A-7
B-?
C-14
Pythagorean theorem

The induced emf in a region of the brain when a conducting loop is held near a person's head and the current in the loop is changed rapidly, is equal to -525 V.

The induced emf can be calculated using Faraday's law of electromagnetic induction, which states that the emf induced in a loop of wire is equal to the rate of change of magnetic flux through the loop.

The magnetic flux (Φ) is equal to the product of the magnetic field (B) and the area (A) through which it passes. Therefore, the induced emf (ε) is given by:

ε = -dΦ/dt ⇒ -B dA/dt.

Where the negative sign indicates that the emf is induced in a direction that opposes the change in magnetic flux.

In this problem, the magnetic field changes at a rate of 3.00 × 10^4 T/s over an area of 1.75 × 10^-2 m^2. Therefore, the induced emf is:
Plugging in our values, we get:
E = (-3.00 10^4 T/s)(1.75 10^(-2) m^2)/(1 s)
E = -525 V

Therefore, the induced emf, in this case, is -525 V. Here, the negative sign shows that the emf is induced in a direction that opposes the change in magnetic flux

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The star Proxima Centauri is 4.2 light-years away from Earth, making it the sun's nearest rival. The word "nearest" means "nearest" in Spanish.

"A method to find a single unit value from a multiple unit value and to find a multiple unit value from a single unit value."

We always count the unit or amount value first and then calculate the more or less amount value.

For this reason, this procedure is called a unified procedure.

Many set values ​​are found by multiplying the set value by the number of sets.

A set value is obtained by dividing many set values ​​by the number of sets.

Hence, The star Proxima Centauri is 4.2 light-years away from Earth, making it the sun's nearest rival. The word "nearest" means "nearest" in Spanish.

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Let's break this problem down step by step.

First, we can work out the weight of one white ball by subtracting the weight of 6 white and 3 orange balls (20 pounds) from the weight of 2 white and 5 orange balls (8 pounds):

Weight of 1 white ball = 8 - 20 = -12

Next, we can work out the weight of one orange ball by subtracting the weight of 2 white and 5 orange balls (8 pounds) from the weight of 6 white and 3 orange balls (20 pounds):

Weight of 1 orange ball = 20 - 8 = 12

Now that we know how much one white and one orange ball weigh, we can work out the weight of 4 white and 4 orange balls together:

Weight of 4 white and 4 orange balls = (4 x -12) + (4 x 12) = 0

Therefore, the weight of 4 white and 4 orange balls together is 0 pounds.

By solving two given simultaneous equations using algebra, we find that the combined weight of 4 white balls and 4 orange balls is 16 pounds.

The subject matter of this question pertains to simultaneous equations. The equations in question are, 2w + 5o = 8 and 6w + 3o = 20, where w stands for the weight of a white ball and o stands for the weight of an orange ball. We can solve these equations to find the individual weights of these balls. After finding these values, we substitute these into a new equation, 4w + 4o, to find the total weight of 4 white and 4 orange balls together. By solving these equations, we find that the weight of 4 white balls and 4 orange balls together is 16 pounds.

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The height of the triangle is 1.12 units (rounded to two decimal places).

The height of a triangle is the perpendicular distance from the base of the triangle to the opposite vertex. In other words, it is the length of the line segment that is perpendicular to the base and passes through the opposite vertex.

We can use the formula for the area of a triangle:

Area = (1/2) * base * height

And since we know the values of the base (b) and the area (a), we can rearrange the formula to solve for the height (h):

h = (2a) / b

Plugging in the values of a and b:

h = (2 * 14) / 25

h = 28 / 25

Therefore, the height of the triangle is 1.12 units (rounded to two decimal places).

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Answer: One possible solution is to work 12.3 hours landscaping and 3.7 hours clearing tables, earning approximately $167.1.

Step-by-step explanation:

Let x be the number of hours landscaping and y be the number of hours clearing tables.

