Answer:
shushhhgggvvv vgfxgh
Explanation:
gey laahhg
Rick works off commission. He earns 10 percent of all manufacturing equipment he sells. if he made a sale of $9,000 how much was his commission
Answer:
$900
Explanation:
Step 1: Our output value is 9000.
Step 2: We represent the unknown value with x.
Step 3: From step 1 above,$9000=100\%$
Step 4: Similarly, x=10%
Step 5: This results in a pair of simple equations:
$9000=100
Step 6: By dividing equation 1 by equation 2 and noting that both the RHS (right hand side) of both
equations have the same unit (%); we have
\frac{9000}{x}=\frac{100\%}{10\%}
Step 7: Again, the reciprocal of both sides gives
\frac{x}{9000}=\frac{10}{100}$
\Rightarrow x=900$
Therefore, $10\%$ of $9000$ is $900$
unknown value with x
step 1 above,$9900=100%
similarly ,x=10%
It was found that ice cream sales decrease significantly as the temperature outside decreases; a very strong relationship was found. What is the most likely correlation coefficient from this hypothetical study
Answer:
Value closest to 1
Explanation:
It is described from the scenario above that ice cream sales decreases as the outside temperature increases, hence showing a strong relationship between both variables (icream sales and temperature). The correlation Coefficient is a metric used in regression modeling to depict the strength of relationship between two variables, (The dependent and independent variables). Correlation Coefficient ranges from (-1 to +1). With values close to 1 or - 1. Also the positive and negative signs are used to show the type of relationship between the variables. If an increase in variable A leads to a decrease in variable B, then we have negative correlation (-) ; while an increase or decrease in both variables depicts a positive correlation. The most likely correlation Coefficient for the study above will be a positive value which is close to 1 since the relationship is described as strong.
explain the role of standard units to bring uniformity in the measurement
Answer:
We need standard unit for measurement to make our judgement more reliable and accurate. For proper dealing, measurement should be same for everybody. Thus there should be uniformity in measurement. For the sake of uniformity we need a common set of units of measurement, which are called standard units.
Which of these would have the greatest pressure?
Group of answer choices
A large balloon with few gas molecules at a high temperature
A small balloon with many gas molecules at a low temperature
A small balloon with many gas molecules at a high temperature
A large balloon with few gas molecules at a low temperature
In uplifting 750 newton load with the help of 2 meter long lever lever took 250 newton efforts . What will be the efficiency of a machine if the fulcrum is kept 50 cm from the load
Answer:
the efficiency of the machine is 100%
Explanation:
Given;
load, L = 750 N
length of the lever, L = 2 m
effort applied, E = 250 N
Position of the load from the fulcrum, = 50 cm
50cm
0↓--------------------------Δ-------------------------------↓---------200 cm
750 N x cm 250 N
Apply the principle of moment;
750(50) = 250(x)
x = (750 x 50) / (250)
x = 150 cm
the distance of the effort = 150 cm = 1.5 m
the distance of the load = 50 cm = 0.5 m
The velocity ratio of the machine = 1.5/0.5
= 3
The mechanical advantage of the machine is calculated as;
M.A = Load/effort
M.A = 750 / 250
M.A = 3
The efficiency of the machine is calculated as;
E = (M.A / V.R) x 100%
E = (3/3) x 100% = 100%
Therefore, the efficiency of the machine is 100%
Two identical metallic sphere having unequal opposite charges are are placed
distance of 0.05m apart in air.
After bringing them in contact
with each other, they are again placed at the same distance apart, now the force of repulsion between them is 0.108 N. Calculate the final charge on each of them.
Answer:
Let the initial charges be q1 and q2 respectively.
After they come in contact, the charges are rearranged such that they acquire same charge.
let us say that charge on each of them is Q.
They are again brought apart at a distance of 0.9 m. Hence, the force between them will be given as
F = kQ2 / r2
0.025 = (9×109 x Q2) / 0.92
Q2 = 0.025 x 0.92 / 9×109
Q = 1.5 x 10-6 C
Explanation:
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State Newton’s second law of motion. Derive this law mathematically. A 1000 kg vehicle moving with a speed of 20m/s is brought to rest in a distance of 50 metres. Find the acceleration and calculate the force acting on the vehicle.
Answer:
-4000 N
Explanation:
newton second law F=ma
m=1000kg
vi=20m/s
vf=0
d=50 m
vf^2=vi^2+2ad
0=20^2+2a×50
100 a= -400
a= -4 m/S2
F=ma = 1000×-4 = -4000 N
What is photosynthesis??
Explanation:
The process in which green plants prepare their food in their body by using carbon dioxide and water in the presence of sunlight is called photosynthesis.hope it is helpful to you
Hey there!
