lipase breaks down fats and then the fats break down to gylcerol.

Hope it's help you.If it is right

The difference between active transport and passive transport is that a. concentration gradients are involved in one and not in the other. b. glycolipids play a role in one and not in the other. c. one requires expenditure of energy by the cell and the other does not. d. ions are transported into and out of the cell by one process and not by the other.

Answers

Answer:

D) ions are transported into and out of the cell by one process and not by the other

A population of lab rats recently escaped into the sewer system of Washington, D.C. A brave researcher sampled this population and estimated the following phenotypic frequencies (which were caused by a single gene with two alleles: E and e).
61% normal eyes (EE)
26% cross-eyed (Ee)
13% blind (ee)
If this population were to reach a Hardy-Weinberg Equilibrium (HWE) in one generation, what would the phenotypic frequencies be in that new HWE generation? Let freq (e)=p and freq (e)=q. (Tip first calculate p and q from the observed, and provided, phenotypic frequencies)
freq EE =
freq Ee =
freq ee =

Answers

Answer:

freq EE = 0.55 freq Ee = 0.38  freq ee = 0.07

Explanation:

Due to technical problems, you will find the complete explanation in the attached files.

The structure that hotds two chromosomes together until they separate for cett divisionois




1.chromatid .

2.cytoplasm .

3.chromatin .

4.centromere

Answers

The answer is 4. Centromere

When observing a group of children at a daycare center, Emily made the following observations:
Five year old children played in one location during independent play time. Three year old children moved between different activities, rather than staying in one location.
By analyzing Emily’s observations, what could be a valid conclusion?
a.
Five-year-old children have longer attention spans than three-year-old children.
b.
Three year old children do not like being in daycare.
c.
Five-year-old children are favored over three-year-old children at the daycare center.
d.
Three-year-old children are favored over five-year-old children at the daycare center.

Answers

Answer:

the answer is a

Explanation:

you can read twice. it show the 5 year emily have longer attention. thay why he see 3 year children go around

the answer is a. five year olds have a longer attention span which means that they can do one activity for a longer amount of time. three year olds are easily distracted so it would be more beneficial to keep them intrigued with multiple short activities.

Traditionally, the classification of fungi has been based on the nature of sexual stages of the life cycle. For Penicillium, however, no sexual stages of the life cycle have been observed. Without evidence from sexual stages, speculate about other possible sources of evidence that scientists may use in classification.

Answers

Answer:

Without the evaluation of sexual stages, fungi can be classified according to the type of colony they present, the speed of growth, the formation of pigments and the type of coloration.

Explanation:

Although the observation of sexual stages is extremely efficient for the classification of fungi in the laboratory. This type of analysis is not always possible to be carried out. In that case, scientists need to find other methods that allow for the classification of fungi. These methods are carried out with the help of a microscope, where scientists observe the morphology of the fungi and are able to classify them according to the type of colony they present, the speed of growth, the formation of pigments and the type of coloration.

The endogenous cholesterol synthesis by the liver that we need to function normally it can lead to
plaque formation within the blood vessels.
Оа.
False
b. True

Answers

I believe the answer is true. Hope this helps !!

Answer:

It should be true

Explanation:

online health class and quick double check

What is the process of
evaporation?

A. The process in which plants release vapor into
the atmosphere

B. Any process that returns water from the
atmosphere to the earth

C. The process in which liquid water turns to
water vapor

Answers

The answer to your question is C

Given that the intracellular concentration of potassium is 150 mEq/L, how would the potassium equilibrium potential be affected if the extracellular concentration of potassium is changed from 5.0 to 3.5 mEq/L

Answers

Answer:

The potassium equilibrium potential would increase, meaning that more K+ would be leaving the cell.

Explanation:

Let us assume that the only ion transported through the cell membrane is K+. We need to use the Nernst equation to know the destiny of the ion.

Nernst equation:

E = 58 millivolts/z. [Log₁₀ (C-out/C- in)

Where,    

• E = Equilibrium potential

• 58 millivolts/z = Constant

• z = Ion charge + positive or negative symbol

• C-out = Ion concentration out of the cell

• C-In = Ion concentration inside the cell

By convenience, in the Nerts equation, the bigger concentration value corresponds to the numerator and the smaller concentration value to the denominator.

Now let us see the provided values,

• z = Ion charge + positive or negative symbol ⇒ +1 ⇒ K+

• C-out = Ion concentration out of the cell ⇒ 5 mEq/L

• C-In = Ion concentration inside the cell ⇒ 150 mEq/L

E = 58 millivolts/z. [Log₁₀ (Ion in/Ion out)

E = 58 millivolts/+1. [Log₁₀ (150 mEq/L / 5 mEq/L)

E = 58 millivolts (Log₁₀ 30)

E = 58 millivolts (1.477)

E = 85.67 millivolts

85.7 mV is the absolute value of equilibrium potential.

E = 58 millivolts/z. [Log₁₀ (Ion in/Ion out)

E = 58 millivolts/+1. [Log₁₀ (150 mEq/L / 3.5 mEq/L)

E = 58 millivolts (Log₁₀ 42.85)

E = 58 millivolts (1.63)

E = 94.65 millivolts

94.7 mV is the absolute value of equilibrium potential.