The system of inequalities can be written as:

x ≤ 13 (maximum of 13 hours landscaping)

x + y ≤ 16 (maximum of 16 hours total)

13x + 8y ≥ 160 (minimum earnings of $160)

To graph this system of inequalities, we can start by graphing the boundary lines of each inequality as follows:

x = 13 (vertical line at x = 13)

x + y = 16 (line with intercepts at (0, 16) and (16, 0))

13x + 8y = 160 (line with intercepts at (0, 20) and (12.3, 0))

Note that we only need to graph the portion of the lines that are in the feasible region (i.e. where x and y are non-negative).

The feasible region is the triangle formed by the intersection of the three boundary lines, as shown below:

    |

20 --|--------------------------

    |              /|

    |           /   |

    |        /      |

    |     /         |

16 --|------------------

    |  /              |

    |/                 |

    -------------------------

           13         12.3

Let x be the number of hours landscaping and y be the number of hours clearing tables.

The system of inequalities can be written as:

x ≤ 13 (maximum of 13 hours landscaping)

x + y ≤ 16 (maximum of 16 hours total)

13x + 8y ≥ 160 (minimum earnings of $160)

To graph this system of inequalities, we can start by graphing the boundary lines of each inequality as follows:

x = 13 (vertical line at x = 13)

x + y = 16 (line with intercepts at (0, 16) and (16, 0))

13x + 8y = 160 (line with intercepts at (0, 20) and (12.3, 0))

Note that we only need to graph the portion of the lines that are in the feasible region (i.e. where x and y are non-negative).

The feasible region is the triangle formed by the intersection of the three boundary lines, as shown below:

lua

Copy code

    |

20 --|--------------------------

    |              /|

    |           /   |

    |        /      |

    |     /         |

16 --|------------------

    |  /              |

    |/                 |

    -------------------------

           13         12.3

The vertices of the feasible region are (0, 16), (12.3, 3.7), and (13, 0).

To determine one possible solution, we can evaluate the objective function (total earnings) at each vertex:

(0, 16): 13(0) + 8(16) = $128

(12.3, 3.7): 13(12.3) + 8(3.7) ≈ $167.1

(13, 0): 13(13) + 8(0) = $169

Therefore, one possible solution is to work 12.3 hours landscaping and 3.7 hours clearing tables, earning approximately $167.1.

The sampling approach that was used in the statement "Kane randomly sampled 250 nurses from urban areas and 250 from rural areas from a list of licensed nurses in Wisconsin to study their attitudes toward evidence-based practice" is Stratified random sampling.

Stratified random sampling is a method of sampling that is based on dividing the population into subgroups called strata. Stratified random sampling is a statistical sampling method that involves the division of the population into subgroups or strata, and a sample is then drawn from each stratum in proportion to the size of the stratum. It's a sampling method that ensures the representation of all population strata in the sample, making it more effective than simple random sampling.

Stratified random sampling is used when there are variations in the population that are likely to influence the outcome of the study. The stratified random sampling method is used to ensure that these differences are reflected in the sample. In this way, the results of the study are more representative of the entire population than they would be if a simple random sample were used.

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The image of (-2, 6) after a dilation by a scale factor of 1/2 centered at the origin is given as follows:

(-1, 3).

A dilation is a transformation that changes the size of a figure, but not its shape. Specifically, a dilation is a type of similarity transformation that involves multiplying the coordinates of each point in a figure by a scale factor. This causes the figure to either enlarge or reduce in size.

The scale factor in the context of this problem is given as follows:

1/2.

The coordinates of the original point are given as follows:

(-2, 6).

Multiplying the coordinates of the original point by the scale factor, the coordinates of the image are given as follows:

(-1,3).

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The solution to the system of equations is x = 16/5 and y = 11/5.

Graphing, substitution, elimination, and matrices are the four methods for solving systems of equations.

Using the substitution method, we can find x and y.

To begin, let us solve the first equation for x:

2x + 3y = 13

2x = 13 - 3y

x = (13 - 3y)/2

This expression for x can now be substituted into the second equation:

x - y = 1

[(13 - 3y)/2] - y = 1

To remove the denominator, multiply both sides by 2:

13 - 3y - 2y = 2

Simplifying:

13 - 5y = 2

Taking 13 off both sides:

-5y = -11

-5 divided by both sides:

y = 11/5

Now that we've discovered y, we can plug it back into either of the original equations to find x. Let's look at the first equation:

2x + 3y = 13

2x + 3(11/5) = 13

To eliminate the fraction, multiply both sides by five:

10x + 33 = 65

Taking 33 away from both sides:

10x = 32

Divide both sides by ten:

x = 16/5

As a result, the system of equations solution is x = 16/5 and y = 11/5.

