A basketball team is to play two games in a tournament. The probability of winning the first game is .10.1 the first game is won, the probability of winning the second game is 15. If the first game is lost, the probability of winning the second game is 25. What is the probability the first game was won if the second game is lost? Express the answer with FOUR decimal points.

Answers

Answer 1

Answer:

[tex]P(\frac{A}{B'})[/tex]=0.111

Step-by-step explanation:

Given:

The probability of winning the first game is 10.1

The first game is won

The probability of winning the second game is 15

If the first is lost, the probability of winning the second game is 25

Solution:

[tex]P(B)=P(A)P(\frac{B}{A})+P(A')P(\frac{B}{A'})\\ =0.1(0.15)+(0.3)*0.25)\\P(B)=0.24 ------(1)\\P(\frac{A}{B})=\frac{P(\frac{B}{A})P(A) }{P(B)}\\ =\frac{0.15(0.1)}{0.24}\\ =0.0625 ------(2)\\P(B')=1-P(B)=0.76 ------(3)\\P(A)=P(B)P(\frac{A}{B})+P(B')P(\frac{A}{B'})\\0.1=0.24(0.0625)+0.76(p(\frac{A}{B'} ))\\P(\frac{A}{B'})=0.111[/tex]

Answer 2

Answer:

[tex]P(W_1/W_2')=0.1110[/tex]

Step-by-step explanation:

Probability of winning the first game be considering the given factors be, [tex]W_1=0.1[/tex]

Probability of winning the second game be considering the given factors be, [tex]W_2[/tex]= probability of winning the second game when the first game is won + probability of winning the second game when the first game is lost:

[tex]P(W_2)=P(W_1).P(W_2/W_1)+P(W_1').P(W_2/W_1')[/tex]

[tex]P(W_2)=0.1\times 0.15+0.9\times 0.25[/tex]

[tex]P(W_2)=0.24[/tex]

Hence the probability of losing the second game:

[tex]P(W_2')=1-P(W_2)[/tex]

[tex]P(W_2')=0.76[/tex]

Probability of winning the first game when the second game is won:

[tex]P(W_1/W_2)=\frac{P(W_2/W_1).P(W_1)}{P(W_2)}[/tex]

[tex]P(W_1/W_2)=\frac{0.15\times 0.1}{0.24}[/tex]

[tex]P(W_1/W_2)=0.0625[/tex]

Probability of winning the first game be considering the given factors, [tex]W_1[/tex]= probability of winning the first game when the second game is won + probability of winning the first game when the second game is lost:

[tex]P(W_1)=P(W_2).P(W_1/W_2)+P(W_2').P(W_1/W_2')[/tex]

[tex]0.1=0.24\times0.0625+0.76\times P(W_1/W_2')[/tex]

[tex]P(W_1/W_2')=0.1110[/tex]


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Answer:

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The student with lowest score on test 2 is Euan.

What is bar graph ?

Bar graph is used for the graphical representation of data or quantities by using bars or strips.

Here,

The z-score results of four students on two different mathematics tests is represented by the given bar graph.

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Answer:

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Answers

Answer:

The minimum number of drivers you would need to survey is 601.

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of [tex]\pi[/tex], and a confidence level of [tex]1-\alpha[/tex], we have the following confidence interval of proportions.

[tex]\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}[/tex]

In which

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The margin of error is:

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95% confidence level

So [tex]\alpha = 0.05[/tex], z is the value of Z that has a p-value of [tex]1 - \frac{0.05}{2} = 0.975[/tex], so [tex]Z = 1.96[/tex].  

What is the minimum number of drivers you would need to survey to be 95% confident that the population proportion is estimated to within 0.04?

The number is n for which M = 0.04.

We don't have an estimate for the proportion, so we use [tex]\pi = 0.5[/tex]. Then

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[tex]n = 600.25[/tex]

Rounding up:

The minimum number of drivers you would need to survey is 601.

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Answer:

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Step-by-step explanation:

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Answers

This question is solved by proportions.

Step 1:

A nurse is preparing to administer cefaclor 40 mg/kg/day.