If the extracellular concentration of potassium is changed from 5.0 to 3.5 mEq/L, there will be an increase in the membrane potential from 85.7 to 94.7 mV. The increase in the equilibrium potential will result in more potassium diffusing out of the cell, turning the cell interior less positive than before.  

The potassium equilibrium ability might increase, which means that greater K+ might be leaving the cell.

Let us expect that the handiest ion transported via the cell membrane is K+. We want to apply the Nernst equation to recognize the future of the ion.

Nernst equation:

[tex]E = 58 millivolts/z. [Log₁0 (C-out/ -in)[/tex]

Where,

E = Equilibrium ability.58 millivolts/z =Constant.z=lon charge + advantageous or terrible symbol. C - out = Ion awareness out of the cell. C-ln= ion awareness in the cell.

For convenience, withinside the Nerts equation, the larger awareness fee corresponds to the numerator and the smaller awareness fee to the denominator. Now allow us to see the supplied values,

[tex]z=lon charge + effective or terrible ⇒+1 ⇒ K+\\C - out = lon awareness out of the cell ⇒5 mEq/L\\C-ln= lon awareness withinside the cell ⇒150 mEq/LE = 58 millivolts/+ 1.[Log 10 ( 50mEq / L / 5mEq/L)\\E = 58millivolts (Log30)\\E = 58 millivolts (1.477)[/tex][tex]E = 85.67 millivolts\\85.7 mV is absolutely the fee of equilibrium capability.\\E = 58 millivolts/z. [Log10 (lon in/lon out)\\E =58 millivolts/+1. [Log 10 (a 100and 50 mEq/L / 3.five mEq/L)\\E =58 millivolts (Log10 42.85)\\E = 58 millivolts (1.63)\\E = 94.65 millivolts94.7 mV is absolutely the fee of equilibrium capability.[/tex]

What happens if the extracellular attention of potassium is modified from 5.0 to 3.5?

If the extracellular attention of potassium is modified from 5.0 to 3.5mEq/L, there can be a growth withinside the membrane capability from 85.7 to 94.7 mV. The growth withinside the equilibrium capability will bring about extra potassium diffusing out of the cell, turning the cell indoors much less high quality than before.

Thus it is clear from this that the potassium equilibrium potential is affected.

To know more about the potassium equilibrium refer to the link :

https://brainly.com/question/2742049

What’s the following have contributed to historical increases in the global human population?
A.) increases in the number of deaths
B.) unavailability of clean water
C.) decreases in the birth rate
D.)Advances in hygiene

Answers

Answer:

D

Explanation:

people take it into account that the environment is fine for growing children hence giving birth


Over a long period of time the process of deposition causes the formation of

Answers

Answer:

sedimentary rock

Explanation:

the process of deposition refers to rock and soil depositing itself onto a landform and hardening into rock, specifically sedimentary rock.

Deltas formed at the mouth of a river.

Please I really need your help.

Answers

seventy five percent brown hair when we cross

Bb to bb

ATP is considered as nature dehydrating agent.what does it means?show with the help of examples

Answers

Answer:

that man is mental

Which of the following does NOT relate to water?
A. Dehydration damages cells.
B. 70% of the human body.
C. Controls negative feedback mechanisms.
D. Contains and moves ions in and out of cells.

Answers

The answer should be D. Contains and moves ions in and out of cells

The following that does not relate to water is it contains and moves ions in and out of cells. The correct option is D.

What is water?

Water is a chemical compound made up of hydrogen and oxygen. It is a necessary part of life. As our body is made up of 90% of water, and without water, organisms would not survive.

The transport of ions and molecules in and out of the cell is done by the cytoplasm filling in the cell.

Thus, the correct option is D. Contains and moves ions in and out of cells.

Learn more about water, here:

https://brainly.com/question/27156884

#SPJ5

Kevin's supervisor, Jill, has asked for an update on today's sales, Jill is pretty busy moving back and forth between different store locations. How can Kevin most effectively deliver an update to her ? a) Call with a quick update Ob ) Send a detailed text message c ) Book a one-hour meeting for tomorrow morning d) Send a detailed email

Answers

Answer:

d) Send a detailed email

Explanation:

Send a detailed email is the best way to deliver an update to her because in the email he can send all the information in detail form which can satisfy his owner. He can't call or message because it takes too much time to provide information so email is the best way to provide information. Booking a one-hour meeting is not worth it and the reason for this is that there is no big presentation which takes one hour of description one email is enough for it.

Bodily energy Taoists cultivate within themselves is called:
A. Jen
B. Tao
C. Wu
D. Chi

Answers

Answer:

The correct answer is - D. Chi.

Explanation:

Taoist is a Chinese origin tradition that is spiritual and philosophical and focuses on living in harmony with, the source, patter, and substance of everything exists called Tao.

They believe that Chi is the bodily energy one needs to cultivate within oneself it is known as the energy of life and it translates as cultivation of energy. One can cultivate by relaxing and focusing on the body, abdominal breathing, connect to the earth and believe in chi.

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