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Answer:

5/7

Step-by-step explanation:

Make all the denominators 42.

26/42, 27/42, 28/42, 29/42

The pattern is the numerator increases by one each time.

30/42 = 5/7

Hope this helps!

Using proportions, the real height of the telephone mast is estimated to be 9 meters.

A proportion is a fraction of a total amount, and equations are constructed using these fractions and estimates to find the desired measures in the problem using basic arithmetic operations like multiplication and division. Because the telephone box and the mast are similar figures in this problem, their side lengths are proportional.

The following proportional relationship is established as a result:

x / 1.5 cm = 10.8 cm / 1.8 cm.

The relationship's left side can be simplified as follows:

6 = x / 1.5 cm.

The estimate is then calculated using cross multiplication, as shown below:

6 x 1.5 cm = 9.5 cm².

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m∠R is therefore 76 degrees as a triangle's total sides equal 180 degrees.

The degree of rotation between two lines or two planes around a central point is measured by an angle. Typically, it is expressed in radians or degrees. Angles are used in many mathematical and scientific uses, including trigonometry, physics, and engineering, where they are crucial in determining the shape and characteristics of geometric figures. Angles come in four different varieties: acute (less than 90 degrees), right (exactly 90 degrees), oblique (more than 90 degrees), and straight (exactly 180 degrees).

given

Because a triangle's total sides equal 180 degrees, we have:

R, S, and T add up to 180.

Inputting the numbers provided yields:

m∠R + 72 + 32 = 180

Simplifying the equation:

m∠R = 76

m∠R is therefore 76 degrees as a triangle's total sides equal 180 degrees.

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The weight of the package is 56 using arithmetic operations.

Mathematicians use multiplication to calculate the product of two or more integers. It is a fundamental operation in mathematics that is frequently used in everyday living. When we need to combine sets of similar sizes, we use multiplication. The fundamental concept of repeatedly adding the same number is represented by the process of multiplication. The results of multiplying two or more numbers are known as the product of those numbers, and the factors that are compounded are referred to as the factors. Repeated adding of the same number is made easier by multiplying the numbers.

let weight of package be= x

x*5/7=40

x=(40*7)/5

x=56

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Answer:

When a point is reflected over the x-axis, the x-coordinate remains the same, but the y-coordinate is multiplied by -1.

So, the coordinates of X' are (9, -5) since the x-coordinate remains the same and the y-coordinate is multiplied by -1.

Similarly, the coordinates of Y' are (-3, -6) and the coordinates of Z' are (-8, -4).

Therefore, X′ is (9,−5), Y′ is (−3,−6), and Z′ is (−8,−4).

Answer:

Step-by-step explanation:

-11 +23-46+ (-12) =

12 - 46 + (-12) =

-34 - 12 =

-46

Answer:

We see that each fraction is in simplest form, and they add up to 1, so this confirms that 168 is the highest number of similar bouquets that Fatima can make without having any flowers left over.

Step-by-step explanation:

Yeah, I guess what that person said ^^ ??

Step-by-step explanation:

This graph shows a quadratic curve with roots 0 and -4

The polynomial is therefore

x² -x(α+β) + αβ

x² -x(0-4) + 0(-4)

x² +4x +0

x² + 4x

But it's an n-shaped curve, meaning a is negative

Multiply through by -1

-x² - 4x

y = -x² - 4x

So when the input value y = 3, we have

3 = -x² - 4x

Rearrange

x² + 4x + 3 = 0

Factorize

x² + 3x + x + 3 = 0

x(x + 3) +1(x + 3) = 0

(x + 1) (x + 3) = 0

x + 1 = 0 and x + 3 = 0

x = 0-1 and x = 0-3

Therefore,

x = -1 and -3

Check the graph to confirm

Dan’s mistake is that he said the probability of Deshawn not doing basketball or not talking to friends after school is 35% which is not true.

