Answer:
Se determina mediante al auxilio del cálculo integral.
Supongamos una fuerza variable con el tiempo. Entonces el impulso es:
J = ∫F(t) dt, para t entre t y to
Si es variable con la posición o con la velocidad se deberá expresar la integral en términos de la posición o de la velocidad.
Step-by-step explanation:
What is the period of the graph of y=1/2 sin (2πx) -3?
A. 1
B. 1/2
C. 3
D. 2π
Answer:
A. 1
Step-by-step explanation:
Since this graph is in the form A sin (B(x+c))+d, where
the amplitude is the absolute value of AThe period is 2pi/BPhase Shift is CMidline is y=DTherefore, the values are
A=1/2
B=2pi
C=0
D=-3
So the period is 2pi/2pi which is 1.
Worth 6 points please help!!
Answer:
-9
Step-by-step explanation:
The average rate of change is found by
f(5) - f(2)
------------
5-2
10 - 37
----------
5-2
-27
-----
3
-9
The graph below shows the solution set of which inequality?
[tex]\Large \boldsymbol{} \pmb {Answer: |x|<6}[/tex]
Step-by-step explanation :
[tex]\displaystyle \Large \boldsymbol{} |x|< 6 =>{ \left \{ {{\!\!\!x< 6} \atop {x> -6}} \right. } => \boxed{x \in (-6 ; 6 )} \ \ right[/tex]
Write an inequality and show on a number line all numbers:
less than 4 but greater than or equal to 0
Answer:
the inequality is 0<x<4
Step-by-step explanation:
(0,4)
Hola pordrian ayudarme con esto:
Resuelve las ecuaciones aplicando la fórmula general
a) 2xsobre2-7×+3=0
Hace mucho que ni hacia este tipo de problemas y por eso les pido su ayuda
Answer:
sorry I don't understand can somebody help him??
An Olympic diver starts at 7.5 m above the water. During her dive, she goes
1.5
m below the water. What is the vertical distance the diver travels?
Given that an Olympic diver starts at 7.5 m above the water, during her dive, she goes 1.5 m below the water, the vertical distance the diver travels is 9 meters.
To determine what is the vertical distance the diver travels the following calculation must be performed:
The initial height must be subtracted from the final height, in order to obtain the difference between the two heights.
1.5 - (-7.5) = X1.5 + 7.5 = X9 = XTherefore, the vertical distance the diver travels is 9 meters.
Learn more about this topic in https://brainly.com/question/22089868?referrer=searchResults.
The vertical distance traveled by the Olympic diver is 6 m
The given parameters include:
initial position of the Olympic diver, x₁ = 7.5 m above the waterfinal position of the Olympic diver, x₂ = 1.5 m below the waterThe sketch of the Olympic diver's displacement is as follows;
x₁ ---------- 7.5 m
|
|
|
|
----------- water surface
|
↓
x₂ ------------ 1.5 m below water surface
The vertical distance from x₁ to x₂ = 7.5 m - 1.5 m = 6 m
Therefore, the vertical distance traveled by the Olympic diver is 6 m
To learn more about distance visit: https://brainly.in/question/7482539
URGENT PLEASE HELP. In the triangles below, DF MN, DG MP, D P. Can you prove that DFG MNP? Explain your answer. (15 points)
Answer:
FDG=NMP
Step-by-step explanation:
You can see below that the bases DG and MP are equal, and one of the saides DF and NM are equal, and D=P, so the triangles are the same, you can also see the triangles are isosceles, so they are the same since NM=FD=FG=NP and FD=NM is shown in the picture
• What is the smallest distance, in meters, needed for an airplane touching the runway with a velocity of 360 km/h and an acceleration of -10 m/s2 to come to rest? HELP
Answer:
i think ..................
Step-by-step explanation:
society idsbwj ja
if 1/a=1/b+1/c+1/d find c when a=2, b=3 and d=5
guys help me with this question please
Answer:
c is -30
Step-by-step explanation:
I. 1/a - 1/b - 1/d = 1/c
II. 1/2 - 1/3 - 1/5 = 1/c
III. (15-10-6)/30 = 1/c
IV. -1/30 = 1/c
V. so c.value is -30
simplify
please to the end
THIS MIGHT NOT BE RIGHT CAUSE I'M SICK
find the missing side.
Answer:
I htink x ≈ 8
Step-by-step explanation:
Answer:
X is approximately 7.8.
Step-by-step explanation:
You can use SOH-CAH-TOA to help figure out what function (sin, cos, tan) you need to use in order to figure out the missing side.
For this one, we can see the angle is pointing to the opposite side (x length), and we have been given the hypotenuse (18). So we want to use the sin function.
