A blimp is flying to cover a football game. The pilot sights the stadium at an 8° angle of depression. The blimp is flying at an altitude of 420m. How many meters is the blimp from the stadium? Round to the nearest meter.

The original price of the refurbished phone before the 35% discount was £120. If a refurbished phone is sold at a 35% discount with a final price of £78.

To find the original price of a refurbished phone before the discount of 35%, let's use the following formula:

discount = original price - discounted price

35% of the original price can be represented as 0.35 times the original price. This will result in the equation below:

0.35x = original price - 78

Where x is the original price. So, to find the value of x, we can rearrange the equation to get:

0.35x + 78 = original price

Now we substitute the given values into the equation above:

0.35x + 78 = original price

0.35x + 78 = x - 44.1 (if x represents the original price)

Let's subtract 0.35x from both sides to isolate the x variable:

78 = 0.65x

Then, let's divide both sides by 0.65 to solve for x (the original price):

x = £120

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The width of the rectangle is 10 inches, as it is calculated by finding the square root of the ratio of the area to the length.

Let's denote the width of the rectangle as "w" inches. According to the given information, the length of the rectangle is 4 times its width, so the length can be expressed as "4w" inches.

The formula for the area of a rectangle is length multiplied by width. In this case, the area is 400 square inches, so we have the equation:

Area = Length × Width

400 = (4w) × w

400 = 4w^2

To find the width, we can rearrange the equation and solve for "w":

4w^2 = 400

w^2 = 100

w = √100

w = 10

Therefore, the width of the rectangle is 10 inches. This means that the length of the rectangle is 4 times the width, which is 40 inches.

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Leo would need to score at least 99 on the 5th test to achieve at least a B in the course. The likelihood of Leo making a B would depend on his individual abilities, preparation, and performance on the 5th test.

To determine what score Leo would need on the 5th test to achieve at least a B in the course, we first need to know the grading scale or criteria for the course. Different educational institutions and instructors may use different grading scales, so without that information, it is not possible to provide an exact answer.

However, assuming a common grading scale where:

A: 90-100

B: 80-89

C: 70-79

D: 60-69

F: Below 60

We can calculate the average score Leo needs to achieve a B. To find the average, we sum up the scores and divide by the total number of tests:

(69 + 84 + 67 + 81 + x) / 5 >= 80

Simplifying the equation:

301 + x >= 400

x >= 400 - 301

x >= 99

Therefore, Leo would need to score at least 99 on the 5th test to achieve at least a B in the course.

As for whether it is likely that Leo will make a B, it depends on various factors. If Leo has consistently performed well in the course and has a history of earning high scores on tests, it is possible that he can achieve a score of 99 or higher on the 5th test. However, if Leo has struggled in the course or has not performed well on previous tests, it may be challenging for him to score high enough on the 5th test to reach a B. The likelihood of Leo making a B would depend on his individual abilities, preparation, and performance on the 5th test.

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To determine the measure of angle DAB, we need to use the congruence of quadrilaterals ABCD and AMCG.

Quadrilateral ABCD is congruent to quadrilateral AMCG.

Since the two quadrilaterals are congruent, their corresponding angles are equal. Therefore, we can write:

m∠DAB = m∠MAC

However, the measure of angle MAC is not given in the given information. Therefore, without additional information, we cannot determine the exact measure of angle DAB.

The options provided in the question do not correspond to the measure of angle DAB. Therefore, the correct answer cannot be determined based on the given information.

It is important to have additional information about the measures of angles or the side lengths in order to determine the measure of angle DAB accurately.

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Random questions can be solved in your head. option A

In common usage, randomness is the apparent or actual lack of pattern or predictability in information.

 A random sequence of events, symbols or steps often has no order and does not follow an intelligible pattern or combination. Individual random events are, by definition, unpredictable, but if the probability distribution is known, the frequency of different outcomes over repeated events (or "trials") is predictable

A random question has no particular pattern therefore it can be asked any how.

Therefore, we can conclude that random questions can only be answered in your heard with any research.

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Based on the information, the probability is 1/144, or approximately 0.0069.

Each number cube has 12 possible outcomes, as there are 12 faces labeled from 1 to 12.

The probability of rolling an 11 on one number cube is 1 out of 12, as there is only one face labeled 11 out of the 12 possible outcomes.