Given:

Let’s consider the probability of Deshawn not doing basketball after school:Probability of Deshawn not doing basketball after school = 100% - Probability of Deshawn doing basketball after school= 100% - 20% = 80%

Similarly, let’s consider the probability of Deshawn not talking to friends after school: Probability of Deshawn not talking to friends after school = 100% - Probability of Deshawn talking to friends after school= 100% - 45% = 55% Probability of Deshawn doing neither basketball nor talking to friends after school:Probability of Deshawn not doing basketball after school * Probability of Deshawn not talking to friends after school= 80% * 55% = 44%

The probability of Deshawn doing either basketball or talking to friends after school is 65%, and the probability of Deshawn doing neither basketball nor talking to friends after school is 44%, which is greater than 35% which is Dans mistake. Hence, Dan’s mistake is that he said the probability of Deshawn not doing basketball or not talking to friends after school is 35% which is not true.

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It pays to purchase the information for any value of c less than $13.25 then we buy the information for a price less than $13.25, we can increase our expected payoff above a loss of $1.

To calculate it Let C1 be the event that the first coin is selected and C2 be the event that the second coin is selected. Then, we have:

P(C1) = P(C2) = 1/2 (since one of the two coins is randomly chosen)

P(H|C1) = 0.6 (probability of getting heads when the first coin is flipped)

P(H|C2) = 0.3 (probability of getting heads when the second coin is flipped)

Let's consider the case when we do not buy the insider's information. Then, our expected payoff can be calculated as follows:

E(X) = P(C1) * P(H|C1) * (10) + P(C1) * P(T|C1) * (-10) + P(C2) * P(H|C2) * (10) + P(C2) * P(T|C2) * (-10)

= (1/2) * (0.610 - 0.410 + 0.310 - 0.710)

= -1

Therefore, if we do not buy the insider's information, our expected payoff is a loss of $1.

Now, let's consider the case when we buy the insider's information for an amount c.

If we buy the information, we will know which coin was selected and we can bet accordingly to maximize our expected payoff.

If we know that the first coin was selected, we should bet on heads since it has a higher probability of occurring. If we know that the second coin was selected, we should bet on tails since it has a higher probability of occurring.

Therefore, if we buy the insider's information, our expected payoff can be calculated as follows:

E(X|buying information) = P(C1) * P(H|C1) * (10-c) + P(C1) * P(T|C1) * (-c) + P(C2) * P(H|C2) * (-c) + P(C2) * P(T|C2) * (10-c)

= (1/2) * (0.6*(10-c) - 0.4c + 0.3(-c) - 0.7*(10-c))

= -0.2c + 1.5

To find the values of c for which it pays to purchase the information, we need to solve the inequality:

E(X|buying information) > E(X)

-0.2c + 1.5 > -1

Solving for c, we get:

c < 13.25

Therefore, it pays to purchase the information for any value of c less than $13.25. If we buy the information for a price less than $13.25, we can increase our expected payoff above a loss of $1.

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When one of the coin is flipped it lands on heads with probability 0.6 and when the other is flipped, it lands on heads with probability 0.3, then the probability that the coin lands on heads is 0.45 and the coin lands on heads but the probability that the chosen coin was the one that lands on heads with probability 0.6 is 0.67.

a) The probability of getting heads, we can use the law of total probability.

There are two coins, and each has a probability of landing on heads. So we can calculate the probability of getting heads by weighting each coin's probability by its probability of being chosen.

Therefore,

P(heads) = P(heads from coin 1) * P(choose coin 1) + P(heads from coin 2) * P(choose coin 2)

Plugging in the values, we have:

P(heads) = 0.6 * 0.5 + 0.3 * 0.5 = 0.45

Therefore, the probability of getting heads is 0.45.

b) The probability that the chosen coin was the one that lands on heads with probability 0.6, given that the coin lands on heads, we need to use Bayes' theorem. Specifically, we have:

P(choose coin 1 | heads) = P(heads from coin 1 | choose coin 1) * P(choose coin 1) / P(heads)

Plugging in the values, we have:

P(choose coin 1 | heads) = 0.6 * 0.5 / 0.45 = 0.67

Therefore, the probability that the chosen coin was the one that lands on heads with probability 0.6, given that the coin lands on heads, is 0.67.

