A diagonal of rectangle is inclined to one side of the rectangle at 25 degree the acute angle between diagonal is

120 is 30 percent of 400

I inserted in an image below to help you with the rule.

The 1st point  is (6,1) . This becomes (1,-6).

The 2nd point is (-5,-6). This becomes (-6, 5)

A hexagon with two lines

hope helped you please make me brainalist and keep smiling dude

I hope you are form India

Answer:

the maximum height is 2 meters

Answer:

All of the statements are true.

The first statement is true because a graph represents all the possible solutions to an equation or function.

The second statement is true because a system of equations may have no solution, one solution, or infinitely many solutions, depending on the equations.

The third statement is true because graphing technology allows us to see the visual representation of the functions and their intersection points, which are the solutions to the system of equations.

The fourth statement is true because the solution to a system of equations is the point where both equations intersect and are true.

The fifth statement is also true because finding the x-coordinate of the point of intersection is equivalent to finding the solution to f(x) = g(x).

The sixth statement is true because systems of equations can involve any combination of linear, quadratic, exponential, or other functions.

The seventh statement is true because a table of values can only show a limited number of solutions, but finding the approximate solution between two values on the table can still be useful in many practical situations.

We can see that:

1.  True: A graph of an equation in two variables or a function represents an infinite number of solutions because each point on the graph corresponds to a solution of the equation or function.

2. True: A system of equations may not have an exact solution that meets the conditions of a real-world solution. It is possible for a system to have no solution or infinite solutions.

3. False: Using graphing technology is a very efficient way to find solutions to equations and systems of equations.

In mathematics, a graph is a visual representation or diagram that displays the relationship between different elements or variables.

4. True: The intersection point of two graphed functions represents the solution for a system of equations. The coordinates of the intersection point satisfy both equations simultaneously.

5. True: When two different functions f(x) and g(x) are graphed, the x-coordinate of the point of intersection represents a solution to the equation formed from f(x) = g(x). However, it's important to note that there could be multiple points of intersection, so the x-coordinate of the intersection is not necessarily the only solution.

6. True: Systems of equations may indeed be a combination of linear and non-linear functions. The equations in a system can involve various types of functions, including linear, quadratic, exponential, logarithmic, etc.

7. True: A table of values may not show every possible solution to a system of equations. It provides a limited set of data points, and there may be solutions that fall between the values in the table. However, finding an approximate solution that lies between two values in the table can be a reasonable approach in many situations.

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The complete question is seen below:

True or False:

A graph of an equation in two variables or a function is a representation of an infinite number of solutions to the equation or function.

A system of equations may not have an exact solution that meets the conditions of a real-world solution.

Using graphing technology is a very efficient way to find solutions to equations and systems of equations.

The intersection point of two graphed functions is the solution for a system of equations. It is the point that makes both equations true.

When two different functions f(x) and g(x) are graphed, the x-coordinate of the point of intersection is the solution to the equation formed from f(x) = g(x)

Systems of equations may be a combination of linear and non-linear functions.

A table of values very rarely shows every possible solution to a system of equations. Finding the approximate solution that is between two values on the table can be a good answer in many situations.

Answer:

Let the height of the parallelogram be h

From :the formula of finding Area of the parallelogram

Answer: y is equal to 8

Step-by-step explanation:

by substituting the x for its vale of three we can add the two values to get 8 or y=8

The given square with a side length of one unit is known to contain five points. One must prove that at least two of these points are within square root 2/2 units of each other.

According to the Pigeonhole principle, "if n items are put into m containers, with n > m, then at least one container must contain more than one item."In this context, the square is the container, and the points inside it are the objects. If more than four points are picked, the theorem is true, and two points are nearer to each other than the square root of 2/2 units.

Let's place four points on the square's four corners. The distance between any two of these points is the square root of two units since the square's side length is 1.

Let's add another point to the mix. That point is either inside the square or outside it. Without loss of generality, let us assume that the point is inside the square. It must then be within the perimeter outlined by joining the square's corners to the point that was not a corner already.

The perimeter of the square described above is a square with a side length of square root 2 units.

Since we have five points in the square, at least two of them must be in the same smaller square, due to the pigeonhole principle. Without loss of generality, let's assume that two of the points are in the upper-left square. As a result, any points within this square are within the square root 2 units of any of the other four points. Hence, at least two points of the five selected are within the square root of 2/2 units of each other.