Since the two number cubes are rolled simultaneously, the total number of possible outcomes is the product of the possible outcomes for each cube, which is 12 * 12 = 144.

The number of favorable outcomes, in this case, is 1, as both number cubes need to show 11.

Therefore, the probability that both number cubes land with the number 11 facing up in one roll is:

Number of favorable outcomes / Total number of possible outcomes

= 1 / 144

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To create a 40 L solution with a 45% acid concentration, a chemist combines a 25% acid solution and a 50% acid solution. Therefore, the chemist used 32 L of the 50% acid solution and (40 - 32) = 8 L of the 25% acid solution to create the 40 L solution with a 45% acid concentration.

Let's assume the chemist uses "x" liters of the 50% acid solution. Since the total volume of the mixture is 40 L, the remaining volume will be (40 - x) liters of the 25% acid solution.

The acid content in the 50% solution is 0.5x, while the acid content in the 25% solution is 0.25(40 - x).

To find the acid content in the final 45% solution, we multiply the acid concentration (0.45) by the total volume (40):

0.45 * 40 = 0.5x + 0.25(40 - x)

Simplifying the equation:

18 = 0.5x + 10 - 0.25x

Combining like terms:

0.25x = 8

Dividing both sides by 0.25:

x = 32

Therefore, the chemist used 32 L of the 50% acid solution and (40 - 32) = 8 L of the 25% acid solution to create the 40 L solution with a 45% acid concentration.

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The dimensions of the rectangle are 16 inches in width and 24 inches in length.

Let's assume the width of the rectangle is x inches. According to the problem, the length is 8 inches greater than the width, so the length can be represented as (x + 8) inches.

The formula for the area of a rectangle is length multiplied by width. In this case, the area is given as 384 square inches. So, we can set up the equation:

Length * Width = Area

(x + 8) * x = 384

Expanding the equation:

x^2 + 8x = 384

Rearranging the equation to solve for x:

x^2 + 8x - 384 = 0

We can solve this quadratic equation by factoring or using the quadratic formula. Factoring it, we find:

(x - 16)(x + 24) = 0

So, x = 16 or x = -24.

Since dimensions cannot be negative, we discard the negative solution. Therefore, the width of the rectangle is 16 inches.

Substituting this value back into the equation for the length:

Length = x + 8 = 16 + 8 = 24 inches

Hence, the dimensions of the rectangle are 16 inches in width and 24 inches in length, which gives an area of 384 square inches.

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The expression (f times g)(x) represents the product of the functions f(x) and g(x). In this case, f(x) = x - 1/3 and g(x) = 3x + 1. To find the product, we substitute g(x) into f(x) and simplify the expression.

When we substitute g(x) into f(x), we get:

(f times g)(x) = f(g(x)) = f(3x + 1)

Now, substituting the expression for f(x) into f(g(x)), we have:

f(g(x)) = (3x + 1) - 1/3

Simplifying further, we combine like terms:

= 3x + 1 - 1/3

Thus, the product of f(x) and g(x), (f times g)(x), simplifies to:

(f times g)(x) = 3x + 1 - 1/3

(f times g)(x) equals 3x + 1 - 1/3.

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distance travel by the car with 3 gallons of gas, we have to use a proportion.

To determine how far Martin's car will travel on 3 gallons of gas, we can set up a proportion based on the given information.

We know that Martin's car travels 360 miles on 12 gallons of gas. Therefore, the mileage per gallon can be calculated as:

Mileage per gallon = Total miles / Total gallons

Mileage per gallon = 360 miles / 12 gallons

Mileage per gallon = 30 miles/gallon

Now, we can use this mileage per gallon to calculate the distance the car will travel on 3 gallons of gas:

Distance = Mileage per gallon × Number of gallons

Distance = 30 miles/gallon × 3 gallons

Distance = 90 miles

Therefore, Martin's car will travel 90 miles on 3 gallons of gas.

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The greatest common factor (GCF) of the given expressions 24s^3, 12s^4, and 18s is 6s.

To find the GCF, we need to identify the highest power of each variable (s) that appears in all the expressions. In this case, the highest power of s that appears in all the expressions is s^3.Next, we consider the numerical coefficients. The GCF of the numerical coefficients 24, 12, and 18 is 6.

