Answer:
329 miles
Step-by-step explanation:
Create a proportion where x is the distance the car can travel on 14 gallons of gas:
[tex]\frac{70.5}{3}[/tex] = [tex]\frac{x}{14}[/tex]
Cross multiply and solve for x:
3x = 987
x = 329
So, the car can travel 329 miles on 14 gallons of gas
Answer:
329 miles
Step-by-step explanation:
We can write a ratio to solve
70.5 miles x miles
--------------- = ------------
3 gallons 14 gallons
Using cross products
70.5 * 14 = 3x
987=3x
Divide each side by 3
987/3 = 3x/3
329=x
329 miles
The principle
P=6000 A=6810 T=3 years
Answer:
incomplete question
Step-by-step explanation:
that is what is wrong with your question
Answer:
r = 4.3%
Step-by-step explanation:
6810= 6000(x)^3
6810/6000= (x)^3
x = 1.043114431
r = 043114431
The fuel efficiency of a vehicle is 28 miles per gallon and gasoline cost 2.25 per gallon. What is the cost per mile to drive the vehicle?
Answer:
$.08 per mile
Step-by-step explanation:
$2.25 gallon
------------ * ---------------
gallon 28 miles
$2.25
-------------
28 miles
$.080357143 per mile
Rounding to the nearest cent
$.08 per mile
What are the divisible number(s) for 430?
Answer:
The numbers that 430 is divisible by are 1, 2, 5, 10, 43, 86, 215, and 430.
Line K is parallel to line I.
k
m
n
Which angle is congruent to 24?
21
0 22
025
Answer:
<4 = <1
Step-by-step explanation:
Judging from the picture, <1 and <4 are opposite angles. Opposite angles are always congruent. Hope this helps!
6x — Зу = 5
y - 2x = 8
How many solutions does the system have?
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Answer:
none
Step-by-step explanation:
Multiplying the second equation by -3 gives ...
6x -3y = -24
Values of x and y that satisfy this equation cannot also satisfy the first equation ...
6x -3y = 5
There are no solutions to this system of equations.
__
The equations describe parallel lines. There is no point of intersection.
Help on 3,5,7,9,11,13.15,17, please thank you
Answer:
3. 6a+60
5. 25+5w
7. 90-10t
11. 4.5-12c
13. f-2
15. 12z+1.5
Step-by-step explanation:
3.
6(a+10)
Multiply 6 by both factors in the parentheses, in this case, a and 10.
6*a = 6a
6*10 = 60
6(a+10) = 6a + 60
I only put the step- by- step explanation for #3, but you should be able to figure the rest out with that.
The final price of the textbook for an English literature course is 13.5% more than the listed price when tax and shipping costs are included. If the listed price is $147, what is the final price of the textbook?
(Round to the nearest dollar.)
Answer:
The final price of the textbook rounded to the nearest dollar is $167
Step-by-step explanation:
To solve this problem, we need to find out what 13.5% of $147 equals.
13.5% = 0.135
0.135 x $147 = $19.845
$147 + 19.845 = 166.845
Round to the nearest dollar to get $167
(d) (8x2 + 7y2 – z2 + 2yz + 3xz – 5xy) * (2x – 3y) vertical method
Answer:
(8x²+7y²–z²+2yz+3xz–5xy) × ( 2x–3y)
= (16x³+14xy²–2z²x+4yzx+6x²z–10x²y –24yx²–21y³+3z²y–6y²z–9xzy+15xy²)
=( 16x³+29xy²–2z²x–5xyz+6x²z–34x²y–21y³+3z²y–6y²z)
[tex] = 16 {x}^{3} - 21 {y}^{3} - 2 {z}^{2}x + 3 {z}^{2} y - 5xyz - 6 {y}^{2} z + 6 {x}^{2} z - 34 {x}^{2} y+ 29x {y}^{2} [/tex]
I hope I helped you^_^
A $22,000 loan was taken out. If $24,805 is due at the end of the loan after being compounded daily at 2.5%, how many
years was the loan for? (Round to the nearest tenth of a year)
Provide your answer below
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Answer:
4.8 years
Step-by-step explanation:
Solving the compound interest formula for the number of years gives ...
t = log(A/P)/(n·log(1 +r/n))
where principal P invested at rate r compounded n times per year produces value A after t years.
t = log(24805/22000)/(365·log(1 +0.025/365)) ≈ 4.800
The loan was for 4.8 years.
