Answers:
(a) 1/10(b) 3/10(c) 3/10(d) 2/5===========================================
Explanations:
Part (a)
There is only one disc labeled "3" out of 10 total. So we end up with the probability 1/10.
---------------------
Part (b)
The list of numbers less than 4 are {1,2,3} which are 3 items out of 10 discs. We end up with 3/10.
---------------------
Part (c)
A square number, aka a perfect square, smaller than 10 is the list {1,4,9}
Since 1 = 1^2, 4 = 2^2 and 9 = 3^2
Like part (b), we end up with the same result of 3/10.
---------------------
Part (d)
The list of primes smaller than 10 is {2, 3, 5, 7}. Notice that 1 is not prime.
So we end up with 4/10 = 2/5.
If P = (7,-4), Find:
(180° (P)
([?], []
Enter
Step-by-step explanation:
the answer is in the above image
For a certain river, suppose the drought length Y is the number of consecutive time intervals in which the water supply remains below a critical value y0 (a deficit), preceded by and followed by periods in which the supply exceeds this critical value (a surplus). An article proposes a geometric distribution with p = 0.365 for this random variable. (Round your answers to three decimal places.)
a. What is the probability that a drought lasts at most 3 intervals?
b. What is the probability that the length of a drought exceeds its mean value by at least one standard deviation?
Solution :
a). P(X = x)
= [tex]$p(1-p)^x$[/tex] for x = 0, 1, 2, ....
P(x ≤ 3) = 0.837
b). Expectation = [tex]$\frac{(1-p)}{p}$[/tex]
= 1.7397
Variance = [tex]$\frac{(1-p)}{p^2}$[/tex]
= 4.7663726
Standard deviation = 2.1832
Therefore, mean + standard deviation
= 1.7397 + 2.1832
= 3.9229
[tex]$P(x > 3.9229) = 0.1626$[/tex]
So the required P = 2 x 0.1626
= 0.325
The hourly earnings (in dollars) for a sample of 25 railroad equipment manufacturers are:15.60 18.7514.60 15.8014.3513.90 17.5017.5513.8014.20 19.05 15.35 15.20 19.45 15.95 16.50 16.30 15.2515.05 19.10 15.20 16.22 17.75 18.40 15.25Find the median and the mode(s)(if they exist) of the data. What is the interquartile range
Answer:
[tex]Median = 15.80[/tex]
[tex]Mode = 15.20\ \&\ 15.25[/tex]
[tex]IQR = 2.35[/tex]
Step-by-step explanation:
Given
[tex]15.60,\ 18.75,\ 14.60,\ 15.80,\ 14.35,[/tex]
[tex]13.90,\ 17.50,\ 17.55,\ 13.80,\ 14.20,[/tex]
[tex]19.05,\ 15.35,\ 15.20,\ 19.45,\ 15.95,[/tex]
[tex]16.50,\ 16.30,\ 15.25,\ 15.05,\ 19.10,[/tex]
[tex]15.20,\ 16.22,\ 17.75,\ 18.40,\ 15.25.[/tex]
Solving (a): The median and the mode
First, we sort the data.