Finally, we combine the GCF of the numerical coefficients (6) with the highest power of the variable (s^3) to obtain the GCF of the entire expressions, which is 6s^3.Therefore, the greatest common factor of 24s^3, 12s^4, and 18s is 6s^3.

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We have to find the ratio of Ms Seema's annual spending to her annual savings given that Ms. Seema's annual salary is Rs 288000 and her annual savings is Rs 72000.

The first step is to determine the annual spending of Ms. Seema.Subtracting the annual savings of Ms. Seema from her annual salary, we can determine her annual spending. Annual spending = Rs 288000 - Rs 72000 = Rs 216000We now know that Ms. Seema's annual spending is Rs 216000 per year and her annual savings is Rs 72000 per year.

We can now compute the ratio of her annual spending to her annual savings. Annual spending : Annual savings= 216000 : 72000= 3 : 1Therefore, the ratio of Ms. Seema's annual spending to her annual savings is 3 : 1. It implies that her annual spending is three times the annual savings.In conclusion, the ratio of Ms. Seema's annual spending to her annual savings is 3 : 1.

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The mean train ride time for the week was 49.4 minutes, with a median of 48 minutes. The range of the train ride times was 3 minutes.

The mean, median, and range of Santos' train ride times for the week were as follows:

Mean: 49.4 minutes

The mean is calculated by adding up all the values and dividing the sum by the total number of values. In this case, the sum of the train ride times (48 + 51 + 48 + 48 + 50) is 245 minutes. Dividing this sum by the total number of days (5), we get the mean of 49.4 minutes.

Median: 48 minutes

The median is the middle value in a sorted list of numbers. To find the median, we arrange the train ride times in ascending order: 48, 48, 48, 50, 51. Since there is an odd number of values, the middle value is the median. In this case, the median is 48 minutes.

Range: 3 minutes

The range is the difference between the largest and smallest values in a set. To calculate the range, we subtract the smallest value (48 minutes) from the largest value (51 minutes). In this case, the range of the train ride times for the week is 3 minutes.

In summary, the mean train ride time for the week was 49.4 minutes, with a median of 48 minutes. The range of the train ride times was 3 minutes. These metrics provide insights into the average, central tendency, and variability of Santos' train rides throughout the week.

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The possible denominations of notes that Vicky and Ricky can have, in increasing order, are:

Vicky: ₹50, ₹100

Ricky: ₹10, ₹20, ₹50, ₹100

To determine the possible denominations of notes that Vicky and Ricky can have, we need to find combinations of notes that add up to their respective amounts.

Let's consider Vicky first. With ₹300, the possible combinations of notes are:

3 number of notes of ₹100 (₹100 + ₹100 + ₹100)

1 note of ₹100 and 2 notes of ₹100 (₹100 + ₹100 + ₹100)

two notes of ₹100 and 5 notes of ₹50 (₹100 + ₹100 + ₹50 + ₹50 + ₹50 + ₹50 + ₹50)

Now let's consider Ricky. With ₹260, the possible combinations of notes are:

2 notes of ₹100 and 3 notes of ₹20 taking their sum (₹100 + ₹100 + ₹20 + ₹20 + ₹20)

1 note of ₹100, 3 notes of ₹50, and 1 note of ₹10 (₹100 + ₹50 + ₹50 + ₹50 + ₹10)

2 notes of ₹100, 2 notes of ₹20, and 1 note of ₹10 (₹100 + ₹100 + ₹20 + ₹20 + ₹10)

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i) I was proven innocent by virtue of the law.

ii) Don’t leave without your coat.

In sentence (i), the prepositional phrase "by virtue of" introduces the reason or cause for being proven innocent. It indicates that the law is the basis or foundation for the proof.

In sentence (ii), the prepositional phrase "without your coat" indicates the absence or lack of something. It specifies that the action of leaving should not occur unless the person has their coat with them.

Prepositional phrases consist of a preposition (such as "by," "of," or "without") followed by a noun or pronoun object. They provide additional information about location, time, manner, or other relationships in a sentence. Recognizing and understanding prepositional phrases helps in comprehending the structure and meaning of sentences.

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The mean rainfall for the highland storms is 15.27 millimeters, and the mean rainfall for the lowland storms is 12.05 millimeters.

In the dot plots, each dot represents the rainfall total for a spring storm in either the highland or lowland areas. To find the mean rainfall, we calculate the average of all the rainfall values in each plot.

