Answer: The number of electrons in given amount of silver are [tex]1.839\times 10^{24}[/tex]
Explanation:
The number of moles is defined as the ratio of the mass of a substance to its molar mass.
The equation used is:
......(1)
We are given:
Mass of silver = 7.0 g
Molar mass of silver = 107.87 g/mol
Putting values in equation 1:
[tex]\text{Moles of silver}=\frac{7.0g}{107.87g/mol}=0.0650 mol[/tex]
According to the mole concept:
1 mole of a compound contains [tex]6.022\times 10^{23}[/tex] number of particles.
Number of electrons per atom of silver = 47
So, 0.065 moles of silver will contain = [tex](0.065\times 6.022\times 10^{23}\times 47)=1.839\times 10^{24}[/tex] number of electrons
Hence, the number of electrons in given amount of silver are [tex]1.839\times 10^{24}[/tex]
Look at picture please
Answer:
Keep temperature constant and increase the pressure of the reaction. The rate of reaction increases.
Explanation:
First of all, the question is asking us to design an experiment to investigate the effect of pressure on the rate of reaction hence the pressure can not be held constant since it is the variable under investigation. This eliminates the first option.
Secondly, increasing the pressure of the reaction means that particles of the gas collide more frequently leading to a greater number of effective collisions and a consequent increase in the rate of reaction according to the collision theory.
Hence the answer above.
A bottle containing a reagent was weighed to show a mass of 25.3658 g. Some material was carefully transferred to a reaction flask, and the bottle reweighed to show a mass of 22.1287 g. What mass of the material was transferred to the flask
Answer:
3.2371 g
Explanation:
Step 1: Given data
Initial mass of the bottle and the reagent: 25.3658 gFinal mass of the bottle and the reagent: 22.1287 gStep 2: Calculate the mass of the material was transferred to the flask
Since the bottle is unaltered, the mass of the material transferred to the flask is equal to the difference between the initial mass of the system and the final mass of the system.
m = 25.3658 g - 22.1287 g = 3.2371 g
What is the definition of outer layer? *
Answer:
1 being or located on the outside; external
2 further from the middle or central part
Explanation:
how many grams of O2 are produced when 0.065 mol of water decompose ?
Answer: The answer is 0.52 grams.
2H2O->2H2+O2
So, we can say that,
2 moles of water= 16 gm of O2
Then
0.065 moles of water=16/2*0.065 gm
=0.52 gm
Hope you understood:)
How many grams of Al2O3 is extracted from 250. g of FeO?
Answer:
[tex]m_{Al_2O_3}=118.27gAl_2O_3[/tex]
Explanation:
Hello there!
In this case, if we consider the following chemical reaction, whereby Al2O3 is produced from Al and FeO:
[tex]3FeO+2Al\rightarrow 3Fe+Al_2O_3[/tex]
Thus, since there is 3:1 mole ratio of FeO to Al2O3, it turns out feasible for us to use their molar masses, 71.844 g/mol and 101.96 g/mol respectively, to obtain the grams of the latter as follows:
[tex]m_{Al_2O_3}=250.gFeO*\frac{1molFeO}{71.844gFeO}*\frac{1molAl_2O_3}{3molFeO} *\frac{101.96gAl_2O_3}{1molAl_2O_3}\\\\m_{Al_2O_3}=118.27gAl_2O_3[/tex]
Regards!
A voltaic cell consists of a standard hydrogen electrode and a second half-cell in which a magnesium electrode is immersed in a 1.00 M solution of Mg2+ ions. Calculate Ecell given that the standard reduction potential for the magnesium half-reaction is -2.37 V.
Answer:
The correct answer is "+2.37 V".
Explanation:
Given that,
Concentration of [tex]Mg^{2+}[/tex]
= 1.00 M
[tex]E^0 \ Mg^{2+}/Mg[/tex],
= -2.37 V
[tex]E^0 \ \mu^+/H_2[/tex],
= 0.00V
When S.H.E as well as anode act as cathode, then
⇒ [tex]E^0 cell=E^cathode-E^0 anode[/tex]
By putting the values, we get
⇒ [tex]=0.00V-(-2.37 V)[/tex]
⇒ [tex]=+2.37 \ V[/tex]
In the clinical laboratory, testing to identify specific porphyrins is performed using Group of answer choices Fluorometric emission scanning Chemical derivatization and spectrophotometry Liquid chromatography with fluorescent detection Thin layer chromatography
Answer:
Fluorometric emission scanning.
Explanation:
Fluorometric emission scanning is used to detect the presence of porphyrins. There are various types of porphyrins and they can be tested in a lab with either, urine or blood sample testing.