[tex]13.80,\ 13.90,\ 14.20,\ 14.35,\ 14.60,\ 15.05,\ 15.20,\ 15.20,\ 15.25,\ 15.25,[/tex]
[tex]15.35,\ 15.60,\ 15.80,\ 15.95,\ 16.22,\ 16.30,\ 16.50,\ 17.50,\ 17.55,\ 17.75,[/tex]
[tex]18.40,\ 18.75,\ 19.05,\ 19.10,\ 19.45.[/tex]
The median position is:
[tex]Median = \frac{n + 1}{2}th[/tex]
[tex]Median = \frac{25 + 1}{2}[/tex]
[tex]Median = \frac{26}{2}[/tex]
[tex]Median = 13th[/tex]
The 13th item is: 15.80
Hence:
[tex]Median = 15.80[/tex]
The modes are:
[tex]Mode = 15.20\ \&\ 15.25[/tex] --- they both have frequency of 2 while others occur once
Solving (b): The interquartile range
This is calculated as:
[tex]IQR = Q_3 - Q_1[/tex]
Since the median is at the 13th position, Q1 is:
[tex]Q_1 = \frac{1 + 13}{2}th[/tex]
[tex]Q_1 = \frac{14}{2}th[/tex]
[tex]Q_1 = 7th[/tex]
The 7th item is: 15.20
[tex]Q_1 = 15.20[/tex]
Similarly, Q3 is:
[tex]Q_3 = \frac{13+n}{2}[/tex]
[tex]Q_3 = \frac{13+25}{2}[/tex]
[tex]Q_3 = \frac{38}{2}[/tex]
[tex]Q_3 = 19th[/tex]
The 7th item is: 17.55
So:
[tex]Q_3 = 17.55[/tex]
Hence,
[tex]IQR = 17.55 - 15.20[/tex]
[tex]IQR = 2.35[/tex]
Four students want to have their picture taken together. They will stand side-by-side for the picture. In how many different ways can the four students be arranged to take a picture?
Show your work, please :')
Answer:
24 waysStep-by-step explanation:
This is the permutation of 4:
4P4 = 4! = 1*2*3*4 = 24 ways[tex]\huge\qquad \mathbb{\fcolorbox{red}{lavenderblush}{✰Answer}}[/tex]
✶⊶⊷⊶⊷❍❁❥❀❥❁❍⊶⊷⊶⊷✶
Four students want to have their picture taken together. They will stand side-by-side for the picture. In how many different ways can the four students be arranged to take a picture
so we have to find the permutation of 4
4×3×2×124.°. In 24 different ways can the four students be arranged to take a picture
What are some easy ways to find the value of
(2017^4−2016^4)/(2017^2+2016^2) without calculator
Answer:
4033
Step-by-step explanation:
An easy way to solve this problem is to notice the numerator, 2017^4-2016^4 resembles the special product a^2 - b^2. In this case, 2017^4 is a^2 and 2016^4 is b^2. We can set up equations to solve for a and b:
a^2 = 2017^4
a = 2017^2
b^2 = 2016^4
b = 2016^2
Now, the special product a^2 - b^2 factors to (a + b)(a - b), so we can substitute that for the numerator:
[tex]\frac{(2017^2+2016^2)(2017^2 - 2016^2)}{2017^2+2016^2}[/tex]We can notice that both the numerator and denominator contain 2017^2 + 2016^2, so we can divide by [tex]\frac{2017^2+2016^2}{2017^2+2016^2}[/tex] which is just one, and will simplify the fraction to just:
2017^2 - 2016^2
This again is just the special product a^2 - b^2, but in this case a is 2017 and b is 2016. Using this we can factor it:
(2017 + 2016)(2017 - 2016)
And, without using a calculator, this is easy to simplify:
(4033)(1)
4033
Jesse takes two data points from the weight and feed cost data set to calculate a slope, or average rate of change. A hamster weighs half a pound and costs $2 per week to feed, while a Labrador Retriever weighs 62.5 pounds and costs $10 per week to feed. Using weight as the explanatory variable, what is the slope of a line between these two points? Answer choices are rounded to the nearest hundredth.
a. $0.13 / Ib.
b. $4.00 / Ib
c. $6.25 / Ib.
d. $7.75 / Ib.
Answer:
a. $0.13 / Ib.
Step-by-step explanation:
Slope of a line:
Suppose we have two data-points in a line. The slope is given by the change in the output divided by the change in the output.
In this question:
Input: weight(in pounds)
Output: Weekly cost to feed.
A hamster weighs half a pound and costs $2 per week to feed, while a Labrador Retriever weighs 62.5 pounds and costs $10 per week to feed.
Inputs: 0.5, 62.5
Outputs: 2, 10
Change in the outputs: 10 - 2 = 8
Change in the inputs: 62.5 - 0.5 = 62
Slope: [tex]m = \frac{8}{62} = 0.13[/tex]
So the correct answer is given by option A.