For the highland storms, the mean is 15.27 millimeters, which indicates that, on average, the rainfall for the spring storms in the highland areas is 15.27 millimeters.

For the lowland storms, the mean is 12.05 millimeters, suggesting that the average rainfall for the spring storms in the lowland areas is 12.05 millimeters.

These values provide a measure of the central tendency or average rainfall for the respective areas and can help in comparing the rainfall patterns between the highlands and lowlands.

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This means that the expression 10x² + 2x - 8  completely factored as 2(5x - 2)(x + 2).

The correct factored form of the expression 10x² + 2x - 8 is:

2(5x - 2)(x + 2).

To factor the quadratic expression completely for common factors first that the coefficient 2 is a common factor in all three terms. After factoring out 2, left with (5x² + x - 4).

An factor the trinomial (5x² + x - 4). However, this trinomial cannot be factored further using integer coefficients.

So, the factored form of the expression is 2(5x - 2)(x + 2).

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To find the ratio of the area of 11 million km² to the area of the Pacific Ocean (165 million km²), we can express it as a fraction:

Ratio = Area of 11 million km² / Area of the Pacific Ocean

Ratio = 11 million km² / 165 million km²

To simplify the fraction, we can divide both the numerator and the denominator by 11 million:

Ratio = (11 million km² / 11 million km²) / (165 million km² / 11 million km²)

Ratio = 1/15

Therefore, the ratio of the area of 11 million km² to the area of the Pacific Ocean is 1/15.

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The Apostle Paul demonstrates humility in Acts 15:36-39 and 2 Timothy 4:11 through his willingness to resolve differences. In these passages, Paul's actions and attitudes reflect his humility and his desire for reconciliation and unity among believers.


In Acts 15:36-39, Paul and Barnabas had a disagreement regarding taking John Mark on a missionary journey. Barnabas wanted to bring John Mark along, but Paul did not because John Mark had previously left them on a previous journey. Despite the disagreement, Paul shows humility by accepting Barnabas' decision and allowing him to take John Mark as his companion, while Paul chooses Silas as his own companion. This act demonstrates Paul's willingness to prioritize unity and reconciliation over personal preferences.

In 2 Timothy 4:11, Paul shows humility by reconciling with John Mark. He requests Timothy to bring Mark with him because Paul considers Mark to be helpful in his ministry. This shows a change in Paul's attitude towards Mark, indicating that he was willing to put aside any past differences and extend forgiveness and acceptance. Paul's willingness to reconcile and work alongside Mark reveals his humility and his understanding of the importance of resolving differences for the sake of the Gospel and the unity of believers.

Overall, both passages highlight Paul's humility through his willingness to resolve differences and prioritize unity, showcasing his desire for reconciliation and harmony among fellow believers.

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The surface area of a sphere is 4πr2, where r is the radius of the sphere. The cost of a sphere is 2 per square foot, so the cost of a sphere with radius r is 8πr2. Selim can spend 20 per sphere, so he can purchase a sphere with radius r such that 8πr2≤20. This inequality can be solved for r to get r≤8π20​​=2π5​​. The diameter of a sphere is 2r, so the maximum diameter of the spheres Selim can purchase is 22π5​​=10π​≈3.162 feet.

We are to determine an equation in vertex form that models the height of the basketball above the ground versus time. We can determine this using the formula:h(t) = -16t² + vt + h₀

We are given that the basketball reaches its highest point of 12 m above the ground 0.5 s after it is released from his hands. Thus, the initial height is:h₀ = 12 mWe are also given that the ball lands on the ground after 1.3 seconds. Thus, the time it took for the ball to reach the ground is:t = 1.3 sLet's find the initial vertical velocity using the information that the basketball reaches its highest point 0.5 seconds after it is released.

The vertical velocity of the basketball at its highest point is zero since it stops before coming down.So we know:

v + (-9.8)(0.5) = 0v = 4.9 m/s

Substituting the given information into the equation above, we obtain:

h(t) = -16t² + vt + h₀h(t) = -16t² + (4.9)t + 12

The vertex form of this equation can be determined by completing the square. To complete the square, we can add and subtract the square of half of the coefficient of t from the equation above

:h(t) = -16(t² - 0.30625t) + 12

To complete the square, we add and subtract

(0.30625/2)² = 0.02368164062:h(t) = -16(t² - 0.30625t + 0.02368164062 - 0.02368164062) + 12h(t) = -16(t - 0.153125)² + 12

The vertex of this equation is the point (0.153125, 12) and is the highest point of the basketball. The coefficient of t² is negative, which means that the graph of this equation is a downward-facing equation .

