A 6 kg object's Ug increases by 150 J. What was its change in height?
Please help I don’t understand this and fast please

Answers

Answer 1

Answer:

2.5 m

Explanation:

Potential energy is the energy stored in an object as a result of its position relative to other objects

The change in potential energy is given by:

ΔPE = mgh;

where ΔPE is the change in potential energy, m is the mass if the object, g is the acceleration due to gravity and h is the change in height of the object.

Hence given that g = 10 m/s², ΔPE = 150 J, m = 6 kg, hence:

ΔPE = mgh

150 = 6 * 10 * h

150 = 60h

h = 2.5 m

Hence the change in height is 2.5 m


Related Questions

Draw a closed circuit diagram of the battery of 2 cells arranged in series, connecting wire, switch and bulb; mark the direction of the current.
pls ill give brainly

Answers

This is the open switch 2 cells connecting wire and bulb

8. A copper container of 84g mass contains 84g of water at 20°C. 46g of water at 200°C is mixed with water in the copper ontainer. What is the final temperature of the water? Specific heat capacity of water = 4200 J kg-1 °C-1, Specific heat capacity of copper = 400 J kg-1 °C-1 ​

Answers

Answer:

80 °C

Explanation:

The heat transfer parameters for the water and copper container are;

Mass of the copper container, m₁ = 84 g

Mass of the water in the container, m₂ = 84 g

Initial temperature of the water in the container, T₂ = 20°C

Mass of the hot water added, m₃ = 46 g

Initial temperature of the hot water, T₃ = 200°C

Specific heat capacity of water, c₂ = 4,200 J·kg⁻¹·°C⁻¹

Specific heat capacity of copper, c₁ = 400 J·kg⁻¹·C⁻¹

The formula for the specific heat, ΔQ = m·c·ΔT

The heat lost by the hot water = The heat gained by the container the and the cold water

The formula for the specific heat of the mixture is presented as follows;

m₃ × c₃ × (T₃ - T)  = m₁ × c₁ × (T - T₁) + m₂ × c₂ × (T - T₂)

Where T represents the final temperature of the water

Therefore, by plugging in the values, we get;

46 × 4200 × (200 - T) = 84 × 400 × (T - 20) + 84 × 4200 × (T - 20)

38640000 - 193200·T = 386400·T - 7728000

38640000 + 7728000 = 46368000 = 386400·T + 193200·T = 579,600·T

∴ T = 46368000/579,600 = 80

The final temperature of the water, T = 80°C

Use the information below the answer the following 3 questions.

A 50 kg crate is being dragged across a floor by a force of 225 N at an angle of 40o from the horizontal. The crate is dragged a distance of 5.0 m and the frictional force is 60 N.



Question 2 (2 points)
Question 2 options:
The work done on the crate by the applied force is ___x102 Nm. (Give your answer with the correct number of sign digs and do not include units).
Question 3 (2 points)
Question 3 options:
The work done on the crate by the frictional force is -___x102 Nm. (Give your answer with the correct number of sign digs and do not include units).
Question 4 (2 points)
Question 4 options:
The net work done on the crate is ___x102 Nm. (Give your answer with the correct number of sign digs and do not include units).

Hint: Do not use rounded answers in subsequent calculations

Answers

Answer:

2. 8.62×10² Nm

3. 2.30×10² Nm

4. 6.32×10² Nm

Explanation:

2. Determination of the work done by the applied force.

Force (F) = 225 N

Distance (d) = 5 m

Angle (θ) = 40°

Workdone (Wd) =?

Wd = Fd × Cos θ

Wd = 225 × 5 × Cos 40

Wd = 8.62×10² Nm

3. Determination of the work done by the frictional force.

Frictional Force (Fբ) = 60 N

Distance (d) = 5 m

Angle (θ) = 40°

Workdone (Wd) =?

Wd = Fբd × Cos θ

Wd = 60 × 5 × Cos 40

Wd = 2.30×10² Nm

4. Determination of the net work done.

We'll begin by calculating the net force acting on the crate

Force applied (F) = 225 N

Frictional Force (Fբ) = 60 N

Net force (Fₙ) =?