Photosynthesis is the reaction that converts light energy to chemical energy in sugar and carbohydrates. Humans can't eat sunlight, so we eat plants. Plants convert the energy in the sunlight into chemical energy using chlorophyll. Chlorophyll is a molecule produced by plants, algae, and cyanobacteria, which aids in the conversion of light energy into chemical bonds. It is the green pigment found in the chloroplasts of higher plants. They are a part of our ecosystem, and they are lower on the food chain.
Hope this helps!
Have a great day! :)
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26. D. crushing the sugar cube and dissolving it in water.
27. A. atom
28. B. molecule
29. B. plum pudding model of Joseph John Thomson
30. B. He used cathode ray tubes which showed that all atoms contain tiny negatively charged subatomic particles or electrons
31. D. protons and neutrons are relatively heavier than electrons.
What do you mean by kinematics?
Explanation:
study of motion of an object ...plzz if anyone knies the correct meaning of it ..do comment
Let's first consider the dynamics behind the motion in this video. After the student releases the wheel by cutting the cord, what forces are acting on the wheel
Answer:
Hello. You did not provide the video to which the question refers, however, given the context of your question, we can consider that the forces acting on the wheel are the weight of the wheel, the tension that this weight promotes on the rope and the normal force of the axle.
Explanation:
According to the context of the question, we can see that the wheel is being pulled by a rope. The weight of the wheel is the first force that acts on it, promoting resistance to the impulse that the rope promotes on the wheel. When this wheel is pulled by the rope, the weight of the wheel creates tension in the rope, which stretches and becomes tensioned in response to this force. However, this tension is also a force acting on the wheel, as is the normal force on the axis between these two elements.
If 6000 J of heat is added to 200 gm of water at 25° C. What will be its final
temperature?
Answer:
T₂ = 305.17 K
Explanation:
Given that,
Heat, Q = 6000 J
Mass, m = 200 gram
Initial temperature, T₁ = 25° C
We need to find its final temperature. Let it is T₂.
We know that,
[tex]Q=mc\Delta T[/tex]
Where
c is the specific heat of water, c = 4.18 J/g°C
So,
[tex]6000=200\times 4.18\times (T_2-298)\\\\\dfrac{6000}{200\times 4.18}=(T_2-298)\\\\7.17=(T_2-298)\\\\7.17+298=T_2\\\\T_2=305.17\ K[/tex]
So, the final temperature is equal to 305.17 K.
Question 23 of 23
Suppose a current flows through a copper wire. Which two things occur?
O A. The field is parallel to the direction of flow of the current.
B. An electric field forms around the wire.
OC. A magnetic field forms around the wire.
U
D. The field is perpendicular to the direction of flow of the current.
SUBM
Answer:
The field is parallel to the direction of flow of the current.
a)Watt (W) is a derived unit.
b)The atomic clock is suitable for measuring time.
c)There is fluctuation in time measured by a pendulum clock.
d)The weight of an object is more at pole and less at equator of the earth.
e)The weight of an object on the moon is about one-sixth the weight it would have on the earth.
f)In average, the weight of 1 kilogram mass on the earth surface is 9.8 N.
please answer all questions
Answer:
a) Watt is a derived unit because it's not a “base unit.”
b) The atomic clock is suitable for measuring time because natural atomic oscillations happen at a higher frequency and as a result they are more stable.
c) There is fluctuation in time measured by a pendulum clock because the pendulum rod changes in length slightly with changes in temperature, causing changes in the rate of the clock. An increase in temperature causes the rod to expand, making the pendulum longer, so its period increases and the clock loses time.
D) The weight of an object is more at pole and less at equator of the earth because the distance of the pole is less than the distance of the equator from the centre of the earth.
e) The weight of an object on the moon is about one-sixth the weight it would have on the earth because the moon's gravitation force is determined by the mass and the size of the moon. Hence, the weight of an object on the moon is 1/6th its weight on the earth.
Presence of _______- in retina gives us night vision that is help us to see in dim light.Required to answer. Single choice. Immersive Reader (1 Point) cornea retina lens rods
Answer: Rods
Explanation:
The rod cells in the retina are the reason we are able to see at night and in dim light. They exist on the edges of the retina which is why they are also very useful for the peripheral vision of a human.
Rod cells number over 90 million in the eyes and although very useful for seeing in dimmer light, they are not very useful for color vision which is why humans see less colors in the dark.
A Bullet Off mass 100 gm is fired From A Gun Off mass 5 Kg. If the backward velocity of the gun's 5 m / s, what is forward velocity of the bullet?