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Answer:

Step-by-step explanation:

[tex]\angle R+\angle S+ \angle T =180[/tex]       (angle sum of a triangle is 180°)

[tex]2x+11+3x+23+x+42=180[/tex]

                              [tex]6x+76=180[/tex]

                                      [tex]6x=104[/tex]

                                        [tex]x=17.667[/tex]

[tex]\text{So we get: } \angle R= 46.33,\angle S=76,\angle T=59.667[/tex]

In ascending order:

   [tex]\angle R= 46.33,\angle T=59.667,\angle S=76[/tex]

Answer:

700

Step-by-step explanation:

28 % of n = 28/100 x n = 0.28n

If 28% of n = 196 that means

0.28n = 196

Divide both sides by 0.28

0.28n/0.28 = 196/0.28

n = 700

Given that a 0.625 kg basketball is dropped from a height of 3 meters straight down. The coefficient of restitution between the ball and the ground is e = 0.87. At 0.15 seconds after the basketball is dropped, a 58.5-gram tennis ball is dropped from the same 3-meter height straight onto the basketball. If the coefficient of restitution between the tennis ball and the basketball is e = 0.9,

    determine how high the tennis ball bounces above the ground after the collision. Neglect the size of the balls.

The balls meet at a height of 0.5073 m above the ground. Hence the height that the tennis ball bounces above the ground is to be calculated.

Given that the coefficient of restitution between the ball and the ground is e = 0.87The coefficient of restitution between the tennis ball and the basketball is e = 0.9

The coefficient of restitution(e) is defined as the ratio of the relative velocity of separation and relative velocity of approach between two objects.

When a ball falls from height, it gains potential energy.

Potential energy (PE) = mghWhere, m = mass of the object, g = acceleration due to gravity, h = height

PE of Basketball = mgh= 0.625 kg * 9.81 m/s² * 3 m= 18.4 Joules

Initial kinetic energy (KE) = PE of Basketball

KE of Basketball = 18.4 J

Let the velocity of the basketball before collision be u1 and the velocity of the tennis ball before collision be u2. After the collision, let the velocity of the basketball be v1 and the velocity of the tennis ball be v2.

Using the coefficient of restitution (e) we can find the velocity of the balls after collision

   v1 - v2 = -e(u1 - u2)

Initial momentum (P) = Final momentum (P)

before the collision  P = m1u1 + m2u2

after collision  P = m1v1 + m2v2P = (0.625 kg * u1) + (0.0585 kg * u2)P

                           = (0.625 kg * v1) + (0.0585 kg * v2)

        Using the above two equations and the given coefficients of restitution, we can find the velocity of the balls after collisionv1 = (m1u1 + m2u2 + e * m2 * (u2 - u1)) / (m1 + m2)v2 = (m1u1 + m2u2 + e * m1 * (u1 - u2)) / (m1 + m2)

     Here, m1 = mass of basketball

                     = 0.625 kg,

                m2 = mass of tennis ball

                      = 0.0585 kg,

  u1 = 0, u2 = 0P = m1v1 + m2v2 => v1 + v2 = P / (m1 + m2)

Also given that the time taken by the balls to meet is 0.15 seconds

Let h be the height to which the tennis ball bounces after the collision.

When the tennis ball bounces to height h, it gains potential energy.

KE + PE = Total energy

             = Constant Using the principle of conservation of energy we can find the height to which the tennis ball bounces after collision(1/2) * m2 * v2² + (1/2) * m2 * g * h

              = (1/2) * m2 * u2² + (1/2) * m2 * g * 0(1/2) * m2 * v2²

              = (1/2) * m2 * u2² - (1/2) * m2 * g * h(1/2) * v2²

              = (1/2) * u2² - g * h

Substituting the values of u1, u2, m1, m2, e, t and g, we get:

v1 = (0 + 0.0585 kg * 9.81 m/s² + 0.9 * 0.0585 kg * (0 - 0)) / (0.625 kg + 0.0585 kg)v1

   = 1.96 m/sv2

    = (0.625 kg * 0 + 0 + 0.9 * 0.625 kg * (0 - 0)) / (0.625 kg + 0.0585 kg)v2

    = 5.5 m/s

Here, u1 = u2 = 0.

