A copper (Young's modulus 1.1 x 1011 N/m2) cylinder and a brass (Young's modulus 9.0 x 1010 N/m2) cylinder are stacked end to end, as in the drawing. Each cylinder has a radius of 0.24 cm. A compressive force of F = 7900 N is applied to the right end of the brass cylinder. Find the amount by which the length of the stack decreases.

Answers

Answer 1

We have that for the Question, it can be said that the amount by which the length of the stack decreases is

[tex]dl'=3.621*10^{-4}m[/tex]

From the question we are told

A copper (Young's modulus 1.1 x 1011 N/m2) cylinder and a brass (Young's modulus 9.0 x 1010 N/m2) cylinder are stacked end to end, as in the drawing. Each cylinder has a radius of 0.24 cm.

A compressive force of F = 7900 N is applied to the right end of the brass cylinder. Find the amount by which the length of the stack decreases.

Generally the equation for copper cylinder   is mathematically given as

[tex]dl=\frac{Flo}{yA}[/tex]

[tex]dl=\frac{7900*3*10^-^2}{1.1*10^{11}*\pi(0.24*10^{-2})^2}[/tex]

[tex]dl=1.19064778*10^-^4[/tex]

Generally the equation for brass cylinder   is mathematically given as

[tex]dl=\frac{7900*5*10^-^2}{9*10^{10}*\pi(0.24*10^{-2})^2}[/tex]

[tex]dl=2.43*10^{-4}[/tex]

Therefore Total change in length

[tex]dl'=1.191*10^-^4+(2.43*10^{-4})[/tex]

[tex]dl'=3.621*10^{-4}m[/tex]

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Answer:

It is unique among planets in our solar system for having water in its liquid form at the surface, in an amount conducive to life evolving. ... No one knows why Earth has the exact amount of water it does, which is relatively small considering that water molecules outnumber silicate molecules in the galaxy, he said. so no one actually found out who actually put water on the earth and why

Explanation:

Answer:

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The horizontal acceleration of a ball that is launched horizontally is equal to: B. 0 [tex]m/s^2[/tex]

Given the following data:

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Mathematically, acceleration is given by the formula;

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Answers

The speed of the man and the chair after the book is thrown is 0.2 m/s.

The given parameters:

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Answer:

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I will give a 5-star answer and Brainlest
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Answer:

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Explanation:

 

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Answer:

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Answer:

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Answer:

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[tex]▪▪▪▪▪▪▪▪▪▪▪▪▪  {\huge\mathfrak{Answer}}▪▪▪▪▪▪▪▪▪▪▪▪▪▪[/tex]

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The person is in motion

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The conversion from meters to astronomical units is done by dividing the average distance by 1. 5 × 10^11.

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Hi there!

Since the ball is directed 60° above the horizontal, we must use its HORIZONTAL component to find its displacement.

We can take the cosine to do so:

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Can anyone help me with this question? I’ll give BRAINLIEST to whoever answers first

Answers

Answer:

a) F = 84.64N

b) The force has to increase.

Explanation:

First of all, let's convert everything to the same unit system:

Vo = 0 m/s    Vf = 98 mi/h * 1609.34 m / 1mi * 1h / 3600s = 43.8m/s

d = 1.7m         m = 0.15kg

We can calculate force as:

F = m*a    where a is the acceleration experiencd by the ball and m is its mass.

In order to calculate acceleration, we can use this formula:

   Solving for a:

Now, the force will be:

F = m * a = 84.6N

As we can see in that previous equation, the force is directly proportional to the mass of the ball, so, assuming the final speed of the ball is the same as before (that is, the acceleration is the same), the force will increase in the same proportion as the mass does.

Plzzzzzzzzz
Help
Will give brainlessness

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Answer:

1. A

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A guitar string has a fundamental frequency f. The tension in the string is increased by 1.70%. Ignoring the very small stretch of the string. How does the fundamental frequency change?

Answers

The characteristics of the speed of the waves in strings and the resonance allows to find the change in the fundamental frequency when changing the tension is:

 The change in fundamental frequency is: f = 1.08 f₀

The speed of the chord wave is given by the relationship between the tension and the density of the medium.

          [tex]v= \sqrt{\frac{T}{\mu } }[/tex]  

Where v is the velocity of the wave, T the tension of the string and μ the density

In a rope held at the ends, a process of standing waves occurs, two at the point where it is attached we have a node and a anti-node in the center.

             2L = n λ

Where L is the length of the chord and call the wavelength

Wave speeds are related to wavelength and frequency.

        v = λ f

We substitute.

            [tex]\sqrt{\frac{T}{\mu } } = \frac{2L}{n} \ \ f[/tex]  

For the fundamental frequency n = 1

            f₀ = [tex]f_o = \sqrt{\frac{T}{\mu } } \ \ \frac{1}{2L}[/tex]  

They indicate that the tension increases 1.70%

           T = T₀ + 0.17 T₀

           T = 1.17 T₀

We substitute.

         [tex]f = \sqrt{1.17 } \ \sqrt{\frac{T_o}{\mu } } \ \ \frac{1}{2L}[/tex]

         f = ra1.17 f₀

         f = 1.08 f₀

In conclusion, using the characteristics of the velocity of the waves in strings and the resonance we can find the change in the fundamental frequency when changing the tension is:

 The change in fundamental frequency is: f = 1.08 f₀

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Answer:

Explanation:

true

The answer going to be true

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50km/hour

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How to calculate specific heat.

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Need more information to answer this question
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