Fₙ = F – Fբ

Fₙ = 225 – 60

Fₙ = 165 N

Finally, we shall determine the net Workdone. This can be obtained as follow:

Net force (Fₙ) = 165 N

Distance (d) = 5 m

Angle (θ) = 40°

Workdone (Wd) =?

Wd = Fₙd × Cos θ

Wd = 165 × 5 × Cos 40

Wd = 6.32×10² Nm

Two astronomy students travel to South Dakota. One stands on Earth’s surface and enjoys some sunshine. At the same time, the other descends into a gold mine where neutrinos are detected, arriving in time to detect the creation of a new radioactive argon nucleus. Although the photon at the surface and the neutrinos in the mine arrive at the same time, they have had very different histories. Describe the differences.

Answers

Answer:

The photon takes millions of years to reach the Surface of the sun while the Neutrinos travelling at the speed of light reaches the surface of the sun in approximately 2 seconds

The Photon is million year old while the neutrino is just some minutes old as observed by the student .

Explanation:

Although The Photon ( sunshine from the sun's surface ) heating up the student standing on the Earth's surface and the neutrinos discovered by the other student inside the gold mine are both formed in the Sun's core.

The difference between both are

The photon takes millions of years to reach the Surface of the sun while the Neutrinos travelling at the speed of light reaches the surface of the sun in approximately 2 seconds

The Photon is million year old while the neutrino is just some minutes old as observed by the student .

How can we measure electromotive force of a battery illustrated answer with the help of circuit diagram

Answers

Answer:

the emf of the cell can be determined by measuring the voltage across the cell using a voltmeter and the current in the circuit using an ammeter for various resistances.

absolute potential difference ,due of point charge of 1C at a distance of 1 m is given by

Answers

Answer:

[tex] \implies U = \dfrac{kq}{r} [/tex]

[tex]\implies U = \dfrac{9 \times {10}^{9} \times 1}{1} [/tex]

[tex]\implies U = 9 \times {10}^{9} \: J[/tex]

We have that absolute potential difference ,due of point charge of 1C at a distance of 1 m is given by

[tex]\rho=9x10 ^{10}J[/tex]

From the question we are told that

point charge of 1C at a distance of 1 m

Generally the equation for the Electrostatic potential energy  is mathematically given as

[tex]\rho=\frac{kq_1q_2}{r}[/tex]

Where k is a constant

[tex]k=9*10^9Nm^2/c^2[/tex]

Therefore

[tex]\rho=\frac{(9*10^9)1*10^(-6)*1*10^{-6}}{1}[/tex]

[tex]\rho=9x10 ^{10}J[/tex]

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What is the final step in the fourth stage of technological design, after a product has been improved abs approved

Answers

Answer:

Evaluate the solution.

Explanation:

A technological design is designed as the design and study of a solution that can be provided from the solution by identifying the root cause or problem and trying to solve by various means.

A good technological design requires the minimum effort and resources while meeting the requirement of the problem.

The steps involved in the technological design are :

1. search and identify the problem or need.

2. design a solution

3. Implement a solution.

4. Evaluate the solution.

Therefore, the final step or the fourth step in the process of a technological design is " evaluating or communicating the final design solution".

how far should an object be from a converging mirror of radius 36cm to form a real image one - ninth of its size​

Answers

Answer:

focal length :

[tex]{ \tt{f = \frac{r}{2} }} \\ focal \: length = \frac{36}{2} = 18 \: cm[/tex]

From linear magnification:

[tex]{ \tt{ \frac{1}{m} + 1 = \frac{u}{f} }} \\ \frac{1}{9} + 1 = \frac{u}{18} \\ \\ u = \frac{18 \times 10}{9} \\ u = 20 \: cm[/tex]

The object must be at 20 cm

What is the relationship between electric field lines and equipotential lines that you observed in doing the lab

Answers

Answer:

Explained below

Explanation:

Generally speaking, we know in physics that Electric field lines are lines which usually start at positive charges and deflect away from them to terminate at the negative charges. Meanwhile Equipotential lines are lines that are used to connect points located on the same electric potential.

