a cat measures 76 cm from its nose to its tail the length of a lion is 3 times as long as a car how long is a lion? Give your answer in meters

First, I'll make f(x) = sin(px) + cos(px) because this expression shows up quite a lot, and such a substitution makes life a bit easier for us.

Let's apply the first derivative of this f(x) function.

[tex]f(x) = \sin(px)+\cos(px)\\\\f'(x) = \frac{d}{dx}[f(x)]\\\\f'(x) = \frac{d}{dx}[\sin(px)+\cos(px)]\\\\f'(x) = \frac{d}{dx}[\sin(px)]+\frac{d}{dx}[\cos(px)]\\\\f'(x) = p\cos(px)-p\sin(px)\\\\ f'(x) = p(\cos(px)-\sin(px))\\\\[/tex]

Now apply the derivative to that to get the second derivative

[tex]f''(x) = \frac{d}{dx}[f'(x)]\\\\f''(x) = \frac{d}{dx}[p(\cos(px)-\sin(px))]\\\\ f''(x) = p*\left(\frac{d}{dx}[\cos(px)]-\frac{d}{dx}[\sin(px)]\right)\\\\ f''(x) = p*\left(-p\sin(px)-p\cos(px)\right)\\\\ f''(x) = -p^2*\left(\sin(px)+\cos(px)\right)\\\\ f''(x) = -p^2*f(x)\\\\[/tex]

We can see that f '' (x) is just a scalar multiple of f(x). That multiple of course being -p^2.

Keep in mind that we haven't actually found dy/dx yet, or its second derivative counterpart either.

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Let's compute dy/dx. We'll use f(x) as defined earlier.

[tex]y = \ln\left(\sin(px)+\cos(px)\right)\\\\y = \ln\left(f(x)\right)\\\\\frac{dy}{dx} = \frac{d}{dx}\left[y\right]\\\\\frac{dy}{dx} = \frac{d}{dx}\left[\ln\left(f(x)\right)\right]\\\\\frac{dy}{dx} = \frac{1}{f(x)}*\frac{d}{dx}\left[f(x)\right]\\\\\frac{dy}{dx} = \frac{f'(x)}{f(x)}\\\\[/tex]

Use the chain rule here.

There's no need to plug in the expressions f(x) or f ' (x) as you'll see in the last section below.

Now use the quotient rule to find the second derivative of y

[tex]\frac{d^2y}{dx^2} = \frac{d}{dx}\left[\frac{dy}{dx}\right]\\\\\frac{d^2y}{dx^2} = \frac{d}{dx}\left[\frac{f'(x)}{f(x)}\right]\\\\\frac{d^2y}{dx^2} = \frac{f''(x)*f(x)-f'(x)*f'(x)}{(f(x))^2}\\\\\frac{d^2y}{dx^2} = \frac{f''(x)*f(x)-(f'(x))^2}{(f(x))^2}\\\\[/tex]

If you need a refresher on the quotient rule, then

[tex]\frac{d}{dx}\left[\frac{P}{Q}\right] = \frac{P'*Q - P*Q'}{Q^2}\\\\[/tex]

where P and Q are functions of x.

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This then means

[tex]\frac{d^2y}{dx^2} + \left(\frac{dy}{dx}\right)^2 + p^2\\\\\frac{f''(x)*f(x)-(f'(x))^2}{(f(x))^2} + \left(\frac{f'(x)}{f(x)}\right)^2 + p^2\\\\\frac{f''(x)*f(x)-(f'(x))^2}{(f(x))^2} +\frac{(f'(x))^2}{(f(x))^2} + p^2\\\\\frac{f''(x)*f(x)-(f'(x))^2+(f'(x))^2}{(f(x))^2} + p^2\\\\\frac{f''(x)*f(x)}{(f(x))^2} + p^2\\\\[/tex]

Note the cancellation of -(f ' (x))^2 with (f ' (x))^2

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Let's then replace f '' (x) with -p^2*f(x)

This allows us to form  ( f(x) )^2 in the numerator to cancel out with the denominator.

[tex]\frac{f''(x)*f(x)}{(f(x))^2} + p^2\\\\\frac{-p^2*f(x)*f(x)}{(f(x))^2} + p^2\\\\\frac{-p^2*(f(x))^2}{(f(x))^2} + p^2\\\\-p^2 + p^2\\\\0\\\\[/tex]

So this concludes the proof that [tex]\frac{d^2y}{dx^2} + \left(\frac{dy}{dx}\right)^2 + p^2 = 0\\\\[/tex] when [tex]y = \ln\left(\sin(px)+\cos(px)\right)\\\\[/tex]

Side note: This is an example of showing that the given y function is a solution to the given second order linear differential equation.