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The probability that a continuous random variable is equal to a single number zero because the area under a continuous probability density function (pdf) between any two points, even two extremely close points, is never equal to zero.

In other words, since the continuous random variable is infinite and continuous, the probability that it is equal to a single value is almost zero.

Steps in Hypothesis Testing:State the null and alternative hypotheses.Calculate the test statistic.

Determine the critical value or p-value.Calculate the p-value, if necessary.Make a decision and interpret the results.

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The system of inequalities of the company with the better offer is 75 + 20x ≤ y and 15 + 65x ≤ y

Let's use A to represent the total cost (in dollars) of purchasing a pool membership from the Aquatics Club,

Let S represent the total cost of purchasing a pool membership from the Swimming Hole.

Then we can write the following system of inequalities:

A = 75 + 20x (total cost of Aquatics Club membership)

S = 15 + 65x (total cost of Swimming Hole membership)

Alfonso has no more than y dollars to spend

So, we have

75 + 20x ≤ y

15 + 65x ≤ y

Hence, the system is 75 + 20x ≤ y and 15 + 65x ≤ y

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So, the right response is that, in order to more accurately fit the scatterplot that depicts a curve in the data, you need add a quadratic component while performing regression.

As ax² +bx + c, a quadratic equation can be expressed. In a quadratic equation, the largest exponent is 2, which limits the number of terms to a maximum of 3. These terms are exponent 2 (ax²) and exponent 1 (bx) fixed term.

Regression can be improved by including a quadratic component to better match scatterplots of data that display curves. This is so that the independent and dependent variables can have a nonlinear connection, which is made possible by a quadratic term. A quadratic component can assist capture inherent curvature of a data and enhance the fit of a regression model in cases where the connection between both the variables isn't really strictly linear.

A quadratic term may not be appropriate or required, though. A quadratic factor would not increase the model's fit if the variables' relationships are strictly linear and might even result in overfitting. In addition, if the scatterplot contains too many anomalies or the data is not consistent, adding a quadratic factor might not be beneficial.

In order to properly fit a scatter plot graph that depicts a curve in the data, the correct response is you would like to add a quadratic term while performing regression.

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Parachutist's rate during free fall is 40 meters per second and will fall approximately 490 meters during 10 seconds of free fall.

First, we need to convert 132 feet per second to meters per second. We know that 1 meter is equal to 3.3 feet, so we can use the following conversion factor:

[tex]$\frac{3meter}{3.3 feet}[/tex]

To convert feet per second to meters per second, we can multiply by the conversion factor:

[tex]132 (\frac{1}{3.3} ) = 40 meters/second[/tex]

Therefore, the parachutist's rate during free fall is 40 meters per second.

Next, we can use the following formula to find the distance the parachutist falls during 10 seconds of free fall:

distance =[tex]\frac{1}{2}[/tex] * acceleration * time²

where acceleration due to gravity is approximately 9.8 meters/second^2.

Substituting the given values, we get:

distance = [tex]\frac{1}{2}[/tex] * 9.8 meters/second² * (10 seconds)²

distance = 490 meters

Therefore, the parachutist will fall approximately 490 meters during 10 seconds of free fall.

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Let n be a positive integer. We can use the properties of modular arithmetic to calculate this remainder. Let's start with a = (32n + 4)-1 mod 9. We can rewrite this as a = 9 - (32n + 4)-1 because 9 = 0 mod 9.

We can use Fermat's Little Theorem to calculate (32n + 4)-1. This theorem states that (32n + 4)-1 mod 9 = (32n + 4)8 mod 9.

Using the identity (a + b)n mod m = ((a mod m) + (b mod m))n mod m, we can simplify the equation to (32n mod 9 + 4 mod 9)8 mod 9.

32n mod 9 = 0, so (32n mod 9 + 4 mod 9)8 mod 9 = 48 mod 9 = 1.

Finally, a = 9 - 1 = 8 mod 9, so the remainder when a is divided by 9 is 8.

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The customers of Rhythm Time, an online music service, downloaded 397,970 songs last year.

Rhythm Time, an online music service, had 278,579 songs downloaded this year by its customers. That figure is 30% less than last year. Last year

We can begin by assuming that the total number of songs downloaded last year was x. According to the problem statement, 278,579 songs were downloaded this year, which is 30% less than last year. We can write it as an equation:x - 0.30x = 278,579 Simplifying, we get:0.70x = 278,579 Dividing both sides by 0.70, we get:x = 397,970Therefore, last year, Rhythm Time's customers downloaded 397,970 songs.