Using the above equation, we can find the height to which the tennis ball bounces after collision (1/2) * (0.0585 kg) * (5.5 m/s)² = (1/2) * (0.0585 kg) * (0 m/s)² - (0.0585 kg) * 9.81 m/s² * h12.83 J

                = -0.286 J - 0.572 h0.572 h

                = -12.83 J / 2h

                = -12.83 J / (2 * 0.572)

                = 11.2 m

Hence the height to which the tennis ball bounces above the ground after the collision is 11.2 m.

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The x-intercepts are (0, 0) and (4, 0), and the y-intercept is (0, 0).

By graphing linear equatiοns, yοu can explain the relatiοnship between twο variables visually. We can easily see what happens tο οne variable as the οther grοws by using a graph. The value οf the x variable rises as we mοve tο the right οn a graph.

[tex]y = (3/2)x^2 - 6x[/tex] is the given equatiοn.

We can use the fοrmula tο find the x-cοοrdinate(s) οf the vertex οf this parabοla:

x = -b/2a

where a and b are the cοefficients οf the equatiοn's x² and x terms, respectively.

In this case, a = 3/2 and b = -6, resulting in:

x = -(-6)/(2*3/2) = 4

As a result, the vertex's x-cοοrdinate is 4.

Tο find the y-cοοrdinate οf the vertex, enter this value οf x intο the fοllοwing equatiοn:

[tex]y = (3/2)(4)^2 - 6(4) = -12[/tex]

As a result, the parabοla's vertex is at the pοint (4, -12).

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Answer :

1. We are given with a parallelogram whose opposite sides are :-

We know that opposite sides and angles of the parallelogram are equal.

PS = RQ

[tex] \implies \sf \: (-1 + 4x) = (3x + 3) \\ [/tex]

[tex] \implies \sf \: 4x - 3x = 3 + 1\\ [/tex]

[tex] \implies \sf \: x = 4 \\ [/tex]

Length of RQ is (3x + 3)

Substituting value of x = 4 in RQ.

[tex] \implies \sf \: (3x +3) \\ [/tex]

[tex] \implies \sf \: 3(4) + 3 \\ [/tex]

[tex] \implies \sf \: 12 + 3 \\ [/tex]

[tex] \implies \sf \: 15 \\ [/tex]

Therefore, Length of RQ will be 15

2. Find [tex] \sf \angle G [/tex]

We are given with :-

Since, Opposite angles of parallelogram are also equal :

[tex]\angle G = \angle E \\ [/tex]

[tex]\implies \sf \: 5x -9 = 3x + 11 \\ [/tex]

[tex]\implies \sf \: 5x - 3x = 11 +9 \\ [/tex]

[tex] \implies \sf \: 2x = 20 \\ [/tex]

[tex] \implies \sf \: x = \dfrac{20}{10} \\ [/tex]

[tex] \implies \sf \: x = 10 \\ [/tex]

Since [tex] \sf \angle G [/tex] is 5x - 9.

Substituting value of (x = 10) in [tex] \sf \angle G [/tex]

[tex] \implies \sf \: 5(10) - 9 \\ [/tex]

[tex] \implies \sf \: 50 -9 \\ [/tex]

[tex] \implies \sf \: 41 \\ [/tex]

Therefore, [tex] \sf \angle G [/tex] is 41.

Answer:

19. QR = 15 units.

20. m ∡G=41°

Step-by-step explanation:

The properties of a parallelogram are:

Question No. 19.

We know that the opposite side of parallelogram is equal, So

PS=QR

-1+4x=3x+3

First of all we will find the value of x.

-1 + 4x = 3x + 3

Subtracting 3x from both sides, we get:

x - 1 = 3

Adding 1 to both sides, we get:

x = 4

SO, QR=3*4+3=15

Side QR is 15 units.