[tex]sin\ (angle)=\frac{opposite}{hypotenouse}[/tex]
[tex]sin (26)=\frac{x}{18}[/tex]
[tex]0.438=\frac{x}{18}[/tex]
[tex]7.890... = x[/tex]
Using Pythagorean theorm, you can figure out the other side if need be :)
For reference:
[tex]sin (angle)=\frac{opposite}{hypotenuse}[/tex]
[tex]cos(angle)=\frac{adjacent}{hypotenuse}[/tex]
[tex]tan(angle)=\frac{opposite}{adjacent}[/tex]
If $a$ and $b$ are positive integers such that $\gcd(a,b)=210$, $\mathop{\text{lcm}}[a,b]=210^3$, and $a
Answer:
[tex]a * b = 210^4[/tex]
Step-by-step explanation:
Given
[tex]a,b>0[/tex]
[tex]gcd(a,b) = 210[/tex]
[tex]lcm(a,b) = 210^3[/tex]
Required
The product of a and b --- missing from the question
To do this, we make use of the following formula:
[tex]a * b = gcd(a, b) * lcm(a, b)[/tex]
So, we have:
[tex]a * b = 210 * 210^3[/tex]
Using the product law of indices, we have:
[tex]a * b = 210^4[/tex]
This means that the product of a and b gives [tex]210^4[/tex]
Can someone help me here and check out the other two i have posted there both due soon and i have no clue how to do them
Answer:
Since the question doesn't mention in what tide the answer should be, I will be giving a solution to both, the high and low tide. Hope this helps :)
Step-by-step explanation:
Using a cosine function, where time is measured in hours past high
tide: y=4cos30x + 10
Using a cosine function, where time is measured in hours past low
tide: y = 4cos[30(x-6)]+10
Given: m∠V=103°, m∠VRT=71°, RS ∥ VU Find: m∠TRS, m∠U
Answer:
m∠TRS = 6°
m∠U = 103°
Step-by-step explanation:
In the given figure,
O is the center
RS ∥ VU
m∠V = 103° &
m∠VRT = 71°
So,
m∠V + m∠R = 180° (∵ sum of co-interior angles)
⇒ m∠R = 180° - 103° (m∠V = 103° is given)
∵ m∠R = 77° ...(i)
Now,
m∠R = m∠TRS + m∠VRT
by putting the values given
⇒ m∠TRS = 77° - 71°
∵ m∠TRS = 6°
As we know that,
VURT is a cyclic quadrilateral. So,
m∠U + m∠R = 180°
⇒ m∠U + 77° = 180° (from equation (i)
∵ m∠U = 180° - 77° = 103°
9. An equation representing the height of a burning candle is H = 2(9 - 2t), where
H is the height of the candle in cm and
t is the amount of time that the candle has been burning in minutes.
How long will it take for the candle to burn down to a height of 4 cm?
a. 2 min
b. 3.5 min
C. 5.5 min
d. 7 min
Answer:
H= 4cm
we want t
4=2(9-2t)
2=(9-2t)
-7=-2t
t=3.5 minutes
Mary can do a job in 80 minutes, Working with Jané, both can do the job in 30
minutes. How long will it take Jane to do the job alone?
Answer:
see below
Step-by-step explanation:
The equation to determine the work time is
1/a+1/b = 1/c where a and b are the times alone and c is the time together
1/80 + 1/30 = 1/c
Multiply by the least common denominator to clear the fractions, which is 240c
240c(1/80 + 1/30 = 1/c)
3c+8c = 240
11c = 240
Divide by 11
11c/11 =240/11
c = 240/11 minutes
c=21.81818
Approximately 22 minutes
2x+3y=19 // 6x+2y=22
Answer:
(2, 5 )
Step-by-step explanation:
Given the 2 equations
2x + 3y = 19 → (1)
6x + 2y = 22 → (2)
Multiplying (1) by - 3 and adding to (2) will eliminate the x- term
- 6x - 9y = - 57 → (3)
Add (2) and (3) term by term to eliminate x
0 - 7y = - 35
- 7y = - 35 ( divide both sides by - 7 )
y = 5
Substitute y = 5 into either of the 2 equations and solve for x
Substituting into (1)
2x + 3(5) = 19
2x + 15 = 19 ( subtract 15 from both sides )
2x = 4 ( divide both sides by 2 )
x = 2
solution is (2, 5 )
Please help me solve this!
Answer:
Step-by-step explanation:
Reference angle = 27
height = 2
Sin(27) = opposite / hypotenuse
hypotenuse = opposite / sin(27)
opposite = 2
hypotenuse = 2 / sin(27)
hypotenuse = 4.405
The ramp has to be 4.41 feet long.
Write the equation of the line with a slope of 4 that contains the point (5, 8).