A construction crane lifts a bucket of sand originally weighing 145 lbs at a constant rate. Sand is lost from the bucket at a constant rate of .5lbs/ft. How much work is done in lifting the sand 80ft?
Answer: [tex]10,000\ lb.ft[/tex]
Step-by-step explanation:
Given
Initial weight of the bucket is [tex]145\ lb[/tex]
It is lifted at constant rate and rate of sand escaping is [tex]0.5\ lb/ft[/tex]
At any height weight of the sand is [tex]w(h)=145-0.5h[/tex]
Work done is given by the product of applied force and displacement or the area under weight-displacement graph
from the figure area is given by
[tex]\Rightarrow W=\int_{0}^{80}\left ( 145-0.5h \right )dh\\\\\Rightarrow W=\left | 145h-\dfrac{0.5h^2}{2} \right |_0^{80}\\\\\Rightarrow W=\left [ 145\times 80-\dfrac{0.5(80))^2}{2} \right ]-0\\\\\Rightarrow W=11,600-1600\\\\\Rightarrow W=10,000\ lb.ft[/tex]
1. Find the volume of the shipping box using the two methods and show your work plzzzzzzzz i neeeeeeeeeeeeeed help
Step-by-step explanation:
Measure the width, length and height of the shipping box in inches. Multiply the width, length and height of the box to calculate its volume in cubic inches. For example, if the box is 20 inches wide, 24 inches long and 16 inches high, then the volume is (20)(24)(16) = 7,680 cubic
Answer:
The volume of the shipping box would be 36 9/16
Step-by-step explanation:
One method to find the volume of the shipping box would be (l)(w)(h)
one we plug in our dimensions the equation would become 3 1/4 x 3 x 3 3/4
To simplify this we would first
Multiply
3 1/4 x 3 x 3 3/4 = 39/4 x 3 3/4
The bolded parts are the pieces we are working on
3 1/4 as an improper fraction is 13/4
13/4 x 3 = 13 x 3/4 = 39/4
- The second step would be to
Convert the mixed number to an improper fraction.
3 3/4 = ( 3 × 4 ) / 4 + 3/4 = 12 + 3 / 4 = 15/4
Now we have to Multiply
39/4 x 15/4 = 39 x 15 / 4 x 4 = 585/16
Lastly, we have to simplify
585/16 = 36 9/16
Type the correct answer in each box. Use numerals instead of words. If necessary, use / for the fraction bar(s).
Consider the equation below.
[tex]3x^{3x-2}=81[/tex]
To solve the given exponential equation, solve the linear equation [tex]3x-2=[/tex]
Answer:
[tex]ıf \: {3x}^{3x - 2} = 81[/tex]
Step-by-step explanation:
use logarithmic function
[tex] log_{3x}(81) = 3x - 2[/tex]
Answer:
4 and x=2
Step-by-step explanation:
:}
A particle is moving such that its height h at time t is given by h(t) = 2 + 8t - 3t^2 + 1/5t^3. The average velocity of the particle on the period [0,3] is
[tex]\\ \Large\sf\longmapsto h(t)[/tex]
[tex]\\ \Large\sf\longmapsto 2+8t-3t^2+\dfrac{1}{5}t^3[/tex]
[tex]\\ \Large\sf\longmapsto 2+8(3)-3(3)^2+\dfrac{1}{5}(3)^3[/tex]
[tex]\\ \Large\sf\longmapsto 2+24-3(9)+\dfrac{27}{5}[/tex]
[tex]\\ \Large\sf\longmapsto 26-27+5.4[/tex]
[tex]\\ \Large\sf\longmapsto -2+5.4[/tex]
[tex]\\ \Large\sf\longmapsto h(t)=3.4m[/tex]
Estimate the product of 0.235 and 13.467 to the nearest hundredth. Round each value to the nearest hundredth before multiplying. Your final answer should also be rounded to the nearest hundredth.