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We are interested in the population proportion of drivers who claim they always buckle upa.i. x = 320 ii. n = 400 iii. p′ = 0.8

b. The random variable X represents the number of drivers out of the sample of 400 who claim they always buckle up, while P′ represents the sample proportion of drivers who claim they always buckle up.

c. The distribution to use for this problem is the normal distribution because the sample size is large enough (n=400) and the population proportion is not known.

d. i. The 95% confidence interval for the population proportion who claim they always buckle up is (0.7709, 0.8291).

ii. The graph is a normal distribution curve with mean p′ = 0.8 and standard deviation σ = sqrt[p′(1-p′)/n].

iii. The error bound is 0.0291.

e. Three difficulties the insurance companies might have in obtaining random results from a telephone survey are:

Selection bias: The survey might not be truly random if the telephone numbers selected are not representative of the population of interest.

Nonresponse bias: People may choose not to participate in the survey or may not be reached, which could bias the results.

Social desirability bias: Respondents may give socially desirable answers rather than their true opinions, which could also bias the results.

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In the given diagram, ΔHIJ ≈ ΔFIG, the value of u in triangle FIG is calculated as: IG = 8 yd

A triangle is a geometric shape that is formed by three line segments that intersect at three non-collinear points. The three line segments are called the sides of the triangle, while the three points where they intersect are called the vertices of the triangle.

A triangle is a three-sided polygon formed by three line segments intersecting at three non-collinear points, and it can be classified based on the length of its sides and the measure of its angles.

∆HIJ similar to ∆FIG

HI/FI = IJ/IG

5/10 = 4/IG

IG = 8 yd

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In the given diagram, ΔHIJ ≈ ΔFIG, the value of u in triangle FIG is calculated as: IG = 8 yd

A triangle is a geometric shape that is formed by three line segments that intersect at three non-collinear points. The three line segments are called the sides of the triangle, while the three points where they intersect are called the vertices of the triangle.

A triangle is a three-sided polygon formed by three line segments intersecting at three non-collinear points, and it can be classified based on the length of its sides and the measure of its angles.

∆HIJ similar to ∆FIG
HI/FI = IJ/IG
5/10 = 4/IG
IG = 8 yd

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By the congruence postulate, we have shown that the quadrilateral is  ΔAED ≅ ΔCED.

Let's start by showing that AD = CD. Since AB = AD and BC = CD, we can rewrite AB + BC as AD + CD. This means that AD = AB + BC - CD. But we know that AB = AD, so we can substitute AD for AB to get AD + BC = 2AD + CD. Simplifying this equation, we get AD = CD.

Next, we can show that AE = CE. Since AC is a diagonal of the kite, we know that AC bisects angle BAD and angle BCD. This means that angle BAC = angle DAC and angle BDC = angle CDC. Since AD = CD, we know that triangle ACD is isosceles, so angle ACD = angle CAD.

Using these angle equalities, we can conclude that angle CAE = angle CDE. Since AC ⊥ BD, we know that angle CAD = angle CDE, so we can conclude that triangle ACE is isosceles, which means that AE = CE.

Finally, we need to show that angle AED = angle CED. Since AD = CD and AE = CE, we know that triangles AED and CED have two pairs of congruent sides. Additionally, we know that AC is a common side of the triangles.

Since AC is perpendicular to BD, we know that angle ACD and angle BDC are complementary angles.

This means that angle ACD = 90 - angle BDC and angle CAD = 90 - angle BAC. Using these angle equalities, we can conclude that angle AED = angle CED.

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Answer:

i think 16 im not sure

Step-by-step explanation:

a. The mean of X is 1.7549 and the standard deviation is 0.3536.

b. To calculate the proportion of washing machines that will last for more than 15 years, we need to use the standard normal distribution table. The z-score for 15 years is (15-14)/0.3536 = 2.822. Using the table, we find that the proportion of washing machines that will last for more than 15 years is 0.9968.

c. To calculate the proportion of washing machines that will last for less than 10 years, we need to use the standard normal distribution table. The z-score for 10 years is (10-14)/0.3536 = -2.822. Using the table, we find that the proportion of washing machines that will last for less than 10 years is 0.0032.

d. To calculate the 90th percentile of the life of the washing machines, we need to use the standard normal distribution table. The z-score for the 90th percentile is 1.28. Using the table, we find that the 90th percentile is 17 years.