Alkenes undergo an addition reaction with borane in tetrahydrofuran (THF). For the reaction below: Write a mechanism for the reaction using curved arrows to show electron reorganization. b. write a mechanism
Answer:
See explanation and image attached
Explanation:
Alkenes react with borane (BH3) as shown in the image attached. Borane is a good electrophile since it is an electron deficient compound.
It can attack the electron rich pi bond. The attack of borane on the pi bond occurs as shown and leads to an addition reaction. Hydrogen and BH2^- are added across the double bond as shown.
The product of this reaction is shown in the image attached.
if a cold piece of metal is added to hot water, the water will
Answer:
Over time the metal will cool and the water will heat up. Eventually the two objects will have the same temperature
Explanation:
Significant number of
A) 2348
B) 7.0001
C) 0.0023
D)24,500
E) 0.1060
Answer:
significant number of what
What type of reaction is the following
chlorine +
potassium nitride
- nitrogen
+
potassium chloride
Explanation:
Answer
Open in answr app
Correct option is
A
Precipitation reaction
B
Double displacement reaction
Balanced equation for the reaction is:
KCl(s)+AgNO3(aq)→AgCl(s)+KNO3(aq)
It is a double displacement reaction as both reactants exchange ions to form new products. Also, it is a precipitation reaction as white precipitates of silver chloride(AgCl) are formed.
If something is not an acid or a base what is it
Answer:
neutral one with ph equal to 7
C2H6O2 is infinitely miscible (soluble) in water. Ethylene glycol is a nonelectrolyte that is used as antifreeze. What is the lowest possible melting point for engine coolant that is 27.1 % (by mass) ethylene glycol
Answer:
-11.13 Degree Celsius
Explanation:
Here
Kf for H20 is 1.86 C/m
Mass of ethylene glycol = 27.1/100 * 100 = 27.1 grams
Number of moles of ethylene in 30 grams of ethylene = 27.1 g/molar mass of ethylene glycol = 27.1/62.07 = 0.4366 mol
Mass of water = 100 – 27.1 = 72.9 grams
Molality = Moles/Mass of water in Kg = 0.4366 /0.0729 = 5.989 m
Melting Point Depression = Kf * Molality = 1.86 *5.989 = 11.13 deg C
Melting point of solution = Melting point of water - Melting Point Depression
= 0 – 11.13 = -11.13 Degree Celsius
Cesium-137 is part of the nuclear waste produced by uranium-235 fission. The half-life of cesium-137 is 30.2 years. How much time is required for the activity of a sample of cesium-137 to fall to 9.32 percent of its original value
Answer:
t(9.32% remaining) = 203 yrs (3 sig. figs.)
Explanation:
All radioactive decay follows a 1st order decay profile. This is defined by the expression ...
A =A₀e^-k·t
A = final activity = 9.32%
A₀ = initial activity = 100%
e = base of natural logs
k = rate constant = 0.693/t(1/2) = (0.693/30.2) yrs⁻¹ = 0.023 yrs⁻¹
t = time of decay = ln(A/A₀)/-k = ln(9.32%/100%)/-0.023 yrs⁻¹
= 203.286637 yrs (calc. ans.)
≅ 203 yrs (3 sig. figs.)
What causes heat energy when you rub two objects against each other? (2 points)
Group of answer choices
The air around the objects
The flow of heat from one object to the other
The friction between the two objects
The pull of gravity on the two objects
What is the heat of a reaction, in joules, with a total reaction mixture volume of 61.2 mL if the reaction causes a temperature change of 4.6 oC in a calorimeter
Answer:
1178J is the heat of the reaction
Explanation:
Assume that the reaction mixture has a density of 1.00 g/mL and a specific heat of 4.184 J/g-oC. The calorimeter has a heat capacity of 10.0 J/oC
The heat of a reaction follows the equation:
Q = m*S*ΔT
Where Q is the heat of the reaction,
m is the mass:
61.2mL * (1.00g/mL) = 61.2g
S is specific heat = 4.184J/g°C
ΔT = 4.6°C
Replacing:
Q = 61.2g*4.184J/g°C*4.6°C
Q = 1178J is the heat of the reaction
While studying abroad in France, you offer to bake your grandmother's famous cookies for other students in your program.
have a recipe which calls for 3.95 lb of flour, but, of course, in France you will need to purchase flour in kilograms. How m
kilograms of flour does the recipe call for?
3.95 lb =
Answer:
The mass of the flour required to prepare the cookies is 1.8 kg.
Explanation:
The flour required to prepare the cookies is 3.95 lb.
1 lb = 0.454 kg
So, 3.95 lb = 3.95 x 0.454 kg = 1.8 kg
So, the mass of the flour required to prepare the cookies is 1.8 kg.
What is the pH of a sodium hydroxide solution that has an OH- concentration of 1.5 × 10^-10?
