The force constant of the spring is 42.1 m.
What is force?Force is a physical quantity that is related to the interaction between two objects. It is a vector quantity, meaning it has both magnitude and direction. Force can be thought of as a push or a pull between two objects. When one object exerts force on another object, the second object experiences an equal and opposite reaction force. Some of the most common examples of force include friction, gravity, electric fields, and magnetism. Force is a key concept in physics, as it is often used to explain the motion of objects and the behavior of physical systems.
The force constant, or spring constant, of the spring can be calculated using the equation:
k = (4π^2m)/T^2. In this equation, m is the mass of the object and T is the period of oscillation.
Therefore, the force constant of the spring is
k = (4π^2*7.00kg)/(2.60s)^2 = 42.1 N/m.
This means that if a 1 N force is applied to the spring, it will stretch by 42.1 m.
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1. A car moving 11 m/s accelerates at 1.5 m/s². How fast is it moving after it accelerates for 50
seconds?
Type a response (show work please)
We may be aware that, for example, a car leaving a stop sign would move farther in a given amount of time the faster it accelerates.
what an acceleration is?acceleration is the rate of change in both speed of velocity over time. When anything moves faster or slower in a straight line, it is said to have been accelerated. So because direction is always shifting, motion on a circle accelerates even while the speed is constant.
What prompts accelerating?An object's velocity is altered by a net force, and acceleration increases with net force. To accelerate at the same rate as less massive objects, more massive objects need greater net forces.
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Uing two billiard ball and 3 to 4 entence decided experiment to demontrate the law of conervation of momentum. (4 point)
So let's talk about billiard balls and the law of conservation of momentum. For the purposes of this simplified discussion, momentum is always conserved for collisions between balls.
What is momentum?Momentum is a commonly used term in sports. A team that has the momentum is on the move and is going to take some effort to stop. A team that has a lot of momentum is really on the move and is going to be hard to stop. Momentum is a physics term; it refers to the quantity of motion that an object has. A sports team that is on the move has the momentum. If an object is in motion (on the move) then it has momentum.Momentum can be defined as "mass in motion." All objects have mass; so if an object is moving, then it has momentum - it has its mass in motion. The amount of momentum that an object has is dependent upon two variables: how much stuff is moving and how fast the stuff is moving. Momentum depends upon the variables mass and velocity. In terms of an equation, the momentum of an object is equal to the mass of the object times the velocity of the object.To learn more about velocity refer to:
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it’s actually 7th grade science no physics pls answer it’s a lot of points
What do the historical communication technologies in these photos have in common?
(pictures are shown below)
All the tools of communication such as the drum, telegraph et cetra were used for emergency communication.
What is communication?We know that communication has to do with the art of sending and receiving information between two people who may or may not be at the same place. We know that the dissemination of information is a very important aspect of life and we have always tried to invent means of communication especially at times when we have an emergency situation that needs a kind of an immediate remedy.
We can see that all the kinds of communication gadgets that have been show here are all from a period that is far behind the kind of civilization that we have to day and the kind of thge communication gadgets that are quite available to the people that are around today.
However, all the tools shown could be used to send information in times of emergency.
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a dog lifts a 0.75 kg bone straight up through a distance of 0.11 m. How much work was done by the dog ?
The work done by the dog is 0.81J.
What is work done?Work done is a measure of energy expended in moving an object; most commonly calculated by multiplying the force by the distance.
It is said that no work is done if the object does not move.
The work done on an object is the amount of energy transferred to an object through work.
According to this question, a dog lifts a 0.75 kg bone straight up through a distance of 0.11 m. The force applied to break the bone must be calculated first as follows:
Force = mass × acceleration
Force = 0.75kg × 9.8m/s²
Force = 7.35N
Work done = 7.35N × 0.11m = 0.81J
Therefore, 0.81J is the work done by the dog.