Answer:
y = 4x - 12
Step-by-step explanation:
y = 4x + b
8 = 4(5) + b
8 = 20 + b
-12 = b
[tex] \green{ \boxed{\boxed{\begin{array}{cc} \maltese \bf \: \: \: we \: know \: that \: \\ \sf \: if \: any \: equation\:of \: line \: which \: slope (m) \\ \sf \: and \: passes \: through \: (x_1,y _1) \: \: then \: its \\ \sf equation \: is \: : \\ \\ \red{ \boxed{ \bf y - y_1 = m(x - x_1)}}\bf\end{array}}}}[/tex]
Given that,
A equation of the line with a slope of m = 4 and that contains / passes through the point (5, 8).
So,
[tex] \green{ \boxed{\boxed{\begin{array}{cc} \bf \: x_1 = 5 \: \: \: \\ \bf y_1 = 8 \\ \bf \: m \: = 4 \: \: \end{array}}}}[/tex]
NOW,
The equation is :
[tex] \green{ \boxed{\boxed{\begin{array}{cc} \bf \: y - 8 = 4(x - 5) \\ \\ = > \bf \: y - 8 = 4x - 20 \\ \\ = > \pink{ \boxed{\bf\:4x - y - 12 = 0}} \end{array}}}}[/tex]
Find the slope of the line that passes through (-26, 9) and (32, 71).
Answer:
[tex]Slope = \frac{31}{29}[/tex]
Step-by-step explanation:
Step 1: Define the slope formula
[tex]Slope = \frac{y_{2}-y_{1}}{x_{2}-x_{1}}[/tex]
Step 2: Find the slope
[tex]Slope = \frac{71-9}{32-(-26)}[/tex]
[tex]Slope = \frac{62}{58}[/tex]
[tex]Slope = \frac{31}{29}[/tex]
Answer: [tex]Slope = \frac{31}{29}[/tex]
3/5 of 1 hour is? pls give me the answer
1hr=60min
[tex]\\ \sf\longmapsto \dfrac{3}{5}\;of\;60min[/tex]
[tex]\\ \sf\longmapsto \dfrac{3}{5}\times 60[/tex]
[tex]\\ \sf\longmapsto \dfrac{180}{5}[/tex]
[tex]\\ \sf\longmapsto 36min[/tex]
Evaluate the Expression z(z-7) when z=10
Answer:
30
Step-by-step explanation:
z(z-7)
Let z= 10
10(10-7)
Parentheses first
10 (3)
Multiply
30
Answer:
[tex]\huge\boxed{\sf 30\\}[/tex]
Step-by-step explanation:
= z ( z - 7 )
Put z = 10
= 10 ( 10 - 7 )
= 10 ( 3 )
= 30
[tex]\rule[225]{225}{2}[/tex]
Hope this helped!
~AH1807Peace!If x^2-ax+b and x^2-cx+d both have a factor x-m prove that m=d-b/c-a
Answer:
see explanation
Step-by-step explanation:
Given (x - m) is a factor of both then x = m make both expressions equal to zero.
m² - am + b = 0
m² - cm + d = 0
Then
m² - am + b = m² - cm + d ( subtract m² - cm from both sides )
cm - am + b = d ( subtract b from both sides )
cm - am = d - b ← factor out m from each term on the left side
m(c - a) = d - b ← divide both sides by (c - a)
m = [tex]\frac{d-b}{c-a}[/tex] ← as required
On another map, the distance between Saugerties and
Kingston is 2 inches. What would the distance from
Saugerties to Catskill be on this map?
Answer:
10miles
Step-by-step explanation:
Answer:
I have no clue what is going on wit dis g
I need help for this question 3 so can anyone help me please
1. In a group of 500 students, 280 like bananas, 310 like apples, and 55 dislike both the fruits.
i) Find the number of students who like both the fruits.
ii) Find the number of students who like only one fruits.
iii) Show the result in venn-diagram
Answer:
Please see the attached images
Step-by-step explanation:
am thinking of a number multiplying it by 4 then subtracting 6 the answer is greater than 14. Write the inequality
Michelle gets10rewards points for each of her purchases at Starbucks. With 500 rewards points, she can get a free smoothie. If she has 370 points saved, how many purchases will it take her to get her free smoothie?
she needs 130 points saved up
Answer:
13
Step-by-step explanation:
The first term of an arithmetic sequence is -3 and the fifteenth term is 53. What is the common difference of the
sequence?
Answer:
53=-3+14d
56=14d
d=4 that is the common difference
Line A is represented by the following equation: X + y = 2
What is most likely the equation for line B so the set of equations has no solution?
Answer:
x+y=3
Step-by-step explanation:
For an equation to have no solution, their slope needs to be same and y intercept needs to be different,
so in this case where x+y=2
doing simply, x+y=3 makes a set of equation which has no solution, you can take any real value which is not 2