Answer:
0.235 = 0.24
13.467 = 13.47
0.24+13.47=13.71
find the missing length indicated
Answer:
192
Step-by-step explanation:
geometric mean theorem :
with p and q being the segments of the Hypotenuse, then
h = x = sqrt(p×q)
p = 144
q = 400-144 = 256
h = x = sqrt(144×256) = 12×16 = 192
Write a quadratic equation with integer coefficients having the given numbers as solutions.
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Answer:
x² -22 = 0
Step-by-step explanation:
The roots are opposites, so the equation is pretty simple.
x = ±√22
x² = 22 . . . . . square both sides
x² -22 = 0 . . . . your quadratic equation in standard form
Which choices are equivalent to the quotient below? Check All That Apply.
Answer:
Option C. √5/3
Step-by-step explanation:
We'll begin by simplifying √15 / 3√3. This can be obtained as follow:
√15 / 3√3
Rationalise
√15 / 3√3 × (√3 /√3)
(√15 × √3) / (3√3 × √3)
√45 / (3 × 3)
√45 / 9
Recall:
√45 = √(9 × 5) = √9 × √5 = 3√5
Thus,
√45 / 9 = 3√5 / 9
√45 / 9 = √5 / 3
Therefore,
√15 / 3√3 = √5 / 3
Thus, option C gives the right answer to the question.
Which of the relations given by the following sets of ordered pairs is a function?
o {(5,2), ( - 4, 2), (3,6), (0,4), (- 1, 2)}
o {(5, 4), (5, 6), (5,8), (5, 10), (5, 12)}
{(-3, - 2), ( - 2, – 1), (0, - 1), (0, 1), (1, 2)}
{(7,3), ( – 6,8), ( – 3,5), (0, – 3), (7, 11)}
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Answer:
(a) {(5, 2), (-4, 2), (3, 6), (0, 4), (-1, 2)}
Step-by-step explanation:
The only relation with no repeated x-values is the first one. The first relation is a function.
the cost of 1 kg tomato is RS . 75.Find the cost of 14 kg
Answer:
Cost of 1kg tomato=rs.75
Cost of 14kg tomato=(75×14)
rs.1050
Describe and correct the error in determining the formula for the sequence below
Answer:An arithmetic progression or arithmetic sequence is a sequence of numbers such that the difference between the consecutive terms is constant. For instance, the sequence 5, 7, 9, 11, 13, 15.. . is an arithmetic progression with a common difference of 2.
Step-by-step explanation:
Please help!!!!
CE is tangent to this circle, CD is a radius and ECB=48 what is BAC
Answer:
48degrees
Step-by-step explanation:
From the circle geometry shown, traingle BDC is an isosceles triangle which shows means that their base angels are the same. Hence;
<B = <C
<CBD + <BCD + <D = 180
<BCD + <BCD + <D =180
2<BCD + <BDC = 180
Get <BCD;
<BCD+ <ECB = 90
<BCD + 48 = 90
<BCD = 90 - 48
<BCD = 42degrees
Get <BDC
2<BCD + <BDC = 180
2(42)+ <BDC = 180
84 + <BDC = 180
<BDC = 180 - 84
<BDC = 96
Since angle at the centre is twice that at the circumference, then;
<BAC = 1/2(<BDC )
<BAC = 96/2
<BAC = 48degrees
A trader sold 90 oranges at 3 for GHC 0.75.
How much did she get from selling all the
oranges?