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The number of minutes needed to complete a job, m, varies inversely with the number of workers, w.

Three workers can complete a job in 30 minutes.

To find, out how many minutes would it take 6 workers to complete the job.

The formula used for inverse variation is, m1w1 = m2w2

Where, m1 = 30,

w1 = 3,

m2 = ?

and w2 = 6

Substitute the given values in the above formula, 30 × 3 = m2 × 6

Simplify the above expression,90 = 6m2

Divide both sides by 6,90 / 6 = m2m2 = 15

Hence, it will take 15 minutes for 6 workers to complete the job.

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We have that, if they put 40 chips in a hat, each one with the numbers 1, 2, 3, 4, 5, 6, 7, 8, 9 or 10, and each number is put on four chips. Four tokens are drawn from the hat at random and without replacement, the value of q/p, q,p as probabilities, will be given by 360, therefore, the correct option is (D) 360

The probability that all four tokens have the same number (p) is equal to the total number of possible outcomes that meet that criterion divided by the total number of possible outcomes.

In this case, there are 10 possible numbers that could come up (1-10). Therefore, there are 10 possible outcomes for the four slips of paper that have the same number. Each outcome has the same probability of 1/10, so p = (1/10)^4 = 1/10000.

The probability that two of the slips have a number a and the other two have a number b (q) is equal to the total number of possible outcomes meeting that criterion divided by the total number of possible outcomes.

In this case, there are 10 possible numbers that could be drawn (1-10) and 2 ways to choose 2 different numbers out of 10, so there are 20 possible outcomes for two of the slips bearing a number and the other two bearing a number b. Each outcome has the same probability of 1/20, so q = (1/20)^4 = 1/3200000.

The ratio of q to p is q/p = 3200000/10000 = 360. Therefore, the value of q/p is 360.

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The daily dose is 40mg, this dose per kilogram per day is within the therapeutic range of 2-3mg/kg/day, which means that the medication is within the safe and effective range for this patient's weight.

The weight of the patient is 20kg, and the prescribed dosage is 10mg every 6 hours. To calculate the daily dose, we need to multiply the prescribed dosage by the number of doses per day. Since the medication is prescribed every 6 hours, this means that the patient will take it 4 times a day.

=> (10mg x 4 doses) = 40 mg

The therapeutic range is the range of doses at which the medication is most effective and safe. In this case, the therapeutic range is 2-3mg/kg/day. To determine if the daily dose is within the therapeutic range, we need to divide the daily dose (40mg) by the patient's weight (20kg) to get the dose per kilogram per day, which is 2mg/kg/day.

However, it's important to note that the therapeutic range is a general guideline and may vary depending on the patient's individual circumstances and medical history.

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The number of individuals who are homozygous dominant (VV) is 160 individuals, and the number of individuals who are heterozygous (Vv) is 320 individuals.

The population of Drosophila has 1000 individuals, 360 of which display the recessive phenotype. Homozygous dominant and heterozygous for this trait in Drosophila would be expected to be found in how many individuals?

In Drosophila, the dominant allele for normal-length wings is denoted as 'V' and the recessive allele for vestigial wings is denoted as 'v.'To determine the number of individuals who are homozygous dominant or heterozygous for this trait, we'll first determine the number of individuals who are homozygous recessive:

Homozygous recessive individuals in the population = number of individuals displaying the recessive phenotype = 360

This indicate that there are 360 individuals with the genotype vv (homozygous recessive), which will be used to determine the remaining genotypes via the Punnett square. To get the number of individuals who are heterozygous (Vv), we first need to identify the number of individuals with the dominant V allele (VV and Vv). The sum of these two genotypes equals the total number of individuals minus the homozygous recessive individuals, as follows:

Total number of individuals - homozygous recessive individuals = (VV + Vv) individuals+ (vv) individuals = 1000 individuals

Hence, VV + Vv = 1000 - 360 = 640 individuals.Now that we know VV + Vv = 640, we can use the expected genotypic ratio of 1:2:1 to calculate the number of homozygous dominant (VV) and heterozygous (Vv) individuals.1:2:1 represents the expected genotypic ratio in the progeny derived from a cross involving two heterozygotes of the same gene. The first "1" represents the proportion of dominant homozygotes, the second class, or class "2", the heterozygotes, and the second "1" the recessive homozygotes.