Answer:

$54.32

Step-by-step explanation:

19=$36.48/19 =1.94

1=$1.94 * 28= 54.32

28=54.32

Answer:

(B) -4

Step-by-step explanation:

so, do the multiplications and see :

(a - 1/a)² = a² - 2×a/a + 1/a² = a² - 2 + 1/a²

(a + 1/a)² = a² + 2×a/a + 1/a² = a² + 2 + 1/a²

now we need to subtract the second from the first :

(a² - 2 + 1/a²) - (a² + 2 + 1/a²) =

= a² - 2 + 1/a² - a² - 2 - 1/a² = -4

and that's it !

Answer:

4

Step-by-step explanation:

There are 4 reflectional symmetry

Answer:

Step-by-step explanation:

(1 + 2i) / (1 + i)                            Rationalize the denominator.

(1 + 2i)(1+i) / (1 + i)(1-i)                  Remove the brarckets

(1 + i + 2i - 2) / (1 - i + i  - i^2)     Combine

-1 + 3i / (2)                                i^2 = - 1 in the denominator

Answer:

9×10^7 + 9×10^6 + 9×10^4 + 8×10^3 + 1 ×10^2 + 9×10 + 2

please mark this answer as brainlist

Step-by-step explanation:

Three-halves = 4 = 6

HOPE SO IT HELP'S YOU

Answer:

586 cm^3 and 486 in^2

Step-by-step explanation:

4) The volume of the triangular prims is (1/2)*(a*c*h) = 0.5*(8*9*16)=586 cm^3

5) Wrapping paper needed is equal to the surface area of the cube, 6s^2=486 in^2

Answer:504

This is the answer

504

Answer:

Hello,

Just using the theorem of Thalès,

Step-by-step explanation:

Let say h the hight of the building

[tex]\dfrac{h}{3} =\dfrac{42.75}{1.23}\\\\h=104.268296...\approx{104(m)}[/tex]

Step-by-step explanation:

Many factors would be used to assess the effectiveness of a human rights campaign, including the following:

Social Influence. Direct Interpersonal Reach. Participant Observation. Reputation. Volume of Search & Interest. Website Traffic.

National Research.

Answer:

H0: µd = 0 (claim)

H1: µd ≠ 0

This is a two-tail t-test for µd

Step-by-step explanation:

This is a paired (dependent) sample test, with its hypothesis is written as :

H0: µd = 0

H1: µd ≠ 0

From the equality sign used in the hypothesis declaration, a not equal to ≠ sign in the alternative hypothesis is used for a two tailed t test

The data isn't attached, however bce the test statistic cannot be obtained. However, the test statistic formular for a paired sample is given as :

T = dbar / (Sd/√n)

dbar = mean of the difference ; Sd = standard deviation of the difference.

Answer:

The state can issue 456,976,000 license plates.

Step-by-step explanation:

For digits, it is assumed that we can use 0-9. Thus, there are 10 options for each slot with a digit.

For letters, it is assumed that we can use the 26 letters of the alphabet (i.e. A through Z). Thus, there are 26 options for each slot with a letter.

For this particular problem, the slot method can be used. Assuming that repetition of letters/digits is allowed:

[tex]\frac{10}[/tex] [tex]\frac{26}[/tex] [tex]\frac{26}[/tex] [tex]\frac{26}[/tex] [tex]\frac{26}[/tex] [tex]\frac{10}[/tex] [tex]\frac{10}[/tex]

= 10*26*26*26*26*10*10

=456,976,000.

Therefore, the state can issue 456,976,000 license plates.

9514 1404 393

Answer:

  21.  D

  22.  C

Step-by-step explanation:

21. The expansion of the given expression is ...

  [tex]\displaystyle -\frac{1}{2}\left(-\frac{3}{2}x+6x+1\right)-3x=\frac{3}{4}x-3x-\frac{1}{2}-3x\\\\=\left(\frac{3}{4}-3-3\right)x-\frac{1}{2}=\boxed{-5\frac{1}{4}x-\frac{1}{2}}[/tex]

__

22. The least likely team to make the championship game is the one with the lowest probability.

  3/8 < 1/2 < 2/3 < 4/5

The Bulldogs are least likely to play in the championship game.

Answer:

[tex]106 \frac{3}{5}[/tex]

Explanation:

Convert any mixed numbers to fractions.

Reduce fractions where possible.

Then your initial equation becomes:

[tex]\frac{26}{5} \times \frac{-31}{3}[/tex]

Next, apply the fractions formula for multiplication. Formula below:

[tex]\dfrac{a}{b} \times \dfrac{c}{d} = \dfrac{a \times c}{b \times d}[/tex]

[tex]= \frac{26 \times -41}{5 \times 2}= \frac{-1066}{10}[/tex]

Simplifying -1066/10, (you can do this by using division) the answer is:  

[tex]106 \frac{3}{5}[/tex]

Answer:

-3 1/3

Step-by-step explanation:

5 2/10 x -10 1/3

10/10 x -10/3

1 x-10/3

-10/3

-3 1/3

your question is unclear. I think I understand it correctly

Answer:

Step-by-step explanation:

If two triangles have two congruent sides and a congruent non included angle, then triangles are not necessarilly congruent.