Question No. 20.

We know that the opposite angle of parallelogram is equal, So

EF=GD

3x+11=5x-9
Subtracting 3x from both sides:

3x + 11 - 3x = 5x - 9 - 3x

11 = 2x - 9

Next, we can add 9 to both sides to isolate the variable term on one side:

11 + 9 = 2x - 9 + 9

20 = 2x

Finally, we can solve for x by dividing both sides by 2:

20/2 = 2x/2

x=10

Now

m ∡G=5x-9=5*10-9=41°

therefore m ∡G=41°

Maria's capital gain is 55.21%. Rounded to the nearest tenth of a percent, this is 55.2%.

To determine Maria's capital gain as a percent, we need to calculate the difference between the selling price and the purchase price, and then express this difference as a percentage of the purchase price.

The purchase price for 1,000 shares of stock was:

$35.50 x 1,000 = $35,500

The selling price for 1,000 shares of stock was:

$55.10 x 1,000 = $55,100

The capital gain is the difference between the selling price and the purchase price:

$55,100 - $35,500 = $19,600

To express this gain as a percentage of the purchase price, we divide the capital gain by the purchase price and multiply by 100:

($19,600 / $35,500) x 100 = 55.21%

In summary, to calculate the percent capital gain from the purchase and selling price of a stock, we simply divide the difference between the two prices by the purchase price and multiply by 100.

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The given family of functions is y = c1ex + c2e−x which is the general solution of the differential equation y'' − y = 0 on the indicated interval which is (−∞, ∞).

       Now, we are required to find a member of the family that is a solution to the initial-value problem which is

                             y(0) = 0 and y′(0) = 5.

     The differential equation is y'' − y = 0

      The characteristic equation is r2 − 1 = 0r2 = 1r1 = 1 and r2 = −1

     The general solution of the differential equation is y = c1ex + c2e−x

      Let us solve for the constants by using the given initial conditions:

                    At x = 0,y(0) = c1e0 + c2e0 = 0 + 0 = 0y(0) = 0

                    means c1 + c2 = 0or c1 = -c2At x = 0, y′(0) = c1ex |x=0 + c2e−x |x=0(d/dx)(c1ex + c2e−x) |x=0y′(0) = c1 - c2 = 5c1 - c2 = 5c1 - (-c1) = 5c1 + c1 = 5c1 = 5/2c1 = 5/2

                    Let's replace c1 = 5/2 in c1 = -c2, c2 = -5/2

                The solution of the initial-value problem y = (5/2)ex − (5/2)e−x is a member of the family y = c1ex + c2e−x that is a solution of the initial-value problem y(0) = 0 and y′(0) = 5.

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The particular solution to the differential equation is given by: y(t) = y_ h(t) + y_ p(t) = c exp (-5/2 t) + t + 3Here, y_ h(t) is the homogeneous solution, which we don't need to find for this problem.

To solve the given differential equation, we'll need to use the method of undetermined coefficients. In this method, we assume that the particular solution to the differential equation has the same form as the forcing term. Here's how we can solve the given differential equation: Identify the forcing term and its derivatives. The forcing term is given by: f(t) = 68 - 20tWe can find its first derivative as follows: f'(t) = -20We can find its second derivative as follows: f''(t) = Guess the form of the particular solution We assume that the particular solution has the same form as the forcing term.

Since the forcing term is a first-degree polynomial, we assume that the particular solution also has the form of a first-degree polynomial: y_ p(t) = At + B Here, A and B are constants that we need to determine. Find the derivatives of the assumed form of the particular solution. Here are the first and second derivatives of the assumed form of the particular solution: y_ p(t) = At + B ==> y_ p'(t) = A ==> y_ p''(t) = 0. Substitute the assumed form of the particular solution and its derivatives into the differential equation Substituting y_ p(t), y_ p'(t), and y_ p''(t) into the differential equation, we get:8A + 20(At + B) = 68 - 20t Simplifying the above equation, we get: (8A + 20B) + (20A - 20)t = 68Comparing the coefficients of t and the constant terms on both sides,

we get two equations:8A + 20B = 68 (1)20A - 20 = 0 (2)Solving equation (2) for A, we get: A = 1 Substituting A = 1 into equation (1), we get:8 + 20B = 68Solving for B, we get: B = 3. Write the particular solution to the differential equation Substituting A = 1 and B = 3 into the assumed form of the particular solution, we get :y_ p(t) = t + 3Therefore, the particular solution to the differential equation is given by: y(t) = y_ h(t) + y_ p(t) = c exp (-5/2 t) + t + 3Here, y_ h(t) is the homogeneous solution, which we don't need to find for this problem.