Answer:
GHC22.5
Step-by-step explanation:
90/3=30
30=0.75
30×0.75
=22.5
Một đài khí tượng thủy văn muốn xem xét khả năng dự báo thời tiết của mình. Từ số liệu thống kê chỉ ra rằng: xác suất dự báo có nắng trong ngày không mưa là 0,95; có nắng trong ngày mưa là 0,8; xác suất một ngày sẽ không mưa là 0,6. a. Tính xác suất dự báo ngày sẽ có nắng. b. Biết đã có dự báo là ngày có nắng, tính xác suất để ngày đó là ngày không mưa.
Answer:
ask in English then I can help u
7. Find HCF of: x'y and ly*
8. Find LCM of 4x - 20 and 6x - 30
9. Factorize Factorize: -m-+ 1 + me
10. Factorize: 4x100
11. Simplify: V18+ va 12. If a = 2, b = 3 and c= 4, fmd the value of a b c 13. Subtract: 125- 45 a--200+ 14. Simplify: ***
PLEASE HELP ME
Answer:
7 ans-HCF is y
Step-by-step explanation:
soln
first expression=X and y
second expression=l and y
so HCF means common so the Ans is y
a recent survey shows that 66% of college students have a cat and 37% have a HBO subscription. Assuming these two events are independent, what is the probability that a randomly selected student has neither a cat nor HBO
Answer:
[tex]P(C'\ and\ H') =0. 2178[/tex]
Step-by-step explanation:
Let
[tex]C \to[/tex] Student with cat
[tex]H \to[/tex] Student has HBO sub
[tex]P(C) = 66\% \\ P(H) = 37\%[/tex]
Required
[tex]P(C'\ and\ H')[/tex]
This is calculated as:
[tex]P(C'\ and\ H') = P(C') * P(H')[/tex]
Using complement rules, we have:
[tex]P(C'\ and\ H') = [1 - P(C)] * [1 - P(H)][/tex]
So, we have:
[tex]P(C'\ and\ H') = [1 - 66\%] * [1 - 37\%][/tex]
[tex]P(C'\ and\ H') = [33\%] * [66\%][/tex]
[tex]P(C'\ and\ H') =0. 2178[/tex]
Domain and range of g(x)= 5x-3/2x+1
Solve for domain and range?
Apply Simpson's rule to approximate the value of integration 1 to 4 e^x In x dx with n = 3.
[tex]Here, h=41,0.25,y=1+x21
[/tex]
[tex]x y101.020.25 0.9413 0.250.94140.750.64510.5
[/tex]
[tex]By Simpson's Rule:
[/tex]
[tex]∫011+x2dx=4×31
[/tex]
[tex][(1+0.5)+4(0.941+0.941+0.64)+2(0.8)]
[/tex]
[tex]=121[9.424]=0.785
[/tex]
13.
а/8 = $1.25
Can someone help explain
Answer:
a= $10.00
Step-by-step explanation:
It's very simple. Move /8 to the other side of the equation. It should give you $1.25 x 8. Solve the multiplication and you should get $10.00.
If I didn't make my explanation clear enough, please comment. I sometimes don't even explain myself very well.
Answer:
a = 10
Step-by-step explanation:
a/8 = 1.25
multiply both sides by 8 to isolate a.
(8)(a/8) = 1.25(8)
which gives you
a = 1.25(8)
which simplifies to
a = 10
Convert 2546 in base 10 to base 5
Answer:
40141
Step-by-step explanation:
round to the nearest Ten-thousand: 849,708
Answer:
850,000
Step-by-step explanation:
Answer: 850,000
Concept:
Here, we need to know the order and name of each place value.
Please refer to the attachment below for the specified names.
Solve:
8 = Hundred thousands
4 = Ten thousands
9 = One thousands
7 = Hundreds
0 = Tens
9 = Ones
Since the values before the ten thousands place, which would be the one thousands place, is greater than 5, then we should round up.
Therefore, the rounded value would be [tex]\boxed{850,000}[/tex]
Hope this helps!! :)
Please let me know if you have any questions