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The simplified equivalent expression for the sum (5x – 2) + (2x + 9) is 7x + 7.

This can be obtained by combining like terms, which involves adding the coefficients of x and the constant terms separately.

In the given expression, we have (5x – 2) and (2x + 9). To simplify, we can add the coefficients of x together: 5x + 2x = 7x. Similarly, we can add the constant terms: -2 + 9 = 7. Therefore, the simplified expression becomes 7x + 7, where 7x represents the combined coefficient of x and 7 represents the combined constant term.

Overall, by combining like terms, we obtain the simplified equivalent expression of the sum (5x – 2) + (2x + 9) as 7x + 7.


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The factored form of a quadratic expression with a double root at 3 and a single root at -7 is (x - 3)^2(x + 7).

A quadratic expression in factored form has the general form (x - r1)(x - r2), where r1 and r2 are the roots of the expression. In this case, the roots are a double root at 3 and a single root at -7, which means that the expression can be factored as follows: (x - 3)(x - 3)(x + 7).

Simplifying, we can write this expression as (x - 3)^2(x + 7). The double root at 3 means that the quadratic equation has two identical roots, so (x - 3) appears twice in the factored form. The single root at -7 means that (x + 7) appears only once. The factored form can be useful for solving quadratic equations and for finding the roots of a quadratic expression.

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To calculate the amount of sand Maija should order, we need to find the volume of the sandbox. The sandbox is in the shape of a cube, so its volume is determined by multiplying the length, width, and height.

Given that the sides of the square sandbox are 2 feet long and the desired depth of the sand is 1.55 feet, we can calculate the volume as follows:

[tex]\[ \text{Volume} = \text{Length} \times \text{Width} \times \text{Height} \][/tex]

Since all sides of the sandbox are equal in length (2 feet), the formula simplifies to:

[tex]\[ \text{Volume} = \text{Side}^3 \][/tex]

Substituting the values:

[tex]\[ \text{Volume} = 2 \, \text{ft} \times 2 \, \text{ft} \times 1.55 \, \text{ft} \][/tex]

[tex]\[ \text{Volume} = 6.2 \, \text{cubic feet} \][/tex]

Therefore, Maija should order 6.2 cubic feet of sand for her sandbox.

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The given statement describes a relationship between two angles that are not adjacent, stating that they do not form a linear pair. The different types of logical statementsstatements from this statement are the converse statement, inverse statement, contrapositive statement, and conditional statement.

Converse statement: The converse of a conditional statement switches the hypothesis and the conclusion. In this case, the converse statement would be: If two angles do not form a linear pair, then they are not adjacent.
Inverse statement: The inverse of a conditional statement negates both the hypothesis and the conclusion. The inverse statement would be: If two angles are adjacent, then they form a linear pair.
Contrapositive statement: The contrapositive of a conditional statement switches and negates both the hypothesis and the conclusion. The contrapositive statement would be: If two angles form a linear pair, then they are adjacent.
Conditional statement: The original statement itself is the conditional statement. It follows the form: If two angles are not adjacent, then they do not form a linear pair.
These different logical statements provide alternative ways to express the relationship between angles that are not adjacent and their formation of a linear pair.

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Given a quadrilateral ABCD, with the sides AB and DC parallel and equal in length. Let us denote angle BAD as ∠α and angle ADC as ∠β. Now, we have to find the values of the variables x and y such that ABCD is a parallelogram.

Parallelogram has a pair of parallel sides. So, we have AB ∥ CD. It is given that ∠α = ∠β and AB = CD. So, by angle-angle-side rule, the two triangles ABD and DCA are congruent.