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a 6.2 kg object heading north at 3.0 m/s collides with an 8.0 kg object heading west at 3.5 m/s. if these two masses stick together upon collision, what is their velocity after collision?
The velocity of both objetcs after the collision is 3.07m/sec if both object masses are 6.2 kg and 8.0kg respectively.
To find the velocity of both objects we need to conserve the momentum. We need to follow the law of conservation of momentum which states that initial momentum is equal to final momentum.
Now, we know that momentum =mass × velocity
So, initial momentum of first object=6.2×3=18.6Kg-m/sec
Similarly, initial momentum of second object=8×3.5=28.0kg-m/sec
Now, it is given that both object stick together, so total mass of both objects are=(6.2+8)=14.2kg
Now, both objects are moving with common velocity, so assume both have velocity v
=>So, final momentum of both objects is =14.2×v
according to law of conservation of momentum
=>18.6+25=14.2v
=>43.6=14.2v
=>v=43.6/14.2
=>v=3.07m/sec
Hence, final velocity of objects are 3.07m/sec.
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John walks to the pizza place for lunch. He walks 2 km north, then 1 km east. To get home, he walks 2 km west and 1 km south. What distance did he travel? What is his displacement?
Answer:
The total distance covered is 3 km and the displacement is 2.24 km.
Explanation:
For the total distance covered by Anthony, we just add all of the distances.
1 km (going east) + 1 km (going east again) + 1 km (going south) = 3 km
Hence, the his total distance covered when he went to the pizza place is 3 km.
Solving for the displacement is a different matter. We cannot just add all of the distances. From analysis of the problem, Anthony traveled and formed a right triangle. He traveled 1 km east twice, making it 2 km east in total, then he traveled 1 km south.
When dealing with a right triangle with 2 sides given (for this problem the two sides are the 2 km east and the 1 km south), we use the Pythagorean Theorem.
Solution:
c² = a² + b² (Pythagorean Theorem)
c will be the longest side of the right triangle
a and b will be the other sides of the right triangle
c = √ (a² + b²)
c = √ (2² km + 1² km)
c = √5 km
c = 2.2361 km ≈ 2.24 km
Therefore, the displacement of Anthony is 2.24 km.
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a uniform meter stick of mass 24 g with two weights hanging from it is balanced on a knife edge at the 40 cm mark. a weight of mass 96 g hangs from the 9 cm mark. at which cm mark must the other weight of mass 96 g be located to keep the meter stick balanced?
The second weight of mass 96 g must be located at the 9 cm mark on the meter stick to keep it balanced.
To determine the location of the second weight that will keep the meter stick balanced, we need to consider the principles of equilibrium.
The weight of the meter stick can be calculated as follows:
Weight of meter stick = mass * acceleration due to gravity
= 24 g * 9.8 m/s^2
= 235.2 N
The total weight of the two hanging weights is 96 g + 96 g = 192 g = 1.92 N.
The sum of the forces acting on the meter stick is equal to zero when:
235.2 N + 1.92 N = 0
This equation tells us that the sum of the forces acting on the meter stick is equal to zero when the total weight of the two hanging weights is equal to the weight of the meter stick.
To determine the location of the second weight, we also need to consider the moments about the pivot point. The moment of a force is calculated as the product of the force and the distance from the pivot point. The moments about the pivot point are equal to zero when the sum of the moments of the forces on one side of the pivot point is equal to the sum of the moments of the forces on the other side of the pivot point.