Therefore, homozygous dominant (VV) and heterozygous (Vv) individuals in the population would be expected in the following ratio:VV:Vv:vv = 1:2:1. Therefore, the number of individuals who are homozygous dominant (VV) is 1/4 of the total individuals (VV + Vv + vv):

Number of individuals who are homozygous dominant (VV) = 1/4 (VV + Vv + vv)= 1/4 (640) = 160 individuals

And the number of individuals who are heterozygous (Vv) is 2/4 of the total individuals (VV + Vv + vv):

Number of individuals who are heterozygous (Vv) = 2/4 (VV + Vv + vv)= 2/4 (640) = 320 individuals

Therefore, the number of individuals who are homozygous dominant (VV) is 160 individuals, and the number of individuals who are heterozygous (Vv) is 320 individuals.

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c. The mean of the random variable X is calculated as:

mean(X) = (-5)(1/4) + (0)(1/2) + (5)(1/4) = 0

The variance of X is calculated as:

var(X) = (-5 - 0)^2(1/4) + (0 - 0)^2(1/2) + (5 - 0)^2(1/4) = 25/2

d. The mean of the random variable X is calculated as:

mean(X) = (-5)(.01) + (0)(.98) + (5)(.01) = 0

The variance of X is calculated as:

var(X) = (-5 - 0)^2(.01) + (0 - 0)^2(.98) + (5 - 0)^2(.01) = 50.25

e. The mean of the random variable X is calculated as:

mean(X) = (-50)(.0001) + (0)(.9998) + (50)(.0001) = 0

The variance of X is calculated as:

var(X) = (-50 - 0)^2(.0001) + (0 - 0)^2(.9998) + (50 - 0)^2(.0001) = 500

g. The mean of the random variable X is calculated as:

mean(X) = (0)(1/2) + (2)(1/2) = 1

The variance of X is calculated as:

var(X) = (0 - 1)^2(1/2) + (2 - 1)^2(1/2) = 1

h. The mean of the random variable X is calculated as:

mean(X) = (.01)(.01) + (1.01)(.99) = 1

The variance of X is calculated as:

var(X) = (.01 - 1)^2(.01) + (1.01 - 1)^2(.99) = .098

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The probability density function (PDF) of Y can be determined by the transformation of the PDF of X. Using the transformation rule, we can calculate that fy(y) = fx(x) |dx/dy|, where x is a function of y, since y = Fx(x).

We can use the Chain Rule to determine the derivative of x with respect to y. Since Fx is a monotone increasing function, dx/dy = 1/F'x(x). Substituting this into the transformation rule, fy(y) = fx(x) / F'x(x).

Therefore, to find fy(y), we need to calculate F'x(x). Fx is the cumulative distribution function, which means that its derivative F'x(x) is the probability density function of X, or fx(x). Substituting this into the transformation rule, fy(y) = fx(x) / fx(x). Since fx(x) = fx(2) and fx(2) is a constant, fy(y) = 1/fx(2).

To summarize, the probability density function of Y is given by fy(y) = 1/fx(2).

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The volume of the solid is 2160ft^3

Volume of Cuboid is the multiplication of length breath and height.

We know that, Volume of Cuboid = l×b×h

put the given values from figure,

= 12×10×15

=1800ft^3

Volume of top = Area of triangle × length

= 1/2 × 4× 12× 15

=360ft^3

Total volume= 1800 + 360

= 2160ft^3

Therefore, the volume of the solid is 2160ft^3

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Cuboid: According to the question the volume of the solid is [tex]2160ft^3[/tex].

A cuboid is a three-dimensional geometric shape which is composed of six rectangular faces. It has 12 edges and 8 vertices. It is also referred to as a rectangular prism. The three dimensions of a cuboid are its length, width, and height. The cuboid is a versatile shape that can be used in many different ways and can be seen in everyday objects such as boxes, desks, and bookshelves. It is also a common shape for mathematically-based problems such as calculating the volume of a cuboid.