In triangle ABD, we have:∠DAB = 180° - ∠α = 180° - ∠β (as ∠α = ∠β)⇒ ∠DAB + ∠CDA = 180° (linear pair of angles)⇒ ∠CDA = ∠β.In triangle DCA, we have:∠CDA = ∠β (as obtained above)⇒ ∠CAD = ∠α (as ∠α = ∠β)⇒ ∠BDC = 180° - ∠α = 180° - ∠β (linear pair of angles)⇒ ∠BDC = ∠DAB.In quadrilateral ABCD, the adjacent angles are supplementary. So, we have:∠BDC + ∠BCD = 180° (adjacent angles are supplementary)⇒ ∠DAB + ∠BCD = 180° (as ∠BDC = ∠DAB)⇒ ∠BCD = 180° - ∠DAB.In triangle ACD, we have:∠C = ∠C (common)⇒ ∠CAD + ∠BCD = 180° (angles of a triangle add up to 180°)⇒ ∠α + (180° - ∠DAB) = 180°⇒ ∠α + ∠β = 180°.

Now, we can solve for x and y.In triangle ABD, we have:AB = BD⇒ 3x = 21 - x⇒ 4x = 21⇒ x = 21/4.In triangle DCA, we have:CD = DA⇒ 3y = 22 - y⇒ 4y = 22⇒ y = 11/2. Therefore, the value of x is 21/4 and the value of y is 11/2.

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Mrs. Rodriguez sold 128.8 ounces of popcorn.We know that each bag of popcorn weighs 2.3 ounces. Therefore, to find out the total amount of popcorn Mrs. Rodriguez sold in 56 bags, we need to multiply 2.3 by 56. That is;2.3 × 56 = 128.8Therefore, there are 128.8 ounces of popcorn in 56 bags

We are given that Mrs. Rodriguez is selling popcorn at the snack stand. Each bag holds 2.3 ounces of popcorn. In one hour, she sold 56 bags of popcorn. Our task is to find out how many ounces of popcorn are in 56 bags.In order to find out how many ounces of popcorn are in 56 bags, we need to first find out the weight of one bag of popcorn. We are told that each bag holds 2.3 ounces of popcorn. So, we have:

Weight of one bag of popcorn = 2.3 ounces Now, we can use this information to calculate the total weight of popcorn Mrs. Rodriguez sold in 56 bags. To do this, we need to multiply the weight of one bag of popcorn (2.3 ounces) by the number of bags she sold (56). That is;Weight of 56 bags of popcorn = 2.3 × 56= 128.8Therefore, Mrs. Rodriguez sold 128.8 ounces of popcorn in one hour.

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The measure of the angle x is 59 degrees. Option A

The different trigonometric identities are listed as;

From the information given, we have that;

The measure of the adjacent is 880 feet

The opposite side is the ocean's surface = 1450 feet

The angle is x

Using the tangent identity, we have;

tan θ = opposite/adjacent

Now, we have to substitute the values, we get;

tan x = 1450/880

Divide the values, we get;

tan x = 1. 6477

Take the tangent inverse, we get;

x = 59 degrees

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The work done is 400.0 Joules A force of 80 Newtons pushes a 50-kilogram object across a level floor for 8.0 meters.

To find the work done, we can use the formula:work = force x distance x cos(theta)where force is 80 N, distance is 8.0 m, and theta is the angle between the force and the displacement. Since the force is applied in the direction of motion, theta is 0° and cos(0°) is 1.

we can simplify the formula as:work = force x distance x cos(theta)work = 80 N x 8.0 m x cos(0°)work = 640.0 JHowever, we need to check the units of our answer to make sure they are in Joules (J). The units of force are Newtons (N), the units of distance are meters (m), and the units of cos(theta) are dimensionless. Therefore, our answer is in Joules (J).So, the work done is 640.0 Joules.

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The set of transformations that would prove ΔQRS ~ ΔUTS is to translate ΔUTS by the rule (x - 2, y + 0) and reflect ΔU'T'S' over y = 2.

To prove that ΔQRS ~ ΔUTS, we need to show that the two triangles are related through a combination of transformations.

The first transformation is a translation of ΔUTS by the rule (x - 2, y + 0). This means that every point in ΔUTS will be moved 2 units to the left and 0 units vertically. The translated triangle is denoted as ΔU'T'S'.

The second transformation is a reflection of ΔU'T'S' over the line y = 2. This reflection flips the triangle across the line, maintaining the same shape but reversing the orientation.

These two transformations combined, translation and reflection, establish a correspondence between the corresponding vertices of the two triangles. ΔU'T'S' is the transformed version of ΔUTS.

Since the two triangles undergo the same transformations, they have a proportional relationship and are therefore similar, which can be denoted as ΔQRS ~ ΔU'T'S'.

Learn more about set of transformations:

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