Answer:
0.13
Step-by-step explanation:
PLEASE ANSWER MAKE SURE YOU ARE RIGHT PLEASE I WILL MARK AS BRAINIEST
FIND THE VOLUME OF THE SPHERE
Answer:
Step-by-step explanation:
r = 1/2 unit
[tex]Volume= \frac{4}{3}\pi r^{3}\\\\=\frac{4}{3}\pi *\frac{1}{2}*\frac{1}{2}*\frac{1}{2}\\\\=\frac{1}{3}*\pi *\frac{1}{2}\\\\=\frac{1}{6}\pi[/tex]
what is the value of a+bc when a=4, b=6 and c =2? also please include how to do it step by step :)
Answer:
16
Step-by-step explanation:
a+bc
a+(b×c)
4+(6×2)
4+12
answer=16
ASAP. There are three marbles in a bag. When is red and two are black. What is the probability of picking a black marble first, putting it back in the bag and then picking a black marble? Use the following probably need to find the answer.
Answer:
Number of black balls=2
Total number of balls=3
Probability =2/3
Use the formula v = IR for current flowing through a resistor, where V is the voltage in volts, I is current in amps, and R is resistance in ohms. Find the current through a resistor with resistance 15 ohms if the voltage across it is 3 volts.
Answer:
0.2 amps
Step-by-step explanation:
Given data
The formula V=IR is the formula for ohms law
Which state that the voltage is directly proportional to the current and the resistance in an electric circuit
Now
R= 15 ohms
V= 3volts
V= IR
3= I*15
I= 3/15
I= 0.2 amps
Hence he current flowing is 0.2 amps
In practice, the most frequently encountered hypothesis test about a population variance is a _____. a. two-tailed test, with equal-size rejection regions b. two-tailed test, with unequal-size rejection regions c. one-tailed test, with rejection region in upper tail d. one-tailed test, with rejection region in lower tail
Answer:
c. one-tailed test, with rejection region in the upper tail.
Step-by-step explanation:
One tailed test is statistical test in which critical area of distribution is one sided and greater or less than certain value. One tailed test can be left or right sided depending on the population distribution. Rejection region of the one tailed test will determine whether to accept or reject the null hypothesis.
2) A block of ice weighs 12 400 kg. It has the shape of a cylinder, with a radius of 1.2 m and
a height of 3 m. What is the density of the ice? Give your answer to one decimal place.
Answer:
= 3.6
Step-by-step explanation:
Do you know how to find the volume of a cylinder? Like any prism, it's area of base x height, in this case the base is a circle of radius 1.2m.
Density is simply mass / volume (kg / m3 ).
clarify its 1.2 x 3 = 3.6
12400 / 3.6 = 3.444 occuring
John throws a biased four-sided dice.
The probabilities of getting each number are summarised in the table below.
Number
1
2
3
4
Probability
0.2
x
0.2
0.2
Work out the probability that the dice lands on 2.
Answer:
0.4
Step-by-step explanation:
0.2+0.2+0.2=0.6
1.0-0.6=0.4
This isn't 0.2 like the others which is why it's a biased dice like it says.
HW HELP ASAP PLZZZZZ
[tex]\implies {\blue {\boxed {\boxed {\purple {\sf { \: (x - 5)(x - 4) }}}}}}[/tex]
[tex]\large\mathfrak{{\pmb{\underline{\blue{Step-by-step\:explanation}}{\blue{:}}}}}[/tex]
[tex] {x}^{2} - 9x + 20[/tex]
[tex] = {x}^{2} - 4x - 5x + 20[/tex]
Taking "[tex]x[/tex]" as common from first two terms and "[tex]5[/tex]" from last two terms, we have
[tex] = x(x - 4) - 5(x - 4)[/tex]
Taking the factor [tex](x-4)[/tex] as common,
[tex] = (x - 5)(x - 4)[/tex]
[tex]\red{\large\qquad \qquad \underline{ \pmb{{ \mathbb{ \maltese \: \: Mystique35♛}}}}}[/tex]
Find the zeros of the quadratic function: y = 6x2 + x – 35.