Finally, in conclusion, electric field lines are usually lines that go through in a perpendicular manner across every equipotential lines.

The search for black holes involves searching for Group of answer choices single stars that emit large amounts of X-rays. a stellar core greater than 3 solar masses large spherical regions from which no light is detected. pulsars with periods less than one millisecond. pulsars that are orbited by planets.

Answers

Answer:

A stellar core greater than 3 solar masses

Explanation:

The process of the evolution of a star in which the star changes form with time, includes phases of evolution which are determined by the mass of the core of the star, which involves a process of conversion of elements and the contraction of the star

Where the mass of the core of the star is more than the mass of three Suns, (3 solar masses) the contraction of the star continues, due to the gravitational force being larger than the pressure exerted by neutron, such that the star collapses to a black hole

Therefore, the search for black holes involves searching for a stellar core greater than 3 solar masses.


A force of 825N is required to push
a car across a lot.Tow students push the car 35m.How much work is done?

Answers

Answer:

the work done by the two students is 28,875 J

Explanation:

Given;

applied force, f = 825 N

distance through which the car is pushed, d = 35 m

The work done by the two students who pushed the 825 N across 35 m lot is calculated as follows;

Work done = force x distance

Work done = 825 N x 35 m

Work done = 28,875 Nm = 28,875 J

Therefore, the work done by the two students is 28,875 J

if the pelican in item 3 was traveling at the same speed but was only 2.7m above the water, how far would the fish travel horizontally before hitting the water?​

Answers

Answer:

5.66 m

Explanation:

From online sources, the speed in item 3 being referred to was discovered to be 7.62 m/s

Now, let's get the time of flight from one of Newton's equation of motion;

S = ut + ½gt²

Considering the vertical component, we have u = 0 m/s.

Thus;.

S = ½gt²

Plugging in the relevant values;

2.7 = ½ × 9.8 × t²

t² = 2.7/4.9

t = √(2.7/4.9)

t = 0.7423 s

Now, when we consider the horizontal component of the motion, we have;

S = vt

Where;

S is the distance the fish will travel horizontally before hitting the water.

v = 7.62 m/s

t = 0.7423

Thus

s = 7.62 × 0.7423

s ≈ 5.66 m

The graph shows the motion of a car. Which segment
shows that the car is slowing down?
O A
OB
Ос
OD

Answers

Answer: its C

Explanation:

you are pedaling forward on your bike. which of the following would decrease your acceleration?
A. A decrease in your mass
B. A increase in your applied force
C. An increase in your mass
D. An increase in your speed

Answers

Pedaling forward over the bike with the increase in your applied force would decrease your acceleration. Thus, option B is correct.

What is acceleration?

Acceleration is define as the rate at which velocity changes with time, in terms of both speed and direction. The equation for acceleration is:

a=F/m

where, a = acceleration,

F = force applied

m =  mass of the object

The acceleration of an object depends directly upon the net force acting upon the object, and inversely upon the mass of the object.

As the force acting upon an object is increased, the acceleration of the object is increased. As the mass of an object is increased, the acceleration of the object is decreased.

Therefore, if you are pedaling forward on your bike then a increase in your applied force would decrease your acceleration. Thus, option B is correct.

Learn more about acceleration here:

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Answer:

I just did it. A is right.

Explanation:

Which statement describes why energy is released in a nuclear fission reaction based on mass-energy equivalence?

A. For large nuclei, the mass of the original nucleus is greater than the mass of the products.
B. For large nuclei, the mass of the original nucleus is less than the mass of the products.
C. For small nuclei, the binding energy of the lighter nuclei is greater than the binding energy of the heavier nucleus.
D. For small nuclei, the binding energy of the lighter nuclei is less than the binding energy of the heavier nucleus.

Answers

Answer:

A is the answer!

Explanation:

Edge 2021

Answer:

A

Explanation:

Edge

An electron enters the magnetic field at right angle from left B into paper. The electron will be deflected?

Answers

Answer:

According to this direction of force is perpendicular to the direction of current and magnetic field. Therefore force is opposite to electron into the paper at 90°.