The moment of the weight of the meter stick about the pivot point is calculated as follows:
Moment of the weight of meter stick = force * distance from pivot point
= 235.2 N * 0.4 m
= 94.08 N*m
The moment of the weight hanging from the 9 cm mark about the pivot point is calculated as follows:
Moment of weight hanging from 9 cm mark = force * distance from pivot point
= 1.92 N * 0.09 m
= 0.1728 N*m
To keep the meter stick balanced, the moment of the second weight must be equal in magnitude but opposite in direction to the moment of the weight hanging from the 9 cm mark. The moment of the second weight can be calculated as follows:
Moment of second weight = force * distance from pivot point
= 1.92 N * distance from pivot point
Substituting the value of the force and setting the moment equal to the negative of the moment of the weight hanging from the 9 cm mark, we get the following equation:
1.92 N * distance from pivot point = -0.1728 N*m
Solving for the distance from the pivot point, we find that the second weight must be located at a distance of 0.09 m from the pivot point, or 9 cm. This is the same distance from the pivot point as the weight hanging from the 9 cm mark.
Therefore, the second weight of mass 96 g must be located at the 9 cm mark on the meter stick to keep it balanced.
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A 1.5 kg block is on a 15° frictionless incline plane.
a) What is the normal force?
b) What is the downhill force?
c) What is the acceleration?
Answer:
Below
Explanation:
Normal force will be mg cos 15° = 1.5*9.81 cos 15° Newtons
Downplane force will be mg sin 15° = 1.5 * 9.81 sin 15° N
Acceleration
F = ma
F/m = a
1.5 ( 9.81) sin 15° / 1.5 m/s^2 = a
A physics student walks 6 meters east, 4 meters north, then 9 meters
west. What is the student's magnitude of displacement from starting
position?
Answer:
5 m
Explanation:
Displacement is the straight-line distance from the starting point to the end point. Student ends up 4m north and 3m west from where he started. Use pythagorean theorem to solve for displacement (d).
d² = 3² + 4² = 25
d = [tex]\sqrt{25}[/tex] = 5 m
Or, if you remember from geometry, a right triangle with legs of 3 and 4 has a hypotenuse of 5 (3-4-5 right triangle)
what is the kinetic energy of a 60.0 g tennis ball traveling at 177.0 kilometers per hour? report your answer in joules (j).
The kinetic energy is 939.87 J.
what is kinetic energy?Kinetic energy is the power that an object has as a result of motion. If we want to accelerate an object, we have to exert force. Applying force requires effort on our part. The object will be moving at a new, constant speed once the work is done because energy has been transferred to it.
A particle, an object, or a collection of particles can move because of kinetic energy, which is the force that drives motion. Kinetic energy is used by objects in motion like a person walking, a baseball being thrown, food falling from a table, and charged particles in an electric field.
Kinetic energy = 1/2mv²
Kinetic energy = 1/2×0.06×177²
Kinetic energy = 939.87 J.
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sir lancelot, who weighs 800 n, is assaulting a castle by climbing a uniform ladder that is 5.0 m long and weighs 180 n. the bottom of the ladder rests on a ledge and leans across the moat in equilibrium against a frictionless, vertical castle wall. the ladder makes an angle of 53.1 deg with the horizontal. lancelot pauses one third of the way up the ladder. (a) find the normal force and friction forces on the base of the ladder. (b) find the minimum coefficient of static friction needed to prevent slipping at the base. (c) find the magnitude and direction of the contact force on the base of the ladder. (that is, the vector sum of the forces at the base.)
(a) The normal force is 267.7 N and frictional force is 980 N.
(b) The minimum coefficient of static friction is 0.27, which is needed to prevent slipping at the base.
(c) The direction of the contact force is 1016 N.
∈(t) = 0
N₂ ( L sinθ ) = 800 ( [tex]\frac{L}{3}[/tex] cosθ )
N₂ = 267.7 N
(a) Normal force F(d) = N₂ = 267.7 N
Frictional force N = 800 + 180
N = 980 N
(b) The minimum coefficient of static friction,
F(d) = μ N₁
μ = F / N₁
μ = 267.7 / 980
μ = 0.27
(c) The direction of the contact force,
R = [tex]\sqrt{(980)^{2} + (267.7)^{2} }[/tex]
R = 1016 N
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a constriction in a pipe reduces its diameter from 4.0 cm to 2.0 cm. where the pipe is narrow the water speed is 8.0 m/s. where it is wide the water speed is:
The velocity on the narrow side is 11.6 m/s. This is the velocity of the water in the narrow part of the pipe.