The zeros of the quadratic function: y = 6x^2 + x – 35 are x = -2.5 or x = 7/3
How to determine the zeros?The function is given as:
y = 6x^2 + x - 35
Expand the function
y = 6x^2 + 15x - 14x - 35
Factorize the function
y = (2x + 5) * (3x - 7)
Set the function to 0
(2x + 5) * (3x - 7) = 0
Split
2x + 5 = 0 or 3x - 7 = 0
Solve for x
x = -2.5 or x = 7/3
Hence, the zeros of the quadratic function: y = 6x^2 + x – 35 are x = -2.5 or x = 7/3
Read more about quadratic functions at:
https://brainly.com/question/1214333
#SPJ1
Solve the simultaneous equations.
Show all your working.
3x + 4y = 14
5x+2y=21
Step-by-step explanation:
hear is your answer in attachment
Find the whole using the percent proportion. 70% of what number of hay bales is
63 hay bales?
Answer:
90
Step-by-step explanation:
Let the whole number be x.
100% is to x as 70% is to 63
100/x = 70/63
10/x = 10/9
10x = 90 * 10
x = 90
Answer: 90
Step-by-step explanation:
0.7x = 63, x = 63/0.7 = 90
Multiply the polynomials.
(4x- + 4x + 6)(7x + 5)
[tex]\implies {\blue {\boxed {\boxed {\purple {\sf { \: 28 {x}^{3} + 48 {x}^{2} + 62x + 30}}}}}}[/tex]
[tex]\large\mathfrak{{\pmb{\underline{\red{Step-by-step\:explanation}}{\red{:}}}}}[/tex]
[tex](4 {x}^{2} + 4x + 6)(7x + 5)[/tex]
[tex] = \: 7x(4 {x}^{2} + 4x + 6) + 5(4 {x}^{2} + 4x + 6)[/tex]
[tex] = \: 28 {x}^{3} + 28 {x}^{2} + 42x + 20 {x}^{2} + 20x + 30[/tex]
Combining like terms, we have
[tex] = \: 28 {x}^{3} + (28 {x}^{2} + 20 {x}^{2} ) + (42x + 20x) + 30[/tex]
[tex] = \: 28 {x}^{3} + 48 {x}^{2} + 62x + 30[/tex]
[tex]\large\mathfrak{{\pmb{\underline{\orange{Mystique35 }}{\orange{❦}}}}}[/tex]
1/3(-15 divide 1/2) 1/4 what does it equal
Answer:
-2.5 or - 2 1/2
Step-by-step explanation:
Writing out the expression Mathematically ;
1/3(-15÷1/2)1/4
Using PEMDAS :
Solving the bracket first
(-15 ÷ 1/2) = (-15 * 2/1) = - 30
We have :
1/3(-30)1/4 = - 10 * 1/4 = - 10 / 4 = - 2.5
-2.5 = - 2 1/2
A, B, and C are collinear points:
B is between A and C.
If AB = 3x + 4, BC = 4x - 1, and AC = 6x + 5,
find AC.
9514 1404 393
Answer:
AC = 17
Step-by-step explanation:
The segment sum theorem tells you ...
AB +BC = AC
Substituting the given expressions, we have ...
(3x +4) +(4x -1) = (6x +5)
x = 2 . . . . . . . . . . . . . . . . . . subtract 3+6x from both sides
AC = 6x +5 = 6(2) +5
AC = 17
_____
AB = 10, BC = 7
Which of the following is the equation of a line in slope-intercept form for a
line with slope = and yintercept at (0, -1)?