For saving lives, what is the most important safety feature on a car? A. Air bag B. Safety Belt C. Anti-lock brakes

Answers

i'd imagine the answer is safety belt, but i don't have anything to back that up with

For saving lives  the most important safety feature on a car is B. Safety Belt

What are safety features of  a car ?

Safety features of  a car is a feature of a product designed to ensure or increase safety.

Air bag and Anti-lock brakes are the supplemental protection and designed to work best with combination with seat bells.

Air bag reduce the chance that upper body or head will strike the vehicle's interior during a crash alongside with belt that will  also hold your upper body

so, the primary safety feature is seat belt and Air bag and Anti-lock brakes  comes in secondary safety feature  as they increases the safety and risk of getting an injury during any accident

correct answer is B. Safety Belt

learn more about Safety features

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it will be easier to lift a load in wheel barrow if the load is moved towards the wheel. Give Reason.

Answers

Answer:

Here's your answer: The wheelbarrow's wheel and axle help the wheelbarrow to move without friction thus making it easier to push or pull. That's why it will be easier to lift a load in wheel barrow of the load is transferred towards the wheel.

Explanation:

Answer:

Explanation:

The wheel barrows wheel and axle helps the wheelbarrow to move without friction this making it easier to push or pull.thats why it will be easier to lift a load in a wheelbarrow if it's transferred towards the wheel..

Hope it helps

(d) Below shows a hydraulic press with a pump piston of area 4 cm2 and a ram area of

12 cm2 . IF A force of 300 N is applied on the pump piston, find:

(i)the maximum load on the ram.

(ii) the velocity ratio of the machine.

(iii) the mechanical advantage of the machine.

(iv)the efficiency of the machine.

Answers

Answer:

Explanation:

hi

Select the definition that best describes the term “strain.”


A measure of the degree of plastic deformation that a material can withstand before failure.


The elongation (or change in length) of a specimen divided by the original length, sometimes referred to as percent elongation.


Indication of how much energy a material can absorb before failure.


Also known as the modulus of elasticity, this is the constant of proportionality as defined by Hooke’s Law.


The instantaneous force applied to a specimen divided by the cross-sectional area.

Answers

Answer:

The elongation (or change in length) of a specimen divided by the original length, sometimes referred to as percent elongation.

Explanation:

Strain is defined mathematically as follows .

strain = Δ L/ L

Δ L is change in length of a wire when some force is applied on it to stretch it along its length and L is original length of a wire .

Stress is The elongation (or change in length) of a specimen divided by the original length, sometimes referred to as percent elongation.

Answer:

The elongation (or change in length) of a specimen divided by the original length, sometimes referred to as percent elongation.

Explanation:

Every object has some elastic and inelastic properties.

The strain is defined as the ratio of change in dimensions to the original dimensions.

There are three types of strains:

1. Longitudinal strain

2. Volumetric strain

3. Shear strain

So, it is defined as elongation (or change in length) of a specimen divided by the original length, sometimes referred to as percent elongation.

A rectangular coil of wire, 22.0 cm by 35.0 cm and carrying a current of 1.40 A, is oriented with the plane of its loop perpendicular to a uniform 1.50-T magnetic field pointing into the plane of the loop. Let the loop be in x-y Cartesian plane so that the long and short sides of the loop are parallel to x- and y-axis, respectively. The loop center is at the origin of x-y Cartesian plane. Note that the magnetic field is in the direction of the negative z-axis.a. Calculate: (i) the net force that the magnetic field exerts on the coil; (ii) the torque about the z-axis that the magnetic field exerts on the coil.b. The plane of the coil is now rotated through +30º from its initial orientation (the x-y plane of the Cartesian coordinate system that remains the same). Calculate: (i) the net force that the magnetic field exerts on the coil; (ii) the torque about the rotation axis that the magnetic field exerts on the coil.