How to find velocity ?To find the velocity of the water where the pipe is narrow, you can use the formula for the mass flow rate, which is given by:
Mass flow rate = Density * Flow rate
= Density * (Area * Velocity)
Where:
Density is the density of the fluid
Flow rate is the volume flow rate, or the rate at which volume flows through the pipe
Area is the cross-sectional area of the pipe
Velocity is the velocity of the fluid
The mass flow rate is constant, so you can set the mass flow rate on either side of the constriction equal to each other and solve for the velocity on the other side.
The cross-sectional area of the pipe on the narrow side is given by the formula for the area of a circle:
A = pi * r^2
Where:
A is the cross-sectional area of the pipe
r is the radius of the pipe
The radius of the pipe on the narrow side is 3 cm / 2 = 1.5 cm. Plugging this value into the formula for the cross-sectional area, you get:
A = pi * (1.5 cm)^2
= 7.07 cm^2
The cross-sectional area of the pipe on the wide side is given by the same formula, with a radius of 6 cm / 2 = 3 cm:
A = pi * (3 cm)^2
= 28.27 cm^2
Since the mass flow rate is constant, you can set the mass flow rates on either side of the constriction equal to each other and solve for the velocity on the other side:
(Density * 7.07 cm^2 * v) = (Density * 28.27 cm^2 * 8 m/s)
Solving for v, the velocity on the narrow side, you get:
v = (Density * 28.27 cm^2 * 8 m/s) / (Density * 7.07 cm^2)
= 11.6 m/s
The final value for the velocity on the narrow side is 11.6 m/s. This is the velocity of the water in the narrow part of the pipe.
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disregarding friction, how far will the cart move in 3.2 s, starting from rest? answer in units of m.
If the cart moves in 3.2 seconds from rest, then the distance traveled by cart is 2 meters.
Which definition of distance suits you best?How do you define distance? Regardless of direction, distance measures an object's overall movement. Distance is defined as the amount of ground covered by an object, regardless of its starting or stopping position.
Horizontal force acting on the cart, F = 11 N
Mass of the cart, m = 35 kg
To find,
Distance covered by the cart in 3.5 seconds if it starts from rest.
Solution,
Let x is the distance moved by the cart. It can be calculated using the second equation of motion as :
s = 1.925 meters
What is the definition of a distance?In terms of "how much land an object is covered" while traveling, distance—a scalar quantity—describes this. Displacement is a vector number that expresses the overall change in the object's location, and it is related to the phrase "how far from place the thing is."
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when you looked at solar activity on the heliophysics event registry website, on which date did you find activity on the sun?
You did look at solar activity on the heliophysics event registry website, and we found activity on the sun on the specified day.
What three sorts of solar occurrences are there?Any natural occurrence in the upper atmosphere of the sun is referred to as a solar phenomenon. Solar flares, prominences and filaments, and coronal mass ejections are three different categories of solar phenomena.
How can I follow the cycle of solar activity the best?The simplest way we can investigate how solar activity changes over time is to survey sunspots, which is also how we track the solar cycle. Sunspots are associated with the Sun's natural 11-year cycle, during which the planet's surface changes from calm to turbulent.
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a vertical spring has a spring constant of 100 n/m. when an object is attached to the bottom of the spring, the spring changes from its unstretched length of 0.50 to a length of 0.65 m. the magnitude of the weight of the object is
Answer: Hookes law states F=kX where F is the force applied, k is the spring constant, and X is the extension of the spring from its resting point.Substituting the values in, we get:F=100*(0.65-0.5)=100*0.15=15N
a simple harmonic oscillator takes 11.5 s to undergo five complete vibrations. (a) find the period of its motion. s (b) find the frequency in hertz. hz (c) find the angular frequency in radians per second. rad/s
The required values are a) T = 2.3 seconds, b) f = 0.434 Hz, c) ω = 2.7 rd/s.