Explanation: hi go to hell
What is the wavelength of light that has a frequency of 3.7 x 1014 Hz? Show all work!!!
Answer:
Explanation:
Speed of light = Frequency * Wavelength
Speed of light is 3*10^8 m/s
Wavelength = Speed / Frequency = 3*10^8 / 3.7*10^14
= 8.11*10^(-7) m
= 811 nanometer
The wavelength of light will be
What is wavelength?The wavelength of such a periodic wave would be the interval in which the shape of the wave repeats.
Calculation of wavelength of light
It is given that,
frequency = 3.7 x [tex]10^{14}[/tex] Hz
Speed of light = 3 × [tex]10^{8}[/tex] m/s
frequency × wavelength = speed of light.
wavelength = speed of light / frequency
wavelength = 3 × [tex]10^{8}[/tex] m/s / 3.7 x [tex]10^{14}[/tex] Hz
wavelength = 0.81 × [tex]10^{-7}[/tex] m
wavelength = 8.1 × [tex]10^{-7}[/tex]
Therefore, wavelength of light will be 8.1 × [tex]10^{-7}[/tex].
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Calculate the molarity of a potassium hydroxide solution if 25.0 ml of this solution was completely neutralized by 23.3 ml of 0.506 M sulfuric acid.
Answer: 0.943 M of potassium hydroxide solution is required.
Explanation:
A neutralization reaction is defined as the reaction in which an acid reacts with a base to form a salt and water molecule.
To calculate the molarity of potassium hydroxide, the equation used is:
[tex]n_1M_1V_1=n_2M_2V_2[/tex] ........(1)
where,
[tex]n_1, M_1\text{ and }V_1[/tex] are the n-factor, molarity and volume of acid that is [tex]H_2SO_4[/tex]
[tex]n_2, M_2\text{ and }V_2[/tex] are the n-factor, molarity and volume of the base that is KOH
We are given:
[tex]n_1=2\\M_1=0.506M\\V_1=23.3mL\\n_2=1\\M_2=?M\\V_2=25.0mL[/tex]
Putting values in equation 1, we get:
[tex]2\times 0.506\times 23.3=1\times M_2\times 25.0\\\\M_2=\frac{2\times 0.506\times 23.3}{1\times 25.0}\\\\M_2=0.943M[/tex]
Hence, 0.943 M of potassium hydroxide solution is required.
Decide whether a chemical reaction happens in either of the following situations. If a reaction does happen, write the chemical equation for it. Be sure your chemical equation is balanced and has physical state symbols. situation chemical reaction
The question is incomplete, the complete question is;
Decide whether a chemical reaction happens in either of the following situations. If a reaction does happen, write the chemical equation for it. Be sure your chemical equation is balanced and has physical state symbols. situation chemical reaction? chemical equation A strip of solid lead metal is put into a beaker of 0.043M Fe(NO3)2 solution. yes no A strip of solid iron metal is put into a beaker of 0.044M Pb(NO3)2 solution.
Answer:
No
Yes
Explanation:
A single replacement reaction occurs when a metal that is higher in the electrochemical series is placed in a solution of the salt of a metal which is lower than it in the electrochemical series.
For instance, when a strip of solid iron metal is put into a beaker of 0.044M Pb(NO3)2 solution, a reaction occurs as follows;
Fe(s) + Pb(NO3)2(aq) ---------> Fe(NO3)2(aq) + Pb(s)
However, when a strip of solid lead metal is put into a beaker of 0.043M Fe(NO3)2 solution no reaction occurs because lead is lower than iron in the electrochemical series hence it can not displace iron from an aqueous solution of its salt.
Why is iodine always Used in a solution containing excess I2
Answer:
If a standard iodine solution is used as a titrant for an oxidizable analyte, the technique is iodimetry. If an excess of iodide is used to reduce a chemical species while simultaneously forming iodine.
Iodine always used in a solution excess KI is given to aid in the solubilization of free iodine, which would be insoluble in clean water during normal circumstances.
What is Iodine?
Iodine is a kind of element which are mainly used in iodometry titration. It can be represented by I.
What is solution?A solution would be a homogenous mixture of two components, usually a solute as well as a solvent.
Iodimetry would be a technique that uses a standard iodine solution as a titrant for such an oxidizable analyte. When an excessive amount of iodide is used to decrease a chemical while somehow producing iodine.
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Name the parts of an electromagnet
Answer:
The iron core, copper wire, and an electricity source.