O A. y - x-
1
B. y = 4x-1
O c. y= |x-1
O D. y=x+1
Answer:
y=1/4x - 1
Step-by-step explanation:
going off of the picture, I'd say this is your answer
Solve the system 6x -2y+z= -2 2x+ 3y - 3z =11 x+ 6y=31
Answer:
x = 1
y = 5
z = 2
Step-by-step explanation:
System of equations:
6x - 2y + z = -2
2x + 3y - 3z = 11
x + 6y = 31
Isolate one variable in any of the equations:
x + 6y = 31
x = 31 - 6y
Plug in this value for x in another equation:
6(31 - 6y) - 2y + z = -2
186 - 36y - 2y + z = -2
186 - 38y + z = -2
-38y + z = -188
z = -188 + 38y
Plug in these values in the remaining equation:
2(31 - 6y) + 3y - 3(-188 + 38y) = 11
62 - 12y + 3y + 564 - 114y = 11
626 - 12y + 3y - 114y = 11
626 - 9y - 114y = 11
626 - 123y = 11
-123y = -615
y = 5
Plug in value of y into our other answers to solve for x and z:
x = 31 - 6(5)
x = 31 - 30
x = 1
z = -188 + 38(5)
z = -188 + 190
z = 2
Check your work:
6x - 2y + z = -2
6(1) - 2(5) + 2 = -2
6 - 10 + 2 = -2
-4 + 2 = -2
-2 = -2
Correct!
*Note there are several ways to solve for these types of problems. I used substitution*
Substance A decomposes at a rate proportional to the amount of A present. a) Write an equation that gives the amount A left of an initial amount A0 after time t. b) It is found that 8 lb of A will reduce to 4 lb in 4.6 hr After how long will there be only 1 lb left?
a) Choose the equation that gives A in terms of A0, t, and k, where k > 0.
b) There will be 1 lb left after 14 hr (Do not round until the final answer. Then round to the nearest whole number as needed.)
Answer:
(a) [tex]A = A_0 * e^{kt}[/tex]
(b) There will be 1lb left after 14 hours
Step-by-step explanation:
Solving (a): The equation
Since the substance decomposes at a proportional rate, then it follows the following equation
[tex]A(t) = A_0 * e^{kt}[/tex]
Where
[tex]A_0 \to[/tex] Initial Amount
[tex]k \to[/tex] rate
[tex]t \to[/tex] time
[tex]A(t) \to[/tex] Amount at time t
Solving (b):
We have:
[tex]t = 4.6hr[/tex]
[tex]A_0 = 8[/tex]
[tex]A(4.6) = 4[/tex]
First, we calculate k using:
[tex]A(t) = A_0 * e^{kt}[/tex]
This gives:
[tex]A(4.6) = 8 * e^{k*4.6}[/tex]
Substitute: [tex]A(4.6) = 4[/tex]
[tex]4 = 8 * e^{k*4.6}[/tex]
Divide both sides by 4
[tex]0.5 = e^{k*4.6}[/tex]
Take natural logarithm of both sides
[tex]\ln(0.5) = \ln(e^{k*4.6})[/tex]
This gives:
[tex]-0.6931 = k*4.6[/tex]
Solve for k
[tex]k = \frac{-0.6931}{4.6}[/tex]
[tex]k = -0.1507[/tex]
So, we have:
[tex]A(t) = A_0 * e^{kt}[/tex]
[tex]A(t) = 8e^{-0.1507t}[/tex]
To calculate the time when 1 lb will remain, we have:
[tex]A(t) = 1[/tex]
So, the equation becomes
[tex]1= 8e^{-0.1507t}[/tex]
Divide both sides by 8
[tex]0.125= e^{-0.1507t}[/tex]
Take natural logarithm of both sides
[tex]\ln(0.125)= \ln(e^{-0.1507t})[/tex]
[tex]-2.0794= -0.1507t[/tex]
Solve for t
[tex]t = \frac{-2.0794}{-0.1507}[/tex]
[tex]t = 13.7983[/tex]
[tex]t = 14[/tex] --- approximated
What's the area of the trapezoid
Answer:
i dont know just study hard bro
Step-by-step explanation:
Answer:
A =36 ft^2
Step-by-step explanation:
The area of a trapezoid is given by
A = 1/2 ( b1+b2)h where b1 and b2 are the lengths of the bases
A = 1/2 ( 13+5) *4
A = 1/2 ( 18)*4
A =36 ft^2
Help me calculate Lim for this lesson
Answer:
I'm acutally not too sure on this but give me a moment to solve this
Step-by-step explanation:
Question 31 of 50
An electrician charges (1) an initial fee of $20 and then $30 per hour. Which linear equation represents this if (h) represents hours?
f = 20h + 30
f=30h + 20
f = 50h
Answer:
ok so if it is 30 dollars per hour so 30h plus 20 so
f=30h+20
Hope This Helps!!!