Which of the following motions is simply harmonic?Simple harmonic motion, a particular kind of periodic motion in which a particle repeatedly oscillates around a mean location, In U-tube oscillating liquid column motion is hence simple harmonic.
According to question:Given,
Time = 11.5 seconds to five complete vibrations.
a) Time period is time taken to complete one vibration,
So T = 11.5/5 = 2.3 seconds
b) Frequency(f) = 1/T
f = 1/2.3 = 0.434 second inverse.
c) By using formula of angular frequency ω = 2π/T
ω = 2π/2.3 = 2.7 hz
Thus, final values are a) T = 2.3 seconds, b) f = 0.434 second inverse, c) ω = 2.7 rd/s.
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7. What is the weight of a ball with a mass of 0.77 kg? (hint: how fast is gravity?)
Answer:
While on the earth, any object with a mass of 0.77 kg weighs 7.546 newtons (1.698 pounds).
On the moon, the same 0.77-kg object would weigh 1.232 newtons (0.277 pound)
Explanation:
how long (in s) does it take a child on a swing to complete one swing if her center of gravity is 5.53 m below the pivot?
4.71 s long (in s) does it take a child on a swing to complete one swing if her center of gravity is 5.53 m below the pivot.
What is the center of the gravity?The average position of an object's weight is known as its center of gravity. Any object's travel through space may be entirely explained in terms of how its gravitational center moves from one location to another and, if it is free to spin, how it rotates around that center of gravity. Calculations combining gravitation and dynamics may be made much simpler by treating an object's mass as though it were concentrated at a single location.
Briefing:T=2π√(l/g)
T=2π√(5.53/9.81)
T=4.71
T =4.71 s
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a vertical spring scale can measure weights up to 210 n . the scale extends by an amount of 13.5 cm from its equilibrium position at 0 n to the 210 n mark. a fish hanging from the bottom of the spring oscillates vertically at a frequency of 2.15 hz . part a ignoring the mass of the spring, what is the mass m of the fish?
sheesh sheesh
Explanation:
The diagram below represents a wave.
What is the speed of the wave if its wavelength is 3.0 m?
The speed of the wave is determined as 18 m/s.
option D is the correct answer.
What is the speed of the wave?
The speed of the wave is the rate of change of wave's displacement with time.
The speed of the wave is calculated by applying the formula relating speed, wavelength and frequency of the wave as shown below.
v = fλ
where;
v is the speed of the wavef is the frequency of the waveλ is the wavelength of the waveThe frequency of the wave is calculated as follows;
f = 1 / T
where;
T is the period of the waveThe period of a wave is the time taken for the wave to complete one cycle.
In the picture given, 3 cycles of the wave = 0.5 s
1 cycle of the wave = ?
= 0.5 s / 3
= 0.16667 s
f = 1 / T
f = 1 / 0.16667
f = 6 Hz
The speed of the wave is calculated as follows;
v = fλ
v = 6 Hz x 3 m
v = 18 m/s
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1. a 1.4 x 103 kg car is westbound at a velocity of 37.0 km/h when it collides with a 2.0 x 103 kg truck northbound at a velocity of 35 km/h. if these two vehicles lock together upon collision, what is the initial velocity of the vehicles after collision? (7.2 m/s 37o w of n) 2. a 6.2 kg object heading north at 3.0 m/s collides with an 8.0 kg object heading west at 3.5 m/s. if these two masses stick together upon collision, what is their velocity after collision? (2.4 m/s 56o w of n) 3. a 4.0 x 104 n truck moving west at a velocity of 8.0 m/s collides with a 3.0x104 n truck heading south at a velocity of 5.0 m/s. if these two vehicles lock together upon impact, what is their velocity?(5.0 m/s 25o s of w)
The velocity of vehicles after the collision is 15.82m/sec if car mass is 1.4 × 10³kg and truck mass is 2×10³kg
We know that we need to conserve the momentum of watermelon in a certain direction. Also,we know that initial momentum of watermelon is zero,it means that according to law of conservation of momentum final momentum should be zero.