We know that, Volume of Cuboid = l×b×h
put the given values from figure,
= 12×10×15
=[tex]1800ft^3[/tex]
Volume of top = Area of triangle × length
= 1/2 × 4× 12× 15
=[tex]360ft^3[/tex]
Total volume= 1800 + 360
= [tex]2160ft^3[/tex]
Therefore, the volume of the solid is [tex]2160ft^3[/tex]

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The factοred fοrm οf a pοlynοmial is

1. 30b³- 54b² = 6b²(5b−9)

2. 3y⁵ - 48y³ = 3y³(y  −4)(y + 4)

3. x³ + 8 = (x + 2) (x² – 2x + 2²)

4. y³ - 64 = (y - 4) (y² – 4y + 4²)

5.  8c³ + 343(2c + 7)(4c² − 14c + 49)

The factοred fοrm οf a pοlynοmial is represented as a³ + b³ = (a + b) (a² – ab + b²). All equatiοns are cοmpοsed οf pοlynοmials. Earlier we've οnly shοwn yοu hοw tο sοlve equatiοns cοntaining pοlynοmials οf the first degree, but it is οf cοurse pοssible tο sοlve equatiοns οf a higher degree.

One way tο sοlve a pοlynοmial equatiοn is tο use the zerο-prοduct prοperty. If yοu remember frοm earlier chapters the prοperty οf zerο tells us that the prοduct οf any real number and zerο is zerο.

We will use the formula

a³ + b³ = (a + b) (a² – ab + b²)

And

a³ - b³ = (a - b) (a² – ab + b²)

1. [tex]30b^3-\ 54b^2[/tex]

⇒ 6b²(5b−9)

2. 3y⁵ - 48y³

⇒ 3y³(  y² - 16y)

⇒ 3y³(  y² - 4 + 4 - 16y)

⇒ 3y³(y  −4)(y + 4)

3. x³ + 8

⇒ x³ + 2³

Using a³ + b³ = (a + b) (a² – ab + b²)

⇒ x³ + 2³

⇒ (x + 2) (x² – 2x + 2²)

4. y³ - 64

⇒ y³ -  4³

Using a³ - b³ = (a - b) (a² – ab + b²)

⇒ y³ -  4³

⇒ (y - 4) (y² – 4y + 4²)

5. 8c³ + 343

Using a³ + b³ = (a + b) (a² – ab + b²)

2c + 7

(2c + 7)(4c² − 14c + 49)

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Answer:

1 minute = 1/6

2 minutes = 1/3

3 minutes =1/2

Step-by-step explanation:

one can eat a bag in 15 minutes so in 1 minute this cat can eat 1/15 of a bag

the other cat can eat a bag in 10 minutes so in 1 minute the cat can eat 1/10 of the bag

to find how much they can eat in 1 minute, add 1/10 and 1/15 which gives you 1/6. to find 2 and 3 minutes just multiply by 1/6 by 2 or 3

the HCF of x, 2y, 3y, 4z, x², 3z, and 5, where x, y, z are

distinct prime numbers is 1.

To find the highest common factor (HCF) of the given numbers, we need to find the common factors of each pair of numbers and then find the highest common factor of all the resulting common factors.

First, let's find the prime factors of the given numbers:

x = a prime number (distinct from y and z)

2y = 2 × y

3y = 3 × y

4z = 2² × z

3z = 3 × z

x² = a prime number squared (distinct from y and z)

5 = a prime number

Next, we can pair up the numbers and find their common factors:

Common factors of x and 2y: 1, 2, y

Common factors of 3y and 4z: 1, 2, 3, y, z, 6

Common factors of x² and 3z: 1, 3, x, z, xz

Common factors of 5 and 2: 1

Finally, we find the highest common factor of all the resulting common factors:

The highest common factor of x, 2y, 3y, 4z, x², 3z, and 5 is 1, since it is the only factor that is common to all the pairs.

Therefore, the HCF of x, 2y, 3y, 4z, x², 3z, and 5 is 1.

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Therefore, when the equation  x = 72 - 3x, the value of 2 - 3x is -52.

An equation is a mathematical statement that shows the equality of two expressions. It typically contains one or more variables, which are symbols that can represent any number or value. The expressions on both sides of the equal sign are called the left-hand side (LHS) and the right-hand side (RHS) of the equation. Equations are used to describe relationships between quantities or to solve problems. They can be represented in various forms, including linear equations, quadratic equations, exponential equations, and trigonometric equations. Equations can be solved by performing operations on both sides of the equation to isolate the variable or variables.

Here,

When we are given that x = 72 - 3x, we can solve for x by first adding 3x to both sides of the equation:

x + 3x = 72

Combining like terms, we get:

4x = 72

Dividing both sides by 4, we get:

x = 18

Now that we know x = 18, we can substitute this value into the expression 2 - 3x:

2 - 3x = 2 - 3(18)

2 - 3x = 2 - 54

2 - 3x = -52

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