Assume that you purchased a new car today and financed $55,000 of the price on a 72-month payment contract with a nominal rate of 6.00%. Further, assume that you plan on paying off the balance of the car loan after you make your 48th payment. How much will your loan balance be when you pay off the car?
Answer:
The amount that your loan balance will be when you pay off the car is $20,566.18.
Step-by-step explanation:
Step 1. Calculation of monthly payment
This can be calculated using the formula for calculating the present value of an ordinary annuity as follows:
PV = P * ((1 - (1 / (1 + r))^n) / r) …………………………………. (1)
Where;
PV = Present value or the cost of the new car = $55,000
P = Monthly payment = ?
r = Monthly nominal rate = Nominal rate / 12 = 6% / 12 = 0.06 / 12 = 0.005
n = number of months = 72
Substitute the values into equation (1) and solve for P, we have:
$55,000 = P * ((1 - (1 / (1 + 0.005))^72) / 0.005)
$55,000 = P * 60.3395139355201
P = $55,000 / 60.3395139355201 = $911.51
Step 2. Calculation of the loan amount balance when you pay off the car
This can be calculated using the ballon payment formula as follows:
P = (PV - (Ballon / (1 + r)^n)) * (r / (1 – (1 + r)^-n)) ...................... (1)
Where:
P = Monthly payment = $911.51
PV = Present value or the cost of the new car = $55,000
Ballon = Ballon payment or the loan amount balance when you pay off the car = ?
r = Monthly nominal rate = Nominal rate / 12 = 6% / 12 = 0.06 / 12 = 0.005
n = number months to pay off the loan amount balance = 48
Substituting the values into equation (1) and solve for Ballon, we have:
911.51 = (55,000 - (Ballon / (1 + 0.005)^48)) * (0.005 / (1 - (1 + 0.005)^-48))
911.51 = (55,000 - (Ballon / 1.27048916109538)) * 0.0234850290479363
911.51 / 0.0234850290479363 = 55,000 - (Ballon / 1.27048916109538)
38,812.39 = 55,000 - (Ballon / 1.27048916109538)
Ballon / 1.27048916109538 = 55,000 - 38,812.39
Ballon / 1.27048916109538 = 16,187.61
Ballon = 16,187.61 * 1.27048916109538
Ballon = $20,566.18
Therefore, the amount that your loan balance will be when you pay off the car is $20,566.18.
Find all solutions to the equation.
cos^2 x +2cosx+1=0
[tex]x= \pi[/tex]
Step-by-step explanation:
[tex]\cos^2x+\cos x+1=0[/tex]
Let [tex]u= \cos x[/tex]
Then [tex]u^2+2u+1=(u+1)^2=0[/tex]
or
[tex]\cos x = -1[/tex]
This gives us [tex]x= \pi[/tex] or all integer multiples of [tex]\pi (n \pi)[/tex]
help with algebra 1 equation pls help
Answer:
b. [tex] \blue{k = \dfrac{l - 14j}{3}} [/tex]
Step-by-step explanation:
[tex] l = 14j + 3k [/tex]
Switch sides.
[tex] 14j + 3k = l [/tex]
Subtract 14j from both sides.
[tex] 3k = l - 14j [/tex]
Divide both sides by 3.
[tex] \blue{k = \dfrac{l - 14j}{3}} [/tex]
Can someone please answer this ASAP?
Answer:
Letter C
Step-by-step explanation:
Given:
[tex]5a+18<-27[/tex]
Subtract 18 from both sides
[tex]5a<-45[/tex]
Divide 5 from both sides to get [tex]a[/tex] alone
[tex]a<-9[/tex]
Letter C is the correct answer choice because the dot is at -9, the arrow is facing to the left, and the dot is open indicating that it's not greater/less than ""or equal to"".
Hope this is helpful