We know that momentum =mass × velocity
So,initial momentum of car is =1.4 × 10³kg × 37km/hr
Similarly,,initial momentum of truck=2×10³kg × 35km/hr
Now,it is given that both vehicles lock together,so total mass of both vehicles is =1.4 × 10³kg + 2×10³kg=3.4 ×10³kg
Assume final velocity of both vehicle is v
So,following the law of conservation,we get
=>1.4 × 10³kg × 37 + 2×10³kg × 35 = 3.4 ×10³ ×v
=>51.8 ×10³ + 2×10³=3.4×10³ ×v
=>53.8 ×10³ kg-m/sec = 3.4×10³ ×v
=>v = 53.8/3.4
=>v=15.82m/sec
Hence,final velocity of both vehicle after collision is 15.82m/sec.
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which sentence correctly describes when the triple-alpha process occurs in the life cycle of an average-mass star
Three helium-4 nuclei (alpha particles) are turned into carbon by a series of nuclear fusion processes known as the triple-alpha process.
What results from the triple-alpha procedure as the finished product?
The triple-alpha process and the alpha process are two classes of nuclear fusion reactions that stars use to change helium into heavier elements. The alpha process is also referred to as the alpha ladder. [1] Only helium is used in the triple-alpha process, which also yields carbon.
Which statement concerning alpha particles in an atom is accurate?
Two protons and two neutrons make up alpha particles, which are identical to helium nuclei and have a positive charge.
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Three point charges are arranged in a straight line. The point charges are q1 = 10.0 μC, q2 = –40.0 μC, and q3 = –30.0 μC. Charge q1 is 10.0 cm from charge q2, and charge q3 is 20.0 cm from charge q2. Determine the magnitude of the net electric force on charge q1.
Let us find first the forces at 1, 2 & 3 points.
We know that ke= 8.99 * 109N.m2 / C2
The forces are: -
F1 = keq1q2 / r212 = {8.99 * 109N.m2 / C2} * {10 * 10-6 C} * {40 * 10-6 C} / {10 * 10-2 m}2
F1 = 359.6 N
F2 =keq1q3 / r213 = {8.99 * 109N.m2 / C2} * {10 * 10-6 C} * {30 * 10-6 C} / {30 * 10-2 m}2
F2 = 29.96 N
F3 = keq2q3 / r213 = {8.99 * 109N.m2 / C2} * {40 * 10-6 C} * {30 * 10-6 C} / {20 * 10-2 m}2
F3 = 269.7 N
Now,
The net force on q1 is F1 – F2,
i.e. F1 + F2 = 359.6 + 29.96
F(q1) = 389.56 N to the left
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5. if the star sirius emits 23 times more energy than the sun, why does the sun appear brighter in the sky? include the terms luminosity and apparent brightness in your response.
The star Sirius is indeed brighter but our Sun appears to be brighter because it is closer to us.
The intrinsic luminosity of Sirius is exactly 25.4 times more than the sun but if we compare the distances of these stars, Sirius is 8.6 light years away from us and the Sun is just 8 light minutes away from us. This marks the obvious reason why our Sun appears more bright.
Even mathematically, it can be justified as the apparent brightness of any luminous object depends on the inverse square of the distance of that luminous object. Therefore the sun's light energy dominates our sky and we can't see any traces of Sirius from the earth.
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Study the following systems: SYSTEM A: Electricity is used to heat a hot plate which heats water making steam which powers a turbine and a generator which makes electricity which is used to power a radio. SYSTEM B: Electricity is used to power a radio. Which system (A or B) is more energy efficient and explain why.
