A car driver sees a rabbit on the road. The driver makes an emergency stop after he sees the rabbit. Figure given shows the speed of the car from the time the driver sees the rabbit until the car stops. ) Calculate the distance that the car travels in the first 0.5 seconds.

2. A car of mass 1000 kg is moving with a velocity of 10 m/s. If the velocity-time graph for this car is a horizontal line parallel to the time axis, then the velocity of the car at the end of 25 s will be:

Answers

Answer 1

Answer:

car go vroom

Explanation:


Related Questions

the movement of liquid particles through a circular motion

Answers

Answer:

Solids - vibrational (and rotational); moving very slowly.

Liquids - vibrational, rotational, and translational; moving quickly.

Gases - vibrational, rotational, and translational; moving very quickly.

Explanation:

Particles are always moving. No matter what. There is a certain point where they move so slowly it is considered minuscule, but they are in fact moving.

Thus, in solids, liquids, and gases, you can expect particles to move in a certain trend. That trend is average kinetic energy of the particles and the forces holding them together (attraction).

Explanation:

It’s how the way of the motion is

A ball of mass 100g thrown by a man moves at a velocity of 100m/s. what is the momentum? need the answer step by step plssss!!​ i need it fast!!!!!!!

Answers

Explanation:

Mass of the ball= 100 g = 0.1 kg

Velocity of the ball before collision=10 m/s

Momentum of the ball before collision, p(i)=mv= 0.1×10=1 kgm/s

Since, ball returns back with same velocity

Therefore, velocity of ball after collision = -10 m/s (-ve sign due to opposite direction)

So, momentum of ball after collision,p(f) = 0.1 ×(-10) = -1 kgm/s

Now, Impulse generated in the ball= change in momentum= p(f)-p(i)= -1–1= -2 kgm/s

λ=
mv
h


λ⟶De Broglie wavelength
m=100 g=
1000
100

kg=0.1 kg
v=100 ms
−1

λ=
mv
h

=
0.1×100
6.623×10
−34


=6.626×10
−35
m
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