Answers

Answer:

a)  [tex]F_{net}=0[/tex]

b)  [tex]T=0[/tex]

Explanation:

From the question we are told that:

Dimensions:

[tex]L*B=22.0*35.0cm[/tex]

Current [tex]I=1.40A[/tex]

Magnetic field [tex]B=1.40[/tex]

Therefore

[tex]Area=L*B[/tex]

[tex]A=22.0*35.0cm[/tex]

[tex]A=770cm=>770*0^{-4}[/tex]

a)

Generally Force on Looping gives

[tex]F_1-F_2[/tex]

[tex]F_3=F_4[/tex]

Therefore

[tex]F_{net}=0[/tex]

b)

Generally the equation for Torque is mathematically given by

[tex]T=i*Asin \theta[/tex]

Since A and B are on opposite direction

[tex]\theta=180[/tex]

Therefore

[tex]T=1.40*770*10^{-4}sin 180[/tex]

[tex]T=0[/tex]

A bowling ball is pushed with a force of 22.0 N and accelerates at 5.5 m/s2. What is the mass of the bowling ball?

Answers

Answer:

4 kg

Explanation:

F (force) = 22.0 N

m (mass) = ? (in Kg)

a (acceleration) = 5.5 m/s²

We apply the data to the Resultant Force formula, we have:

f=ma

22=m x 5.5

5.5m=22

m=22/5.5

m=4kg

Answer:

[tex]\boxed {\boxed {\sf 4 \ kilograms}}[/tex]

Explanation:

According to Newton's Second Law of Motion, force is the product of mass and acceleration.

[tex]F= m*a[/tex]

The bowling ball was pushed with a force of 22.0 Newtons and the acceleration was 5.5 meters per second squared.

1 Newton is equal to 1 kilogram meter per second squared. Therefore, the force of 22.0 N is equal to 22 kg*m/s² (we do this conversion so we can easily cancel the units later).

F= 22.0  kg*m/s²a= 5.5 m/s²

Substitute the values into the formula.

[tex]22.0 \ kg*m/s^2 = m * 5.5 \ m/s^2[/tex]

We are solving for the mass, so we must isolate the variable m. It is being multiplied by 5.5 meters per second squared. The inverse of multiplication is division, so we divide both sides by 5.5 m/s²

[tex]\frac { 22.0 \ kg*m/s^2}{5.5 \ m/s^2} = \frac{m * 5.5 \ m/s^2}{5.5 \ m/s^2}[/tex]

[tex]\frac { 22.0 \ kg*m/s^2}{5.5 \ m/s^2}=m[/tex]

The units of meters per second squared (m/s²) cancel.

[tex]\frac { 22.0 \ kg}{5.5 }=m[/tex]

[tex]4 \ kg =m[/tex]

The mass of the bowling ball is 4 kilograms.

1. A 5 cm3 balloon is filled by a gas at a pressure

of 1 x 105 Pa . When the balloon is filled by 20

cm3 of the gas, what is the new pressure of the

gas?



A 1.0 x 105 Pa B 4.0 x 104Pa

C 2.5 x 104Pa D 4 x 103 Pa

E 5x 103 Pa


2. A bubble of air is formed at the base of a lake.

At that moment, its volume is 30 cm3 and it

experiences a pressure of 190 of cm Hg. What

is the volume of the bubble when it reaches the

surface of the sea.

[ The atmospheric pressure =

76 cm of Hg ]

A 25 cm3 B 50 cm3

C 75 cm3 D 100 cm3

E 150 cm3

Answers

Answer:

1) C. 2.5 x 10⁴ Pa

2) C. 75 cm³

Explanation:

Question 1.

Given the following data;

Initial volume, V1 = 5 cm³Initial pressure, P1 = 1 * 10⁵ PaFinal volume, V2 = 20 cm³

To find the final pressure, P2, we would use Boyle's law;

Boyles states that when the temperature of an ideal gas is kept constant, the pressure of the gas is inversely proportional to the volume occupied by the gas.

Mathematically, Boyles law is given by;

PV = K

P1V1 = P2V2

Making P2 the subject of formula, we have;

P2 = (P1V1)/V2

Substituting into the formula, we have;

P2 = (1 * 10⁵ * 5)/20

P2 = (500,000)/20

Final pressure, P2 = 25,000 Pa or 2.5 x 10⁴ Pa.

Question 2.