Answer:
250 m/s
Explanation:
The mass of the bullet, m₁ = 100 g = 0.1 kg
The mass of the gun, m₂ = 5 kg
The backward velocity of the gun, v₂ = -5 m/s
Given that the momentum is conserved, we have;
The total initial momentum = The total final momentum
The gun and the bullet are at rest, therefore, we have;
The initial momentum = 0
The total final momentum = m₁·v₁ + m₂·v₂
Where;
v₁ = The forward velocity of the bullet
Therefore, we get;
m₁·v₁ + m₂·v₂ = 0
0.1 kg × v₁ + 5 kg × (-5 m/s) = 0
0.1 kg × v₁ = 5 kg × 5 m/s
v₁ = (5 kg × 5 m/s)/(0.1 kg) = 250 m/s
The forward velocity of the bullet, v₁ = 250 m/s
The Sun is an enormous ball of gas. Left to itself, a ball of so many atoms should collapse under its own tremendous gravity. Why is our Sun not collapsing
Answer:
Nuclear fusion in the Sun's core causes the release of tremendous amounts of energy that leads to very high temperatures and pressure which is much hotter and higher than the temperature and pressure at the exterior surface of the Sun causing the particles in the inner core region to push outwards towards the Sun's surface
Explanation:
An electrostatic paint sprayer has a 0.17 m-diameter metal sphere at a potential of 25.0 kV that repels charged paint droplets onto the object to be painted, which is grounded (electric potential of 0).
Answer:
[tex]q=0.236uC[/tex]
Explanation:
From the question we are told that:
Diameter [tex]d=0.17m[/tex]
Radius [tex]r=0.17/2=>0.085[/tex]
Potential [tex]E=25.0kV[/tex]
Generally the equation for Potential on spere is mathematically given by
[tex]E=\frac{1}{4 \pi e_0}*\frac{q}{r}[/tex]
Therefore
[tex]q=\frac{25*10^3*0.085}{\frac{1}{4 \pi e_0}}[/tex]
Where
[tex]\frac{1}{4 \pi e_0}=9*10^9[/tex]
Therefore
[tex]q=\frac{25*10^3*0.085}{(9*10^9}}[/tex]
[tex]q=0.236uC[/tex]
A pair of forces with equal magnitude, opposite directions, and different lines of action is called a "couple." When a couple acts on a rigid object, the couple produces a torque that does not depend on the location of the axis. The drawing shows a couple acting on a tire wrench, each force being perpendicular to the wrench. Determine an expression for the torque produced by the couple when the axis is perpendicular to the tire and passes through the following. Express your answers in terms of the magnitude F of the force and the length L of the wrench.
The drawing shows the couple acting on a tire wrench is missing and so i have attached it.
We are to find an expression for the torque when the axis is perpendicular to the tire and passes through the points A, B & C
Answer:
Point A: τ = Fl
Point B: τ = 0
Point C: - Fl
Explanation:
Formula for torque is;
τ = F × d
Where;
F is perpendicular force
d is distance.
Thus;
> At point A, it means we are taking torque about point A and so we have;
τ = (-F × 0) + (F × L)
τ = Fl
> At point B, it means we are taking torque about point B and so we have;
τ = (-F × L/2) + (F × L/2)
τ = -(FL/2) + (FL/2)
τ = 0
> At point C, it means we are taking torque about point C and so we have;
τ = (-F × L) + (F × 0)
τ = -FL
suppose the pilot starting again from rest opens the throttle part.way at constant acceleration the airboat then covers a distance of 60.0m in 10.0s find the net force action on the boat
Answer:
Acceleration is 1.2 m/s^2.
Explanation:
initial velocity, u = 0
distance, d = 60 m
time, t = 10 s
Let the acceleration is a.
use second equation of motion
[tex]s= u t +0.5 at^2\\\\60 = 0 + 0.5 \times a \times 10\times 10\\\\a = 1.2 m/s^2[/tex]
Now according to the Newton's second law
Force = mass x acceleration
Let the mass is m.
F = m x 1.2 = 1.2 m Newton
18.How much momentum will a dump-bell of mass 10 kg transfer to the floor if it falls from a height.of 80 cm ? Take its downward acceleration to be 10 m s-2
Such asSuch ToSuch aSuch as طHow do I send the answer to the question?OkI don't know how to use this program
Answer:
MOMENTUM = 40kg ms-¹
hope it helps
have a nice day
You pull your little sister across a flat snowy field on a sled. Your sister plus the sled have a mass of . The rope is at an angle of 45 degrees to the ground. As you pull with a force of , the sled travels a distance of . How much work do you do
Answer:
W = 0.7071 F x, W = 35.355 J
Explanation:
Work is defined
W = F. d
bold indicates vectors,
W = F d cos θ
where the angle is between force and displacement.