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Since the calculated t-value (3.14) is greater than the critical value (1.98), we reject the null hypothesis.

In statistical hypothesis testing, the null hypothesis is a statement about a population parameter that is assumed to be true until there is sufficient evidence to suggest otherwise. The null hypothesis is typically denoted by H0 and represents the status quo or default assumption.

The null hypothesis often takes the form of an equality or a statement of "no difference" or "no effect" between two or more groups, variables, or populations. For example, the null hypothesis could be that the mean score of a group of students on a test is equal to a certain value, or that there is no difference in the average height of males and females in a population.

We want to test the hypothesis that the mean amount of time spent in extracurricular activities per week is the same in the suburban and city school districts. Set up the null and alternative hypotheses is as given by:

Null hypothesis: u1 - u2 = 0

Alternative hypothesis: u1 - u2 ≠ 0

To test this hypothesis, we can use a two-sample t-test. We first calculate the test statistic:

t = ((x1 - x2) - (u1 - u2)) / √(s1²/n1 + s2²/n2)

where x1, s1, and n1 are the sample mean, standard deviation, and sample size for the suburban school district, and x2, s2, and n2 are the sample mean, standard deviation, and sample size for the city school district.

Plugging in the values, we get:

t = ((6 - 4) - 0) / √((3²/60) + (2²/40)) ≈ 3.14

This test's degrees of freedom are given by:

df = (s1²/n1 + s2²/n2)² / ( (s1²/n1)² / (n1 - 1) + (s2²/n2)² / (n2 - 1) )

Plugging in the values, we get:

df = ((3²/60) + (2²/40))² / ( (3²/60)² / 59 + (2²/40)² / 39 ) ≈ 93.24

Using a t-distribution table with 93 degrees of freedom and a level of significance of 0.05, we find the critical values to be approximately -1.98 and 1.98.

Since the calculated t-value (3.14) is greater than the critical value (1.98), we reject the null hypothesis and conclude that there is sufficient evidence to suggest that the mean amount of time spent in extracurricular activities per week is different between the suburban and city school districts.

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Step-by-step explanation:

A. To find f(x+h), we substitute (x+h) for x in the equation f(x) = 4x + 7:

f(x+h) = 4(x+h) + 7

Expanding the brackets:

f(x+h) = 4x + 4h + 7

Simplifying, we get:

f(x+h) = 4x + 7 + 4h

Therefore, f(x+h) = 4x + 7 + 4h.

B. To find f(x+h)-f(x)/h, we use the formula for the difference quotient:

[f(x+h) - f(x)] / h

Substituting the expressions we derived earlier:

[f(x+h) - f(x)] / h = [(4x + 7 + 4h) - (4x + 7)] / h

Simplifying, we get:

[f(x+h) - f(x)] / h = (4x + 4h - 4x) / h

Canceling out the 4x terms, we get:

[f(x+h) - f(x)] / h = 4h / h

Simplifying further, we get:

[f(x+h) - f(x)] / h = 4

Therefore, f(x+h)-f(x)/h = 4.

Answer:

Step-by-step explanation: In the problem, they tell us that

dL / dt = 7 cm/s (the rate at which the length is changing) and

dw / dt = 8 cm/s (the rate at which the width is changing)

Want dA/dt (the rate at which the area is changing) when L = 7 cm and w = 5 cm

The equation for the area of a rectangle is:

A = L·w, so will need the product rule when taking the derivative.

dA/dt = L (dw/dt) + w (dL/dt)

Now just plug in all of the given numbers:

dA/dt = (7)(7) + (5)(8) = 49+40 = 89  cm²/s