Given the following data;

Initial volume, V1 = 30 cm³Initial pressure, P1 = 190 of cm HgFinal pressure, P2 = 76 cm of Hg

To find the final volume, we would use Boyle's law;

Mathematically, Boyles law is given by;

PV = K

P1V1 = P2V2

Making V2 the subject of formula, we have;

V2 = (P1V1)/P2

Substituting into the formula, we have;

V2 = (190 * 30)/76

V2 = 5700/76

Final volume, V2 = 75 cm³

The net charge difference across the membrane, just like the charge difference across the plates of a capacitor, is what leads to the voltage across the membrane. How much excess charge (in picocoulombs, where 1 pc = 1x10-12 C) must lie on either side of the membrane of an axon of length 2 cm to provide this potential difference (0.07 V) across the membrane? You may consider that a net positive charge with this value lies just outside the axon cell wall, and a negative charge with this value lies just inside cell wall, like the equal and opposite charges on capacitor plates. Again, make sure to include LaTeX: \kappa=7κ = 7 for the lipid bilayer.

Answers

Answer:

a)  Q = 1.24 10⁻² pC,  b) Q = 8.68 10⁻² pC

Explanation:

a) the capacitance is defined

          C = [tex]\frac{Q}{\Delta V} = \epsilon_o \frac{A}{d}[/tex]

           Q = ε₀  [tex]\frac{A}{d} \ \Delta V[/tex]

let's calculate

           Q = 8.85 10⁻¹²  0.07 [tex]\frac{A}{d}[/tex]

           Q = 0.6195 10⁻¹²  [tex]\frac{A}{d}[/tex]

where a is the area of ​​the membrane

            A = d L

            Q = 0.6195 10⁻¹² Ll

            Q = 0.6195 10⁻¹² 0.02

             Q = 1.24 10⁻¹⁰ C

             Q = 1.24 10⁻² pC

       

B) the membrane is full of fat with k = 7

            C = [tex]\frac{Q}{\Delta V} = k \epsilon_o \ \frac{A}{d}[/tex]

            Q = k ε₀  [tex]\frac{A}{d} \ \Delta V[/tex]

             Q = k Q₀

            Q = 7   1.24 10⁻²

            Q = 8.68 10⁻² pC

In certain ranges of a piano keyboard, more than one string istuned to the same note to provide extra loudness. For example, thenote at 1.10 x 102 Hz has two strings at this frequency.If one string slips from its normal tension of 6.00 x102 N to 5.40 x 102 N, what beatfrequency is heard when the hammer strikes the two stringssimultaneously?

Answers

Answer:

The beat frequency is 5.5 Hz.

Explanation:

f = 110 Hz, T = 600 N , T' = 540 N

let the frequency is f'.

[tex]\frac{f'}{f}=\sqrt\frac{T'}{T}\\\\\frac{f'}{f}=\sqrt\frac{540}{600}\\\\\frac{f'}{f}=0.95\\\\f'= 104.5 Hz[/tex]

So, the beat frequency is f - f' = 110 - 104.5 = 5.5 Hz

A parallel combination of a 1.47 μF capacitor and a 2.95 μF capacitor is connected in series to a 4.89 μF capacitor. This three‑capacitor combination is connected to a 15.5 V battery. Determine the charge on each capacitor.

Answers

Answer:

a. i. 35.96 μC  b. i. 11.98 μC ii. 24.04 μC

Explanation:

We need to find the total capacitance of the system C.

The total capacitance of the parallel combination of a 1.47 μF capacitor and a 2.95 μF capacitor is C' = 1.47 μF + 2.95 μF = 4.42 μF.

C' = 4.42 μF is in series with the 4.89 μF capacitor and for a series combination of capacitors, we have the total capacitance, C from

1/C = 1/4.42 μF + 1/4.89 μF

1/C = (4.42 μF + 4.89 μF)/(4.42 μF × 4.89 μF)

1/C = 9.31 μF/21.6138 μF²

C = 21.6138/9.31 μF

C = 2.32 μF

So, the total charge in the circuit Q = CV where C = total capacitance = 2.32 μF and v = voltage = 15.5 V

So, Q = CV

Q = 2.32 μF × 15.5 V

Q = 35.96 μC

i. The charge on the 4.89 μF capacitor

Since the 4.89 μF is in series with C', the total charge flowing i the circuit is the total charge in the 4.89 μF capacitor. So, its charge Q = 35.96 μC

b. The charge in the 1.47 μF and 2.95 μF capacitors.