As the system runs on snow, the friction force is negligible, therefore
W = F x cos 45
W = 0.7071 F x
Unfortunately the values of the force and the distance do not appear, suppose that the force is F = 10 N and the distance x = 5m
W = 0.7071 10 5
W = 35.355 J
Work is positive because force and displacement go in the same direction
An inquisitive physics student and mountian climber climbs a 43.6 m cliff that overhangs a calm pool of water. He throws two stones vertically downward, 1.35 s apart and observes that they cause a single splash. The first stone has an initial velocity of 1.8 m/s. How long after release of the first stone do the two stones hit the water
Answer:
Explanation:
What we are basically looking for here is how long it takes the first stone to hit the water. We have everything we need to figure that out. We will use the equation
Δx = . Filling in, we will solve for t, the time is takes the first stone to hit the water (which is the same for both since they both hit the water at the same time):
which is a quadratic that we will have to factor. Get it into standard form, setting it equal to 0:
and factor to get that
t = 3.2 s and t = -2.8 s
Since time can't ever be negative, it takes 3.2 s for the stones to hit the water.
iv. An object is 14 cm in front of a convex mirror. The image is 5.8 cm behind the mirror. What is the focal length of the mirror? A. 4.1cm B. 8.2 cm C. 9.9 cm D. 20 cm
Answer:
C. 9.9 cm
Explanation:
The location of the object, u = 14 cm
The location of the image, v = 5.8 cm
The focal length of the mirror, f = Required
The mirror formula for a convex mirror is given as follows;
[tex]\dfrac{1}{u} -\dfrac{1}{v} = -\dfrac{1}{f}[/tex]
Therefore, we get;
[tex]\dfrac{1}{14 \ cm} -\dfrac{1}{5.8 \ cm} =- \dfrac{41}{406 \ cm} = -\dfrac{1}{f}[/tex]
Therefore;
[tex]f = \dfrac{406 \ cm}{41} \approx 9.9 \ cm[/tex]
The focal length of the mirror, f ≈ 9.9 cm
Calculate the gravitational force between two bodies of masses 10kg and 55kg, if they are placed at a distance of 2m apart.
Answer:
F = 9.177*10^-9N
Explanation:
Gravitational force between the two bodies is expressed as;
F = GMm/r²
Given tha
M = 55kg
m = 10kg
r = 2m
G = 6.67408 × 10-11 m³ kg-1 s-2
Substitute;
F = GMm/r²
F = 6.67408 × 10-11*55*10/2²
F = 3,670.744× 10-11/4
F = 9.177*10^-9N
que es la energia electrica
Answer:
:) :) :) :) :) :) :) :) :)
Explanation:
:) :) :) .......
A uniform meter rule of mass 10g is balanced on a knife edge placed at 45cm mark. Calculate the distance of a mass 25g from the pivot
Answer:
2 cm.
Explanation:
Please see attached photo for diagram.
In the attached photo, y is the distance from the pivot to which the 25 g is placed.
The value of y can be obtained as follow:
Clockwise moment = 5 × 10
Anticlock wise moment = y × 25
Anticlock wise moment = Clockwise moment
y × 25 = 5 × 10
y × 25 = 50
Divide both side by 25
y = 50/25
y = 2 cm
Thus, the distance is 2 cm
A piano string of density 0.0050 kg/m is under a tension of 1,350 N. Find the velocity with which a wave travels on the string.
Answer:
519.62 m/s
Explanation:
Applying,
v = √(T/m').............. Equation 1
Where v = velocity of the wave, T = Tension on the string, m' = mass per unit length of the string
From the question,
Given: T = 1350 N, m' = 0.005 kg/m
Substitute these values into equation 1
v = √(1350/0.005)
v = √(270000)
v = 519.62 m/s
Mean diameter of cylinder measured by A is 2.50 cm with a possible error of 0.25 cm whereas mean height of cylinder measured by B is 10.0 cm with a possible error of 0.5 cm. Whose measurement is more accurate?
Answer:
The measurement of first cylinder is more accurate.(A)
Explanation:
The least possible error higher will be accuracy.
A 0.15-mm-wide slit is illuminated by light of wavelength 462 nm. Consider a point P on a viewing screen on which the diffraction pattern of the slit is viewed; the point is at 26.9° from the central axis of the slit. What is the phase difference between the Huygens' wavelets arriving at P from the top and midpoint of the slit?
Answer:
[tex]\triangle \phi=461.5rad[/tex]
Explanation:
From the question we are told that:
Silt width [tex]w=0.15=>0.1510^{-3}[/tex]
Wavelength [tex]\lambda=462nm=462*10^{-9}[/tex]
Angle [tex]\theta=26.9[/tex]
Generally the equation for Phase difference is mathematically given by
[tex]\triangle \phi=\frac{2 \pi}{\lambda}(\frac{wsin\theta }{2})[/tex]
[tex]\triangle \phi=\frac{2 \pi}{462*10^{-9}}(\frac{0.1510^{-3}*sin 26.9 }{2})[/tex]
[tex]\triangle \phi=461.5rad[/tex]
[tex]\triangle \phi=146.89\pi[/tex]