Explanation: Me
If you have 9.06 x 10^24 molecules of NaNO3, how many grams do you have of NaNO3
Answer:
Explanation:
1 mol of anything is 6.02 * 10^23 (in this case molecules)
x mol has 9.06 * 10^24 molecules of NaNO3
x * 6.02 * 10^23 = 9.06 * 10^24 * 1 Divide by 6.02 * 10^23
x = 9.06 * 10^24/6.02 * 10^23
x = 1.5 * 10
x = 15 mols of NaNO3
1 mol of NaNO3
Na = 23
N = 14
O3 = 48
Total = 85
1 mol of NaNO3 = 85 grams
15 mols = x Cross Multiply
x = 15 * 85
x = 1275 grams
Note: these numbers are approximate but they are very close. You have to use your own values from your periodic table to find the mass of NaNO3. Your answer will be very close to 85.
What is the
of a 750 milliliters solution containing 54.0 grams of KBr?
Answer:
0.605 M
Explanation:
What is the molarity of a 750 milliliters solution containing 54.0 grams of KBr?
Step 1: Given data
Mass of KBr (solute): 54.0 gVolume of solution: 750 mL (0.750 L)Step 2: Calculate the moles corresponding to 54.0 g of KBr
The molar mass of KBr is 119.00 g/mol.
54.0 g × 1 mol/119.00 g = 0.454 mol
Step 3: Calculate the molarity of the solution
Molarity is equal to the moles of solute divided by the liters of solution.
M = 0.454 mol / 0.750 L = 0.605 M
Hydrogen iodide is not produced by the same method as for hydrogen chloride.why??
Answer:
Using Phosphoric acid will work perfectly for producing Hydrogen halides because its not an Oxidizing agent. ...
Using an ionic chloride and Phosphoric acid
H3PO4 + NaCl ==> HCl + NaH2PO4
H3PO4 + NaI ==> HI + NaH2PO4
H2SO4 + NaCl ==> HCl + NaHSO4
This method(Using H2So4) will work for all hydrogen hydrogen halide except Hydrogen Iodide and Hydrogen Bromide.
The Sulphuric acid won't be useful for producing Hydrogen Iodide because its an OXIDIZING AGENT. Whist producing the Hydrogen Iodide... Some of the Iodide ions are oxidized to Iodine.
2I-² === I2 + 2e-
Explanation:
Identify the compound with the lowest dipole moment. Identify the compound with the lowest dipole moment. CH3CH2CH3 CH3OCH3 CH3CHO CH3OH CH3CN
Answer:
CH3CH2CH3
Explanation:
Dipole moment is the measure of the polarity of a chemical bond. It is the extent of charge separation in a molecule.
Dipole moment is the product of the magnitude of charge and the distance separating the charges from each other.
The molecule having the lowest dipole moment among the options is the molecule that has the least polarity. The least polar molecule among the options is CH3CH2CH3, it has no polar bonds in its structure.
We have that for the Question "Identify the compound with the lowest dipole moment. Identify the compound with the lowest dipole moment. CH3CH2CH3 CH3OCH3 CH3CHO CH3OH CH3CN "
it can be said that
[tex]CH_3CH_2CH_3 have the lowest dipole moment[/tex]From the question we are given
CH3CH2CH3
CH3OCH3
CH3CHO
CH3OH
CH3CN
Generally alkanes have the lowest dipole moment, they have C-H bond which are non polar.
Therefore,
[tex]CH_3CH_2CH_3[/tex] have the lowest dipole moment
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Which characteristics are most likely found in mammals living in a tundra ecosystem
Answer:
Tundra and desert ecosystem are different especially when talking about their climate. Tundra is situated in northern latitude and is very cold having a negative 34 degrees and has a permafrost while desert is often situated closer to equator and thus have hot climate yet they have a similar characteristic when it comes to vegetation or the plants as both experience a water scarcity thus plants are already adapted to live in water-barren environment.
Explanation:
Salt water contains n sodium ions (NA ) per cubic meter and n chloride ions (Cl-) per cubic meter. A battery is connected to metal rods that dip into a narrow pipe full of salt water. The cross-sectional area of the pipe is A:
Answer: hello your question is incomplete below is the complete question
Salt water contains n sodium ions (Na+) per cubic meter and n chloride ions (Cl−) per cubic meter. A battery is connected to metal rods that dip into a narrow pipe full of salt water. The cross sectional area of the pipe is A. The magnitude of the drift velocity of the sodium ions is VNa and the magnitude of the drift velocity of the chloride ions is VCl.
What is the magnitude of the ammeter reading ?
answer :
| I | = neAVₙₐ + neAV (Cl-)
Explanation:
Given that there are N sodium ions
Determine the Magnitude of the ammeter reading
| I | = current due to sodium ions + current due to (Cl-) ions
= neAVₙₐ + neAV (Cl-)
To what Celsius temperature does 750. mL of gas originally at −12°C need to be heated to bring the volume to 2.10 L?
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