The system that is more energy efficient is system A because it makes use of electricity to produce more results.
What is energy efficiency?Energy efficiency is the use of less energy to perform the same task or produce the same result.
Energy-efficient homes and buildings use less energy to heat, cool, and run appliances and electronics, and energy-efficient manufacturing facilities use less energy to produce goods.
Energy efficiency has the following benefits:
It saves moneyIt increases the resilience and reliability of the electric gridIt provides environmental, community, and health benefitsAccording to this question, the following applies:
SYSTEM A: Electricity is used to heat a hot plate which heats water making steam which powers a turbine and a generator which makes electricity which is used to power a radioSYSTEM B: Electricity is used to power a radioBased on the above explanation, it can be observed that system A is more energy efficient because it uses the same electricity to achieve more.
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Maher is trying to find the density of a plastic toy. The toy’s mass is 160 g.
Maher placed the toy in a graduated cylinder that has 70 ml of water, the water level increased
till 150 ml.
a) Find the toy’s volume.
The volume of the toy is 80 ml.
To find the volume of the plastic toy, Maher can use the principle of buoyancy. When an object is placed in a fluid, it will displace an amount of fluid equal to its own volume. The volume of the displaced fluid can be measured and used to calculate the volume of the object.
In this case, Maher has placed the toy in a graduated cylinder filled with water, and he has observed that the water level increased from 70 ml to 150 ml. This means that the toy displaced 150 - 70 = 80 ml of water.
The volume of the toy is equal to the volume of the displaced water, so the toy's volume is 80 ml. This is the volume of the toy when it is completely submerged in water.
It's important to note that the volume of an object can change depending on its temperature, pressure, and other factors. To get an accurate measurement of the volume of the toy, Maher should make sure to measure the volume of the displaced water carefully and under controlled conditions.
Answer:
Volume of the toy: [tex]80\; {\rm mL}[/tex].
Average density of the toy: [tex]2\; {\rm g\cdot mL^{-1}}[/tex] (or equivalently, [tex]2\; {\rm g \cdot cm^{-3}}[/tex].)
Explanation:
The graduated cylinder initially measures the volume of water in this cylinder:
[tex]V(\text{water}) = 70\; {\rm mL}[/tex].
Assume that the toy is submerged in the water. The graduated cylinder would then measure the volume of the water and the toy, combined:
[tex]V(\text{water}) + V(\text{toy}) = 150\; {\rm mL}[/tex].
Rearrange to find the volume of the toy:
[tex]\begin{aligned}V(\text{toy}) &= 150\; {\rm mL} - V(\text{water}) \\ &= 150\; {\rm mL} - 70\; {\rm mL} \\ &= 80\; {\rm mL}\end{aligned}[/tex].
To find the average density of this toy, divide mass by volume:
[tex]\begin{aligned}(\text{average density}) &= \frac{(\text{mass})}{(\text{volume})} \\ &= \frac{160\; {\rm g}}{80\; {\rm mL}} \\ &= 2\; {\rm g\cdot mL^{-1}}\end{aligned}[/tex].
two planets are identical, except planet x has an atmosphere of mostly nitrogen and planet y has an atmosphere of mostly carbon dioxide. what can you determine about the planets
Two planets are identical, except planet x has an atmosphere of mostly nitrogen and planet y has an atmosphere of mostly carbon dioxide therefore what we can determine about the planets is that x is Earth while y is Venus.
What is Atmosphere?This is referred to as the envelope of gases surrounding the earth or another planet and it makes life possible by providing different organisms with air to breathe
In the atmosphere of the planet Venus there is a high concentration of carbon dioxide as it is made up of it is made of 96.5% of CO₂ and a 3% of nitrogen.
On the other hand in the atmosphere of the planet Earth, there is a high concentration of nitrogen which is about 78% and is therefore the reason why they were chosen as the correct choices.