This means that the first step is finding the baby's weight in kg.

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Step 2:

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Since the baby weighs 21.7724 kg, the daily dose is of 40*21.7724 = 870.896 mg.

Step 3:

Here, we find how many mL in a day.

For 375 mg, 5 mL are administered. How many mL for 870.896 mg?

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870.896 mg - x mL

Applying cross multiplication:

[tex]375x = 5*870.896[/tex]

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Step 4:

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Equal doses every 8 hours, so 24/8 = 3 doses per day.

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Thus, the nurse should administer 3.9 mL per dose.

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Step-by-step explanation:

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Answer:

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3x+8x - 3 = -25

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[tex]\large\bf{\pink{ \longrightarrow \: }} \tt \:3x \: + \: 8x \: - \: 3 \: = \: - 25[/tex]

[tex]\large\bf{\pink{ \longrightarrow \: }} \tt \:11x \: - \: 3 \: = \: - 25[/tex]

[tex]\large\bf{\pink{ \longrightarrow \: }} \tt \:11x \: = \: - 25 \: + \: 3[/tex]

[tex]\large\bf{\pink{ \longrightarrow \: }} \tt \:11x \: = \: - 22[/tex]

[tex]\large\bf{\pink{ \longrightarrow \: }} \tt \: x \: = \: {\cancel\frac{ {- 22} \:^{ - 2} }{11}} \\ [/tex]

[tex]\large\bf{\pink{ \longrightarrow \: }} \tt \:x \: = \: - 2[/tex]

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Answer:

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Step-by-step explanation:

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II. Isosceles triangle: it has two (2) of its sides equal in length and two (2) equal angles.

III. Scalene triangle: it has all of its three (3) sides and interior angles different in length and size respectively.

In Geometry, an acute angle can be defined as any angle that has its size less than ninety (90) degrees.

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hopefully this answer can help you to answer the next question. can you choose this answer as the brainliest answer and give five stars


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Answers

Answer:

12 days

Step-by-step explanation:

The answer of the problem is the LCM of 3 and 4=12. Hence the answer is 12 days

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What is LCM?

It is defined as the common number of two integers, which is the lowest number that is a multiple of two or more numbers. The full name of LCM is the least common multiple.

We have:

Amira starts an exercise program on the 3rd of March.

She will swim every 3 days and cycle every 4 days.

Total days =3 + 4 = 7 days = 1 week

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Answer:

6,78

Step-by-step explanat

ion:data size :10

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Answer:

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Answer:

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Answer:

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Tìm diện tích của mặt. Phần mặt x2+y2+z2=9 nằm bên trên mặt phẳng z=1.

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If you're familiar with surface integrals, start by parameterizing the surface by the vector-valued function,

r(u, v) = 3 cos(u) sin(v) i + 3 sin(u) sin(v) j + 3 cos(v) k

with 0 ≤ u ≤ 2π and 0 ≤ v ≤ arccos(1/√8).

Then the area of the surface (I denote it by S) is

[tex]\displaystyle\iint_S\mathrm dA = \int_0^{2\pi}\int_0^{\arccos\left(1/\sqrt8\right)}\left\|\dfrac{\partial\mathbf r}{\partial u}\times\frac{\partial\mathbf r}{\partial v}\right\|\,\mathrm dv\,\mathrm du \\\\ = \int_0^{2\pi}\int_0^{\arccos\left(1/\sqrt8\right)}9\sin(v)\,\mathrm dv\,\mathrm du \\\\ =18\pi \int_0^{\arccos\left(1/\sqrt8\right)}\sin(v)\,\mathrm dv = \boxed{\frac{9(4-\sqrt2)\pi}2}[/tex]

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Answer:

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Answers

295 is left in her account.

Answer:

263

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use a calculator its easy

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Answer:

ABC

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The lower bound, or left endpoint, is 1.5 - 0.85 = 0.65

The upper bound, or right endpoint, is 1.5 + 0.85 = 2.35

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The left endpoint should be between the 0.6 and 0.7 to indicate 0.65

The right endpoint should be between 2.3 and 2.4 to indicate 2.35

See the diagram below.

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