Answer:

5а⁶=а⁶+а⁶+а⁶+а⁶+а⁶

~~~~~~~~

The probability that a randomly selected finishing time is greater than 80 seconds is 0.84.

Mean = 87

Standard deviation = 7

We convert this to standard normal as

P( X < x) = P( Z < x - Mean / SD)

Since, 80 = 87 - 7

80 is one standard deviation below the mean.

Using the empirical rule, about 68% of data falls between 1 standard deviation of the mean. So, 32% is outside the 1 standard deviation of the mean, and 16% is outside to either side.

We have to calculate P( X > 80) = ?

That is probability of all values excluding lower tail of the distribution.

P(X > 80) = 68% + 16%

= 84%

= 0.84

Learn more about probability on:

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#SPJ1

Given:

The function is:

[tex]f(x)=x^2-x+1[/tex]

To find:

The result of the operation [tex]-f(x)=-(x^2-x+1)[/tex].

Solution:

If [tex]g(x)=-f(x)[/tex], then the graph of f(x) is reflected across the x-axis to get the graph of g(x).

We have,

[tex]f(x)=x^2-x+1[/tex]

The given operation is:

[tex]-f(x)=-(x^2-x+1)[/tex]

So, it will result in a reflection across the x-axis.

Therefore, the correct option is A.

Answer:

A) reflection across the x-axis.

Step-by-step explanation: I took the test

9514 1404 393

Answer:

  7,6 cm

Step-by-step explanation:

The law of sines can be used to find the length AB.

  AB/sin(C) = BC/sin(A)

A = 180° -48° -52° = 80°

  AB = BC·sin(C)/sin(A) = 12,8·sin(52°)/sin(80°)

The sine function can be used to find AD from AB.

  AD/AB = sin(48°)

  AD = AB·sin(48°) = 12,8·sin(48°)sin(52°)/sin(80°)

  AD ≈ 7,61 cm

__

The dimension of interest is ha in the attachment, the height from vertex A.

9514 1404 393

Answer:

  B)  K′ = (–2,2), L′ = (1,2), M′ = (1,–1), N′ = (–2,–1)

Step-by-step explanation:

Translation 2 units right adds 2 to the x-coordinate.

Translation 4 units upward adds 4 to the y-coordinate.

The translation can be represented by the relation ...

  (x, y) ⇒ (x +2, y +4)

__

You can choose the correct answer by looking at the translation of K.

  K(-4, -2) ⇒ K'(-4+2, -2+4) = K'(-2, 2) . . . . . matches choice B

Answer:

The equation of the line is y = -2/3x - 29/3

Step-by-step explanation:

The slope of these points (-7,-5) and (-1,-9) is m = -2/3

Once you plug that into the y = mx + b equation, you can see that the y-intercept is -29/3.

Put all of that into the y = mx + b equation and you'll get -->  y = -2/3x - 29/3

Answer:

c) centroid

Step-by-step explanation:

Answer

33 percent

Step-by-step explanation:

Answer:

33 squares are shaded 23%

Step-by-step explanation:

I hope this answer works out for you if it doesn't I'm really sorry have a great day

Answer:

8/52

Step-by-step explanation:

The first thing to do is write it out;

How many aces are in a deck and how many sixes?

There are 4 of each so, 4+4 = 8 therefore our beginning ratio will be;

8/52 cards are going to be an ace or a six.

The focus here is the use of "Compounding interest rate" and these entails addition of interest to the principal sum of the deposit.

The below calculation is to derive maturity value when annual rate of 3.1% is applied.

Principal = $5,400

Annual rate = 3.1% semi-annually for 1 years

A = P(1+r/m)^n*t where n=1, t=2

A = 5,400*(1 + 0.031/2)^1*2

A = 5,400*(1.0155)^2

A = 5,400*1.03124025

A = 5568.69735

A = $5,568.70.

In conclusion, the accrued value she will get after one years for this account is $5,568.70,

- The below calculation is to derive maturity value when the amount compounds continuously at an annual rate of 4%

Principal = $5,400

Annual rate = 4% continuously

A = P.e^rt where n=1

A = 5,400 * e^(0.04*1)

A = 5,400 * 1.04081077419

A = 5620.378180626

A = 5620.378180626

A = $5,620.39.

In conclusion, the accrued value she will get after one years for this account is $5,620.39.

Referring to how much would Tyra's balance be from Account 2 over 3.7 years. It is calculated as follows:

Annual rate = 4% continuously

A = P.e^rt where n=3.7

A = 5,400 * e^(0.04*3.7)

A = 5,400 * e^0.148

A = 5,400 * 1.15951289636

A = 6261.369640344

A = $6,261.37

Therefore, the accrued value she will get after 3.7 years for this account is $6,261.37

Learn more about Annual rate here

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Answer:

x=0,-3

Step-by-step explanation:

x(x+3)(x+3)=0

Using the zero product property

x=0  x+3=0 x+3 =0

x=0  x=-3  x=-3