To find the charge in the 4.89 μF and 2.95 μF capacitors, we need to find the voltage across the combined parallel combination of a 1.47 μF capacitor and a 2.95 μF capacitor. The voltage, V' across the 4.89 μF capacitor, since Q = CV', V' = Q/C = 35.96 μC/4.89 μF = 7.35 V

So, the voltage V" across the combined parallel combination of a 1.47 μF capacitor and a 2.95 μF capacitor, C' is V" = 15.5 V - V' (since V' + V" = 15.5 V).

So, V" = 15.5 V - V'

V" = 15.5 V - 7.35 V

V" = 8.15 V

i. The charge on the 1.47 μF capacitor

Using Q' = CV" where Q' = charge across capacitor, C = 1.47 μF and V" = 8.15 V.

So, Q' = CV"

Q' = 1.47 μF × 8.15 V

Q' = 11.98 μC

ii. The charge on the 2.95 μF capacitor

Using Q" = CV" where Q' = charge across capacitor, C = 2.95 μF and V" = 8.15 V.

So, Q" = CV"

Q" = 2.95 μF × 8.15 V

Q" = 24.04 μC

Which activity is best described as a scientific endeavor?
A. Designing devices astronauts can use to help them stay healthy
while in space
B. Developing a procedure for testing how extended stays in space
affect the human body
C. Performing tests on devices used by astronauts to ensure they
can be used safely
D. Creating a process for improving the design of equipment used to
monitor astronauts' health

Answers

Answer:

B

Explanation:

BECAUSE TO DO THE TESTS YOU NEED TO DO THE SCIENTIFIC METHOD.

FOR EXAMPLE: OBSERVATIONS AND EXPERIMENTS TO OBTAIN RESULTS.

ANYWAY I LEAVE YOU THE LINK:

https://gscourses.thinkific.com

An object 20mm high is placed 10cm from a sperical mirror and forms a virtual image which is 40mm high. what is the radius of curvature off the mirrors​

Answers

Answer:

R = 40 cm

Explanation:

From the formulae of magnification:

[tex]\frac{q}{p}=\frac{image\ height}{object\ height}\\\\\frac{q}{10\ cm} = \frac{4\ cm}{2\ cm}\\\\q = (10\ cm)(2)\\\\q = 20\ cm[/tex]

where,

q = image distance from mirror

p = object distance from mirror

Using thin lens formula:

[tex]\frac{1}{f}=\frac{1}{p}+\frac{1}{q}\\\\\frac{1}{f}=\frac{1}{10\ cm}+\frac{1}{-20\ cm}\\\\\frac{1}{f} = 0.05\\\\f = 20\ cm[/tex]

q is negative for the virtual image.

Now, the radius of the spherical mirror is double the focal length (f):

R = 2f

R = 2(20 cm)

R = 40 cm

A toy airplane is flying at a speed of 3 m/s with an acceleration of 1.1 m/s squared how fast is it flying after five seconds

Answers

Answer:

[tex]8.5\frac{m}{s}[/tex]

Explanation:

Use Kinematics:

[tex]v = v_0 + at[/tex]

[tex]v = 3 + 1.1 * 5[/tex]

[tex]v = 8.5 \frac{m}{s}[/tex]

Help
The Euler buckling load of a 160-cm-long column will be _____ times the Euler buckling load of an equivalent 120-cm-long column.


1.78


0.56


0.75


2.37


1.33


0.42

Answers

Answer:

Length in times = 0.75 times

Explanation:

Given:

Length of Euler buckling load = 160 cm

Equivalent load length = 120 cm

Find:

Length in times

Computation:

Length in times = Equivalent load length / Length of Euler buckling load

Length in times = 120 / 160

Length in times = 12 / 16

Length in times = 3 / 4

Length in times = 0.75 times

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