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A car travels down a road at a certain velocity, vcar. The driver slows down so that the car is traveling only a third as fast as before. Which of the following is the correct expression for the resulting velocity?
a. 2vcar
b. 1/3vcar
c. -1/2vcar
d. -2vcar
The correct expression for the resulting velocity is -1/2 vcar. The correct option is c.
What is velocity?
The directional speed of an item in motion, as measured by a specific unit of time and observed from a certain point of reference, is what is referred to as velocity.
A car travels down a road at a certain velocity, is Vcar.
Let the initial velocity of the car travel downward be -V car
It is also, given, that the driver slows down so that the car is traveling only half as fast as before.
Resulting velocity = -1/2 vcar
Therefore, the correct option is c. -1/2vcar.
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The adjacent figure shows a solid 'S' of weight 15N connected to a thread and put on an inclined plane. 1) a-Is the weight of solid 'S' a contact force or a force acting from a distance? b- List the characteristics of the weight of solid 'S'. Thread Inclined plane c- Represent the weight of solid 'S' by a vector. Choose a convenient scale. 2) a- Name the other forces acting on solid 'S' and indicate their types. b- Represent each force by a vector without respecting a scale. c- List the characteristics of each of the above forces. (Without the magnitude) 3) The thread is cut and solid 'S' moves as shown in the adjacent figure a- Name the new force that acts on solid 'S' and indicate its type. b- List the characteristics of this force.(scale 1cm-1.3N). Thread Inclined plane Solid 'S' Solid 'S'
Answer:
Here is answer
Explanation:
a) The weight of the solid 'S' is a contact force because it acts on the solid 'S' through physical contact with the ground.
b) The characteristics of the weight of solid 'S' are:
It acts in the downward direction.
It is a gravitational force that is exerted by the Earth on the solid 'S'.
It is equal to the mass of the solid 'S' multiplied by the acceleration due to gravity (W = m*g).
c) The weight of solid 'S' can be represented by a vector as shown below:
[asy]
unitsize(1cm);
draw((0,0)--(0,15),Arrow(6));
label("$W$", (0,7.5), W);
[/asy]
a) The other forces acting on solid 'S' are the normal force exerted by the inclined plane on the solid 'S' and the frictional force exerted by the inclined plane on the solid 'S'. The normal force is a contact force, while the frictional force is also a contact force.
b) These forces can be represented by vectors as shown below:
[asy]
unitsize(1cm);
draw((0,0)--(0,15),Arrow(6));
label("$W$", (0,7.5), W);
draw((0,0)--(15sqrt(2)/2,15/2),Arrow(6));
label("$N$", (7.5sqrt(2),7.5), NE);
draw((0,0)--(-15sqrt(2)/2,-15/2),Arrow(6));
label("$F_f$", (-7.5sqrt(2),-7.5), SW);
[/asy]
c) The characteristics of these forces are:
The normal force acts perpendicular to the surface of the inclined plane.
The frictional force acts in the opposite direction to the direction of motion or intended motion of the solid 'S'.
The magnitude of the normal force is equal to the weight of the solid 'S', but in the opposite direction.
The magnitude of the frictional force depends on the coefficient of friction between the solid 'S' and the inclined plane, as well as the normal force.
a) The new force acting on solid 'S' is the gravitational force, which is a force acting from a distance.
b) The characteristics of the gravitational force are:
It acts in the downward direction.
It is a force that is exerted by the Earth on the solid 'S'.
Its magnitude can be represented by the vector shown below (using a scale of 1 cm to represent 1.3 N):
[asy]
unitsize(1cm);
draw((0,0)--(0,-1.3),Arrow(6));
label("$W$", (0,-0.65), S);
[/asy]
Classify the type of reaction below.
C2H6 + O2
--> CO2 + H2O
a. Synthesis
b. Decomposition
c. Combustion
d. Single Replacement
e. Double Replacement
Answer: Synthesis
Explanation: You are combining multiple Elements